which of these values could be the slopebof the line? select 2 options.​

d)An error because d cannot be negative.

According to the data, effect sizes such as Cohen's d typically range from 0 to positive values, and negative values do not make sense in this context. Therefore, an effect size of d = -63 is likely an error or a typo.

Assuming that the correct effect size is a positive value, the magnitude of the effect size can be described as follows based on Cohen's convention:

However, it's important to note that the interpretation of effect sizes also depends on the context and the specific field of study.

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a. It is b. Permutation

b. Using permutation, the number of different codes is 3024 passcodes.

Permutation is the total number of ways of arranging n different objects in x ways ⁿPₓ  = n!/(n - x)! while combination is the total number of ways of selecting n objects x at a time ⁿCₓ = n!/x!(n - x)!

a. Since Sara is setting a new code for her garage. The key pad has the numbers 0-9 to choose from, and she needs to set a 4-digit passcode. Since no digit is to be repeated, it is a permutation since in permutation, we are looking for differnt arrangemnets of the objects.

So, it is b. Permuation

b. Since Sara the key pad has the numbers 0-9 to choose from, and she needs to set a 4-digit passcode and no digit is to be repeated. We have 9 digits permuted or arranged in 4 ways. So, our permutation is ⁹P₄ = 9 × 8 × 7 × 6

= 3024 passcodes

So, the number of different codes is 3024 passcodes.

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The expression sin 4x / cos 2x simplifies to 2 sin 2x (option b).

To simplify the expression sin 4x / cos 2x, we can use the trigonometric identity:

sin 2θ = 2 sin θ cos θ

Applying this identity, we have:

sin 4x / cos 2x = (2 sin 2x cos 2x) / cos 2x

Now, the cos 2x term cancels out, resulting in:

sin 4x / cos 2x = 2 sin 2x

So, the expression sin 4x / cos 2x simplifies to 2 sin 2x, which is option b.

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The side which corresponds to QS is VU, and the scale factor is 2.

A scale factor is defined as the ratio between the scale of a given original object and a new object, which is its representation but of a different size (bigger or smaller).

Given that, the figure on the right is a scaled copy of the figure on the left.

We need to find the corresponding side of QS and scale factor,

The figure is 90° counterclockwise rotated,

Therefore,

The corresponding sides are:

PR ~ TW

RQ ~ VT

QS ~ UV
PS ~ WU

∵ the measure of QS = 4 units and the measure of UV = 2 units

∴ scale factor = 4/2 = 2

Hence, the side which corresponds to QS is VU, and the scale factor is 2.

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The question do not contain figure, the similar question is solved.

Answer:

see below

Step-by-step explanation:

Take the number of people surveyed and multiply by 30 %

8 * 30%

Change to decimal form

8 * .3

2.4

About 2.4 will purchase online

The box and whisker plot can be created by :

Minimum value - 6

Maximum Value - 15

Median - 10

Quartiles - Q1 - 7.5, Q2 - 10, Q3 - 13.5

To create a box and whisker plot for the given data set {6,7,7,8,9,10,10,10,10,13,13,14,14,15,15}, we need to first find the minimum value, maximum value, median, and quartiles.

Minimum value: 6

Maximum value: 15

Median: To find the median, we need to first arrange the data set in ascending order:

6,7,7,8,9,10,10,10,10,13,13,14,14,15,15

The median is the middle value in the data set, which is 10.

Quartiles: To find the quartiles, we need to divide the data set into four equal parts.

First quartile (Q1): The first quartile is the median of the lower half of the data set. In our case, the lower half of the data set is:

6,7,7,8,9,10

The median of this set is (7+8)/2 = 7.5.

Second quartile (Q2): The second quartile is the median of the entire data set, which we already found to be 10.

Third quartile (Q3): The third quartile is the median of the upper half of the data set. In our case, the upper half of the data set is:

10,10,10,10,13,13,14,14,15,15

The median of this set is (13+14)/2 = 13.5.

Now, we can use the above information to create the box and whisker plot.

The horizontal line inside the box represents the median (10). The bottom of the box represents the first quartile (7.5), and the top of the box represents the third quartile (13.5). The whiskers extend from the box to the minimum value (6) and maximum value (15).

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Answer:

36 - 18 longest side = 18

Step-by-step explanation: This would mean both sides are 18.

