which of the following describes a boiling point?

Each element is defined by its number of protons.

The mass, in kilograms, of aluminum sulfate required to produce 35.85 kilograms of lead (IV) sulfate would be 13.48 kilograms.

The equation of the reaction is as follows:

\(3Pb(CH_3COO)_2 + Al_2(SO_4)_3 -- > 3Pb(SO_4) + 2Al(CH_3COO)_3\)

Mole ratio of aluminum sulfate and lead (IV) sulfate = 1:3

Mole of 35.85 kilograms of lead (IV) sulfate = 35.85x1000/303.26 = 118.2154 moles.

Equivalent moles of aluminum sulfate = 118.2154/3 = 39.41 moles

Mass of 39.41 moles of aluminum sulfate = 39.41 x 342.15 = 13484 grams

13484 grams = 13484/1000 = 13.48 kg

In other words, the mass of aluminum sulfate required to produce 35.85 kilograms of leave (IV) sulfate is 13.48 kilograms.

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The equilibrium constant of the reaction on the basis of concentration is  1.2 * 10^-7.

We know that the equilibrium constant has to do with the value that shows the extent to which the reactants can be converted into products in the reaction as shown. We have been given in the question, the equilibrium constant that is based on the partial pressures of the reactants.

We then have the formula that we have to use to solve the problem as;

Kp = Kc(RT)^Δn

Kp = Equilibrium constant based on partial pressure

Kc = Equilibrium constant based on concentration

R = Gas constant

T = temperature

n = Number of moles

Thus we have;

Kc = Kp/(RT)^Δn

Kc =  2.9×10⁻⁴/(8.314 * 298)^(3-2)

Kc = 2.9×10⁻⁴ /2477.57

Kc = 1.2 * 10^-7

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Answer: D- ecotourism helps pay for conservation efforts

Explanation:

says help and the others exploit and harm

Answer:

Future tense.

Explanation:

The different tenses in grammar are used to denote the time or condition of when the action occurs. This means that tenses tell us the form or condition of the verbs.

The present tense tells us about a present scene while the past tense tells us about an action that happened in the past. Likewise, the future tense tells us about an event that will happen in the future. This means that future tenses are used to describe events that have not taken place, and are yet to happen.

Answer:

B. The substances that are formed

Explanation:

a chemical reaction is a reaction that there's a formation of a new compound or substance.

can i have brainliest? and btw, let me know if you get it right! hope i helped <3

1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

Answer: Pressure of the gas is 19.65 atm.

Explanation: Known quantities=

No of moles=37

Temperature=167 °C=440K

Volume=68 liters

unknown quantities

Pressure=x atm

The unknown quantity pressure can be found out by using the ideal gas law equation given by:

PV=nRT ---------- (1)

P = pressure.

V =volume.

n =amount of substance.

R= ideal gas constant.

Substituting the values in equation (1)

P=(37x0.0821x440)/(68)

=19.65 atm

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Answer:

11318 feet and 10.771 inches

Explanation:

there is 3280.84 in one Km

just do 3280.84x3.45

Explanation:

Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

By convention in standard cell notation, the anode is written on the left and the cathode is written on the right. So, in this cell: Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

Answer:

B

Explanation:

The product would be aluminum oxide, \(Al_2O_3\).

The word equation for a reaction can be interpreted as the formula equation of the same reaction by writing out the chemical formulas of the reactants and products accordingly.

Now, let's consider the reaction in question:

Four atoms of aluminum metal react with three molecules of oxygen to produce two molecules of aluminum oxide.

Four atoms of aluminum = 4 Al

Three molecules of oxygen = \(3O_2\)

two molecules of aluminum oxide = \(2Al_2O_3\)

Thus, the formula equation would be: \(4Al + 3O_2 --- > 2Al_2O_3\)

In other words, the product would be  \(Al_2O_3\).

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The rate expression is k [BF₃]²[NH₃], overall order is 3, rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

The rate expression for this reaction can be written as:

Rate = k [BF₃]^m[NH₃]^n

The method of initial rates can be used to calculate the values of m and n. When we compare experiments 1 and 2, notice that halving the concentration of [NH3] reduces the initial rate of reaction. This suggests that the reaction is first order in terms of [NH3], implying that n = 1.

When comparing experiments 1 and 3, notice that increasing the concentration of [BF3] by a factor of 2.5 increases the initial rate of reaction by a factor of 9.39 (i.e., 2.13/0.227). This shows that the reaction is about second order in relation to [BF3], i.e., m 2.

Therefore, the rate expression for the reaction is:

Rate = k [BF₃]²[NH₃]

The overall order of the reaction is m + n = 3.

Using the data from experiment 4, substitute the values and solve for k:

Rate = k [BF₃]²[NH₃]

1.02 × 10-¹ = k (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.02 × 10-¹ / (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹

Therefore, the rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

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The subshell with quantum numbers n=2 and l=2 is the 2D subshell.

The set of numbers used to describe the position and energy of the electron in an atom are called quantum numbers.

There are four known quantum numbers, and they include:

The  principal quantum number (n) indicates the energy level or shell of an electron, while the azimuthal quantum number (l) indicates the shape of the electron cloud or subshell.

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The statement that is correct about Urban areas is that they have higher temperatures.

Urban Area is a term to refer to cities. Urban areas are characterized by having a developed infrastructure (wide roads, vehicular bridges, wide platforms, tall buildings, residential areas, industrial areas, among others).

Recent studies affirm that urban areas are warmer than surrounding areas; This phenomenon is because the materials with are built buildings, roads, houses, and others, concentrate the sun's rays, increasing the temperature of cities. In addition, the lack of trees deepens this phenomenon, because the trees contribute to cooling by physicochemical processes such as evapotranspiration.

According to the above, it is possible to affirm that urban areas are hotter than their surrounding area because they lack vegetation, and the materials with which it is built contribute to the increase in temperature.

On the other hand, urban areas are characterized by habitat fragmentation, more problems with soil erosion, and less rain infiltration into the soil.

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Answer:

A) higher temps

Explanation:

Answer:

40 litres

Explanation:

using Boyle's law V1P1=V2P2

V1=20 l

P1= 60atm

P2= 30 atm V2=?

substituting we will have that

20×60=V2×30

V2={20×60}/30

V2=40 l

2-Bromopropane is created when hydrobromic acid and propene undergo an addition process. The identical reaction results in 1 bromopropane when benzoyl peroxide is present.

While the halide group attaches to the carbon atom with the most alkyl substituents when a protic acid (HX) is introduced to an asymmetric alkene, the acidic hydrogen adheres to the carbon with the most hydrogen substituents.

The free-radical mechanism governs the addition reaction of HBr to an asymmetrical alkene in the presence of peroxide.  Here, bromine radical is formed which reacts with an alkene and produces an anti-markovnikov product.

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Answer:

c. they make it easier to see the oxidation and reduction parts of the reactions separately

Explanation:

just took the quiz :)

The total number of atoms in 3.75 mol of ammonium nitrate, NH4NO3, is equal to the Avogadro's number, which is 6.022 x 10^23, times the number of moles, which is 3.75 in this case.

Thus, the total number of atoms in 3.75 mol of ammonium nitrate is equal to 2.26 x 10^24 atoms.

This number can be further broken down into the number of atoms of each element present in the compound. Ammonium nitrate is composed of two elements, nitrogen (N) and hydrogen (H). For each mole of ammonium nitrate, there are 4 moles of hydrogen atoms and 2 moles of nitrogen atoms.

Therefore, in 3.75 moles of ammonium nitrate, there are 15 moles of hydrogen atoms and 7.5 moles of nitrogen atoms, which is equal to 9 x 10^24 hydrogen atoms and 4.05 x 10^24 nitrogen atoms.

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The density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

To determine the density of ammonia gas (NH3) in a 6.0 L container at a pressure of 820 mm Hg, we need to use the ideal gas law equation, which relates pressure, volume, number of moles, and temperature for a given gas.

The ideal gas law equation is:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we are given the pressure (820 mm Hg), volume (6.0 L), and assuming standard temperature and pressure (STP), we can use the values for R (0.0821 L·atm/(mol·K)) and convert the pressure to atm by dividing by 760 (1 atm = 760 mm Hg).

820 mm Hg / 760 mm Hg/atm = 1.08 atm

Now we can rearrange the ideal gas law equation to solve for density (d):

d = (P * M) / (RT)

Where M is the molar mass of ammonia (NH3), which is approximately 17.03 g/mol.

Substituting the values, we have:

d = (1.08 atm * 17.03 g/mol) / (0.0821 L·atm/(mol·K) * 298 K)

Simplifying the equation, we find:

d ≈ 0.805 g/L

Therefore, the density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

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Answer:4.2J/(g.°c)

I hope this helps

Explanation:

Answer:

just be smart and learn you gotta learn it first

The final pressure of the gas is obtained as 4.80 atm.

We know that the root mean square speed of the gas would depend on the temperature of the molecules of the gas. Here we are told that the root mean square speed of the gas molecules is doubled and it means that the temperature was also doubled.

We have;

P1/T1 =P2/T2

2T1 = 2P1

The final pressure would  be 2(2.40)atm = 4.80 atm

Thus we ought to have the temperature at the end as 4.80 atm from the calculation that has been done.

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If the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77 and the solution is basic.

To calculate the pOH of a solution, we can use the formula:

pOH = -log[OH-]

Given that the [OH-] concentration is 5.9 x 10^(-M), we can substitute this value into the formula:

pOH = -log(5.9 x 10^(-M))

Calculating this expression, we find:

pOH = -log(5.9 x 10^(-M))

pOH ≈ -log(5.9) + (-log(10^(-M)))

Since log(10^(-M)) is equal to -M, the equation simplifies to:

pOH ≈ -log(5.9) - M

Now, we need the value of M (the exponent) to calculate the exact pOH value. It appears that the value of M is missing in the given information. However, assuming M is a positive value, we can continue the calculation.

If we consider M = 6, for instance, the equation becomes:

pOH ≈ -log(5.9) - 6

Now, we can evaluate the expression:

pOH ≈ 1.23 - 6

pOH ≈ -4.77

Therefore, if the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77.

To determine whether the solution is acidic, basic, or neutral, we can use the relationship between pH and pOH. The sum of the pH and pOH of a solution at 25°C is always equal to 14.

Since pOH = -4.77, the pH would be:

pH = 14 - pOH

pH ≈ 14 - (-4.77)

pH ≈ 18.77

A solution with a pH above 7 is considered basic. In this case, the calculated pH is greater than 7. Therefore, the solution is basic.

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The volume of gas when the pressure is 45 psi is 2,833.33mL.

The volume of a substance can be calculated using Boyle's law equation as follows:

P₁V₁ = P₂V₂

Where;

According to this question, a tank of carbondioxide has a pressure of 850 psi and a volume of 150 mL. The volume can be calculated as follows:

850 × 150 = 45 × V

V = 127,500 ÷ 45

V = 2,833.33mL

Therefore, 2,833.33mL is the volume of the gas.

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Answer:

3rd law

Explanation:

His third laws states that every action has an equal and opposite reaction. because you are putting force on your wall, the wall is giving the force of wall on your finger.

Because the speed limit sign is in kilometres per hour and the driver is accustomed to miles per hour, no other cars are passing too quickly. The permitted speed is roughly 62 mph.

A regulatory sign is the speed limit sign. The purpose of speed limit signs is to inform drivers of the legal maximum and minimum speeds that are required of them. Drivers are not permitted to go over the limit stated by the sign.

When approaching or passing a troop, police, or military procession, or when driving past construction workers fixing roads, a motor vehicle's driver must travel at a pace of no more than 25 kph.

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