Which of the following will not be deflected by charged plates?
O Cathode rays
O Alpha particles
O Protons
O Hydrogen

Answer:

Please did you ever get an answer??

Explanation:

Im doing usa test prep too and its really late

Answer:

1. determining the pOH of the solution from the given pH of 10.00 assuming the solution is at 25° C.

The ideal gas law, which relates the pressure, volume, temperature, and number of moles of an ideal gas, can be applied to real-world situations. By considering a specific scenario and applying the ideal gas law, we can analyze the behavior of gases and make predictions about their properties.

Let's consider a situation where a scuba diver is exploring underwater at a depth of 30 meters. We can apply the ideal gas law, specifically the form known as Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Question: How does the pressure of the gas in the scuba tank change as the diver descends to a depth of 30 meters, assuming the temperature remains constant?

To answer this question, we can use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. By keeping the temperature constant, we can observe the relationship between pressure and volume as the diver descends and calculate the change in pressure based on the change in volume.

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Answer:

Explanation:

The ozone layer acts as a shield for life on Earth. Ozone is good at trapping a type of radiation called ultraviolet radiation, or UV light, which can penetrate organisms' protective layers, like skin, damaging DNA molecules in plants and animals.

for centuries scholars have argued over how to explicate  certain cryptic passages in Milton’s plays and poems.

Cryptic Passage (originally titled as Passage to Transylvania) is described as  the first expansion pack for Blood developed by Sunstorm Interactive and released in June 30, 1997.

The first of Blood's two expansion packs is called Cryptic Passage.

The expansion, unlike the Plasma Pak, was created by a third party, Sunstorm Interactive, and it was released by WizardWorks Software; as a result, it doesn't have any bug patches or new features.

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Answer:

left

Explanation:

8 has the strongest force

During each step of the electron transport system, electrons move to a more electronegative carrier, and thus move closer to a more stable state of energy.

Electrons are transferred to more electronegative carrier molecules during the electron transport chain (ETC) of cellular respiration. This creates an electron gradient across the membrane that can be used to produce ATP energy molecules. In the mitochondria of eukaryotic cells, the electron transport chain takes place. The electron transport chain includes several carriers of electrons that are membrane-bound.

NADH and FADH2 transfer electrons and hydrogen ions to the electron transport chain carriers during cellular respiration. These electrons then pass from one carrier molecule to the next, which allows the carriers to pump protons from the mitochondrial matrix to the intermembrane space. This sets up an electrochemical gradient that leads to the creation of ATP by the enzyme ATP synthase.

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Answer:

16.8dm3

Explanation:

2 moles of CO gives 1 mole of N2

2 moles of CO= 2* 28= 56g

1 mole of N2 = 1* 22.4dm

56g of CO gives 22.4dm3 of N2

42.7 of CO will give> (42.7*22.4)/56

=16.8dm3

The volume of \(N_{2}\) gas will be produced 16.8 \(dm^{3}\).

Volume is sometimes referred to as capacity. The volume of a cylindrical jar, for example, is used to determine how much water it can hold.

Calculation of volume is shown below:

The given reaction is: 2CO(g) + 2NO) → N2(g) + 2CO2(g)

It can be seen that 2 moles of CO give 1 mole of \(N_{2}\).

So, 2 moles of CO = 2×28 = 56 g.

Hence, 1 mole of \(N_{2}\) = 1×22.4 = 22.4 \(dm^{3}\).

56 g of CO will give 22.4 \(dm^{3}\) of nitrogen atom.

42.7 of CO will give = (42.7×22.4) / 56

= 16.8 \(dm^{3}\).

Therefore, the volume of nitrogen will be 16.8 \(dm^{3}\).

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Answer:

5 million million atoms can fit at the end of a needle

Answer:

Let's just say 5 million million hydrogen atoms could fit at the end of a needle.

Explanation:

Atoms are 100 picometers, and to compare, the amount of even 1 centimeter, a calculator can't even figure out how many picometers are in a centimeter because there is just too much picometers.

Lithium, as a stronger ion-dipole interaction results from a smaller atomic radius.

The number of miles from a nuclear charge to its outermost electron orbital is typically defined as the atomic radius. Only by determining the separation seen between nuclei of two contacting molecules and halving a certain distance can one determine the dimension of an atom.

The type of chemical bond that the atoms are engaged in determines the value of their atomic radii (metallic, ionic, or covalent bond). A portion of the observable distance separating atoms is attributed to one type of atom and the remainder to another type when the neighboring atoms are not identical, as in sodium chloride.

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Answer:

Genetic modification or GMOs can change foods. It's typically used to preserve foods, enlargen foods or create seedless grapes

Explanation:

Two Cl-atoms form a sigma bond with sp3 hybrid orbitals. Thus, SCl2 has sp3 hybridization.

The Lewis structure shows us that the carbon atom makes 4 sigma bonds to hydrogen and has no non-bonding electron pairs. The central carbon atom combines its 2s, 2px, 2py, and 2pz valence orbitals to make four, 2sp3 hybrid orbitals. Each one of these combines with a 1s atomic orbital from a hydrogen atom.

What is hybridization of SCl2?

In its most stable state, Sulfur acts as the central atom and forms two covalent bonds with the Chlorine atoms. It also possesses two lone pairs. Due to the presence of 4 electron domains and its steric number being 4, the hybridization of SCl2 is given by sp3.

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Answer:

28.00 g is the answer

Answer:200

Explanation:

It’s is the answer

Answer:

pre lab information would be the thing you to ressearch the lab to get the information

Limiting Reactant and Percent Yield Lab Report attached

Temporary and permanent hardness of water Temporary hardness of water is caused by the presence of bicarbonate, carbonate, and sulfate ions, while permanent hardness is caused by the presence of chlorides, sulfates, and nitrates.

Carbonate and bicarbonate hardness can be removed using a process called boiling. Permanent hardness, on the other hand, can be removed using a process called ion exchange.ii. Organic, ortho, and polyphosphorus in wastewaterOrganic phosphorus is present in wastewater in the form of organic molecules like DNA, RNA, and phospholipids. Orthophosphate is the most common form of phosphorus found in wastewater. Polyphosphates, which are a chain of orthophosphate molecules, can also be found in wastewater.iii. Self-cleansing and scouring velocity in sewersSelf-cleansing velocity is the minimum velocity of wastewater flow required to prevent the deposition of solids in the sewer. Scouring velocity, on the other hand, is the minimum velocity required to remove previously deposited solids. Scouring velocity is higher than self-cleansing velocity.

Type 1 and Type 2 settling in water/wastewater treatment  Type 1 settling occurs when particles of different sizes and densities settle separately, forming distinct layers. In type 2 settling, particles of different sizes and densities settle together in a mixed floc. Type 1 settling is more effective at removing larger particles, while type 2 settling is better at removing smaller particles.v. Chloramines and disinfection by-products (DBPs)Chloramines are a combination of chlorine and ammonia that are used as a disinfectant in water treatment. Disinfection by-products (DBPs) are formed when chlorine reacts with organic matter in the water. Some common DBPs include trihalomethanes (THMs) and haloacetic acids (HAAs), which are known to be carcinogenic.

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Answer:

5 meter/second.

Explanation:

You dived the seconds, 10, by the meters, 50.

There are 48.72 g  Fluorine ions

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison

%F in CaF₂ :

\(\tt \%F=\dfrac{2.Ar~F}{MW~CaF_2}\times 100\%\\\\\%F=\dfrac{2.19}{78}\times 100\5=48.72\%\)

mass of Fluorine :

\(\tt 48.72\%\times 200=97.44~g\)

So mass Fluorine ions(2 ions F in CaF₂⇒Ca²⁺+2F⁻) :

\(\tt =\dfrac{97.44}{2}=48.72~g\)

Answer:

See below

Explanation:

First determine the mass (weigh it) .....    then place it in a graduated container of water to see the volume of the object (by the amount of water it displaces)

  then  density  = mass / volume  

Answer:

0.600

Explanation:

2.120/3.670 = 0.578 so 790*0.578 = 456.349 when converted to atm that is 456.349/760 = V2

0.600

If a gas has a volume of 3.67 L and a pressure of 790 mm Hg, the pressure if the volume is compressed to 2.12 L is 1367 mm Hg.

The combined gas law is the law of of gaseous state which is made by combination of Boyle's law, Charle's law, Avogadro's law and Gay Lussac's law.

It is a mathematical expression that relates Pressure, Volume and Temperature.

(P1 × V1)÷T1 = (P2 × V2)÷T2

Boyle's law states that if temperature is constant then product of pressure and volume is constant.

(P1 × V1)= (P2 × V2)

Given,

P1 = 790 mm Hg

V1 = 3.67L

P2 = ?

V2 = 2.12 L

(P1 × V1)= (P2 × V2)

P2 = 1367 mm Hg

Therefore, If a gas has a volume of 3.67 L and a pressure of 790 mm Hg, the pressure if the volume is compressed to 2.12 L is 1367 mm Hg.

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Answer:

0.0220 g (22 mg) of NO2.

