An electron is placed midway between two fixed charges, ql = 2.5 X 10^- 10 C and q2 = 5 X 10^- 10 C. If the charges are 1 m apart, what is the velocity of the electron when it reaches a point 10 cm from q2?
To find the velocity of the electron when it reaches a point 10 cm from q2, we can use the principle of conservation of energy.
The electric potential energy between two charges is given by the equation:
PE = k * (|q1*q2| / r)
Where:
PE is the electric potential energy
k is the Coulomb's constant (8.99 × 10^9 N·m^2/C^2)
q1 and q2 are the charges
r is the distance between the charges
Given:
q1 = 2.5 × 10^-10 C
q2 = 5 × 10^-10 C
r = 1 m
The electric potential energy when the electron is midway between the charges (r = 0.5 m) is:
PE_initial = k * (|q1*q2| / r_initial)
= (8.99 × 10^9 N·m^2/C^2) * (|(2.5 × 10^-10 C)*(5 × 10^-10 C)| / 0.5 m)
Now, let's calculate the electric potential energy when the electron is at a point 10 cm (0.1 m) from q2:
PE_final = k * (|q1*q2| / r_final)
= (8.99 × 10^9 N·m^2/C^2) * (|(2.5 × 10^-10 C)*(5 × 10^-10 C)| / 0.1 m)
According to the conservation of energy, the change in electric potential energy is equal to the change in kinetic energy:
ΔPE = ΔKE
PE_final - PE_initial = (1/2) * m * v^2
We know the electron's mass is approximately 9.10938356 × 10^-31 kg.
Rearranging the equation to solve for the velocity (v):
v = √((2 * (PE_final - PE_initial)) / m)
Substituting the given values and calculating:
v = √((2 * (PE_final - PE_initial)) / m)
= √((2 * ((8.99 × 10^9 N·m^2/C^2) * (|(2.5 × 10^-10 C)*(5 × 10^-10 C)| / 0.1 m)) - (8.99 × 10^9 N·m^2/C^2) * (|(2.5 × 10^-10 C)*(5 × 10^-10 C)| / 0.5 m))) / (9.10938356 × 10^-31 kg)
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A 2. 9 kg model rocket accelerates at 15. 3 m/s2 with a force of 44 N. Before launch, the model rocket was not moving. After the solid rocket engine ignited, hot gases were pushed out from the rocket engine nozzle and propelled the rocket toward the sky. Which of Newton’s laws apply in this example? Select three options. The first law the second law the third law the fourth law the fifth law.
Answer:
The first law: the law of Inertia.
Explanation:
Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
Answer:
1st, 2nd, & 3rd law
Explanation:
there is no 5th/4th law ppl
I did this question and it says SELECT 3 OPTIONS not 1 (This answer isn’t meant to be rude but just stating what the question says.)
A ball with a mass of 2.31 kilograms is rolling down a hill. What is the weight of the
ball? Write your calculation with units for all quantities. PLEASE HELP T-T
Answer:
cities grow all around
making bunches of funny sounds
Explanation:
A new fridge is empty and is switched on for the first time. It contains 0277m^3 of air. It also contains plastic shelves of mass 595g. The fridge can offer internal energy at a rate of 10.3W.
Calculate the time, in seconds taken for the fridge to cool to 5.00 degrees celcius.
room temp = 19.5 degrees celcius.
Specific heat capacity of air = 1.0*10^3
density of air = 1.29
Specific heat capacity of the plastic = 2.30*10^3
The time taken for the fridge to cool is 571 seconds.
How long does it take the fridge to cool?
To calculate the time taken for the fridge to cool, we need to determine the amount of heat that must be removed from the air in the fridge to cool it from room temperature to 5.00 degrees Celsius.
First, we need to calculate the mass of air in the fridge. The density of air is given as 1.29 kg/m^3, so the mass of air in the fridge is:
mass = density x volume
mass = 1.29 x 0.277
mass = 0.35673 kg
The specific heat capacity of air is given as 1.0 * 10^3 J/kgK, so the initial internal energy of the air in the fridge is:
U = mass x specific heat capacity x temperature
U = 0.35673 x 1.0 x 10^3 x (19.5 + 273.15)
U = 1.06 x 10^5 J
Assuming the initial temperature of the shelves is the same as the air in the fridge, the initial internal energy of the shelves is:
U_shelves = mass_shelves x specific heat capacity x temperature
= 0.595 x 2.30 x 10^3 x (19.5 + 273.15)
= 3.67 x 10^5 J
The total initial internal energy of the fridge is therefore:
U_total = U + U_shelves = 1.06 * 10^5 + 3.67 x 10^5
= 4.73 x10^5 J
To cool the air in the fridge to 5.00 degrees Celsius, we need to remove heat from the air. The amount of heat removed can be calculated using the formula:
Q = mass x specific heat capacity x Δ temperature
Q = 0.35673 x 1.0 x 10^3 x (5.00 - 19.5)
Q = -5.88 x 10^3 J
The negative sign indicates that heat is being removed from the air.
Finally, we can calculate the time taken to remove this amount of heat using the power of the fridge, which is given as 10.3 W:
t = Q / P = (-5.88 x 10^3) / 10.3 = -570.9 seconds
The negative sign here indicates that the time taken is actually 570.9 seconds longer than the time taken to remove 5.88 kJ of heat at a constant power of 10.3 W. However, since time cannot be negative, we can take the absolute value of the time taken to get:
t = 571 seconds (to the nearest second)
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1. Which of the following statements is false? A) During a reaction, electrons move from an electrophile to a nucleophile B) Homolytic bond cleavage yields neutral radicals in which each atom gains on
The false statement is B) Homolytic bond cleavage yields neutral radicals in which each atom gains one electron.
In homolytic bond cleavage, each atom retains one electron from the shared pair of electrons, resulting in the formation of two neutral radicals, where each atom retains its original number of electrons.
No atoms gain or lose electrons in this process.
In a homolytic bond cleavage, a covalent bond is broken, and the shared pair of electrons is split equally between the two atoms involved in the bond.
This results in the formation of two neutral radicals, with each atom retaining one of the electrons from the shared pair.
A radical is a chemical species characterized by the presence of an electron that is unpaired, meaning it does not have a partner electron with which it forms a complete pair. When a covalent bond is homolytically cleaved, each atom involved in the bond gains one electron, resulting in the formation of two radicals.
These radicals are highly reactive due to the presence of the unpaired electron, which makes them prone to participate in further chemical reactions.
It's important to note that in homolytic bond cleavage, there is no transfer of electrons from one atom to another.
Instead, the bond is broken in a way that allows each atom to retain one of the electrons, leading to the formation of two neutral radicals.
Therefore, statement B, which suggests that each atom gains one electron, is false.
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What is the biggest quad muscle
A. Vastus Intermedius
B. Vastus Lateralis
C. Rectus Femoris
D. Vastus Medialis
Answer:
b
Explanation:
Answer:
B. Vastus Lateralis
Explanation:
The vastus lateralis muscle is located on the side of the thigh. This muscle is the largest of the quadriceps group.
Water flowing through an 8-cm-diameter pipe enters a porous section, as in fig. P3. 10, which allows a uniform radial velocity vw through the wall surfaces for a distance of 1. 2 m. If the entrance average velocity v1 is 12 m/s, find the exit velocity v2 if (a) vw
What is average speed?
Average velocity is outlined because the amendment in position or displacement (∆x) divided by the time intervals (∆t) within which the displacement occurs.
The average velocity will be positive or negative relying upon the sign of the displacement. The SI unit of average velocity is meters per second (m/s or ms-1).
For a suction velocity of Vw = 0.15 m/s
Cylindrical suction expanse.
Aw = 2π (0.04) (1.2) = 0.30 lbm2
Q1 = Qw+Q1
(12* π * (0.08)2 / 4 = (0.15)(0.30) + V2 π
(0.08)2 / 4
V2 = 3 m/s
Hence, the exit velocity is Vw = 0.15 m/s
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A cyclist and a motorcyclist ride on a straight road. The speed of a cyclist is 21.6 km/h , of a motorcyclist
68.4 km / h
After what time interval will the distance between them be 550 m , if at the beginning the distance between
them was 1375 m ?
As you know, the earth has an orbital period of 1.0 year at an orbital radius of 1.0 AU (astronomical unit, the average distance between the earth and the sun). If a new "minor planet" were to be found in a circular orbit with radius 13 AU, what would be its orbital period?
If a new "minor planet" were to be found in a circular orbit with a radius of 13 AU, 47 years would be its orbital period.
What is the Orbital Period?The amount of time it takes for an astronomical object to complete one orbit around another object is known as the orbital period (also called the revolution period). It typically refers to planets or asteroids that orbit the Sun, moons that orbit planets, exoplanets that orbit other stars, and binary stars in astronomy.
The relationship between an object's average distance from its object of orbit and its period is depicted by Kepler's third law. In its most basic form, this can be applied to anything naturally orbiting around other things. Formula: Where: P2=ka3 The orbit's time-based period is called P.
A year is a time it takes for a planet to circle the Sun once, which for Earth is just over 365 days.
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The sum of two component vectors is referred to as the
vector.
Addition
Quantitative
Subtraction
Resultant
Brian Berg of lowa built a house of cards 4.88 m tall. Suppose Berg throws a ball from ground level
with a velocity of 9.98 m/s straight up. What is the velocity of the ball as it first passes the top of
the card house?
Answer:
Vf = final velocity = 1.96 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
\(v_{f}^{2}=v_{o}^{2}-2*g*x\)
where:
Vf = final velocity [m/s]
Vo = initial velocity = 9.98 [m/s]
g = gravity acceleration = 9.81 [m/s²]
x = vertical distance [m]
\(v_{f}^{2}=(9.98)^{2}-2*9.81*4.88\\v_{f}^{2} = 99.6-95.74\\v_{f}=\sqrt{3.8544}\\v_{f}=1.96[m/s]\)
Note: The negative sign of the gravity acceleration means that the gravity acceleration is pointing in the opposite direction of the movement.
E-mail is usually a poor choice for the distribution of sensitive electronic files because __________. A. Paper copies seem more official than e-mail B. Not all computers can read e-mails correctly C. It is easy to send e-mail to the wrong person D. E-mail is saved on the server that transfers it Please select the best answer from the choices provided A B C D.
Answer: D.) e-mail is saved on the server that transfers it
Explanation:
D. E-mail is saved on the server that transfers it is the right answer
What is an email?Email (Email) is a computerized application for exchanging messages between users. The global email network enables rapid exchange of email messages. Email is an electronic version of a letter, but it has advantages in terms of topicality and flexibility.
All emails in all inboxes around the world are stored on the server. An incredible amount of data requires a huge server farm. This is a huge center with millions of computers that store and send information.
A mail server (or email server) is a computer system that sends and receives emails. Web and mail servers are often integrated on a single machine.
E-mail is usually a poor choice for the distribution of sensitive electronic files because E-mail is saved on the server that transfers it
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Quantum physics
a) Calculate the binding energy per nucleon for the technetium-98 core.
b) Calculate the binding energy per nucleon for the carbon-12 nucleus.
c) How would you explain the difference
The answers to the given questions are as follows:
a) The Binding Energy per nucleon of Technetium-98 is 8.009 × 10⁻¹³ J/nucleon
b) The Binding Energy per nucleon of Carbon-12 is 7.766 × 10⁻¹⁰ J/nucleon
c) Technetium-98 is more stable than Carbon-12 because it has a greater binding energy per nucleon.
What is Binding energy per nucleon?The binding energy per nucleon can be defined as the amount of energy required to break apart an atomic nucleus completely. It is typically expressed in MeV per nucleon.
The binding energy per nucleon is a measure of the stability of the nucleus. If it is negative, the nucleus is unstable and will tend to decay. If it is positive, the nucleus is stable, and if it is zero, it is marginally stable. Binding energy per nucleon is calculated by using the following formula:
Binding energy = [(Number of protons × Mass of proton) + (Number of neutrons × Mass of neutron) - Mass of the nucleus] × c²
Where,
c is the speed of light (3 × 10⁸ m/s)
To calculate the binding energy per nucleon we will need to use the given data:
The mass of the proton = 1.007276 u
The mass of the neutron = 1.008665 u
a) Binding Energy per nucleon of Technetium-98:
Mass of Technetium-98 nucleus= 97.907216 amu
= (97.907216 u) × (1.66054 × 10⁻²⁷ kg/u)
= 1.62699 × 10⁻²⁵ kg
Number of protons = 43 (as Technetium has atomic number 43)
Number of neutrons = 98 - 43
= 55
Binding energy = [(43 × 1.007276 u) + (55 × 1.008665 u) - 97.907216 u] × (1.66054 × 10⁻²⁷ kg/u) × (3 × 10⁸ m/s)²
= 7.861 × 10⁻¹² J
The mass of one nucleon = mass of the nucleus/number of nucleons = 1.62699 × 10⁻²⁵ kg/98 nucleons
= 1.658 × 10⁻²⁷ kg/nucleon
The Binding energy per nucleon= (7.861 × 10⁻¹² J)/98
= 8.009 × 10⁻¹³ J/nucleon
Therefore, the Binding Energy per nucleon of Technetium-98 is 8.009 × 10⁻¹³ J/nucleon
b) Binding energy per nucleon of Carbon-12:
Mass of Carbon-12 nucleus = 12.000 amu
= (12.000 u) × (1.66054 × 10⁻²⁷ kg/u)
= 1.993 × 10⁻²⁶ kg
Number of protons = 6 (as Carbon has atomic number 6)
Number of neutrons = 12 - 6
= 6
Binding energy = [(6 × 1.007276 u) + (6 × 1.008665 u) - 12.000 u] × (1.66054 × 10⁻²⁷ kg/u) × (3 × 10⁸ m/s)²
= 9.319 × 10⁻¹⁰ J
The mass of one nucleon = mass of the nucleus/number of nucleons
= 1.993 × 10⁻²⁶ kg/12 nucleons
= 1.661 × 10⁻²⁷ kg/nucleon
Binding energy per nucleon= (9.319 × 10⁻¹⁰ J)/12
= 7.766 × 10⁻¹⁰ J/nucleon
Therefore, the Binding Energy per nucleon of Carbon-12 is 7.766 × 10⁻¹⁰ J/nucleon
c) Technetium-98 has a greater binding energy per nucleon than Carbon-12. Technetium-98 has 8.009 × 10⁻¹³ J/nucleon, while Carbon-12 has 7.766 × 10⁻¹⁰ J/nucleon. The higher the binding energy per nucleon, the greater the stability of the nucleus. Technetium-98 is more stable than Carbon-12 because it has a greater binding energy per nucleon.
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__________ is the theory that living things come from other living things.
A.
spontaneous generation
B.
evolution
C.
Darwinism
D.
cell theory
Answer:
A.spontaneous generation
the tweeter in a speaker system delivers as much power at 5khz as the woofer does at 50hz. which speaker must generate a larger displacement amplitude?
Both the woofer and the tweeter would need to generate a larger displacement amplitude in order to produce the same sound pressure level in the room.
The tweeter in a speaker system delivers as much power at 5kHz as the woofer does at 50Hz. In order to determine which speaker must generate a larger displacement amplitude, we need to consider the frequency response of each driver and the volume of the room.
Assuming that the room is a typical living room with a volume of around 100 cubic meters, we can calculate the approximate displacement amplitude required to produce a given sound pressure level (SPL) in the room. According to the inverse square law, the sound pressure level decreases by 6 dB for every doubling of the distance from the source. Therefore, to produce the same SPL in the room, the woofer and the tweeter would need to have roughly equal sound pressure levels at their respective frequencies.
Assuming that the woofer has a sound pressure level of 100 dB at 50Hz and the tweeter has a sound pressure level of 100 dB at 5kHz, we can calculate the required displacement amplitude for each driver using the following formula:
Displacement amplitude = √(2 * P / A)
where P is the sound pressure level, A is the area of the driver's cone, and √2 is a constant. Substituting the given values, we get:
Displacement amplitude = √(2 * 100 dB / A)
where A is the area of the driver's cone.
For the woofer, the area of the cone is typically on the order of a few square centimeters, so the required displacement amplitude would be on the order of millimeters.
For the tweeter, the area of the cone is typically on the order of a few square centimeters, so the required displacement amplitude would also be on the order of millimeters.
Therefore, both the woofer and the tweeter would need to generate a larger displacement amplitude in order to produce the same sound pressure level in the room.
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Pls help: A spring has a length of 1.0 meter when there is no tension on it. The spring is then stretched between two points 10 meters apart. A wave pulse travels between the two end points in the spring in a time of 1.0 seconds. The spring is now stretched between two points that are 20 meters apart. What is the new time it takes for a wave pulse to travel between the ends of the spring?
The new time it takes for a wave pulse to travel between the ends of the spring is 2.0 s.
The question has to do with period of a stretched spring.
What is the period of a stretched spring?The frequency of a stretched spring is given by f = 1/2L√(T/μ) where
L = length of spring, T = tension and μ = linear density of springWe then find the period
What is the period of a stretched spring?The period of a stretched spring T = 1/f
T = 2L√(μ/T)
How to find new time it takes the wave pulse to travel?
We know that the time it takes the wave pulse to travel is the period, T = 1/f
So, T = 2L√(μ/T)
Since T and μ are constant, we have that
T ∝ L
So, T₂/T₁ = L₂/L₁ where
L₁ = initial length of spring = 10 m, T₁ = initial wave pulse time = 1.0 s, L₂ = final length of spring = 20 m, T₂ = final wave pulse timeMaking T₂ subject of the formula, we have
T₂ = (L₂/L₁)T₁
Substituting the values of the variables into the equation, we have
T₂ = (L₂/L₁)T₁
T₂ = (20 m/10 m)1.0 s
T₂ = (2)1.0 s
T₂ = 2.0 s
So, the new time it takes for a wave pulse to travel between the ends of the spring is 2.0 s.
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An astronaut of mass m is launched from the surface of the moon in a space craft having an initial vertical acceleration of 5g, where g' is the acceleration of free fall in moon. The vertical reaction of the space craft on the astronaut is
The vertical reaction of the space craft on the astronaut is 5mg.
What is the vertical reaction of the space craft on the astronaut?The vertical reaction of the space craft on the astronaut is calculated by applying Newton's second law of motion as shown below.
F = mg
where;
m is the mass of the astronautg is acceleration due to gravity on moon = 1.67 m/s²The vertical reaction of the space craft on the astronaut is calculated as;
F = m x 5g
F = 5mg
Thus, the vertical reaction of the space craft on the astronaut is equal to the weight of the astronaut exerted downwards.
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If 10mC of charge passes through a battery of 12 V, how much energy is transferred to the charge?
Energy is transferred to the charge is 120J
What is energy?
Energy is a general term that we use frequently in our daily lives. Although the term "energy" is frequently misused, it has a specific physical meaning. In physics, energy is defined as something's ability to accomplish work. Energy can take various forms. All energy is either kinetic or potential. Let us take a closer look at what energy is and the many sorts of energy in this post.
On Earth, there are various types of energy. On Earth, the sun is considered the elemental form of energy. Energy is a quantifiable property in physics that can be transferred from an item to perform work. As a result, we can define energy as the ability to perform any type of physical activity.
According to the laws of energy conservation, "energy cannot be generated or destroyed; it can only be transformed from one form to another." Joule is the SI unit of energy. One of the fundamental rules of physics is the law of energy conservation. It regulates the movements of individual atoms in a chemical process at the microscopic level. According to the rule of conservation of energy, "the entire energy of the system is conserved in a closed system, i.e., a system that is separated from its surroundings." Even when energy transformation happens, the overall energy in a system is conserved, according to the law. Energy can't be created or destroyed.
E = Q X V
E=10X12
E=120J
Therefore, energy is transferred to the charge is 120J
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What was one of the reasons the media used propaganda in america during wwii? (1 point)
o to motivate people to boycott the war
to motivate people to watch more cartoons
to show the germans as enemies
to show the japanese as our allies
One of the main reasons why the media used propaganda in America during World War II was to create a sense of unity and support for the war effort.
Propaganda was used to promote patriotism and encourage citizens to make sacrifices for the greater good. It was also used to demonize the enemy, particularly the Germans and the Japanese, and portray them as a threat to American values and way of life. This helped to boost morale and create a sense of determination among the American people. Additionally, propaganda was used to recruit soldiers, promote war bonds, and encourage women to join the workforce. Overall, propaganda played a crucial role in shaping public opinion during the war and rallying support for the American cause.
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If
you weigh 140 pounds, what is your weight in kilograms
A block is on a surface with µs=0.276. It takes 1.11 N to break it free from static friction. What is the mass of the block?
Answer:
0.407 kg
Explanation:
Given :
Coefficient of static friction, µs = 0.276
Force, F = 1.1 N
Using the relation :
μ = F/N
N = normal reaction ; N = mg
μ = F / mg
g = acceleration due to gravity = 9.8 m/s²
0.276 = 1.1 / m * 9.8
0.276 = 1.1 / 9.8m
0.276 * 9.8m = 1.1
2.7048m = 1.1
m = 1.1 / 2.7048
m = 0.4066844
Mass = 0.407 kg
Mr Mann cut a cucumber. Mr Mann said, you have performed a chemical change. Is he right?
Answer:
No.
Explanation:
The cut cucumber is still a cucumber.
Answer:
Nope.
Explanation:
Chemical change is transforming the cucumber into a pickle. However, you need vinegar, so it isn't a full change.
Therefore, Mr. Mann would not be right either way, because all he did was cut a cucumber, and he should probably get some help with all this "chemical change".
A boulder rolls off a 100 meter cliff with a horizontal velocity of 2 m/s.
Make a sketch of the cliff and the boulder. Be sure to label the height of the cliff, the horizontal velocty of the
boulder, and the trajectory of the boulder
Explanation:
It is given that,
Height of the cliff is 100 m
Its horizontal velocity is 2 m/s
The attached figure shows the sketch of the cliff and the boulder. It will go in the form of parabola. Its trajectory is parabolic in nature. The horizontal distance is called the range of the parabola.
a metal cube of density 2700 kg/m³ has an edge length of 10cm. what is the mass of the metal?
Answer:
The mass of the metal is 2.7 Kg.
Explanation:
As we know the mass of an object is:
m = ρ * v .........(i)
where ρ is the density of the metal cube, &
v is the volume of the cube
Now as per the question:
Density of metal cube, ρ = 2700 kg/m³
Edge Length, l = 10 cm
∵ 1 m = 100 cm
∴ edge length, l = 0.1 m
∴ Volume, v = (l)³ = (0.1)³ = 0.001 m³
Now putting all the values in equation (i), we get
m = 2700 * 0.001 kg
m = 2.7 kg
∴ A metal cube of density 2700 kg/m³ and edge length 10 cm has a mass of 2.7 kg.
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An ideal gas is compressed isothermally to one-fourth of its initial volume. the resulting pressure will be:________
An ideal gas is compressed isothermally to one-fourth of its initial volume. The resulting pressure will is 4 times the initial pressure.
The equation of state for ideal gases is described below:
P.V. = n. R.T. .........................(1)
Where:
P- Pressure.
V- Volume.
n- Molar quantity, in moles.
R- Ideal gas constant.
T- Temperature
Given that ideal gas is compressed isothermally, this is, temperature remains constant, pressure is increased and volume is decreased, then we can simplify (1) into the following relationship:
P1 V1= P2 V2
If we know that V2/V1 = 1/4 , then the resulting pressure of the system is:
P2 = P1 (V1/V2)
P2 = 4 P1
The resulting pressure is 4 times the initial pressure.
