Which of the following equations produces a linear function?
A y=x?
B = 2x + 3
C y = |x|
D y=2x2 + 3x - 2

Answer:

Your answer should be A x=+- 3

Step-by-step explanation:

Answer:

d. x = 14; angle measurement is 28 degrees

Step-by-step explanation:

2x is equivalent 28 so divide 28 by 2 to get 14

Answer:

Step-by-step explanation:

Grace: -40t+250

Hannah: -54t+306

-40t+250 = -54t+306

SOLVE THE EQUATION ABOVE

t=4

The total number of hours afternoon when Grace and Hannah are the same distance from the stadium is 4 and this can be determined by forming the linear equations.

Given :

The following steps can be used in order to determine the number of hours afternoon when Grace and Hannah are the same distance from the stadium:

Step 1 - According to the given data, 'G' represents Grace's distance, in miles, away from the stadium and 'H' represents Hannah's distance, in miles, away from the stadium.

Step 2 - The linear equation that represents Grace's distance from the stadium is:

\(G = 250-40t\)

Step 3 - The linear equation that represents Hannah's distance from the stadium is:

\(H = 306 - 54t\)

Step 4 - The value of 't' when Grace and Hannah are the same distance from the stadium is:

\(306-54t = 250-40t\)

Step 5 - Simplify the above expression.

\(56=14t\)

\(\rm t = 4\;hr\)

So, the total number of hours afternoon when Grace and Hannah are the same distance from the stadium is 4.

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Answer:

Total cost =3over8 x 48 x0. 55=9.9

Answer:

$9.90

Step-by-step explanation:

First, we need to find the number of vanilla cupcakes.

The question tell us that 3/8 of the 48 cupcakes are Vanilla flavored, so we can start by dividing 48 by 8 to find what 1/8 of 48 is:

48/8 = 6

1/8 of 48 = 6

Now to find 3/8, we just need to multiply that number by 3:

6 x 3 = 18

3/8 of 48 = 18

So now we know that she bought 18 vanilla cupcakes.

Finally to find the price, we just need to multiply the price per cupcake by the number of cupcakes:

$0.55 per cupcake x 18 cupcakes = 0.55 x 18 = $9.90

The total cost of the vanilla cupcakes was $9.90

Hope this helped!

Therefore , the solution of the given problem of inequality comes out to be the solutions x = -6 or x = -10 would be acceptable.

Algebra, which lacking a symbol for this difference, can represent it using a pair or group of numbers. Equity usually comes after equilibrium. Inequality is bred by the persistent gap of standards. Equality and disparity are not the same thing. As was my least preferred symbol, notwithstanding knowing that the pieces are often not connected or close to one another. (). No matter how small the variations, they all affect value.

Here,

Finding values of x that cause the left side of the inequality to be bigger than the right side is necessary to make the inequality -2x > 10 true. Divide both sides by -2 and invert the inequality sign to achieve this:

=> -2x > 10

=> x < -5

The inequality is therefore true for any value of x that is less than -5. For instance, the solutions x = -6 or x = -10 would be acceptable.

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The simplified expression is \(21x^2 - 25x - 28\) in the given case.

An expression in mathematics is a combination of numbers, symbols, and operators (such as +, -, x, ÷) that represents a mathematical phrase or idea. Expressions can be simple or complex, and they can contain variables, constants, and functions.

"Expression" generally refers to a combination of numbers, symbols, and/or operations that represents a mathematical, logical, or linguistic relationship or concept. The meaning of an expression depends on the context in which it is used, as well as the specific definitions and rules that apply to the symbols and operations involved. For example, in the expression "2 + 3", the plus sign represents addition and the meaning of the expression is "the sum of 2 and 3", which is equal to 5.

To simplify the expression, first distribute the -3x and (3x + 4) terms:

\(-3x(4 - 5x) + (3x + 4)(2x - 7) = -12x + 15x^2 + (6x^2 - 21x + 8x - 28)\)

Next, combine like terms:

\(-12x + 15x^2 + (6x^2 - 21x + 8x - 28) = 21x^2 - 25x - 28\)

Therefore, the simplified expression is \(21x^2 - 25x - 28.\)

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Based on the given values, we can compute the expected returns and expected standard deviations for different weightings of the stocks in the portfolio. The results are as follows:

a. When w1 = 1.00, the expected return of the two-stock portfolio is 0.13, and the expected standard deviation is 0.03.

b. When w1 = 0.65, the expected return of the two-stock portfolio is 0.1095, and the expected standard deviation is 0.0214.

c. When w1 = 0.60, the expected return of the two-stock portfolio is 0.104, and the expected standard deviation is 0.0222.

d. When w1 = 0.30, the expected return of the two-stock portfolio is 0.074, and the expected standard deviation is 0.0262.

e. When w1 = 0.10, the expected return of the two-stock portfolio is 0.038, and the expected standard deviation is 0.0324.

To calculate the expected return of the two-stock portfolio, we use the weighted average of the individual expected returns based on the given weights. For example, in part (a), where w1 = 1.00, the expected return is simply equal to E(R1) = 0.13.

To calculate the expected standard deviation of the two-stock portfolio, we use the formula:

σ = √(w1^2 * E(a1)^2 + w2^2 * E(q2)^2 + 2 * w1 * w2 * E(a1) * E(q2) * ρ)

where E(a1) is the expected standard deviation of stock 1, E(q2) is the expected standard deviation of stock 2, and ρ is the correlation coefficient.

Regarding the risk-return graph, without the specific details of the graph options provided, it is not possible to determine which graph is correct for the given weightings and correlation coefficient. The graph would typically depict the risk-return tradeoff for different weightings and correlation coefficients, showing the relationship between expected return and expected standard deviation of the portfolio.

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One example of a proportional relationship in daily life could be the relationship between the distance traveled by car and the time it takes to travel that distance, assuming a constant speed.

We have,

Let's say we have a car that is traveling at a constant speed of 60 miles per hour.

We can create a table of data to show the relationship between distance and time:

Distance (miles) Time (hours)

60                             1

120                             2

180                             3

240                             4

300                             5

We can see from the table that as the distance traveled increases by a factor of 2, the time it takes to travel that distance also increases by a factor of 2.

This is a proportional relationship.

Thus,

One example of a proportional relationship in daily life could be the relationship between the distance traveled by car and the time it takes to travel that distance, assuming a constant speed.

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To compute the performance measures using the Naive Forecast, we need to use the actual values from April to December.

ME (Mean Error) is the average of the forecast errors. To compute it, we subtract the actual values from the forecasts and take the average. In this case, since we are using the Naive Forecast, the forecast for each month is equal to the actual value of the previous month. Therefore, we have:

ME = (1086 - 1008) + (1081 - 1086) + (1036 - 1081) + (1058 - 1036) + (1128 - 1058) + (1113 - 1128) + (1027 - 1113) + (1021 - 1027) + (1081 - 1021) = -29

The MSE (Mean Squared Error) is the average of the squared forecast errors. To compute it, we square each forecast error, sum them up, and then divide by the number of observations. In this case, we have:

MSE = [(1086 - 1008)^2 + (1081 - 1086)^2 + (1036 - 1081)^2 + (1058 - 1036)^2 + (1128 - 1058)^2 + (1113 - 1128)^2 + (1027 - 1113)^2 + (1021 - 1027)^2 + (1081 - 1021)^2] / 9 = 2218

MAD (Mean Absolute Deviation) is the average of the absolute forecast errors. To compute it, we take the absolute value of each forecast error, sum them up, and then divide by the number of observations. In this case, we have:

MAD = (|1086 - 1008| + |1081 - 1086| + |1036 - 1081| + |1058 - 1036| + |1128 - 1058| + |1113 - 1128| + |1027 - 1113| + |1021 - 1027| + |1081 - 1021|) / 9 = 33

MAPE (Mean Absolute Percentage Error) is the average of the absolute forecast errors as a percentage of the actual values. To compute it, we divide each absolute forecast error by the actual value, sum them up, and then divide by the number of observations. In this case, we have:

MAPE = (|1086 - 1008| / 1008 + |1081 - 1086| / 1086 + |1036 - 1081| / 1081 + |1058 - 1036| / 1036 + |1128 - 1058| / 1058 + |1113 - 1128| / 1128 + |1027 - 1113| / 1113 + |1021 - 1027| / 1027 + |1081 - 1021| / 1021) / 9 * 100 = 2.99%

The Tracking Signal is the ratio of the cumulative forecast errors to the MAD. To compute it, we sum up the forecast errors and divide by the MAD. In this case, we have:

Tracking Signal = (-29) / 33 = -0.88

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Creation

There is no other way

Step-by-step explanation:

tu lo que pusiste es falso

Answer:

15

Step-by-step explanation:

(-2,3)-x1,y1

6,r -x2,y2

slope(m)=3/2

m= y2-y1/x2-x1

3/2= r-3/8

r=15

Answer:

5+2+2(5)+3=4(5)

simplify

5+2+10+3=20 and  4(5)=20  

20=20

Answer: 20

Step-by-step explanation:

Simplify:

5+2+2x5+3

Remove parentheses:

5+2+2(5)+3=4(5)

Multiply the numbers 2x5=10:

5+2+10+3

Add the Numbers:

=20

Simplify (4)5 :

Remove Parentheses:

4 x 5

Multiply:

=20

20=20

Identically, (abc)d = Id and d(abc) = Id. This completes the proof. Therefore, we have shown that if a, b, and c are invertible matrices, then abc is also invertible.

Suppose a, b, and c are invertible matrices. Let’s find a matrix d such that (abc)d = Id and d(abc) = Id, where Id is the identity matrix. Therefore, we can prove that abc is also invertible by introducing a matrix d such that (abc)di and d(abc)i.Proof:We know that the product of invertible matrices is also invertible. Therefore, we can assume that abc is invertible. We need to find a matrix d such that (abc)d = Id and d(abc) = Id.Suppose that (ab)c = e, where e is invertible. Then we have a(bce) = e and (bce)c−1 = a−1. Since c−1 and e are invertible, (bce) is invertible, and we can define d = (bce)−1, which means that d exists. Now we can prove that d satisfies our condition.(abc)d = a(bcd) = a(ec−1b−1) = a(e−1)b−1 = a−1b−1 = (abc)−1.Identically, d(abc) = (bce)−1(ab)c = (bce)−1e = c−1b−1a−1 = (abc)−1.Identically, (abc)d = Id and d(abc) = Id. This completes the proof. Therefore, we have shown that if a, b, and c are invertible matrices, then abc is also invertible.

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Answer:

b

Step-by-step explanation:

Answer:

-4( 4x^2 -y^2)

Step-by-step explanation:

so I did the step on the paper

first line : is the equation itself

2nd line : I multiple the term in the parentheses together

3rd line: I multiple the - 2 to the term I got

4th line : I simplify it

Answer:

-16x^2 + 4y^2

Step-by-step explanation:

-2(4x+2y) x (2x-y)

(-8x-4y) x (2x-y)

-16x^2+8xy+8xy+4y^2

-16x^2+4y^2

Answer:

y= 2x + (-2)

Step-by-step explanation:

The algebraic formula y=mx+b can be broken down into mx, equaling slope +x, and b, which is the y intercept. Taking two points from the slope, you can see that the slope is 2, as the line moves up 2 on the y axis for every 1 move horizontally on the x axis. Additionally, we see that this particular line crosses the y axis at the point (-2), meaning that is the y intercept. Hope this can offer some assistance.

b. convergent Since the limit approaches infinity, the integral diverges. Therefore, the answer is convergent .

To determine the convergence of the integral [infinity] 39 ln(x) x dx, we can use the integral test. This test states that if f(x) is a continuous, positive, and decreasing function on [a, infinity), then the improper integral [a, infinity) f(x) dx converges if and only if the series sum from n=a to infinity of f(n) converges.

In this case, we have f(x) = 39 ln(x)/x, which is a continuous, positive, and decreasing function on [1, infinity). Thus, we can apply the integral test.

Let's evaluate the integral using integration by parts:

∫ 39 ln(x)/x dx = 39 ∫ ln(x) d(ln(x))
= 39 (ln(x))^2/2 + C

Now, we need to check whether the integral converges or diverges.

As x approaches infinity, ln(x) grows without bound, so (ln(x))^2 grows even faster. Thus, the integral is improper at infinity.

We can evaluate the limit as x approaches infinity of (ln(x))^2/2 to determine whether the integral converges or diverges:

lim (x → infinity) (ln(x))^2/2 = infinity

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The number of customers (n) must be between 0 and 100 (inclusive) to be within the valid domain of the function.

In this context, the domain of the function h(n) represents the valid values for the number of customers (n) that can attend the theater on Thursday nights.

Given that the theater holds 100 customers at capacity, the domain would be limited to values of n that fall within the capacity of the theater, which is from 0 to 100. This is because the theater cannot accommodate more than 100 customers, and it is not possible to have a negative number of customers.

Therefore, the domain of the function h(n) in this context would be:

Domain: 0 ≤ n ≤ 100

It means that the number of customers (n) must be between 0 and 100 (inclusive) to be within the valid domain of the function.

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Answer:

therefore According to the diagram y= start over

The transformation of the parent graph of y = √x to y = (1/2)√x is a vertical compression by a factor of 1/2.

A point is transformed when it is moved from where it was originally to a new location. Translation, rotation, reflection, and dilation are examples of different transformations.

As per the shown graph, for any value of x, the output of the function y = (1/2)√x is half of the output of the function y = √x. This means that the y-values of the transformed graph are compressed vertically by a factor of 1/2 compared to the parent graph, while the x-values remain unchanged.

Visually, the graph of y = (1/2)√x will be flatter and closer to the x-axis than the graph of y = √x, with the same x-intercepts (0,0) and (1,1).

Thus, the y-values of the transformed graph are compressed vertically by a factor of 1/2 compared to the parent graph.

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Answer:

The answer is p=576

Step-by-step explanation:

Answer:

sin 41 = 0.656

COS 37 = 0.799

tan 74 = 3.487

sin 16 = 0.276

cos 50 = 0.643

tan 29 = 0.554

Answer:I think it’s answer B

Step-by-step explanation:because if you measure figure 2 it will be about 451 and you need it to hold about 300 so it can’t be a or c and figure 3 holds about 321 while figure 1 holds about something so I think it’s B

Answer:\(-10, -10, -10\)

Step-by-step explanation:

\(h(x)\) is not dependent on x.

The depreciation expense Apollo would recognize on this equipment for the first two years using the Double Declining Balance Method (200% declining balance method) is $16,000 for Year 1 (2014) and $9,600 for Year 2 (2015).

The Cost of Equipment (COE) is $40,000, Salvage Value (SV) is $4,000, and Useful Life (UL) is 5 years. Now, we need to calculate the depreciation expense.

First, we need to find the Depreciation Rate (DR):

DR = 2/UL

where, UL = 5

So, DR = 2/5 = 0.4 or 40%

For Year 1, the Depreciation Rate (DR) would be applied on the cost of equipment (COE) of 2014. So, the depreciation expense of Year 1 would be:

Depreciation expense of Year 1 = DR x COE of 2014

Depreciation expense of Year 1 = 0.4 x $40,000

Depreciation expense of Year 1 = $16,000

For Year 2, the Depreciation Rate (DR) would be applied on the remaining balance of the equipment (COE - Depreciation Expense of Year 1). So, the depreciation expense of Year 2 would be:

Remaining balance of the equipment = COE - Depreciation Expense of Year 1

Remaining balance of the equipment = $40,000 - $16,000

Remaining balance of the equipment = $24,000

Depreciation expense of Year 2 = DR x Remaining balance of the equipment

Depreciation expense of Year 2 = 0.4 x $24,000

Depreciation expense of Year 2 = $9,600

Therefore, the depreciation expense Apollo would recognize on this equipment for the first two years using the Double Declining Balance Method (200% declining balance method) is $16,000 for Year 1 (2014) and $9,600 for Year 2 (2015).

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The given problem asks for specific function values based on the graph of two functions, f(x) and g(x). We evaluate the sum of the function values of f(x) and g(x) at x=1.

a) (f+g)(1): To find the value of (f+g)(1), we evaluate the sum of the function values of f(x) and g(x) at x=1. b) (f-g)(2): To find the value of (f-g)(2), we evaluate the difference of the function values of f(x) and g(x) at x=2.

c) (f+g)(0): To find the value of (f+g)(0), we evaluate the sum of the function values of f(x) and g(x) at x=0.d) (f×g)(5): To find the value of (f×g)(5), we evaluate the product of the function values of f(x) and g(x) at x=5.

e) (f-¹-g-¹)(-1): To find the value of (f-¹-g-¹)(-1), we first take the inverse of f(x) and g(x), and then evaluate their difference at x=-1. By substituting the corresponding x-values into the given expressions and evaluating the functions, we can determine the indicated function values.Please note that without the actual graph and specific functions f(x) and g(x), we cannot provide the exact numerical values.

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#complete the question

Closed-end

You can answer "yes" or "no" to the completed question. Or, the number of answers is limited (eg A, B, C, or all of the above). Closed-end questions are often suitable for voting, as response rates are high when users don't have to type too much.

Closed-end questions are defined as question types that require respondents to choose from a specific set of predefined answers. B. Between "yes/no" or fixed multiple-choice questions. In a typical scenario, closed-end questions are used to collect quantitative data from respondents.

An indefinite definition represents a situation or question with a predetermined number of results. An example of a closed ending is the question "Do you need help?" This usually has only four answers-yes, no, maybe, or not.

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Referring to the truth table, -P is false, and the only case with -P false is when both T and S are false.

This means that 5657 is not a triangular or square number.

(a) To create a truth table for the statement "If a number is triangular or square (T ∨ S), then it is not prime (-P)," we will have columns for T, S, T ∨ S, and -P.

Then we will consider all possible combinations of T and S (true and false) and fill out the remaining columns.
| T   | S   | T ∨ S | -P  |
|-----|-----|-------|-----|
| T   | T   | T     | T   |
| T   | F   | T     | T   |
| F   | T   | T     | T   |
| F   | F   | F     | F   |

(b) If the statement were false, a counterexample would need to have T ∨ S true, but -P false.

In other words, a number that is either triangular or square, and also prime. However, no such counterexample exists in the table, indicating that the statement is true.
(c) Since the statement is true, knowing that 5657 is prime (P) allows us to conclude that it is neither triangular (T) nor square (S).

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Answer: No Solution

Step-by-step explanation:

||3x - 1| + 5| <1  ⇒

\(\left \{ {{|3x - 1| + 5 < 1} \atop {|3x - 1| + 5 > -1 }} \right.\)    ⇒

\(\left \{ {{|3x - 1| < -4} \atop {|3x - 1| > -6} \right.\)        ⇒

The first equation does not make sense because absolute value and as it is a system of equations, the whole system does not have a solution.