Which of the following is the Arrhenius equation?
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The quantum numbers that are not possible are 16,14,15.

The quantum numbers are used to address the position of the electron in an atom. They are the set of numbers that show the most probable position of the electron in an atom. There are four sets of quantum numbers that describe the position of an electron and they are;

1) Principal quantum number

2) Orbital quantum number

3) Magnetic quantum number

4) Spin quantum number.

The set of quantum numbers 16,14,15 is not possible because ml must have values of -l to +l as we know.

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If we sum the molar masses of the elements, we find that the molar mass of the compound C₅₅H₇₂N₄O₅ is 869.31 g/mol.

The molar mass is the mass in grams of 1 mole of a substance.

To calculate the molar mass of a compound, we need to sum the molar masses of the elements that form it, which can be found in the periodic table.

M(C₅₅H₇₂N₄O₅) = 55 M(C) + 72 M(H) + 4 M(N) + 5 (O)

M(C₅₅H₇₂N₄O₅) = 55 (12.01 g/mol) + 72 (1.01 g/mol) + 4 (14.01 g/mol) + 5 (16.00 g/mol) = 869.31 g/mol

There is a mistake in the question. The original question is:

C₅₅H₇₂N₄O₅, what is the molar mass?

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Answer:stow the hairspray

Explanation:

Answer:

The balanced chemical equation:

3 NH₃ + H₃PO₄ → (NH₄)₃PO₄

From the equation we see:

3 moles of NH₃ gives 1 mole (NH₄)₃PO₄

0.085 mole NH₃ will gives ?? mole (NH₄)₃PO₄

By cross multiplication:

number of moles of (NH₄)₃PO₄ = 0.085 * 1/3 = 0.028 mole

Explanation:

Answer: 4

Explanation: because the zero doesn't count

Answer:

X(HCO3)2 is X2(C2H2O6), so the total number of atoms for each element can be calculated:

2 X atoms

4 H atoms

6 C atoms

12 O atoms

Calculate the total atomic mass of the elements:

2 X atoms * atomic mass of X = 2X * atomic mass of X

4 H atoms * 1.0 amu = 4.0 amu

6 C atoms * 12.0 amu = 72.0 amu

12 O atoms * 16.0 amu = 192.0 amu

The molar mass of X(HCO3)2 is 162 g/mol, so the total atomic mass of the elements should add up to 162 g/mol:

2X * atomic mass of X + 4.0 amu + 72.0 amu + 192.0 amu = 162 g/mol

Solve for X by rearranging the equation:

2X * atomic mass of X = 162 g/mol - 4.0 amu - 72.0 amu - 192.0 amu = -12.0 amu

2X = -12.0 amu / atomic mass of X

Divide both sides by 2:

X = -6.0 amu / atomic mass of X

So the relative atomic mass of X is 6.0 amu.

Answer:

How do amoeba respire.

Define Diffusion.

CuI2 is not a known compound. Copper compounds typically have different oxidation states for copper, resulting in various compound names.

Copper(II) oxide (CuO): It is a black solid compound where copper is in the +2 oxidation state. It is commonly used as a pigment and in catalytic reactions.

Copper(II) sulfate (CuSO4): It is a blue crystalline compound in which copper is in the +2 oxidation state. It is used in various applications such as agriculture, electroplating, and as a laboratory reagent.

Copper(I) oxide (Cu2O): It is a red crystalline compound in which copper is in the +1 oxidation state. It is used as a pigment, in solar cells, and as a catalyst.

Copper(II) chloride (CuCl2): It is a greenish-brown solid compound in which copper is in the +2 oxidation state. It is utilized in various chemical processes, including etching and catalyst synthesis.

Copper(II) nitrate (Cu(NO3)2): It is a blue crystalline compound where copper is in the +2 oxidation state. It is commonly used in the production of catalysts, as a coloring agent, and in electroplating.

These are just a few examples of copper compounds with different oxidation states and properties. It's important to note that the compound CuI2 mentioned in the question, if it exists, would be an exception to the typical nomenclature for copper compounds.

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Answer:

Limitation of comparative investigation is that when it is done on a huge population, huge amount cost is required. Explanation: Benefit of comparative investigation is that we can get descrete information about specific breed or species. It is important for the study of behaviour of many organisms.

Explanation:

Answer:

which language is this please tell me

The right brain part of the brain is affected by a smell, a song, or a photograph.

The right brain is more intuitive and visually oriented. It is occasionally referred to as the analog brain. It thinks less logically and with more creativity. According to out-of-date research by Sperry, the right brain aids in creativity.

Posterior parietal cortex of the parietal lobe of the brain mainly deals with the photographs.

The olfactory bulb, a structure in the front of the brain, processes smells before sending data to other regions of the body's central nervous system.

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The right brain part of the brain is affected by a smell, a song, or a photograph.

