which of the following represents a case in which you are not accelerating? group of answer choices driving 100 kilometers per hour around a curve going from 0 to 100 kilometers per hour in 10 seconds driving in a straight line at 100 kilometers per hour slamming on the brakes to come to a stop at a stop sign

Answer:

The forces acting on the root beer is the ice cream. This means that the 'air' in the ice cream keeps it at the top of the root beer enabling it to float right at the top.

The acceleration of a circular track if a car's speedometer reads 32 m/s and the track has a radius of 56 m is 18.29 m / s²

\(a_{c}\) = v² / r

\(a_{c}\) = Centripetal acceleration

v = Linear / Tangential velocity

r = Radius

v = 32 m / s

r = 56 m

\(a_{c}\) = 32² / 56

\(a_{c}\) = 1024 / 56

\(a_{c}\) = 18.29 m / s²

Centripetal acceleration is the acceleration of an object in circular motion. It is always acting to center point with which the object is rotating about. The velocity used in the formula is tangential velocity which acts perpendicular to the motion of the object.

Therefore, the acceleration of a circular track is 18.29 m / s²

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The temperature change produced when 0.35 kg of water is heated using 9600 J is 6.34 °C.

What is Specific Heat Capacity?

Specific heat capacity is the amount of heat energy required to raise the temperature of one unit of mass of a substance by one degree Celsius (or one Kelvin). It is a measure of the substance's ability to store heat energy. The specific heat capacity is a physical property of the substance and is usually denoted by the symbol c.

The amount of heat required to raise the temperature of a substance is given by the formula:

Q = mcΔT

where Q is the amount of heat energy transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

In this problem, we are given:

m = 0.35 kg (mass of water)

c = 4200 J/kg/°C (specific heat capacity of water)

Q = 9600 J (amount of heat energy transferred)

We can rearrange the formula to solve for ΔT:

ΔT = Q/(mc)

Substituting the given values, we get:

ΔT = (9600 J) / (0.35 kg x 4200 J/kg/°C)

ΔT = 6.34 °C

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Answer:

A) 0 V

B) -117 kV

C) -0.468 J

Explanation:

q1=+2.00μC  q2=−2.00μC q3 = -4.00 μC

A) The electric potential at point a due to q1 and q2 (\(V_a\)) is given as:

\(V_a=k\Sigma \frac{q}{r_i} = k(\frac{q_1}{r_1}+\frac{q_2}{r_2} )\\ but\ r_2=r_1=d.\ Therefore\\V_a=k(\frac{q_1}{d}+\frac{q_2}{d} )=k(\frac{2}{d}-\frac{2}{d} )=0\)

B) he electric potential at point b due to q1 and q2 (\(V_b\)) is given as:

\(V_b=k\Sigma \frac{q}{r_i} = k(\frac{q_1}{r_1}+\frac{q_2}{r_2} )\\ but\ r_2=4.5 cm=0.045m,\ r_1=\sqrt{0.045^2+0.045^2}= 0.0636.\ Therefore\\V_b= k(\frac{q_1}{r_1}+\frac{q_2}{r_2} )= 9*10^{9}(\frac{2*10^{-6}}{0.0636}-\frac{2*10^{-6}}{0.045} )=-117\ kV\)

C) The work done on q3 by the electric forces exerted by q1 and q2 (W) is given by:

\(W=q_3(V_a - V_b)=-4*10^{-6}(0-(-117*10^3))=-0.468\ J\)

Answer:

ANSWER IS A CONVECTION

B CONDUCTION

Point A heat transfer as steam is type of a convection heat transfer

Point B a source is the type of conduction heat transfer

Conduction = It is a process of heat transfer in which energy is transferred between successive molecules For example If we put the one end of the spoon to the boiling water then other end also become hot due to conduction.

Convection = It is type of heat transfer in which the heat flows due to movement of molecules or convection currents. convection heat transfer takes place in water and gases.

Just like this at point B the heat is transferred from one molecule to other which is conduction.

And point A heat transferred from steam which is convection as explained in above definition.

