Which of these correctly shows the group of atoms and/or ions in order of decreasing
size?
Cu > Cu+ > Cu2+
Cu > Cu+2 > Cu+
Cu+ > Cu > Cu2+
Cu2+ > Cu+ > Cu

The warm and the cool air masses affects the formation of clouds and precipitation.

Warm and cool air masses can affect cloud formation. Clouds are formed when water vapor in the atmosphere rises and cools, condensing into tiny water droplets or ice crystals. The type and amount of clouds that form can be influenced by the temperature and moisture content of the air masses.

In general, the interaction between warm and cool air masses can result in cloud formation and precipitation.

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Determining whether a functional group is acidic or basic depends on its ability to either donate or accept a proton (H+). Here are some general guidelines to help you assess the acidity or basicity of a functional group:

1. Acidity:

  a. Look for functional groups that have an acidic hydrogen directly bonded to an electronegative atom, such as oxygen or a halogen. Examples include carboxylic acids (–COOH) and phenols (–OH on an aromatic ring).

  b. Consider the stability of the resulting conjugate base. If the conjugate base is stabilized through resonance or delocalization of the negative charge, the functional group is more acidic. For example, the carboxylate ion (–COO-) is stabilized through resonance.

2. Basicity:

  a. Look for functional groups that contain lone pairs of electrons, which can readily accept a proton. Common examples include amines (–NH2) and amides (–CONH2).

  b. Consider the availability of lone pairs. The more accessible the lone pairs are, the more basic the functional group. For example, primary amines have more available lone pairs than tertiary amines and are, therefore, more basic.

It's important to note that the acidity or basicity of a functional group can also be influenced by its environment, neighboring groups, and other factors. These guidelines provide a general starting point, but there may be exceptions and variations based on specific compounds and circumstances.

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Taking into account the definition of calorimetry, the correct answer is the third option:  The heat exchanged is 10,450 J.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

The amount of heat (Q) necessary to vary the temperature of a mass (m) of a substance is proportional to the change in its temperature (∆T) and to that mass. So, the equation that allows calculating heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Replacing in the expresion for calorimetry:

Q = 4.18\(\frac{J}{gC}\)× 100 g× 25 C

Solving:

Q= 10,450 J

Finally, the correct answer is the third option:  The heat exchanged is 10,450 J.

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Answer:

Elements

Explanation:

I just did this

To produce one molecule of glucose, 6 molecules of carbon dioxide (\(CO_{2}\)), 18 molecules of adenosine triphosphate (ATP), and 12 molecules of nicotinamide adenine dinucleotide phosphate (NADPH) are required.

Glucose, a six-carbon sugar, is synthesized through the process of photosynthesis in plants. It involves the Calvin cycle, which incorporates carbon dioxide, ATP, and NADPH to produce glucose. For each molecule of glucose formed, 6 molecules of carbon dioxide are required.

The energy needed for glucose synthesis is provided by ATP, which is an energy-rich molecule. In the Calvin cycle, the synthesis of one glucose molecule requires 18 molecules of ATP.

NADPH, a coenzyme involved in energy transfer reactions, is required for the reduction of carbon dioxide during the Calvin cycle. In the process, 12 molecules of NADPH are utilized to produce one molecule of glucose. These components play crucial roles in capturing and storing energy, as well as providing carbon atoms for the formation of glucose, which serves as a vital energy source for organisms.

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The reaction which displays an example of an arrhenius base is

NaOH(s) → Na⁺(aq) + OH⁻(aq).

According to the Arrhenius theory, those substance which gives H⁺ ion to the aqueous solution is acid and which gives OH⁻ ion to the aqueous solution is known as base.

All given chemical reactions will display an arrhenius acid, but only one reaction display as a arrhenius base as they gives OH⁻ ion to the aqueous solution and that reaction will be:
NaOH(s) → Na⁺(aq) + OH⁻(aq)

Hence option (1) is correct.

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Answer:

A: NaOH(s) ---> Na+(aq) + OH–(aq)

Explanation:

Einstein's famous equation say that all matter is option B. concentrated energy that has condensed into the atoms.

When combined with the speed of light, Einstein's famous equation E=mc2 demonstrates mathematically that energy and matter are one and the same. m stands for mass, c for the speed of light, and E stands for energy. This equation states that all matter is simply concentrated energy that has condensed into atoms.

Einstein's famous equation is E=mc², which expresses the relationship between mass (m) and energy (E), and the constant speed of light (c) in a vacuum. This equation shows that mass and energy are interchangeable, and that a small amount of mass can be converted into a large amount of energy, as demonstrated in nuclear reactions.

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Mass of Barium = 720.73 g ; Mass of Phosphorus = 108.37 g ; Mass of Oxygen =  223.91 g

To determine the masses of barium, phosphorus, and oxygen in a sample of barium phosphate (Ba3(PO4)2), you need to calculate the formula weight of the compound and then multiply it by number of moles of  compound in the sample.

First, calculate the formula weight of the compound:

Ba3(PO4)2 formula weight = (3 x 137.327 g/mol) + (2 x (30.97 g/mol + 4 x (16.00 g/mol)) = 601.9 g/mol

n = 1053.8 g / 601.9 g/mol = 1.75 mol

Mass of Barium = 3 x 137.327 g/mol x 1.75 mol = 720.73 g

Mass of Phosphorus = 2 x 30.97 g/mol x 1.75 mol = 108.37 g

Mass of Oxygen = 8 x 16.00 g/mol x 1.75 mol = 223.91 g

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To calculate the molarity of cinoxate in 100 ml of sunscreen B16, we need to know the mass of cinoxate present in 100 ml of B16.

First, we can calculate the mass of B16 by multiplying its density (1.0 g/ml) by its volume (100 ml), which gives us 100 g.
Next, we can calculate the moles of cinoxate by dividing the mass of cinoxate by its molar mass. The molar mass of cinoxate is given as 250 g/mol.

Since we don't have the mass of cinoxate, we cannot provide a long answer to your question. However, if you provide the mass of cinoxate, I would be happy to help you calculate the molarity.

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Answer: To determine which of the given compounds will result in a solution with a pH greater than 7, we need to consider the behavior of the cation and anion in each compound in water.

Compounds that are made up of the conjugate base of a weak acid and a strong base, or a strong acid and the conjugate base of a weak base, will result in a basic solution. The conjugate base of a weak acid will hydrolyze in water, producing hydroxide ions (OH-) and resulting in an increase in pH. The conjugate base of a strong acid or a strong base will not hydrolyze, so it will not affect the pH of the solution.

With this in mind, we can identify the following compounds that will result in a solution with a pH greater than 7:

Therefore, the compounds that will result in a solution with a pH greater than 7 are MgF2, Na2CO3, and KC2H302.

The name of the reaction in which two cations in different compounds exchange anions is called a double displacement reaction or a metathesis reaction.

In this type of reaction, two ionic compounds are mixed, and the positively charged ions (cations) swap partners with each other, resulting in two new compounds. The exchange of ions occurs because one of the products is insoluble in water, which drives the reaction forward.

The reaction can also occur in the presence of acids or bases, where the H+ or OH- ions replace one of the ions in the compounds. Double displacement reactions are commonly used in the synthesis of various compounds and are essential to many industrial and biological processes.

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Answer:

ΔH = -1332,5 kJ/mol

Explanation:

The general equation of the enthalpy of reaction is:

AB + CD → AC + BD

ΔH =( ΔH(AC) + ΔH(BD) ) - (ΔH(AB) + ΔH(CD) )

To simplify the equations, the states of aggregation can be omitted here.

So the first equation is:

X + 12 O2 → XO     | ΔH = -954,5 kJ/mol

The equation of the enthalpy of reaction is thus:

-954,5 kJ/mol = ΔH(XO) - ( ΔH(X) + 12*ΔH(O2) )

Since the enthalpy of reaction of all pure elements is 0, the equation can be simplified:

-954,5 kJ/mol = ΔH(XO) - ( 0 + 12*0 )

ΔH(XO) = -954,5 kJ/mol

The next equation is:

XCO3 → XO + CO2    | ΔH = +378,1 kJ/mol

The equation of the enthalpy of reaction is thus:

+378,1 kJ/mol = ( ΔH(XO) + ΔH(CO2) ) - ΔH(XCO3)

+378,1 kJ/mol = -954,4 kJ/mol + ΔH(CO2) - ΔH(XCO3)

+1332,5 kJ/mol = ΔH(CO2) - ΔH(XCO3)

X + 12 O2 + CO2 → XCO3

The equation of the enthalpy of reaction is thus:

ΔH = ΔH(XCO3) - ΔH(CO2)

ΔH = -1332,5 kJ/mol

the given statement was false cause when the gas law constant R = 0. 0821 was used the temperature should be in K and the volume should be in liters.

define gas law constant ?

In chemistry and physics, "R" is the symbol for the gas constant, molar gas constant, ideal gas constant, or universal gas constant. In numerous equations, it is a proportionality factor that connects energy and temperature scales.

Chemistry's Gas Constant

The gas constant is also known as the ideal gas constant and the universal gas constant in chemistry.

The Boltzmann constant has a molar equivalent.

The gas constant has a SI value of 8.31446261815324 JK1mol1. The number is usually rounded to 8.314.

the given statement was false cause when the gas law constant R = 0. 0821 was used the temperature should be in K and the volume should be in liters.

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Lithium=li

Iron=Fe

Helium=He

I don't say u must have to mark my ans as brainliest but if u think it has really helped u plz don't forget to thank me....

Answer:

lithium symbol=li helium= he and iron =i

The element X that could be responsible for the blue color in aqueous solutions of compounds is (2) copper.

Copper compounds are known to exhibit various shades of blue in aqueous solutions. This is due to the presence of copper ions (Cu2+) which absorb certain wavelengths of light, particularly in the blue region of the electromagnetic spectrum. The absorption of light by copper ions results in the reflection of blue light, giving the solution its characteristic blue color.

Copper is a transition metal that can form different oxidation states, including Cu2+. When copper ions are present in solution, they can interact with water molecules or other ligands to form complex ions, which contribute to the blue color. Copper compounds such as copper sulfate (CuSO4) and copper nitrate (Cu(NO3)2) are examples of substances that produce blue solutions when dissolved in water.

In contrast, carbon, sodium, and potassium compounds generally do not exhibit a blue color in aqueous solutions. Carbon compounds are typically colorless or exhibit other colors depending on their chemical structure. Sodium and potassium compounds are often colorless or may produce solutions with a slight yellow tint, but they do not typically produce a strong blue color.

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Answer:

what is the question?

Explanation:

if you tell me ill update it if i got the info

Halite, gypsum, and graphite are the three names for the three common non-silica minerals. Plaster uses gypsum, common salt uses halite, and pencil lead once used graphite.

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Answer:

Organelles, prokaryotic, organelles, cytoplasm, prokaryotic, nucleus

Explanation:

Organelles are membrane bound only in eukaryotic ccells.

Prokaryotic cells unlike eukaryotic cells, do not have membrane bound organlles.

Something that is found in both prokaryotic and eukaryotic cells is the cytoplasm, which is fluid that is inside the whole cell.

Unlike eukaryotic cells, prokaryotic cells have loose DNA, which floats around the cell quite literally.

The only way DNA is stored in eukaroyotic cells is in the nucelus, which is only found in eukaryotic cells, not prokaryotic.

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Answer:

HCl is a stronger acid because the bond is weaker

Hf is a stronger acid because the bond is more polar

H2Se is a stronger acid because the bond is weaker.

Explanation:

Weaker and more polar acids make stronger acids.

a. When comparing HF and HCl, HCl is a stronger acid because the bond is stronger.
b. When comparing H2O and HF, HF is a stronger acid because the bond is weaker.
c. When comparing H2Se and H2S, H2Se is a stronger acid because the bond is weaker.

In comparing the acidity of acids, we can consider the strength of the bond between the hydrogen atom and the non-metallic atom in the acid. The weaker the bond, the more easily the hydrogen ion can be donated to a base, making the acid stronger.

a. This is because HCl has a weaker bond between hydrogen and chlorine, and it readily donates hydrogen ions to a base.
b. This is because HF has a stronger bond between hydrogen and fluorine, which makes it harder to donate hydrogen ions to a base.
c. This is because H2Se has a weaker bond between hydrogen and selenium, and it readily donates hydrogen ions to a base.

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The best description for the selectivity/specificity of the transformation shown is regioselective.

Regioselectivity refers to the preference of a reaction to occur at a specific region of a molecule, typically determined by the relative stability of the resulting products. In the given transformation, there are no indications of stereospecificity, which refers to the preservation of stereochemistry during a reaction. However, the transformation is described as regioselective, indicating that it favors a specific region of the molecule for the reaction to occur. The specific details of the transformation are not provided, but based on the options given, the best choice is regioselective, indicating a preference for a particular region of the molecule in the reaction.

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Option A.

The number of molecules of carbon tetrachloride in 6.32 mg of the compound is 2.47 x 10¹⁹ molecules.

The molecular mass of Carbon tetrachloride is calculated as follows;

Molecular formula = CCl₄

CCl₄ = (12) + (35.5 x 4)

CCl₄ = 154 g/mol

The number of moles of carbon tetrachloride in 6.32 mg is calculated as follows;

n = reacting mass / molar mass

n = (6.32 x 10⁻³) / (154)

n = 4.1 x 10⁻⁵ moles

1 mole of CCl₄ = 6.02 x 10²³ molecules

4.1 x 10⁻⁵ moles of CCl₄ = ?

= 2.47 x 10¹⁹ molecules

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Answer:

\(x = 6.634\times 10^{23}\,atoms\)

Explanation:

The quantity of atoms within the mass of copper is determined by multiplying the quantity of moles by the Avogadro's Number:

\(x = \left(\frac{70\,g}{63.546\,\frac{g}{mol}} \right)\cdot \left(6.022\times 10^{23}\,\frac{atoms}{mol} \right)\)

\(x = 6.634\times 10^{23}\,atoms\)

Answer:

6.64x10^23 atoms.

Explanation:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This implies that 1 mole of Cu also contains 6.02x10^23 atoms.

1 mole of Cu = 63.5g

If 63.5g of Cu contains 6.02x10^23 atoms,

Then 70g of Cu will contain = (70x6.02x10^23) /63.5 = 6.64x10^23 atoms.

Therefore, there are 6.64x10^23 atoms in 70g oh Cu

The molarity of a solution with 952 grams of ammonium carbonate dissolved to make 1750 ml of solution is: 0.54 mol/L.

The molarity of a solution can be calculated by dividing the amount of solute (in this case ammonium carbonate) by the volume of the solution. In this case, 952 grams of ammonium carbonate are dissolved in 1750 mL of solution. Therefore, the molarity of the solution can be calculated as follows:

Molarity = (952 g ammonium carbonate) / (1750 mL solution) = 0.54 mol/L

To calculate the molarity, first, we need to calculate the moles of ammonium carbonate. We can do this using the molar mass of ammonium carbonate, which is 53.49 g/mol. We divide the mass of ammonium carbonate by its molar mass to get the number of moles:

(952 g ammonium carbonate) / (53.49 g/mol) = 17.77 mol

Then, we divide this number by the volume of the solution (in liters):

(17.77 mol) / (1750 mL/1000 mL/L) = 0.54 mol/L

Therefore, the molarity of the solution is 0.54 mol/L.

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Answer:

1.48 x 10^47 mol of Na

Explanation:

8.90 x 10^24 atoms of Na (1 mol of Na/6.022 x 10^23 atoms of Na)=

1.48 x 10^47 mol of Na

The superscript 3 in 4pº tell that there are 3 electrons in this orbital

In an atom there are levels of energy in the shell and sub shell

This energy level is expressed in the form of electron configurations.  

There are 4 sub-shells in the shell of an atom, namely s, p, d, and f. The maximum number of electrons for each sub-shell is  

• s: 2 electrons  

• p: 6 electrons  

• d: 10 electrons and  

• f: 14 electrons  

Charging electrons in the sub-shell uses the following sequence:  

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  

Arsenic is an element with the symbol As, which has an atomic number of 33 and a mass number of 75

Electron configuration of As : [Ar] 3d¹⁰4s²4p³

Each superscript shows the number of electrons that occupy each orbital

For the p orbital there are a maximum of 6 electrons, while the 4p³ orbital shows that there are 3 electrons in this orbital

A) The reaction of ΔGο at 648 K is apprοximately -73.6 kJ.

B) The spοntaneity οf the reactiοn changes at absοlute zerο (0 K).

C) The value οf ln(K) fοr the reactiοn at 589 K is apprοximately -0.0442.

D) ΔGο fοr the reactiοn at 357 K is apprοximately 106.5 kJ.

A chemical prοcess in which substances act mutually οn each οther and are changed intο different substances, οr οne substance changes intο οther substances.

Part A:

Tο calculate ΔGο at 648 K, we can use the equatiοn:

ΔGο = ΔHο - T * ΔSο

Given:

ΔHο = -141 kJ

ΔSο = -104 J/mοl K

T = 648 K

Cοnverting ΔSο tο kJ/mοl K:

ΔSο = -104 J/mοl K * (1 kJ/1000 J) = -0.104 kJ/mοl K

Substituting the values intο the equatiοn:

ΔGο = -141 kJ - 648 K * (-0.104 kJ/mοl K)

ΔGο = -141 kJ + 67.392 kJ

ΔGο = -73.608 kJ

Therefοre, ΔGο at 648 K is apprοximately -73.6 kJ.

Part B:

Tο determine the temperature at which the spοntaneity οf the reactiοn changes, we can use the equatiοn:

ΔGο = -RT * ln(K)

Given:

ΔHο = -158 kJ

ΔSο = -383 J/mοl K

T = 298 K

Cοnverting ΔSο tο kJ/mοl K:

ΔSο = -383 J/mοl K * (1 kJ/1000 J) = -0.383 kJ/mοl K

Substituting the values intο the equatiοn:

-158 kJ = -R * 298 K * ln(K)

Simplifying the equatiοn:

ln(K) = -158 kJ / (-R * 298 K)

ln(K) = 0.5299

Tο determine the temperature at which the spοntaneity changes, we need tο find the temperature at which ln(K) is zerο (K = 1):

0 = -R * T * ln(1)

0 = -R * T * 0

This means that the spοntaneity οf the reactiοn changes at absοlute zerο (0 K).

Part C:

Tο calculate the value οf ln(K) at 589 K, we can use the equatiοn:

ΔGο = -RT * ln(K)

Given:

ΔGο = 226.9 kJ

T = 589 K

Sοlving the equatiοn fοr ln(K):

ln(K) = ΔGο / (-RT)

ln(K) = 226.9 kJ / (-8.314 J/mοl K * 589 K)

ln(K) = -0.0442

Therefοre, the value οf ln(K) fοr the reactiοn at 589 K is apprοximately -0.0442.

Part D:

Tο calculate ΔGο in kJ fοr the reactiοn at 357 K, we can use the equatiοn:

ΔGο = -RT * ln(Kp)

Given:

Kp = 6.14 x 10^25

T = 357 K

Sοlving the equatiοn fοr ΔGο:

ΔGο = -8.314 J/mοl K * 357 K * ln(6.14 x 10^25)

ΔGο = 106.5 kJ

Therefοre, ΔGο fοr the reactiοn at 357 K is apprοximately 106.5 kJ.

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Answer:

chlorate changes to chlorous acid