Which of the following molecules is correctly paired with its macromolecule class? (2 points)
Enzyme-nucleic acid
Cholesterol-protein
Glycogen-protein
RNA-nucleic acid

Explanation:

Using a derivative of the combined gas law we can explain what is happening in both instances.

Assuming that the volume is constant which is predicated on the bottle shape and structure, the pressure of a given mass of gas varies directly with the absolute temperature.

As temperature increases, the pressure also increases and vice versa.

Answer:

-1300. kJ  

Explanation:

We have two equations:

1. P₄(s)       +3O₂(g) ⟶ P₄O₆(s);                 ΔH₁  = -1640.1 kJ

2. P₄O₁₀(s)               ⟶ P₄(s)      + 5O₂(g); ΔH₂ =  2940.1 kJ

From these, we must devise the target equation:

3. P₄O₆(s)  + 2O₂(g) ⟶ P₄O₁₀(s);               ΔH = ?

The target equation has P₄O₆(s) on the left, so you reverse Equation 1.

When you reverse an equation, you reverse the sign of its ΔH.

4. P₄O₆(s)                 ⟶ P₄(s)       +3O₂(g); ΔH₁  =  1640.1 kJ

Equation 4 has P₄ on the right. That is not in the target equation.

You need an equation with P₄ on the left, so you reverse Equation 2.  

5. P₄(s)      + 5O₂(g)  ⟶ P₄O₁₀(s);               ΔH₂ = -2940.1 kJ

Now, you add equations 4 and 5, cancelling species that appear on opposite sides of the reaction arrows.

When you add equations, you add their ΔH values.

You get the target equation 3:

4. P₄O₆(s)                      ⟶ P₄(s)        + 3O₂(g);      ΔH₁ =   1640.1 kJ

5. P₄(s)       + 2(5)O₂(g) ⟶ P₄O₁₀(s);                       ΔH₂ = -2940.1 kJ

3. P₄O₆(s)   + 2O₂(g)     ⟶ P₄O₁₀(s);                       ΔH   = -1300.  kJ

ΔH for the reaction is -1300. kJ

Answer:

the troposphere because we are living in atmosphere when the atmosphere next troposphere the sudden flashes of light and discharge resulting atmosphere condition sound waves of trambeling

thank you

Answer:

While many of the subjects became extremely agitated, distraught, and angry at the experimenter, they nevertheless continued to follow orders all the way to the end. Milgram's results showed that 65% of the participants in the study delivered the maximum shocks.

Explanation:

Answer:

Zinc metals was oxidized ,zinc ions were reduced

Explanation:

The zinc atoms lose electrons and becomes oxidized . And zinc ions gain electrons (becomes reduced)

The redox reaction taking place here, is the zinc metal is oxidized and zinc ions are reduced further by accepting electrons. Hence, option a is correct.

In a redox reaction, one reactant species is oxidized and another one is reduced. Oxidation is the process of loss of one or more electrons to form its higher oxidation state.

Reduction is the process of gaining electrons forming its lower oxidation state. The species which undergoes oxidation is called oxidant and the one reduced is called reductant.

Zn metal have higher negative electrode potential and undergoes oxidation by losing two electrons to form the Zn²⁺ ions. Thus the Zn metal is oxidized.  The Zn²⁺ ions further undergoes reduction to form the metal by gaining electrons.

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The correct statement among the options is that

Gina should put “rubber tires” under “Synthetic.”

Gina should put “starch” under “Natural.”

A polymer is a natural polymer if the polymer is only composed of the compounds that occur in nature. We know that there are several polymers that occur in nature and a lot of these naturally occurring polymers are also known to have biological origin and can even be found in the body of organisms as it were.

We know that a polymer is composed of small molecules that come together. These small molecules that come together are what we call the monomers that compose the polymer.

A polymer is synthetic if it is composed of the compounds that do no occur in nature. These are the polymers that are compose of the monomers that may be produced in the laboratory or are the products of other industrial process.

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Answer:

C & D

Explanation:

Gina should put “rubber tires” under “Synthetic.”

Gina should put “starch” under “Natural.”

Answer:

if we look closer we can see that many being 50

There are approximately 1.615 x 10^24 zinc atoms in a piece of zinc that has a mass of 175 g.

We need to use the molar mass of zinc, which is 65.38 g/mol. This means that for every 65.38 grams of zinc, there is 1 mole of zinc atoms, which contains 6.022 x 10^23 atoms.

To find out how many zinc atoms are in a piece of zinc that has a mass of 175 g, we first need to calculate how many moles of zinc are in 175 g:
175 g / 65.38 g/mol = 2.68 mol of zinc
Next, we can use Avogadro's number (6.022 x 10^23) to calculate the number of zinc atoms
2.68 mol x 6.022 x 10^23 atoms/mol = 1.615 x 10^24 atom

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Answer:

i think it is a the full moon

By create calibration curve.

What is calibration curve?

In many different disciplines, such as analytical chemistry and biochemistry, calibration curves are frequently utilized. A calibration curve is used to calculate the limit of detection and the limit of quantitation, as well as the concentration of an unknown material. The instrument response to a series of standard samples at various concentrations is used to produce the curve. To enable the prediction of unknown concentrations, the data are then fitted with a function.

A calibration curve can be used to figure out the concentration of an unidentified medication. By comparing these curves to data from known medications at different doses, researchers and developers can utilise them to establish where an unfamiliar compound plots. A spectrophotometer is used to collect absorbance for varied concentrations.

This method of identifying unknown substances can be advantageous to numerous industries. For instance, coffee roasting might make use of a calibration curve. A plot can be used by roasters to estimate a bean's caffeine spectrum. Gelatin's food colour content could be displayed on a calibration curve for the food industry.

Additional applications include

production of chemicals, plastics, paints, and cosmetics

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Answer:

Ionic Bonds are formed from metal to nonmetals. Covalent Bonds usually form from nonmetals.

Explanation:

Answer:

speed= 0.14km/h

Explanation:

it is 9 feet 10 inches long by 9 feet 1 inch wide

has 4 main science goals

-Determine whether life arose on Mars

-Characterise the climate of Mars

-characterise the geology of Mars

-prepare for human exploration

Answer:

i am not sure but its 2 ican"t qry

Explanation:

The value of Gibbs free energy is 143876.5 joules

The maximum amount of work that can be accomplished by a thermodynamically closed system at constant temperature and pressure can be calculated using the Gibbs free energy (also known as Gibbs energy; symbol: Δ G). Additionally, it offers a prerequisite for any processes like chemical reactions that might take place in such circumstances.

The maximum amount of non-expansion work that can be taken from a closed system (one that may exchange heat and work with its surroundings but not matter) at fixed temperature and pressure is known as the Gibbs free energy change (ΔG =ΔH - TΔS), measured in joules in SI. This maximum is only possible with a fully reversible method. Under these circumstances, when a system changes reversibly from an initial state to a final state, the reduction in Gibbs free energy is equal to the work performed by the system on its surroundings less the work of the pressure forces.

ΔH=-158 kj = enthalpy change

T=655k = temperature

ΔS=-219.9 j/k = entropy

ΔG =ΔH - TΔS

     =-158 -(655 x -219.9)

    = -158 -(-144034.5)

    =143876.5 joules

so, the value of Gibbs free energy is 143876.5 joules

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Answer:

In the 1970s, Epel and other researchers showed that calcium is the essential factor that sparks development in eggs. As calcium levels rise, metabolic changes occur that cause the egg to divide and form into an embryo.

Explanation:

The \(K_s_p\) of \(BaCrO_4\) is \(1.2 *10^{-10}\). \(BaCrO_4\) will not precipitate upon mixing 10 ml of  \(1*10^{-4} M\ Ba(NO_3)_2\)  with 10 ml of  \(1*10^{-4 }m\ K_2CrO_4\).

BaCrO4 will precipitate upon mixing the two solutions.

To determine if \(BaCrO_4\) will precipitate upon mixing 10 mL of \(1*10^{-4} M\)\(Ba(NO_3)_2\) with 10 mL of \(1*10^-^4 M\) \(K_2CrO_4\), we need to compare the ion product (IP) of \(BaCrO_4\) with its solubility product constant (\(K_s_p\)).

The ion product (IP) is calculated by multiplying the concentrations of the ions involved in the precipitation reaction. In this case, the ions are \(Ba^2^+\)and \(CrO_4^2\)-.

IP = \([Ba^2^+][CrO_4^2^-]\)

Given that both solutions have a concentration of 1x10^-4 M, the IP can be calculated as:

\(IP = (1*10^-^4)(1*10^-^4) = 1*10^-^8\)

Comparing the IP with the \(K_s_p\), if the IP is greater than the \(K_s_p\), precipitation will occur. If the IP is less than the \(K_s_p\), no precipitation will occur.

In this case, the \(K_s_p\) for \(BaCrO_4\) is \(1.2*10^-^1^0\), and the IP is \(1*10^-^8\). Since the IP is less than the \(K_s_p\),  will not precipitate upon mixing the two solutions.

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1 meter = 1000 km

2500 meter = 2500/1000 km

= 2.5 km

Answer:

Yes. Since for a substance to be a Bronsted-Lowry acid they have to be able to donate protons, and to be a Lewis acid a substance would have to accept electrons, there are substances which cannot donate protons but can accept electrons.

Explanation:

Hope this helped!

Answer:

1.08 x 10^2 gm of H2O

Explanation:

number of moles of O2 = 97g /32 g/moles = 3.03 moles

3.03 moles of O2 produces 6.06 moles of H2O

amount of water produced = 6.06 mol x 18 g /mol = 109.08 g = 1.08 x 10^2 g

Answer:

n=m/M

n=48/32

n=1.5 moles

the correct answer is B

Answer:

\(\large \boxed{\text{3.45 L}}\)

Explanation:

We will need a balanced chemical equation with molar masses, so, let's gather all the information in one place.

Mᵣ:       122.55

           2KClO₃ ⟶ 2KCl + 3O₂

m/g:       25.5

(a) Moles of KClO₃

\(\text{Moles of KClO}_{3} =\text{25.5 g KClO}_{3} \times \dfrac{\text{1 mol KClO}_{3}}{\text{122.55 g KClO}_{3}} = \text{0.2081 mol KClO}_{3}\)

(b) Moles of O₂

The molar ratio is 3 mol O₂:2 mol KClO₃

\(\text{Moles of O$_{2}$}= \text{0.2081 mol KClO}_{3} \times \dfrac{\text{3 mol O$_{2}$}}{ \text{2 mol KClO}_{3}} = \text{0.3121 mol O$_{2}$}\)

(c) Volume of O₂

We can use the Ideal Gas Law to calculate the volume of hydrogen.

pV = nRT

T = (25.44 + 273.15) K =  298.59 K

\(\rm V = \dfrac{nRT}{p}= \dfrac{\text{0.3121 mol $\times$ 0.0821 L$\cdot$atm$\cdot$K$^{-1}$mol$^{-1}\times$ 298.59 K}}{\text{ 2.22 atm}} = \textbf{3.45 L} \\\\\text{The volume of oxygen is $\large \boxed{\textbf{3.45 L}}$}\)

Answer:

Solution:-

The balanced equation:

2KClO3 (s)  \rightarrow 2KCl (s) + 3 O2 (g)

Molar mass of KClO3 = 122.55 g/mol

Number of moles of KClO3 = (Mass of KClO3 / Molar mass of KClO3) = (25.5 g / 122.55 g/mol) = 0.2081 mol

From balanced equation, 2 mol of KClO3 produce 3 mol of O2. Or, 1 mol of KClO3 produces (3/2) mol of O2.

therefore, 0.2081 mol of KClO3 will produce = (3/2) × (0.2081) = 0.3121 mol of O2

Now, we have number of moles (n) of O2 = 0.3121 mol

Pressure (P) = 2.22 atm

Temperature (T) = 25.44°C = (273.15 + 25.44) K = 298.59 K

R (Gas constant) = 0.0821 L.atm/mol.K

Volume (V) of O2 = ?

Using the ideal gas equation,

V = nRT / P

Substituting the values in the equation, we get :

V = (0.3121 mol × 0.0821 L.atm/mol.K × 298.59 K) / (2.22 atm) = 3.45 L

Hence, the volume of O2 gas produced = 3.45 L

Explanation:

Answer:

7.56°C is the temperature when the gas occupies 400cm³

Explanation:

Based on Charles's law, the volume of a gas is directly proportional to its absolute temperature under constant pressure. The equation is:

V₁T₂ = V₂T₁

Where V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.

