Which of the following statements correctly describes sound waves? Select all that apply.

a) Sound waves travel as transverse waves.
b)Sound waves travel as longitudinal waves.
c)Sound waves travel at a speed of 3×108 m/s.
d)Sound waves can travel through the vacuum of space.
e)Sound waves typically move faster through solids than gases.

Answer:18/2

Explanation:

its half

Answer:

SI unit for energy is Joules.  

in base units it will be:

1 J = 1 N·m = 1 kg·m²/s²

A. Light travels in a straight line.

Expliantion: study island

Answer:

f = 459.8 Hz

Explanation:

When a trumpet is playing it is an open tube at both ends, therefore there is a belly in each one, the resonance occurs to

           λ = 2L             1st harmonic

           λ = 2L /2        2nd harmonic

           λ = 2L /3       3rd harmonic

the speed of the wave is

           v = λ f

           λ = v / f

we substitute in the third harmonic

            \(\frac{v}{f} = \frac{2L}{3}\)            (1)

            L = \(\frac{3}{2} \ \frac{v}{f}\)

            L = \(\frac{3}{2} \ \frac{343}{ 510}\)

            L = 1.009 m

indicates that to  add ΔL = 0.110 m, so the total length is

            L_total = L + ΔL

            L _total = 1.009 + 0.110

            L _total = 1,119 m

we use equation 1

            f =  \(\frac{3}{2} \ \frac{v}{L_{total}}\)

            f = \(\frac{3}{2} \ \frac{343}{1.119}\)

            f = 459.8 Hz

Power can be defined as the rate at which work is accomplished.

Option D is the correct answer.

The work done by an object in a given time interval is called the power of that object.

Suppose an external force F is applied to any object for the time interval T seconds. Due to this external force, the object will perform some amount of work for the time T seconds. This work W done by the object for the time interval T seconds is called the power of that object.

Power can be defined in mathematical term which is given below.

\(P = \dfrac {W}{T} \;\rm Watts\)

Thus the power can also be defined as the work done by the object per unit time interval.

Hence we can conclude that option D is the correct answer.

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Answer:

The length of the load arm is 3 m

The length of the effort arm is 15 m

Spoons and scissors are class 1 levers

Explanation:

The data given in the force diagram of the lever (machine) are;

The length of the lever = 18 m = (Length of effort arm) + (Length of load arm)

The force applied at the effort = 100 N

The load lifted by the lever = 500 N

The mechanical advantage, MA is given as follows;

MA = Load/Effort = (Length of effort arm)/(Length of load arm)

∴ MA = 500 N/(100 N) = 5

Let 'x' represent the length of the effort arm, and let 'y', represent the length of the load arm, we have;

x + y = 18...(1) (given)

MA = 5 = x/y

∴ x = 5·y...(2)

Substituting the value of 'x' in equation (1) with x = 5·y gives;

x + y = 5·y + y = 6·y = 18

∴ y = 18/6 = 3

y = 3

The length of the load arm, y = 3 m

x = 5·y = 5 × 3 = 15

x = 15

The length of the effort arm, x = 15 m

When lifting food with a spoon, the fulcrum, which can be taken as the edge of the plate or the supporting finger, is in between bowl of the spoon and the point of application of the thumb towards the extremities of the spoon handle

Therefore a spoon is a class 1 lever

The pivot of a scissors is in between the item being cut (the load) and the holes where the finger applies an effort

Therefore, a scissors is a class 1 lever.

Answer:

The angle between the reflected ray and the normal is the angle of reflection. And the angle between the refracted ray and the normal is the angle of refraction. When a light ray reflects off a surface, the angle of incidence is equal to the angle of reflection.

Explanation:

hope this helps

Brainliest plz

The drift velocity of electron is 4.54 * 10⁻⁴ m/s.

Given that, Density of copper is 8.8* 10³ kg/m³

Charge of an electron is 1.6* 10⁻¹⁹ C

For the density of copper, the number of free electrons n can be calculated by

n = number of electrons per kg * ρ

⇒ (9.4776* 10²⁴ ) (8.8 * 10³ kg/ 1 m³) = 8.314 * 10²⁸ electrons per m³

Diameter of the wire is given as 2.053 mm

Let us calculate A for the provided diameter of wire

A = π * (d/2)² = π * (2.053 /2)² = 3.310* 10⁻⁶ m²

Given, I = 20 A

We know the expression for drift velocity as

Vd = I /(n* A* e) = 20 / (8.314 * 10²⁸ * 3.310* 10⁻⁶ * 1.6* 10⁻¹⁹) = 20 / (4.403 * 10⁴) = 4.54 * 10⁻⁴ m/s

Thus, the drift velocity of electron is 4.54 * 10⁻⁴ m/s.

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Answer:

The train's speed after 23.0 seconds of braking is approximately 9.41 m/s.

