Which of the following Lewis structure is invalid (because it breaks the octet rule or because it uses too many/too few electrons?

Answer:

62.6

Explanation:

formula = (°C x 9/5) + 32

(17°C x 9/5) + 32

30.6 + 32

62.6

Answer:the process of dissovlving makes the ecectrons in their atoms more closely bound

Explanation:

thats what my lesson said

The solution of water and salt are good conductor of electricity because the process of dissolving makes the electrons in their atoms free to move.

The correct option is (A).

Pure water and salt are bad conductor of electricity.

But the solution of water and salt is a good conductor because when a salt's dissociated it's ions are free to move about in solution when it dissolves, allowing a charge to flow freely.

Because it includes ions, the resulting solution will conduct electricity.

Thus, option (A) the process of dissolving makes the electrons in their atoms free to move, that's why the solution of water and salt are good conductor of electricity.

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Equivalent of sulfate ions = 4.00 EqSO4^2−

1) equivalent weight of sulphate = 96.0636/2

= 48.0328 g/equivalent

2) 2 mol will have a weight of = 2*96.0636 = 192.1272 g

3) so the equivalent of sulphate = 192.1272/48.0328

= 3.999, round it up to 4.00

Sulfur and oxygen atoms make up the majority of the sulphate ion's mass. Four oxygen atoms that are placed at equal intervals around the centre sulphur atom in this structure. In terms of bonding, two oxygen atoms make S=O bonds, while the other two form S-O bonds.

Two double bonds and two single bonds with O make up the more stable structure of SO42-, however the single bonds have a formal charge of -1.

An insoluble precipitate of BaSO4 forms when aqueous barium chloride is introduced to an acidified solution containing sulphate ions. This precipitate, which is white in colour, proves that sulphate is present.

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Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

The molarity of the dilute solution prepared by taking 10 mL of the concentrated solution is 0.08 M

The following data were obtained from the question give above:

The molarity of the diluted solution can be obtained by using the dilution formular as shown below:

M₁V₁ = M₂V₂

2 × 10 = M₂ × 250

20 = M₂ × 250

Divide both side by 250

M₂ = 20 / 250

M₂ = 0.08 M

Thus, we can conclude from the above calculation that the molarity of the diluted solution is 0.08 M  

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Answer:

First of all, you should write the given .

Explanation:

And then, formula then write step by step. Your answer will be there.

The vapor pressure is obtained as 3.7 atm.

The Clausius-Clapeyron equation is the equation that we could use to obtain the vapor pressure of a solution at any temperature. Of course we would always have two different temperatures to work with.

Hence;

ln(P1/P2) = ΔHvap/R (1/T2 - 1/T1)

P1 = initial pressure

P2 = final pressure

ΔHvap =  enthalpy of vaporization

T2 = final temperature

T1 = initial temperature

ln(1/P2) = 35.2 * 10^3/8.314 (1/338 - 1/307)

ln(1/P2) = 4234(0.00295 - 0.00326)

ln(1/P2) = -1.31

1/P2 = e^-1.31

P2 = 1/e^-1.31

P2 = 3.7 atm

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Answer:

Explanation:

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is:

HCl(aq) + NaOH(s) → NaCl(aq) + H2O(l)

From the balanced equation, we can see that one mole of hydrochloric acid reacts with one mole of sodium hydroxide to produce one mole of sodium chloride and one mole of water.

First, we need to determine which reactant is limiting, i.e., which reactant is completely consumed in the reaction. To do this, we need to compare the number of moles of each reactant, using their respective molar masses:

Molar mass of HCl = 1.008 g/mol (atomic weight of hydrogen) + 35.45 g/mol (atomic weight of chlorine) = 36.46 g/mol

Molar mass of NaOH = 22.99 g/mol (atomic weight of sodium) + 16.00 g/mol (atomic weight of oxygen) + 1.008 g/mol (atomic weight of hydrogen) = 39.99 g/mol

Number of moles of HCl = mass / molar mass = 30.0 g / 36.46 g/mol ≈ 0.823 mol

Number of moles of NaOH = mass / molar mass = 14.3 g / 39.99 g/mol ≈ 0.358 mol

Since the stoichiometric ratio between HCl and NaOH is 1:1, NaOH is the limiting reactant because it has fewer moles than HCl.

Therefore, we can calculate the maximum mass of NaCl that can be produced by the reaction using the number of moles of NaOH:

Number of moles of NaCl produced = number of moles of NaOH used in the reaction = 0.358 mol

Mass of NaCl produced = number of moles of NaCl produced x molar mass of NaCl

Molar mass of NaCl = 22.99 g/mol (atomic weight of sodium) + 35.45 g/mol (atomic weight of chlorine) = 58.44 g/mol

Mass of NaCl produced = 0.358 mol x 58.44 g/mol = 20.9 g

Therefore, the maximum mass of NaCl that can be produced by the reaction is approximately 20.9 g

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

5.916x10⁻³ mol OH⁻

Explanation:

The reaction that takes place is:

First we calculate the added moles of each reagent, using the given volumes and concentrations:

Now we calculate how many KOH moles reacted with 3.967 mmol H₂SO₄:

Finally we calculate how many OH⁻ moles remained after the reaction

Answer:

N2O5

Explanation:

1. Convert to moles

24.5g N * 1mol/14g = 1.75

70.0g * 1mol/16g = 4.375

2. Divide each value by the smallest

1.75/1.75 = 1

4.375/1.75 = 2.5

3. Multiply each by a whole number so that they are both whole numbers

1*2 = 2

2.5*2 = 5

4. These are moles of elements present in the compound

Answer: N2O5

Question: You decompose a compound containing nitrogen and oxygen in the laboratory and produce 24.5 g of nitrogen and 70.0 g of oxygen. Calculate the empirical formula of the compound.

Answer:

4.62 g of Ag (silver).

Explanation:

What is given?

Mass of Cu (copper) = 734 g.

Mass of AgNO3 (silver nitrate) = 7.27 g.

Molar mass of Cu = 63.5 g/mol.

Molar mass of AgNO3 = 170 g/mol.

Molar mass of Ag = 108 g/mol.

Step-by-step solution:

First, let's state the chemical equation with copper (Cu) and silver nitrate (AgNO3) reacting:

Now, let's find the number of moles of each reactant using their molar mass:

Now, let's see how many moles of Ag are being produced based on the number of moles that we found in each reactant.TBy doing this calculation, we will find the limiting reactant.

You can see in the chemical equation that 1 mol of Cu reacted, produces 2 moles of Ag, so the moles of Ag produced are:

And you can see that moles of Ag NOa reacte, produces2 moles of Ag too. This means that the mola r ratio betwee tehem is 22, more simply sis 1:1. This is telling u that 0.0428 moles of AgNO3 will produce 0.00428 moles of Ag too.

In this case, as you can see the limiting reactant is AgNO3because this is tbeing consumed first in the reaction, so the final step is to find the mass using its molar mass. The conversion from 0.0428 moles of Ag to mass in grams is:

The answer is that we're producing 4.62 g of Ag (silver).

Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

Answer:

Your answer would be 6

Answer:

1 it is 1

Explanation:

Answer: 4

Explanation: because the zero doesn't count

ideal gas

PV=nRT

T = PV/nR

T = 1 x 12/9 x 0.08205

T = 16.25 K

Explanation:

\(d = \frac{m}{v} \\ m = d \times v \\ m = 0.791 \times 750 \\ m = 593.25 \: g\)

There are 3.44 x 10^{22} particles in 0.057 moles of lithium bromide.

The lithium bromide formula also known as the lithium monobromide formula or Bromo lithium formula is explored. It is a counterion bromide-based salt of lithium.

we have to use Avogadro's constant,

Avogadro's constant, is approximately equal to 6.022 x 10^{22} particles per mole.

we can use the following formula:

number of particles = moles x Avogadro's constant

Substitute the values,

number of particles = 0.057 moles x 6.022 x 10^{23} particles/mol

Simplifying the equation

number of particles = 3.44 x 10^{22} particles

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Answer:

copper - 52 (or Cu - 52)

⁵²Cu

Explanation:

Isotopes are different atoms of the same element that differ in the number of neutrons. Therefore, you can determine which element this is by examining the number of protons. All atoms with 29 protons are copper (Cu).

The mass number is the total number of protons and neutrons in an atom. Therefore, the mass number of this isotope is 52 (29 + 23 = 53). When writing an elemental symbol, the mass number is found on the top left.

As such, the name of this isotope is copper - 52 (or Cu - 52) and the symbol is ⁵²Cu.

When there is an increase in an activity, like sales or manufacturing, the overall amount of an expense, known as a fixed expense, does not change.

Thus, Normal definitions typically include the phrase within a relevant or appropriate range of activity since a change is likely to take place at fixed expense either an exceptionally high or low volume or expense.

Of course, the rent will probably need to adjust if sales quadruple or fall to 20% of the average level. However, as the extreme circumstances are outside of the relevant range for short-term analysis, the current rent of $2,000 is regarded as a fixed expense.)

The following are some instances of costs that are probably set within a fair range of retail sales, The yearly pay for the shop manager.

Thus, When there is an increase in an activity, like sales or manufacturing, the overall amount of an expense, known as a fixed expense, does not change.

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The ph value of human saliva is between 6.2-7.6 with 6.7 being the average pH

ph value of human saliva is 7 and 6

By using filtration, the sand and fine salt can be effectively separated based on their difference in particle size, providing a clean separation of the two components.

Filtration is a separation technique that takes advantage of the difference in particle size between sand and salt. It involves passing the mixture through a porous material, such as filter paper or a filter funnel, which allows the liquid (saltwater) and small salt particles to pass through while retaining the larger sand particles.

Here's how the filtration process can be carried out:

1. Set up a filter apparatus with a funnel and filter paper or a filter flask.

2. Place the mixture of sand and salt in a beaker or a flask.

3. Slowly pour the mixture into the filter paper or funnel, allowing the liquid (saltwater) to pass through while retaining the sand on the filter paper.

4. Once the liquid has passed through completely, the sand will be left behind on the filter paper or in the filter flask.

5. Carefully remove the sand from the filter paper or filter flask, and the saltwater solution can be collected separately.

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Answer:

11.23 atm

Explanation:

Given

Mass = 13.7 g

Volume = 500mL = 0.5 L

Molar concentration =  \(\frac{\text{Moles}}{\text{Volume}}\\\)

Moles =\(\frac{\text{MassC3H7OH }}{\text{Molar mass C3H7OH }}\) = \(\frac{13.7}{0.5}\)= 0.2279534 moles

Molar concentration =\(\frac{0.2279534}{0.5}\)  = 0.4559 M

π = icRT

where

Osmotic pressure = π

Van't Hoff factor (i) = 1

Molar concentration of solute (c) = 0.4559 M

Ideal gas constant (R) = 0.0821 L.atm/K.mol

Kelvin Temperature (T) = 273 + 27 = 300 K

\(\pi\) = 1 * 0.4559 * 0.0821 * 300

= 11.23 atm

The value of osmotic pressure is 11.23 atm.

\(pi= icRT\)......(1)

where Osmotic pressure = pi

Van't Hoff factor=i=1

Ideal gas constant =R= 0.0821 L.atm/K.mol

Temerature=T,(273 + 27) = 300 K

Concentration=c

Given:-

Mass = 13.7 g

Volume = 500mL = 0.5 L 

Moles = \(\frac{Mass}{Molar mass} =\frac{13.7g}{60.09g/mol} =0.2279534\ mol\)

Molar concentration = \(\frac{0.2279\ mol}{0.5\ L}\) = 0.4559 M

Molar concentration of solute (c) = 0.4559 M

Substitute all the values in equation (1) as follows:-

\(pi = 1 * 0.4559 * 0.0821 * 300= 11.23 atm\)

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Answer:

The volume of the flask is 20.245 litres .

Explanation:

We are given with following information-

\(PV=nRT\) -------- 1

where R =\(0.0821L.atom/mole.K\)

Molar mass of \(PCl_5=208.22g/mole\)

The given chemical equation is -

\(2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5 _(_s_)\) --------- 2

Now , calculation -

Mass of \(PCl_5\) formed = 118g

Molar mass of \(PCl_5\) = \(208.22g/mole\)

      Mole = \(\frac{mass (g)}{molar mass}\)

Therefore , moles of \(PCl_5\) formed = \(\frac{118}{208.22}\)

     From equation 2 , we get to know that ,

 2mole \(PCl_5\) formed from 5 mole \(Cl_2 _(_g_)\)

Therefore , \(\frac{118}{208.22}\) mole \(PCl_5\) formed from \(\frac{5}{2} \times\frac{118}{208.22}\) mole \(Cl_2 _(_g_)\)

Moles of \(Cl_2 _(_g_)\) used =\(\frac{5\times118}{2\times208.22} mole\)

R= \(0.0821L.atom/mole.K\)

Pressure (P)= 1.85atm

Temperature (T)= 322K

Moles of  \(Cl_2 _(_g_)\) (n)= \(\frac{5}{2} \times\frac{118}{208.22}\) moles

Applying  the formula above in 1 equation , that is

PV = nRT

putting the given values -

\(1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322\)

 V = 20.245 litres.

Hence , the volume of the flask is 20.245 litres .

The molarity of the chloride ions in the final solution is 0.747 M.

Given:

1.60 g of solid NaCl to 50.0 mL of 0.100 M calcium chloride solution.

To find:

The molarity of chloride ions in the final solution.

Solution:

Molarity of the calcium chloride solution = 0.100 M

Volume of the  calcium chloride  solution = V = 50.0 mL

\(1mL=0.001 L\\\\V=50.0mL=50.0 \times 0.001 L\\\\= 0.050 L\)

Moles of calcium chloride = n

\(0.100 M=\frac{n}{0.050 L}\\\\n=0.100 M\times 0.050 L=0.005 mol\)

\(CaCl_2(aq)\rightarrow Ca^+(aq)+2Cl^-(aq)\)

Moles of chloride ions in solution = \(2\times 0.005 mol=0.010 mol\)

Mass of sodium chloride = 1.60 g

Moles of sodium chloride :

= \(\frac{1.60 g}{58.5 g/mol}=0.02735 mol\)

\(NaCl(s)\rightarrow Na^+(aq)+Cl^-(aq)\)

Moles of chloride ions coming from 1.60 grams of NaCl = 0.02735 mol

Total moles of chloride ion in the final solution:

\(= 0.010 mol+0.02735 mol=0.03735 mol\)

The molarity of the chloride ion in the final solution:

\(=\frac{0.03735 mol}{0.050 L}=0.747M\)

The molarity of the chloride ions in the final solution is 0.747 M.

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Answer: The volume of the new solution​ is 83.33 mL.

Explanation:

Given: \(V_{1}\) = 200 mL,    \(M_{1}\) = 0.5 M

\(V_{2}\) = ?,             \(M_{2}\) = 1.2 M

Formula used to calculate the volume of new solution is as follows.

\(M_{1}V_{1} = M_{2}V_{2}\)

Substitute the values into above formula as follows.

\(M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 200 mL = 1.2 M \times V_{2}\\V_{2} = 83.33 mL\)

Thus, we can conclude that volume of the new solution​ is 83.33 mL.

The molecules in a copper penny is closely packed and and has no space to move apart thus the material will be denser than that in the molten state. That's why the penny sink in the molten copper.

Copper is a transition metal exhibiting all the metallic properties. The molten state of metals is the fluid state where the molecule are not strongly held by the metallic bonds.

Molten material is made by melting them and the liquid like state contains molecules with some space to move apart. Whereas, in solid state as in a copper penny, the molecules are closely packed and have no space to move apart.

An object will sink in a liquid if it is less dense than the liquid. Copper penny is denser than the molten copper because the molecules are densely packed and it will sink on to it.

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