Computing the values:

V₁ = 560cm³

T₂ = ?

V₂ = 400cm³

T₁ = 120°C + 273.15 = 393.15K

560cm³*T₂ = 400cm³*393.15K

T₂ = 280.71K - 273.15 =

A constant voltage rectifier is normally adjusted by changing the secondary transformer taps. Therefore the correct option is option D.

The secondary transformer taps control the rectifier circuit's output voltage. The voltage level of the output of the transformer can be changed to a desired value by choosing various taps on the secondary winding.

The output voltage is unaffected by changing the primary transformer taps, which are utilised to match the input voltage to the rectifier circuit. Although they do not directly affect the output voltage level, series and parallel resistors are employed to manage the current flow and the ripple in the output voltage.

In rectifier circuits, the third transformer taps are not frequently employed. Therefore the correct option is option D.

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Answer:

Presence of an Electrolyte

Metal Surface

Oxygen or Other Oxidizing Agent

Difference in Potential

Electrochemical Pathway

Explanation:

Answer:

Word equation carbon + oxygen → carbon dioxide

Chemical equation C + O2 → CO2

Fingerprints on the cuvet in spectrophotometry can block the path of light, leading to lower calculated concentrations than are actually present. Therefore, it is crucial to maintain clean cuvets and avoid touching them with bare hands to ensure accurate and reliable results in spectrophotometric analysis.

It is important to not have fingerprints on the cuvet in spectrophotometry because fingerprints can block the path of light, leading to incorrect readings and affecting the accuracy of the analysis. Spectrophotometry is a technique that measures the absorption or transmission of light by a substance at different wavelengths.

It is commonly used in various scientific fields, including chemistry and biology, to determine the concentration of a substance in a solution.

Fingerprints on the cuvet act as barriers to the light passing through the sample. As a result, the light cannot fully reach the detector, causing a decrease in the measured absorbance. This leads to lower calculated concentrations than are actually present in the solution being analyzed.

The presence of fingerprints introduces an additional source of interference that can significantly impact the accuracy and reliability of the experimental results.

To ensure accurate measurements, cuvets should be handled with clean gloves or using other appropriate means to avoid leaving fingerprints. Cuvets should also be cleaned thoroughly before each use to remove any residue that could interfere with the transmission of light.

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A primary explosive is a sensitive explosive that almost always explodes with a single ignition from a primary heat source of sufficient intensity, such as a spark, flame, impact, or other primary heat source.

Primary explosives can explode as a result of a spark or a relatively weak mechanical stress. They start the primary explosive when used as blasting caps (detonators). Additionally, they are loaded with friction-mixed materials and other ingredients in percussion caps.

A highly brisant starting explosive with a high triggering velocity is required. Mercury fulminate, lead azide, lead trinitroresorcinate, silver azide, diazodinitrophenol, and tetrazene, which is a primer additive, are the most significant primary explosives.

Only if they have already been pressed into capsules must initiation charges be transported.

Therefore, A primary explosive is a sensitive explosive that almost always explodes with a single ignition from a primary heat source of sufficient intensity, such as a spark, flame, impact, or other primary heat source.

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Answer:

heat

Explanation:

Answer: .5m

Explanation:

Conduction is the process through which heat is transferred from an object's hotter end to its cooler end. A hotter body naturally transfers heat to a cooler body.

Convection is single- or multiphase fluid flow that develops on its own as a result of the interaction between a fluid's body forces—most frequently gravity and density—and material property heterogeneity.

Thermal radiation is electromagnetic energy released when matter particles move thermally. When heat from the movement of charges in the material is converted to electromagnetic radiation, thermal radiation is produced. Thermal radiation is emitted by all matter that has a temperature higher than absolute zero.

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Answer: Fluorine

Explanation:   There are many variables that can affect the strenght of attraction of the electrons in a chemical bond.

The most significant of them is the electronegativity: a meassure of the affinity an element has with the electrons . The higher the electronegativity, the stronger the attraction with electrons.

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