Which of the following represents the graph of f(x) = 3^x + 1?

The circle with a 7 feet radius cut into 6 equal sectors, indicates, using 22/7 approximation for pi, that the area of 2 of the pieces is 51 and one third square feet. The correct option is option C.

C. 51 and one third square feet

A sector of a circle is a pie shaped part of a circle that is bounded by an arc and two radii of the circle.

The specified radius of the circle, r = 7 feet

The number of pieces to which the circle is cut into = 6 equal pieces (sectors)

The area of 2 of the pieces, using 22/7 as an approximation for π are found as follows;

Area of a circle, A = π × The square of the radius

Therefore; A = π × r²

A = (22/7) × 7² = 154

The area of the circle is about A = 154 square feet

The area of one of the pieces into which the circle is cut is therefore;

Area of a piece = A/6

Area of one piece = (154 square feet)/6 = 25 and two thirds square feet

The area of 2 of the pieces = 2 × (A/6) = A/3

Therefore, the area of two of the pieces = (154 square feet)/3 = 51 1/3

The area of 2 of the pieces = \(51\frac{1}{3}\) square feet

Option C is correct

C. 51 and one third square feet

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Using the 22/7 approximation for pi, the circle with a radius of 7 feet divided into 6 equal sectors shows that the area of 2 of the sections is 51 and a third square feet. Option C is the one that is right.

51 and a third square feet in C.

Step-by-step explanation:

divide 15 by 2 to get the radius which is 7.5

then 7.5² = 56.25 x3.15=177.1875 round and its A=177.188

if this is incorrect someone else correct me

Answer:

x= 4

Y= -1

Z= 3

step by step procedure:

let x+y+z=6, x-y+z=8, x+y-z=0 be equations 1, 2, and 3 respectively.

you are welcome bro....

Kindly note that the question says 4; maybe the final question was intended to be the probability that he gets exactly 2 of the 4 correct. However. If it is the other way round. This a e procedure used in the solution should also be followed.

Answer:

0.21

Step-by-step explanation:

Number of options = 4

One correct answer per option ; hence, the probability of success, p = 1/4 = 0.25

Using the binomial probability relation :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

x = 2 ; n = 4

p = 0.25 ; 1 - p = 0.75

P(x = 2) = 4C2 * 0.25^2 * 0.75^2

P(x = 2) = 6 * 0.0625 * 0.5625

P(x = 2) = 0.2109375

P(x = 2) = 0.21 (2 decimal places)

Note : if the question was 3, then put, n = 3 instead of 4

Answer360

Step-by-step explanation:

Answer: 9/2500

Step-by-step explanation:

We start with turning it into a fraction:

0.36/100

Then, we turn every number into a whole number by multiplying by whatever the last decimal place is called (hundreth= x100)

36/10000

Lastly, we simplify as much as we can by finding the least common denominator. In this case, the smallest whole number both 36 and 10000 can be divided by is 4:

(36/4)/(10000/4)

= 9/25000

There are 14 dogs and 46 chickens in the farmyard.

The supposition that there are d dogs and c chickens.

Each chicken has two legs, but each dog has four.

Consequently, the total number of legs may be written as follows:

4d + 2c

Since we are aware that there are 148 legs in total, we can construct the following equation:

4d + 2c = 148

We may create another equation since we know that there are a total of 60 heads (dogs and chickens):

d + c = 60

Now that we have two equations with two variables, we may answer them both at the same time.

2d + 2c = 120 is the result of multiplying the second equation by two.

When we deduct this from the first equation, we obtain 2d = 28.

So, d = 14.

Reintroducing this into the second equation, we get:

14 + c = 60

So, c = 46.

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Answer: Usually the mean is more accurate without outliers.

Step-by-step explanation: Outliers can skew the data, or make it inaccurate. So without the outliers, the mean is more accurate.

hope this helps

Answer:She is not correct The graph of g grows at a faster rate

than the graph of because 8 greater than 2

Step-by-step explanation:

Using PEMDAS, the exponents are done first.

8^3 = 512

4*2^3 = 32

This works for every number that X can be, 3 was just an example.

Answer:

the meaning is "a collection of historical documents or records providing information about a place, institution, or group of people."

Step-by-step explanation:

hope this helped and plz mark me as brainliest!

Answer:

a collection of historical documents or records providing information about a place, institution, or group of people

Step-by-step explanation:

Answer:

700,120

Step-by-step explanation:

hope this helps!

9514 1404 393

Answer:

  90°

Step-by-step explanation:

On a standard 12-hour analog clock, the minute hand will be at the 12, and the hour hand will be at the 3 at 3:00. The smaller angle between the two hands is 90°. Of course, the larger angle is 360° -90° = 270°.

Answer:

(A)

Step-by-step explanation:

The survey follows of women's height a normal distribution.

The height of 98.51% of women that meet the height requirement are between 58 inches and 80 inches.

The new height requirements would be 57.7 to 68.6 inches

The given parameters are:

\mathbf{\mu = 63.5}μ=63.5 --- mean

\mathbf{\sigma = 2.5}σ=2.5 --- standard deviation

(a) Percentage of women between 58 and 80 inches

This means that: x = 58 and x = 80

When x = 58, the z-score is:

\mathbf{z= \frac{x - \mu}{\sigma}}z=

σ

x−μ

This gives

\mathbf{z_1= \frac{58 - 63.5}{2.5}}z

1

=

2.5

58−63.5

\mathbf{z_1= \frac{-5.5}{2.5}}z

1

=

2.5

−5.5

\mathbf{z_1= -2.2}z

1

=−2.2

When x = 80, the z-score is:

\mathbf{z_2= \frac{80 - 63.5}{2.5}}z

2

=

2.5

80−63.5

\mathbf{z_2= \frac{16.5}{2.5}}z

2

=

2.5

16.5

\mathbf{z_2= 6.6}z

2

=6.6

So, the percentage of women is:

\mathbf{p = P(z < z_2) - P(z < z_1)}p=P(z<z

2

)−P(z<z

1

)

Substitute known values

\mathbf{p = P(z < 6.6) - P(z < -2.2)}p=P(z<6.6)−P(z<−2.2)

Using the p-value table, we have:

\mathbf{p = 0.9999982 - 0.0139034}p=0.9999982−0.0139034

\mathbf{p = 0.9860948}p=0.9860948

Express as percentage

\mathbf{p = 0.9860948 \times 100\%}p=0.9860948×100%

\mathbf{p = 98.60948\%}p=98.60948%

Approximate

\mathbf{p = 98.61\%}p=98.61%

This means that:

The height of 98.51% of women that meet the height requirement are between 58 inches and 80 inches.

So, many women (outside this range) would be denied the opportunity, because they are either too short or too tall.

(b) Change of requirement

Shortest = 1%

Tallest = 2%

If the tallest is 2%, then the upper end of the shortest range is 98% (i.e. 100% - 2%).

So, we have:

Shortest = 1% to 98%

This means that:

The p values are: 1% to 98%

Using the z-score table

When p = 1%, z = -2.32635

When p = 98%, z = 2.05375

Next, we calculate the x values from \mathbf{z= \frac{x - \mu}{\sigma}}z=

σ

x−μ

Substitute \mathbf{z = -2.32635}z=−2.32635

\mathbf{-2.32635 = \frac{x - 63.5}{2.5}}−2.32635=

2.5

x−63.5

Multiply through by 2.5

\mathbf{-2.32635 \times 2.5= x - 63.5}−2.32635×2.5=x−63.5

Make x the subject

\mathbf{x = -2.32635 \times 2.5 + 63.5}x=−2.32635×2.5+63.5

\mathbf{x = 57.684125}x=57.684125

Approximate

\mathbf{x = 57.7}x=57.7

Similarly, substitute \mathbf{z = 2.05375}z=2.05375 in \mathbf{z= \frac{x - \mu}{\sigma}}z=

σ

x−μ

\mathbf{2.05375= \frac{x - 63.5}{2.5}}2.05375=

2.5

x−63.5

Multiply through by 2.5

\mathbf{2.05375\times 2.5= x - 63.5}2.05375×2.5=x−63.5

Make x the subject

\mathbf{x= 2.05375\times 2.5 + 63.5}x=2.05375×2.5+63.5

\mathbf{x= 68.634375}x=68.634375

Approximate

\mathbf{x= 68.6}x=68.6

Hence, the new height requirements would be 57.7 to 68.6 inches

The five-number summary for this data set is 29, 32, 43.5, 50.5, and 53, and the interquartile range is 18.5.

Measures of statistical dispersion, or the spread of the data, include the interquartile range. In addition to the IQR, other names for it include the midspread, middle 50%, fourth spread, and H-spread.

To find the five-number summary and interquartile range for this data set, we first need to find the quartiles.

