The graph that looks like this
Answer: D
Step-by-step explanation:
I think
please help me..... i will mark your answer.
Answer:
B
Step-by-step explanation:
do you want an explanation? thoit'll be hard to give lol
btw plz brainliest :)
Help due tomorrow would highly appreciate this.
The value of the part of side of triangle given as x is equal to 11/3 in simplified fraction.
What is fraction?
A fraction is referred to as the part of something a whole in maths. For instance, if a pizza is cut into four equal pieces, each one is represented by a quarter (¼). Fractions can make calculations faster and easier through making it easier to distribute and judge different numbers. The depiction of fractions appears easier than when decimal values are used.
As given in the question, in the given triangle DE is parallel to AC,
It implies that the ration of the sides are equal.
i.e. AD/DB = CE/EB
Putting the value from the figure given in the question,
we get,
11/x = 9/3
11/x = 3
x = 11/3
Therefore, The value of the x is 11/3 in the form of simplified fraction.
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Please help me(ik it’s not C)
I think the correct answer is B :)
Stephan borrowed $125 to buy an electric scooter. The function f(x) = 125 - 12.5x
can be used to represent the amount of money Stephan owes on the loan, where X is the number of weeks that Stephan pays towards the loan.
The amount that Stephen owed after 2 weeks is $100.
How to illustrate the expression?Expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both.
In this case, Stephan borrowed $125 to buy an electric scooter and the function f(x) = 125 - 12.5x
can be used to represent the amount of money Stephan owes on the loan, where X is the number of weeks that Stephan pays towards the loan.
The amount after 2 weeks will be:
f(x) = 125 - 12.5x
= 125 - 12.5(2)
= 125 - 25
= $100
The amount is $100.
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Complete question
Stephan borrowed $125 to buy an electric scooter. The function f(x) = 125 - 12.5x
can be used to represent the amount of money Stephan owes on the loan, where X is the number of weeks that Stephan pays towards the loan. What is the amount owed after 2 weeks?
andrea has 37 coins, all nickels and dimes. The value of the 37 coins is $3.10. How many dimes does andrea have ?
Answer:
It would be 25
Step-by-step explanation:
Hope this helps:)....if not then sorry for wasting your time and may God bless you:)
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Answer:
mean only
Step-by-step explanation:
the expensive house does not affect mode or median :)
Answer:
A
Step-by-step explanation:
simple interest = P × r × t
Kate borrowed $400 from her friend. She will repay this amount plus 3 percent simple interest after one year. What is the total amount she will pay her friend?
A.
$401.20
B.
$412.00
C.
$400.12
Answer: B. $412.00
I just did it on Edg and got the right answer
Answer:
b is right answer
Step-by-step explanation:
20 right and service right and service right answer
Part A
In the table, describe the shape of the cross section formed when a particular plane passes through the cone..
A
Description of Plane
plane parallel to the circular base, not passing through the tip of the cone
plane parallel to the circular base, passing through the tip of the cone
plane not parallel to the base, not passing through the base, and making an angle with the horizontal that is less than that made by the
slant height of the cone
plane making an angle with the horizontal that is greater than that made by the slant height, passing through the tip of the cone
Description of Cross
Section
All the solutions are;
1) Circle
2) A point
3) An oval that becomes more elongated as the angle with the horizontal increases.
4) An isosceles triangle.
Since, A cross-section is a plane section that is a section of a three-dimensional object that is parallel to one of its planes of symmetry or perpendicular to one of its lines of symmetry.
Now, We can formulate;
1) Plane Parallel to the circular base, not passing through the tip of the cone:
⇒ Circle.
2) Plane Parallel to the circular base, passing through the tip of the cone:
⇒ A point.
3) Plane not parallel to the base, not passing through the base, and making an angle with the horizontal that is less than that made by the slant height of the cone:
⇒ An oval that becomes more elongated as the angle with the horizontal increases.
4) Plane making an angle with the horizontal that is greater than that made by the slant height, passing through the tip of the cone :
⇒ An isosceles triangle.
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If a mean weight of two groups of children were different with a p level of .03 is the difference statistically significant? What p level identifies statistical significance?
Yes, if the mean weight of two groups of children is different with a p-value of 0.03, the difference is statistically significant. Typically, a p-value of less than 0.05 is considered statistically significant, indicating that the observed difference is unlikely to be due to chance alone.
