Which of the following would most likely have grains cemented together?
a. marble
C. limestone
b. schist
d. diorite
Please select the best answer from the choices provided
c
A
B
С
D

The pressure (in atm) of hydrogen gas in the 20.0 L headspace of a reactor vessel when 3.36 kg sodium is reacted with excess water at 50.0 °C can be calculated using the ideal gas law, which states that the pressure, volume, and temperature of a gas are related by the equation PV = nRT, where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas in Kelvin.

To calculate the pressure of the hydrogen gas, we first need to determine the number of moles of hydrogen gas produced by the reaction. We can do this by using the balanced chemical equation for the reaction, which is 2 Na(s) + 2 H₂O(l) → 2 NaOH(aq) + H₂(g).

From the balanced chemical equation, we can see that for every 2 moles of sodium that react, 1 mole of hydrogen gas is produced. Therefore, if 3.36 kg of sodium is reacted with excess water, the number of moles of hydrogen gas produced is 3.36 kg / (22.99 g/mol) = 146.4 moles.

Next, we need to convert the temperature of the gas from degrees Celsius to Kelvin. This can be done by adding 273.15 to the temperature in Celsius, which gives us a temperature of 50.0 + 273.15 = 323.15 K.

Now that we have the number of moles of hydrogen gas and the temperature of the gas, we can plug these values into the ideal gas law equation to calculate the pressure of the hydrogen gas:

P = (nRT) / V

P = (146.4 mol * 0.08206 L*atm / mol*K * 323.15 K) / 20.0 L

P = 4.31 atm

Therefore, the pressure (in atm) of hydrogen gas in the 20.0 L headspace of a reactor vessel when 3.36 kg sodium is reacted with excess water at 50.0 °C is 4.31 atm.

Answer:

C: The conjugate base of hydrofluoric acid is weaker than that of acetic acid.

Explanation:

I took the quiz and I put the answer that the other guy put and got it wrong but then it showed me the right answer which is C

Keeping pollutants from getting into the water system is better than cleaning the water up after it is polluted this statement is false

Water pollutant means it is the contamination of water sources by substances which make the water unusable for drinking as well as cooking, cleaning, swimming and other activities so the given statement are false because if we do not pollute the water system then there is no need for cleanup the water system that's why the keeping pollutant from getting into the water is better

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The true statement about acids and bases is; acids mixed with bases neutralize each other. Option 1 is correct.

When an acid reacts with a base, they undergo a chemical reaction called neutralization, resulting in the formation of water and a salt. The hydrogen ions (H⁺) from the acid react with the hydroxide ions (OH⁻) from the base to form water (H₂O), while the remaining ions from the acid and the base combine to form a salt.

The neutralization reaction between acids and bases results in the formation of a neutral solution, with a pH close to 7. This is because the acidic and basic properties of the original substances are cancelled out or neutralized by each other.

Hence, 1. is the correct option.

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Answer:

The angle of sunlight varies on different parts of Earth at different times.

Explanation:

The seasons are a result of the Earth's tilt and are caused by the differential intensity of sunlight on different areas of Earth across the year.

Hope this is helpful to you!

Answer:

L-2.75 W-2.75 H-2.85

Explanation:

Radiocarbon dating, also known as carbon-14 dating, is a method used to determine the age of organic materials. It is based on the radioactive decay of the isotope carbon-14 (14C).

Living organisms constantly absorb carbon, including a small amount of carbon-14, from the atmosphere. When an organism dies, it no longer takes in carbon-14, and the existing carbon-14 begins to decay at a known rate. By measuring the ratio of carbon-14 to stable carbon isotopes (carbon-12 and carbon-13) in a sample, scientists can estimate the time that has elapsed since the organism's death. Radiocarbon dating is effective for dating materials up to about 50,000 years old.

Therefore, both radiocarbon dating and radiopotassium dating rely on the principles of radioactive decay. The decay rates of the isotopes used in these methods are well-established and constant, allowing for accurate age determinations.

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Answer:

Crest

Explanation:

The crest of the wave crashed over the railing of our boat.

The correct word to fill in the gap should be crest. The crest represents the highest part of a wave while the trough is the opposite, that is, the lowest part of a wave. Hence, the part of a wave that is capable of crashing over the railing of a boat is the peak or the crest.

Two isotopes of the FAKE element Sz, Average mass of  Seabreezium is equal to 199.77625 amu.

Given that Two isotopes of of Sz is given as :

Seabreezium-71 75%

Seabreezium - 76 25%

Now,

Isotopes of Seabreezium is given as:

Now,

 1st isotope = 71 75% of 271

                    = 194.44amu

  2nd isotope = 76 25% of 269

                       = 205.11 amu

Now,

Average Mass of Seabreezium = 205.11 + 194.44/2

 Average Mass of Seabreezium = 199.77625 amu

Thus, from the above conclusion we can say that, Average mass of  Seabreezium is equal to 199.77625 amu.

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The solubility of \(\\M(OH)_2}\) in a buffered solution is calculated to be 7.0 × \(10^{-2}\) at pH 7.0, 5.8 x \(10 ^{-6}\) M at pH 10.0, and 0.17 M at pH 14.0.

A substance's solubility refers to its capacity to dissolve in a solvent and condense into a homogenous solution. Temperature, pressure, and the chemical makeup of the solvent and solute all affect how soluble a material is. For instance, whereas sugar is insoluble in oil or petrol, it is soluble in water. In contrast, oil is insoluble in water but is soluble in petrol. The greatest quantity of solute that may dissolve in a given amount of solvent at a specific temperature and pressure is used to determine a substance's solubility.

Kw = [\(H^+\)][\(OH^{-}\)]

At pH 7.0, [\(H^+\)] = 1.0 x \(10^{-7}\)

[\(OH^-\)] = 1.0 x \(10^{-7}\) M.

Kw = 1.0 x \(10^-14\)

[\(OH^-\)] = Kw/[\(H^+\)]

          = 1.0 x \(10^{-7}\) M.

At pH 10.0, [\(H^+\)] = 1.0 x \(10^{-10}\) M

[\(OH^-\)] = 1.0 x\(10^-4\)M

Kw = \(1.0 x 10^{-14 }\)

[\(OH^-\)] = Kw/[\(H^+\)]

         = 1.0 x \(10^{-4}\) M.

At pH 14.0, [\(H^+\)] = 1.0 x\(10^{-14}\) M

[\(OH^-\)] = 1.0 M

Kw = 1.0 x \(10^{-14}\)

[\(OH^-\)] = Kw/[\(H^+\)]

          = 1.0 M.

Ksp = [\(M^{2+}\)]\([OH^-]^2\)\([OH^-]^2\)

7.0 x \(10^{-16 }\)= [\(M^{2+}\)]\([1.0 * 10^{-7}]^2\)

[\(M^{2+}\)] = 7.0 x \(10^{-2}\) M

Kf = \([M(OH)_4]^{2-}\)/\(([M^{2+}][O]^2)\)

0.03 = \([M(OH)_4]^{2-}/([M^{2+}][1.0 x 10^-4]^2)\)

[\(M^{2+}\)] =\(5.8 * 10^{-6 }\)M

Kf =\([M(OH)_4]^{2-}/([M^{2+}][OH^-]^2)\)

\(0.03 = [M(OH)_4]^{2-}/([M(OH)_4]^{2-}x [1.0]^2)\)

\([M(OH)_4]^{2-} = 0.17 M\)

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Therefore, the value of Ka for this solution of monoprotic acid is 3.9 x 10^-5.

The Ka of a monoprotic acid is the acid dissociation constant, which is a measure of its strength. It tells us how much of the acid will dissociate into its conjugate base and hydrogen ions when it is dissolved in water. The expression for Ka is:

Ka = [H+][A-]/[HA]

where [H+] is the concentration of hydrogen ions, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the undissociated acid.

We are given that the acid in question is monoprotic, meaning it can donate only one proton (H+) to the solution. We are also given that the solution has a concentration of 1.04 m, which means that the total concentration of the acid is 1.04 M.

We are also given that 4.66% of the acid is ionized, which means that 4.66% of the acid has dissociated into its conjugate base and hydrogen ions. This also means that 95.34% of the acid remains undissociated.

Let x be the concentration of hydrogen ions and [A-] in the solution, and let 1.04-x be the concentration of undissociated acid. Then we can set up the following equilibrium expression:

Ka = x^2/(1.04-x)

We can solve for x by plugging in the given value of Ka and the known value of the percent ionization:

4.66/100 = x^2/(1.04-x)

Simplifying this equation and solving for x, we get:

x = 0.0633 M

Now we can use this value of x to calculate Ka:

Ka = x^2/(1.04-x) = (0.0633)^2/(1.04-0.0633) = 3.9 x 10^-5

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A battery is a device that converts chemical energy into electrical energy through a process known as an electrochemical reaction.

When a battery is connected to a circuit, the electrochemical reaction causes a flow of electrons from the anode to the cathode, generating an electric current that can power a device.

The metal chosen for the anode must be capable of losing electrons easily, while the metal chosen for the cathode must be capable of accepting electrons. The choice of metals can also affect the voltage and capacity of the battery, as well as its overall efficiency.

In general, the metals used in a battery should have a large difference in their electronegativity values, which determines how easily an atom can attract electrons. Common metals used in batteries include zinc, lithium, nickel, and cadmium.

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Answer:

V2 = 0.98mL

Explanation:

Using Charles' law equation which I as follows:

V1/T1 = V2/T2

Where;

V1 = initial volume (mL)

T1 = initial temperature (K)

V2 = final volume (mL)

T2 = final temperature (K)

Based on the information provided in this question; V1 = 0.80 mL, V2 = ?, T1 = 23°C, T2 = 88°C

Temperature in °C must be converted to Kelvin

T1 (K) = 23°C + 273 = 296K

T2 (K) = 88°C + 273 = 361K

Hence, using V1/T1 = V2/T2

0.80/296 = V2/361

296 × V2 = 0.80 × 361

296V2 = 288.8

V2 = 288.8/296

V2 = 0.9756

V2 = 0.98mL

Answer:

6.39 × 10^23 kg (0.107 M⊕)

Explanation:

To reduce camphor with NaBH4, you can follow these steps:

1. Dissolve the camphor in a suitable solvent such as methanol or ethanol. 2. Prepare a solution of NaBH4 in the same solvent, making sure to handle the reagent with care as it is a strong reducing agent. 3. Slowly add the NaBH4 solution to the camphor solution while stirring continuously. 4. The reaction will proceed quickly, and you should observe the solution becoming cloudy or forming a precipitate. 5. Allow the mixture to stir for a few more minutes to ensure complete reduction of the camphor. 6. After the reaction is complete, you can isolate the product by filtering the mixture and washing it with water or a suitable solvent to remove any impurities.

The reduction of camphor with NaBH4 is a complex chemical reaction that involves several steps and variables, including the choice of solvent, reaction conditions, and the stoichiometry of the reagents. Therefore, it's important to have a good understanding of the chemistry involved and to follow proper safety protocols when working with NaBH4.

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Answer:

Nitrogen is the main component because it comprises 78% of total air while oxygen comprises 21%

\(.\)

Answer:nitrogen

Explanation:

Lattice enthalpy of dissociation of Na₂O is +3739 kJ/mol.

Na₂O dissociates into two Na+ and one O2- ions. Using the Born-Haber cycle and Hess's law, we can calculate the lattice enthalpy of dissociation as the sum of the following steps: Na solid → Na(g) + 108 kJ/mol, 1/2 O2(g) → O(g) + 1st EA = +108 kJ/mol, Na(g) → Na+(g) + e- + 496 kJ/mol, O(g) + e- → O-(g) + 2nd EA = +649 kJ/mol, Na+(g) + O2-(g) → Na2O(s) + Lattice Enthalpy. Solving for Lattice Enthalpy gives +3739 kJ/mol.

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Here is a MATLAB code that calculates and plots the concentration profiles of NH ₃, NH₄+, NO₂-, and NO₃- as a function of time at T=298 K and neutral pH, given the rate constants and initial concentrations:

```matlab

% Rate constants (k) and initial concentrations ([C])

k1 = 0.1;   % Rate constant for NH₃ + H₂O₂ -> NH₂ + H₂O

k2 = 0.05;  % Rate constant for NH₂ + NO₃- -> NO₂- + H₂O

k3 = 0.08;  % Rate constant for NO₂- -> NO₃- + N₂

C_NH₃ = 1.0;    % Initial concentration of NH₃

C_H2₂O₂ = 0.5;   % Initial concentration of H₂O₂

C_NH₄ = 0.0;    % Initial concentration of NH₄+

C_NO₂ = 0.0;    % Initial concentration of NO₂-

C_NO₃ = 0.0;    % Initial concentration of NO₃-

% Time vector

t = 0:0.1:10;   % Time range from 0 to 10 with a step size of 0.1

% Calculation of concentrations at each time point

for i = 1:length(t)

   NH₃(i) = C_NH₃ * exp(-k1*t(i));

   NH₄(i) = C_NH₃ - NH₃(i);

   NO₂(i) = C_NO₂ + k₂ * (NH₄(i) - C_NH₄) * t(i);

   NO₃(i) = C_NO₃ + k₃ * NO₂(i) * t(i);

end

% Plotting concentration profiles

plot(t, NH₃, 'r-', t, NH₄, 'g-', t, NO₂, 'b-', t, NO₃, 'm-');

xlabel('Time');

ylabel('Concentration');

legend('NH₃', 'NH₄+', 'NO₂-', 'NO₃-');

```

The provided MATLAB code calculates and plots the concentration profiles of NH₃, NH₄+, NO₂-, and NO₃- as a function of time based on the given rate constants and initial concentrations. The code uses a time vector to define the time range for which the concentrations will be calculated.

Inside the for loop, the concentrations of NH₃, NH₄+, NO₂-, and NO₃- are calculated at each time point using the given rate constants and the previous concentrations. The concentration of NH₃ decreases exponentially over time due to the reaction NH₃ + H₂O₂ -> NH₂ + H₂O, where k1 is the rate constant. NH₄+ concentration is the difference between the initial NH₃ concentration and the current NH₃ concentration.

The concentration of NO₂- increases with time due to the reaction NH₂ + NO₃- -> NO₂- + H₂O, where k₂ is the rate constant. The change in NH₄+ concentration from its initial value is multiplied by k₂ and the time to calculate the increase in NO₂- concentration.

Finally, the concentration of NO₃- increases with time due to the reaction NO₂- -> NO₃- + N₂, where k₃ is the rate constant. The previous NO₂- concentration is multiplied by k₃ and the time to determine the increase in NO₃- concentration.

The resulting concentration profiles are then plotted using the plot function, with time on the x-axis and concentration on the y-axis. Each compound is represented by a different color line in the plot.

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Methionine is always the first one to be incorporated into a newly made protein followed by identification of the only start codon on mRNA.

Amino acids are transferred by initiator tRNAs to the mRNA strand by the process of translation. Each tRNA has an anticodon, which is a group of three nucleotides that pairs with an appropriate mRNA codon to form a stable bond. The amino acid that the codon specifies is carried by the opposite end of the tRNA. AUG is one codon that serves as a "start" signal to initiate translation (it also specifies the amino acid methionine).

All newly created proteins have methionine as the first amino acid at their N-terminal end, the end of a protein that is synthesised initially, because the initiator tRNA always carries this amino acid (in bacteria, a modified version of methionine called formylmethionine is employed).

Transfer RNAs, or tRNAs, are molecules that read an mRNA's codons sequentially (from the 5' end to the 3' end) during translation.

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The emission spectrum of hydrogen is a series of colored lines that are produced when an electron in a hydrogen atom falls from a higher energy level to a lower energy level.

The spectral lines in the hydrogen emission spectrum correspond to different energy transitions within the atom. The energy of a photon is directly proportional to its frequency, so the emission lines correspond to specific frequencies of light.  The emission spectrum of hydrogen consists of a series of discrete lines, called the Balmer series, which correspond to specific wavelengths of light emitted when electrons in a hydrogen atom transition from higher energy levels to lower ones.

This emission spectrum is related to the energy levels in the hydrogen atom as follows:
1. When an electron in a hydrogen atom absorbs energy, it jumps to a higher energy level, also known as an excited state.
2. The electron then releases the absorbed energy in the form of a photon when it transitions back to a lower energy level. The energy of the emitted photon corresponds to the difference between the two energy levels involved in the transition.
3. The distinct lines in the emission spectrum represent the specific energy differences between these energy levels, and each line corresponds to a unique transition between two energy levels.  In summary, the emission spectrum of hydrogen is a direct result of electrons transitioning between different energy levels in the atom, and the specific wavelengths of light emitted correspond to the energy differences between these levels.

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Answer:

4is the answer

Explanation:

The concentration, in grams of solute per mL solvent) at 20.5 °C is 0.780 g/mL, hence option A is correct.

Divide the solute's mass by the solvent's volume to get the concentration in grammes of solute per millilitre of solvent.

Mass of solute = 0.078 g

Mass of solvent = 0.100 g

Volume of solvent = 0.100 g (since 1 g H₂O = 1 mL H₂O)

Concentration = Mass of solute / Volume of solvent

Concentration = 0.078 g / 0.100 mL

Divide the supplied mass of the solute by the volume of the solvent to obtain the concentration in grams of solute per mL of solvent. Let's figure it out:

Concentration = 0.078 g / 0.100 mL = 0.78 g/mL

Thus, the concentration is 0.78 g/mL.

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Answer:

Comrade, figures, and sad

Explanation

The solution of sugar, salt etc in water.

Sublimation of substances like iodine, camphor etc into the air.

Hydrated salts, mercury in amalgamated zinc,

Alcohol in water, benzene in toluene

(A) R_r represents the rate of change of resistance with respect to the radius of the artery, r. The units of R_r are mmHg/mm. A negative value for R_r indicates that an increase in the radius of the artery will result in a decrease in resistance, meaning it becomes easier for blood to flow through the wider artery.

(b) The derivative is zero because the resistance with respect to the radius does not depend on the length of the artery.

(a) To calculate R_L (L, r), we differentiate the equation with respect to L while keeping r constant:

\(R_L(L, r) = d/dL (kL/r^4) = k/r^4\)

R_L represents the rate of change of resistance with respect to the length of the artery, L. The units of R_L are mmHg/cm. A positive value for R_L indicates that an increase in the length of the artery will result in an increase in resistance, meaning it becomes harder for blood to flow through the longer artery.

To calculate R_r (L, r), we differentiate the equation with respect to r while keeping L constant:

\(R_r(L, r) = d/dr (kL/r^4) = -4kL/r^5\)

R_r represents the rate of change of resistance with respect to the radius of the artery, r. The units of R_r are mmHg/mm. A negative value for R_r indicates that an increase in the radius of the artery will result in a decrease in resistance, meaning it becomes easier for blood to flow through the wider artery.

(b) To calculate R_rr (L, r), we differentiate R_r (L, r) with respect to r while keeping L constant:

\(R_rr(L, r) = d/dr (-4kL/r^5) = 20kL/r^6\)

R_rr represents the rate of change of R_r with respect to r. The units of R_rr are mmHg/mm^2. A positive value for R_rr indicates that as the radius of the artery increases, the rate of decrease in resistance increases. In other words, the wider the artery becomes, the easier it is for blood to flow through.

To calculate R_rL (L, r), we differentiate R_r (L, r) with respect to L while keeping r constant:

\(R_rL(L, r) = d/dL (-4kL/r^5) = 0\)

R_rL represents the rate of change of R_r with respect to L. The units of R_rL are mmHg/(cm·mm). The derivative is zero because the resistance with respect to the radius does not depend on the length of the artery. This implies that changes in the length of the artery do not affect the rate of change of resistance with respect to the radius.

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Based on the equation of the reaction and the limiting reactant of the reaction, molarities of the ions are determined from the amount in moles of excess reactants and soluble products formed.

The limiting reactant is he reavtant that is used up in the reaction after which the reaction stops.

The limiting reactant is obtained from the mole ratio of the reactants in the equation of the reaction.

Equation of reaction is given as follows:

Molar mass of AgNO3 = 170 g/mol

Molar mass of Na3P = 100 g/mol

Molar mass of Ag3P = 355 g/mol

Molar mass of NaNO3 = 85 g/mol

Mass of AgNO3 reacting = 83.4 g

Moles of AgNO3 reacting = 83.4/170 = 0.49 moles

Mass of Na3P reacting = 62.9

Moles of Na3P reacting = 62.9/100 = 0.629 moles

Moles ratio of AgNO3 to Na3P = 3 : 1

Mole rational of AgNO3 and NaNO3 1 : 1

Based on the mole ratio;

At the end of the reaction, molarity of the ions are as follows:

Molarity of Na+ = {0.49 + (3 × 0.46)}/1.71

Molarity of P^{3+} = 0.465/1.71

Molarity of NO3^{-1} = 0.49/1.71

Therefore, molarities of the ions are determined from the amount in moles of excess reactants and soluble products formed.

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The optimum temperature for sucrase activity is 37 °C. The hydrolysis of sucrose is slowest at 0 °C.

The optimum temperature for sucrase activity is 37 °C, which means that the enzyme functions most efficiently at this temperature. As the temperature deviates from the optimum, the enzyme activity decreases. Therefore, the hydrolysis of sucrose would be slowest at a temperature that is significantly lower or higher than 37 °C.

Among the given choices, the temperature that is significantly lower than 37 °C is 0 °C (choice e). Enzyme activity is typically greatly reduced or completely halted at very low temperatures, as the enzyme molecules become less active or may even denature. Therefore, the hydrolysis of sucrose would be slowest at 0 °C.

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