Which of the following examples, would best represent the input energy and then
'wasted energy forms when watching TV.
A. Chemical, and then heat and electrical.
B. Chemical, and then heat, kinetic, sound
C. Electrical, and light, sound, heat
D. Electrical, and then sound and heat

A hollow sphere made out of electrically insulating material is electrically neutral (no excess charge) then the correct option is  b) The excess charge has distributed itself evenly over the outside surface of the sphere.

The metal spherical is a conductor and hollow. Charges can therefore circulate freely across its surface as a result. A metal body serves as an equipotential body on the other side. Once a charge has been established and there is no longer a voltage differential imprinted across the body, the charges must be distributed uniformly across the exterior surface for the body to continue to be an equipotential body. There must not be any charge in the volume because otherwise an electrical field and consequent voltage differential would arise.

Additionally, the interior surface's charge distribution must be zero. The enclosed charge must be zero if the Gauss Theorem is applied to a gaussian sphere with a radius between the internal and external surfaces and the knowledge that field E is zero.

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Hey there!

The energy that is stored in food is called CHEMICAL ENERGY

So, when humans/people eat foods their bodies transfigure the energy that is stored which is known as the calories.

Whereas the chains (bonds) in the middle of the atoms in the food humans eat that break up the check mal reactions that has been taken into place and newer compounds will be created. Each food that you eat stores unlikeable amounts of energy

Answer: Chemical energy

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

a) The main advantages of an epicyclic gearbox are:

b) i) Using the formula for the gear ratio of an epicyclic gear train:

T4/T3 = (t2/t1) x (t5/t2) x (t4/t5)

T4/30 = (1/2) x (60/20) x (40/60)

T4 = 40 Nm

ii) From the law of gearing for an epicyclic gear train:

w21 = (t3/t2) x (t5/t4) x w31 - (t3/t2) x w2

Substituting the given values:

w21 = (30/20) x (60/40) x 200 - (30/20) x 100

w21 = 150 rad/s

iii) The fixing couple that must be applied to wheel 5 can be found from the power transmitted by the gear train:

P = w3 x T3 = w2 x T2 = w1 x T1

Substituting the given values:

9 kW = 200 rad/s x 30 Nm = w2 x T2 = w2 x 20 Nm

w2 = 450 rad/s

T2 = (9 kW) / (450 rad/s) = 20 Nm

The fixing couple that must be applied to wheel 5 is equal in magnitude and opposite in direction to T2, so it is -20 Nm.

iv) The tangential force at the pitch point between wheels 3 and 4 can be found from the formula:

Ft = (2 x Pd) / (m x z3)

where Pd is the diametral pitch, m is the module, and z3 is the number of teeth on wheel 3.

Substituting the given values:

Pd = 25.4 / 5 = 5.08 teeth/inch

z3 = t3 / m = 30 / 5 = 6 teeth

Ft = (2 x 5.08) / (5 x 6) = 0.846 N

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The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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Answer:

White or lighter colored, shirt REFLECTS most of the visible wavelengths or all colors of light while a black or dark shirt ABSORBS more wavelengths.

So, Absorbed radiation is converted into heat, making the darker or black shirt warmer to wear.

-TheUnknownScientist 72

Answer:

ultraviolet light

plz mark me as brainliest.

Answer:

Ultra violet

Explanation:

Answer:

From the initial height h

Explanation:

When a material or substance is drop from a height h, it possesses potential energy, immediately it is dropped from that height, the potential energy is gradually converted to kinetic energy, it gets to a point where the potential energy equals the kinetic energy, as the material touches the ground, all potential energy has been converted to kinetic energy already

Answer:206.3

Explanation:

Answer:

convex lens

Explanation:

An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

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The kinetic energy of the cat is 2 joules (J).

The kinetic energy of an object can be calculated using the formula KE = 1/2 * mass * velocity^2.

The kinetic energy of an object can be calculated using the formula:

Kinetic Energy (KE) = 0.5 * mass * velocity^2

In this case, the mass of the cat is 4 kilograms, and its velocity is 1 m/s. Plugging these values into the formula:

KE = 0.5 * 4 kg * (1 m/s)^2

Simplifying the equation:

KE = 0.5 * 4 kg * 1 m^2/s^2

KE = 0.5 * 4 kg * 1

KE = 2 kg

Therefore, the kinetic energy of the cat is 2 joules (J).

Kinetic energy is the energy possessed by an object due to its motion. In this case, the cat's kinetic energy is determined by its mass and velocity. The formula for kinetic energy demonstrates that it is directly proportional to the mass and square of the velocity. As the mass increases, the kinetic energy also increases. Similarly, as the velocity increases, the kinetic energy increases exponentially.