Yes, if the p level is .03, then the difference in mean weight between the two groups of children is statistically significant. The p level that identifies statistical significance is generally considered to be .05 or less, meaning that there is a 5% or less chance that the difference observed is due to random chance rather than a true difference between the two groups. Therefore, a p level of .03 is below the commonly accepted threshold for statistical significance and suggests that the difference in mean weight is not likely due to chance alone.
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Investigate the equilibria of ˙x = a − x2 , ˙y = x − y. Show that the system has a saddle and a stable node for a > 0, but no equilibrium points if a < 0. This system is said to undergo a bifurcation as a increases through a = 0. This bifurcation is an example of a saddle-node bifurcation. Draw the phase diagrams for a = 1 and a = −1.
The phase diagrams provide a visual representation of the system's behavior by plotting the vector field and trajectories in the x-y plane.
The given system of differential equations is described by:
\(˙x = a - x^2˙y = x - y\)
To find the equilibria, we set ˙x and ˙y equal to zero:
\(a - x^2 = 0 -- > x^2 = a -- > x = ±√ax - y = 0 -- > y = x\)
So, the equilibria are (±√a, ±√a).
Now let's analyze the behavior of the system for different values of 'a'.
For a > 0:
In this case, there are two real equilibria, (√a, √a) and (-√a, -√a). We can observe that (√a, √a) is a stable node, as the eigenvalues of the linearized system around this point have negative real parts. On the other hand, (-√a, -√a) is a saddle point, as the eigenvalues have opposite signs (one positive and one negative).
For a < 0:
In this case, there are no real equilibria since √a and -√a are imaginary. Therefore, the system has no equilibrium points.
To visualize the phase diagrams for a = 1 and a = -1:
For a = 1:
The system has two real equilibria, (1, 1) and (-1, -1). The point (1, 1) is a stable node, and (-1, -1) is a saddle point. The phase diagram would show trajectories converging towards (1, 1).
For a = -1:
Since a < 0, there are no equilibrium points, and thus the phase diagram would show no fixed points or trajectories.
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What are the solutions of x2 + 20 = 12x.
Answer:
x₁ = 2
x₂ = 10
Step-by-step explanation:
x² + 20 = 12x
x² - 12x + 20 = 0
(x-2)(x-10) = 0
then:
x₁ = 2
x₂ = 10
Check:
x₁
2² + 20 = 12*2
3 + 20 = 24
x₂
10² + 20 = 12*10
100 + 20 = 120
Evaluate 8j - k+14 when j=0.25 and k=1
Answer:
(8)(0.25)−1+14
=15
Step-by-step explanation:
Find the equation of a line parallel to 3x + 3y = 21 that passes through the point
(8,-2).
Answer:
do you have like any picture of a graph?
1. Let the distribution of X be the normal distribution N (μ, σ2) and let Y = aX + b. Prove that Y is distributed as N (aμ + b, a2σ2).
2. Let X and Y be two independent random variables with E|X| < [infinity], E|Y| < [infinity] and E|XY| < [infinity]. Prove that E[XY] = E[X]E[Y].
1 Y is distributed as N(aμ + b, a^2σ^2), as desired.
2 We have shown that under these conditions, E[XY] = E[X]E[Y].
To prove that Y is distributed as N(aμ + b, a^2σ^2), we need to show that the mean and variance of Y match those of a normal distribution with parameters aμ + b and a^2σ^2, respectively.
First, let's find the mean of Y:
E(Y) = E(aX + b) = aE(X) + b = aμ + b
Next, let's find the variance of Y:
Var(Y) = Var(aX + b) = a^2Var(X) = a^2σ^2
Therefore, Y is distributed as N(aμ + b, a^2σ^2), as desired.
We can use the definition of covariance to prove that E[XY] = E[X]E[Y]. By the properties of expected value, we know that:
E[XY] = ∫∫ xy f(x,y) dxdy
where f(x,y) is the joint probability density function of X and Y.
Then, we can use the fact that X and Y are independent to simplify the expression:
E[XY] = ∫∫ xy f(x) f(y) dxdy
= ∫ x f(x) dx ∫ y f(y) dy
= E[X]E[Y]
where f(x) and f(y) are the marginal probability density functions of X and Y, respectively.
Therefore, we have shown that under these conditions, E[XY] = E[X]E[Y].
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Explain why t distributions tend to be flatter and more spread out than the normal distribution.
t distributions tend to be flatter and more spread out than the normal distribution.
This is due to the fact that in the formula, the denominator is s rather than σ.
The distribution of the sample mean is normal if some samples are taken from a normal population with known variance. However, if the population variance is unknown, the distribution is not normal but Student-t with long tails. This means that sample means tend to be extreme when the population variance is unknown. Using the normal distribution instead of the t distribution to test the hypothesis increases the chance of error.
Note that there is a different t-distribution for each sample size. That is, the class of distributions. When talking about a particular t-distribution, we need to specify the degrees of freedom. The degrees of freedom for this t-statistic is given by the sample standard deviation s in the denominator of Equation 1. The spread is larger than the standard normal distribution. This is because the denominator of equation (1) is s, not σ. Because s is a random variable that changes from sample to sample, t becomes more volatile and more spread out.
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Brendan earns 1,826 each month.How much money does he earn in a year??
Answer:
21912 per year
Step-by-step explanation:
There are 12 months in a year, so multiply by 12
1826 * 12
21912 per year
Answer:
=> 21912 per year
Step-by-step explanation:
=> 1826×12
=> 21912
Jeff made 2 out of every 5 baskets he shot during basketball practice. If he took 25 shots, how many baskets did he make? You MUST show your proportion and work!
Answer:
30 many shoot basket did he make
I need this answered please
cybil and ronda are sisters. the letters from their names are placed on identical cards so that each of cards contains one letter. without replacement, two cards are selected at random from the cards. what is the probability that one letter is from each sister's name? express your answer as a common fraction.
Using the theories of probability, we got that 5/9 is the probability that one letter is from each sister's name if the letters from their names are placed on identical cards so that each of cards contains one letter. without replacement.
We know very well that if we want to count number of ways by which r object can be chosen from n objects ,this can be done in \(^nC_r\) ways which is equivalent to =(n!/(r!.(n-r)!)
Here are the same case, we have 10 cards, in each of the card there is letter written on it. So number of ways to choose two cards such that it contains any letter is can be done in \(^1^0C_2\) ways which is equivalent to 45 ways.
Similarly, number of ways of choosing card which contains only Cybil`s name =\(^5C_2\) ways=10 ways.
Similarly, number of ways of choosing card which contains only Ronda`s name =\(^5C_2\) ways=10 ways.
So the number of ways containing one letter from each name = 45 - 10 - 10 = 25
So....the probability of choosing one of these sets = 25 / 45 = 5 / 9 =0.55
Hence, Cybil and Ronda are sisters. the letters from their names are placed on identical cards so that each of cards contains one letter. without replacement, two cards are selected at random from the cards. the probability that one letter is from each sister's name is = 5/9.
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(Complete question) is:
cybil and ronda are sisters. the 10 letters from their names are placed on 10 identical cards so that each of cards contains one letter. without replacement, two cards are selected at random from the 10 cards. what is the probability that one letter is from each sister's name? express your answer as a common fraction.
Plzz helppp plzzzzzzzzzzz asap
Terra argues that is not a function because two different inputs produce the same output, as shown in the table.
Is Terra correct in claiming that is not a function?
Input Output
-1 2
0 0
1 2
Terra is
correct/incorrect
. In order for a relationship to be a function, each input value must result in
only one input/ multiple outputs
. In this equation, each input value does result in only one output value. It is
allowed/not allowed
for more than one input to have the same out. This does not mean that the relationship is not a function.
Terra is correct. In order for a relationship to be a function, each input value must result in only one input.
What is a function?A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a connection between inputs in which each input is connected to precisely one output. Each function has a range, codomain, and domain. The usual way to refer to a function is as f(x), where x is the input. A function is often represented as y = f. (x).
We know that for a function each input value must result in a unique output value. Terra claims this statement, and hence she is correct.
