Which of the following is true about particles of matter?

The simplest, obvious category is " Satellites " .

But there's a lot of good reason to call it "Component of Binary Planet" .

As a fraction of the size and mass of its planet, our moon is the largest in the solar system.  

Several writers have pointed out that an alien astronomer studying our solar system might describe the 3rd body from the Sun as a "Binary planet".  

Answer:Each goal line is 11 feet (3.4 m) from the end boards. NHL blue lines are 75 feet (22.9 m) from the end boards and 50 feet (15.2 m) apart.

Explanation:When the other team is on the attack, the defensive zone is the area between your goal line and your blue line. The central ice area between the two blue lines (neither the defending nor the attacking zone). When the your team is on the attack, the offensive zone is the area between blue line and your opponents goal.

After considering the given data the height from which the gannet dived is approximately 51.84 m.

To evaluate the height from which a gannet dived if it hits the water at 32 m/s, assuming that the gannet was motionless before starting its dive, we can apply the law of conservation of energy, which projects  that the initial potential energy of the gannet is equivalent to its final kinetic energy prior to hitting the water. Then, we can write:
\(mgh = (1/2)mv^2\)
Here:
m = mass of the gannet
g = acceleration due to gravity
h = height from which the gannet dived
v = velocity of the gannet just before hitting the water
Considering that the mass of the gannet is 1 kg, and applying substitution of the given values, we get:
\((1 kg)(9.8 m/s^2)(h) = (1/2)(1 kg)(32 m/s)^2\)
\(h = (1/2)(32 m/s)^2 / (9.8 m/s^2)\)
h = 51.84 m
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The complete question is
A gannet is a seabird that fishes by diving from a great height. If a gannet hits the water at 32 m/s , what height did it dive from? Assume that the gannet was motionless before starting its dive.

The depth below the surface of the glycerine at which the pressure is 2470 Pa greater than atmospheric pressure is 0.2 m.

Let us consider that the height of the container as h₀. The difference in pressure Δp = 2470 Pa. The density of glycerine is ρ = 1.26 × 10³ kg/m³. Let the depth below the surface of the glycerine be h. Let us use the formula of pressure and substitute the given values in it.

pressure = ρ × g × h + atmospheric pressure

The atmospheric pressure is constant and hence can be taken as a reference. We are looking for the depth of glycerine at which the pressure is greater than atmospheric pressure by 2470 Pa. Hence, we can write the above equation as follows.

Δp = ρ × g × h

The acceleration due to gravity is 9.8 m/s².

Substituting the values, we get:

Δp = ρ × g × h⇒ 2470 = 1.26 × 10³ × 9.8 × h⇒ h = 2470 / (1.26 × 10³ × 9.8)⇒ h = 0.2 m

Therefore, the depth below the surface of the glycerine at which the pressure is 2470 Pa greater than atmospheric pressure is 0.2 m.

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Given data

*The given mass of the person is m = 40 kg

*The value of the acceleration due to the gravity is g = 9.8 m/s^2

(A)

The reading on the scale is calculated when the elevator is stationary is given as

(B)

The formula for the reading on the scale when the elevator is moving up at constant speed is given as

(C)

The formula for the reading on the scale when the elevator accelerates upwards at 5.00 m/s^2 is given as

Substitute the known values in the above expression as

(D)

The formula for the reading on the scale when the elevator accelerates downwards at 5.00 m/s^2 is given as

Substitute the known values in the above expression as

Answer:

Two positively charged particles

Explanation:

I said two positively charged particles because if I say c or d what ever it is for you guy it can be wrong so just pick the one that says Two positively charged particles

Answer: C  Two positively charged particles.

Explanation:

just trust me on it, i've done the same quiz.

Earth's gravitational field = 10N/kg

Jupiter's gravitational field = 23.6 N/kg

Jupiter's gravitational field > Earth's gravitational field

Therefore, we will weigh more on Jupiter.

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When the mirror is moved so that the tree is between the focus point F and the mirror, the image appears shorter and on the same side of the mirror.This happens because of the phenomenon known as Reflection of Light. The mirror reflects light in such a way that it appears as if the light is coming from behind the mirror.

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Answer: 8.75 km/hr

Explanation:

Concept to know

Average speed: total distance/total time

-------------------------------------------------------

 total distance/total time

=(12.2+19.3)/(1.4+2.2) ⇔ add the numbers of two time running together

=31.5/3.6 ⇔ simplify

=8.75 km/hr

Hope this helps!! :)

Please let me know if you have any question

Answer:

it's D

Explanation:

Newton's first law of motion states that a body at rest remains at rest or if in motion remains in motion at a constant velocity unless acted upon by a external Force

The correct option is D. In uniform motion will remain in motion unless it is acted upon by an outside force .

Unless influenced by an imbalanced force, an item at rest stays at rest, and an object in motion keeps moving in a straight path at a constant pace. An object's acceleration is determined by its mass and the force being applied.

Every time one object applies force to another, the other object applies an equal and opposite force to the first.

According to Newton's first law, unless pushed to alter its condition by the operation of an external force, every object will continue to be at rest or in uniform motion in a straight line. Inertia is the propensity to resist changes in a condition of motion.

Therefore, The correct option is D. In uniform motion will remain in motion unless it is acted upon by an outside force .

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The speed of the stone when it reaches point B is: 22.64m/s.

Speed is a measure of how fast an object is moving, usually measured in units of distance per unit time, such as meters per second (m/s), kilometers per hour (km/h), or miles per hour (mph). It is a scalar quantity that describes how quickly an object is changing its position over time.

In order to find the speed of the stone, we have:

The mass of the stone is m = 15kg.

The height of snow hill is \(h_{A}\) = 20m and it is 15m wide.

The speed from point A is \(v_{A}\) = 11m/s.

The force constant is k = 2.50N/m.

The coefficient of kinetic friction and static friction between the stone and horizontal ground are μ\(_{k}\) = 0.20 and μ\(_{s}\) = 0.80 respectively.

As there is no friction between point A and B, the total energy at point A is equal to total energy at point B.

Therefore we get,

E\(_{A}\) = E\(_{B}\)

1/2mv²\(_{A}\) + mgh\(_{A}\) = 1/2mv²\(_{B}\) + mgh\(_{B}\)

v²\(_{B}\) = v²\(_{A}\) + 2g(h\(_{A}\) − h\(_{B}\))

But height at point B is zero i.e. h\(_{B}\) = 0.

Substituting known values in the equation, we have:

v\(_{B}\) =  \(\sqrt{v_A+ 2gh_{A} } }\)

= √[(11m/s)² + 2(9.8m/s²) (20m)] = 22.64m/s

Thus, the speed of the stone when it reaches at point B is 22.64m/s.

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The complete question is:

A 15.0-kg stone slides down a snow-covered hill that is 20 m high and 15 m wide, leaving point A at the top with a speed of 11.0 m/s. There is no friction on the hill between points A and B at the bottom of the hill, but there is friction on the level ground at the bottom of the hill, between B and the wall. After entering the rough horizontal region, the stone travels 100 m and then runs into a very long, light spring with a force constant of 2.50 N/m. The coefficients of kinetic and static friction between the stone and the horizontal ground are 0.20 and 0.80, respectively.

What is the speed of the stone when it reaches point B?

Answer:

i hardly havent got teach this sorry

Answer:

Sport lowers high blood pressure, Keeps cholesterol level right. Blood circulation in the body is relatively high during play, so nutrients can go to all parts of the body. Moreover, white blood cells increase during play that increases the body’s immunity power. That’s why sports is important in our life.

Explanation:

yes

Answer:

Shape

Density

color

Explanation:

Length times width gives the surface area of the pool. Multiplying that by the average depth gives the volume in cubic feet. Since there are 7.5 gallons in each cubic foot, multiply the cubic feet of the pool by 7.5 to arrive at the volume of the pool (expressed in gallons).

Answer:

the answer is volume

Explanation:

The value of the spring constant of the spring is 14.7 N/m.

The given parameters;

The extension of the spring is calculated as follows;

\(\Delta x = L_1 - L_0\\\\\Delta x = 12 \ cm - \ 10 \ cm\\\\\Delta x = 2 \ cm = 0.02 \ m\)

The value of the spring constant of the spring is calculated by applying Hooke's law;

\(F = mg = k\Delta x\\\\k = \frac{mg}{\Delta x } \\\\k = \frac{0.03 \times 9.8}{0.02} \\\\k = 14.7 \ N/m\)

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The minimum and maximum braking distances needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection are as follows:

- For small cars: Minimum ≈ 1773.028 m, Maximum ≈ 1568.850 m

- For large trucks: Minimum ≈ 3285.760 m, Maximum ≈ 2409.595 m

To calculate the minimum and maximum braking distances, we can use the equations of motion for a decelerating vehicle.

The equation for the braking distance of a vehicle is given by:

d = (v^2) / (2 * μ * g)

where d is the braking distance, v is the initial velocity of the vehicle, μ is the coefficient of friction between the tires and the road, and g is the acceleration due to gravity.

Let's calculate the minimum and maximum braking distances separately for small cars and large trucks.

For small cars with a mass of 563 kg:

- Minimum braking distance:

  v = 8989 km/h = (8989 * 1000) / 3600 m/s = 2496.944 m/s

  μ_min = 0.536

  d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.536 * 9.8) ≈ 1773.028 m

  Maximum braking distance:

  μ_max = 0.599

  \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.599 * 9.8) ≈ 1568.850 m\)

For large trucks with a mass of 3951395 kg:

- Minimum braking distance:

  v = 8989 km/h = 2496.944 m/s (same as for small cars)

  μ_min = 0.350

 \(d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.350 * 9.8) ≈ 3285.760 m\)

  Maximum braking distance:

  μ_max = 0.480

 \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.480 * 9.8) ≈ 2409.595 m\)

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Answer:

calculation presented a speed of 125,000 miles per second (200,000 km/s).

Explanation:

Answer:

visual are used as a way for our brains to Kriti understand information which is the powerful tool is used for glass can show a large amount of data quickly in a way that it is to process with a bunch of numbers

Explanation:

graph and charts communicate information visually they can show pattern self scientist simply corrections and guess the point of experiment across quickly depended variable is y axis

Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

Answer:

9. The Sun's Gravity

10. The core is the densest layer

The velocity of the mass at t = 3.8 seconds is -5.192m/s (approx) when rounded off to three decimal places.

Given ,The position of a mass oscillating in a fluid is given by x(t) = 6e−tcos(2πt), where t is time in seconds.

To find:

Determine the velocity of the mass at t = 3.8 seconds rounded off to three decimal places.

The velocity of an object is equal to the first derivative of its position with respect to time.

The velocity v(t) is the first derivative of x(t) with respect to time.t is given as 3.8 seconds in the given function, x(t).

Differentiate the function x(t) with respect to time,

t.v(t) = dx(t)/dt = d/dt [6e^(−t) cos(2πt)]v(t)

= -6e^(−t) sin(2πt) - 12πe^(−t) cos(2πt)

When t = 3.8 seconds, put the value of t in the above equation

v(3.8) = -6e^(−3.8) sin(2π × 3.8) - 12πe^(−3.8) cos(2π × 3.8)v(3.8) = -5.192m/s

Hence, the velocity of the mass at t = 3.8 seconds is -5.192m/s (approx)

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Here your answer

Fossils are formed in a number of different ways, but most are formed when a plant or animal dies in a watery environment and is buried in mud and silt. Soft tissues quickly decompose leaving the hard bones or shells behind. Over time sediment builds over the top and hardens into rock.

hope it helps ☺️✌️

Answer:

over years of being underground the pressure causes the organism to press into the rock and form a mold. this mold is the fossil and are found in sedimentary rock

Answer:

true

Explanation:

Answer:

100 joules (J).

Explanation:

Converting Units - 36 km/h = 10 m/s

                               72 km/h = 20 m/s ( 1 km/h =  5/18 m/s)

Change in speed = 20 - 10 = 10 m/s

Applying the Work-Energy theorem,

\(Work done = \frac{1}{2} 2 (10)^2\)

                 = 100 J.

Answer:

Friction creates warmth

The statement which is true about a piece of ice at 0°C which is put into a freezer at -18°C is it having the temperature of the freezer.

This is referred to the degree of hotness or coldness of a body and the unit is Celsius or Kelvin.

The ice at 0°C will experience a change in temperature of the freezer when put in it in this scenario.

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