Which of the following amino acids would most likely be found on the exterior of a protein molecule, interacting with an aqueous environment?A. valineB. serineC. alanineD. prolineE. leucine

Answers

Answer 1

(Option B.) Serine is an amino acid that is found on the exterior of a protein molecule, interacting with an aqueous environment. This is because serine has a non-polar side chain that is hydrophilic, allowing it to interact with the aqueous environment.

Amino Acids Found on the Exterior of a Protein Molecule Interacting with an Aqueous Environment

Option B. Serine

Serine is an amino acid that is found on the exterior of a protein molecule and interacts with an aqueous environment due to its non-polar side chain that is hydrophilic. This allows it to bind with water molecules, giving it an affinity for aqueous environments. As a result, Serine is the most likely amino acid to be found on the exterior of a protein molecule, interacting with an aqueous environment. It is also important in many biological processes, such as protein synthesis, as it is essential for the formation of peptide bonds.

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Related Questions

List the 2 pKa's for H2SO4

Answers

No pKa1 because it is strong acid, pKa2 = 1.99

What is the oxidation number change for the iron atom in the following reaction? 2 Fe2O3(s) + 3 C(s) → 4 Fe(s) + 3 CO2(g)

Answers

Answer:

\(\boxed{From \ +6 \ to \ 0}\)

Explanation:

2 Fe2O3(s) + 3 C(s) → 4 Fe(s) + 3 CO2(g)

In the given reaction, Iron in the reactants side have the oxidation number of +6. This is because \(O_{3}\) with \(Fe_{2}O_{3}\) has oxidation state -6, So any atom with it would have an oxidation state of +6 to give the resultant of zero.

In the products side, Iron acts as a free element reacting with no other atom. So, as per the rule of oxidation states, the oxidation state of Iron in the products side will be zero.

So, the oxidation number changes from +6 to 0 .

Extra Info: Decrease in oxidation state is Reduction , So Iron is being reduced here.

The change in the oxidation number of the iron atom in the reaction is from +3 to 0

Oxidation is simply defined as the the loss of electron. However, Oxidation number simply talks about the number of electrons that is either gained or lossed during bond formation.

The change in the oxidation number of iron in the reaction can be obtained as follow:

2Fe₂O₃(s) + 3C(s) → 4Fe(s) + 3CO₂(g)

Oxidation number of Fe in Fe₂O₃

Oxidation number of Fe₂O₃ = 0 (ground state)

Oxidation number of oxygen = –2

Oxidation number of Fe =?

Fe₂O₃ = 0

2Fe + 3O = 0

2Fe + 3(–2) = 0

2Fe – 6 = 0

Collect like term

2Fe = 6

Divide both side by 2

Fe = 6/2

Fe = +3

Thus, the oxidation number of Fe in Fe₂O₃ is +3

Oxidation number of Fe (ground state) is zero

Therefore, the change in the oxidation number of the iron, Fe, atom in the reaction is from +3 to 0

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Why are diamagnetic substances repelled by a magnetic field​

Answers

Answer:

Diamagnetic materials are repelled by a magnetic field; an applied magnetic field creates an induced magnetic field in them in the opposite direction, causing a repulsive force.  The magnetic permeability of diamagnetic materials is less than the permeability of vacuum.

Explanation:

As you move down a group the electronegativity of an element will

Answers

As you move down EN generally decreases.

The boiling point of H2O is much higher than that of the analogous molecule H2S. This is mostly due to _________.

Answers

The boiling point of water is higher than that of hydrogen sulfide. the molecular mass of H₂S is higher than that of H₂O.

Despite the fact that H₂O has a lower molar mass than H₂S, why is the normal boiling point of H₂O higher than that of H₂S?

Unlike H₂O, which has a hydrogen bond, H₂S exhibits dipole-dipole attraction. Since the hydrogen bond is stronger than the attraction between the dipoles, it takes more energy to separate the molecule and form a gas, giving H₂O a higher boiling point.

Compared to hydrogen sulfide, water has a higher boiling point. Due to hydrogen bonding in H2O and the hydrogen atoms' small size and high electronegativity, the intermolecular forces between water molecules are stronger than those between H2S molecules.