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Blaine and Lindsay McDonald have total assets valued at $346,000 and total debt of $168,000. What is Blaine and Lindsay's asset-to-debt ratio? a-0.49 b. 0.51 c.2.06 d.1.00
The correct answer is option (c) 2.06. For every dollar of debt, Blaine and Lindsay have approximately $2.06 in assets
The asset-to-debt ratio for Blaine and Lindsay McDonald can be calculated by dividing their total assets by their total debt. Using the given values, the calculation would be as follows:
Asset-to-debt ratio = Total assets / Total debt
= $346,000 / $168,000
The asset-to-debt ratio is a financial metric that provides insight into the financial health and leverage of an individual, company, or entity. It measures the proportion of assets to debt and is used to assess the ability to meet financial obligations and the level of risk associated with the amount of debt.
In this case, Blaine and Lindsay McDonald have total assets valued at $346,000 and total debt of $168,000. By dividing the total assets by the total debt, we obtain the asset-to-debt ratio of approximately 2.06. This means that for every dollar of debt, Blaine and Lindsay have approximately $2.06 in assets. A higher asset-to-debt ratio generally indicates a stronger financial position and lower risk, as there are more assets available to cover the debt obligations.
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The absolute maximum value of f(x)= x^3 -3x^2 +12 on the closed interval [-2,4] occurs at x=a) 4b) 2c) 1d) 0e) -2
The absolute maximum value of f(x) on the closed interval [-2, 4] occurs at x = -2 and x = 0, and the maximum value is 16. So the answer is option (e) -2.
To find the absolute maximum value of the function f(x) = x³ - 3x² + 12 on the closed interval [-2, 4], we need to evaluate the function at the critical points and at the endpoints of the interval, and then choose the largest value.
To find the critical points, we take the derivative of the function and set it equal to zero
f'(x) = 3x² - 6x = 3x(x - 2)
Setting f'(x) = 0 gives x = 0 and x = 2 as critical points.
Next, we evaluate the function at the critical points and at the endpoints of the interval
f(-2) = (-2)³ - 3(-2)² + 12 = 16
f(0) = (0)³ - 3(0)² + 12 = 12
f(2) = (2)³ - 3(2)² + 12 = 4
f(4) = (4)³ - 3(4)² + 12 = 4
Therefore, the correct option is (e) -2
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The absolute maximum value occurs at x = 4, with a value of 28. So, the answer is a) 4.
We occasionally encounter operations with hills and valleys. Hill and valley points in polynomial functions typically have many locations. We are aware that these places, which can be categorized as maxima or minima, are the function's critical points. The valley points are referred to as minimal and the hill points are as maxima. We must determine the locations of the function's global maxima and global minima, which are known as the minimum and maximum values, respectively, due to the fact that there are several maxima and minima.
To find the absolute maximum value of the function \(f(x) = x^3 - 3x^2 + 12\) on the closed interval [-2, 4], we need to examine the critical points and the endpoints of the interval.
First, find the critical points by taking the derivative of f(x) and setting it equal to 0:
\(f'(x) = 3x^2 - 6x\\0 = 3x^2 - 6x\\0 = 3x(x - 2)\)
The critical points are x = 0 and x = 2.
Next, evaluate the function at the critical points and the interval endpoints:
\(f(-2) = (-2)^3 - 3(-2)^2 + 12 = -8 - 12 + 12 = -8\\f(0) = 0^3 - 3(0)^2 + 12 = 12\\f(2) = 2^3 - 3(2)^2 + 12 = 8 - 12 + 12 = 8\\f(4) = 4^3 - 3(4)^2 + 12 = 64 - 48 + 12 = 28\)
The absolute maximum value occurs at x = 4, with a value of 28. So, the answer is a) 4.
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The larger of two numbers is 7 less than twice the
smaller number. If the sum of the numbers is 47,
find both numbers.
Answer:
The two numbers are 29 and 18
Step-by-step explanation:
Let x and y be the two numbers
x = 2y-7
x+y = 47
We have two equations and 2 unknowns
Substituting the first equation into the second equation
2y-7+y = 47
Combine like terms
3y -7 = 47
3y-7+7 = 47+7
3y = 54
Divide by 3
3y/3 = 54/3
y = 18
Now find x
x = 2y-7
x = 2*18 -7
x = 36-7
x = 29
The two numbers are 29 and 18
Your uncle wants to create a dog small enough to fit into a purse. Of the hundreds of dogs on his farm, he breeds only the smallest 10% of them. He then breeds only the smallest 10% of their offspring, and continues to breed only the smallest 10% of each generation. Over 20 years, he observes that his group of dogs did become smaller (though not small enough to fit into a purse). Which line of support does he have that his dogs have evolved?.
A kind of evolution through artificial selection is the practice of choosing creatures with desired features over several generations.
The mix of alleles found in an organism is known as its genotype. A phenotype is also the culmination of all the organism's discernible traits. In artificial selection, people choose animals or plants with favored phenotypic features for reproduction.
Since the phenotype is impacted by the genotype, the process of artificial selection alters allele frequencies throughout generations, resulting in the evolution of desirable features in offspring.
In conclusion, a kind of evolution through artificial selection is the practice of selecting creatures with desired qualities over several generations.
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Evaluate ∫ ∫ (x² + y²)dx dy over the region in the positive quadrant which x+y≤1.
The given double integral is ∫ ∫ (x² + y²)dx dy, and we need to evaluate it over the region in the positive quadrant where x+y≤1.
To evaluate this double integral, we can first determine the limits of integration for both x and y based on the given region. In the positive quadrant, x and y both range from 0 to 1.
Now, integrating the inner integral with respect to x, we get:
∫ (x² + y²)dx = (1/3)x³ + y²x + C1,
where C1 is the constant of integration.
Next, we integrate the resulting expression with respect to y:
∫ [(1/3)x³ + y²x + C1] dy = (1/3)x³y + (1/3)y³x + C1y + C2,
where C2 is another constant of integration.
Finally, we evaluate this double integral over the given region by substituting the limits of integration:
∫∫ (x² + y²)dx dy = ∫[0 to 1] ∫[0 to 1-x] (x² + y²)dy dx.
Performing the integration, we can find the numerical value of the double integral within the given region.
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Please help! i need 5 answers expect for the 1st one! 20 points
Answer:
The answer for number 2 is 700,000
3: 125,991 (62,776+439= 63,215, 63,215+ 62,776= 125,991)
4:754 (193+368=561, 561+193=754)
5: 350,000 (266,176+68,525+10,996=345,424: rounded to the nearest 10,000 is 350,000)
The volume of the right triangular prism is 19 in . If DE is equal to 16 inches and EF is equal to 24 inches, what is the length of EB
The length of EB is approximately 0.099 inches.
To solve this problem, we can use the formula for the volume of a right triangular prism, which is:
V = (1/2)bh × l
where V is the volume, b is the base of the triangle, h is the height of the triangle, and l is the length of the prism.
We are given that the volume of the prism is 19 in^3, so we can plug in that value:
19 = (1/2)(DE)(EF) × EB
Substituting the given values for DE and EF:
19 = (1/2)(16)(24) × EB
Simplifying:
19 = 192 × EB
Dividing both sides by 192:
EB = 19/192
So the length of EB is approximately 0.099 inches.
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HELP I NEED HELP ASAP
Answer:
C
Step-by-step explanation:
the first person's grows in a line/ with a slope and the second persons grows with a growth rate (the percent).
Answer:
C
Step-by-step explanation:
and forvthe explination the other person explained pretty well
Let Pij = the production of product i in period j. To specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units, we need to add which pair of constraints?
P52-P42 <= 80; P42-P52 <= 80
None of the other above.
P24 - P25 <= 80; P25-P24 >= 80
O P24 - P25 >= 80; P25-P24 >= 80
P24 - P25 <= 80; P25-P24 <= 80
The correct pair of constraints that needs to be added to specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units is: P24 - P25 <= 80; P25-P24 <= 80. Therefore, the correct option is 5.
Here, the given information is Pij = the production of product i in period j. We need to find the pair of constraints that will specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units. Thus, let the production of product 2 in period 4 and in period 5 be represented as P24 and P25 respectively.
Therefore, we can write the following inequalities:
P24 - P25 <= 80
This is because the production of product 2 in period 5 can be at most 80 units less than that of period 4. This inequality represents the difference being less than or equal to 80 units.
P25-P24 <= 80
This is because the production of product 2 in period 5 can be at most 80 units more than that of period 4. This inequality represents the difference being less than or equal to 80 units.
Therefore, we need to add the pair of constraints P24 - P25 <= 80 and P25-P24 <= 80 to specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units. Hence, option 5 is the correct answer.
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