What is Right Brain?

The right brain is more intuitive and visually oriented. It is occasionally referred to as the analog brain. It thinks less logically and with more creativity. According to out-of-date research by Sperry, the right brain aids in creativity.

Which part of brain deals with photograph?

Posterior parietal cortex of the parietal lobe of the brain mainly deals with the photographs.

Which part of brain deals with Smell?

The olfactory bulb, a structure in the front of the brain, processes smells before sending data to other regions of the body's central nervous system.

The cell produces an emf of 2.32 V. For this cell reaction at 25 degrees Celsius, use the Nernst equation. where n represents the number of electrons exchanged during the cellular process.

According to measurements, the electromotive force (EMF) is 1.100 V. The standard condition is specified as a concentration of 1 M in an ideal solution, and as a result, 1.100 V is the standard electromotive force, DEo, or standard cell potential for the Zn–Cu galvanic cell.

Due to the larger standard reduction potential of the silver half-cell, the reduction will occur. The half-cell of tin will oxidize. The formula E0cell=E0red+E0oxid can be used to get the overall cell potential.

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The ion that could bond with a calcium ion (Ca2+) to form a neutral ionic compound is option A. Cl-.

This is because the calcium ion has a +2 charge, and the chloride ion (Cl-) has a -1 charge. When these two ions bond together, they form the compound CaCl2, which has a net charge of zero and is therefore neutral.

In order for an ionic compound to be neutral, the charges of the ions must cancel each other out. Therefore, the calcium ion needs to bond with an ion that has a -2 charge in order to form a neutral compound. The chloride ion is the only ion listed that has a -1 charge, and therefore it is the only one that can bond with the calcium ion to form a neutral compound.

So the correct answer is option A. Cl-.

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If 10.0 g of MgSO4⋅7H2O is thoroughly heated, the mass of anhydrous magnesium sulfate will remain is 4.88 grams.

Mass is the unit that quantify the matter in a physical body.

The molar mass of the MgSO4⋅7H2O is 246.47 grams.

When magnesium sulfate is heated, the molar mass of magnesium sulfate become 120.36 g/mol

Now, both molar masses are divide and multiplied by 10

\(\dfrac{120.36 g/mol}{246.47} \times 10 = 4.88 g.\)

Thus, the mass of anhydrous magnesium sulfate will remain is 4.88 grams.

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The amount of heat required to raise the temperature of the 34.2 g sample of aluminum by 34 oC is 1043.52 J.

What is Temperature?

Temperature is a measure of the average kinetic energy of the particles in a substance. It is a physical property that determines the direction of heat flow between two objects or systems in contact with each other. Temperature is measured in degrees Celsius (°C) or Fahrenheit (°F), or in kelvin (K) in the International System of Units (SI).

The amount of heat (q) required to raise the temperature of a substance can be calculated using the formula:

q = m x c x ΔT

Where:

m = mass of the substance (in grams)

c = specific heat of the substance (in J/g oC)

ΔT = change in temperature (in oC)

Plugging in the values given:

m = 34.2 g

c = 0.9 J/g oC

ΔT = 34 oC

q = (34.2 g) x (0.9 J/g oC) x (34 oC)

q = 1043.52 J

Therefore, the amount of heat required to raise the temperature of the 34.2 g sample of aluminum by 34 oC is 1043.52 J.

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Answer:

It is electrical → heat, sound, and motion

because a hair dryer makes heat to dry your hair and sound is the blowing and motion is how it goes

Explanation:

Answer:

A

Explanation:

electrical -- heat sound, and motion

Answer:

Kc = 2.55x10⁻³

Kp = 10.97

Explanation:

Based on the reaction:

2 NH₃(g) ⇄ N₂(g) + 3H₂(g)

2 moles of ammonia produce 1 mole of nitrogen and 3 of hydrogen.

Kc is defined as:

Kc = [N₂] [H₂]³ / [NH₃]²

When 2.00 moles of NH₃ are added in a vessel and the reaction occurs, when the reaction is in equilibrium the moles of each specie is:

NH₃: 2.00moles - 2X

N₂: X

H₂: 3X

Where X represents reaction coordinate.

As moles in equilibrium of NH₃ are 1.740moles:

1.740 mol = 2.00 - 2X

0.13moles = X

That means moles of N₂ are 0.13 and H₂ 0.39

Replacing in Kc formula:

Kc = [0.13] [0.39]³ / [1.74]²

To obtain Kp from Kc you need to use the formula:

Kp = Kc (RT)^Δn

Where R is 0.082atmL/molK, T is temperature in Kelvin (800K) and Δn is change in moles of gas, that is moles of products - moles of reactants ( 4 - 2 = 2)

Replacing:

Kp = 2.55x10⁻³(0.082atmL/molKₓ800K)²7

The values of Kp and Kc for the decomposition reaction of ammonia at 800k is 2.5 × 10⁻³ and 10.97 respectively.

