Which of the following simple machines is designed primarily to redirect a force rather than reduce the effort required to move a load?

Lever
Wedge
Inclined Plane
Wheel and Axle

a) The cost of using the microwave oven for one hour is 6 cents.

b) The cost of using the microwave oven for 20 minutes in a day is 2 cents.

c) The cost of using the microwave oven for 20 minutes a day for a month of 30 days is 59 cents.

a) The microwave oven draws 0.8 kWh of electricity for one hour. The cost of electricity per kWh is 7.5 cents. Therefore, the cost of using the microwave oven for one hour can be calculated as follows:

Cost = 0.8 kWh x $0.075/kWh = $0.06

b) If the microwave oven is used for 20 minutes in a day, the energy consumed can be calculated as follows:

Energy consumed = Power x Time

Power = Energy consumed / Time

We know that the microwave oven draws 0.8 kWh of electricity for one hour. Therefore, the power can be calculated as:

Power = 0.8 kWh / 1 hour = 0.8 kW

The time for which the microwave is used is 20 minutes, or 0.33 hours. Therefore, the energy consumed can be calculated as:

Energy consumed = Power x Time = 0.8 kW x 0.33 hours = 0.264 kWh

The cost of using 0.264 kWh of electricity can be calculated as:

Cost = 0.264 kWh x $0.075/kWh = $0.02

c) If the microwave oven is used for 20 minutes a day for a month of 30 days, the energy consumed can be calculated as:

Energy consumed = Power x Time x Number of days

Power = Energy consumed / Time

Using the same values of power and time as in part b, the energy consumed for 30 days can be calculated as:

Energy consumed = 0.8 kW x 0.33 hours x 30 days = 7.92 kWh

The cost of using 7.92 kWh of electricity can be calculated as:

Cost = 7.92 kWh x $0.075/kWh = $0.59

In summary, the cost of using a microwave oven for electrical energy consumption depends on the power rating of the oven and the cost of electricity per kWh. By calculating the energy consumed and multiplying it by the cost per kWh, one can determine the cost of using the microwave for a particular period of time.

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Answer:

36N

Explanation:

Given parameters:

Mass of apple  = 0.25kg

length of string  = 1m

tangential speed  = 12m/s

Unknown:

magnitude of centripetal force = ?

Solution:

The centripetal force keeps a body moving along a circular path.

It is mathematically derived using the expression below;

      F = \(\frac{mv^{2} }{r}\)

F is the centripetal force

m is the mass

v is the tangential speed

r is the radius

  Now insert the parameters and solve;

     F = \(\frac{0.25 x 12^{2} }{1}\)  = 36N

The methods to determine the specific charge of an electron are The J. J. Thomson Method and The Millikan Oil Drop Method.

The J. J. Thomson Method

In this method, an electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen. When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force, which is given by the formula: $F= evB$ $F= evB$

When a magnetic field is applied at right angles to an electron beam, it bends the path of the beam into a circular path. The radius of the path of an electron beam in a magnetic field is determined by the relationship:r = mv/eB. As a result, the specific charge of an electron may be calculated from the expression: $e/m = 2V / B^2r^2$

The Millikan Oil Drop Method

This is another technique for determining the specific charge of an electron. The oil drop experiment was first done by Robert A. Millikan in 1909. He did this experiment by suspending charged droplets of oil in a uniform electric field between two parallel plates.

The fall of the oil droplets in the absence of an electric field was also noted. The fall velocity of the oil droplet was determined by measuring the time taken by the oil droplet to pass through a fixed distance between the plates in the absence of an electric field. By measuring the electric field strength, the voltage applied to the plates, and the fall velocity of the oil droplet, the specific charge of the electron was determined.

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The methods to determine the specific charge of an electron are :

In the J. J. Thomson Method, an  electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen.

When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force.

The Millikan Oil Drop Method is an experiment by which is created by suspending charged droplets of oil in a uniform electric field between two parallel plates.

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The magnitude of the normal force on the crate for the different cases are-

1.1) 100 N

1.2) 150 N

1.3) 80 N

2) 30 N

What is the normal force ?

1.1

The weight of the crane, W = 100N

Since, Weight = Normal Force

Therefore the normal force on the crate is 100 N

1.2

A 50N downward force is applied to the crate.

As the body is not moving and is in equilibrium, so considering all the forces acting on the body we get,

Normal Force  = Weight  + 50

                        = 100 + 50

                         = 150 N

1.3

A 20N upward force is applied to the crate.

As the body is not moving and is in equilibrium, so considering all the forces acting on the body we get,

Normal Force + 20 = Weight

Normal Force = Weight - 20

                       = 100 - 20

                       = 80 N

2.