A. The behavior of the solution to Airy's equation on the interval [-10, 10] exhibits oscillatory behavior, resembling a wave-like pattern.

B. Airy's equation, given by y'' + xy = 0, is a second-order differential equation that arises in various fields, including aerodynamics.

To understand the behavior of the solution, we can make use of our knowledge of constant-coefficient equations as a basis for guessing the behavior.

First, let's examine the behavior of the polynomial term xy = 0.

When x is negative, the polynomial is equal to zero, resulting in a horizontal line at y = 0.

As x increases, the polynomial term also increases, creating an upward curve.

Next, let's consider the initial conditions y(0) = 1 and y'(0) = 0.

These conditions indicate that the curve starts at a point (0, 1) and has a horizontal tangent line at that point.

Combining these observations, we can sketch the graph of the solution on the interval [-10, 10].

The graph will exhibit oscillatory behavior with a wave-like pattern.

The curve will pass through the point (0, 1) and have a horizontal tangent line at that point.

As x increases, the curve will oscillate above and below the x-axis, creating a wave-like pattern.

The amplitude of the oscillations may vary depending on the specific values of x.

Overall, the true behavior of the solution to Airy's equation on the interval [-10, 10] resembles an oscillatory wave-like pattern, as determined by the nature of the equation and the given initial conditions.

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Based on the given information, the best choice would be to reduce the aircraft weight by at least 100 pounds. This would allow the aircraft to take off within the available runway distance of 2,100 feet

Based on the given information, the pilot and the two passengers landed on a 2,100 foot east-west gravel strip with an elevation of 1,800 feet. After computing the density altitude, it is determined that the takeoff distance over a 50 foot obstacle is 1,980 feet. The airplane is 75 pounds under gross weight. In this case, the best choice would be to reduce the aircraft weight by at least 100 pounds.

Here's why:

Since the takeoff distance over a 50-foot obstacle is 1,980 feet, this distance is greater than the available runway of 2,100 feet. This means that the aircraft will not be able to take off from the runway. Therefore, the pilot needs to take necessary steps to ensure that the aircraft can take off safely.

One option is to reduce the aircraft's weight, which would decrease the required takeoff distance. Since the aircraft is only 75 pounds under gross weight, the pilot would need to reduce the weight by at least 100 pounds to ensure a safe takeoff. This would allow the aircraft to take off within the available runway distance of 2,100 feet.

Therefore, reducing the weight by 100 pounds would be the best choice.

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The estimated monthly average daily radiation on a horizontal surface in June in Amman is approximately 7.35 kWh/m(^2)/day.

To estimate the monthly average daily radiation on a horizontal surface H in June in Amman, we can use the following equation:

\([H = S \times H_s \times \frac{\sin(\phi)\sin(\delta)+\cos(\phi)\cos(\delta)\cos(H_a)}{\pi}]\)

where:

S is the solar constant, which is approximately equal to 1367 W/m(^2);

\(H(_s)\) is the average number of sunshine hours per day in Amman in June, which is given as 10 hours;

(\(\phi\)) is the latitude of the location, which for Amman is approximately 31.9 degrees North;

(\(\delta\)) is the solar declination angle, which is a function of the day of the year and can be calculated using various methods such as the one given in the answer to Q1;

\(H(_a)\) is the hour angle, which is the difference between the local solar time and solar noon, and can also be calculated using various methods such as the one given in the answer to Q1.

Substituting the given values, we get:

\([H = 1367 \times 10 \times \frac{\sin(31.9)\sin(\delta)+\cos(31.9)\cos(\delta)\cos(H_a)}{\pi}]\)

Since we are only interested in the monthly average daily radiation, we can assume an average value for the solar declination angle and the hour angle over the month of June. For simplicity, we can assume that the solar declination angle (\(\delta\)) is constant at the value it has on June 21, which is approximately 23.5 degrees North. We can also assume that the hour angle \(H(_a)\) varies linearly from -15 degrees at sunrise to +15 degrees at sunset, with an average value of 0 degrees over the day.

Substituting these values, we get:

\([H = 1367 \times 10 \times \frac{\sin(31.9)\sin(23.5)+\cos(31.9)\cos(23.5)\cos(0)}{\pi}]\)

Simplifying the equation, we get:

\([H \approx 7.35 \text{ kWh/m}^2\text{/day}]\)

Therefore, the estimated monthly average daily radiation on a horizontal surface in June in Amman is approximately 7.35 kWh/m(^2)/day.