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Sliding off a sphere A small mass rests on top of a fixed frictionless sphere of radius R. The mass is given a tiny kick and slides downward. At what vertical height does it lose contact with the sphere? Hint: This problem brings together various aspects from this unit. Use conservation of mechanical energy, and also, consider the normal force on the puck. At what value of this normal force does the puck leave the sphere?
When the puck has descended to a height of R/2, it no longer makes touch with the sphere.
To solve this problem, we can use the conservation of mechanical energy. Initially, the mass is at rest and has only potential energy, which is given by mgh, where m is the mass of the puck, g is the acceleration due to gravity, and h is the height of the puck above the ground. When the puck slides down the sphere, it loses potential energy and gains kinetic energy, which is given by \((\frac{1}{2}mv^2)\), where v is the velocity of the puck. However, as the puck slides down the sphere, it also experiences a normal force from the sphere, which reduces the force of gravity and affects the speed of the puck.
Let's start by finding the normal force on the puck. At the top of the sphere, the normal force is equal to the weight of the puck, which is mg. As the puck slides down the sphere, the normal force decreases until it reaches zero when the puck loses contact with the sphere. At this point, the gravitational force is equal to the centrifugal force, which is mv^2/R, where R is the radius of the sphere.
Setting these forces equal, we get:
\(mg = \frac{mv^2}{R}\)
Simplifying, we get:
\(v^2 = gR\)
Now we can use conservation of mechanical energy to find the height at which the puck loses contact with the sphere. At this point, all the potential energy has been converted into kinetic energy, so we have:
\(mgh = (\frac{1}{2})mv^2\)
Substituting \(v^2 = gR\), we get:
\(h = R(1 - \frac{1}{2}) = \frac{R}{2}\)
Therefore, the puck loses contact with the sphere when it has fallen to a height of R/2.
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A pathogen has entered your body and you become sick. You develop a fever and vomit. This is your body's way of trying to maintain
What problems might we face if measuring system were not established?
If a standardized measuring system were not established, several problems could arise such as Lack of uniformity, Inefficiency and errors, Safety concerns and Economic impact.
Lack of uniformity: Without a standardized system, different regions or communities might develop their own measurement units, leading to confusion and inconsistency in communication and trade. It would be challenging to compare and reconcile measurements across different contexts.
Inefficiency and errors: A lack of standardized measurements could result in inefficiency in various sectors, such as construction, engineering, and manufacturing. Precision and accuracy would be compromised, leading to errors in calculations, designs, and product quality.
Safety concerns: Standardized measurements play a crucial role in ensuring safety, particularly in areas like medicine, transportation, and infrastructure. Without a common system, it would be difficult to establish safety standards, monitor compliance, and ensure uniformity in critical aspects like dosage, weight limits, and structural integrity.
Economic impact: Inconsistent measurement systems would hinder international trade and commerce. Harmonized measurements facilitate smooth transactions, accurate pricing, and quality control, leading to a stable and efficient economy. Without a standardized system, business operations and global collaborations would be significantly hindered.
In conclusion, a lack of a standardized measuring system would result in confusion, inefficiency, safety concerns, and economic setbacks, emphasizing the importance of establishing and adhering to universally accepted measurements.
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HELP PLEASE ?? can u answer this multiple choice for me please?
Answer:
.04 kg m/s
Explanation:
Momentum is simply mass multiplied by velocity given by p = mv. You can consider momentum as mass in motion.
Before the collision, the data given for the toy train:
v = 0.5m/s
m = 75g
We need to convert grams into the SI unit of mass, kg.
75g / 1000g * 1kg = 0.075kg
Using p = mv, we can determine:
p = 0.075kg * 0.5m/s = 0.0375 kg m/s
Rounding to the value of 1 sig-fig, it comes out to be 0.04 kg m/s.
What happens when an electron moves from an excited energy state to a lower energy state?
Answer:
emission of radiation
Explanation: