Which of the following elements has the largest atomic radius?

As, S, Sr

PLS HELP ITS DUE TONIGHT thank u

The correct option is D. Lactic acid is fashioned and irritates myocardial nerve fibers. while myocardial oxygen name for exceeds oxygen deliver, mobile metabolism modifications from cardio to anaerobic, and lactic acid accumulates, irritating myocardial nerve fibers, which causes aches.

Lactic acid is a shape of herbal acid this is produced naturally in the body within the direction of numerous metabolic strategies. It has the chemical additive C3H6O3 and is classified as an alpha-hydroxy acid. Lactic acid is used in numerous commercial enterprises and meal programs, consisting of the manufacturing of biodegradable plastics, detergents, and prescription drugs.

In chemistry, lactic acid is classified as a carboxylic acid because it includes a carboxyl organization (-COOH). it could exist in two paperwork: L-lactic acid and D-lactic acid, which may reflect pictures of every other. The L-shape is the most commonly discovered in nature and is the sort that is produced thru the body all through exercise.

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Answer:

True

Explanation:

Answer:

prison cells

Explanation:

Robert hook thought of prison cells when he first was the cells

Answer:

Robert Hooke called what he saw a cell because it reminded him of the cells in a monastery.

I hope this helps you

Answer

a) Ba

b) Si

c) Zn

Explanation

The presence of unpaired electrons in an atom orbitals indicates paramagnetic properties. When no unpaired electron is observed in an atom orbitals, such an atom possesses diamagnetic properties.

Therefore, atoms in their ground states that are expected to be diamagnetic in the options are:

a) Ba

b) Si

c) Zn

Answer:

2.8J

Explanation:

Given parameters:

Specific heat capacity  = 0.129J/g°C

Mass  = 0.7g

Initial temperature  = 53°C

Final temperature  = 22°C

Unknown:

Quantity of heat released  = ?

Solution:

To solve this problem, we use the expression below;

       H  = m c Ф

 H is the quantity of heat released

m is the mass

 c is the specific heat capacity

  Ф is the change in temperature

Now,

  Insert the given parameters and solve;

  H  = 0.7 x 0.129 x (22  - 53)  = -2.8J

The amount of heat released is 2.8J, the negative depicts the heat released.

Answer:

Try doing this: 50.7/.9327 for the answer.

In each repetition of the β-oxidation pathway, one molecule of FADH2 is generated, resulting in the production of 1.5 ATPs. Additionally, one molecule of NADH is generated, leading to the production of 2.5 ATPs.

The β-oxidation pathway is responsible for the breakdown of fatty acids into acetyl-CoA molecules. During this process, each repetition of the pathway generates one molecule of FADH2 and one molecule of NADH.

For every molecule of FADH2 produced, 1.5 ATPs are generated through the electron transport chain and oxidative phosphorylation. Similarly, for every molecule of NADH produced, 2.5 ATPs are generated.

Therefore, in each repetition of the β-oxidation pathway, the FADH2 molecule contributes 1.5 ATPs, and the NADH molecule contributes 2.5 ATPs, making them essential for energy production in cellular respiration.

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We need 3.547 mL of 2.155 M KOH solution to titrate 25.00 mL of 0.3057 M HC3H5O2 solution. To determine the number of milliliters of 2.155 M KOH(aq) required to titrate 25.00 mL of 0.3057 M HC3H5O2(aq) (propionic acid), we need to use the balanced chemical equation between KOH and HC3H5O2.

The equation is:

KOH(aq) + HC3H5O2(aq) → KC3H5O2(aq) + H2O(l)

From the equation, we can see that 1 mole of KOH reacts with 1 mole of HC3H5O2. Therefore, the number of moles of HC3H5O2 in 25.00 mL of 0.3057 M solution is:

n(HC3H5O2) = M(HC3H5O2) × V(HC3H5O2) = 0.3057 mol/L × 0.02500 L = 0.0076435 mol

Since the stoichiometric ratio between KOH and HC3H5O2 is 1:1, we need 0.0076435 moles of KOH to react with the given amount of HC3H5O2. The number of milliliters of 2.155 M KOH solution required is:

V(KOH) = n(KOH) ÷ M(KOH) = 0.0076435 mol ÷ 2.155 mol/L = 0.003547 L or 3.547 mL (rounded to three significant figures)

Therefore, we need 3.547 mL of 2.155 M KOH solution to titrate 25.00 mL of 0.3057 M HC3H5O2 solution.

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a. The rate at which it consumes NO2 is 300 molecules NO2/sec and the rate at which it consumes O3- is 150 molecules O3-/sec.

The rate at which the reaction consumes NO2 and O3- can be determined using the stoichiometry of the reaction. The balanced chemical equation for the reaction is:
2NO2 + O3- → 2O2 + 2NO3-

From this equation, we can see that for every 2 molecules of O2 produced, 2 molecules of NO2 are consumed and 1 molecule of O3- is consumed. Therefore, if the reaction is producing O2 at the rate of 300 molecules per second, the rate at which it consumes NO2 is:

(300 molecules O2/sec) x (2 molecules NO2/2 molecules O2) = 300 molecules NO2/sec

And the rate at which it consumes O3- is:
(300 molecules O2/sec) x (1 molecule O3-/2 molecules O2) = 150 molecules O3-/sec

b. The rate equation for a reaction that is first order in NO2 and first order in O3- is rate = k[NO2][O3-]
where k is the rate constant, [NO2] is the concentration of NO2, and [O3-] is the concentration of O3-.

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Answer:

Because graphite has delocalised electrons ,just like metal

Graphite is the allotrope of carbon. Allotropes are chemical compounds of the single element present and arranged in a complex form.

The uses of the graphite are as follows:-

Graphite the is allotropes of the carbon which means it has a free electron in the valence shell. In graphite, there is one free electron which moves from one place to another.

The movement of transferring the electron in the compound can allow the graphite to conduct heat.

Hence, the free electron is the answer.

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The principal law governing pollution of the nation’s surface waters is the Federal Water

Pollution Control Act, or Clean Water Act. Originally enacted in 1948, it was totally revised by

amendments in 1972 that gave the act its current dimensions. The 1972 legislation spelled out

ambitious programs for water quality improvement that have since been expanded and are still

being implemented by industries and municipalities.

This report presents a summary of the law, describing the statute without discussing its

implementation. Other CRS reports discuss implementation, including CRS Report R42883,

Water Quality Issues in the 113th Congress: An Overview, and numerous products cited in that

report.

The Clean Water Act consists of two major parts, one being the provisions which authorize

federal financial assistance for municipal sewage treatment plant construction. The other is the

regulatory requirements that apply to industrial and municipal dischargers. The act has been

termed a technology-forcing statute because of the rigorous demands placed on those who are

regulated by it to achieve higher and higher levels of pollution abatement under deadlines

specified in the law. Early on, emphasis was on controlling discharges of conventional pollutants

(e.g., suspended solids or bacteria that are biodegradable and occur naturally in the aquatic

environment), while control of toxic pollutant discharges has been a key focus of water quality

programs more recently.

Prior to 1987, programs were primarily directed at point source pollution, that is, wastes

discharged by industrial and municipal facilities from discrete sources such as pipes and outfalls.

Amendments to the law in that year authorized measures to address nonpoint source pollution

(runoff from farm lands, forests, construction sites, and urban areas), which is estimated to

represent more than 50% of the nation’s remaining water pollution problems. The act also

prohibits discharge of oil and hazardous substances into U.S. waters.

Under this act, federal jurisdiction is broad, particularly regarding establishment of national

standards or effluent limitations. Certain responsibilities are delegated to the states, and the act

embodies a philosophy of federal-state partnership in which the federal government sets the

agenda and standards for pollution abatement, while states carry out day-to-day activities of

implementation and enforcement.

To achieve its objectives, the act is based on the concept that all discharges into the nation’s

waters are unlawful, unless specifically authorized by a permit, which is the act’s principal

enforcement tool. The law has civil, criminal, and administrative enforcement provisions and also

permits citizen suit enforcement.

Financial assistance for constructing municipal sewage treatment plants and certain other types of

water quality improvements projects is authorized under Title VI. It authorizes grants to capitalize

State Water Pollution Control Revolving Funds, or loan programs. States contribute matching

funds, and under the revolving loan fund concept, monies used for wastewater treatment

construction are repaid to states, to be available for future construction in other communities.

if 1.888 g of bismuth metal reacts with sulfur to give 2.323 g of bismuth sulfide, Bi2S3  is the empirical formula of the product.

The relatively simple entire numbers ratios of elements in a physical compound is its empirical formula. The empirical formula for sulphur monoxide, or SO, and disulfur dioxide, both of which are basic illustrations of such a notion, are both SO. S₂O₂ An empirical formula is just a cell's chemical formula that only specifies the ratios of the components it has and not the exact number or atom arrangement. This would be compound's element with the greatest whole number ratio. The simplest pretty much the entire ratio of the elements in a molecule is shown by empirical formulae, the quantity of each atom type is shown by molecule formulas, and the organization of the atoms in a structure is determined by structural formulas where molecules are bounded to each other.

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A balanced chemical equation, which demonstrates that all mass is conserved throughout the reaction, demonstrates the law of conservation of mass. The quantity and types of atoms on either side of a chemical equation should be equal in a balanced chemical equation.

In accordance with the principle of mass conservation, There is neither creation nor destruction of mass during a chemical process. In other words, the total masses of the reactants and products must be equal.

The reactants of photosynthesis are sunlight, 6 carbon dioxide, and 6 water. The mass of the products, which are 1 glucose and 6 oxygen, is equal to the mass of these reactants added together. Contrarily, cellular respiration uses glucose and oxygen gas to create water, carbon dioxide, and ATP, a source of useable energy.

The products of photosynthesis are the reactants of cellular respiration, which is the reverse of photosynthesis. The law of conservation of mass is also observed during cellular respiration.

A balanced chemical equation, which demonstrates that all mass is conserved throughout the reaction, demonstrates the law of conservation of mass. The quantity and types of atoms on either side of a chemical equation should be equal in a balanced chemical equation.

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The 95% margin of error for the mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment is ±1.98 (rounded off to two decimal places).

The mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment can be estimated by using the formula;μ = x ± z(\(a^{2}\)) * σ/√n

Where;μ is the population mean increase.x is the sample mean increase.z(\(a^{2}\)) is the z-scoreα is the level of significanceσ is the population standard deviationn is the sample size.

Substituting the given values into the formula;μ = 9.1 ± 1.96 * 5.5/√37= 9.1 ± 1.98

The mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment lies between 7.12 to 11.08.

Hence, the estimated mean increase is between 7.12 to 11.08 millimeters of mercury.

The 95% margin of error can be calculated using the formula;

Margin of error (E) = z(\(a^{2}\)) * σ/√n

Margin of error (E) = 1.96 * 5.5/√37

Margin of error (E) = 1.98 (approximated to two decimal places).

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Answer:

thank you for this oibnki

Answer:

Sure I'll go ahead and like your answers and follow you if that's what you wanted! :)

Explanation:

Answer:

the mass of an does not change with speed but changes when we add or cut a part of it.

Explanation:

Answer:

weight

Explanation:

The height at which the firework explodes is 1258.7 m and the time taken to travel upward is 9.57 seconds.

Given data:

Initial velocity, u = 74 m/s

Acceleration due to gravity, g = 7.73 m/s²

To find:

Height at which the firework explodes, H

Time it will be traveling upward, t

We know that,

Height of the object, H = ut - 1/2gt²

Now, the firework will explode at the moment it will start moving down, which means it will reach maximum height at this point. So, at maximum height, v = 0

Using v = u - gt

0 = 74 - 7.73t

t = 74 / 7.73t = 9.57 s

The total time taken by the firework to reach the maximum height will be twice the time it takes to reach the maximum height. So, the time taken to reach the maximum height, t/2 = 4.785 s

Substituting the value of t in the height formula,

H = ut - 1/2gt²H = 74 × 4.785 - 1/2 × 7.73 × (4.785)²H

= 1367.6 - 108.9H

= 1258.7 m

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Answer:

a gas has a changeable shape and has the same volume in any container

Answer:

19.79%

Explanation:

mass % = (mass solute / total mass) * 100

total mass = 129.54 + 525 = 654.54

solute = C6H12O6

(129.54/654.54) = .1979

.1979 * 100 = 19.79%

Answer:

B

Explanation:

The heated atmosphere cause glaciers and ice caps to melt causing the sea level to rise

Answer:

Rising temperatures melt more glaciers and polar ice caps, which add water to the ocean.

Explanation:

The molarity of NaOH solution is 0.114 M.

Given, Mass of flask and vinegar solution= 25.17 g.Mass of flask= 15.12 gVolume of vinegar solution (in mL)= 10.00 mlInitial volume of NaOH (in mL)= 0.00 mlFinal volume of NaOH (in mL)= 39.00 mlThe Mass of vinegar solution is 10.0503 g.The volume of NaOH used in titration is 39.00 ml.Let's calculate the molarity of the NaOH solution.First, calculate the moles of NaOH used in the reaction. Moles of NaOH = Molarity × Volume of NaOH (in L) Converting volume in mL to L,Volume of NaOH used = 39.00 mL = 39.00/1000 L = 0.0390 LThe molarity of NaOH solution is given by;Molarity of NaOH = Moles of NaOH / Volume of vinegar solution (in L)Converting volume in mL to L,Volume of vinegar solution = 10.00 mL = 10.00/1000 L = 0.0100 LNow, substituting the values; Molarity of NaOH = 0.114 M.

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The statement is FALSE. Non-ferrous metals can be hardened by heat treatment, although the mechanisms and processes involved may differ from ferrous metals.

Heat treatment techniques such as precipitation hardening can be used to increase the strength of non-ferrous metals. Non-ferrous metals are metals or alloys that do not include iron (or iron allotropes, such as ferrite, etc.) in significant quantities. Non-ferrous metals are employed because they have desired qualities like reduced weight (for example, aluminium), greater conductivity (for example, copper), non-magnetic characteristics, or corrosion resistance (for example, zinc), even though they are often more expensive than ferrous metals. In the iron and steel sectors, several non-ferrous materials are also employed. Bauxite, for instance, is used as a flux in blast furnaces, whereas wolframite, pyrolusite, and chromite are utilised to create ferrous alloys.

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The value of k for this aqueous reaction at 298 k a b↽−−⇀c  dδ°=10. 35 KJ/mol is 30.37 mol.

K is the song which is used to donate the equilibrium of a reaction and the equilibrium of the reaction can only be obtained when the concentration of reactant is equal to the concentration of the product.

K is also known as the equilibrium constant.

δG or dδ° = - R T In K

                     R = universal gas constant

                     T = 298 k or 24.4Celciuss

                      dδ°= 10. 35

substituting the value in the equation

10. 35 = - 8.313 ×  24.4 celcius  In k

 In k =  - 8.313 ×  24.4 celcius / 10. 35

 In k = 30.37 mol.

Therefore, the value of k for this aqueous reaction at 298 k a b↽−−⇀c  dδ°=10. 35 KJ/mol is 30.37 mol.

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Answer:

January 9th 1915

Explanation:

Answer:

People show more interest in personal broadcasting.

Explanation:

The art of oration (speaking) is being  replaced by personal broadcasting mean now people used webcam or camcorder for creating its own content and transmit it to other people through internet. Personal broadcasting provides audio and video to the individual that make it more interesting as compared to oration. People show more interest in personal broadcasting as compared to oration so that's why oration is replaced by personal broadcasting.

To solve this, we must know the formula for mass defect. Protons and neutrons are the nucleons at play here. Therefore,  the mass defect of the nucleus of thorium-232 is 1.911384 amu.

The difference or disparity between the mass of the nucleus and the mass of the nucleons is known as a mass defect.

mass of protons = 1.6727 x 10⁻²⁴ g

                           = 1.007316 amu

mass of neutrons= 1.6750 x  10⁻²⁴  g

                           = 1.008701 amu

mass of Thorium= 234 g/mol

                            = 234 amu

In thorium -232

protons = 90

neutrons = 144

mass defect = mass of protons×90 + mass of neutrons ×144 - 234

mass defect = 1.911384 amu

Therefore,  the mass defect of the nucleus of thorium-232 is 1.911384 amu.

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Answer: Citation generators are programs that turn information about a source into a citation that the writer can use in a project.

Explanation:

An ACS citation generator is an online tool that creates citations in the American Chemical Society (ACS) citation style. It does this automatically by taking in a key identifier for an article or document, such as a URL for websites, ISBN for books, or ISSN for journal articles.

Programs known as "citation generators" transform information about a source into a citation that the author can use in a project. Although there are numerous citation generators, the majority operate in the same way generally: Information about a source is given to the generator.

Citefast is an online citation generator that advertises itself as both a quick and free tool. Citefast can create citations for you using many sources, including ISBNs and web page URLs. You can enter the data on your own by typing.

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