Step 1: Find the median (Q2)

When a data collection is sorted from least to largest, the median is the midway value. Since there are 12 values in this data set, the median is the average of the sixth and seventh values:

Median (Q2) = (41 + 46)/2 = 43.5

Step 2: Find the lower quartile (Q1)

The lower quartile is the median of the lower half of the data set. Since there are 6 values below the median, we take the median of those values:

Q1 = (32 + 32)/2 = 32

Step 3: Find the upper quartile (Q3)

The upper quartile is the median of the upper half of the data set. Since there are 6 values above the median, we take the median of those values:

Q3 = (50 + 51)/2 = 50.5

Now we have all the information we need to construct the five-number summary and interquartile range:

Minimum: 29

Lower quartile (Q1): 32

Median (Q2): 43.5

Upper quartile (Q3): 50.5

Maximum: 53

Interquartile range (IQR) = Q3 - Q1 = 50.5 - 32 = 18.5

the five-number summary for this data set is 29, 32, 43.5, 50.5, and 53, and the interquartile range is 18.5.

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Number of 20-cent coins in the box are 33.

1. Let's assume the number of 20-cent coins to be x and the number of 50-cent coins to be y.

2. We can set up two equations based on the given information:

  - x + y = 54   (since the total number of coins in the box is 54)

  - 0.20x + 0.50y = 20.70   (since the total value of all the coins is $20.70)

3. We can multiply the second equation by 100 to get rid of the decimals:

  - 20x + 50y = 2070

4. Now, we can use the first equation to express y in terms of x:

  - y = 54 - x

5. Substitute the value of y in the second equation:

  - 20x + 50(54 - x) = 2070

6. Simplify and solve for x:

  - 20x + 2700 - 50x = 2070

  - -30x = -630

  - x = 21

7. Substituting the value of x back into the first equation:

  - 21 + y = 54

  - y = 33

8. Therefore, there are 21 20-cent coins and 33 50-cent coins in the box.

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Answer:

(a) Yes, the data suggest that females are more likely to graduate from high school than males.

(b) A 95% confidence interval for the difference in the graduation rates between females and males is [0.024, 0.404] .

Step-by-step explanation:

We are given that a survey of over 25,000 Americans aged between 18 and 24 years revealed the following: 88.1% of the 12,678 females and 84.9% of the 12,460 males had high school diplomas.

Let \(p_1\) = population proportion of females who had high school diplomas.

\(p_2\) = population proportion of males who had high school diplomas.

(a) So, Null Hypothesis, \(H_0\) : \(p_1\leq p_2\)    {means that females are less or equally likely to graduate from high school than males}

Alternate Hypothesis, \(H_A\) : \(p_1 > p_2\)     {means that females are more likely to graduate from high school than males}

The test statistics that will be used here is Two-sample z-test statistics for proportions;

                        T.S.  =    ~  N(0,1)

where, \(\hat p_1\) = sample proportion of females having high school diplomas = 88.1%

\(\hat p_2\) = sample proportion of males having high school diplomas = 84.9%

\(n_1\) = sample of females = 12,678

= sample of males = 12,460

So, the test statistics =  

                                    =  7.428  

The value of the standardized z-test statistic is 7.428.

Now, at a 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 7.428 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that females are more likely to graduate from high school than males.

(b) Firstly, the pivotal quantity for finding the confidence interval for the difference in population proportion is given by;

                        P.Q.  =  \(\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }\)  ~  N(0,1)

where, \(\hat p_1\) = sample proportion of females having high school diplomas = 88.1%

\(\hat p_2\) = sample proportion of males having high school diplomas = 84.9%

\(n_1\) = sample of females = 12,678

\(n_2\) = sample of males = 12,460

Here for constructing a 95% confidence interval we have used a Two-sample z-test statistics for proportions.

So, 95% confidence interval for the difference in population proportions, (\(p_1-p_2\)) is;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                      of significance are -1.96 & 1.96}    

P(-1.96 < \(\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }\) < 1.96) = 0.95  

P( \(-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }\) < \({(\hat p_1-\hat p_2)-(p_1-p_2)}\) < \(1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }\) ) = 0.95  

P( \((\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }\) < (\(p_1-p_2\)) < \((\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }\) ) = 0.95

95% confidence interval for (\(p_1-p_2\)) = [\((\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }\) , \((\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }\) ]

= [ \((0.881-0.849)-1.96 \times {\sqrt{\frac{0.881(1-0.881)}{12,678}+\frac{0.849(1-0.849)}{12,460}} }\) , \((0.881-0.849)+1.96 \times {\sqrt{\frac{0.881(1-0.881)}{12,678}+\frac{0.849(1-0.849)}{12,460}} }\) ]

= [0.024, 0.404]

Therefore, a 95% confidence interval for the difference in the graduation rates between females and males is [0.024, 0.404] .

(c) The assumptions and conditions necessary for the above inferences to hold are;

Answer:

\(22440=6200e^{0.06T}\)

\(\implies \dfrac{561}{155}=e^{0.06T}\)

\(\implies \ln\dfrac{561}{155}=\ln e^{0.06T}\)

\(\implies \ln\dfrac{561}{155}=0.06T\)

\(\implies T=\dfrac{50}{3}\ln\dfrac{561}{155}\)

\(\implies T=21.43826314...\)

\(22440=6200e^{0.1T}\)

\(\implies \dfrac{561}{155}=e^{0.1T}\)

\(\implies \ln\dfrac{561}{155}=\ln e^{0.1T}\)

\(\implies \ln\dfrac{561}{155}=0.1T\)

\(\implies T=10\ln\dfrac{561}{155}\)

\(\implies T=12.86295789...\)

Answer:

See below

Step-by-step explanation:

y-3=1/2(x+2) Indicates a graph with slope 1/2 that runs through the point (-2,3). I have graphed it below. Hope this helps!

Graph of y - 3 = 1/2 (x + 2) is shown in figure.

Here,

We have to draw the graph of y - 3 = 1/2 (x + 2).

What is Slope of line?

The slope of a line is a number that describes both the direction and the steepness of the line.

Now,

The function is;

y - 3 = 1/2 (x + 2)

Compare with the equation of line,

y - y₁ = m (x - x₁)

Where, m is slope of the line on the graph between any two points and point ( x₁, y₁) are point on graph.

We get the point (-2, 3) and slope 1/2.

Here, Let two points on graph is (-4, 2) and (-6, 1).

Hence, Slope = \(\frac{1-2}{-6 -(-4)} =\frac{1}{2}\)

So, The graph of y - 3 = 1/2 (x + 2) has slope 1/2 and point ( -2, 3 ) on the graph.

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In (2, 7), 2 is the input

Answer:

B) 9  3/8 in

Step-by-step explanation:

The scale model of the model is 1/2 in for 4 feet, or 1 in for 8 feet.

The real light house is 75 feet. Divide 75 with 8:

75 feet/8 feet per inch = 9.375, or 9 3/8 inches.

B) 9  3/8 in. is your answer.

~

Answer:

Becky is 7 years old.

Step-by-step explanation: Let b - Becky's age ; Equation - 3b = 21. Divide both size by 3 to isolate the variable.

Answer:

Becky's 7 seven years old

Step-by-step explanation:

If 21 = 3x

x = 21/3

x = 7

Hope this helps :)

Pls brainliest...

The limits of the function for this problem are given as follows:

In this problem, we are given the graph of the function, hence the limit is given by the value of the function as the function approaches x = a, not the actual numeric value of the function at x = a.

At x = -2, we have that:

As the lateral limits are equal, lim x -> -2 f(x) = 3.

At x = 1, we have that:

As the lateral limits are different, the lim x -> 1 f(x) does not exist.

At x = 4, we have that:

As the lateral limits are equal, lim x -> 4 f(x) = -3.

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Answer: 4.1 gallons to 8.3 gallons

Step-by-step explanation:

just took the quiz

99.7% of the cows will produce an amount of milk in the range is 5.5 gallons to 6.9 gallons option (A) is correct.

It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.

The missing options are:

We have:

A study has shown that the daily amount of milk produced by a dairy cow is normally distributed, with a mean of 6.2 gallons and a standard deviation of 0.7 gallons.

The mean = 6.2 gallons

Standard deviation = 0.7 gallons

The range can be calculated:

Lower range = 6.2 - 0.7 = 5.5 gallons

Upper range = 6.2 + 0.7 = 6.9 gallons

Thus, 99.7% of the cows will produce an amount of milk in the range is 5.5 gallons to 6.9 gallons option (A) is correct.

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Answer: Number 4

Step-by-step explanation: None

Answer:

The answer to 1 + 1 is 2.

Answer:

7/24

Step-by-step explanation:

red counters= 0.25 of all counters so yellow + green= 0.75

7x+11x= 75k

18x=75k

6x= 25k

x=25, k=6

18x= 450 ⇒ 0.75 of all

⇒ total= 450/3*4= 600

green= 7*25= 175

probability of green= 175/600= 7/24

Answer:

the area is 130

Step-by-step explanation:

The area of the rectangle for the given case is obtained as 0.7x².

A linear equation is a equation that has degree as one.To find the solution of n unknown quantities n number of equations with n number of variables are required. A linear equation can be solved by doing operations with the same number on both sides of the equation.

Suppose the length of the rectangle be x.

Then, its width is given as 70% × x = 0.7x.

Since, the area of the rectangle is the product of length and width, the following equation can be written as,

x × 0.7x = 0.7x².

Hence, the required expression for the area of the rectangle is given as 0.7x².

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