Which of the following examples shows an increase of energy in the particles of matter? (Select THREE that are true)
liquid to solid
liquid to gas
gas to liquid
OOO
solid to liquid
solid to gas

Answer:

6-hydroxyhexanoic acid

Explanation:

5-hydroxypentanoic acid will form a 7 member group, while 6-hydroxyhexanoic acid will form a 6 member group.

In polymerization, polymers with 6 member groups are more stable than the ones with 7 member groups. This means that 6-hydroxyhexanoic acid will have a higher chance of polymerization, and therefore give a greater yield of polymers, than 5-hydroxypentanoic acid.

The balanced chemical equation for the reaction is:

HBr(aq) + KOH(aq) → KBr(aq) + H₂O(l)

The neutralization reaction between nitric acid (HNO₃) and barium hydroxide (Ba(OH)₂) produces barium nitrate (Ba(NO₃)₂) and water (H₂O). The balanced chemical equation for the reaction is:

HNO₃(aq) + Ba(OH)₂(aq) → Ba(NO₃)₂(aq) + 2H₂O(l)

In this reaction, the hydrogen ions from the acid react with the hydroxide ions from the base to form water, while the remaining ions form the salt.

The neutralization reaction between hydrobromic acid (HBr) and potassium hydroxide (KOH) produces potassium bromide (KBr) and water (H₂O). The balanced chemical equation for the reaction is:

HBr(aq) + KOH(aq) → KBr(aq) + H₂O(l)

In this reaction, the hydrogen ions from the acid react with the hydroxide ions from the base to form water, while the remaining ions form the salt. The resulting solution will be neutral, with a pH of 7.0, as all the acidic and basic properties have been neutralized.

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Answer:

Aà bhûtÿ ñhjkjłfd hÿrèërqw

Explanation:

The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.

Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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Answer:

Explanation:

Bromine >Tellurium > Phosphorus > Helium > Sodium

Electron affinity of Bromine , Tellurium , Phosphorus are positive , of helium is zero and of sodium is negative .

1. The formula of the hydrate is FePO₄•4H₂O

2. The name of the hydrate is Iron(iii) phosphate tetrahydrate.

1. Determination of the formula of the hydrate

The formula of the hydrate can be obtained as follow:

Divide by their molar mass

H₂O = 32.3 / 18 = 1.794

FePO₄ = 67.7 / 151 = 0.448

Divide by the smallest

H₂O = 1.794 / 0.448 = 4

FePO₄ = 0.448 / 0.448 = 1

Therefore, the formula of the hydrate is FePO₄•4H₂O

The name of the hydrate is Iron(iii) phosphate tetrahydrate

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The ionic and net ionic equations for the following reaction is

Co(NO3)2(aq) +Na2CO3(aq)->NaNo3 + CaCO3

Co(NO3)2(aq) +Na2CO3(aq)+CH3COOH-> NaNo3 + CH3COOCo + H2O

Ionic equation is defined as a chemical equation that expresses electrolytes in aqueous solution as dissociated ions.

An ionic equation can also be defined as one that solely depicts the atoms and ions that really participate.

Net ionic equation is defined as only those elements, molecules, and ions actually involved in the chemical process are shown in the chemical equation.

It can also be defined as an equation that simply includes the components that are really involved in the reaction.

Thus, the ionic and net ionic equations for the following reaction is

Co(NO3)2(aq) +Na2CO3(aq)->NaNo3 + CaCO3

Co(NO3)2(aq) +Na2CO3(aq)+CH3COOH-> NaNo3 + CH3COOCo + H2O

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Answer:

Discovered two new radioactive elements They came up with the term radio activity.conducted experiments with uranium-containing

Explanation:

Answer:

ask a pro

Explanation:

hope this was helpful

Answer:

Explanation:

Carbon and water = carbon dioxide and hydrogen

Ethers are less reactive than alkanes but it undergoes a polymerization reaction. The statement is false.

Although ethers are less reactive than alkanes but only a certain group of ethers undergo polymerization reactions and polymerization reactions are one of them. Alkanes do not undergo polymerization reactions.

The polymerization reaction is the joining of monomers of an organic compound to form a polymer chain. This happens through the formation of covalent bonds between the monomeric units. This process happens in alkenes and functional groups containing organic compounds which have unsaturated bonds (double or triple bonds). Thus, they undergo addition reactions. cyclic ethers (epoxides) undergo polymerization reaction.

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Answer:

0.636 moles of CO2

Explanation:

The molar mass of CO2 is 44.01 g/mol (12.01 g/mol for one carbon atom and 2 x 16.00 g/mol for two oxygen atoms). To find the number of moles in 28g of CO2, you can divide the mass by the molar mass: 28g / 44.01 g/mol = 0.636 moles of CO2.

Answer:

Explanation:k

Answer:

Explanation:

It is the 4th scenario is the dependent event. There are 7 gold tokens and 4 silver tokens in a cup. The first student randomly draws a gold token and keeps it. A second student randomly draws a gold token from the cup.

The fouth scenario is a dependent event because the probability of the second student drawing a gold token is affected by the outcome of the first student's draw.

If the first student draws a gold token, then there are only 6 gold tokens left in the cup, the probability changes. but  if the first student does not draw a gold token, then there are 7 gold tokens left in the cup, the probability will remain the same

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Masses of water and carbon dioxide be 54 g and  66 g respectively.

Mass is a measure of the amount of matter that an object contains

Here given data is 1.00 x10⁵ grams of oxygen and  1.00 x10⁵ grams of methane and the reaction is

CH₄ +2O₂ → CO₂ + 2H₂O

Then (12+4)= CH₄ , 2×(16×2)=2O₂  , 12+(16×2)=CO₂  , 2×(16+2)=2H₂O

CH₄ = 16 g, 2O₂ = 64 g, CO₂ = 44 g, 2H₂O = 36 g

Then, we have to find masses of water and carbon dioxide = ?

24g of CH₄=24/16×44 = 66 g of CO₂

16 g of CH₄ will produce 36 g of water

Then, 24 g of CH₄ = 24/16×36 = 54 g of water

Mass of water is  54 g and mass of carbon dioxide is 66 g

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Answer:

nucleus

Explanation:

It is an electron

Answer:

its sodium hydroxide

Explanation:

Answer:

We can use the combined gas law to solve this problem:

(P1V1/T1) = (P2V2/T2)

where:

P1 = 1 atm (pressure of nitrogen gas in the first container)

V1 = 300 cm^3 (volume of the first container)

T1 = 3°C + 273.15 = 276.15 K (temperature of the nitrogen gas in the first container, converted to Kelvin)

P2 = 0.8 atm (pressure of nitrogen gas in the second container)

V2 = ? (volume of the second container, what we want to find)

T2 = 25°C + 273.15 = 298.15 K (temperature of the nitrogen gas in the second container, converted to Kelvin)

Plugging in the values, we get:

(1 atm x 300 cm^3) / 276.15 K = (0.8 atm x V2) / 298.15 K

Simplifying and solving for V2, we get:

V2 = (1 atm x 300 cm^3 x 298.15 K) / (0.8 atm x 276.15 K)

V2 = 1309.5 cm^3

Therefore, the volume of the larger container is approximately 1309.5 cm^3.

Answer:

The flashlight does not want to work.

Explanation:

Im asumming its this one, hope this helps! even though im a little late :/

Explanation:

Force=mass *acceleration

F=300*5

f

F=1500N

The ion with a +3 charge, 28 electrons, and an atomic mass of 71 is the aluminum ion (\(Al^{3+}\)).

Aluminum (Al) typically has an atomic number of 13, which means it has 13 protons and 13 electrons in its neutral state. However, in the given ion, \(Al^{3+}\), the ion has lost three electrons, resulting in a +3 charge. This means that the ion now has 13 protons and only 10 electrons remaining, giving it a net positive charge of +3.

The atomic mass of aluminum is 26.98 atomic mass units (amu). The given ion has an atomic mass of 71 amu, which suggests that the ion has gained additional particles. In this case, the ion has also gained three neutrons, resulting in a higher atomic mass.

The total number of particles (protons, neutrons, and electrons) in the ion can be calculated by adding the number of protons (13) and the number of neutrons (3), which equals 16. Since the ion has a net charge of +3, it only contains 10 electrons.

In summary, the ion with a +3 charge, 28 electrons, and an atomic mass of 71 is the aluminum ion (\(Al^{3+}\)), which has 13 protons, 10 electrons, and 3 neutrons.

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Dissolve 60g of potassium bromide in 340g of water to produce 15% (mass/mass) aqueous solution of potassium bromide.

Here we have to prepare a total of 400 g of solution. Aqueous solution means the solvent we use here is water.

So to prepare 400 g of 15% aqueous solution of potassium bromide, we need to find out how many grams of potassium bromide need to be dissolved in water and how many grams of water must be used.

Here the weight percent is given, that is 15%

       15/100 = weight of potassium bromide/ 400 g

       0 .15      = weight of potassium bromide / 400

      weight of potassium bromide needed = 0.15 × 400

                                                                       =  60 g

So, we calculated the required amount of potassium bromide as 60 grams. The total weight of the solution to be made is 400 grams.

So amount of water required = 400 - 60

                                                =  340 g

So we need to mix 60 grams of potassium bromide in 340 grams of water to get a 15% (mass/mass) aqueous solution.

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Answer:

Condensation

Explanation:

Zoe is quite keen to have noticed what we call condensation. Air contains many components, one of those being water vapor. Like how sugar is soluble in water, water can be said to be "soluble" in air. Water will evaporate into the air to a certain extent. The higher the temperature of the air, the more water the air can hold. If the air has more water that it can hold (potentially because of a temperature decrease), the extra water will come out of the air. Zoe's water bottle was cold, and because the air around Zoe's bottle had cooled down, the air can not hold as much water as it could when it was warm, so the air deposited the extra water in the form of liquid water onto the bottle, giving the illusion that her bottle was sweating.

Answer:

The answer is 82

Explanation:

Dude in the stop says so

Answer: carbon dioxide and water.

Explanation: I took the test

Answer:

water and carbon dioxide

Explanation:

i took the K12 test :p

Answer:

Large crystals

Slowly

Explanation:

Recrystallization is a procedure used to purify an impure compound in a solvent. The concept used here is that the solubility of most of the solids increases with increase in temperature.

Recrystallization is also called as method of fractional crystallization.

After a recrystallization, a pure substance will ideally appear as a network of large crystals. If this is not the case, it may be worthwhile to reheat the flask and allow the contents to cool more slowly.

The correct answer is 76.9 g of \(Cl_{2}\) is required to react with 19.5 g of \(Al\). Therefore, the correct option is: 76.9 g.

What is Atomic Mass?

Atomic mass, also known as atomic weight or relative atomic mass, is a measure of the mass of an atom of a chemical element. It is expressed in atomic mass units (amu) or unified atomic mass units (u). Atomic mass is a weighted average mass of the naturally occurring isotopes of an element, taking into account their relative abundances.

The balanced chemical equation for the reaction is:

\(2Al\) (s) + 3\(Cl_{2}\) (g) → \(Al_{2}\)\(Cl_{6}\)

From the equation, we can see that the molar ratio between \(Al\)and Cl2 is 2:3. This means that 2 moles of \(Al\) react with 3 moles of \(Cl_{2}\)

To find out how many grams of \(Cl_{2}\) are required to react with 19.5 g of \(Al\) we need to convert the given mass of \(Al\) to moles using its molar mass, and then use the mole ratio from the balanced equation to calculate the amount of \(Cl_{2}\).

The molar mass of \(Al\) is 27 g/mol, and the molar mass of \(Cl_{2}\) is 2 * 35.45 g/mol = 70.9 g/mol.

Moles of \(Al\)= Mass of \(Al\)/ Molar mass of\(Al\)

Moles of \(Al\) = 19.5 g / 27 g/mol ≈ 0.722 mol

According to the mole ratio from the balanced equation, 2 moles of \(Al\)react with 3 moles of \(Cl_{2} .\)

Moles of \(Cl_{2}\)= Moles of \(Al\) * (3 moles of \(Cl_{2}\) / 2 moles of \(Al\))

Moles of \(Cl_{2}\) = 0.722 mol * (3/2) ≈ 1.083 mol

Now, we can convert moles of \(Cl_{2}\) to grams using its molar mass.

Mass of\(Cl_{2}\) = Moles of \(Cl_{2}\) * Molar mass of \(Cl_{2}\)

Mass of\(Cl_{2}\) = 1.083 mol * 70.9 g/mol ≈ 76.9 g

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