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To solve for a variable means to ISOLATE the variable on one side of the equation. To do so, divide both sides by the coefficient of y.

Look:

2y/2 = (-x+7)/2

Answer: y = (-x + 7)/2

The answer can also be written as

y = -(x/2) + (7/2)

Both answers mean the same thing.

The difference in the rate of change between Function A and function B is -2.

The difference in the rate of change between function A and function B, we first need to identify the rate of change for each function. The rate of change, also known as the slope, represents how much the dependent variable (y) changes for every unit increase in the independent variable (x).

Let's assume function A is represented by the equation y = 2x + 3, and function B is represented by the equation y = 4x - 1.

For function A: y = 2x + 3, the coefficient of x is 2, indicating that for every unit increase in x, y increases by 2. Therefore, the rate of change for function A is 2.

For function B: y = 4x - 1, the coefficient of x is 4, indicating that for every unit increase in x, y increases by 4. Therefore, the rate of change for function B is 4.

Now, to find the difference in the rate of change between function A and function B, we subtract the rate of change of function B from the rate of change of function A:

Difference in rate of change = Rate of change of function A - Rate of change of function B

                          = 2 - 4

                          = -2

The difference in the rate of change between function A and function B is -2. This means that for every unit increase in x, function B increases at a rate that is 2 units greater than function A. It indicates that function B has a steeper slope and a faster rate of change compared to function A.

In summary, the difference in the rate of change between function A and function B is -2.

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Answer:

a. The interval: 26,978 miles and 32,022 miles

b. The interval: 26,000 miles and 32,000 miles

Step-by-step explanation:

a. It can be guaranteed that 75% of the lifetimes of tires of this brand will be in what interval?

0.674

We solve question a, using z score formula.

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 29,000 miles

σ is the population standard deviation = 3,000 miles

We are asked to find the interval = x

z = z score of 75th and 25th percentile = ±0.674

Hence:

For z = -0.674

-0.674 = x - 29,000/3,000

Cross Multiply

-0.674 × 3,000 = x - 29,000

-2022 = x - 29,000

x = - 2022 + 29,000

x = 26,978 miles

For z = 0.674

0.674 = x - 29,000/3,000

Cross Multiply

0.674 × 3,000 = x - 29,000

2022 = x - 29,000

x = 2022 + 29,000

x = 31,022 miles

The interval: 26,978 miles and 32,022 miles

b. Using the empirical rule, it can be estimated that approximately 68% of the lifetimes of tires of this brand will be in what interval?

68% of data falls within 1 standard deviations from the mean - between μ – σ and μ + σ .

Mean (μ) = 29,000 miles

Standard deviation (σ) = 3,000 miles.

Hence the interval is calculated as:

μ – σ

= 29,000 - 3,000

= 26,000 miles

μ + σ

= 29,000 + 3,000

= 32,000 miles

The interval: 26,000 miles and 32,000 miles

Answer:

34

Step-by-step explanation:

2x + 15 + 3x - 5 = 180

2x + 3x = 5x

15 - 5 = 10

5x + 10 = 180

-10 + 180 = 170

5x = 170

\(\frac{170}{5} = 34\)

x = 34

Answer:

150 miles

Step-by-step explanation:

8/2 = 4

4x37.5 = 150

By permutation, in 95040  ways we can choose a starting lineup consisting of a center, a power forward, a shooting forward, a point guard, and a shooting guard

A permutation is a set up of things in a certain sequence. Here, the members of sets or their constituent parts are sorted in a linear or sequential manner.

Take the number of possibilities for each event and multiply it by itself X times, where X is the total number of events in the sequence, to find the number of permutations. For instance, four-character PINs have a total of 10 possible combinations because each digit can vary from 0 to 9.

\(12^P_{5} = \frac{12!}{(12-5)!} =\frac{12!}{5!} = 12 X 11 X 10 X 9 X 8 = 95040\)

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Answer:

Step-by-step explanation:

You want two methods of choosing points on the line with slope 1/2 through A(-1, 2).

Writing the equation in standard form, we can find the x- and y-intercepts. To get there, we can start from point-slope form:

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

  y -2 = 1/2(x -(-1)) . . . . . using given slope and point

  2y -4 = x +1 . . . . . . . . . . multiply by 2

  x -2y =  -5 . . . . . . . . . . . . add -1 -2y

Setting x=0 tells us the y-intercept is ...

  0 -2y = -5

  y = -5/-2 = 5/2

So, the y-intercept is (0, 5/2).

Setting y=0 tells us the x-intercept is ...

  x -2(0) = -5

  x = -5

So, the x-intercept is (-5, 0).

It will be convenient to choose an arbitrary y-value to find another point on the line. We can pick y = 6, for example, Then the corresponding x-value is ...

  x -2y = -5

  x = -5 +2y = -5 +2(6) = 7

Another point on the line is (7, 6).

__

Additional comment

If we were to choose an arbitrary value for x, we would want it to be odd, so the corresponding y-value would be an integer. We chose to pick an arbitrary value of y so we didn't have to worry about how to make the x-value an integer.

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The probability that a daily average over a given month is greater than x is 2.5% , the value of x is 232.08

Given:

Mean of number of diners is 138

Standard deviation of diners is 48

(Mean and standard deviation does not follow a normal distribution necessarily.)

Let z be the standardized variable that is z= (X- μ)/ σ

where, mean = μ and standard deviation =σ

Such as Z follows N(μ,σ) = N(0,1)

We know that in continuous distribution, probability of a single point is 0, so we can write

P( Z<=z)= P(Z<z)

For the given case, let the random variable X tracks the number of dinners at given restaurant. Assuming normal distribution being pertained by X, we get:

X follows N(138,48)

The given data shows that:

2.5% of all daily averages records lie bigger than value X = x

or

P(X > x) = 2.5%  0.025

Converting it to standard normal distribution(so that we can use z tables and p values to get the unknown x), we get:

z= (x-138)/48

The given probability statement is expressed as:

P(Z>z)=0.025

P( Z<=z)=0.975

We get z = 1.96.

Thus

z=1.96= (x- 138)/48

=> x=232.08

Thus, the value of x is 232.08 approximately.

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Answer:

83.3%

Step-by-step explanation:

Answer:

 3xyz

 ————

  4  

Answer:

it would be 5

Step-by-step explanation:

V=80 is the volume of a square-base pyramid with a base side length of 4 cm and a height of 15 cm.

When a structure's outer surfaces are triangular and converge to a single step at the summit, the structure is said to essentially resemble a geometric pyramid. Any polygonal shape, including triangles and quadrilaterals, can serve as the base of a pyramid. Hence, there are at least three outside triangle surfaces on a pyramid. Pyramids at Giza. Countrywide Geographic. Three of Giza's famed pyramids, along with their elaborate burial complexes, were hastily built between approximately 2550 and 2490 B.C. The pyramids were built by the Pharaohs Khufu (tallest), Khafre (background), and Menkaure (front).

Let's calculate the volume of a pyramid with a base that is b*b square and a height of h.

The square cross-sectional area A(y) of the pyramid can be written as if y is the vertical distance from the top.

\(A(y) = (\frac{b*y}{h}^{2})= \frac{b^{2}}{h^{2}}y^{2}\)

The integral can therefore be used to find the volume V.

V= \(\int\limits^0_h {A(y)dy} \,=\frac{b^{2} }{h^{2}}\int\limits^0_h {ydy} =\frac{b^{2} }{h^{2}}[y^{3}/3]=\frac{1}{3}b^{2}h\)

V= \(\frac{1}{3}*4^{2}*15\)

V\(=80\)

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Answer:

See explanation

Step-by-step explanation:

The graph of y = |x| is a graph of the absolute value function, which is a piecewise defined function. The graph of this function is a V-shaped curve, with the vertex of the V at the origin (0,0). The graph of y = |x + 1| + 4 can be obtained by shifting the graph of y = |x| to the right by 1 unit, and then shifting it up by 4 units.

The resulting graph of y = |x + 1| + 4 will be a V-shaped curve with the vertex at the point (1,4). The curve will be shifted to the right and up compared to the graph of y = |x|, and it will have the same general shape as the original graph.

By adding all the money she spend we get $0.69

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

We are given that Dee spends $0.25, $0.30, $0.10 and $0.04.

We need to find the money she spend in all.

Therefore, we have to add all the expenditure

0.25 + 0.30 + 0.10 + 0.04 = 0.69

The total money she spend could be 0.69.

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Given:

Where, g = 4

To simplify the expression, substitute g for 4 and evaluate.

We have:

ANSWER:

37