For the reaction:
H₂O(1)→ H₂O(g)
ΔΗ = 44 kJ
How much heat is required when 9.0 g of H₂O is used?
1mol H_2O requires 44kJ heat
Moles of water
Given mass/Molar mass9/181/20.5molHeat required
0.5(44)22kJAs per the reaction given
Moles of H_2O=1
∆H=44kJMoles of water in 9g
Given mass/Molar mass9g/18g/mol0.5mol∆H
44(0.5)22KJHow does a Physical reaction affect a substance? (How does the substance change?)
Answer: the particles of which it is composed and the numbers of particles remain unchanged
or Physical changes result only in a change in the form (i.e., solid, liquid, gas) or appearance of a substance, but not the chemical composition of the substance.
A crop is sprayed with a pesticide to prevent infestation and damage from insects. However, the next season the same pesticide fails to prevent the insects from damaging the crop. Why
Answer:
Farmers spray to mitigate crop damage caused by pests. A pest is any biological organism, including weeds, pathogens, and arthropods, that interferes with the production of crops affecting quality and/or yield. ... Pesticides work in many different ways by affecting their target, whether it be a weed, pest, or disease.
Explanation:
this is my answer❤︎
Calculate [OH - ] given [H 3 O + ] = 5.69x10 -5 M.
Answer:
7
Explanation:
for the following solution, choose the formula of a chemical that you could add to the solution to make a buffer: 0.1 m hc2h2o2cl (chloroacetic acid). nac2h3o2 nac3h2o2cl nac2h3o2cl nac2h2o2cl
We require the conjugate base of an acid if we have one, and vice versa. If the required species is an ion. NaC2H2O2F is one alternative for the fluoroacetate ion, C2H2O2F-, which we need as a soluble molecule.
What are solutions for buffers?The solution can act as a buffer because it contains sizable amounts of both the conjugate base, F-, and the conjugate acid, HF. The titration curve of a buffer solution shows this buffering activity.
What is a buffer, exactly?The solution of reserve acidity or alkalinity that resists pH change upon the addition of a modest amount of acid or alkali is known as a buffer. A steady pH is necessary for the majority of chemical processes. Numerous pH regulating systems in nature employ buffering.
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1. Billy Beaker is reacting 7.98 mL of 2.50 M HCl with excess NaOH. How many grams of water will be produced by this neutralization reaction?
2. Emily Erlenmeyer is reacting 2.43 mL of 2.50 M H2SO4 with 2.51 mL of 3.00 M NaOH. How many grams of water will be produced by this neutralization reaction?
Use molarity and stoichiometry
1. The amount of water produced by the reaction is 0.359 g.
2. The amount of water produced by the reaction is 0.219 g.
How do you calculate the number of moles neutralized in a titration?To calculate the number of moles of acid neutralized by the tablet, subtract the number of moles of acid neutralized in the titration from the initial solution's moles of acid. Understand and explain standardization in the context of acidic and basic solutions used as reagents in experiments.
1. The neutralization reaction,
HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)
we have to calculate the number of moles of HCl that react,
moles of HCl = volume of HCl x concentration of HCl
= 7.98 mL x 2.50 mol/L / 1000 mL/L
= 0.01995 mol
Since NaOH is in excess,
As a result, the amount of water produced will be equal to the amount of HCl that reacts:
moles of water = moles of HCl = 0.01995 mol
we can use the molar mass of water (18.015 g/mol)
mass of water = moles of water x molar mass of water
= 0.01995 mol x 18.015 g/mol
= 0.359 g
2. The neutralization reaction between H2SO4 and NaOH is:
H2SO4 (aq) + 2 NaOH (aq) → Na2SO4 (aq) + 2 H2O (l)
we have to calculate the number of moles of H2SO4 that react,
moles of H2SO4 = volume of H2SO4 x concentration of H2SO4
= 2.43 mL x 2.50 mol/L / 1000 mL/L
= 0.00608 mol
Now, we have to calculate the number of moles of NaOH that react:
moles of NaOH = volume of NaOH x concentration of NaOH
= 2.51 mL x 3.00 mol/L / 1000 mL/L
= 0.00753 mol
we need to use the stoichiometry of the balanced equation,
moles of water = moles of H2SO4 x (2 moles of water / 1 mole of H2SO4)
= 0.00608 mol x 2
= 0.01216 mol
we can use the molar mass of water (18.015 g/mol)
mass of water = moles of water x molar mass of water
= 0.01216 mol x 18.015 g/mol
= 0.219 g
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Scenario: You are an employee of the Dupont Chemical Industry working with a team off 3-4 chemists. The laboratory division for which you work for focuses on the synthesis of ammonia (NH3) from hydrogen and nitrogen. (This reaction is commonly referred to as the Haber Process) Your supervisor has informed your group that he needs you to produce at least 125 grams of ammonia by the end of the day or else your division will be shut down. When checking your supplies you realize that you have exactly 100 grams of nitrogen and 30 grams of hydrogen gas. Will your group still be employed at the end of the day? Show all dimensional analysis steps that are necessary to this problem. What is the maximum amount of ammonia that can be made given your supplies?
Firstly, we need to write the equation for the process.
We start with hydrogen gas, H₂, and nitrpgen gas, N₂, and end with NH₃, so the unbalanced reaction is:
\(H_2+N_2=NH_3\)To balance it, we can add a coefficient of 2 to NH₃ so that N gets balanced and then we will need to add a coefficient of 3 to H₂ so H gets balanced:
\(3H_2+N_2=2NH_3\)With the balanced reaction, we will need the molar mass of each component, which we can calculate using the molar masses of the atoms H and N:
\(\begin{gathered} M_{H_2}=2\cdot M_H=2\cdot1.00794g\/mol=2.01588g\/mol \\ M_{N_2}=2\cdot M_N=2\cdot14.0067g\/mol=28.0134g\/mol \\ M_{NH_3}=1\cdot M_N+3\cdot M_H=1\cdot14.0067g\/mol+3\cdot1.00794g\/mol=17.03052g\/mol \end{gathered}\)Now, we need to convert the masses of nitrogen gas and hydrogen gas to number of moles:
\(\begin{gathered} M_{H_{2}}=\frac{m_{H_2}}{n_{H_{2}}} \\ n_{H_2}=\frac{m_{H_2}}{M_{H_{2}}}=\frac{30g}{2.01588g\/mol}=14.8818\ldots mol \end{gathered}\)\(\begin{gathered} M_{N_{2}}=\frac{m_{N_2}}{n_{N_{2}}} \\ n_{N_2}=\frac{m_{N_2}}{M_{N_{2}}}=\frac{100g}{28.0134g\/mol}=3.5697\ldots mol \end{gathered}\)Now, we need to find which of the two is the limiting reactant, that is, which we have less considering the ratio they react.
Each 1 mol of N₂ that react will need 3 mol of H₂, so if all the 3.5697... mol of N₂ react, than we will need
\(3\cdot3.5697\ldots mol=10.7091\ldots mol\)10.7091... mol of H₂. Since we have 14.8818 mol of H₂, we have excess of H₂, which means that N₂ is the limiting reactant.
Since H₂ is the limiting reactant, the most that we can produce of NH₃ is the corresponding of 3.5697... mol of reacting N₂.
From the equation again, we can see that each mol of N₂ that reacts will produce 2 mol of NH₃, so if all the limiting 3.5697... mol react, we will get:
\(2\cdot3.5697\ldots mol=7.1394\ldots mol\)7.1397... mol of NH₃, so this is the maximum number of moles we can get of NH₃:
\(n_{NH_{3}}\)Using the molar mass of NH₃, we can convert this to mass:
\(\begin{gathered} M_{NH_{3}}=\frac{m_{NH_3}}{n_{NH_{3}}} \\ m_{NH_3}=n_{NH_3}\cdot M_{NH_3}=7.1394\ldots mol\cdot17.03052g\/mol=121.58\ldots g\approx121g \end{gathered}\)So, the maximum mass of NH₃ you can produce with the given masses of reactant is 121 grams, which is not enough for whats has been asked.
Calculate the mass (in kg) of 4.87 x 10 25 atoms of Zn
Answer:
5.29kg
Explanation:
5.29kg
The mass of 4.87×10²⁵ atoms of Zn is 5.29 Kg
From Avogadro's hypothesis,
6.02×10²³ atoms = 1 mole of ZnRecall,
1 mole of Zn = 65.38 g
Converting 65.38 g to Kilogram (Kg), we have:
1000 g = 1 Kg
Therefore,
65.38 g = 65.38 / 1000
65.38 g = 0.06538 KgThus, we can say that,
6.02×10²³ atoms = 0.06538 Kg of ZnFinally, we shall determine the mass of Zn that contains 4.87×10²⁵ atoms. This can be obtained as follow:
6.02×10²³ atoms = 0.06538 Kg of Zn
4.87×10²⁵ atoms = \(\frac{4.87*10^{25} * 0.06538}{6.02*10^{23} } \\\\\)
4.87×10²⁵ atoms = 5.29 Kg of ZnTherefore, the mass of 4.87×10²⁵ atoms of Zn is 5.29 Kg
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the pressure on 20 milliliters of a gas at constant temperature is changed from 4 atmospheres to 2 atmospheres. what is the new volume of the gas?
The new volume of the gas whose pressure was changed would be = 40 milliliters.
How to calculate the new volume of the given gas?The initial volume(V1)of the gas= 20ml
The initial pressure(P1) = 4 atm
The final pressure(P2) = 2 atm
The final volume(V2) = ?
Using the general gas formula;
P1V1 = P2V2
V2 = P1V1/P2
= 4×20/2
= 40ml
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Using the two cell reduction potentials shown for their corresponding reaction, calculate the cell potential for a voltaic cell made from these two systems.
A)
–1.68 V
B)
1.68 V
C)
0.78 V
D)
–0.78 V
Answer:
C: 0.78 V
Explanation:
The Cr2O7 cell has a higher reduction potential, so it will be reduced (as it is a better oxidizing agent). This means that Fe will be oxidized. Its oxidation potential is simply the negative of its reduction potential, 0.45: \(E_{ox}=-0.45\). We know that cell potential is the sum of the reduction and oxidation potentials of each reaction (it is not an extensive property like enthalpy or entropy, so we don't need to worry about multiplying anything). Therefore, \(E_{cell}=(-0.45+1.23)V=0.78V\).
Fructose‑2,6‑bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolysis and the fructose‑1,6‑bisphosphatase reaction of gluconeogenesis. In turn, the concentration of fructose‑2,6‑bisphosphate is regulated by many hormones, second messengers, and enzymes.
Answer:
Activate glycolysis/Inhibit gluconeogenesis: Increased levels of fructose-2,6-bisphosphate, activation of PFK-2
Activate gluconeogenesis/Inhibit glycolysis: Increased levels of glucagon, Increased levels of cAMP, Activation of fructose-2,6-bisphosphatase (FBPase-2)
Note: The question is incomplete. The complete question is given below and in the attachment.
Fructose‑2,6‑bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolysis and the fructose‑1,6‑bisphosphatase reaction of gluconeogenesis. In turn, the concentration of fructose‑2,6‑bisphosphate is regulated by many hormones, second messengers, and enzymes. How do the following affect glycolysis and gluconeogenesis?
Explanation:
Fructose-2,6-bisphosphate is an allosteric effector for the enzymes phosphofructokinase-1 (PFK-1) and fructose-1,6-bisphosphatase (FBPase-1). It increases the affinity of PFK-1 for fructose-6-phosphate thereby activating glycolysis. However, it reduces the affinity of FBPase-1 for its substrate, fructose-1,6-bisphosphate thereby inhibiting gluconeogenesis.
Activation of phosphofructokinase-2 activates glycolysis and inhibits gluconeogenesis by catalyzing the phosphorylation of fructose-6-phosphate to form fructose-2,6-bisphosphate.
Increased levels of glucagon stimulates the synthesis of cAMpP which activates cAMP-dependent ptrotein kinase which phosphorylates the bifunctional enzyme PFK-2/FBPase-2. The phosphorylation of this enzyme inhibits its PFK-2 activity and activates its FBPase-2 activity. This results in the activation of gluconeogenesis and inhibition of glycolysis.
Fructose-2,6-bisphosphatase breaks down fructose-2,6-bisphosphate to fructose-6-phospshate and a phosphoryl group. This results in the activation of gluconeogenesis and the inhibition of glycolysis.
Question 4 of 35
What did Thomson discover as a result of his experiments with cathode ray
tubes?
A. Electrons are found within electron clouds of atoms.
B. Each atom has a positive nucleus at its center.
C. Electrons travel along circular paths within atoms.
D. Atoms are made up of smaller subatomic particles
Answer:
D
Explanation:
Answer:
D Atoms are made up of smaller subatomic particles
Explanation:
I just took the quiz, I hope this helps!
What are the coordinates of the midpoint between (3,-7) and (-5, 2)?
(-4,-4.5)
O (1, 2.5)
O (-2,-5)
(-1,-2.5)
The coordinates of the midpoint : (-1,-2.5)
Further explanationGiven
The coordinates of (3,-7) and (-5, 2)
Required
Midpoint
Solution
Can be formulated :
\(\tt midpoint=\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\)
Input the value :
x₁=3
x₂=-5
y₁=-7
y₂=2
\(\tt midpoint=(\dfrac{3+(-5)}{2},\dfrac{-7+2}{2})\\\\midpoint=(\dfrac{-2}{2},\dfrac{-5}{2})\\\\midpoint=(-1,-2.5)\)
David prepared the potassium phosphate solution by adding 46.3g to 250 mL of water. Kim needs 0.10M potassium phosphate solution. How many stock solutions does she need if she wants to mix 150 ml of diluent?
Answer:
17.2mL
Explanation:
Step 1:
Determination of the molarity of potassium phosphate K3PO4 solution.
This is illustrated below:
Mass of K3PO4 = 46.3g
Molar Mass of K3PO4 = (39x3) + 31 + (16x4) = 212g/mol
Mole of K3PO4 =..?
Mole = Mass /Molar Mass
Mole of K3PO4 = 46.3/212 = 0.218 mole
Volume of water = 250mL = 250/1000 = 0.25L
Molarity = mole /Volume
Molarity of K3PO4 = 0.218/0.25
Molarity of K3PO4 = 0.872M
Step 2:
Determination of the volume of the stock solution of K3PO4 needed.
Molarity of stock solution (M1) = 0.872M
Volume of stock solution needed (V1) =..?
Molarity of diluted solution (M2) = 0.1M
Volume of diluted solution (V2) = 150mL
The volume of the stock solution needed can be obtained as follow:
M1V1 = M2V2
0.872 x V1 = 0.1 x 150
Divide both side by 0.872
V1 = (0.1 x 150)/0.872
V1 = 17.2mL
Therefore, the volume of the stock solution needed is 17.2mL
17. A 55-gram egg is placed in a pot. After the egg is boiled, which is most likely the mass of
the egg?
A. 50g
B. 55g
C. 110g
D. 100g
Answer:
B. 55g
Explanation:
When an egg is boiled, its albumin (the main component of its yolk) is denaturalized due to the high temperatures, making it apt for human consumption.
This is only a physical change and no mass is lost nor gained during this process.
That's why the correct answer is the original mass of the egg, in this case, option B.
_Al(OH)3 + __H2SO4 →
_Al2(SO4)3 +___ H2O
In this equation, two molecules of aluminum hydroxide react with three molecules of sulfuric acid to produce one molecule of aluminum sulfate and six molecules of water.
What is Molecules?
A molecule is a group of two or more atoms that are chemically bonded together. Atoms can combine to form molecules by sharing electrons between them, forming a covalent bond. Molecules can also be formed by the attraction between oppositely charged ions, known as ionic bonding.
Molecules can be made up of atoms of the same element or atoms of different elements. For example, oxygen gas (O2) is a molecule made up of two oxygen atoms, while water (H2O) is a molecule made up of two hydrogen atoms and one oxygen atom.
The balanced chemical equation for the reaction between aluminum hydroxide and sulfuric acid is:
2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
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A student collects 500cm^3 of methane gas at STP. Determine the moles of gas present, the number of methane molecules and the mass of methane.
Assignment Your Unde a professor in a University has Sent you an touration 6 his Inaugural lectore wate a letter to him, showing appreciation for him on halind gesture and Congratulating! his achievements So far
In this letter, express gratitude to your uncle, a university professor, for his invitation and congratulate him on his achievements.
Here are the steps to be followed:
By following these steps, you can write a thoughtful and appreciative letter to your uncle, expressing your gratitude for his invitation and congratulating him on his achievements.
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how many milliliters of .100 M NaOH are required to neutralize the following solution 75.5mL of .215 M H2SO4
In order to find how many milliliters of .100 M NaOH are required to neutralize the following solution 75.5mL of .215 M H2SO4, we will use the following formula :
M1*V1 = M2*V2
Where M1 =0.215
V1=75.5ml
M2 =0.100
V2 =?
∴ V2 = M1*V1/M2
= 0.215M* 75.5ml/0.100M
= 162.33 ml
• This means that ,162.33 milliliters, of 0.1M NaOH will be required,
Sarah loves animals and wants to become a veterinarian one day. She decides to learn all she can about vertebrates, and she finds that they all have certain characteristics in common. Identify and explain the traits that vertebrates have in common.
Answer:
Vertebrates have spines as Invertebrates don't
Explanation:
Vertebrates Invertebrates
They have spine or backbone. These animals lack the spine or backbone.
Notochord, a self-supporting rod, is present in the embryos during the embryonic period. They lack notochord.
Generally, large and fast-moving animals. Generally, small and slow-moving animals.
**Find the speed of an object that travels 500 miles in 5 hours. S = d/t
Answer:
I believe that would be 100 mph.
Explanation:
Your distance (d) is 500 miles and your time (t) is 5 hours.
So when you replace the variables with numbers you bet 500/5 which is 100.
Therefore, you speed (S) would be 100mph.
What is the correct definition of speed?
A. time per distance (hours per mile or seconds per meter)
B.distante per time (miles per hour or meters per second)
C.time (hours or seconds
D.distance (miles or meters)
Answer:
B
Explanation:
what is the original pressure of a 750 ml sample of He at 0 degrees Celsius if it exerts 2 atm at 25 degrees Celsius and 500 ml
To determine the original pressure of a 750 ml sample of helium (He) at 0 degrees Celsius, we can use the combined gas law, which relates the initial and final conditions of a gas sample. The combined gas law equation is:
(P1 × V1) / (T1) = (P2 × V2) / (T2)
Where:
P1 and P2 are the initial and final pressures, respectively.
V1 and V2 are the initial and final volumes, respectively.
T1 and T2 are the initial and final temperatures, respectively.
Let's assign the given values:
P1 = unknown (original pressure)
V1 = 750 ml (initial volume)
T1 = 0 degrees Celsius (initial temperature)
P2 = 2 atm (final pressure)
V2 = 500 ml (final volume)
T2 = 25 degrees Celsius (final temperature)
Before using the combined gas law equation, we need to convert the temperatures to Kelvin scale by adding 273.15 to both T1 and T2:
T1 = 0 + 273.15 = 273.15 K
T2 = 25 + 273.15 = 298.15 K
Now we can plug in the values into the combined gas law equation:
(P1 × 750 ml) / (273.15 K) = (2 atm × 500 ml) / (298.15 K)
To solve for P1, we can cross multiply and rearrange the equation:
P1 = (2 atm × 500 ml × 273.15 K) / (750 ml × 298.15 K)
P1 = 0.924 atm
Therefore, the original pressure of the 750 ml sample of helium at 0 degrees Celsius is approximately 0.924 atm.
Which of the following is an incorrect representation for a neutral atom?
36Li
613C
3063Cu
1530P
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li
To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.
Let's analyze the given representations:
36Li:
This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.
613C:
This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.
3063Cu:
This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.
1530P:
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.
Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.
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What is the reason for heat transfer from one substance to another?
Answer:
Difference in temperature
Explanation:
According to thermodynamics, heat transfer occurs when heat from a high temperature reservoir moves to a low temperature reservoir. For heat to be transferred, the two objects should have different temperatures with one having more temperature than the other. Heat transfer in solids is by conduction, in fluids is by convection and by radiation.
at standard pressure, what is the temperature at which a saturated solution of NH4Cl has a concentration of 60g NH4CL/100 g H2O
Answer: Temperature = T, unknown
Saturated Solution, NH4Cl concentration = 60g/100g H2O = 0.6g NH4Cl/g H2O
Assume density of H2O = 1 g/ml
m = 0.6g NH4Cl/g H2O / 1 g/ml
m = 0.6g NH4Cl/ml
See the table of saturated solutions and identify the temperature at which the concentration of NH4Cl is 60g/100g H2O.
Explanation: The line on the graph on reference table G indicates a saturated solution of NH4CL as a concentration of 60. g NH4 Cl/100. g H2O
Robert Delaunay's Homage to Blériot (1914) was inspired by
O the invention of stroboscopic photography
the construction of the Eiffel Tower
his wife's new dress designs
the first flight across the English channel
Answer:
Robert Delaunay's Homage to Blériot (1914) was inspired by the first flight across the English channel.
What is a solvent ?
Answer:
A solvent is a substance that dissolves a solute, resulting in a solution. A solvent is usually a liquid but can also be a solid, a gas, or a supercritical fluid.
Explanation:
A galvanic (voltaic) cell has the generic metals X and Y as electrodes. X is more reactive than Y, that is, X more readily reacts to form a cation than Y does. Classify the descriptions by whether they apply to the X or Y electrode.
a. Anode
b. Cathode
c. Loses mass
d. Electrons in the wire flow away from it
e. Anions from the salt bridge flow toward it
f. Cations from the salt bridge flow toward it
g. Gains mass
f. Electrons in the wire flow toward it
Answer:
X
Anode
Loses mass
Electrons in the wire flow away from it
Anions from the salt bridge flow toward it
Y
Cathode
Gains mass
Electrons in the wire flow toward it
Cations from the salt bridge flow toward it
Explanation:
A galvanic cell consists of an anode, a cathode and a salt bridge. The cathode is the negative electrode. The cathode increases in mass due to mass deposition. The cathode becomes increasingly negative as the cell reaction progresses, hence cations from the salt bridge flow towards it.
The anode is the positive electrode. It becomes more positive as the cell reaction progresses hence anions from the salt bridge flow towards it. The anode is the electrode where oxidation reaction occurs hence electrons are lost here and flow towards the cathode. The anode looses mass as the cell reaction progresses due to oxidation.
What is the name of the Group 17 elements?
A. Nobel gases
B. Alkaline earth metals
C. Alkali metals
D. Halogens
Answer:
Halogens
Explanation:
Halogen, any of the six nonmetallic elements that constitute Group 17 (Group VIIa) of the periodic table. The halogen elements are fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At), and tennessine (Ts).