Which of these is a good conductor?
wood
silver
paper
air

Step-by-step explanation:

LxW

Answer:

A=1344cm²

Step-by-step explanation:

Answer: (1) Measure of angle K = x degrees

(12) Measure of angle L = (5x) degrees

(3) Measure of angle k + Measure of angle L + Measure of angle N = 180 degrees

Step-by-step explanation: First of all, what we have is a triangle, and one of the properties of a triangle is all three angles add up to 180 degrees. This simply means that the addition of angles K and L and N would be equal to 180 degrees.

The question states that angle K is represented as x degrees, and angle L is 5 times the measure of angle K. Therefore, if K is x degrees, then L is 5 times x, which becomes 5x degrees. Also, angle N is given as 16 degrees less than 8 times the measure of angle K (x degrees). Eight times the measure of angle K is given as 8x. Sixteen degrees less than 8x would now become, 8x - 16 (degrees). Therefore, the angles have been derived as;

Angle K = x degrees

Angle L = 5x degrees

Angle N = 8x - 16 degrees

Having known that one of the properties of any triangle is all angles adding up to 180 degrees, we can now derive the following equation;

x + 5x + 8x - 16 = 180

14 x - 16 = 180

Add 16 to both sides of the equation

14x = 196

Divide both sides of the equation by 14

x = 14

Therefore, angle K = 14 degrees (x), angle L = 70 degrees (5x) and angle N = 96 degrees (8x - 16)

*14 + 70 + 96 = 180*

Answer:

145

Step-by-step explanation:

Answer: 1259 meters

Step-by-step explanation:

Highest elevation = 1232 meters

Lowest elevation = -27 meters

The difference in elevation between the highest and lowest points will be:

= 1232 - (-27)

= 1232 + 27

= 1259 meters

Note that (-) × (-) = +

Answer:

22

Step-by-step explanation:

Range is the highest value - the lowest value so in this case it's:

27-5 = 22

Answer:

1/25

Step-by-step explanation:

4 over 100 = 1/25

Answer:

-13

Step-by-step explanation:

−2+3(1−4)−2

=−2+(3)(−3)−2

=−2+−9−2

=−11−2

=−13

hope it helped

please mark me as brainliest.

Answer:x is 23

Step-by-step explanation:f(x) = x - 10

13 = x - 10

13 + 10 = x

23 = x

So x  is 23

Answer:

The value of x is 23

Step-by-step explanation:

Given:

\(f(x)=x-10\)

Find:

The value of x

Explanation:

\(f(x)=x-10\\f(x)=13\\\\13=x-10\\x=13+10\\x=23\)

Final Answer

Hence, the value of x is 23

Step-by-step explanation:

6)

\(k = \frac{6}{4} \\ k = \frac{3}{2} \)

7)

\( \frac{ab}{mn} = \frac{bc}{no} = \frac{cd}{op} = \frac{da}{pm} \)

8)

\(y = 8 ( \frac{3}{2} ) \\ y = 12\)

\(z = 6 ( \frac{3}{2} ) \\ z = 9\)

9)

\(5k = 8 \\ k = \frac{8}{5} \\ x( \frac{8}{5}) = 32 \\ x = 20ft\)

The limit of the infinite series \(\sum_{n=1}^{\infty} \frac{5n^5}{4n^{5.5}}\) is zero.

In this series, each term consists of the expression (5n⁵) divided by (\($4n^{5.5}$\)). We can simplify this expression by canceling out common factors:

\(\(\frac{{5n^5}}{{4n^{5.5}}} = \frac{5}{4} \cdot \frac{{n^5}}{{n^{5.5}}} = \frac{5}{4} \cdot \frac{1}{{n^{0.5}}} = \frac{5}{{4n^{0.5}}}\)\)

Now, let's analyze the behavior of the terms as n approaches infinity. As n increases, the denominator \($n^{0.5}$\) grows larger while the numerator remains constant. Consequently, the value of each term approaches zero.

Since the series consists of an infinite sum of terms approaching zero, the sum of the series also approaches zero as the number of terms increases.

Therefore, the limit of the infinite series \(\sum_{n=1}^{\infty} \frac{5n^5}{4n^{5.5}}\) is zero.

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Answer:

C.Tammy’s estimate is right, but the actual product should be 24.78.

Step-by-step explanation:

i took the assessment! thank you for your attention and i hope i helped!!

Answer:

the answer is C which is Tammy’s estimate is right, but the actual product should be 24.78.

Step-by-step explanation:

The possible values of ∠F 131.9°

In ΔFGH, f = 7.5 inches, h = 7 inches and ∠H = 44°

Law of sines is a/sin A = b/sin B = c/sin C where a, b, c are sides of the triangle and A, B, C are angles of the triangle.

Using Law of sines and applying reciprocal we get sin A/a = sin B/b.

where a = f = 7.5 inches, b = h = 7 inches, ∠A=∠F and ∠B = ∠H.

∠H = 44°.

sin F/7.5 = sin44°/7

Therefore,

sin F = (7.5sin44°)/7

≈ 0.74427

F = sin-1(0.74427) ≈ 0.83944 = 48.1°

Quadrant II: 180° - 48.1° = 131.9°

To check for possibility

44° + 48.1° = 92.1°   [This is not possible because 99° is less than 180°]

44° + 131.9° = 175.9°  [This is possible because 175.9° is less than 180°]

Hence, the triangle FGH, the all possible values of ∠F is 131.9⁰.

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The expression to represents the phrase: "6 times a number plus 3." is:

6n + 3

Here, "n" represents an unknown number, and "6" and "3" are constants. The expression means that 6 is being multiplied by "n" to get an intermediate result, and then 3 is being added to that result to get the final answer.

For example, if n = 2, then the expression would evaluate to 6 * 2 + 3 = 12 + 3 = 15. So, the expression "6n + 3" represents the mathematical relationship between the unknown number "n" and the final result.

Therefore, the expression "6 times a number plus 3" can be represented as "6n + 3".

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In one-year, the promised yields have risen to 7%, then the 1-year holding-period return was : (a) 0.61%.

The "Par-value" of the bond (face value) is = $1,000;

Coupon rate = 6% (annual payment coupon)

Yield at purchasing time is = 6%

Yield after 1 year = 7%

Step 1: Calculate the present value of the redeemable value:

We know that PVIF at 7% for 7 years is 0.623,

So, Present value of redeemable value = (Par value) × PVIF = $1,000 × 0.623 = $622.75,

Step 2: Calculate the present value of coupon payments:

Coupon payment = (Coupon rate)×(Par value) = 6% × $1,000 = $60,

We know that PVAF at 7% for 7 years is 5.389,

So, Present value of coupon payments = (Coupon payment) × (PVAF) = $60 × 5.389 = $323.36,

Step 3: Calculate the price of bond after 1 year:

Price of bond = Present value of redeemable value + Present value of coupon payments,

Substituting the values,

We get,

Price of bond = $622.75 + $323.36 = $946.11

Step 4: Calculate the 1-year holding-period return:

Holding return = (Price in next year + Coupon interest - Price in current year) / Price in current year,

Holding return = ($946.11 + $60 - $1,000) / $1,000

Holding return = $6.11 / $1,000

Holding return = 0.00611 = 0.61%.

Therefore, the correct option is (a).

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The given question is incomplete, the complete question is

You buy an 8-year $1,000 par value bond today that has a 6% yield and a 6% annual payment coupon. In 1 year promised yields have risen to 7%. Your 1-year holding-period return was

(a) 0.61%

(b) -5.39%

(c) 1.28%

(d) -3.25%

Answer:

Step-by-step explanation:

area is \(R^{2} \pi =(x+1)^{2}\pi =(x^{2} +2x+1)\pi\)

ANSWER

112

EXPLAINATION

28÷16 = 7

7×16 = answers

Probability helps us to know the chances of an event occurring. The probability that the woman shared the same profession is 0.334.

Probability helps us to know the chances of an event occurring.

\(\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}\)

The probability of both being a waiter is,

P(Both Waiter) = (3/9)×(4/12) = 1/9

The probability of both being chefs,

P(Both Chef) = (2/9)×(4/12) = 2/27

The probability of both being a Dishwashers,

P(Both Dishwasher) = (4/9)×(4/12) = 4/27

Thus, the probability that the woman shared the same profession is,

Probability = P(Both Waiter) + P(Both Chef) + P(Both Dishwasher) = 0.33

Hence, the probability that the woman shared the same profession is 0.334.

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It is TRUE that If you want to calculate the total magnification, take the power of the objective (4X, 10X, 40x) and multiply by the power of the eyepiece, usually 10X.

If you want to get the total magnification of a microscope, you need to multiply the magnification of the objective lens by the magnification of the eyepiece lens. The objective lens typically has a magnification of 4X, 10X, or 40X, and the eyepiece lens usually has a magnification of 10X. So, for example, if you are using a 10X objective lens and a 10X eyepiece lens, the total magnification would be 10 × 10 = 100X.

On the other hand, these numbers may be the total magnification for a lower powered stereomicroscope. 10X and 40X are achievable with 10X eyepieces and 1X or 4X objective lenses. Or it can be a zoom stereomicroscope with zoom set to 1X and 4X and 10X eyepieces. To get a total of 4X, you can use the 0.8X zoom setting (which is common) plus the 5X eyepiece. Or you can use the 0.5x auxiliary lens, 0.8x zoom and 10x eyepieces.

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Complete Question:

True, or False

To get the total magnification take the power of the objective (4X, 10X, 40x) and multiply by the power of the eyepiece, usually 10X.

The unit that is most appropriate for the time at which the number of weeks is 120 is given as follows:

Week.

The general format for an exponential function is given as follows:

\(y = a(b)^{\frac{x}{n}}\)

The parameters for the exponential function are defined as follows:

The number of weeds in my yard doubles every 3 weeks, and the initial number of weeks is of 80, hence the values of the parameters are given as follows:

a = 80, b = 2, n = 3.

As n = 3, we have that the unit of the output variable is of weeks, hence weeks is the appropriate measure in this problem.

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Answer:

C. 72

Step-by-step explanation:

your are given the adjacent length of 2.4 cm and the hypotenuse of 7.8cm

so we know cos = adjacent/ hypotenuse

so to find the angle of cos you use the inverse of cos^-1(2.4/7.8)

after typing into calculator you should get about 72

Answer:

C

Step-by-step explanation:

cos(0)= Adjacent/Hypotenuse

cos(0)= n/p

cos(0)=2.4/7.8

cos(0)=4/13

(0)=cos‐¹(4/13)

(0)=72.07978686

(0)=72°

angle (0)= 72°

0.45 or %45 is left of the circular cake.

Hope this helps; have a great day!

Answer:

Specifically, if we want to think of multiplication as repeated addition, exponentiation as repeated multiplication, and ↑↑ as repeated exponentiation, three groups of five is the way to go. 53 means 5×5×5, not 3×3×3×3×3.

Step-by-step explanation:

Answer:

13.7. with tax it is 14.8

(a) The initial concentration of the solution in the tank is 0.05 kg/L. (b) After 2.5 hours, the amount of salt in the tank remains unchanged at 50 kg. (c) As time approaches infinity, the concentration of salt in the solution remains constant at 0.05 kg/L.

(a) The initial concentration of the solution in the tank can be calculated by dividing the total amount of salt initially present by the total volume of the solution initially.

Total amount of salt initially = 50 kg

Total volume of the solution initially = 1000 L

Concentration of the solution initially = (Total amount of salt initially) / (Total volume of the solution initially)

Concentration of the solution initially = 50 kg / 1000 L = 0.05 kg/L

Therefore, the concentration of the solution in the tank initially is 0.05 kg/L.

(b) Find the amount of salt in the tank after 2.5 hours.

In this case, we need to consider the amount of salt entering and leaving the tank over time.

Amount of salt entering the tank per minute = concentration of the incoming solution × rate of incoming solution

Amount of salt entering the tank per minute = 0.025 kg/L × 10 L/min = 0.25 kg/min

Amount of salt leaving the tank per minute = concentration of the solution in the tank × rate of outgoing solution

Amount of salt leaving the tank per minute = (amount of salt in the tank) / (total volume of the solution in the tank) × 10 L/min

Since the incoming and outgoing rates are equal (10 L/min), the amount of salt in the tank after a certain time remains constant. Let's calculate the amount of salt in the tank after 2.5 hours (150 minutes).

Amount of salt entering the tank in 150 minutes = 0.25 kg/min × 150 min = 37.5 kg

The amount of salt in the tank after 2.5 hours remains the same as the initial amount, as there is no net change in the salt content.

Therefore, the amount of salt in the tank after 2.5 hours is 50 kg.

(c) Find the concentration of salt in the solution in the tank as time approaches infinity.

As time approaches infinity, the concentration of salt in the solution in the tank will be determined by the ratio of the total amount of salt in the tank to the total volume of the solution in the tank.

Total amount of salt in the tank = 50 kg

Total volume of the solution in the tank = 1000 L

Concentration of salt in the solution as time approaches infinity = (Total amount of salt in the tank) / (Total volume of the solution in the tank)

Concentration of salt in the solution as time approaches infinity = 50 kg / 1000 L = 0.05 kg/L

Therefore, as time approaches infinity, the concentration of salt in the solution in the tank will be 0.05 kg/L, the same as the initial concentration.

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Complete question:

A tank contains 50 kg of salt and 1000 L of water. A solution of a concentration 0.025 kg of salt per liter enters a tank at the rate 10 L/min. The solution is mixed and drains from the tank at the same rate. (a) What is the concentration of our solution in the tank initially? (b) Find the amount of salt in the tank after 2.5 hours. (c) Find the concentration of salt in the solution in the tank as time approaches infinity.

a) It is like winning a free entry ticket raffle.

b) The probability that you will win something (either a free raffle entry or a cash prize -  \(\frac{1}{3}\) .

c) The probability that you win nothing at all is - \(\frac{2}{3}\)

a)  One of every five people plays and gets a free entry in a raffle.

  P(Free entry)= \(\frac{1}{5}\)

Two of every fifteen people play and win a small cash prize.

   P( Small prize)= \(\frac{2}{15}\)

  P(Free entry) = \(\frac{1}{5}\)

                        = \(\frac{1 . 3}{5 . 3}\) = \(\frac{3}{15}\)

​                 \(\frac{3}{15}\) > \(\frac{2}{15}\)

​    P(Free entry) > P( Small prize)

b)  P(Win something)   =P(Free entry)  +  P(Small prize)

                                     = \(\frac{1}{5} + \frac{2}{15}\)

                                     = \(\frac{3}{15} + \frac{2}{15}\)      ( use addition)

                                     = \(\frac{3 + 2}{15}\)

                                     = \(\frac{5}{15}\) = \(\frac{1}{3}\)

c) P(Win nothing)  +  P(Win something) = 1

  P(Win nothing) = 1 - P(Win something)

   P(Win nothing)  = 1 - \(\frac{1}{3}\)         (use subtraction)

   P(Win nothing) = \(\frac{3}{3} - \frac{1}{3}\)

   P(Win nothing) = \(\frac{2}{3}\)

So,

a) It is like winning a free entry ticket raffle.

b) The probability that you will win something (either a free raffle entry or a cash prize -  \(\frac{1}{3}\) .

c) The probability that wins nothing at all is - \(\frac{2}{3}\)

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The complete question is :

The city has created a new contest to raise funds for a big Fourth of July fireworks celebration. People buy tickets and scratch off a special section on the ticket to reveal whether they have won a prize. One out of every five people who play gets a free entry in a raffle. Two out of every fifteen people who play win a small cash prize. a. If you buy a scratch-off ticket, is it more likely that you will win a free raffle ticket or a cash prize? Explain your answer. b. What is the probability that you will win something (either a free raffle entry or a cash prize)? c. What is the probability that you will win nothing at all? To justify your thinking, write an expression to find the complement of winning something.

​

​

The electron domain charge cloud geometry of \(BrF_5\) is trigonal bipyramidal.

To determine the electron domain charge cloud geometry of \(BrF_5\), we need to examine the number of electron domains around the central atom (Br).

\(BrF_5\) consists of one central bromine atom (Br) surrounded by five fluorine atoms (F). Each bond and lone pair of electrons represents an electron domain.

In \(BrF_5\), there are five bonding pairs (Br-F) and no lone pairs around the central bromine atom. Therefore, the total number of electron domains is five.

Based on this information, the electron domain charge cloud geometry of \(BrF_5\) is trigonal bipyramidal.

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The counterclockwise circulation around c is 12 and the outward flux through c is zero.

Green's theorem is a useful tool for calculating the circulation and flux of a vector field around a closed curve in two-dimensional space.

In this case,

we have a field f=(7x−4y)i+(9y−4x)j and

a square curve c bounded by x=0, x=4, y=0, y=4.

To find the counterclockwise circulation, we can use the line integral of f along c, which is equal to the double integral of the curl of f over the region enclosed by c.

The curl of f is given by (0,0,3), so the line integral evaluates to 12.

To find the outward flux, we can use the double integral of the divergence of f over the same region, which is equal to zero since the divergence of f is also zero.

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The statement "increasing the threshold does not change the values in the confusion matrix of a model for a given dataset" is incorrect.

Increasing the threshold can indeed lead to changes in the values of the confusion matrix. Increasing the threshold does not necessarily change the values in the confusion matrix of a model for a given dataset. However, it can affect how the predictions are classified and thus impact the composition of the confusion matrix.

The confusion matrix is a table that summarizes the performance of a classification model by showing the counts of true positive, true negative, false positive, and false negative predictions. It is typically based on a fixed threshold for determining the predicted class labels. When the threshold is increased, it may lead to a shift in the classification of instances.

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