A 130N upward force is applied to the crate.

As the body is not moving and is in equilibrium, so considering all the forces acting on the body we get,

Normal + Weight = 130

Normal Force = 130 - Weight

                       = 130 - 100

                       = 30 N

Hence, The magnitude of the normal force on the crate for the different cases are-

1.1) 100 N

1.2) 150 N

1.3) 80 N

2) 30 N

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The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

A concave mirror has a reflective surface that is curved inward and away from the light source.

Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.

Apply mirrors formula as shown below;

1/f = 1/v + 1/u

where;

when image height = object height, magnification = 1

u/v = 1

v = u

Substitute the given parameters and solve for the distance of the object from the mirror's vertex

1/f = 1/v + 1/v

1/f = 2/v

v = 2f

v = 2(19.5 cm)

v = 39 cm

Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

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Two objects are held close together. When they are released, they move toward one another. The conclusion is supported by this evidence is  the objects have opposite charges.

An electric charge is a physical property that causes matter to experience a force when in close proximity to other electrically charged matter. There are two types of electric charges: positive and negative. Protons, which are positively charged, and electrons, which are negatively charged, are subatomic particles that make up matter.

In general, the protons and neutrons in the nucleus of an atom have a net positive charge, while electrons, which orbit the nucleus, have a net negative charge. The charges of these subatomic particles are indicated by the symbols "p" for proton, "n" for neutron, and "e" for electron.

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Radius of rotation, r = \(mv^2\)/F = (3.0 kg)(5.0 \(m/s)^2\)/(8.0 N) = 9.375 m.

To find the radius of rotation for a rotating object with a mass of 3.0 kg and a force of 8.0 N acting upon it,

we can use the centripetal force formula:

F = \(mv^{2/r\). In this formula, F represents the force, m is the mass, v is the velocity, and r is the radius.

Given a mass of 3.0 kg, a force of 8.0 N, and a rotational speed of 5.0 m/s,

we can rearrange the formula to solve for the radius: r = \(mv^{2/F\).

Plugging in the given values,

we get r = (3.0 kg)(5.0 \(m/s)^2\)/(8.0 N) = 9.375 m.

Thus, the radius of rotation is 9.375 meters.

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Answer:

The displacement is 6.4m

Explanation:

Step one:

given

we are told that Lucy runs 4 meters to the east,

then 5 meters south.

let the distance east be the displacement in the x-direction, and south be the y-direction

Step two:

The resultant of the x and y displacement is the magnitude of the total displacement z

applying Pythagoras theorem we have

z=√x^2+y^2

z=√4^2+5^2

z=√16+25

z=√41

z=6.4m

The potential and kinetic energy of the system at the following time instances is zero and maximum.

From the given,

The displacement of the system is, x = A cos(3πt/T)

1) At t =0, the displacement of the system is given by, x = cos(3π×0/T)= cos(0) = 1. The displacement is maximum at t=0. Hence, the potential energy is maximum and kinetic energy is zero.

2) At t=T, the displacement, x = cos(3πT/T)= cos(3π) = -1. The displacement is minimum and hence, the potential energy is minimum and kinetic energy is maximum.

3) At t = T/6, the displacement x = cos(3πT/6T)=cos(π/2)=0, the displacement is zero, and hence, both the potential and kinetic energy is zero.

4) At t=T/3, the displacement, x= cos(3πt/T)=cos(3πT/3)= -1. The displacement is minimum and hence, the potential energy is minimum and kinetic energy is maximum.

5) At t=T/2, the displacemetn x = cos(3πt/T) = cos(3πT/2T) = cos (3π/2)=0. Hence, both the potential and kinetic energy is zero.

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If a person swims at a constant speed of 1 meter per second, than the linear function will be used to model the distance travelled by the swimmer.

The parent function is "the principal's of ice"

A linear function is a function that forms a straight line on a graph. It is generally a polynomial function whose degree is at most 1 or 0. Although linear functions are also represented in terms of calculus and linear algebra.

Here Y-axis represents Distance and X-axis represents Time.

Also speed is the rate of change of distance with respect to time i.e. distance is changing linearly with time

Mathematically it is  \(Speed = \frac{distance}{time}\).

Change in Distance = Change in time and hence speed is constant.

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The answer is 1) The pressure at point D is 80 kPa. 2) The temperature at point D is 800 K. 3) The net work done on the gas over four cycles is zero. 4) The internal energy of the gas at point A is 100 J. 5) The total change in internal energy during four complete cycles is zero.

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We have that the speed of the spaceship must be

\(V=2.47m/s\)

From the Question we are told that

Mass \(8.7*10^{17} kg\)

Positive charge of 4400 C

Spaceship mass m_s=3.3* 10^5 kg

Solar wind has given their spaceship a charge of -1.2 C.

Diameter d=8300-km-diameter

Generally the equation for the force of attraction   is mathematically given as

\(v^2=\frac{Gm}{r}+\frac{kQq}{rm}\\\\v^2=\frac{6.67*10^{-11}*8.7*10^{17}}{9.5*10^5}}+\frac{9*10^9*4400*-1.2}{9.5*10^5*3.3*10^{15}}\)

\(V=2.47m/s\)

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The speed will be "6.98 m/s". A complete solution is provided below.

The given values are:

Mass of asteroid,

Mass of spaceship,

Charge,

As we know,

→ \(F_G +F_E = \frac{mv^2}{R}\)

or,

→ \(\frac{GMm}{R_2} +\frac{kq_1 q_2}{R_2}=\frac{mv^2}{R}\)

By putting the given values, we get

→ \(\frac{6.67\times 10^{-11}\times 8.7\times 10^{17}\times 3.3\times 10^5}{\frac{8.3\times 10^6}{2} } +\frac{9\times 10^9\times 4400\times 1.2}{\frac{8.3\times 10^6}{2} } = 3.3\times 10^5\times v^2\)

→                                                                   \(v=6.98 \ m/s\)                                                                                                                                                      

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Explanation:

speed=distance/time

=50/10

=5 m/s

Speed ​​is defined as the rate of position in a given amount of time. Hence, the speed covered by the bird is 5m/s.

The speed of an object is defined as the magnitude of change of its position with time or the magnitude of change of its position per unit time. Speed ​​is a scalar quantity because it has only magnitude, not direction.

Speed is expressed as:

Speed= Distance/ Time taken

s=d/t

Where, s= speed

d= distance travelled

t= time taken

Given,

Distance travelled= 50 m

Time take= 10 sec

Speed= 50/10= 5m/s

Thus, Speed ​​is defined as the rate of position in a given amount of time. Hence, the speed covered by the bird is 5m/s.

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The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.

Potential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.

This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.

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Answer:

1metre

Explanation:

height gained is equal to speed multiplied by angle

Answer:

F = 0 N

Explanation:

The problem does not talk about any acceleration. We can just assume it always moves at a constant speed so the resultant force will be 0 newtons. Of course you could say that it accelerates for a certain amount of time, as the wind blows, but the problem doesn't tell us when to calculate the resultant force (if during the acceleration or after) + we don't have the mass of the jet.

Answer: D

Explanation:

Objects 3 and 5.

Virtual images are always formed by convex mirrors and are formed by concave mirrors when the object is placed in front of f.

Answer:The correct answer is mass

Using Newton's second law and kinematics we find that the correct answer are:

Kinematics studies the motion of bodies, establishing relationships between the position, velocity and acceleration of bodies.

               v = v₀ + a t

                y = v₀ t + ½ a t²

Where v i de veloicity, a the acceleration,y the position and t the time

Newton's second law states that force is proportional to the mass and acceleration of bodies

               F = ma

Where F es the force, m the mass ( scalr) and a de acceleraction

In the experiment shown, the car starts with zero initial velocity from a zero initial position, as the hanging mass creates a force that pulls the car, it increases its position and speed as time stops.

Therefore the position and speed are changing with time.

As the hanging mass is constant the applied force is constant consequently due to Newton's second law the mass of the body and its acceleration must be constant

In summary the acceleration, the mass and the applied force are constant.

The variable magnitude with time is the speed

In conclusion using Newton's second law and kinematics we find that the correct answer is

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Complete Question    

The magnetic field of a plane-polarized electromagnetic wave moving in the z-direction is given by

\(B=1.2* 10^{-6} sin [2\pi[(\frac{z}{240} ) - ( \frac{t * 10^7}{8} ) ] ]\)    in SI units.

Answer:

The  value  is  \(f = 1.98918*10^{5}\ Hz\)

Explanation:

From the question we are told that

   The magnetic field is    \(B=1.2* 10^{-6} sin [2\pi[(\frac{z}{240} ) - ( \frac{t * 10^7}{8} ) ] ]\)

 This above  equation can be modeled as

       \(B=1.2* 10^{-6} sin [2\pi[(\frac{z}{240} ) - ( \frac{t * 10^7}{8} ) ] ] \equiv A sin ( kz -wt )\)

So  

       \(w = \frac{10^7}{8}\)

Generally the frequency is mathematically represented as

       \(f = \frac{w}{2 \pi}\)

=>    \(f = \frac{ \frac{10^7}{8} }{2 \pi}\)

=>    \(f = 1.98918*10^{5}\ Hz\)

To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.

The weight ⃗ can be resolved into two components:

- the vertical component, Wsin(30°), acting downward

- the horizontal component, Wcos(30°), acting to the left

The forward thrust ⃗ can also be resolved into two components:

- the vertical component, Tsin(30°), acting upward

- the horizontal component, Tcos(30°), acting to the right

Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.

The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.

Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.

Answer:

Explanation:

1. First draw a free body diagram of the scenerio (a block sliding down a a slant surface).
2. Then we analyze the forces and write equations that satisfy Fnet = ma. This will give us the acceleration as the block slides down the surface.

3. Last, we can use the kinematic equation (vf^2 = vi^2 + 2as) and to solve the final speed of the block.

A. Keith appears to have a Type A personality. He is highly organized and has a strong desire for structure and order, which is evident from his insistence on following the project templates.

He also seems to be somewhat inflexible in his approach to the project, which can be seen from his unwillingness to consider alternative ideas and his "my way or the highway" attitude. Additionally, his need to recharge after social interactions indicates that he may be introverted.

B. Openness: 3, Conscientiousness: 5, Extraversion: 2, Agreeableness: 2, Neuroticism: 3.

C. Keith demonstrates high conscientiousness, as he is organized, methodical, and committed to completing the project.

He is less agreeable, as he appears to be unwilling to consider alternative ideas and can be inflexible in his approach.

Keith's introversion is consistent with his need to recharge after social interactions, and he does not exhibit high levels of extraversion.

Finally, while he does not seem to be anxious about the project deadline, he also does not exhibit high levels of neuroticism.

Overall, Keith's personality seems to be consistent with the Type A personality, which is characterized by high levels of conscientiousness and a need for structure and order.

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Answer:

impulse = change in linear momentum

3.75kgm/s

Explanation:

initial momentum is 0 because at the start golf ball is at rest

and our final momentum 0.050kg × 75m/s = 3.75kgm/s

momentum final - momentum initial

3.75kgm/s  -  0

3.75kgm/s

A. The output voltage, Vout, as a function of time, t, in a series RL circuit can be determined using the equation: Vout(t) = Vmax * (1 - e^(-t/τ)), where τ = L/R.

B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can approximate the output voltage Vout using the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.

A. To determine the output voltage Vout as a function of time t in a series RL circuit, we use the following equation:

Vout(t) = Vmax * (1 - e^(-t/τ))

Here, Vmax is the maximum input voltage, τ = L/R is the time constant of the circuit (where L is the inductance and R is the resistance).

B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can make the following approximation:

Vout(t) ≈ Vmax * e^(-t/τ)

In this case, we substitute VmaxT with Φimp, which is the total magnetic flux in the circuit.

Rearranging the equation, we get:

Vout(t) ≈ Φimp * e^(-t/τ)

This approximation is valid when the time interval T is very small compared to the time constant τ of the circuit and when the maximum voltage is sufficiently high.

The time constant τ is determined by the values of inductance (L) and resistance (R) in the circuit. It represents the characteristic time scale over which the current and voltage in the circuit change in response to a voltage or current input.

Therefore, in the given scenario, when T is very small and Vmax is high, we can approximate the output voltage Vout(t) in the series RL circuit by the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.

Note: The symbol Φimp in the equation represents the total magnetic flux in the circuit.

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The centripetal acceleration of the plane is 0.255 g.

What is centripetal acceleration?

centripetal acceleration is the rate at which a body moves through a circle. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude, the speed, and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in velocity, which results in an acceleration. The circle's Centre is where the acceleration is pointed radially.

Since we are given the tension in the cable and the angle of inclination, we can use trigonometry to find the vertical and horizontal components of tension.

Tsinθ = mg

Tcosθ = mv²/r

where θ = 35°, v = 180 km/h = 50 m/s, r = 1000 m, and m = 1000 kg.

Solving for Tsinθ and Tcosθ, we get:

Tsinθ = mg = (1000 kg)(9.81 m/s²) = 9810 N

Tcosθ = mv²/r = (1000 kg)(50 m/s)²/(1000 m) = 2500 N

Now we can use the horizontal and vertical components of tension to find the centripetal acceleration:

Tcosθ = ma

a = Tcosθ/m = (2500 N)/(1000 kg) = 2.5 m/s²

To express this acceleration in terms of g, we divide by the acceleration due to gravity:

a/g = 2.5 m/s² / 9.81 m/s² = 0.255

Therefore, the centripetal acceleration of the plane is 0.255 g.

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Answer:

option c is the correct one

Dense because food do be dense tho