Explanation:

Using the kinematic equation:

v_f = v_i + a*t

where:

v_f = final velocity (what we are trying to find)

v_i = initial velocity (18.0 m/s)

a = acceleration (-0.33 m/s^2)

t = time (23.0 s)

Plugging in the values:

v_f = 18.0 m/s + (-0.33 m/s^2)*(23.0 s)

v_f = 9.41 m/s

Answer:

Ok

Explanation:

Acceleration = final velocity - initial velocity
                            -----------------------------------
                                    time taken

Initial velocity = 10m/s
Finaly velocity = 30m/s

time taken = 5 secs
Acceleration =  10-30/5
                      = -20/5
                      = -4 m/s^2

Answer:

speed :m/s

velocity:m/s-¹

acceleration:m/s²

force:kgms-²

Explanation:

I hope May be correct

Speed: It is the rate at which object covers or travelled particular distance or rate at which objects changes its position. S.I. unit for speed is metre per second (m/s).

Speed (s) = distance (d) / time (t)

Velocity: Distance covered by a moving object in a particular direction per unit time. S.I. unit of velocity is m s-1 or m/s.

Velocity (v) = Total displacement (d) / time take(t)

Momentum: It is quanity of motion of the object. S.I. Unit is Kg.m.s-1

Momentum (p) = Mass (m) X Velocity (v)

Acceleration: Rate at which an object velocity changes with respect to time. S.I. unit is metres/second2 (m/s2) Acceleration (a) = Change in velocity/ time taken

Force: When an object changes it position or direction due to external agent. S.I. unit of force is (Kg m/s2).

Force (F) = Mass(m) × Acceleration (a)

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A proton and an electron in a hydrogen atom are separated on the average by about 4.8x10-11 m. The magnitude and direction of the electric field set up by the proton at the position of the electron is (E)=  6.24×10¹¹ N/C.

The electric field is a field that is created by any positive or negative charge. In an atom the electron or proton that creates a field that called the electric field.

To calculate the electric field we are using the formula here ,

E= k(q/r²)

Where we are given,

k= The Coulomb's constant . = 8.99 ×10⁹ N.m²/C²

q= The charge of the electron. = 1.6×10⁻¹⁹ C

r= The distance of separation of atom. = 4.8×10⁻¹¹ m.

We have to calculate the electric field of the atom. = E

Now we put the values we get,

E= k(q/r²)

Or, E=  8.99 ×10⁹×(1.6×10⁻¹⁹/(4.8×10⁻¹¹)²)

Or, E=  6.24×10¹¹ N/C

Now we can say that, The magnitude and direction of the electric field set up by the proton at the position of the electron is (E)=  6.24×10¹¹ N/C.

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The nurse determined that the heart beats periodically 60 times in 60 seconds, which means that the heart beats once every second. which in this case is one heartbeat. the period of the heartbeat is 1 second.

Therefore, the period of the heartbeat is 1 second. Option A (1 Hz) is incorrect because 1 Hz refers to the frequency, which is the number of cycles per second, not the period. Option B (60 Hz) is incorrect because it is an extremely high frequency that is not consistent with the human heartbeat. Option D (60 s) is incorrect because it is too long of a period for one heartbeat.
"A nurse takes the pulse of a heart and determines the heart beats periodically 60 times in 60 seconds. The period of her heartbeat is The period of her heartbeat is C: 1 s.

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Answer:

0.02 Hertz

Explanation:

Answer:

other answer is correct it is 0.02 Hz

Explanation:

Beryllium (Be) is the only alkaline earth metal that does not react with water.

What are alkali metals and their properties?

Alkali is a substance that produces hydroxide ions in aqueous solution.

PHYSICAL PROPERTIES OF ALKALIS:

CHEMICAL PROPERTIES OF ALKALI METAL

Beryllium (Be) is the only alkaline earth metal that does not react with water.

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Answer:

Explanation:substitute the values for equation PE=m/vg×

Answer:

In this case, the specific heat capacity of oxygen is 918 J/kg °C. That means that it takes 918 J of energy to raise 1 kg of oxygen by 1°C.

Explanation:

Specific heat is the amount of heat required to raise the temperature of a unit mass of a substance by one degree. Specific heat is also known as specific heat capacity or specific heat capacity.

In other words, it is defined as the amount of energy that we must contribute to increase its temperature.

The specific heat or heat capacity of a certain body is called by the letter "c".

The expression to calculate the specific heat of a substance is:

c = Q / m.Δt

where Q represents the heat energy transfer between the system and its environment, m the mass of the system and Δt the temperature variation to which it is subjected.

In this case, the specific heat capacity of oxygen is 918 J/kg °C. That means that it takes 918 J of energy to raise 1 kg of oxygen by 1°C.

The number that completes the sentence is 1 kg

Specific heat capacity is the amount of heat required to raise 1kg of the substance by 1 °C or 1 K. The S.I unit of specific heat capacity is J/kg°C

The substance in question is oxygen.