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To solve this problem, we can use the formula for the period of oscillation of a spring-mass system:

T = 2π√(m/k)

where T is the period of oscillation, m is the mass attached to the spring, and k is the spring constant.

We are given that T = 2.4 seconds and k = 100 N/m. Substituting these values into the formula, we get:

2.4 = 2π√(m/100)

Squaring both sides and rearranging, we get:

m = (100/4π²) × (2.4²) = 12.3 kg (rounded to one decimal place)

Therefore, the mass attached to the spring is 12.3 kg.
Hi! I'd be happy to help you with your question. To find the mass attached to the spring, we need to use the formula for the period of a spring-mass system: T = 2π√(m/k), where T is the period (time for one oscillation), m is the mass, and k is the spring constant.

In this case, the spring constant (k) is 100 N/m, and the period (T) is 2.4 seconds. We can rearrange the formula to solve for the mass (m):

m = (T^2 * k) / (4π^2)

Substitute the given values into the formula:

m = (2.4^2 * 100) / (4π^2)
m ≈ (5.76 * 100) / (39.48)
m ≈ 14.61

The mass attached to the spring is approximately 14.61 kg.

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Answer:

D.

a control group

Explanation:

In a scientific experiment such as the one above, there is an experimental group and a control group. The experimental group is the group that receives the treatment while the control group does not receive any treatment. The control group helps the researcher to observe if the treatment had any significant effect.

In this case, it will help Alan and Monica to determine if fertilizer X actually had an effect on the plant. Therefore, the pot with o grams of fertilizer in it is the control group.

Answer:

daylight savings time

Explanation:

it's because the weather changes

The painter can stand no closer than 9.19 times the length of the board from the end of the board without tipping it over.

The weight of the painter acts downward at a distance of x/2 from the center of the board, and the weight of the board itself acts downward at a distance of L/2 from the center of the board.

The torque due to the weight of the painter is given by:

Tpainter = (mg)(x/2)

The torque due to the weight of the board is given by:

Tboard = (Mg)(L/2)

For the board to be in rotational equilibrium, these two torques must balance each other, so we have:

Tpainter = Tboard

Substituting the expressions for the torques and solving for x, we get:

(mg)(x/2) = (Mg)(L/2)

x = (ML)/m

Substituting the given values, we get:

x = (25 kg) (L)/ (68 kg)

x = 9.19 L

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Answer:

47.515 cm²

In meter square= 4.7515 *10^-3 m²

Explanation:

The radius of a circle = 5.5 cm

In meter= 5.5*0.01

= 0.055 m

the circumference= 34.56 cm

in meters = 34.56 cm*0.01

= 0.3456 meters

the area= 95.03 cm²

in square meters =95.03*(0.01)²

in square meters= 9.503*10^-3 m²

. area under the curve at the right

= Area of semi circle

= Area of circle/2

= 95.03 /2

= 47.515 cm²

In meter square= 4.7515 *10^-3 m²

There is 16 m gap between the deer and the car.

We know that the acceleration is the rate of change of the velocity with time. Let us recall that the acceleration is a vector quantity and the direction is important here. Now, we have the following;

Initial velocity = 21 m/s

Final velocity = 0 m/s

Acceleration = 10 m/ s 2

Distance = 38 m

Given that we want to obtain the distance, we have to use;

V^2 = u^2 - 2as

Now v = 0 m/s because the object comes to a stop

v = final velocity

u = initial velocity

a = acceleration

s = distance covered

s = u^2 /2a = ( 21 m/s)^2/ 2 * 10 m/ s 2

= 22  m

The distance that is left between you and the deer = 38 m -  22  m = 16m

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Answer: its D

Explanation:

because the car is pulling it(trailer) to the left not the right

Explanation:

Find an energy is E =mgh, so E = 45*10*19=8550j

Answer:

erupting volcanoes and oozing fissures

Explanation:

The movement of wave can be detected using scientific instruments.

One such example is Seismometer.

Thus, the statement is false.

A) To determine the coefficient of static and kinetic friction, we can use the given information. The maximum force of 313 N is the threshold where the crate just begins to move. This force is equal to the maximum static friction. The force of 208 N is the force required to keep the crate moving at a steady speed of 25.0 cm/s, which corresponds to the kinetic friction.

Coefficient of static friction (μs):

The maximum static friction force is given by μs times the normal force. The normal force is equal to the weight of the crate, which can be calculated as the mass times the acceleration due to gravity (9.8 \(m/s^2).\) Therefore, we have:

313 N = μs * (39.0 kg * 9.8 \(m/s^2).\))

Solving for μs, we find: μs = 313 N / (39.0 kg * 9.8 \(m/s^2)\)

Coefficient of kinetic friction (μk):

The kinetic friction force is given by μk times the normal force. We already know that the force of kinetic friction is 208 N, and the normal force is the same as before. Therefore, we have:

208 N = μk * (39.0 kg * 9.8 \(m/s^2\))

Solving for μk, we find: μk = 208 N / (39.0 kg * 9.8 \(m/s^2)\)

B) To find the push required to give the crate an acceleration of 1.10 \(m/s^2)\) we need to consider the net force acting on the crate. The net force is equal to the applied force minus the force of kinetic friction. Therefore:

Net force = ma = \(F_applied\) - \(F_kinetic\)

Solving for the applied force, we have:

\(F_applied\) = ma + \(F_kinetic\)

Substituting the given values, we have:

\(F_applied\) = (39.0 kg)(1.10 \(m/s^2\) + 208 N

C) On the moon, where the acceleration due to gravity is 1.62 \(m/s^2\), the weight of the crate would change. The force required to move the crate on the moon would be the sum of the gravitational force and the force of kinetic friction. Therefore:

Force = mg + \(F_kinetic\)

Substituting the given values, we have:

Force = (39.0 kg)(1.62 \(m/s^2\)) + 208 N

D) If the push from part B is maintained, the acceleration of the crate would be zero since the net force (applied force minus the force of kinetic friction) would be zero.

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Answer:

v = 30 m/s

Explanation:

KE = (1/2)*m*v²

675,000J = .5*1500kg* v²

v² = (675,000J)/750kg

v = sqrt(900)

v = 30 m/s

Answer:

the initial force exerted on the rocket is 900 N

Explanation:

The computation of the initial force exterted on the rocket is shown below:

Force exerter = Rate of change of momentum

= 300 m/s × 3kg/s

= 900 N

hence, the initial force exerted on the rocket is 900 N

we simply multiplied the rate with its speed so that the force could come

Answer:

Below

Explanation:

To convert mm to m all you need to do is divide the value by 1,000

so : 3 / 1,000 = 0.003 meters

Hope this helped!

The force vector on the electron at this instant can be calculated using the Biot-Savart Law and Lorentz Force Law.

The magnitude of the force vector is F = |q|vBsinθ, where F is the force, q is the charge of the electron, v is its speed, B is the magnetic field, and θ is the angle between v and B.


1. Calculate the magnetic field B at the electron's position using the Biot-Savart Law: B = (μ₀I)/(2πr), where μ₀ is the permeability of free space (4π x 10⁻⁷ Tm/A), I is the current (9 A), and r is the distance from the wire (2 x 10⁻³ m).

2. Determine the angle θ between the electron's velocity vector and the magnetic field vector. In this case, θ = 90°, as the velocity vector is perpendicular to the magnetic field vector.

3. Calculate the force magnitude using F = |q|vBsinθ, where q is the elementary charge (-1.6 x 10⁻¹⁹ C), v is the electron's speed (3 x 10⁷ m/s), and sinθ = sin(90°) = 1.

4. Finally, express the force vector in terms of its components.

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The kinetic energy of an object with a mass of 30 kilograms and a velocity of 20 m/s is 12,000 joules.

The formula to calculate kinetic energy is given by:

Kinetic Energy = 1/2 * mass * velocity^2

Substituting the given values into the formula:

Kinetic Energy = 1/2 * 30 kg * (20 m/s)^2

              = 1/2 * 30 kg * 400 m^2/s^2

              = 6,000 kg·m^2/s^2

              = 6,000 joules

Therefore, the kinetic energy of the object is 6,000 joules.

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The bowling ball experiences the greater magnitude impulse during the collision since it is initially at rest and is given the momentum of the small ball which has a speed of 5m/s.

The impulse of the bowling ball can be calculated using the equation impulse = change in momentum = mvf - mvi, where m is the mass of the bowling ball, vf is its final velocity, and vi is its initial velocity.

Since the bowling ball is initially at rest (vi = 0), the impulse can be calculated as mvf = m(5m/s) = 5m^2/s. The impulse of the small ball can be calculated in the same way, giving an impulse of 5m^2/s. Therefore, the bowling ball experiences a greater magnitude impulse during the collision.

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Answer:

I'm not 100% sure but I think its Cell membrane

Explanation:

please, correct me if i'm wrong.

The value of length of secant DE in the intersecting secants is determined as 21.3.

The length of segment DE is calculated by applying the following theorem of intersecting secants.

This theorem states that the product of two secants of a chord is equal to the product of the two secants of the second chord.

From the given diagram, we will have the following equation;

(whole secant) (external part) = (whole secant) (external part)

BF x (FC) = EF x ( FD)

The given parameters;

length CB = 13

length BF = 9

length EF = 7

Length FD = DE + EF = DE + 7

Length FC = CB + BF = 13 + 9 = 22

The value of length of DE is calculated as follows;

9 x 22 = 7(DE + 7 )

198 = 7DE + 49

7DE = 149

DE = 149/7

DE = 21.3

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The missing diagram is in the image attached.

Nebulae are red because of the Balmer line, which is created when ionized hydrogen catches an electron and turns back into neutral hydrogen. Ionized hydrogen, which is abundant in nebulae.

In space, a supernova is a huge cloud of gas and dust. Some nebulae, including multiple nebulae, are made of gas and dust that have been released from the exploding of a dead star called a supernova. There are other nebulae that are star-forming regions.

The nebular theory proposes that a swirling cloud of dust, known as a nebula, composed primarily of light components, condensed into a planetary nebula, and eventually developed into a solar system made up of a star and planets in orbit.

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The major ionic species present in an aqueous solution of FeCl3 is Fe³⁺.

Conventionally, the charge of an electron is thought to be negative; this charge is equal to and opposite to the charge of a proton, which is thought to be positive. Because the total number of electrons in an ion is more than the total number of protons, the net charge of an ion is not zero.

A negatively charged ion called an anion has more electrons than protons compared to a positively charged ion called a cation. Electrostatic force causes opposite electric charges to be drawn towards one another, causing cations and anions to attract one another and easily form ionic compounds.

Hence, The major ionic species present in an aqueous solution of FeCl3 is Fe³⁺.

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Answer:

234 oz = 0.0066339 t.

Explanation:

Boom Logic...

Answer:

\(R_s = 0.093 \Omega\)

Explanation:

Voltage of the car battery = 12.0 V

Voltage drop in the battery = 3.4 V

The remainder of the voltage is the starter voltage, that is:

Starter voltage = Initial battery voltage - voltage drop

Starter voltage = 12.0 - 3.4

Starter voltage, \(V_{s}\) = 8.6 V

Current drawn by starter, \(I_s\) = 93 A

According to Ohm's law: \(V_s = I_s R_s\)

Starter Resistance, \(R_s\) = \(V_s/I_s\)

\(R_s = 8.6/93\\R_s = 0.093 \Omega\)

The average force on the squid during the ejection of 0.60 kg of water at a velocity of 15.0 m/s in 0.15 seconds is 60 N.              

We can calculate the average force with the average acceleration as follows:

\( F = m\overline{a} \)   (1)

Where:

The average acceleration is given by the change of velocity in an interval of time

\( \overline{a} = \frac{v_{f} - v_{i}}{t_{f} - t_{i}} \)   (2)

Where:

Now we can find the average force after entering equation (2) into (1)

\( F = m(\frac{v_{f} - v_{i}}{t_{f} - t_{i}}) = 0.60 kg(\frac{15.0 m/s - 0}{0.15 s}) = 60 N \)  

Therefore, the average force on the squid during the propulsion is 60 N.

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I hope it helps you!