In this example, the cat's kinetic energy is relatively low due to its mass and velocity values. If the cat were moving at a higher velocity or had a greater mass, the kinetic energy would be significantly higher. Kinetic energy is an important concept in understanding the energy associated with moving objects and is utilized in various fields such as physics, engineering, and sports science.

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Answer:

36 m/s

Explanation:

t = 3.6s

u = 0m/s

a = +g = 10m/s²

v = ?

using,

v = u + at

v = 0 + 10(3.6)

v = 36 m/s

For a typical middle-aged woman, there are certain priorities for them such as job stability, kids, and so on, but one factor that is generally not a concern for the average middle-aged woman is how to train for the Olympics

Midlife, the stage of a woman's life between childhood and elder maturity, has been called a time of transition. Women between the ages of 40 and 65 have been the focus of midlife research because they often go through a number of social, psychological, and biological shifts during this time.

Hence, it can be seen that while there are genuine concerns for a middle-aged woman, the answer choice that is generally not a concern for the average middle-aged woman is to become an Olympian.

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If Janine is a typical middle-aged woman, she is likely to be concerned about all of the following things except for one. Identify the option that is generally not a concern for the average middle-aged woman ?

train for the Olympics

have kids

raise a family

Thermal Window Curtains and Insulation are the two macroscopic properties that should be considered when constructing a home in the desert.

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Complete Question

Part of the question is shown on the first uploaded image

The rest of the question

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1 and q2 at x3 = -1.220 m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.

Answer:

The net force exerted on the third charge is  \(F_{net}= 3.22*10^{-5} \ J\)

Explanation:

From the question we are told that

    The third charge is  \(q_3 = 55 nC = 55 *10^{-9} C\)

    The position of the third charge is  \(x = -1.220 \ m\)

     The first charge is \(q_1 = -16 nC = -16 *10^{-9} \ C\)

     The position of the first charge is \(x_1 = -1.650m\)

      The second charge is  \(q_2 = 32 nC = 32 *10^{-9} C\)

      The position of the second charge is  \(x_2 = 0 \ m\)  

The distance between the first and the third charge is

      \(d_{1-3} = -1.650 -(-1.220)\)

     \(d_{1-3} = -0.43 \ m\)

The force exerted on the third charge by the first is  

     \(F_{1-3} = \frac{k q_1 q_3}{d_{1-3}^2}\)

Where k is the coulomb's constant with a value  \(9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.\)

substituting values

      \(F_{1-3} = \frac{9*10^{9}* 16 *10^{-9} * (55*10^{-9})}{(-0.43)^2}\)

       \(F_{1-3} = 4.28 *10^{-5} \ N\)

 The distance between the second and the third charge is      

  \(d_{2-3} = 0- (-1.22)\)

   \(d_{2-3} =1.220 \ m\)

The force exerted on the third charge by the first is mathematically evaluated as

       \(F_{2-3} = \frac{k q_2 q_3}{d_{2-3}^2}\)

substituting values

       \(F_{2-3} = \frac{9*10^{9} * (32*10^{-9}) *(55*10^{-9})}{(1.220)^2}\)

       \(F_{2-3} = 1.06*10^{-5} N\)

The net force is

      \(F_{net} = F_{1-3} -F_{2-3}\)

substituting values

    \(F_{net} = 4.28 *10^{-5} - 1.06*10^{-5}\)

    \(F_{net}= 3.22*10^{-5} \ J\)

The net force on the third charge is -3.216 x 10⁻⁵ N.

The given parameters:

The force on the third charge due to the first charge is calculated as follows;

r = x1 - x3

r = -1.65 - (-1.22)

r = -0.43 m

\(F_{13} = \frac{9\times 10^9 \times (-16 \times 10^{-9}) \times (55 \times 10^{-9})}{(0.43)^2} \\\\F_{13} = -4.28 \times 10^{-5} \ N\)

The force on the third charge due to the second charge is calculated as follows;

\(F_{23} = \frac{kq_2 q_3}{r^2} \\\\F_{23} = \frac{9\times 10^9 \times (32 \times 10^{-9}) \times (55 \times 10^{-9})}{(1.22)^2} \\\\F_{23} = 1.064 \times 10^{-5} \ N\)

The net force on the third charge is calculated as follows;

\(F_{net} = F_{13} + F_{23}\\\\F_{net} = -4.28 \times 10^{-5} \ N \ + \ 1.064 \times 10^{-5} \ N\\\\F_{net} = -3.216 \times 10^{-5} \ N\)

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If a frictionless plane is 10.0 m long and inclined at 36.0°.

We can use conservation of energy to find the distance that the first sled travels up the incline. The potential energy of the sled at the bottom of the incline is zero, and its kinetic energy is:

KE = (1/2)mv^2

where m is the mass of the sled and v is its speed. At the point where the sled stops, all of its kinetic energy has been converted into potential energy, so we can write:

mgh = (1/2)mv^2

where h is the height that the sled has traveled up the incline. Solving for h, we get:

h = (v^2)/(2g)

where g is the acceleration due to gravity. Using the given values, we have:

h = (6.00 m/s)^2 / (2 * 9.81 m/s^2) = 1.83 m

So the first sled travels a distance of 10.0 m - 1.83 m = 8.17 m up the incline.

b. To find the initial speed of the second sled, we can use conservation of energy again. At the top of the incline, the sled has potential energy:

PE = mgh

where h is the height of the incline. As the sled slides down the incline, its potential energy is converted into kinetic energy:

KE = (1/2)mv^2

where v is the speed of the sled at the bottom of the incline. We can equate these two expressions and solve for v:

mgh = (1/2)mv^2

v = sqrt(2gh)

Using the given values, we have:

v = sqrt(2 * 9.81 m/s^2 * 10.0 m * sin(36.0°)) = 12.2 m/s

So the second sled must be released from the top of the incline with an initial speed of 12.2 m/s.

The position of the sled as a function of time is given by:

y = -0.5gt^2 + Vi*t + h

where y is the vertical position of the sled, t is the time, Vi is the initial speed of the sled, and h is the height of the incline. At the bottom of the incline, y = 0, so we can solve for the time it takes for the second sled to reach the bottom:

0 = -0.5gt^2 + Vi*t + h

t = (Vi ± sqrt(Vi^2 - 2gh)) / g

Since we want both sleds to reach the bottom at the same time, we set the time for the first sled to slide down the incline equal to this expression for t and solve for Vi:

t = sqrt(2h/g) = sqrt(2 * 1.83 m / 9.81 m/s^2) = 0.619 s

0 = -0.5gt^2 + Vi*t + h

Vi = (h - 0.5gt^2) / t

Vi = (1.83 m - 0.5 * 9.81 m/s^2 * (0.619 s)^2) / 0.619 s

Vi = 5.68 m/s

So the initial speed of the second sled is about  5.68 m/s

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The true statement is "Sam's ball interacting with the track converted energy into heat." The correct option is B.

The law of conservation of energy states that energy cannot be created or destroyed, only transferred or converted from one form to another. This means that the total amount of energy in a closed system remains constant.

The friction between Sam's ball and the track caused some of the energy to be lost as heat, while Keyana's ball experienced no such loss due to the absence of friction in her experiment. Therefore, Keyana's ball retained more of its initial potential energy as kinetic energy, resulting in a greater velocity and hence more kinetic energy at the bottom.

Option A (Sam's ball lost mass as it traveled along the track) is not true because it is not possible for the ball to lose mass during the experiment. The mass of the ball is a constant value and is not affected by the experiment.

Option C (Keyana's ball was able to gain momentum) is not the best explanation because momentum is not conserved in this scenario since external forces like friction are acting on the ball. The ball is only gaining kinetic energy.

Option D (Keyana's ball had more potential energy) is not true because both Keyana and Sam released the ball from the same vertical height. Therefore, both balls had the same initial potential energy. The difference in their kinetic energies at the bottom can be explained by the difference in their conservation of energy due to friction.

Therefore, The correct statement that best explains why Keyana's ball had more kinetic energy than Sam's when it reached the bottom, even though energy is conserved, is: Sam's ball interacting with the track converted energy into heat.

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Answer:

a) DOWN direction,  b)  directed INTO THE SCREEN, c)    F = 0

Explanation:

The direction of the force is

for electric force

           F = q E

where we assume a positive test charge, for which the force has the direction of the electric field.

For a magnetic field

in this case the direction of the force is given by the right hand rule.

For a positive test charge, the thumb points in the direction of velocity, the other fingers extended in the direction of the magnetic field, and the palm gives the direction of force for a positive charge.

           F = q v x B

Let us apply these considerations to our case.

a) negative charge moving to the left

in a magnetic field points away from the screen

In this case the thumb goes to the left, the fingers extended outwards and the palm points upwards, but since the charge is negative the force has a DOWN direction.

b) negative charge moves to the left

in electric field it points off the screen.

The outside is in the direction of the electric field and since the charge is negative, the force is directed INTO THE SCREEN

c) positive charge moves down

in magnetic field points up

in this case the velocity and the field have the same direction so the vector product of them is zero

       F = q v  B sin 0

       F = 0

K+ ions are propelled by a driving force (df) of +15 mV, and the ion movement is inwards directed.

The external effort necessary to move a charge in an electromagnetic field from one position to another is called as an electric potential difference, or voltage. A test charge with a result of +1 will experience an electromagnetic potential difference, which is a shift in electric potential.

At equilibrium, the bottom of the cell ought to be negative in relation to the outside because K+ ions have an electromotive force of Ek = -78 mV.

Since Vm = -93 mV

df = Ek - Vm

= -78 mV - (-93 mV)

= +15 mV.

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Answer:

  72.5 A

Explanation:

There are about 13.6 coulombs of free electron charges in each cubic mm of copper. So, the rate of movement of charge is that quantity multiplied by the volume in the flow.

  V = πr²h  . . . . .  volume of a cylinder

  V = π(1.947 mm/2)²(1.79 mm/s) = 5.329 mm³/s

Then the charge flow rate is ...

  (13.6 C/mm³)(5.329 mm³/s) = 72.5 C/s

The magnitude of the current is about 72.5 amperes.

______

Additional comment

The volume of free charge in copper can be computed from the density, molar mass, number of atoms in a mole, number of charges in a coulomb, and the number of free charges per atom. Some of the combinations of necessary calculations can be found with a web search, so it is not unreasonable to presume that the charge density is known.

Answer:

Explanation:

What is your question? There is multiple questions to answer...

Answer:

what question u want

Explanation:

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

I would think a vector but double check that before turning it in

Explanation:

The drag force acting on the airplanes flying at some height in terms of the density of air at the same height is,

where d is the density of air,

The density of air decreases with the increase in altitude.

Thus, to reduce the drag force on the airplane (and lose its energy in opposing the drag force), it is preferred to fly at large altitudes.

Answer:

9000 m

Explanation:

I multiplied 300 by 30!

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Answer:

light is captured through ozone layer.

Explanation:

as its the ozone layer that protects earth from the harmful radiation of the earth and store only the light and energy needed.

Fun Fact - ozone layer can provide light for about 7 minutes so if sun disappears, we won't even realise it for 7 minute straight.

The work done by the force is zero. This is because the force is only infinite at a single point and becomes finite as the object moves away from that point.

The work done by a force is given by the formula:

W = ∫F.dx

where ∫ represents integration and dx represents a small distance along the x-axis.

In this problem, the force acting on the object is given by:

F₁ = A/Vx

where A = 3.0 N-m1/2.

We need to find the work done by this force on the object as it moves from x = 0.0 to x = 1.0 m along the x-axis.

Now, the force F₁ is infinite at x = 0.0 because Vx = 0 at x = 0.0.

However, we can still calculate the work done by this force by breaking up the integration into two parts - one from x = 0.0 to a small distance δx, and the other from δx to x = 1.0 m.

Let's first calculate the work done by the force from x = 0.0 to δx:

W₁ = ∫(0 to δx) F₁.dx

= ∫(0 to δx) A/Vx.dx

= A ln(Vx)|0 to δx

= A ln(δx)

Now, let's calculate the work done by the force from δx to x = 1.0 m:

W₂ = ∫(δx to 1.0) F₁.dx

= ∫(δx to 1.0) A/Vx.dx

= A (ln(Vx)|δx to 1.0)

= A (ln(1) - ln(δx))

= -A ln(δx)

Therefore, the total work done by the force is:

W = W₁ + W₂

= A ln(δx) - A ln(δx)

= 0

This means that the work done by the force is zero, which might seem surprising given that the force is infinite at x = 0.0. However, this is because the force is only infinite at a single point and becomes finite as the object moves away from that point.

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Answer:

the acceleration of an object is directly proportional to the net force and inversely proportional to its mass.

Explanation:

when the net force on an object goes up, so does the acceleration, meaning one increases as the other increases

the acceleration of an object decreases as the mass increases, therefore this relationship is inversely proportional

The equation of the progressive wave is y = 12 cos(40t - 4x)

The general wave equation is given by:

y = A sin(ωt - kx)

Where A is the amplitude, ω is the angular frequency = 2πf, f is the frequency, k is the wave number and y, x is the displacement.

Given the equation for a progressive wave is y=6 cos⁡(20t-4x). Hence:

The amplitude A = 6,

ω = 20 = 2πf

f = 20/2π = 3.183 Hz

Twice the amplitude = 2 * 6 = 12, twice the frequency = 2 * 3.183.

ω = 2π(3.183*2) = 40

Therefore the other progressive wave has an equation of:

y = 12 cos(40t - 4x)

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