Kp and Kc both are equilibrium constants with respect to the partial pressure and concentration in molaity respectively.

Given chemical reaction with ICE table will be represented as:

                          2 NH₃(g)  ⇄  N₂(g)  +  3H₂(g)

Initial:                        2                0            0

Change:                  -2x              +x          +3x

Equilibrium:            2-2x             x             3x

According to the question moles of NH₃ at equilibrium is 1.740 mol, so

2 - 2x = 1.740 mol

x = 0.13moles

Kc equation for the given reaction is:

Kc = [N₂].[H₂]³ / [NH₃]²

Kc = (x).(3x)³ / (0.13)²

Kc = 2.5 × 10⁻³

Kp will be calculated as:

Kp =  Kc.(RT)ⁿ, where

R = universal gas constant = 0.082atmL/mol.K

T = temperature = 800K

n = change in moles = 4 -2 = 2

Kp = (2.5 × 10⁻³)[(0.082)(800)]²

Kp = 10.97.

Hence value of Kp & Kc is 2.5 × 10⁻³ and 10.97 respectively.

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Answer:

\(\Delta H_{f,C_3H_4}=276.8kJ/mol\)

Explanation:

Hello!

In this case, since the equation we use to model the heat exchange into the calorimeter and compute the heat of reaction is:

\(\Delta H_{rxn} =- m_wC_w\Delta T\)

We plug in the mass of water, temperature change and specific heat to obtain:

\(\Delta H_{rxn} =- (35000g)(4.184\frac{J}{g\°C} )(2.316\°C)\\\\\Delta H_{rxn}=-339.16kJ\)

Now, this enthalpy of reaction corresponds to the combustion of propyne:

\(C_3H_4+4O_2\rightarrow 3CO_2+2H_2O\)

Whose enthalpy change involves the enthalpies of formation of propyne, carbon dioxide and water, considering that of propyne is the target:

\(\Delta H_{rxn}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{f,C_3H_4}\)

However, the enthalpy of reaction should be expressed in kJ per moles of C3H4, so we divide by the appropriate moles in 7.00 g of this compound:

\(\Delta H_{rxn} =-339.16kJ*\frac{1}{7.00g}*\frac{40.06g}{1mol}=-1940.9kJ/mol\)

Now, we solve for the enthalpy of formation of C3H4 as shown below:

\(\Delta H_{f,C_3H_4}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{rxn}\)

So we plug in to obtain (enthalpies of formation of CO2 and H2O are found on NIST data base):

\(\Delta H_{f,C_3H_4}=3(-393.5kJ/mol)+2(-241.8kJ/mol)-(-1940.9kJ/mol)\\\\\Delta H_{f,C_3H_4}=276.8kJ/mol\)

Best regards!

Answer:

P₂ = 1.12 atm

Explanation:

To find the new pressure, you need to use the Combined Gas Law:

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)

In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the new pressure, volume, and temperature. Before plugging the values into the equation, you need to

(1) convert the pressure from mmHg to atm (760 mmHg = 1 atm)

(2) convert the temperatures from Celsius to Kelvin (°C + 273)

The final answer should have 3 sig figs like the given values.

P₁ = 365 mmHg / 760 = 0.480 atm           P₂ = ? atm

V₁ = 5.00 L                                                   V₂ = 2.30 L

T₁ = 20°C + 273 = 293 K                             T₂ = 40°C + 273 = 313 K

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)                                              <----- Combined Gas Law

\(\frac{(0.480 atm)(5.00 L)}{293 K}=\frac{P_2(2.30 L)}{313 K}\)                       <----- Insert values

\(0.00819=\frac{P_2(2.30 L)}{313 K}\)                                     <----- Simplify left side

\(2.56 = P_2(2.30L)\)                                      <----- Multiply both sides by 313

\(1.12 = P_2\)                                                  <----- Divide both sides by 2.30

In the given equation 5.96 L of O2 will be produced.

What is chemical equation?

A chemical equation is a symbolic representation of a chemical reaction that shows the reactants on the left side and the products on the right side, with the coefficients indicating the relative amounts of each substance involved. It follows the law of conservation of mass, which states that mass cannot be created or destroyed in a chemical reaction.