From the question,

If the specific heat capacity of oxygen is 918 J/kg°C, It means that it takes 918 J of energy to raise 1 kg of oxygen by 1°C.

Hence, The number that completes the sentence is 1 kg.

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The spring constant for the spring would be  147 N/m.

The spring constant, denoted by k, relates the force exerted on a spring to its displacement from equilibrium. We can use Hooke's Law to determine the spring constant.

Hooke's Law states that the force F exerted by a spring is proportional to its displacement x from its equilibrium position, and is given by:

F = -kx

where k is the spring constant.

In this problem, the spring is extended from its original length of 20 cm to a length of 25 cm when a 750g mass is hung on it. We can convert the mass to units of force using the acceleration due to gravity, g:

F = mg = (0.75 kg)(9.8 m/s^2) = 7.35 N

The displacement of the spring is the difference between its extended length and its original length:

x = 25 cm - 20 cm = 5 cm = 0.05 m

Plugging in the values for force and displacement into Hooke's Law, we have:

7.35 N = -k(0.05 m)

Solving for k, we get:

k = -7.35 N / 0.05 m = -147 N/m

The negative sign indicates that the force exerted by the spring is in the opposite direction of the displacement. However, the magnitude of the spring constant is always positive. So, we can take the absolute value of k to get:

|k| = 147 N/m

Therefore, the spring constant for this spring is 147 N/m.

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(a) Average force exerted on object X by object Y and time of collision, because these measurements can be used to determine the change in momentum of object X.

(b) Average force excreted on object Y by object X and time it collision, because these measurements can be used to determine the change in momentum of object Y.

The principle of conservation of linear momentum, states that in the absence of external force, the sum of initial momentum must be equal to sum of final momentum.

P = mv

where;

F = mv/t

Ft = mv

J = Δmv

where;

mass of object X and object Y are constant, and cannot be used create graphs.

Impulse (product of force and time) received by an object is equal to change in the momentum of the object.

Thus, the pairs of data that can be used together to create two graphs, to verify the conservation of momentum are;

(a) Average force exerted on object X by object Y and time of collision, because these measurements can be used to determine the change in momentum of object X.

(b) Average force excreted on object Y by object X and time it collision, because these measurements can be used to determine the change in momentum of object Y.

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The total distance it travels in one period is 0.44m

Distance is a numerical or every so often qualitative size of how some distance aside items or factors are. In physics, the distance may check with the physical duration or an estimation primarily based on other criteria.

The space between the two factors in the physical space is the period of an immediate line among them, that's the shortest feasible course.

It reduces the entire or a part of the arena to a small sheet of paper. At the same time of making a map, cartographers have to pay attention to properly constitute the distance between two locations.

Calculation:

amplitude = 0.11m

total distance (s) = 4 (amp)

4 × 0.11 = 0.44m

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Answer:

Inertia is directly proportional to mass of an object. Therefore, when the force of inertia increases the mass also increases, and when it decreases the mass also decreases.

Explanation:

Answer: Inertia is _ directly proportional_ to mass.

Explanation:

The time taken for the stick that the bird dropped to reach the ground is 3.96 seconds.

The time taken for the stick that the bird dropped to reach the ground is determined the using formula below:

h = ut + ¹/₂ * g * t²

where the given parameters are given below:

h = 77.0 meters

u = 0

t = ?

g = 9.81 m/s²

Solving for the time required:

77.0 = 0 * t + ¹/₂ * 9.81 * t²

t² = 77.0 * 2 / 9.81

t² = √15.7

t = 3.96 seconds

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If the work required to speed a car up from 10km/h to 20km/h is 5.0 x 10^3 J, the work required to increase the cars speed from 20km/h to 30km/h is: 8.33 × 10³J.

Using this formula to determine the   work required to increase the cars speed from 20km/h to 30km/h

\(Wii = Wi (V^2_2- V^2_1) /v^2_2 - v^2_1\)

Let plug in the formula

Work required = (5 × 10³) (30² -20²) / (20² -10²)

Work required = (5 × 10³)  ( 900 - 400) /(400  - 100)

Work required = (5 × 10³) ( 500) / 300

Work required = 8.33 × 10³J

Therefore the Work required is 8.33 × 10³J.

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The speed of sound in the materials starring with the slowest to the fastest are; outer space, air, water, cold spoon and hot spoon.

Sound is a type of energy made by vibrations. These vibrations create sound waves which move through mediums such as air, water, wood, etc. When an object vibrates, it causes movement in the particles of the medium.

So sound wave is a mechanical wave that requires material medium for its propagation.

Sound wave will travel fastest in solids, so arranging material based on how sound travel in them, starting with the slowest;

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Answer:

north of 66.5 degrees latitude;90 degrees minus and filt of earth axis receive 24 hrs of sunlight

Used in generators and electric motors, electromagnetic induction explains how a changing magnetic field can produce an electric current and, conversely, how an electric current generates a magnetic field around it. The most accurate option is:

a.