Explanation:

To solve this type of problem, it is best to work with grams. Remember that 1 kg equals 1000 g and 1 g equals 1000 mg. The conversion for 5.26 kg of nitrogen monoxide (NO) would be:

And for 7.64 mg of oxygen (O2) is:

The next step is to find the number of moles of each reactant using its molar mass. The molar mass of NO is 30 g/mol (you can calculate the molar mass of a compound using the periodic table):

And the moles of oxygen (O2) is 32 g/mol:

The next step is to see how many moles of NO" can be produced for each reactant.

You can see in the chemical equation that 2 moles of NO produce 2 moles of NO2, so the molar ratio between them is 1:1. This means that 175.33 moles of NO reacted produce 175.33 moles of NO2.

Now, you can see that 1 mol of O2 reacted produces 2 moles of NO2, so let's see how many moles of NO2 are being produced:

You can note that the limiting reactant, in this case, is oxygen (O2) because this reactant imposes the "limit" to produce the product.

The final step is to convert from 4.776 x 10^(-4) moles of NO2 to grams using its molar mass which is 46 g/mol. The conversion will look like this:

We obtain 0.0220 g (22 mg) of NO2 from 5.26 kg of NO and 7.64 mg of O2.

The average soil resistivity near the substation is approximately 5.612 Ω·m.

To calculate the average soil resistivity near the substation, we can use the Wenner four poles equal method and the given soil resistance readings.

The formula for calculating soil resistivity using the Wenner method is:

ρ = (π * spacing * sum of resistance) / (2 * π * probe length)

Where:

ρ = Soil Resistivity

spacing = Distance between the current electrodes (m)

sum of resistance = Sum of the measured soil resistance values (Ω)

probe length = Length of the probe (m)

In this case, the probe distance intervals are 1, 2, 3, 4, and 5 m, and the corresponding soil resistance values are 16.4, 5.29, 3.05, 1.96, and 1.36 Ω, respectively.

Let's calculate the average soil resistivity:

spacing = 1 m (since the distance between the current electrodes is not mentioned, we assume it to be 1 m)

sum of resistance = 16.4 + 5.29 + 3.05 + 1.96 + 1.36 = 28.06 Ω

probe length = 5 m (as given in the intervals)

Using the formula, we have:

ρ = (π * spacing * sum of resistance) / (2 * π * probe length)

= (π * 1 * 28.06) / (2 * π * 5)

= 5.612 Ω·m

Therefore, the average soil resistivity near the substation is approximately 5.612 Ω·m.

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Answer:

it would decrease  /  increase with the mass

Explanation:

Explanation:

Chemical fertilizers raise crop yields, but their heavy usage has hardened the soil, diminished fertility, reinforced pesticides, contaminated air and water, and emitted greenhouse gases, posing health and environmental risks.

When we do the respective division operation we get the following result 0.171802.

When we do the respective division operation we get the following result 0.171802. But we must adjust the significant figures taking into account the number that has less significant figures, which is 5.68.

5.68 has three significant figures. So we will adjust the significant figures of the result to three.

0.97584 / 5.8 = 0.1718 = 0.172

Answer:

Regional metamorphism occurs at convergent plate boundaries, due to intense pressure. As two plates collide, the Earth's crust folds and faults. The intense pressure changes large areas of the Earth's crust into metamorphic rock. Mountain ranges are typically metamorphic rock, due to plate tectonic processes.

Explanation:

Hope this helps :D

Tectonic plate movement is responsible for forming regional metamorphic rock.

The tectonic plate movement involves the subsurface movement of formation caused by natural force of earth.  These movement can be uplifting, faulting or folding.

There are three main types of tectonic plate movement.

There are mainly three types of rock.

Thus, tectonic plate movement is responsible for forming regional metamorphic rock.

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Your question is incomplete but most probably your full question was

Tectonic plate movement is responsible for forming which type of rock? Choose all that apply

A. Igneous rock

B. Metamorphic rock

C. Sedimentary rock

D. None of the above

The balanced chemical equation for the combustion of gaseous methanol (CH₃OH) is: 2CH₃OH(g) + 3O₂(g) → 2CO₂(g) + 4H₂O(g)

The balanced chemical equation represents the combustion of gaseous methanol (CH₃OH) in the presence of oxygen (O₂). The coefficients in front of the chemical formulas indicate the relative number of molecules or moles involved in the reaction, ensuring that the equation is balanced in terms of mass and charge.

In the combustion reaction, two molecules of gaseous methanol combine with three molecules of oxygen gas. Through the combustion process, the methanol is oxidized, and carbon dioxide (CO₂) and water (H₂O) are produced as the main products.

The balanced equation shows that two molecules of methanol react with three molecules of oxygen to yield two molecules of carbon dioxide and four molecules of water.