The balanced equation for the reaction is:

2Li₂O(s) → O₂(g) + 4Li(s)

From the equation, we can see that 2 moles of Li₂O produces 1 mole of O₂. We can use this ratio to convert the mass of Li₂O to moles of O₂

First, we need to calculate the number of moles of Li₂O:

n(Li₂O) = m/M

where m is the mass of Li₂O and M is the molar mass of Li₂O. The molar mass of Li₂O is:

M(Li₂O) = 2(M(Li) + M(O)) = 2(6.941 g/mol + 15.999 g/mol) = 45.88 g/mol

Plugging in the values, we get:

n(Li₂O) = 25 g / 45.88 g/mol = 0.544 mol

According to the balanced equation, 2 moles of Li₂O produce 1 mole of O2. So, the number of moles of O2 produced is:

n(O2) = 0.544 mol / 2 = 0.272 mol

Finally, we can convert the number of moles of O2 to liters using the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Assuming the reaction occurs at standard temperature and pressure (STP), which is 0°C (273.15 K) and 1 atm, we can simplify the equation to:

V = nRT/P

Plugging in the values, we get:

V = (0.272 mol) (0.08206 L·atm/mol·K) (273.15 K) / 1 atm = 5.96 L

Therefore, we can expect 5.96 L of O2 to be produced.

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Answer:

1.5 × 10² mL

Explanation:

Step 1: Given data

Step 2: Calculate the final volume of the gas

For an ideal gas, we can calculate the final volume of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 1.9 atm × 80 mL/1.0 atm

V₂ = 1.5 × 10² mL

Since the pressure decreased, the volume of the gas increased.

Answer:

Nucleic acid is an important class of macromolecules found in all cells and viruses. Deoxyribonucleic acid (DNA) encodes the information the cell needs to make proteins.

A related type of nucleic acid, called ribonucleic acid (RNA), comes in different molecular forms that participate in protein synthesis.

Answer:

A) An electrolytic cell, because it absorbs energy.

Explanation:

The major difference between an electrolytic cell and a voltaic cell is that, in an electrolytic cell, there must be input of energy from outside (a cell) to drive the non spontaneous reaction while in a voltaic cell, the reaction proceeds on its own and releases energy which could be harnessed to do work.

Hence, considering the equation; 2H2O+ electricity → 2H2 + O2 , energy is supplied as electricity in order for the process to take place. This is an example of an electrolytic cell.

From the attached image, the volume of the air column is 300 mL and the temperature of the gas is 3°C.

The relationship between the temperature and the volume of a given mass of air is described by the gas law known as Charles's law. According to this law, the volume of a fixed amount of gas (such as air) held at constant pressure is directly proportional to its absolute temperature (measured in Kelvin). In other words, as the temperature of the air increases, its volume will also increase, and vice versa.

Mathematically, Charles's law can be expressed as:

V ∝ T

where V is the volume of the gas, T is its absolute temperature, and the symbol "∝" means "is proportional to".

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Explanation:

The following image describes the pH scale:

Between 0 and 7 we have an acidic solution, 7 is a neutral solution, and a solution with pH between 7 and 14 is a basic solution.

Answer: basic

Answer:

C.

Explanation:

The water is being stored for the time being, and potential energy is, essentially, defined like that. Once the energy is utilized, it will turn into kinetic energy.

The median reaction at the second end point in the HCl and NaOH titration is: HCl + NaOH → NaCl + H2O

In a titration between hydrochloric acid (HCl) and sodium hydroxide (NaOH), the reaction involved is the neutralization reaction between an acid and a base. The balanced equation for this reaction is:

HCl + NaOH → NaCl + H2O

In this reaction, one mole of HCl reacts with one mole of NaOH to form one mole of NaCl (sodium chloride) and one mole of water.

During the titration process, the reaction occurs gradually as the base is added to the acid solution.

The first end point of the titration is reached when the moles of HCl and NaOH are stoichiometrically equivalent, meaning they react in a 1:1 ratio. At this point, all the HCl has been neutralized by the NaOH, and no excess of either reagent remains.

However, if the titration is continued beyond the first end point, the reaction between HCl and NaOH can still occur, albeit in a different ratio.

The second end point refers to the point where the moles of NaOH added exceed the stoichiometrically required amount to neutralize the HCl completely. As a result, any excess NaOH added after the second end point reacts with the excess HCl in a 1:1 ratio.

Therefore, the median reaction at the second end point in the HCl and NaOH titration is:

HCl + NaOH → NaCl + H2O

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The process of catalysis  which involves adding a catalyst  to a chemical reaction, increases the rate of the reaction.

Thus, Catalysts are not destroyed during the reaction and are unaffected by it. Very tiny amounts of catalyst are frequently sufficient when the reaction is swift and the catalyst recycles quickly; mixing, surface area, and temperature are key factors in reaction rate.

In order to regenerate the catalyst, it usually reacts with one or more reactants to produce intermediates that then give off the ultimate reaction product.

Homogeneous catalysis, in which all of the components are dispersed in the same phase as the reactant (often a gas or liquid), and heterogeneous catalysis, in which the components are not.

Thus, The process of catalysis  which involves adding a catalyst  to a chemical reaction, increases the rate of the reaction.

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Answer:

I think S.T.E.M but i'm not 100% sure

Explanation: