Which of these reactions successfully models a nuclear fission reaction?

Answer:

It produces two identical daughter cells

Explanation:

1 haploid splits into 2 genetically identical haploid cells which are called daughter cells

same thing with diploid cells

As pressure rises, more gas molecules dissolve. At two atmospheres, nitrogen gas is twice as soluble as it is at one atmosphere. A gas becomes less soluble as pressure is reduced.

At 4.25 atm compared to 1.00 atm, the concentration of gas particles in the solution is greater.

Pressure and solubility relationship

Since a gas becomes more soluble as pressure rises, there is a direct correlation between solubility and pressure. The solubility of a gas increases with increasing pressure because of an increase in molecular collision, and reduces with decreasing pressure due to an increase in molecular collision.

Visit to learn more about solubility :

brainly.com/question/23946616

#SPJ4

Answer:

The answer would probably be C. The clock can be seen and heard.

Answer:

+1

Explanation:

Sodium has one electron in its outermost shell. Sodium can not be able to accept seven electrons because the energy required for that process is very high. Sodium would rather loose its only valence electron to form a univalent positive ion Na^+.

This is an easier process. When sodium looses one electron, it now has a charge of +1.

The velocity of the car is 20 m/s. So, the correct option is  C. 20 m/s north.

To determine the velocity of the car, we need to calculate the displacement and divide it by the time taken.

The car initially moves 50 m south of the library and then ends up 250 m north of the library, resulting in a displacement of 250 m - (-50 m) = 300 m. The time taken is given as 15 seconds.

Therefore, the velocity can be calculated as displacement divided by time: 300 m / 15 s = 20 m/s.

Since the displacement is positive (from south to north), the velocity is also positive, indicating the car is moving north. Therefore, the correct answer is option C: 20 m/s north.

For more such questions on velocity

https://brainly.com/question/1856219

#SPJ11

Answer:

a. 5 8/100 is equivalent to $ 5.08.

Explanation:

i hope this helps :)

The pulse duration of periodic pulse train with a duty cycle of 15% and a period of 115 nanoseconds is 17.25 nanoseconds.

Duty cycle  = 15% or 0.15

Time period = 115 nanoseconds

The ratio of the amount of time the signal spends in the "on" state to its overall duration is known as the duty cycle. The signal is on for 15% of the entire period when the duty cycle is given as 15% in this instance. Duty cycles are a term used to represent the percentage of time that an electrical signal is active in a device, such as the power switch in a switching power supply, or when an organism, like a neuron, fires an action potential.

Calculating the duty cycle and the period of the pulse train -

Pulse duration = Duty cycle x Period

= 0.15 x 115

= 17.25

Read more about pulse train on:

https://brainly.com/question/30548054

#SPJ4

The radius of the Mg atom increases because the Mg²⁺ has gained 2 extra electrons and a new shell has also been added.

General, magnesium atom, Mg has 3 electron shells while magnesium ion, Mg²⁺ has 2 electron shells.

Since Mg is a metal, its atom is bigger that its ion, Mg²⁺.

Thus, to move from Mg²⁺ to Mg, the ion will need 2 extra electrons as shown below:

Mg²⁺ + 2e —> Mg

Since the Mg atom is bigger, it also means that the radius of the Mg is bigger than the radius of the Mg²⁺.

See attached photo for further details

Learn more about atoms and ions:

https://brainly.com/question/491497

1.42 × \(10^{-1}\) mol would take 14.79 min to effuse.

How long would it take to effuse?

Mathematically,

Rate of effusion =  \(\sqrt{1/M}\) ; M= Molar mass

For comparative study between two subjects, we can write:

\(r_{2} / r_{1}\)= \(\sqrt{m1/m2}\)

In this case, Ne be gas 1 and Xe be gas 2,

∴ r(Xe) = r(Ne)\(\sqrt{20.1797/131.293}\)

r(Xe) = 9.60×10\(^{-3}\)mol/min

Thus, for Xe  9.60×10\(^{-3}\) mol effuses in 1 minute,

1.42 × \(10^{-1}\) would effuse in 1.42 × \(10^{-1}\) /9.60×10\(^{-3}\) = 14.79 min

Thus, 1.42 × \(10^{-1}\)  mol would take 14.79 min to effuse.

To know more about effusion, check out:

https://brainly.com/question/2097955

#SPJ4

a-  With ions shown as spheres and solvent molecules omitted for clarity, AgCLof the following best represents the resulting mixture.b- If each sphere represents 5.5*10^-3 mol of ions,  the total concentration of dissolved (separated) ions 0.11 M (molar) and total mass of solid is 32,.61.

a) The resulting mixture of AgCl, CuCl2, and MgCl2 would be a homogeneous solution. All three of these compounds are ionic compounds and when dissolved in water, they will dissociate into their respective cations (Ag+, Cu2+, and Mg2+) and anions (Cl-). These ions will be surrounded by solvent molecules (water) and will be evenly distributed throughout the solution, resulting in a homogeneous mixture.

b) The total concentration of dissolved ions in the solution can be calculated by using the formula:concentration (mol/L) = moles of solute / liters of solvent. If each sphere represents 5.5*10^-3 mol of ions, and the final volume of the solution is 50.0 mL, we can convert the volume to liters and calculate the concentration of ions as follows: 50.0 mL = 0.05 L. Concentration = (5.5*10^-3 mol) / 0.05 L = 0.11 M (molar)

c) To find the total mass of the solid, we need to know the molar mass of each component. AgCl: Ag = 107.87g/mol, Cl = 35.45g/mol, AgCl = 143.32g/mol

CuCl2: Cu = 63.55g/mol, Cl = 35.45g/mol, CuCl2 = 99.00g/mol

MgCl2: Mg = 24.30g/mol, Cl = 35.45g/mol, MgCl2 = 59.75g/mol. Let's assume we have 0.1 mol of AgCl, 0.1 mol of CuCl2 and 0.1 mol of MgCl2, the total mass of the solid would be:

143.32g/mol * 0.1mol + 99.00g/mol * 0.1mol + 59.75g/mol * 0.1mol = 16.73 + 9.90 + 5.98 = 32.61g

Learn more about homogeneous solution here:

https://brainly.com/question/3293242

#SPJ4

Game Proposal: Element Explorers

Name of Game: Element Explorers

Maximum Number of Players: 4-6 players

How to Play: Each player selects a game piece that represents one of the eight elements from the periodic table in the game. Players move around the board, answering questions related to the properties of elements and their reactions. The questions can be multiple-choice, true/false or short-answer format. Players earn points for correct answers and can use them to buy property or "compounds" on the board. The goal of the game is to collect as many compounds as possible and have the most points at the end. The winner is the player with the most points.

Element Properties: Each element in the game will be associated with its chemical symbol, family, atomic number, atomic mass, and properties such as melting point, boiling point, density, and reactivity. The families of elements represented in the game will include alkali metals, alkaline earth metals, halogens, and noble gases.

Patterns in the Periodic Table: Understanding the patterns in the periodic table is key to being successful in Element Explorers. For example, the number of valence electrons in an atom can be predicted based on the family it belongs to, which affects how it will react with other elements. The electronegativity of an element can also be predicted based on its location on the periodic table, which indicates how easily it can attract electrons and form bonds.

Subatomic Particles: Let's take one of the elements from the game, hydrogen (H), as an example. Hydrogen has one proton and one electron in its neutral state, and its atomic mass is approximately 1.0079 atomic mass units (amu). A simple drawing of a hydrogen atom would include a nucleus containing one proton and possibly one or two neutrons, with one electron in the outer shell.

Patterns in Protons and Valence Electrons: Across a period in the periodic table, the number of protons in the nucleus increases, which affects the size of the atom and its reactivity. Within a family, the number of valence electrons is the same, which affects the element's reactivity and the types of compounds it can form.

Ionic and Covalent Compounds: Valence electrons are crucial in determining whether an ionic or covalent bond will form between two elements. In an ionic bond, one element donates electrons to another element that accepts them, forming a positively charged cation and negatively charged anion. In a covalent bond, two atoms share electrons, forming a molecule. The difference in electronegativity between two elements can be used to predict whether they will form an ionic or covalent bond.

Calculating Electronegativity Difference: Let's take an example of two elements from the game, sodium (Na) and chlorine (Cl), which form an ionic compound (NaCl). Sodium has an electronegativity of 0.93, while chlorine has an electronegativity of 3.16. The difference in electronegativity is 2.23 (3.16-0.93), indicating a highly polar bond between the two elements.

If you can, give me brainliest please!

Answer:

All countries need to move their economies away from fossil fuels as soon as possible. Invest in renewable energy. Changing our main energy sources to clean and renewable energy is the best way to stop using fossil fuels. These include technologies like solar, wind, wave, tidal and geothermal power

Answer:

The substances which neutralize the acids of the stomach are called antacids. Acidity in the stomach causes the sensation of heartburn, antacids are taken to relieve this sensation. They are taken orally to suppress the effects of acidity.

In the endpoint when the indicator changes color it gives the information that the acid is neutralized by the base.

Titration is also known as titrimetry is a technique where a solution of known concentration is used to calculate the concentration of the unknown solution. Titration is a laboratory technique.

The point at which the indicator changes the color is known as Endpoint.

Thus from the above conclusion we can say that In the endpoint when the indicator changes color it gives the information that the acid is neutralized by the base.

Learn more about the Titration here: https://brainly.com/question/186765

#SPJ1

According to the research, a vapor is a substance that is in the gas phase at a temperature at which it would normally be a solid or liquid.

It is the state in which a gas is found when it is at a level below its critical point.

A vapor is the result of heating an element that, at room temperature, is usually a solid or liquid.

Therefore, we can conclude that according to the research, a vapor is a substance that is in the gas phase at a temperature at which it would normally be a solid or liquid.

Learn more about a vapor here: https://brainly.com/question/1697813

#SPJ1

Answer:

B.) +6

Explanation:

To find the oxidation number of sulfur, we can assume the oxidation numbers of the other elements.

What I mean is, oxygen (O) always has an oxidation number of (-2). That being said, if there are 4 oxygen atoms, oxygen is contributing -8 overall. We also know that hydrogen generally has an oxidation number of (+1). Like before, if there are 2 hydrogens, it must be contributing +2.

If the overall molecule is neutral, we have to get these charges to balance out.

In essence, -8 + 2 + ? = 0?

If you combine the charges from oxygen and hydrogen, you are left with -6. Therefore, to make the molecule neutral, sulfur must have an oxidation number of +6.

Answer:

It  usually would depend on the strata, which are layers of rock, to know fossil age by looking at them, if a fossil was more on the top of the strata than another one, it’s the later one

Explanation:

Hope this helps!

Mark brainliest please but only if you would like to.

An example of a glycerophospholipid that is involved in cell signaling is phosphatidylinositol.

Glycerophospholipids are one of the major classes of lipids found in cell membranes. They consist of a glycerol backbone, two fatty acid chains, and a polar head group. Phosphatidylinositol is a glycerophospholipid that is particularly important in cell signaling. It is a precursor for a number of signaling molecules such as inositol triphosphate (IP3) and diacylglycerol (DAG) that regulate important cellular processes such as calcium signaling and protein kinase C activation. Phosphatidylinositol is also involved in the regulation of cell growth, differentiation, and apoptosis. Overall, glycerophospholipids are essential components of cell membranes and play critical roles in maintaining cell structure and function, as well as in signaling processes that help to coordinate cell behavior.

To know more about glycerophospholipid visit:

brainly.com/question/14090272

#SPJ11

The concentration of NH3 in the flask is 0.100 M. When titrating NH3 with HCl and using 25.00 mL of NH3 in the flask, it takes 25.00 mL of 0.100 M HCl to reach the equivalence point. This indicates that the concentration of NH3 in the flask is 0.100 M.

When titrating NH3 (ammonia) with HCl (hydrochloric acid), the reaction that occurs is: NH3 + HCl -> NH4Cl
In this reaction, NH3 acts as the base, while HCl acts as the acid. The equivalence point is the point at which the stoichiometric amounts of NH3 and HCl have reacted, resulting in the formation of NH4Cl.
In this specific case, it takes 25.00 mL of 0.100 M HCl to reach the equivalence point with 25.00 mL of NH3 in the flask. This means that the moles of HCl used in the titration are equal to the moles of NH3 present in the flask.

To determine the concentration of NH3 in the flask, we can use the formula:
Moles = Volume (in liters) x Concentration
Since we have 25.00 mL of NH3 in the flask, we need to convert it to liters by dividing by 1000:

25.00 mL / 1000 = 0.025 L
Now, let's substitute the values into the formula: Moles of NH3 = 0.025 L x Concentration of NH3
Since the moles of HCl used in the titration are equal to the moles of NH3, we can write:
Moles of HCl = 0.025 L x 0.100 M
Now, equating the two expressions for moles:
0.025 L x Concentration of NH3 = 0.025 L x 0.100 M
Concentration of NH3 = 0.100 M

To know more about equivalence point visit:
brainly.com/question/32126581

#SPJ11

The heat need to be added to the material to heat 93.3 grams of the material from 23.1°C to 61.8°C is approximately 14,803 Joules

To calculate the heat needed to heat 93.3 grams of the hypothetical material from 23.1°C to 61.8°C, we will use the specific heat formula:

q = mcΔT

Where q represents the heat added, m is the mass of the material, c is the specific heat, and ΔT is the change in temperature.

In this case, we have:
m = 93.3 g (mass of the material)
ΔT = 61.8°C - 23.1°C = 38.7°C (temperature change)

For the specific heat (c), we need to consider whether the material is in its liquid (l) or solid (s) state during this temperature range. Since the melting point is -16.0°C and the boiling point is 126.0°C, the material is in its liquid state between 23.1°C and 61.8°C. Therefore, we use the specific heat for the liquid state, which is 4.1 J/g°C.

Now we can plug these values into the specific heat formula:

q = (93.3 g) × (4.1 J/g°C) × (38.7°C)
q ≈ 14803 J

Approximately 14,803 Joules of heat need to be added to the material to heat 93.3 grams of the material from 23.1°C to 61.8°C.

Know more about melting point    here:

https://brainly.com/question/30148142

#SPJ11

Answer:

Substances 1 and 2

Explanation:

an element only has 1 kind of atoms :3

The original mass of Rn-222 was 0.2 grams.

The quantity of substance in an item or system is measured by its mass, which is a fundamental physical attribute of matter. It is a measurement of an object's resistance to changes in motion and is often expressed in kilogram (kg) or gram (g) units. It's common to conflate weight—the force of gravity acting on an object—with mass. However, weight varies according to the strength of the gravitational field, whereas mass is constant no matter what gravitational field it is in.

The decay of Rn-222 can be modeled using the following equation:

N(t) = N₀ ×  \(\frac{1}{2} ^\frac{t}{T}\)

where N(t) is the amount of Rn-222 remaining at time t, N₀ is the initial amount of Rn-222, T is the half-life of Rn-222, and  \(\frac{1}{2} ^\frac{t}{T}\) is the fraction of  Rn-222 remaining after time t.

We are given that the half-life of Rn-222 is 3.823 days and that 0.05 grams remain after 7.646 days. Using the equation above, we can set up the following equation:

0.05 grams = N₀ × \(\frac{1}{2} ^ \frac{7.646}{3.823}\)

Solving for N₀, we get:

N₀ = 0.05 grams /  \(\frac{1}{2} ^ \frac{7.646}{3.823}\)

N₀ = 0.05 grams / 0.5²

N₀ = 0.05 grams / 0.25

N₀ = 0.2 grams

Therefore, the original mass of Rn-222 was 0.2 grams.

To learn more about mass, refer to:

https://brainly.com/question/86444

#SPJ4

The concentration of volatile suspended solids (Xv) in the lagoon to assess the effluent quality. However, the specific aerator capacity needed cannot be determined without additional information or equations.

To determine if the industry will likely meet the desired effluent quality, we can calculate the BODL concentration in the aerated lagoon and the concentration of volatile suspended solids (Xv) in the lagoon.

BODL concentration in the aerated lagoon:

The BODL concentration in the lagoon can be calculated using the equation:

BODL_lagoon = BODL_influent - q * Xv * θ

where BODL_influent is the initial BODL concentration (2,000 mg/l), q is the specific oxygen utilization rate (27 mgBODL/mgVSSa-d), Xv is the concentration of volatile suspended solids (to be determined), and θ is the hydraulic retention time (1 day).

Concentration of volatile suspended solids (Xv) in the lagoon:

The concentration of volatile suspended solids can be calculated using the equation:

Xv = BODL_influent / (q * θ)

where BODL_influent is the initial BODL concentration (2,000 mg/l), q is the specific oxygen utilization rate (27 mgBODL/mgVSSa-d), and θ is the hydraulic retention time (1 day).

By substituting the given values into the equations, we can calculate the BODL concentration in the lagoon and the concentration of volatile suspended solids.

Regarding the aerator capacity needed, the question asks for the amount of aerator capacity in kW/1,000 m3 of tank volume. To calculate this, we need the field oxygen transfer efficiency (1 kgO2/kWh). However, the equation or method to determine the aerator capacity based on the given information is not provided. Without additional information or equations, it is not possible to calculate the specific aerator capacity needed in this scenario.

In summary, we can calculate the BODL concentration in the aerated lagoon and the concentration of volatile suspended solids (Xv) in the lagoon to assess the effluent quality. However, the specific aerator capacity needed cannot be determined without additional information or equations.

Learn more about volatile from below link

https://brainly.com/question/29394588

#SPJ11

Answer:

Empirical formula: Na3S4O9

Molecular formula: Na6S8O18

Explanation:

1) To find the empirical formula, which is the simplest whole number ratio of each element that makes up this unknown compound, we first divide the portion of each element by it's respective atomic mass.

Na= 23g/mol, S= 32g/mol, O=16g/mol

Na = 20.2/23 = 0.878mol

S = 37.6/32 = 1.175mol

O = 42.2/16 = 2.638mol

Next, we divide each number of moles by the smallest value (0.878mol)

Na = 0.878/0.878 = 1

S = 1.175/0.878 = 1.34

O = 2.638/0.878 = 3.004

Next, we multiply each decimal fraction by 3 to make it whole no:

Na = 3

S= 4.02 ~ 4

O= 9.012 ~ 9

The simplest ratio between Na, S and O is 3:4:9 hence, the empirical formula is Na3S4O9

2) To get the molecular formula, we use the molecular weight of each element in the empirical ratio, and the overall molar mass of the compound i.e.

Molar mass of compound= 682.8g/mol

molecular weight of Na3S9O4 = (3 x 23g/mol) + (4 x 32 g/mol) + (9 x 16 g/mol)

= 69 + 128 + 144

= 341 g/mol

Hence, (Na3S4O9)n = 682.8g/mol

= (341)n = 682.8

n = 682.8/341

n = 2.002

n~ 2

Hence, molecular formula = (Na3S4O9)2

= Na6S8O18

The empirical and molecular formula are Na₃S₄O₉ and Na₆S₈O₁₈

respectively.

The empirical formula can be gotten by dividing each element by it's

respective atomic mass.

Na= 23g/mol, S= 32g/mol, O=16g/mol

Na = 20.2/23 = 0.878mol

S = 37.6/32 = 1.175mol

O = 42.2/16 = 2.638mol

Then divide each number of moles by the smallest value  which in this case is 0.878mol.

Na = 0.878/0.878 = 1

S = 1.175/0.878 = 1.34

O = 2.638/0.878 = 3.004

Next, we multiply each decimal fraction by 3 to make it whole no:

Na = 3

S= 4.02 ~ 4

O= 9.012 ~ 9

The simplest ratio between Na, S and O is 3:4:9 hence, the empirical formula is Na₃S₄O₉

The molecular formula is calculated by multiplying the molecular weight of each element with empirical ratio to get overall molar mass of the compound

Molar mass of compound is given as 682.8g/mol

Molecular weight of Na₃S₉O₄ = (3 x 23g/mol) + (4 x 32 g/mol) + (9 x 16 g/mol)

= 69 + 128 + 144

= 341 g/mol

Hence, (Na3S4O9)n = 682.8g/mol

= (341)n = 682.8

n = 682.8/341

n = 2.002

n~ 2

Hence, molecular formula = (Na₃S₄O₉)²

= Na₆S₈O₁₈

Answer:

there would be chemicals on the food.

Explanation: Hope this helps :)

Whereas physical changes entail a change in a substance's physical attributes without the creation of new substances, chemical changes involve the rearranging of atoms and the creation of new substances.

According to the concept of "The Lost Isle of Change," once a material experiences a chemical shift, it is difficult to restore it to its previous condition, much like an island that vanishes after it has sunk. Nonetheless, substances that are changing physically are frequently simple to reverse, much like an island that may reemerge as the sea recedes. In conclusion, physical changes frequently entail a change in physical attributes, whereas chemical changes involve the synthesis of new substances and are reversible. The irreversibility of chemical changes is symbolised by "The Lost Island of Change."

learn more about physical changes here:

https://brainly.com/question/17931044

#SPJ4

What is the difference between chemical and physical changes, and how do they relate to the concept of "The Lost Isle of change"?

Answer:

D

\( \: \: \: \: \)

Answer:

You didnt give use the choices you have but I can try to help. Climate can change when it snows,rains,when it is sunny,or cloudy.

Explanation:

The rain allows the climate to cool down depending in the weather out. Same with cloudy weather. Snow can also cause temperature to drop down. When it is sunny, the climate in the sun will be warm, until getting in the shade and it gets cold again.

1.232 g of BaO₂ is required to react stoichiometrically with 0.4g of Y(OH)₃ to produce YBa₂Cu₃O₇ and 0.867 g of CuO is required to react stoichiometrically with 0.4g of Y(OH)₃ to produce YBa₂Cu₃O₇.

The equation for the reaction between Y(OH)₃, BaO₂, and CuO to produce YBa₂Cu₃O₇ is:

2BaO₂ + Y(OH)₃ + 3CuO -> YBa₂Cu₃O₇ + 3H₂O

From the stoichiometric ratio of 1:2:3 for Y, Ba, and Cu respectively, we can see that two moles of BaO₂, one mole of Y(OH)₃, and three moles of CuO are required to produce one mole of YBa₂Cu₃O₇.

To determine the amount of BaO₂ and CuO required to react stoichiometrically with 0.4g of Y(OH)₃, we can use the molar masses of the compounds to convert the mass of Y(OH)₃ to moles, and then use the stoichiometric ratio to calculate the amount of BaO₂ and CuO required.

Assuming the molar masses of Y(OH)₃, BaO₂, and CuO are 109.96 g/mol, 169.33 g/mol, and 79.55 g/mol respectively, we can calculate the number of moles of Y(OH)₃ in 0.4g as:

0.4g / 109.96 g/mol = 0.003636 mol Y(OH)₃

Using the stoichiometric ratio of 1:2:3, we can then calculate the number of moles of BaO₂ and CuO required as:

0.003636 mol Y(OH)₃ x (2 mol BaO₂ / 1 mol Y(OH)₃) = 0.007273 mol BaO₂

0.003636 mol Y(OH)₃ x (3 mol CuO / 1 mol Y(OH)₃) = 0.010908 mol CuO

Finally, we can convert the number of moles of BaO₂ and CuO to mass using their respective molar masses:

0.007273 mol BaO₂ x 169.33 g/mol = 1.232 g BaO₂

0.010908 mol CuO x 79.55 g/mol = 0.867 g CuO

Therefore, 1.232 g of BaO₂ and 0.867 g of CuO are required to react stoichiometrically with 0.4g of Y(OH)₃ to produce YBa₂Cu₃O₇.

Learn more about Stoichiometric ratio

brainly.com/question/6907332

#SPJ11