Which of the following is the best description of matter?

Answer:

D

Explanation:

cause overall charge is +1 so will attract

The decomposition of 2 moles of ammonia gas will give one mole of nitrogen gas and 3 moles of hydrogen gas. This is an endothermic reaction.  

Ammonia is an inorganic gas formed by the combination of nitrogen gas and hydrogen gas. The industrial synthesis of ammonia gas is known as Haber process.

The formation of ammonia is a reversible process and ammonia can decompose to form the constituent gases nitrogen and hydrogen.

The balanced chemical equation of the decomposition of ammonia gas is written as follows:

\(\rm 2NH_{3} \rightarrow 3H_{2} + N_{2}\)

Therefore, the decomposition of 2 moles of ammonia gas will produce one mole of nitrogen gas.

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Like charges repel each other, while opposite charges attract each other. This principle is one of the fundamental aspects of electrostatics. According to Coulomb's law, the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

As the distance between two charged particles decreases, the force between them increases. This is because the closer the particles are, the stronger the electric field they create, leading to a stronger force of interaction.

On the other hand, as the magnitude of the charges decreases, the force between the particles also decreases. This is because the force is directly proportional to the product of the charges. If one or both of the charges are smaller, the force they exert on each other will be weaker.

In summary, according to Coulomb's law, decreasing the distance between charged particles increases the force between them, while decreasing the magnitude of the charges decreases the force. This understanding of the relationship between charge, distance, and force is crucial in explaining the behavior of charged particles and the interactions between them.

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Since there are exactly as many electrons in electrically neutral atoms as there are protons in the nucleus, the electron configuration for silver is different.

Therefore, there are 47 electrons in a neutral silver atom. The positive nuclear charge and the other (Z - 1) negative electrons in the atom create electric fields that have an impact on each electron. The silver orbital diagram in the illustration makes this very evident. Silver has a 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s 2 4p 6 4d 10 5s ground-state electron configuration. According to this electron configuration, silver has a single electron in its final shell and ten electrons altogether in its d-orbital.

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Answer:

Dung dịch nào sau đây chỉ chứa các ion (bỏ qua sự điện li của nước, các chất điện li mạnh phân li hoàn toàn)?

A. HBr, Na2S, Mg(OH)2, Na2CO3.

B. H2SO4, NaOH, NaCl, HF.

C. HNO3, H2SO4, KOH, K2SiO3.

D. Ca(OH)2, KOH, CH3COOH, NaCl.

Answer: i think it’s maintaining homeostasis

Explanation: idrk it’s my best guess, i’m taking the test rn and that’s what i’m gonna put. i have an A in this class lol so ‍♀️

Answer:

maintaining homeostasis

Explanation:

I got it on my test and I got it right.

Answer:

a. A color change

c. Precipitate being formed

e. A change in temperature

f. Bubbles being produced

Explanation:

Two types of changes occur namely: physical changes and chemical changes. A physical change does not affect the chemical composition of the substance involved. Physical changes include change of state etc.

However, on the other hand, a chemical change alters the chemical composition of the substances involved, hence, leading to the formation of new product(s). It is also called a chemical reaction. Since a new product is formed from the alteration of the chemical nature of the reacting substances, the following changes or indicators will be present or evident in a chemical reaction:

- color change of substance

- Precipitate being formed i.e. solid deposit

- A change in temperature

- Bubbles being produced (evolution of gas)

Answer:

Explanation:

I₂ + 2 e = 2I⁻

I₂ converts itself into I⁻ by accepting electron . In this process it increases the oxidation number of element from which it takes electron . Hence it is an oxidizing agent .

Similarly O₂ is also an oxidizing agent .

O₂ + 4e = 2O⁻²

Al is a reducing agent .

Al = Al⁺³ + 3 e

Al gives 3 electrons to other element whose oxidation number is reduced . Hence it is reducing agent .

Similarly Cr is also a reducing agent .

Cr = Cr⁺³ + 3 e .

Answer:

see explaination

Explanation:

Case 1) When we consider vapor pressure of H2O;

Let the pressure is 1 atm OR 760 torr.

As H2 is collected over water, we have to consider the vapor pressure of H2O as well.

Using data i.e. vapor pressure of H2O at 40° C = 55.365 torr

So, pressure of H2 = P = 760 - 55.365 = 704.635 torr = 704.635/760 = 0.9272 atm

Volume of H2 = 80 ml = 0.08 liter

Temperature (T) = 40 + 273 = 313 K

Gas constant (R) = 0.0821 L atm/mol K

Let n is moles of H2. Applying ideal gas equation;

PV = nRT

n = PV/RT = 0.9272 * 0.08 / 0.0821 * 313

n = 0.00289 moles

Mass of H2 = moles * molar mass = 0.00289 * 2.016 = 0.00582 grams

OR 5.8*10^-3 grams ...Answer

----> Case 2) When we don't consider vapor pressure;

Pressure of H2 = 1 atm, all other parameters will remain same as in case 1.

So, mass of H2 = 6.3*10^-3 grams

But Case 1) is correct approach as in question it is mentioned that H2 is collected over water.

Answer:

liquid B

Explanation:

because of the density of liquid A being 8, liquid B being 3 would be less dense

Answer:

The role of Chemistry in the field of Economics is as a driving force in all industries, from basic materials for industrial machinery to industrial raw materials.

Answer: B. 430 K

Explanation:

According to Gibb's equation:

\(\Delta G=\Delta H-T\Delta S\)

\(\Delta G\) = Gibbs free energy  

\(\Delta H\) = enthalpy change  = +62.4 kJ/mol

\(\Delta S\) = entropy change  = +0.145 kJ/molK

T = temperature in Kelvin

\(\Delta G\)  = +ve, reaction is non spontaneous

\(\Delta G\)  = -ve, reaction is spontaneous

\(\Delta G\)  = 0, reaction is in equilibrium

\(\Delta H-T\Delta S=0\) for reaction to be spontaneous

\(T=\frac{\Delta H}{\Delta S}\)

\(T=\frac{62.4kJ/mol}{0.145kJ/molK}=430K\)

Thus the Reaction is spontaneous when temperature is 430 K.

Answer:

430 K

Explanation:

i just took the test on a pex :)

Answer:

Explanation:

To calculate the volume of Oxygen gas that would be required to produce a given amount of Fe2O3, we need to use the balanced chemical equation for the corrosion (rusting) of iron. The equation is:

3 O2 (g) + 4 Fe (s) —> 2 Fe,O3 (s)

This equation tells us that for every 3 molecules of Oxygen gas that react with 4 molecules of Iron, 2 molecules of Iron (III) oxide (Fe2O3) are produced. Since the atomic weight of Oxygen is 16.0 g/mol and the atomic weight of Iron is 56.0 g/mol, the molar ratio of Oxygen to Iron in the equation is 3/16 = 0.1875.

We can use this molar ratio to calculate the volume of Oxygen gas that would be required to produce a given amount of Fe2O3. To do this, we first need to convert the mass of Fe2O3 to moles. Since the atomic weight of Fe2O3 is 159.7 g/mol, 32.0 g of Fe2O3 is equivalent to 32.0 / 159.7 = 0.201 moles of Fe2O3.

We can then use the molar ratio of Oxygen to Iron to calculate the number of moles of Oxygen gas that would be required to produce 0.201 moles of Fe2O3. Since the molar ratio of Oxygen to Iron is 0.1875, 0.201 moles of Fe2O3 would require 0.201 * 0.1875 = 0.0376 moles of Oxygen gas.

Finally, we can use the molar volume of a gas at standard temperature and pressure (STP) to convert the number of moles of Oxygen gas to volume. At STP, one mole of a gas occupies a volume of 22.4 liters, so 0.0376 moles of Oxygen gas would occupy a volume of 0.0376 * 22.4 = 0

Geh lang

Answer: 40m/s

Explanation:

Answer:

Hope this helps ;) don't forget to rate this answer !

Explanation:

The molar mass of a sample can be calculated using the formula:

Molar mass = (molecular weight) / (number of moles)

To find the molar mass, we first need to find the molecular weight of the sample. The molecular weight is the weight of a single molecule of the substance in atomic mass units (amu).

To find the molecular weight, we need to convert the weight of the molecule from grams to amu. One amu is equal to 1.66 x 10^-24 grams.

So, to convert the weight of the molecule from grams to amu, we can divide the weight of the molecule (5.34 x 10^-23 grams) by the conversion factor (1.66 x 10^-24 grams/amu):

Molecular weight (amu) = (5.34 x 10^-23 grams) / (1.66 x 10^-24 grams/amu)

= 3.22 x 10^-22 amu

Now that we have the molecular weight, we can use it to calculate the molar mass. However, we need to know the number of moles in order to do this. Without this information, it is not possible to calculate the molar mass.