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Chemical formula for Aluminum Oxide

Answers

Answer: Al₂O₃

Explanation:

what’s is the answer?

whats is the answer?

Answers

The energy of the photon of light can be obtained as 6.27 * 10^-20 J.

What is the energy of the photon?

We know that a photon has to to do with a particular unit of light. We know that light can be said to be composed of very tiny corpuscles and these corpuscles of light is what we call the photon of the light.

We can be able to us the equation that is derived by Max Plank to be able to get the value of the energy of the photon of light. Now we know that a photon of light can have an energy that is able to be obtained by;

E = hf

h = Plank's constant

f = Frequency

Then;

E = 6.6 * 10^-34 Js * 9.5 * 10^13 Hz

= 6.27 * 10^-20 J

Thus as we can see from the parameters in the question, the energy of the photon is 6.27 * 10^-20 J.

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Carbon-14 has a half-life of 5730 years. If an original sample was 100g of C¹4 and it is now 0.781g of C14, how old is your sample?

Answers

Answer:

40,113 years

Explanation:

To find the age of the sample, you need to use the half-life formula:

\(N(t)=N_0(\frac{1}{2})^{t/h\)

In this formula:

------> N(t) = current mass (g)

------> N₀ = initial mass (g)

------> t = time passed (yrs)

------> h = half-life (yrs)

You can plug the given values into the equation and rearrange the formula to find "t".

N(t) = 0.781 g                       t = ? yrs

N₀ = 100 g                           h = 5730 yrs

\(N(t)=N_0(\frac{1}{2})^{t/h\)                                           <----- Half-life formula

\(0.781=100(\frac{1}{2})^{t/5730}\)                                     <----- Insert values

\(0.00781=(\frac{1}{2})^{t/5730}\)                                       <----- Divide both sides by 100

\(log_{1/2}(0.00781)=log_{1/2}((\frac{1}{2})^ {t/5730})\)               <----- Take \(log_{1/2}\) of both sides

\(7.00 = \frac{t}{5730}\)                                                   <----- Solve \(log_{1/2}\)

\(40,113 = t\)                                                   <----- Multiply both sides by 5730

The given sample is 40,113 years .

What do you mean by half-life ?

Half-life, in radioactivity, is the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay.

Half-life formula,

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)   .......(1)

where,

N(t)=current mass

N₀=initial mass

t=time period

h=half -life

Given,

N(t)=0.781g, t=? yrs, N₀=100g, h=5730 years

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)

put the values, in ......(1)

0.781=100(1/2) \(t/5730\\\)

log₁/₂(0.00781)=log₁/₂ ( 1/2)\(t/5730\)

7=t/5730

40,113=t

Hence, the given sample is 40,113 years .

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Help me pretty pls and asfap

Help me pretty pls and asfap

Answers

evaporation because the water is coming out of the water into the air

What is the identity of a cation solution that burns in a flame test with a mix of red and yellow, but viewed through a cobalt filter the flame is red?

Answers

The identity of a cation solution that produces a mix of red and yellow colors in a flame test, but appears red when viewed through a cobalt filter, can be attributed to the presence of the strontium (Sr) cation.

During a flame test, different metal cations emit characteristic colors due to the excitation of electrons and their subsequent emission of light. Strontium, in particular, is known to produce a vibrant red color in flame tests.

The presence of both red and yellow colors indicates the possibility of multiple metal cations in the solution. While the specific metal responsible for the yellow color is uncertain, it could potentially be sodium or another metal that emits a yellow flame.

When the flame is viewed through a cobalt filter, which absorbs yellow wavelengths of light, the yellow color is filtered out, resulting in only the red color being observed. Since strontium is known for its distinctive red flame color and its emission is not affected by the cobalt filter, it is likely the metal cation responsible for the observed red color. Therefore, based on these characteristics, the identity of the cation solution is most likely strontium (Sr).

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Please help, really need this turned in!

While working in the chemistry lab, you dissolve 2.5g of sodium hydroxide chips into a beaker containing 50mL of water. As you pick up the beaker to add it to a separate solution, you notice the outside of the beaker is very cold. What explains this decrease in temperature?

Question 45 options:

Energy was absorbed when the bonds between sodium and hydroxide ions were broken


Energy was gained when the sodium and hydroxide ions formed new bonds with the water.


Energy was released when the sodium and hydroxide ions came together to form NaOH.


Energy was released when the bonds between sodium and hydroxide ions were broken.

Answers

Answer:

Energy was gained when the sodium and hydroxide ions formed new bonds with the water.

Explanation:

The other answer choices are incorrect because:

Energy was absorbed when the bonds between sodium and hydroxide ions were broken: This is incorrect because breaking bonds requires energy, so energy is absorbed rather than released.

Energy was released when the sodium and hydroxide ions came together to form NaOH: This is incorrect because the reaction being described is dissolution of NaOH in water, not formation of NaOH from its constituent ions.

Energy was released when the bonds between sodium and hydroxide ions were broken: This is incorrect for the same reason as the first option. Breaking bonds requires energy, so energy is absorbed rather than released.

Answer: this correct answer will be energy was released when the sodium and hydroxide ions formed new bonds with the water.

Explanation:

Limiting reactant question!

Limiting reactant question!

Answers

The limiting reactant is N₂O₄ and the mass of N₂ formed from the reaction is 45.7 g (Option C)

How do I determine the limiting reactant?

The limiting reactant can be obtained as illusrated below:

N₂O₄ + 2N₂H₄ -> 3N₂ + 4H₂O

Molar mass of N₂O₄ = 92.02 g/molMass of N₂O₄ from the balanced equation = 1 × 92.02 = 92.02 gMolar mass of N₂H₄ = 32.05 gMass of N₂H₄ from the balanced equation = 2 × 32.05 = 64.1 g Molar mass of N₂ = 28.02 gMass of N₂ from the balanced equation = 3 × 28.02 = 84.06 g

From the balanced equation above,

92.02 g of N₂O₄ reacted with 64.1 g of N₂H₄

Therefore,

50 g of N₂O₄ will react with = (50 × 64.1) / 92.02 = 34.83 g of N₂H₄

From the above calculation, we can see that only 34.83 g of N₂H₄ out of 45.0 g reacted.

Thus, the limiting reactant is N₂O₄

How do I determine the mass of N₂ formed?

The limiting reactant shall be used in this case in order to obtain a maximum yield of N₂. Details below:

92.02 g of N₂O₄ reacted to produce 84.06 g of N₂

Therefore,

50 g of N₂O₄ will react to produce = (50 × 84.06) / 92.02 = 45.7 g of N₂

Thus, the mass of N₂ formed is 45.7 g

Therefore, the correct answer to the question is (Option C)

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When iron is combined with copper (1) nitrate, it produces iron (II) nitrate and
copper. Which of the following could NOT be a mole ratio in this chemical
reaction?

A)1 mole Fe / 2 mole Cu

B)1 mole Fe(NO3)2 / 2 mole Cu

C)2 mole Cu(NO3)2 / 2 mole Fe

D)1 mole Fe(NO3)2 / 1 mole Fe

Answers

Answer:

C)2 mole Cu(NO3)2 / 2 mole Fe

Explanation:

I'm pretty sure.

When iron is combined with copper (1) nitrate, it produces iron (II) nitrate and copper. The following could NOT be a mole ratio in this chemical reaction is:

D) 1 mole Fe(NO₃)₂ / 1 mole Fe

To determine which of the given mole ratios could NOT be part of the chemical reaction between iron and copper(1) nitrate, we need to write the balanced chemical equation for the reaction and then compare it to the given ratios.

The balanced chemical equation for the reaction is:

Fe + Cu(NO₃)₂ → Fe(NO₃)₂ + Cu

A) 1 mole Fe / 2 mole Cu

This mole ratio is consistent with the balanced chemical equation, where 1 mole of Fe reacts with 2 moles of Cu(NO₃)₂ to produce 1 mole of Fe(NO₃)₂ and 1 mole of Cu. So, this ratio could be part of the chemical reaction.

B) 1 mole Fe(NO₃)₂ / 2 mole Cu

This mole ratio is also consistent with the balanced chemical equation, where 1 mole of Fe(NO₃)₂ is produced by reacting 2 moles of Cu(NO₃)₂. So, this ratio could be part of the chemical reaction.

C) 2 mole Cu(NO₃)₂ / 2 mole Fe

This mole ratio is consistent with the balanced chemical equation, where 2 moles of Cu(NO₃)₂ react to produce 2 moles of Fe(NO₃)₂. So, this ratio could be part of the chemical reaction.

D) 1 mole Fe(NO₃)₂ / 1 mole Fe

This mole ratio implies that 1 mole of Fe(NO₃)₂ is produced by reacting with 1 mole of Fe, which is not consistent with the balanced chemical equation. The equation shows that 1 mole of Fe reacts with 1 mole of Cu(NO₃)₂ to produce 1 mole of Fe(NO₃)₂ and 1 mole of Cu. Therefore, this ratio could NOT be part of the chemical reaction.

So, the correct answer is:

D) 1 mole Fe(NO₃)₂ / 1 mole Fe

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1. How do aquatic animals obtain oxygen?
They weather sediment to release oxygen.
They filter the water for dissolved oxygen.
They breakdown seashells and other organic materials.
They separate oxygen from hydrogen in water molecules.
1

Answers

Answer:

the second one filter for dissolved

Explanation:

Answer:

They filter the water for dissolved oxygen.

Explanation:

just took test

The average atomic mass of molybdenum (Mo) is 95.94 amu. Which of the following isotopes must have the highest percent abundance?

Answers

Answer:

The two isotopes of Molybdenum have equal natural abundance

Explanation:

\(\frac{(95.94 + x)}{2}\) = 95.95 amu

x = (95.95 * 2) - 95.94

= 95.96 amu is isotope B, while 95.94amu is isotope A

Using the formula x + (1 - x) = 1

95.96x + 95.94 (1-x) = 95.95

95.96x + 95.94 - 95.94x = 95.95

0.02x = 0.01

x = 0.5

∴ Isotope A and B have equal abundance since 0.5 = 50% abundance.

i hope this was helpful.

why
do real gases
divrate from the
Ideal
gas
law​

Answers

90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you
Because it’s chemistry and it’s the law? Cause I don’t get the question;-;

Draw the products of the following reactions, indicating both regiochemistry and stereochemistry when appropriate.
CH3 1. Hg(OAc)
2, H20 2. NaBHA
• Use wedge and hash bonds ONLY when needed to show reaction stereochemistry. • In cases where there is more than one answer, just draw one.

Answers

The product of the reaction is attached.

The reaction provided in the equation is an electrophilic addition reaction. Electrophilic addition refers to a reaction between an electrophile and nucleophile, adding to double or triple bonds. In the given reaction, alkene is converted into neutral alcohol. As an alkene is treated with the reagent (Hg(OAc)₂, NaBH), the product obtained will be alcohol. This type of reaction is called oxymercuration- demercuration reaction.

In the reaction, the addition of water can occur without acidic conditions. In the presence of reagent mercury (II) acetate cyclic mercurinium ion will form, called . Following this, the reagent will reduce, a reaction called demercuration reaction. Together, this is called oxymercuration- demercuration reaction. As Mercury(II) acetate contains empty d- orbitals it will act as an electrophile and as alkene contains a double bond that will act as a nucleophile. They will form cyclic mercurinium ion and Hg-OAC will be released. In the presence of water hydroxide, the ion will attach on most substituted carbon. In the presence of reagent NaBHsubscript4 reduction will occur and carbon– mercury bond will reduce. This reaction will follow Markovnikov’s rule. Hence, the product of the reaction is attached.

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Draw the products of the following reactions, indicating both regiochemistry and stereochemistry when
Draw the products of the following reactions, indicating both regiochemistry and stereochemistry when

Which portion of a molecule of F2O has partial positive charge?
Question 3 options:

A)

The F atoms

B)

The central O atom

C)

The partial charge on each atom is zero

D)

The partial charge on each atom is negative

Answers

The partial charges on each fluorine atom are negative. Option B) The central O atom is the correct answer. Option B

The partial charges in a molecule are determined by the electronegativity values of the atoms involved. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond. In the case of \(F_2O\), fluorine (F) is more electronegative than oxygen.

Fluorine is the most electronegative element on the periodic table, meaning it has a high ability to attract electrons. Oxygen is also relatively electronegative but less so than fluorine. When fluorine atoms bond with oxygen, the shared electrons will be pulled more towards the fluorine atoms, creating a polar covalent bond.

In \(F_2O\), each fluorine atom will pull the shared electrons towards itself, resulting in a higher electron density around the fluorine atoms. This creates a region of partial negative charge around the fluorine atoms.

Conversely, the oxygen atom will have a region of lower electron density and, therefore, a partial positive charge. This is because the shared electrons spend more time around the fluorine atoms due to their higher electronegativity.

Option B

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i need help!!!!!!!!!!!!

i need help!!!!!!!!!!!!

Answers

Answer:

my take on this, is  32 but wait for others to answer as well  as i may be wrong

Explanation:

Popcorn popping in a pot on the stove is an example of:
answer: conduction radiation convection The Kelvin scale

Answers

Answer:

convection

Explanation:

i believe

The popcorn in the pot pops up because of the conduction process when heated. The solid particles transfers heat energy by conduction mode.

What is conduction?

There are three mode of heat transfer namely, conduction, convection and radiation. Conduction is taking place in solids whereas, convection is taking place in liquids and gases. Radiation is the way of heat transfer through vacuum.

In conduction, the heat energy transfers from one molecule to the other which are closely packed in the solids as in a chain. Thus, heat easily moves through the chain.

In gases and liquids, the hot molecules moves to the surface to make other molecules hot and this flow of molecules make the entire substance hot.

Popcorn is a solid substance thus, able to conduct heat energy. This heat energy leads them to thermal vibration and they pop up from the hot pot. Therefore, it is an example of conduction.

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HQ5.40
Homework Answered Due Today, 11:59 PM
The reaction 3H₂(g) + N₂(g) → 2NH3(g) has an enthalpy of reaction of -92.6 kJ/mol. If 1 g of hydrogen and 2 g of nitrogen are
reacted, how much heat is produced (kJ)?

Answers

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

How do i determine the heat energy produced?

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 3 × 2 = 6 g

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Use the standard normal table to determine the percentage of drinks that can be estimated to take more than 3 minutes to make. Type the correct answer in the box. Use numerals instead of words. Express the answer to the nearest percent. About % of drinks will take more than 3 minutes to make.

Answers

Answer: 15%

Explanation:

We must first calculate the z-score. The z-score is calculated using the following procedures:

Z = (x - ) / Z, where x is the value, we are interested in (3 in this example), and is the distribution's mean, which is taken to be 0 for the conventional normal distribution.

This equation gives us the result: z = (3 - 0) / 1 = 3.

A standard normal table may then be used to calculate the percentage of beverages that require more time to prepare than three minutes. As can be seen in the table, the area to the right of z = 3 is approximately 0.00131. Therefore, 0.13% of drinks will require more time to make than 3 minutes.

The standard score, also known as the observed value or data point, is the departure from or excess over the raw score for an item, reported in standard deviations. Standard scores are good for raw scores that are both higher and lower than the mean.

It may be determined by taking the supplied raw score and removing the population mean from it, then dividing the result by the population standard deviation. The act of converting a raw score into a standard score is known as standardization, but "normalizing" can refer to a variety of other ratio types; see normalization for more information.

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If others adopted similar habits, how might the world of science change?

Answers

Answer:

Explanation:

Smoking a cigarette, snorting cocaine, or drinking yourself into oblivion are all easy habits to adopt because they light up your brain with the neurotransmitter …

Does a reaction occur when aqueous solutions of chromium(III) chloride and silver(I) nitrate are combined

Answers

Answer:

CrCl3(aq) + 3AgNO3(aq) -----> Cr(NO3)3(aq) + 3AgCl(s)

Explanation:

Chromium is higher than silver in the electrochemical series. Recall that ions that are high up in the electrochemical series displace those that are lower in the series.

Hence, when a solution of chromium(III) chloride and silver(I) nitrate are mixed together, the reaction occurs as follows;

CrCl3(aq) + 3AgNO3(aq) -----> Cr(NO3)3(aq) + 3AgCl(s)

A 25 ml sample of 1.2 molar potassium chloride mix with 15 ml of 0.90 molar barium nitrate solution and precipitate reaction occurs twice case LX + BA no3s aqueous bacl2 solid + 2ks what is the practical yield percentage yield mass is 2.45 g

Answers

Percentage yield = (actual yield /
theoretical yield) × 100%
Percentage yield = (2.45 g / 2.81 g) x
100%
Percentage yield = 87.2%
Therefore, the practical yield percentage yield is 87.2%, and the mass of the BaCI2 produced is 2.81 g.


Moles of KCI = volume (in L) X
concentration
Moles of KCI = (25/1000) L x 1.2 mol/L
= 0.03 mol
Moles of Ba(NO32 = volume (in L) X
concentration
Moles of Ba(NO3)2 = (15/1000) L x
0.90 mol/L = 0.0135 mol

Moles of BaCI2 formed = 0.0135 mol
The molar mass of BaCI2 is 208.23 g/ mol, so the mass of BaCI2 produced is:
Mass of BaCI2 = moles of BaC12 x
molar mass of BaCI2
Mass of BaCI2 = 0.0135 mol x 208.23
g/mol
Mass of BaCI2 = 2.81 g

Dolphins have the same arm structure as wolves. What type of evidence for evolution does this represent?


A. DNA

B. vestigial structures

C.homologous structures

D. embryology

Answers

The answer is C, homologous structures

what causes the different crusts to rise and lower?

Answers

Answer:

tectonic plates

Explanation:

The hot mantle below the crust and its high pressure on the crusts. It also created volcanoes. The hot mantle rises then sinks back down cause if the mantle rise due to heat, then it will fall due to cooling.


What is the mass of sodium iodide in 50.0 ml of 2.65 x 10^-2 M Nal (aq)?
0.00877 g
78.8 g
0.0788 g
0.00132 g
0.197 g

Answers

Answer:

correct answer is 0.197 g!

Explanation:

To find the mass of sodium iodide in 50.0 ml of 2.65 x 10^-2 M Nal (aq), you need to first determine the moles of sodium iodide present in the solution. You can do this by using the concentration of the solution and the volume of the solution.

First, convert the concentration of the solution from molarity to moles per liter: 2.65 x 10^-2 M x (1 L/1000 ml) = 2.65 x 10^-5 moles/ml

Next, multiply the moles per milliliter by the volume of the solution in milliliters to find the total number of moles of sodium iodide present: 2.65 x 10^-5 moles/ml x 50.0 ml = 1.325 x 10^-4 moles

Finally, multiply the number of moles of sodium iodide by its molecular weight to find its mass: 1.325 x 10^-4 moles x 149.89 g/mol = 0.197 g. Therefore, the mass of sodium iodide in 50.0 ml of 2.65 x 10^-2 M Nal (aq) is 0.197 g. This means that the correct answer is 0.197 g.

Suppose that the power
used by a light bulb in a circuit is 16 W, and the bulb has a resistance of 4 ohms.
Calculate the current (in amps) flowing through it.

Answers

2 A Explanation:The power flowing in a circuit is given by;P= I^2 RWhere;I= current = the unknownR= resistance= 4 ohmsP= power=16 WI= √P/RI= √16/4I= 2 A

Arrange the following compounds in order of increasing solubility in

water and explain your sequence.

C7H15OH C6H13OH C6H6 C2H5OH​

Answers

Answer:

C6H6<C7H15OH<C6H13OH<C2H5OH​

Explanation:

Organic substances are ordinarily nonpolar. This means that they do not dissolve in water. However, certain homologous series of organic compounds actually dissolve in water because they possess certain functional groups that effectively interact with water via hydrogen bonding.

A typical example of this is alcohol family. All members of this homologous series contain the -OH functional group. This group can effectively interact with water via hydrogen bonding, leading to the dissolution of low molecular weight alcohols in water.

Low molecular weight alcohols are miscible with water in all proportions. This implies that they are highly soluble in water. However, as the size of the alkyl moiety in the alcohol increases, the solubility of the alcohol in water decreases due to less effective interaction of the -OH group with water via hydrogen bonding. This explains the fact that C2H5OH​ is the most soluble alcohol in the list.

C6H6 is insoluble in water since it is purely a hydrocarbon with no -OH group capable of interaction with water via hydrogen bonding.

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