Which of the following is not a source of light? *
a) sun
b) star
c) mirror
d)cfl

Answer:

1-a

2-d

3-c

4-b

Explanation:

i tookt he words and put it in the sentance and these made most sence to me

Answer:

answer is b. any movement that uses your muscles and requires energy

Explanation:

Answer:

Hi, so the Answer would basically be Yes, and No because it depends on the form of light but in general I would say that the answer would be No.

Explanation:

We call it visible light because we can see it with our own eyes. There are different forms of light which we cannot see with our bare eyes. Ultraviolet light is an example of a form of light which we cannot see with just our eyes.

Answer:

1. Simply τ = m x g x r = 54kg x 9.8m/s² x 0.050m = 26 N·m

2. The bucket creates a torque

τ = 75kg x 9.8m/s² x 0.075m = 55 N·m,

so we must create the same torque with the handle.

55 N·m = F x 0.25m

F = 220 N

Explanation:

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The value of the unknown force acting on the object represented by the FBD, with a mass of 5.0 kg and experiencing an acceleration of 2.0 m/s² to the left, is 10.0 N.

To solve this problem, we need to understand Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. Mathematically, this can be written as:

Net force (F_net) = mass (m) × acceleration (a)

Given:

Mass of the object (m) = 5.0 kg

Acceleration (a) = 2.0 m/s² to the left

Now, let's analyze the forces acting on the object based on the Free Body Diagram (FBD). You mentioned that there is an unknown force (F_unknown) acting on the object. Additionally, there might be other forces acting on the object, such as friction or gravity. However, since those forces are not specified in the question, we will assume that the only force acting on the object is the unknown force (F_unknown).

According to Newton's second law, the net force (F_net) acting on the object is equal to the sum of all the forces acting on it. In this case, since we only have the unknown force, we can write:

F_net = F_unknown

Substituting the values we know into Newton's second law equation, we get:

F_unknown = m × a

Plugging in the given values:

F_unknown = 5.0 kg × 2.0 m/s²

Calculating the result:

F_unknown = 10.0 kg·m/s²

The unit for force is Newton (N), which is equivalent to kg·m/s². Therefore, the value of the unknown force (F_unknown) is 10.0 N.

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When a car moves around in a circle, the static friction force that it experience is Centripetal force.

Centripetal force is a type of force directed towards the center of the circle when an object moves in circular motion. The centripetal force allows an object to keep moving in a  circle.

Centripetal force is directly proportional to velocity squared of the object. It is given by:

F = mv²/r

m = mass, v = velocity, r = radius, F = centripetal force.

Given that m = 1000kg, v = 45 m/s, r = 60 m, hence:

F = 1000(45)²/60 = 33750 N

When a car moves around in a circle, the static friction force that it experience is Centripetal force.

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The mechanism that is responsible for the formation of snowflakes is the nucleation of ice crystals.

This is defined as a piece of snow which falls from the sky as a result of an extremely cold climate condition and is common in the arctic regions of the world.

Snow flakes are formed when ice crystals stick together to form the flakes which usually has a dust or pollen being formed around the area being talked about.

This is also regarded as a type of precipitation such as rain etc and is therefore the most appropriate choice.

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Answer:

4 times what it is now.

Explanation:

g=G(M/r^2)

G is constant, so ignore.

We have (1M/0.5r^2), or 4.

Answer:

4g

Explanation:

the equation of g (field gravity)

g = G M/R²

because G (Contant of Gravitasion) and M (Mass of earth) same, them

g2/g1 = R1²/R2²

g1 = g now

g2 = g which the value we looking for

g2/g = 1/(1/2)²

g2/g = 1/(1/4)

g2/g = 4

g2 = 4g

Answer:

It is not possible to change direction twice, given constant acceleration. To convince yourself, imagine any general v−t graph - it would be straight line in case of constant acceleration. Change in direction corresponds to v going from positive to negative or vice versa.Explanation:

Answer:It is not possible to change direction twice, given constant acceleration. 

Explanation:To convince yourself, imagine any general v−t graph - it would be straight line in case of constant acceleration. Change in direction corresponds to v going from positive to negative or vice versa.

Answer:

B. 57.4 N horizontal (right)

Explanation:

using cos method:

\(cos(35) = \frac{vertical force}{100}\)

\(vertical force = 57.4 N\)

As its vertical, the direction of this force should be up.

Answer:

i think it is car B because  the greater the speed, the greater the drag force acting on the vehicle

Explanation:

Answer:

Waves come in two kinds, longitudinal and transverse. Transverse waves are like those on water, with the surface going up and down, and longitudinal waves are like of those of sound, consisting of alternating compressions and rarefactions in a medium.

Answer:

c

Explanation:

Answer:

A constant velocity of an object ensures that the rate of change of velocity with time is null, and hence, the acceleration of the object is zero. A constant acceleration of an object ensures that the velocity of the object is changing continuously with time, and the velocity will not be constant.

Explanation:

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thankyou

Answer: A

Explanation:

I want my points so yea

A charged body shares charge with an uncharged conductor, but the charged body does not actually transfer charge to the conduction. The charge is induced only on the conductor.

Charging by conduction:

1. The process of charging a dead conduction by bringing it into electrical contact with a charged body is called conduction charging.

2. Charged bodies share the charge with uncharged conductors.

3.The charge generated on the conductor is of the same nature as the charge generated on the charged body.

Charging by Induction:

1. The process of charging a dead conductor by bringing a charged object close without touching it is called inductive charging.

2. There is no real charge transfer from the charged body to the conductor. The charge is induced only on the conductor.

3. The charge generated on the conduction is opposite to the charge on the charged body.

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Answer:

how?

Explanation:

Answer:

h=103.528m

Explanation:

I have explained everything in the attached photo. make sure to ask me questions if you don't understand any part.

Answer:Δx=v0t + 1/2 at 2

Answer:

a) A force of 367718.75 newtons is needed to get the full airplane safely in the air.

b) The empty airplane would need a runway of 1828.571 meters.

Explanation:

a) This problem can be solved by using the Work-Energy Theorem, which states that work needed by the airplane to get minimum speed is equal to its change in translational kinetic energy, both measured in joules. The resulting formula is presented below:

\(F\cdot \Delta s = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2})\) (1)

Where:

\(F\) - Minimum net force, measured in newtons.

\(\Delta s\) - Runway length, measured in meters.

\(m\) - Mass of the airplane, measured in kilograms.

\(v_{o}\), \(v_{f}\) - Initial and final speeds of the airplane, measured in meters per second.

If we know that \(m = 350000\,kg\), \(v_{o} = 0\,\frac{m}{s}\), \(v_{f} = 82\,\frac{m}{s}\) and \(\Delta s = 3200\,m\), then the minimum net force needed by the airplane to get itself safely in the air:

\(F = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot \Delta s}\)

\(F = \frac{(350000\,kg)\cdot \left[\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (3200\,m)}\)

\(F = 367718.75\,N\)

A force of 367718.75 newtons is needed to get the full airplane safely in the air.

b) If we know that \(m = 200000\,kg\), \(v_{o} = 0\,\frac{m}{s}\), \(v_{f} = 82\,\frac{m}{s}\) and \(F = 367718.75\,N\), then the length of the runway is:

\(\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F}\)

\(\Delta s = \frac{(200000\,kg)\cdot \left[\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (367718.75\,N)}\)

\(\Delta s = 1828.571\,m\)

The empty airplane would need a runway of 1828.571 meters.

The correct answer is dependence of graph remain same. The Speed decreases,

We must first comprehend the difference between distance and displacement in order to understand average speed and average velocity. Distance is a scalar quantity that describes how much space an object has traveled. Displacement, which is a vector quantity, represents the smallest distance between two points. For instance, if a particle moves around a circle, its displacement is 0 but its distance traveled after one rotation is equal to the circle's circumference.

Any object's average speed is calculated by dividing its entire distance traveled by the total amount of time it took to complete that distance. An object's average speed indicates the average speed at which it will travel a given distance.

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Answer:

With the specified solar collector, it would take roughly 50,788.88 seconds or 14.11 hours to raise the temperature of 1.00 m3 of water from 20.0°C to 60.0°C.

The thermal loss is modest at low fluid temperatures, as depicted in Fig. 7.35. The efficiency of the solar collector is determined to be 75% at a fluid temperature of 100 °C, which is 78 °C above ambient temperature.

To start, let's figure out how much water there is in 1.00 m3:

Volume of water = 1.00 m3

Density of water = 1000 kg/m3 (at standard temperature and pressure)

Mass of water = Density x Volume = 1000 kg/m3 x 1.00 m3 = 1000 kg

Next, let's determine how much heat energy is needed to raise the water's temperature:

Q = mcΔT

Q = (1000 kg) x (4.18 J/kg·°C) x (60.0°C - 20.0°C)

Q = 167,200 kJ

Let's now determine how much energy the solar collector has totaled:

Energy = Intensity x Area x Time

Energy = (550 W/m2) x (6.00 m2) x Time

Energy = 3,300 W x Time

We may put the two equations equal since the heat energy necessary to raise the water's temperature must equal the energy received by the solar collector:

3,300 W x Time = 167,200 kJ

To solve for Time, we need to convert units:

1 W = 1 J/s

3,300 W = 3,300 J/s

1 kJ = 1,000 J

167,200 kJ = 167,200,000 J

So the equation becomes:

3,300 J/s x Time = 167,200,000 J

Solving for Time, we get:

Time = 167,200,000 J / 3,300 J/s

Time = 50,788.88 seconds

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The correct option is D. the volume of the ventricle when it is most full.

The volume of the ventricle when it is most full is the most correct description of end-diastolic volume.

It can be defined as the amount of blood in the ventricle immediately before a cardiac contraction or systole occurs. End-diastolic volume is the volume of blood in the ventricles at the end of diastole, after filling with blood from the atria, before the ventricles contract to begin systole.

ventricles are hollow chambers or cavities found in the heart and brain. In the heart, there are two ventricles responsible for pumping blood, while in the brain, there are four interconnected ventricles that produce and circulate cerebrospinal fluid.

Therefore, the correct option is D. the volume of the ventricle when it is most full.

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The balanced half-reaction for the reduction of Cr₂O₇²⁻ to Cr³⁺ in acid in its simplest form is:

Cr₂O₇²⁻ + 14H⁺ + 6e⁻ -> 2Cr³⁺ + 7H₂O

To balance the half-reaction, we need to ensure that the number of atoms and charges are equal on both sides. Here's a step-by-step explanation of how the half-reaction is balanced:

1. Balance the atoms other than hydrogen and oxygen:

  - We start with balancing the chromium (Cr) atoms. On the left side, we have two chromium atoms, so we place a coefficient of 2 in front of  Cr³⁺  on the right side.

  - This gives us: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ -> 2 Cr³⁺  + ...

2. Balance the oxygen atoms:

  - On the left side, we have seven oxygen atoms from the Cr₂O₇²⁻ ion. To balance this, we add seven water (H2O) molecules on the right side.

  - The equation now becomes: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ -> 2 Cr³⁺  + 7H₂O

3. Balance the hydrogen atoms:

  - On the left side, we have 14 hydrogen atoms from the H⁺ ions. To balance this, we add 14 H⁺ ions on the left side.

  - The equation is now balanced: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ -> 2 Cr³⁺  + 7H₂O

The balanced half-reaction shows that for every one Cr₂O₇²⁻ ion reduced, six electrons, 14 hydrogen ions, two  Cr³⁺  ions, and seven water molecules are produced. This balanced half-reaction is in acid and represents the reduction of dichromate ion (Cr₂O₇²⁻) to chromium (III) ion ( Cr³⁺ ).

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ETo determine the acceleration of the crate, we need to resolve the applied force into its horizontal and vertical components. The horizontal component of the force will contribute to the acceleration, while the vertical component will not affect the motion of the crate on a frictionless surface.
Given:
Mass of the crate (m) = 40 kg
Magnitude of the applied force (F) = 140 N
Angle of the force with the horizontal (θ) = 30°

To find the horizontal component of the force (F_horizontal), we can use trigonometry:
F_horizontal = F * cos(θ)
F_horizontal = 140 N * cos(30°)
F_horizontal = 140 N * √3/2
F_horizontal = 140 N * 0.866
F_horizontal ≈ 121.24 N
Since there is no friction or vertical forces acting on the crate, the horizontal component of the applied force will be responsible for the acceleration.
Using Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration (F = m * a), we can calculate the acceleration (a).
a = F_horizontal / m
a = 121.24 N / 40 kg
a ≈ 3.03 m/s²
Therefore, the acceleration of the crate is approximately 3.03 m/s².

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The distance above the ground the rock  should be dropped such that it hits the ground at 2t after it is released from rest is 4h.

The height of fall of the rock is calculated by applying the following kinematic equation as shown below.

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

h = ¹/₂gt²

2h = gt²

g = 2h / t²

h₁ / t₁² = h₂ / t₂²

The distance above the ground the rock  should be dropped such that it hits the ground at 2t after it is released from rest is calculated as;

h₂ = ( h₁ / t₁² )(t₂²)

h₂ = ( h/t²)(2t)²

h₂ = ( h/t²)(4t²)

h₂ = 4h

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