Which of the four models represents a solid

Answer:

Electronegativity is probably the biggest thing that plays into reactivity. Therefore, since fluorine has a higher electronegativity than chlorine, fluorine is more reactive.

Explanation:

I got it right

Considering the Gay-Lussac's law, the final temperature when the gas is heated at constant volume until the pressure triples is 909 K or 636° C.

Gay-Lussac's law establishes the relationship between the temperature and pressure of a gas when the volume is constant. This law says that the pressure of a gas is directly proportional to its temperature: if the temperature increases, the pressure will increase, while if the temperature decreases, the pressure will decrease.

Mathematically, Gay-Lussac's law states that the ratio between pressure and temperature always had the same value:

P÷ T= k

where

Analyzing an initial state 1 and a final state 2, it is fulfilled:

P₁÷ T₁= P₂÷ T₂

In this case, you know that the gas is heated at constant volume until the pressure triples. This is, P₂=3×P₁

Replacing in Gay-Lussac's law:

P₁÷ T₁= (3×P₁)÷ T₂

T₂× (P₁÷ T₁)=(3×P₁)

T₂= (3×P₁)÷ (P₁÷ T₁)

T₂= 3×T₁

If one mole of oxygen gas is at a temperature of 30°C of 303 K (being 0 C= 273 K), then:

T₂= 3×303 K

T₂= 909 K = 636° C

Finally, the final temperature is 909 K or 636° C.

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Answer:

If a rock displaces 1.65L of water, its volume must be 1.65L.
If you want to convert that to cm^3 it's 1000 cm^3 per liter...so 1650 cm^3

Explanation:

Answer:

C

Explanation:

hahhahahabhahahahahahhahaha

Strong lemonade in a pewter pitcher can result in chemical contamination.

The type of Utensils and equipment used to cook or store food and beverages can cause a detrimental effect to the body.

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Complete Question

Storing Lemonade in a pewter pitcher can result in Chemical contamination.

The options were omitted an they  are

A. Physical contamination

B. Chemical contamination

C. Cross-contact

Answer:

1. To understand the differences between natural and synthetic fibers and their properties.

2. To learn about the manufacturing process of synthetic fibers and plastics and the different types of synthetic fibers and plastics available.

3. To explore the various applications of synthetic fibers and plastics in different industries such as fashion, automotive, construction, and electronics.

4. To investigate the environmental impact of synthetic fibers and plastics and the importance of recycling and proper disposal methods.

5. To evaluate the advantages and disadvantages of synthetic fibers and plastics compared to natural materials and their impact on society and the economy.

6. To analyze the future trends and innovations in the field of synthetic fibers and plastics and their potential impact on different industries and the environment.

The balanced redox equation for the given reaction in acidic solution is:

\(3NO + 3Cu^2+ + 2e^- - > 3NO_3^- + 3Cu^+.\)

To balance the redox reaction:

\(NO + Cu^2+ - > NO_3^- + Cu^+\)

First, let's assign oxidation states to each element/ion in the equation:

Oxidation state of N in NO: +2

Oxidation state of N in \(NO_3^-: +5\)

Oxidation state of Cu in \(Cu^2+: +2\)

Oxidation state of Cu in \(Cu^+: +1\)

From the given oxidation states, we can see that N is being oxidized from +2 to +5, and Cu is being reduced from +2 to +1. We need to balance both the charge and the number of atoms on each side of the equation.

Balancing the nitrogen:

We need three NO molecules on the reactant side to balance the nitrogen atoms on the product side. Thus, the equation becomes:

\(3NO + Cu^2+ - > NO_3^- + Cu^+\)

Balancing the charge:

The charge on the reactant side is 0 (since NO is neutral), while on the product side, we have 1- charge from NO_3^- and 1+ charge from Cu^+. To balance the charges, we need two electrons on the reactant side.

Final balanced equation:

\(3NO + 3Cu^2+ + 2e^- - > 3NO_3^- + 3Cu^+\)

In acidic solution, we need to balance the hydrogen ions \((H^+)\). In this case, there are no hydrogen ions on either side of the equation, so no additional steps are needed.

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There are 3.33 moles of \(C_{2}H_{4}\) in the mixture.

The balanced chemical equation for the combustion of methane and ethene is:

\(CH_{4} + 2O_{2} = CO_{2} + 2H_{2}O\\C_{2}H_{4} + 3O_{2} = 2CO_{2} + 2H_{2}O\)

From the equation, we can see that for every mole of \(C_{2}H_{4}\), 3 moles of O2 are needed. Therefore, to burn 10 moles of O2, we need:

10 moles \(O_{2}\)x (1 mole \(C_{2}H_{4}\)/3 moles \(O_{2}\)) = 3.33 moles \(C_{2}H_{4}\)

So, there are 3.33 moles of \(C_{2}H_{4}\) in the mixture.

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Answer:

True

Explanation:

Nitrate is in most plants

NH3 is the chemical compound produced as a product in the given balanced chemical equation.

With the formula NH3, ammonia is a nitrogen and hydrogen inorganic chemical. A Lewis base is urea. Ammonia is a colourless, extremely unpleasant gas that has a strong, suffocating stink when it is present at room temperature. It is hygroscopic and known as anhydrous ammonia in its pure state (readily absorbs moisture). Ammonia is corrosive and has alkaline qualities.

Water molecules' shared dipoles and development of hydrogen bonds with one another account for this. As a consequence, the molecules of water and ammonia are both made up of dipoles that exert significant electrostatic forces on one another.

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a is the correct answer

Two moles or 36 g of water on decomposition gives 32 grams of oxygen gas. Then 494 g of water will give 439.1 g of oxygen.

The decomposition is a type of reaction in which a single compound breaks into its constituent elements or molecules. Water molecules are formed by the combination of hydrogen and oxygen atoms.

Decomposition of two moles of water  decompose to give 2 moles of hydrogen gas and one mole of oxygen gas.

molar mass of water = 18 g/mol

molecular mass of oxygen  = 32 g/mol

Two moles or 36 g of water gives one mole or 32 g of oxygen gas. Then mass of oxygen produced by 494 g of water is :

(494 ×32)/36 g = 439 g

Therefore, 439 g of oxygen gas is formed by the decomposition of 494 g of water.

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The electrons move from left to right through the circle labeled "M" to reach the cathode, where reduction takes place.

If oxidation occurs on the left side of the fuel cell and reduction occurs on the right side, the movement of electrons can be described as follows: Electrons move from left to right through the circle labeled "M."

In a fuel cell, the process of oxidation takes place at the anode (labeled A) where the fuel is oxidized, releasing electrons. These electrons then flow through the external electrical circuit, represented by the wire connecting objects A and B. The electrons reach the cathode (also labeled A) on the right side of the cell, where reduction occurs.The circle labeled "M" represents the membrane or electrolyte in the fuel cell. This membrane allows the transport of ions but blocks the movement of electrons. As a result, electrons cannot flow directly through the electrolyte but must travel through the external circuit.

This movement of electrons through the external circuit is what generates an electric current that can be used to power electrical devices or systems.

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Answer: A

Explanation: Plants us photosynthesis transform sunlight, water, and carbon dioxide into oxygen, and simple sugars that the plant uses as fuel

Answer:

A saturated solution is a mixture in which the maximum amount of a given solute has been dissolved into the solvent. ... At this point adding more solute will not change the concentration of the solution; adding more solute will simply result in more solid at the bottom of the solution.

Answer:

will not change

Explanation:

A saturated solution is a mixture in which the maximum amount of a given solute has been dissolved into the solvent. ... At this point adding more solute will not change the concentration of the solution; adding more solute will simply result in more solid at the bottom of the solution.

When you count atoms, remember to multiply the coefficient number and the subscript number to find the number of atoms of that element. Examples: ▪ 2H2O. Number of atoms Number of molecules = 2. H-4.

The cell potential (Ecell) at 25°C (298 K) for the given reaction is 1.065 V which means that the reaction is spontaneous because the calculated Ecell is positive

The cell potential (Ecell) for the given reaction can be calculated using the Nernst equation:

Ecell = E°cell - (RT ÷ nF) × ln(Q)

where E°cell = standard cell potential, R = gas constant, T = temperature in Kelvin, n = number of electrons transferred in the reaction, F = Faraday constant, and Q is the reaction quotient.

Since two electrons are transported in the half-reactions, n in this instance equals 2. With the help of the species concentrations, it is possible to determine the reaction quotient Q:

Q = [Fe2+] ÷ [Cu2+]

Q = 0.645 ÷ 0.064

Q = 10.078

Now, we can calculate the Ecell:

Ecell = E°cell - (RT ÷ nF) × ln(Q)

Ecell = (0.337 - (-0.440)) - (8.31 × 298 ÷ (2 × 96500)) × ln(10.078)

Ecell = 1.065 V

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Answer: 4 miles

Explanation:

Riding the bike 12 mph (miles per hour) for one hour, we would ride the bike 12 miles. Since 20 minutes is 1/3 of a hour, divide 12 by 3 to find out how far the biker traveled in 1/3 of the time: 4 miles Hope this helps

Hello!

\(\large\boxed{\frac{5}{3}\text{ hours} \text{ or }100 \text{ min}}\)

Use the equation d = s · t where:

s = speed

t = time

d = distance

Plug in the given distance and speed:

20 = 12 ·t

Divide both side by 12 to isolate for t:

20/12 = t

Simplify:

5 / 3 = t

Therefore, it took 5/3 hours to bike. We can convert this to minutes if necessary:

5/3 · 60 min (in one hour) = (60 · 5) / 3 = 100 min.

In this reaction 10.8 moles of carbon dioxide was produced. 10.8moles of carbon monoxide used in this reaction to produce such number of moles of carbon dioxide.

In chemistry, a mole, usually spelt mol, is a common scientific measurement unit for significant amounts of very small objects like molecules, atoms, or other predetermined particles. The mole designates 6.02214076 1023 units, which is a very large number.

For the Worldwide System of Units (SI), the mole is defined as this number as of May 20, 2019, according to the General Convention on Measurements and Weights. The total amount of atoms discovered through experimentation to be present in 12 grammes of carbon-12 was originally used to define the mole.

2CO(g)+O\(_2\)(g)=2CO\(_2\)(g)

moles of carbon dioxide= 10.8 moles

According to stoichiometry

moles of carbon monoxide=  (2/2)× 10.8 =10.8moles.

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Answer

D. If the temperature decreases, then crickets will chirp less.

Explanation

A hypothesis is a testable guess about the relationship between two or more variables. As the temperature rises, it becomes easier to reach a certain activation energy, thereby allowing chemical reactions, such as the ones that allow a cricket to chirp, to occur more rapidly. Conversely, as the temperature falls, the reaction rates slow, causing the chirping to diminish along with it. Therefore the above statem

Answer:

(a) oxygen

(b) 154g (to 3sf)

(c) 79.9% (to 3sf)

Explanation:

mass (g) = moles × Mr/Ar

note: eqn means chemical equation

(a)

moles of P = 84.1 ÷ 30.973 = 2.7152 moles

moles of O2 = 85÷2(16) = 2.65625 moles

Assuming all the moles of P is used up,

moles of O2 / moles of phosphorus = 5/4 (according to balanced chemical eqn)

moles of O2 required = 5/4 × 2.7152moles = 3.394 moles (more than supplied which is 2.65625moles)

therefore there is insufficient moles of O2 and the limiting reactant is oxygen.

(b)

moles of P2O5 produced

= 2/5 (according to eqn) × 2.7152

= 1.08608moles

mass of P2O5 produced

= 1.08608 × [ 2(30.973) + 5(16) ]

= 154.164g

= approx. 154g to 3 sig. fig.

(c)

% yield = actual/theoretical yield × 100%

= 123/154 × 100%

= 79.870%

= approx. 79.9% (to 3sf)

Answer:

same valency electrons

Explanation:

example g 1 elements

The arrows B, C, and E represent the process of cooling.

Solid state: In the solid state, the molecules are arranged in a regular and fixed pattern. The molecules in a solid are closely packed that is the solid particles can not move.

Liquid state: In the liquid state, the molecules are present in an irregular pattern. The molecules are closely packed but particles can move.

Gaseous state: In the gaseous state, the molecules are present in an irregular manner. The molecules of gases are not closely packed and can move freely.

Therefore, the solid changes to liquid on heating, and the liquid changes to solid after cooling.

Liquid changes to a gaseous state on heating while gases changes to liquid on cooling.

Solid changes to gas on heating and gases change to solid after cooling.

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THE ADVANTAGE OF IODIN

THE DISADVANTAGE OF IODIN

The percent natural abundance of Le-19, Le-17, and Le-15 isotopes are 40%, 44%, and 16% respectively.

Lemonium (Le) has three isotopes, which are Le-19, Le-17, and Le-15.

The given image shows a representative sample of 50 atoms of Lemonium, and we are to determine the percent natural abundance of each of the three isotopes.

Lemonium is an element having three isotopes, so we need to calculate the percent natural abundance of each of the three isotopes of Lemonium.

The percent natural abundance of the isotopes can be calculated as follows:Percent natural abundance of Le-19:As we know that Lemonium (Le) has three isotopes, so it can be represented as follows: Le-19, Le-17, and Le-15.

We are given that the number of Le-19 isotopes in the representative sample is 20.

So, the percentage of Le-19 isotopes can be calculated as follows:Percentage of Le-19 = (Number of Le-19 isotopes / Total number of Lemonium atoms) x 100% = (20/50) x 100% = 40%.

Therefore, the percent natural abundance of Le-19 is 40%.

Percent natural abundance of Le-17:Similarly, the number of Le-17 isotopes in the representative sample is 22.

So, the percentage of Le-17 isotopes can be calculated as follows:Percentage of Le-17 = (Number of Le-17 isotopes / Total number of Lemonium atoms) x 100% = (22/50) x 100% = 44%.

Therefore, the percent natural abundance of Le-17 is 44%.

Percent natural abundance of Le-15:Moreover, the number of Le-15 isotopes in the representative sample is 8.

So, the percentage of Le-15 isotopes can be calculated as follows:Percentage of Le-15 = (Number of Le-15 isotopes / Total number of Lemonium atoms) x 100% = (8/50) x 100% = 16%.

Therefore, the percent natural abundance of Le-15 is 16%.

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Answer:

I think its 2 C8H18 + 25 O2 = 18 H2O + 16 CO2

Im not sure!

Explanation:

Alkali metals require least amount of ionization energy.

Peaky Blinder fan? haha

The 2 isotopes of Nitrogen are Nitrogen-14  and Nitrogen-15 .

Isotopes are atoms with the same number of protons and different number of neutrons. Even though they have nearly identical chemical properties, they differ in mass which affects their physical properties.

As you know, the atomic number of nitrogen is = 7.

Isotopes are forms of elements that have the same atomic number (Z) but different mass numbers because they have different numbers of neutrons (A).

Now,

Atomic number = number of protons

Isotopes have the same atomic number.

Atomic number for both isotopes = 7. However, the mass numbers of the two isotopes are different.

In other words, the mass number = the number of (protons + electrons).

Therefore, nitrogen-14 has a mass number of 14 and nitrogen-15 has a mass number of 15.

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Answer:

The combustion of diborane (B2H6) is as follows:

2B2H6(g) + 6O2(g) → 4H2O(g) + B4O(g)

The balanced chemical equation shows that 2 moles of B2H6 react with 6 moles of O2 to produce 4 moles of H2O and 1 mole of B4O. We can use this information to calculate the amount of heat released by the combustion of 0.491 g of B2H6:

0.491 g B2H6 × (1 mol B2H6/27.67 g B2H6) × (1 mole B4O/2 moles B2H6) × (-2037 kJ/mol B4O) = -7.89 kJ

The negative sign indicates that the reaction releases heat.

The heat released by the reaction is absorbed by the calorimeter, which causes its temperature to increase. We can use the equation:

q = Ccalorimeter × ΔT

where q is the amount of heat absorbed by the calorimeter, Ccalorimeter is the heat capacity of the calorimeter, and ΔT is the change in temperature of the calorimeter.

Rearranging the equation, we get:

ΔT = q/Ccalorimeter

Substituting the values we obtained, we get:

ΔT = (-7.89 kJ)/(7.854 kJ/°C) = -1.005°C

The negative sign indicates that the temperature of the calorimeter decreases by 1.005°C. Therefore, the final temperature of the calorimeter is:

19.63°C - 1.005°C = 18.625°C

Rounding to the appropriate number of significant figures, the final temperature of the calorimeter is 18.6°C.

Hope this is what you are looking for.