Answer:

i agree

Explanation:

Answer:

a) 101%

b)59.7%

Explanation:

The equation for the thermal decomposition of baking soda is shown;

2NaHCO3 → Na2CO3 + H2O + CO2

Number of moles of baking soda= mass/molar mass= 1.555g/84.007 g/mol = 0.0185 moles

From the reaction equation;

2 moles of baking soda yields 1 mole of sodium carbonate

0.0185 moles of baking soda will yield = 0.0185 moles ×1 /2 = 9.25 ×10^-3 moles of sodium carbonate.

Therefore, mass of sodium carbonate= 9.25 ×10^-3 moles × 106gmol-1= 0.9805 g of sodium carbonate. This is the theoretical yield of sodium carbonate.

%yield = actual yield/theoretical yield ×100

% yield = 0.991/0.9805 ×100

%yield = 101%

Since ;

2NaHCO3 → Na2CO3 + H2O + CO2

And H2O + CO2 ---> H2CO3

Hence I can write, 2NaHCO3 → Na2CO3 + H2CO3

Molar mass of H2CO3= 62.03 gmol-1

Molar mass of baking soda= 84 gmol-1

Therefore, mass of baking soda=

0.325/62.03 × 2 × 84 = 0.88 g of NaHCO3

% of NaHCO3= 0.88/1.473 × 100 = 59.7%

The decomposition reaction of baking soda is a reaction in which water and carbon dioxide ae given off as gaseous products.

Reasons:

Mass of baking soda = 1.555 g

Mass of Na₂CO₃ produced = 0.991 g

Required:

Calculation for the theoretical yield

Solution:

Theoretical yield (mass) of Na₂CO₃ produced is found as follows;

Molar mass of Na₂CO₃ = 105.9888 g/mol

Molar mass of NaHCO₃ = 84.007 g/mol

\(\displaystyle 1.555 \, g \, NaHCO_3 \times \frac{1 \, mol \, NaHCO_3}{84.007 \, g \, NaHCO_3} \times \frac{1 \, mol \, Na_2CO_3}{2 \, mol \, NaHCO_3} \times 105.9888 \ g \approx 0.9809 \, g \, Na_2CO_3\)

The theoretical yield of Na₂CO₃ ≈ 0.9809 grams.

The percentage yield is given as follows;

\(\displaystyle Percentage \ yield = \mathbf{\frac{Actual \, Yield}{Theorectical \, Yield} \times 100 \%}\)

The percentage yield of Na₂CO₃ is therefore;

\(\displaystyle Percentage \ yield \ of \ Na_2CO_3= \frac{0.991}{0.9809} \times 100 \% \approx \underline{ 101.02 \%}\)

(Some baking soda may remain if the reaction is not completed)

6. Mass of the unknown mixture of baking soda = 1473 g

Mass loss from the mixture = 0.325 g

Required:

The percentage of NaHCO₃ in the mixture.

Solution:

The chemical in the mass loss from heating the NaHCO₃ = H₂CO₃

Molar mass of H₂CO₃ = 62.03 g/mol

\(\displaystyle \mathrm{Number \ of \ moles \ of \ H_2CO_3 \ produced} = \frac{0.325 \, g}{62.03 \, g/mol} \approx 5.2394 \times 10^{-3} \ moles\)

The chemical reaction is presented as follows;

The number of moles of NaHCO₃ in the mixture is therefore;

Mass of NaHCO₃ in the mixture is therefore

\(\displaystyle Percentage \ of \ NaHCO_3 \ in \ the \ mixture \ = \mathbf{ \frac{Mass \ of \ NaHCO_3}{Mass \ of \ mixture} \times 100}\)

Which gives;

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There are 0.2107 moles of KBr are dissolved in 60.2 mL of a 3.50 M solution.

The molarity of a substance is defined as the number of moles of solute present in 1 litre of a solution.

According to the given data, the molarity of the solution tells us that there are 3.50 moles of KBr in 1000mL of solution. But we only have 60.2mL of solution, so with a mathematical rule of three we can calculate the amount of moles in 60.2mL:

1000 ml - 3.50 moles

60.2 ml -x = 60.2 ml× 3.50 moles/1000 ml

x= 60.2 ml -0.2107 moles

So, there are 0.2107 moles of KBr.

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Answer:

7x-2(3-4)-2

Pls help

Explanation:

The term that the scientist would use in this case is partial pressure. Option D

The pressure that one particular gas component within a mixture of gases exerts is referred to as partial pressure. It is the pressure that the gas would experience at the same temperature if it were the only thing in the entire volume.

When researching gas mixtures, such as in gas laws, gas phase equilibria, and gas collecting methods, partial pressures are extremely crucial for the gas.

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The balanced chemical equation is 3 Sr(OH)₂ + Al₂(SO₄)₃\(\rightarrow\) 3 SrSO₄ + 2 Al(OH)₃.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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Answer:

A Parasite.

Explanation:

Viruses and bacteria can survive in most areas without a host. Parasites however need a host to survive. Some parasites include: tapeworm, roundworms, flukes, and protozoa.

Explanation:

Because radioactive isotopes decay at a constant rate, they can be used like clocks to measure the age of the material that contains them. In this process, called radiometric dating, scientists measure the amount of parent isotope and daughter isotope in a sample of the material they want to date.

Answer:

Because radioactive isotopes decay at a constant rate, they can be used like clocks to measure the age of the material that contains them. In this process, called radiometric dating, scientists measure the amount of parent isotope and daughter isotope in a sample of the material they want to date.

Explanation:

The weight of the beaker is 65g.

Comparing the weights:

Finally, the sum of the mass of water and the mass of salt causes the total weight to increase, so the weight of the aquarium changes.

Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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Answer:

Percent yield of reaction is 150%.

Explanation:

Given data:

Percent yield = ?

Actual yield of SO₃ = 586.0 g

Mass of SO₂ = 705.0 g

Mass of O₂ = 80.0 g

Solution:

Chemical equation:

2SO₂ + O₂      →     2SO₃

Number of moles of SO₂:

Number of moles = mass/ molar mass

Number of moles = 586.0 g/ 64.1 g/mol

Number of moles = 9.1 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 80.0 g/ 32g/mol

Number of moles = 2.5 mol

Now we will compare the mole of SO₃ with O₂ and SO₂.

                      SO₂          :          SO₃

                        2             :            2

                     9.1              :           9.1

                       O₂            :          SO₃

                        1              :            2

                     2.5             :           2×2.5 = 5

The number of moles of SO₃ produced by oxygen are less it will limiting reactant.

Theoretical yield of SO₃:

Mass = number of moles × molar mass

Mass = 5 mol × 80.1 g/mol

Mass = 400.5 g

Percent yield of reaction:

Percent yield = actual yield / theoretical yield  × 100

Percent yield = 586.0 g/ 400.5 g× 100

Percent yield = 1.5× 100

Percent yield = 150%

Answer:

The correct Answer IS B

Explanation:

Since B has 5 figures, and all the number are other than zero

Hope i Helped

Answer: I believe the answer is B). 36,238 due to having 5 Different place values all different than zero

Answer:

The Ranking from

Hardest to softest is as follows :

0.80 wt% C with fine pearlite.

0.80 wt% C with spheroidite

0.25 wt% C with coarse pearlite

0.25 wt% C with spheroidite

Explanation:

To find - Rank the following iron-carbon alloys and associated microstructures from the hardest to the softest. Justify this ranking.

Solution -

Ranking is as follows :

(d) 0.80 wt% C with fine pearlite.

(b) 0.80 wt% C with spheroidite

(a) 0.25 wt% C with coarse pearlite

(c) 0 25 wt% C with spheroidite

Justification -

For some wt% C,

Fine pearlite is stronger than spheroidite

and

Coarse pearlite is stronger than spheroidite.

Now,

Due to carbon content,

0.80 wt% C with spheroidite is stronger than 0.25 wt% C with coarse pearlite.

So,

The Ranking from

Hardest to softest is as follows :

0.80 wt% C with fine pearlite.

0.80 wt% C with spheroidite

0.25 wt% C with coarse pearlite

0.25 wt% C with spheroidite

Answer:

Oxygen sodium hydrogen iron potassium chlorine are elements

Water is a compound

And magnesium ion is cation.

Morever oxygen hydrogen and chlorine are gases

Water and magnesium ion are liquid

And sodium iron potassium are solids

Explanation: