The forces applied to the block that perform nonconservative work on the system are: Applied force friction
Friction is a force that resists the motion between two surfaces that are in contact.. Nonconservative forces are forces that dissipate the mechanical energy of a system. The forces that perform nonconservative work are the applied force and the frictional force.
The normal force and the spring force are conservative forces because they do not dissipate mechanical energy but rather conserve it. They do not perform nonconservative work.
Friction can both be beneficial and harmful. For example, it can be useful for preventing slipping and sliding of objects.
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What is the difference between an end moraine and a ground moraine, and how do they relate to the budget of a glacier?
The end moraine is a ridge till forming at the end of the glacier when the ice record is in equilibrium. The ground moraine is a layer of till that is deposited when the ice melts when the ice shear exceeds the accumulation. End moraine is a type of moraine that forms at the end (edge) of a glacier, marking its maximum stride.
What is moraine?A moraine is an accumulation of unconsolidated debris (regolith and rocks), sometimes referred to as glaciation, that occurs in current and former glacial regions, and has previously been covered by glaciers or ice caps. drift ice. It can consist of partially round particles ranging in size from boulders (in this case often called boulder clay) to gravel and sand, in a subdivided mass of clay material sometimes called ice powder. Lateral moraines are mounds that form on the side of the glacial flow, and end glacials that form at the foot, marking the maximum advance of the glacier. Other types of moraines include ground moraines (areas that are covered until the formation of plates over flat or irregular terrain) and intermediate moraines (the morass formed at the encounter) of two glaciers).
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use the superposition principle to solve for va in the circuit
The superposition principle allows us to solve for va in a circuit with multiple sources by finding the individual contributions of each source and adding them up. This can be done by turning off one source at a time and solving for va in each case.
To solve for va in the circuit using the superposition principle, we first need to find the contributions of each source individually and then add them up. We can turn off one source at a time and solve for va in each case. Then we add up the individual contributions to get the final value of va.
For example, if we turn off the voltage source V1, we can redraw the circuit with V2 and the current source as the only active sources. We can then solve for va using Ohm's law and Kirchhoff's laws. We repeat the same process for V2 and the current source, each time turning off the other sources.
After finding the individual contributions, we can add them up to get the final value of va using the principle of superposition. The final value of va will be the algebraic sum of the individual values.
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Write SQL Queries for following set of tables: EMPLOYEE (EmpNo, Name, DoB, Address, Gender, Salary, DNumber) DEPARTMENT (DNumber, Dname, ManagerEmpNo, MnagerStartDate). Display the Age of ‘male’ employees. Display all employees in Department named ‘Marketing’. Display the name of highest salary paid ‘female’ employee. Which employee is oldest manger in company? v) Display the name of department of the employee ‘SMITH’
The SQL queries for the given set of tables: EMPLOYEE (EmpNo, Name, DoB, Address, Gender, Salary, DNumber) DEPARTMENT (DNumber, Dname, ManagerEmpNo, MnagerStartDate) is given below.
What is the SQL Queries?The code that display the age of 'male' employees is given below:
sql
SELECT Name, TIMESTAMPDIFF(YEAR, DoB, CURDATE()) AS Age
FROM EMPLOYEE
WHERE Gender = 'male';
The code that display all employees in the Department named 'Marketing':
sql
SELECT *
FROM EMPLOYEE
WHERE DNumber IN (SELECT DNumber FROM DEPARTMENT WHERE Dname = 'Marketing');
The code that display the name of the highest salary paid 'female' employee:
sql
SELECT Name
FROM EMPLOYEE
WHERE Gender = 'female'
ORDER BY Salary DESC
LIMIT 1;
Therefore, This code shows the age of male workers and workers in the ‘Marketing’ team, and the name of the woman who earns the most, using special statements.
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Most ceilings are covered with plaster or…
Explanation:
Most ceilings are coverd with plaster or board.
What components should you inspect if the crankshaft end play is out of specifications?
Answer:
gdyc ddxtfvytg4dgtfxdwcftcd3rcby
If the crankshaft end play is out of specifications, check for:
Thrust Bearings
Main Bearings
Crankshaft
Crankshaft Thrust Washers
Engine Block
To understand the crankshaft when it is out of specifications, check for:
Thrust Bearings: Check the condition of the thrust bearings, which are located at the front and/or rear of the engine block. Excessive wear or damage to the thrust bearings can contribute to increased crankshaft end play.
Main Bearings: Inspect the main bearings, which support the crankshaft within the engine block. Worn or damaged main bearings can cause excessive movement of the crankshaft.
Crankshaft: Check the crankshaft itself for any signs of damage, such as scoring or bending. A damaged crankshaft may not sit properly within the bearings, leading to increased end play.
Crankshaft Thrust Washers: Some engines use thrust washers to control the end play of the crankshaft. Inspect these washers for wear, damage, or improper installation.
Engine Block: Check the engine block for any signs of damage or distortion that may affect the alignment and support of the crankshaft.
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In the case, the software engineers present at the meeting would concern themselves with ________-level strategy
In the case, the software engineers present at the meeting would concern themselves with functional level strategy.
Software engineers create and construct computer systems and applications to solve problems in the real world. Software engineers usually referred to as software developers, create software for computers and apps.
Functional-level strategies are the tasks and goals assigned to various divisions to support your corporate strategy and business plan. These strategies outline the results you hope to obtain from the regular operations of particular divisions (or functions) of your company.
Things like prompt delivery of commodities, high-quality procedures and products, and process efficiency are examples of functional-level marketing techniques.
Therefore, in the case, the software engineers present at the meeting would concern themselves with functional level strategy.
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which of these is a characteristic of and application A it manages communication with the hardware. B it maintains the user interface. C it is essential to the computer's operation. D it helps the user perform an activity they want to do
Answer:
The answer is D
Explanation:
The characteristic of an application is it helps the user perform an activity they want to do. The correct option is D.
What is an application?An application program is a computer program that is designed to perform a specific activity that is not related to the operation of the computer itself and is typically utilized by end users. Examples include word processors, media players, and accounting software.
The different types of applications: are web, native, cross-platform, hybrid, etc. Scalability, portability, robustness, and agility are four fundamental features and functionalities that modern applications must have. Scalability: Today, we require apps that can scale to millions of people worldwide on demand.
Therefore, the correct option is D, it helps the user perform an activity they want to do.
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The gross weight of a two-place Piper Cherokee is 2000lb and its wing area is 160 ft^2. What is its wing loading
Answer:
\(W = 12.5\ lb/ft^2\) --- in \(lb/ft^2\)
\(W = 598.503N/m^2\) --- in \(N/m^2\)
Explanation:
Given
\(Weight=2000lb\)
\(Area = 160ft^2\)
Required
Determine the wing loading (W)
Wing loading is calculated using:
\(W = \frac{Weight}{Area}\)
Substitute values for Weight and Area
\(W = \frac{2000lb}{160ft^2}\)
\(W = 12.5\ lb/ft^2\)
The answer can also be converted to N/m^2
\(1\ lb = 4.4482216153N\)
\(1ft^2 = 0.092903m^2\)
So, we have:
\(W = \frac{12.5 * 4.4482216153N}{0.092903m^2}\)
\(W = \frac{55.6027701912N}{0.092903m^2}\)
\(W = 598.503N/m^2\)
Hence, the wing loading is:
\(W = 12.5\ lb/ft^2\) --- in \(lb/ft^2\)
\(W = 598.503N/m^2\) --- in \(N/m^2\)
Hot combustion gases, modeled as air behaving as an ideal gas, enter a steady-state turbine at 145 psi, 2700oR, and exit at 29 psi and 1974oR. The power output is 74.26 hp, and heat transfer from the turbine to the surroundings occurs at a rate of 14 BTU/s.
Required:
Determine the power output of the turbine, in hp.
Hot combustion gases, modeled as air behaving as an ideal gas, enter a steady-state turbine at 145 psi, 2700oR, and exit at 29 psi and 1974oR. The power output is 74.26 hp, and heat transfer from the turbine to the surroundings occurs at a rate of 14 BTU/s.
Required:
a)Determine the power output of the turbine, in hp.
b) The Flow rate
Answer:
a) \(w=74.26hp\)
b) \(m=0.22\)
Explanation:
From the question we are told that:
Initial Pressure \(p_1= 145 psi\)
Initial Temperature \(T_1 =2700oR=>2240.33^oF\)
Final Pressure \(p_2= 29 psi\)
Final Temperature \(t_2=1974oR=>1514.33^oF\)
Output Power \(w=74.26hp\)
Heat transfer Rate \(Q=14BTU/s\)
Generally the equation for Steady flow energy is mathematically given by
\(Q-w=m(h_2-h_1)\)
Where
\(m=Flow\ rate\)
From Steam table
\(h_1=704btu/ib (at\ p_1= 145\ psi,\ T_1 =2700oR=>2240.33^oF )\)
\(h_2=401btu/ib (at\ p_2= 29psi\ t_2=1974oR=>1514.33^oF )\)
Therefore
\(-14-74.26=m(401-704)\)
\(m=\frac{-14-74.26}{(401-704)}\)
\(m=0.22\)
Consider a control system with two components: a plant and a controller. The plant receives control u(t) as input and provides a signal y(t) as output according to the following ordinary differential equation: 3
y
˙
(t)+y(t)=2u(t). The controller receives a reference signal r(t) as input and provides a signal u(t) as output according to the following ordinary differential equation: 5
u
˙
(t)+u(t)=3r(t). Define a linear time-invariant state-space model for the closed-loop system described above. Choose x
1
(t)=e(t) and x
2
(t)=u(t) as state variables, r(t) as input, and y(t) as output. Show the derivation of the state-space model equations as well as the final state-space model. What are the matrices A,B,C, and D ?
To derive the state-space model for the given closed-loop system, let's start by writing the differential equations for the plant and the controller:
Plant:
The plant equation is given as:
y˙(t) + y(t) = 2u(t)
Controller:
The controller equation is given as:
u˙(t) + u(t) = 3r(t)
To define the state variables, let's set x1(t) = e(t) and x2(t) = u(t). Now, we need to express the differential equations in terms of the state variables.
Plant:
Differentiating x1(t) = e(t), we get:
x˙1(t) = e˙(t)
Since e(t) = y(t) - r(t), we can rewrite the equation as:
x˙1(t) = y˙(t) - r˙(t)
Using the plant equation, we substitute the value of y˙(t) into the above equation:
x˙1(t) = -y(t) + 2u(t) - r˙(t)
Controller:
Differentiating x2(t) = u(t), we get:
x˙2(t) = u˙(t)
Using the controller equation, we substitute the value of u˙(t) into the above equation:
x˙2(t) = 3r(t) - u(t)
Now, we can express the above differential equations in matrix form:
[x˙1(t)] [ 0 -1 ] [x1(t)] [ 0 ] [x2(t)]
[x˙2(t)] = [ 0 -1 ] [x2(t)] + [ 3 ] [r(t) ]
The matrices A, B, C, and D for the state-space model are:
A = [ 0 -1 ]
[ 0 -1 ]
B = [ 0 ]
[ 3 ]
C = [ 1 0 ]
D = 0
In summary, the state-space model for the given closed-loop system is:
[x˙1(t)] [ 0 -1 ] [x1(t)] [ 0 ] [x2(t)]
[x˙2(t)] = [ 0 -1 ] [x2(t)] + [ 3 ] [r(t) ]
With the matrices A, B, C, and D defined as mentioned above.
This state-space model can be used to analyze and design the closed-loop system. It provides a concise representation of the system dynamics and facilitates control design and analysis.
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control charts for variables are based on data that come from
Control charts for variables are based on data that come from continuous measurement processes.
These processes generate numerical measurements of a characteristic of interest, called a variable. The variable can be any measurable attribute such as weight, length, height, volume, temperature, pressure, and so on. The data obtained from measuring the variable is plotted on a control chart to monitor the stability and performance of the process over time.
Variables control charts consist of two types: X-bar and R charts. The X-bar chart displays the average value of the variable, and the R chart displays the range or variation of the variable. Both charts are used together to detect any shifts or changes in the process mean or variability.
The data used to construct the control charts should be representative of the process being monitored and should be collected in a systematic and consistent manner. The data should be accurate, precise, and unbiased. Typically, a minimum of 20 to 25 consecutive samples of the variable is collected before constructing the control charts.
In summary, control charts for variables are based on data that come from continuous measurement processes of a measurable attribute. The data is used to construct X-bar and R charts to monitor the stability and performance of the process over time. The quality of the data is essential to ensure the reliability and usefulness of the control charts.
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A Field Check is an abbreviated calibration procedure
performed at a work site.
True or false?
Answer:
true
Explanation:
hope this helps!
pls mark as brainliest
Convert an acceleration of 12m/s² to km/h²
Air at 40°C flow steadily through the pipe shown in Fig. 1 below. If P1 = 40 kPa (gage), P2 = 10 kPa (gage), D = 3d, Patm ≅ 100 kPa, the average velocity at section 2 is V2 = 25 m/s, and air temperature remains nearly constant, determine the average speed at section 1.
Based on the average velocity at section 2, and the absolute pressures at both sectors, the average speed at section 1 is 2.226 m/s.
What is the average speed at section 1?Density at P₁:
= (40 + 100) / (0.287 x (40 + 273))
= 1.5585 kg/m³
Density at P₂:
= (10 + 100) / (0.287 x (40 + 273))
= 1.2245 kg/m³
The average speed at section 1 is:
= (Density at P₂ x d² x 25.5) / (Density at P₁ x 9d²)
= 2.226 m/s
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Fill in the truth table for output A.
A = (x+y)(x'+z')(x'+z')
Answer:
1+1×1 multiplay then you get the answer
When an electric current flows through a wire with resistance, energy is a. liberated as x-rays b. liberated as heat c. liberated as light
When an electric current flows through a wire with resistance, energy is liberated as heat.
Thus, when a current flows through the resistor, the electrical energy is converted into heat energy. Hence the heat that is generated in the components of the circuit possesses some resistance and is dissipated into the air around the components.
Resistance in a wire causes a hindrance to the flow of electrons, which results in the conversion of electrical energy into thermal energy. This thermal energy is then dissipated into the surrounding environment, which can be felt as heat.
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(1) Complete E/R diagram from Phase 1 (25 points) On you E/R diagram, clearly describe each entity (including, list of entity attributes, and the primary key), and each relationship with its multiplicities. (2) Relational Model (25 points) Using the method for translating an E/R diagram to relations, produce a set of tables for your database design For each table, specify the attributes, their domains, required data constraints, default values, primary key, candidate keys, foreign keys and the tables which the foreign keys are referencing (everything you need for a CREATE TABLE statement) (3) Complete Database Functionalities and User Interface (40 points) (a) List all actors (i.e. users) of your database (b) For each actor, list all use-cases including all the steps. For each entity, you must have use cases that perform at least one aggregate query, one insert operation, one delete operation, and one update operation; For each relationship, you must have use cases that perform at least one joint query. (Number your use cases. That's a minimum of 34 use cases for 7 entities, and 44 use cases for 9 entities) (c) Use Case Realization: Explain how the relations and relationships are used in EACH of the use cases. Provide the complete relational algebra or SQL statements for every use case. (4) Project Time Table (10 points) (a) List major tasks to a be completed (b) For each task, indicate team member responsible for competing task, and planned completion dates.
Entities, attributes, and relationships are the three main building blocks of E/R diagrams or ERDs. Entities are usually represented by a rectangle and can be objects, people, concepts, or events that contain data.
For more than 35 years, there has been an entity relationship (ER) data model. Because it is rather abstract and simple to describe and explain, it is a good fit for data modelling for usage with databases. Relationship models may be easily converted to relations. ER diagrams serve as a visual representation of ER models, also known as ER schemas. The foundation of the database is comprised on autonomous objects, often known as kernels. They serve as the foundation for additional tables. The meaning of dependent entities, also known as derived entities, is derived from other tables. Additional details about one table are provided by characteristic entities. Each attribute has a name, a domain of allowed values, and an association with an entity. The ERD does not, however, display the attribute domain information.
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Consider a steam power plant that operates on the ideal reheat Rankine cycle. The plant maintains the boiler at 5000 kPa, the reheat section at 1200 kPa, and the condenser at 20 kPa. The mixture quality at the exit of both turbines is 96 percent. Determine the temperature at the inlet of each turbine and the cycle's thermal efficiency.
Answer:
no one liked the play changing active and passive voice
Boiler monitor: Over the following three chapters, we will create an app that monitors the temperature and pressure of a boiler. You can model the app based on the Thyroid app. In this chapter, we will create the skeleton of the app, similar to the Thyroid app. Now, just create the pages and the links to navigate between them; you will implement the functionality of the pages in later chapters. The app will have
• A password-based entry page.
• A page to get basic information about the boiler such as the boiler ID, date of purchase, maximum allowable values of pressure and temperature, and an ability to change the password.
• A menu page with four choices
i. An option and corresponding page to allow you to change the basic information about the boiler.
ii. An option and corresponding page to enter data—temperature and pressure.
iii. An option and corresponding page to graph the data.
iv. An option and corresponding page to make recommendations based on the values of temperature and pressure.
Answer:
Explanation:
Based on the provided description, here is the outline for the pages and their corresponding functionality in the Boiler Monitor app:
1. Password-based Entry Page:
- This page will serve as the initial login screen where users need to enter a password to access the app's features.
- The functionality to validate the password and allow access will be implemented in a later chapter.
2. Boiler Information Page:
- This page will display basic information about the boiler, including the boiler ID, date of purchase, maximum allowable values of pressure and temperature.
- Users will also have the ability to change the password on this page.
- The functionality to update the boiler information and change the password will be implemented in a later chapter.
3. Menu Page:
- This page will present users with four choices to navigate within the app.
- Each choice will correspond to a specific functionality or feature.
i. Change Boiler Information Page:
- Selecting this option will navigate users to a page where they can modify the basic information about the boiler.
- The functionality to update the boiler information will be implemented in a later chapter.
ii. Data Entry Page:
- Choosing this option will lead users to a page where they can enter temperature and pressure data for the boiler.
- The functionality to store and manage the entered data will be implemented in a later chapter.
iii. Data Graphing Page:
- This option will direct users to a page where they can view graphs or visual representations of the recorded temperature and pressure data.
- The functionality to generate and display the graphs will be implemented in a later chapter.
iv. Recommendations Page:
- Selecting this option will navigate users to a page where recommendations based on the values of temperature and pressure will be provided.
- The functionality to analyze the data and generate recommendations will be implemented in a later chapter.
Please note that the actual implementation of the app's functionality will require coding and development work based on the outlined structure. This outline serves as a starting point for the app's architecture and navigation flow.
For the three-point bending test set up in this lab, what would be the shear force and moment distributions along the beam axis
Answer: So to calculate the flexural strength (σ), multiply the force by the length of the sample, and then multiply this by three. Then multiply the depth of the sample by itself (i.e., square it), multiply the result by the width of the sample and then multiply this by two
Explanation:
change the navigation pane grouping option so all database objects of the same type are grouped together
You chose the Header of the Navigation Pane. You choose the Object Type menu item from the Category/Group menu.
How can I alter the quizlet object type grouping option in the navigation pane?Modify the Object Type grouping option in the Navigation Pane. Go to the Navigation Pane on the left, then click the down arrow in the top right corner to select Object Type. Change the report's view to Design.
The object type is one approach to organise items in the navigation pane.Organizing items in the Navigation Pane by object type is one method. The Crosstab Query Wizard is the sole tool available for creating Crosstab queries. You have complete control over every element of a report using the Report Design view. In the Report Layout view, you can resize a control.
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A voltage amplifier with an input resistance of 40 kΩ, an output resistance of 100 Ω, and a gain of 300 V/V is connected between a 10- kΩ source with an open-circuit voltage of 10 mV and a 100-Ω load. For this situation: (a)What output voltage results? (b)What is the voltage gain from source to load? (c)What is the voltage gain from the amplifier input to the load? (d)If the output voltage across the load is twice that needed and there are signs of amplifier saturation, suggest the location and value of a single resistor that would produce the desired output. Choose an arrangement that would cause minimum disruption to an operating circuit. (Hint)
Answer:
a) 2.40 V
b) 120
c) 150
d) 8 kΩ in parallel with the amplifier input
Explanation:
The voltage divider between the source resistance and the amplifier input resistance makes the amplifier input voltage be ...
vi = (10 mV)(ri/(rs+ri)) = (10 mV)(40/(10+40)) = 8 mV
(a) The gain of 300 makes the open-circuit amplifier output voltage be ...
Vo = 300(8 mV) = 2400 mV = 2.40 V . . . . open-circuit output voltage
__
(b) The load voltage is the result of voltage-divider action between the output resistance and the load resistance.
Vl = Vo(rl)/(ro +rl) = 2.40 V(100)/(100 +100) = 1.20 V
So, the overall voltage gain from the source is ...
vl/vs = (1.20 V)/(0.010 V) = 120 . . . . voltage gain from source
__
(c) The voltage gain to the load from the amplifier input is ...
vl/vi = 1.200 V/0.008 V = 150 . . . . voltage gain from input to load
__
(d) To reduce the input of the amplifier without breaking the circuit, we could add a resistor in parallel with the amplifier input. It would need to reduce the gain of that voltage divider from 0.8 to 0.4 to cut the output voltage in half. That is, for some parallel resistor R (in kOhms), we want ...
R(Ri)/(R·(Ri +Rs) +Ri·Rs)) = 0.40
40R/(50R + 400) = 2/5
200R = 100R +800 . . . . cross multiply
100R = 800 . . . . . . . . . . . subtract 100R
R = 8 . . . . kOhms
Putting 8 kOhms in parallel with the amplifier input will reduce the overall gain by the required amount.
A compound Boolean expression created with the _______ operator is true if either of its sub-expressions is true.
A compound Boolean expression created with the OR operator is true if either of its sub-expressions is true.
In a compound Boolean expression, the OR operator is represented by the symbol "||". This operator is used to combine two or more sub-expressions and returns a true value if either of the sub-expressions is true. For example, if we have the following compound Boolean expression:
(x > 5) || (y < 10)
This expression will return a true value if either x is greater than 5 or y is less than 10. If both sub-expressions are false, then the compound Boolean expression will return a false value.
In conclusion, the OR operator is used in compound Boolean expressions to return a true value if either of its sub-expressions is true.
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cubical tank 1 meter on each edge is filled with water at 20 degrees C. A cubical pure copper block 0.46 meters on each edge with an initial temperature of 100 degrees C is quickly submerged in the water, causing an amount of water equal to the volume of the smaller cube to spill from the tank. An insulated cover is placed on the tank. The tank is adiabatic. Estimate the equilibrium temperature of the system (block + water). Be sure to state all applicable assumptions.
Answer:
final temperature = 26.5°
Explanation:
Initial volume of water is 1 x 1 x 1 = 1 \(m^{3}\)
Initial temperature of water = 20° C
Density of water = 1000 kg/\(m^{3}\)
volume of copper block = 0.46 x 0.46 x 0.46 = 0.097 \(m^{3}\)
Initial temperature of copper block = 100° C
Density of copper = 8960 kg/\(m^{3}\)
Final volume of water = 1 - 0.097 = 0.903 \(m^{3}\)
Assumptions:
since tank is adiabatic, there's no heat gain or loss through the wallsthe tank is perfectly full, leaving no room for cooling airtotal heat energy within the tank will be the summation of the heat energy of the copper and the water remaining in the tank.mass of water remaining in the tank will be density x volume = 1000 x 0.903 = 903 kg
specific heat capacity of water c = 4186 J/K-kg
heat content of water left Hw = mcT = 903 x 4186 x 20 = 75.59 Mega-joules
mass of copper will be density x volume = 8960 x 0.097 = 869.12 kg
specific heat capacity of copper is 385 J/K-kg
heat content of copper Hc = mcT = 869.12 x 385 x 100 = 33.46 Mega-joules
total heat in the system = 75.59 + 33.46 = 109.05 Mega-joules
this heat will be distributed in the entire system
heat energy of water within the system = mcT
where T is the final temperature
= 903 x 4186 x T = 3779958T
for copper, heat will be
mcT = 869.12 x 385 = 334611.2T
these component heats will sum up to the final heat of the system, i.e
3779958T + 334611.2T = 109.05 x \(10^{6}\)
4114569.2T = 109.05 x \(10^{6}\)
final temperature T = (109.05 x \(10^{6}\))/4114569.2 = 26.5°
help protect the lower legs and feet from heat hazards like molten metal and welding sparks
Answer:
i think its called leggings thats wut my shop teacher told me
Explanation:
Two long pipes convey water between two reservoirs whose water surfaces are at different elevations. One pipe has a diameter twice that of the other; both pipes have the same length and the same value of f. If minor losses are neglected, what is the ratio of the flow rates through the two pipes?
Answer:
1 : 5.66 ≈ 1 : 6
Explanation:
Determine the ratio of the flow rates through the two pipes
The flow from the bigger pipe is 5.66 times greater than that from the smaller pipe hence the ratio of the flow rates is : 1 : 5.66
attached below is the detailed/remaining part of the solution
Mild neurotoxins can cause which of these physical effects?
What is 90 to the power of 46
Answer:Just multiply 90 by itself 46 times
Explanation:
do it
What is the basic requirement of measurements?
The basic requirement of measurements is to have a standard or reference point against which to compare the quantity being measured. This standard or reference point should be well-defined and stable, and the measurement process should be repeatable and consistent. Additionally, it is important to ensure that the measurement equipment is calibrated and in good working condition.
Answer:
The most basic requirement for measurements is the presence of a standard or reference point against which the quantity being measured can be compared. The measurement process should be repeatable and consistent, and the standard or reference point should be well-defined and stable. Furthermore, ensure that the measurement equipment is calibrated and in good working order.
Explanation:
compare and contrast a software development process with the software project management (poma) process.
Below you can find the compare and contrast of software development process with the software project management (poma) process.
process for developing software
A framework put on the creation of a software product is the software development process or life cycle. Such processes include a number of models, each of which describes methods for a range of tasks or activities that take place during the process. Process approaches are being used by more and more firms that build software.
Analysis of Requirements
The first step in building desired software is to identify its needs. Customers likely think they know what the product is supposed to perform, but identifying incomplete, confusing, or conflicting requirements may take ability and experience in software engineering.
method for managing software projects
The art and science of organising and supervising software projects are known as software project management. It is a branch of project management where software projects are planned, carried out, tracked, and managed. The different operations that make up software project management include project planning, determining the scope of the software product, cost estimating in various forms, task and event scheduling, and resource management.
Project Management
Scope Control
Task Estimation
Project Management
Planning the software project is a step that must be taken before the programme is actually produced. It is there to support software creation, but it doesn't really entail any specific tasks that are directly related to it; rather, it consists of a number of procedures that make software production easier.
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