This balanced equation represents the stoichiometry of the combustion reaction, ensuring that the number of atoms of each element is the same on both sides of the equation.

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The solubility product constant expression for AgI is:

AgI(s) ⇌ Ag⁺(aq) + I⁻(aq)

The Ksp expression for AgI is given as 1.47 x 10⁻¹⁶.

Since AgI dissociates into 1 Ag⁺ ion and 1 I⁻ ion, the molar solubility (s) of AgI is equal to the concentration of Ag⁺ and I⁻ ions in the solution.

Let's assume the molar solubility of AgI is s M.

Since the molar solubility (s) of AgI is equal to the concentration of Ag⁺ and I⁻ ions, we have:

[Ag⁺] = s M

[I⁻] = s M

Using the stoichiometry of the balanced equation, the expression for the solubility product constant is:

Ksp = [Ag⁺][I⁻] = s^2

Substituting the given Ksp value, we have:

1.47 x 10⁻¹⁶ = (s)^2

Taking the square root of both sides, we get:

s = √(1.47 x 10⁻¹⁶)

Calculating the square root, we find:

s ≈ 3.83 x 10⁻⁹ M

Since the solubility is given in grams per milliliter (g/mL), we need to convert the molar solubility to grams per milliliter using the molar mass of AgI.

The molar mass of AgI is:

Ag: 107.87 g/mol

I: 126.90 g/mol

AgI: 107.87 g/mol + 126.90 g/mol = 234.77 g/mol

To convert the molar solubility (s) to grams per milliliter (g/mL):

s (g/mL) = (molar solubility (M) * molar mass of AgI (g/mol)) / 1000

Substituting the values, we have:

s (g/mL) = (3.83 x 10⁻⁹ M * 234.77 g/mol) / 1000

Calculating the value, we find:

s (g/mL) ≈ 9.0 x 10⁻¹² g/mL

Therefore, the solubility of silver iodide (AgI) in grams per milliliter (g/mL) at the given temperature is approximately 9.0 x 10⁻¹² g/mL.

The solubility of silver iodide (AgI) in grams per milliliter can be calculated using the concept of solubility product constant (Kₛₚ). Given that the Kₛₚ of AgI is 1.47 x 10⁻¹⁶.

The solubility product constant (Kₛₚ) is a measure of the equilibrium between a solid and its dissolved ions in a saturated solution. For silver iodide (AgI), the equilibrium equation can be expressed as:

AgI(s) ⇌ Ag⁺(aq) + I⁻(aq)

The Kₛₚ expression for this equilibrium is:

Kₛₚ = [Ag⁺][I⁻]

Given the Kₛₚ value of AgI as 1.47 x 10⁻¹⁶, it indicates that the product of the concentrations of Ag⁺ and I⁻ ions in the saturated solution is equal to 1.47 x 10⁻¹⁶.

To determine the solubility of AgI in grams per milliliter, we need to know the molar mass of AgI and the volume of the saturated solution. The molar mass of AgI is 234.77 g/mol, which is the sum of the atomic masses of silver (Ag) and iodine (I).

To convert the concentration of Ag⁺ or I⁻ ions to grams per milliliter, we need to divide the concentration (in moles per liter) by the molar mass (in grams per mole) and multiply by the solution volume (in milliliters).

However, without the given volume of the saturated solution, it is not possible to calculate the solubility in grams per milliliter directly using the Kₛₚ value. The solubility information typically depends on both temperature and the presence of other ions or substances in the solution. Therefore, additional data or an experimental approach would be needed to determine the solubility of AgI in grams per milliliter at the given temperature.

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In a simple distillation setup, the sequence of equipment from the bench top to the round bottom flask is:

This is the process in which a mixture is separated through selective boiling and condensation.

The distillation flask and liebig condenser are usually located above the round bottom flask in the set up.

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Answer:

The removal of this ion from water by the calcifiers will definitely decrease the pH of water.

What is the bicarbonate ion?

The bicarbonate ion is the ion that is designated as HCO3-. We must notice that this ion is present in abundant amounts in the sea. This amount definitely make the sea slightly alkaline.

Now we must note that the removal of this ion from water by the calcifiers that require it to make their shell will definitely decrease the pH of water.

Explanation:

The removal of this ion from water by the calcifiers will definitely decrease the pH of water.

The bicarbonate ion is the ion that is designated as \(HCO^{3-}.\) We must notice that this ion is present in abundant amounts in the sea. This amount definitely makes the sea slightly alkaline.

Now we must note that the removal of this ion from water by the calcifiers that require it to make their shell will definitely decrease the pH of water.

Hence, the removal of this ion from water by the calcifiers will definitely decrease the pH of water.

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Answer:

Dipole dipole interaction

Explanation: