Answer:
options B,C,D are true
Explanation:
Question below in photo!! Please answer! Will mark BRAINLIEST! ⬇⬇⬇⬇⬇⬇⬇
its wave length
its wave lenght because how its measure
Why is math so hard?
Answer:
its just built different
I could give you a big, fancy scientific answer, but it often comes down to the fact that the way that most instructors teach math is not the way the student(s) can most easily understand it.
car is traveling with a velocity of 40 m/s and has a mass of 1120 kg. The car has
_______________ energy.
Answer:896000 J
Explanation: K.E = 1/2*m*v^2
Answer:
The car has Kinetic energy. 896000 Joules
Explanation:
Kinetic energy formula: 1/2 (mass)(speed)^2
First you multiply 1120 by 1/2 and get 560
Then you take the square root of 40 (\(40x^{2}\)) and get 1600
Finally to get the answer multiply 560 by 1600 and your final answer should be 896000 Joules
A vehicle of mass 100kg has a kinetic energy of 5000 J at an instant. The velocity at that instant is
Answer:
23.51 m/s
Explanation:
Parameters given:
Kinetic energy, K = 295 J
Momentum, p = 25.1 kgm/s
a) The kinetic energy of a body is given as:
where m = mass of the body and v = speed of the body
Answer:
\(\bf\pink{10\:m/s}\)Explanation:
Given :-\(\sf\red{Mass \ of \ vehicle \ (m) = 100 \ kg}\)\(\sf\orange{Kinetic \ energy \ (K.E.) = 5000 \ J}\)To Find :-\(\sf\green{Velocity\: of\: the \:vehicle \:at \:the \:instant}\)Formula to be used :-\(\sf\blue{K.E. = \dfrac{1}{2} mv^{2}}\)Where,
K.E. = Kinetic energy possessed by the bodyM = Mass of the bodyV = Velocity of the bodySolution :-\(\to\:\:\sf\red{K.E. = \dfrac{1}{2}mv^{2}}\)
\(\to\:\:\sf\orange{5000 = \dfrac{1}{2} \times 100 \times v^{2}}\)
\(\to\:\:\sf\green{5000 = 50 \times v^{2}}\)
\(\to\:\:\sf\blue{\dfrac{5000}{50} = v^{2}}\)
\(\to\:\:\sf\purple{100 = v^{2}}\)
\(\to\:\:\sf\red{\sqrt{100} = v}\)
\(\to\:\:\sf\orange{ 10 = v}\)
\(\to\:\:\bf\pink{v = 10\:m/s}\)
Velocity of the vehicle at the instant is \(\bf\green{10\:m/s}\)Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next
Answer: Hope this helps ;) don't forget to rate this answer !
Explanation:
There are two correct answers:
A) A corporation leader makes direct payment to the candidate.
D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.
Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.
Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.
I hope this helps! Let me know if you have any other questions.
Amanda uses a wheelbarrow to lift a load of bricks. The bricks weigh 620 N, which is more than Amanda could normally carry. However, with the wheelbarrow, Amanda can lift the bricks with as little as 120 N. What is the mechanical advantage of the wheelbarrow?
The mechanical benefit of the barrow is the result of the mechanical benefits of the lever (2), the wheel, and the axle (2). The wheelbarrow thus has a tactical energy of 4.
What is class 8 mechanical advantage?The force amplified by utilising a tool, mechanical device, or machine system is known as mechanical advantage. In order to achieve the appropriate output force amplification, the device simply trades on forces against movement while maintaining the input power.
What is the wheelbarrow's mechanism?The axle and wheel as well as the lever are two straightforward machines that contribute to making the load smaller and simpler to transfer. You are actually using force on the lever when you lift the wheelbarrow by the handle. The wheel will begin to move when you exert tension on the lever.
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Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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a student throws a coin vertically downward frok the top of a building. the coin leaves the throwers hand with a speed of 15.0m/s. what is its speed after falling freely for 2.00s?
Answer:
Final speed after 2 seconds = 34.6 m/s
Explanation:
Given:
Initial speed of coin (u) = 15 m/s
Time taken = 2 seconds
Find:
Final speed after 2 seconds
Computation:
Gravitational acceleration of earth = 9.8 m/s²
Using first equation of motion;
v = u + at
or
v = u + gt
where,
v = final velocity
u = initial velocity
g = Gravitational acceleration
t = time taken
v = 15 + 9.8(2)
v = 15 + 19.6
Final speed after 2 seconds = 34.6 m/s
If earth suddenly stops rotating, how will the 'Acceleration due to Gravity' change?
Hope this helps
give at least 10 ways to have a healthy body?
1. A bullet of mass 0.02-kg is shot horizontally into a wooden log, striking it with a
velocity of 200
a) If it penetrates 4-cm before stopping, what is the stopping
force i.e friction force? (work = change in kinetic energy)
b) What is the acceleration of the bullet while slowing in the log.
c) How long does it take for the bullet to stop?
(a) The stopping force is 10,000 N.
(b) The acceleration of the bullet while slowing in the log is 500,000 m/s².
(c) The time taken for the bullet to stop is 0.0004 s.
What is the stopping force?
The stopping force is determined from the change in kinetic energy of the bullet.
W = -ΔK.E
W = ¹/₂ m (u² - v²)
where;
v is the final velocity when the bullet stops = 0u is the initial velocity of the bullet m is the mass of the bulletW = ¹/₂ m (u² - 0)
W = ¹/₂ mu²
W = ¹/₂ (0.02)(200)²
W = 400 J
W = Fd
where;
F is the stopping forced is the distanceF = W / d
F = ( 400 J ) / ( 0.04 m )
F = 10,000 N
The acceleration of the bullet is calculated as follows;
F = ma
a = F / m
a = ( 10,000 N ) / ( 0.02 kg )
a = 500,000 m/s²
The time taken for the bullet to stop is calculated as follows;
v = u - at
when the bullet stops, final velocity, v = 0
0 = u - at
at = u
t = u / a
t = ( 200 ) / ( 500,000)
t = 0.0004 s
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Suppose you have a barometer with mercury and a barometer with water. How does the height hwater compare with the height hmercury?.
The heaviest liquid is mercury. In order to equalize the air pressure, it only climbs 76 cm. Water will rise to a 13.6 because it is 13.6 times lighter than mercury. By a factor of 13.6, mercury is 13.6 times denser than water.
Therefore, the barometer's height would be 13.6 times higher if water were employed in place of mercury. Since water expands when it freezes, the glass tube would be broken.
Because of its high density, mercury is frequently employed in barometers, allowing for a column height that is appropriate for measuring atmospheric pressure. For example, a mercury barometer would need to be 13.6 times taller than a water barometer to measure the same change in pressure.
This is the primary justification for using mercury in thermometers. Mercury will provide accurate readings in comparison to water since it lacks the condensation property that water possesses. Mercury can be used to measure both negative and positive temperatures, whereas water cannot be used to measure either.
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Calculate the critical angle for glass materials of refractive index 1.60
The critical angle for glass materials with a refractive index 1.60 is 38.7°.
What is the critical angle of a refractive material?The critical angle in optics is the incidence angle at which the refraction angle is 90 degrees.
It is possible to calculate the link between the critical angle and the refractive index since the critical angle is inversely proportional to the refractive index.
Refractive index = 1/sin C
where C is the critical angle
Hence, C = sin⁻¹(1/refractive index)
For the glass material, C = sin⁻¹(1/1.60)
C = 38.7°
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(b) In the USA, drones are not allowed to be flown too high above the ground.
Suggest one possible risk of flying a drone too high above the ground.
Plz complete thank you in advance
The 400-foot altitude limit was put in place for the sake of airspace safety, and there is a risk to country security as well as the privacy of citizens.
What are drones?Unmanned aerial vehicles (UAVs), sometimes known as drones, are used for a variety of jobs, from routine to extremely dangerous. These robotic-looking planes can be seen practically everywhere, from delivering groceries to your home to rescuing avalanche victims.
The 400-foot altitude restriction was ultimately implemented for airspace safety. Given the breadth of the airspace above 400 feet, the likelihood of a drone colliding with a human aircraft is exceedingly remote, but the consequences might be disastrous.
Any aerial vehicle that uses software to fly autonomously or that may be controlled remotely by a pilot is referred to as a drone. Numerous drones come equipped with cameras to gather visual data and propellers to stabilize flying paths. Drone technology has been incorporated into industries like videography, search and rescue, agriculture, and transportation.
When in uncontrolled (Class G) airspace, your drone must be flown 400 feet above the ground or less.
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What is the net force on an object if the two forces acting are 10 N north and 5 N west?
11.2 N at 116.6°
15 N at 116.6°
11.2 N at 63.4°
15 N at 63.4°
Answer:
15N at 116.60°
Explanation:
add the forces at an angle greater than 90°
D) The particle displacement due to a sound wave is given by: y = 4.25x10-3 sin[200πt – (2πx /800)]Where x is measured in cm and t in seconds. Write down the amplitude, velocity , wavelength, frequency, andTime period of the wave.Notes:IeI= 1.6 x10-19 C, me=9.1x10-31 kg, mp = 1.67x10-27 Kg, h= 6.62x10-34 J.s, c= 3x108 m/s
Given,
\(y=4.25\times10^{-3}\sin \lbrack200\pi t-(\frac{2\pi x}{800})\rbrack\)The wave equation of a particle is,
\(y=A\sin (\omega t-kx)\)Where
• A is the amplitude.
,• ω is the angular velocity.
,• k is the wavenumber.
On comparing the two equations,
Amplitude, A=4.25×10⁻³
Angular velocity, ω=200π rad/s200
The wavenumber, k=2π/800 /m
The velocity of the particle is equal to the time derivative of its displacement.
Thus, the velocity is,
\(\begin{gathered} v=\frac{dy}{dt} \\ =\frac{d}{dt}(A\sin (\omega t-kx))_{} \\ =A\omega\cos (\omega t-kx) \end{gathered}\)On substituting the known values, the velocity is,
\(\begin{gathered} v=4.25\times10^{-3}\times200\pi\times\cos \lbrack200\pi t-(\frac{2\pi x}{800})\rbrack \\ =0.85\pi\cos \lbrack200\pi t-(\frac{2\pi x}{800})\rbrack \end{gathered}\)The wavelength is given by,
\(\lambda=\frac{2\pi}{k}\)On substituting the known values,
\(\begin{gathered} \lambda=\frac{2\pi}{(\frac{2\pi}{800})} \\ =800\text{ m} \end{gathered}\)Thus the wavelength is 800 m
The frequency is given by,
\(f=\frac{2\pi}{\omega}\)On substituting the known values,
\(\begin{gathered} f=\frac{2\pi}{200\pi} \\ =0.01\text{ Hz} \end{gathered}\)Thus the frequency is 0.01 Hz
The period is given by,
\(T=\frac{1}{f}\)On substituting the known values,
\(\begin{gathered} T=\frac{1}{0.01} \\ =100\text{ s} \end{gathered}\)Thus the time period of the wave is 100 s
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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A compact disc (CD) is played by a cd player, which uses a laser to read the tracks on the disc. The disc spins initially at approximately 200 rotations per minute (rpm), and increases to a maximum of approximately 500 rpm as the laser spirals inward towards the center of the disc. This ensures that the laser covers equal distance in an equal amount of time during playback. During the time that the cd is played, which of the following statements is true?
a. The laser tracking mechanism experiences a changing tangential velocity
b. The laser tracking mechanism experiences a constant angular velocity
c. The laser tracking mechanism experiences a non-zero angular acceleration
d. The laser tracking mechanism experiences a non-zero tangential acceleration
Answer:
a. The laser tracking mechanism experiences a changing tangential velocity
c. The laser tracking mechanism experiences a non-zero angular acceleration
d. The laser tracking mechanism experiences a non-zero tangential acceleration
Explanation:
a. The laser tracking mechanism experiences a changing tangential velocity
This is because the tangential velocity v = rω where r = radius of disc and ω = angular speed of discs. Since r is constant, v ∝ ω.
Since the angular speed changes from 200 rpm to 500 rpm, thus, the tangential velocity would also change.
So, the laser tracking mechanism experiences a changing tangential velocity
c. The laser tracking mechanism experiences a non-zero angular acceleration
Since angular acceleration, α = Δω/Δt where Δω = change in angular speed and Δt = change in time.
Since there is a change in angular speed from 200 rpm to 500 rpm in time Δt, there is thus a non-zero angular acceleration.
So, The laser tracking mechanism experiences a non-zero angular acceleration
d. The laser tracking mechanism experiences a non-zero tangential acceleration
Since tangential acceleration, a = rα where r = radius of disc and α = angular acceleration.
Since there is an angular acceleration of the disc, there is thus going to be a tangential acceleration given by a = rα.
So, the laser tracking mechanism experiences a non-zero tangential acceleration
Statement b is false because, the disc experiences a changing angular speed from 200 rpm to 500 rpm.
If I bought 59 kids off the black market in a secret door in the stalls and I sell 21 kids then ask for 81 more then 12 off the kids runaway in speed of 6 miles and I get in my ice cream truck/van and forget 9 kids and 4 kids out run my ice cream truck/van and I catch 8 of them How Many Do I Have? I'll give a Brainlist.
You will be left with 106 kids
Meaning of word problem
A word problem can be defined as a mathematical problem that is written in word or written in a sentence format.
In a word problem, the student is expected to decode the sentence into a mathematical expression before solving
In conclusion, You will be left with 106 kids
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mechanical energy defintion
Answer: Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.
(The energy acquired by the objects upon which work is done)
What is the reactive force when a fish swims through water
The reactive force when a fish swims through water is the force of the water on the fish. This is an example of Newton’s third law of motion which states that for every action, there is an equal and opposite reaction. The active force is the fish pushing against the water, so the reactive force would be the reverse, the equal force of the water pushing back on the fish.
why all traveller prefer to travel easily in the morning and night and not when the sun is hot
Answer:
Travelers prefer to travel in morning because arthat time the temperature ️ is not too hot and they can easily travel here and there without any problem. and they also prefer to travel in night because moderate temperature ....
If you pull with a constant force of 400n , how much mechanical work does it take to pull pinball launcher back 0.2meters
If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.
What is Work?In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.
The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.
As per the given information in the question,
Force, f = 400 N
Displacement, d = 0.2 meters
\(Work done(W)=Force(f)*Displacement(d)\)
W = 400 × 0.2
W = 80 J.
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Drag each item to indicate whether it is a characteristic of dark matter or baryonic matter. (2 points)
Dark Matter
Baryonic Matter
:: has been observed directly
:: interacts with baryonic matter
:: interacts with electromagnetic radiation
has not been observed directly
:: does not interact with electromagnetic radiation
++ does not interact with baryonic matter
Answer:
Dark matter:
- Doesn't interact with baryonic matter.
- It has not been observed directly
- dark matter does not absorb, reflect or even emit light, thereby making it to be extremely hard to spot. Therefore, it does not interact with electromagnetic radiation.
Explanation:
Dark matter:
- Doesn't interact with baryonic matter.
- It has not been observed directly
- dark matter does not absorb, reflect or even emit light, thereby making it to be extremely hard to spot. Therefore, it does not interact with electromagnetic radiation.
Baryonic matter:
- Has been observed directly because it includes nearly all the matter that we see in the world daily.
- It interacts with baryonic matter
- interacts with electromagnetic radiation
Dark Matter:
It has not been observed directly.It does not interact with baryonic matter.It does not interact with electromagnetic radiation.Baryonic Matter:
It has been observed directly.It interacts with baryonic matter.It interacts with electromagnetic radiation.Dark matter can be defined as often invisible substances that are difficult to spot because they don't absorb, emit or reflect light.
Hence, dark matter do not affect human view because they do not interact or interfere with electromagnetic radiation (force).
Although, humans can see right through the (weakly interacting) dark matter but it has not been observed directly.
Baryonic matter can be defined as a dark matter that is made up of baryons such as neutrons, and protons. Also, they are ordinary matter (both fermions and hadrons), as distinct from exotic forms.
In conclusion. baryonic matter has been observed directly and it can interact with electromagnetic radiation.
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The highness or lowness of a sound is perceived as
a.
compression.
c.
ultrasound.
b.
wavelength.
d.
pitch.
Answer:
i think its D
Explanation:
Answer:
The highness or lowness of a sound is perceived as pitch. Pitch is a perceptual property of sound that allows us to distinguish between sounds that have the same loudness and duration, but differ in their frequency content. The pitch of a sound is determined by the frequency of the sound wave, with higher frequencies producing higher pitches and lower frequencies producing lower pitches. The pitch is what makes a sound distinguishable and is important in music, language, and communication.
What is the mass of a material whose temperature changes from -12°C to 80°C when 4,577 J heat energy is added to it if the specific heat capacity of the material
is 7.0 J/g°C? Give your answer to 2 decimal places.
\( \frac{4577}{7 \times (80 - ( - 12))} \\ \frac{4577}{7 \times92 } \\ \frac{4577}{644} \\ = 8.5g\)
An Olympian lifts a 1,375-kilogram set of weights a vertical distance of 2 meters in the weightlifting event.
The force of gravity equals 9.8 m/s. What is the potential energy of the weights?
Answer:
PE = MGH. 1375 x 9.8 x 2. = 26950 joules
Explanation:
First do 1375 x 9.8 which is MG then times it by 2 which is H
Mass x Gravity x Height
the gravity will always be 9.8
I would love a brainliest
The the potential energy of the weights lifted 2 meters above the surface is E[P] = 26950 joules.
What is Potential energy?The energy of a body by virtue of its position is called potential energy. Mathematically -
E[P] = mgh
Given is an Olympian who lifted a 1,375-kilogram set of weights a vertical distance of 2 meters in the weightlifting event.
We can write the given data as follows -
Mass of weights = [M] = 1375 Kg
Displacement = [h] = 2 meters
Therefore, using the formula for potential energy, we can write -
E[P] = mgh
E[P] = 1375 x 9.8 x 2
E[P] = 26950 joules
Therefore, the the potential energy of the weights lifted 2 meters above the surface is E[P] = 26950 joules.
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This is from P.E , que some please help me
Answer:
I know that 2 is called a foul I dont know about 1 though
Franny drew a diagram to compare images produced by concave and convex lenses.
2 overlapping circles, the left circle labeled Concave lenses and the right circle labeled Convex lenses. An X in the overlap.
Which belongs in the area marked X?
Answer:
Virtual
Explanation:
Answer:
B. Virtual
Good Luck!
the height of the upper falls at Yellowstone falls is 33.2m. when the water reaches the botton of the falls, its speed is 25.8 m/s. neglecting air resistance, what is the speed of the water at the to of te falls.
Answer:
Hi there
The water acquires a vertical velocity component during the fall equal to
Vy = sqrt(2gH) = 25.5 m/s. Its velocity at the bottom is 25.8 m/s, so the horizontal component at the bottom must be sqrt[(25.8)^2 - (25.5)^2] = 3.9 m/s
That must be the horizontal component at the top also, since it does not change during the fall. It is the velocity magnitude there.
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