Which occurence would contradict the big bang theory.

Answer:

All cells come from pre-existing cells

Explanation:

Rudolf Virchow, a German Physician, stated the theory that all cells arise from pre-existing cells. He used this theory to explain disease pathology at the cellular level. His work helped clarify that diseases occur not at tissue or organ level, but at the cellular level. This resulted in more accurate diagnosis of diseases by other scientists.

His legacies includes being among the first to use animals in his research, first to name numerous diseases and also the creation of many medical terms still in use today.

The correct answer is A. Refracting telescopes use lenses to bend and focus light to produce an image. One of the main limitations of refracting telescopes is the size of the lens.

As the diameter of the lens increases, the lens becomes thicker and heavier, which can lead to problems such as sagging or flexing, which can distort the image. Additionally, a larger lens can suffer from spherical aberration, which occurs when the outer edges of the lens bend light more than the center, causing blurring and distortion in the image. sag (flex) too much under the weight of the lens and would be too hard to build.

Refracting telescopes use lenses to bend and focus light to produce magnified images. One of the challenges of constructing refracting telescopes is the potential for aberrations, or distortions in the image produced. As the diameter of the lens increases, so does its weight, which can cause the lens to sag or flex, leading to distortion in the image. This is why option A, "sag (flex) too much under the weight of the lens and would be too hard to build," is the correct answer.Option B, "be too thick, and suffer too much spherical aberration," is not entirely accurate. While thicker lenses can suffer from spherical aberration, this is not the primary reason why larger diameter refracting telescopes are not constructed.

Option C, "give too much magnification," is not a reason why larger diameter refracting telescopes are not constructed. Magnification is determined by the focal length of the telescope, not its diameter.

Option D, "have too little chromatic aberration," is also not a reason why larger diameter refracting telescopes are not constructed. Chromatic aberration is a type of distortion caused by the lens separating different colors of light at different angles. While larger lenses can potentially exhibit more chromatic aberration, this is not the primary reason why larger diameter refracting telescopes are not constructed.

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The sum of these losses can typically result in the system's final output being around 85 to 88 percent of the sum of the rated power of the panels. Therefore, option C. 85 to 88 percent is the correct answer.

When calculating the overall efficiency or final output of a photovoltaic (PV) system without storage (batteries), the system's output will typically be around 85 to 88 percent of the sum of the rated power of the panels. This is due to various losses that occur in a PV system, including but not limited to:

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Answer:

1. By streching

2. false

3. building stronger muscles and bones

4. riding your bike

Explanation:

The routine of exercise begins with the usual basic step of stretching the body.

An essential component of a healthy lifestyle is exercise. Exercise can help you cope with stress and prevent health issues while also enhancing energy and strength. It can also help you control your appetite and keep your weight in a healthy range.

Here,

1. The routine of exercise begins with the usual basic step of stretching the body.

2. People don't have to necessarily go to the gym to get exercise, because exercise includes the activities from the basic one to difficult methods. So, you can do some kind of exercise at the home itself. So, the statement is false.

3. An advantage to exercising is building stronger muscles and bones.

4. Riding your bike is an example of exercise.

Hence,

The routine of exercise begins with the usual basic step of stretching the body.

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The beam can be lifted at a distance of approximately 770.27 meters.

The quantity of energy transmitted when a force is applied across a distance is measured by the physical concept of work. A force must be applied to an object in order for it to move in the direction of the force and perform work. The unit of measurement for work is the joule (J), which has a magnitude but no direction.

To find the distance of the beam can be lifted, use the formula:

Work = force × distance × cos(θ)

Distance = 57000 J ÷ (74 N × cos(θ))

= 770.27 meters

Thus, the capacity of beam 770.27 meter.

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A magnetic field is created between these two charged parallel plates. The field indicates a direction from the positive plate to the negative plate.

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NASA estimates that a white dwarf's surface has 350,000 times as much gravity as Earth has.

If the mass is too enormous (more than 1.4 solar masses, known as the Chandrasekhar limit), a white dwarf star will no longer be in equilibrium between gravity and degeneracy pressure.

Sirius B is smaller than Earth at 7,500 miles (12,000 kilometers) in diameter, but it is more denser. A 150-pound individual would weigh 50 million pounds standing on its surface due to the star's strong gravitational field, which is 350,000 times stronger than Earth's.

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The height of mirror to be cleaned is equal to half the height of the man.

Let the length to be cleaned = x and height = h, distance between mirror and man is p.

The ray from his feet is incident  at B.

As it is plane reflection angle RBC = angle IBC

From geometry, angle ARB = θ

From Δ ARB, Tanθ = x/p

From ΔBIC, Tan θ = H-x/p

Equating them,

2x = H

x = H/2

Hence , the height of mirror to be cleaned is equal to half the height of the man.

The law of reflection states that the incident ray, the reflected ray, and the normal to the surface of the mirror, all lie in the same plane.Also, the angle of incidence is equal to the angle of reflection.

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(a) It can be stated that the 10-gram marble hits the ground first because it has a higher acceleration and travels faster.

(b) Both marbles will travel the same distance since their horizontal components of velocity and initial velocity with respect to the ground are the same.

According to the given statement, a 10-gram marble has a speed that is 5 times faster than that of a 100-gram marble. Both marbles roll off the table at the same time. The questions to answer are as follows:

(a) The acceleration due to gravity is constant at 9.8 m/s², according to Newton's Law of Gravitation.

According to the law of physics, heavier objects fall faster than lighter ones, but since the 10-gram marble has a speed that is five times faster than the 100-gram marble, it implies that the 10-gram marble covers more ground in less time than the 100-gram marble as acceleration is directly proportional to the force applied.

The time taken by both marbles to reach the ground is given byt = √(2h/g)where h is the height from which the marbles were dropped, and g is the acceleration due to gravity.

The height from which the marbles were dropped is the same in both cases, so it can be stated that the 10-gram marble hits the ground first because it has a higher acceleration and travels faster.

(b) The range traveled by both marbles is determined by the horizontal component of their velocity. It's worth noting that the horizontal components of their velocities are identical since they were launched from the same height, so there's no advantage for either marble.

The range of a projectile is determined by the formula:

R = u²sin(2θ)/g where R is the range, u is the velocity of the object, θ is the angle of the initial velocity with the horizontal, and g is the acceleration due to gravity.

Since the angle of the initial velocity with the horizontal is the same for both marbles, and their initial velocity is also the same, it can be stated that both marbles travel the same distance.

Therefore, both marbles will travel the same distance since their horizontal components of velocity and initial velocity with respect to the ground are the same.

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Answer:

Matter can be identified through its properties. One clue to helps us identify matter is magnetism. Magnetism is the ability of a material to be attracted by a magnet. Only certain materials are attracted to magnets, like iron, nickel, and cobalt.

Explanation:

we can identify matter by:  physical properties  and

chemical properties

Answer:

Normal = 33.95N

Friction = 19.6 N

Coefficient of friction = 0.58

Explanation:

We can represent the situation as follows:

First, we need to calculate the normal force. Since the box is not moving perpendicular to the incline, the normal force and the weight in that direction has to be equal, then

Fn = mgcos30

Fn = (4kg)(9.8 m/s²)cos30

Fn = 33.95 N

In the same way, the box won't slide when the force of friction is equal to the parallel component of the weight, so

Ff = mgsin30

Ff = (4kg)(9.8 m/s²)sin(30)

Ff = 19.6 N

Additionally, the friction force is equal to

Ff = μFn

Where μ is the coefficient of friction, so solving for μ and replacing the values, we get:

μ = Ff/Fn

μ = 19.6/33.95

μ = 0.58

Therefore, the answers are:

Normal = 33.95N

Friction = 19.6 N

Coefficient of friction = 0.58

Answer:

they do not function appropriately in the tissue or organ they are a part of.

The statement that is true about cancer cells is They do not function appropriately in the tissue or organ they are a part of. Option C is the correct answer.

Cancer cells differ from normal cells in several ways. One of the key characteristics of cancer cells is that they lose their normal function and behavior within the tissue or organ they originate from. Option C is the correct answer.

Normal cells have specific roles and functions within the body, contributing to the overall health and proper functioning of the tissue or organ they are a part of. In contrast, cancer cells undergo a series of genetic mutations that disrupt their normal function. These mutations can lead to uncontrolled cell growth and division, which is a hallmark of cancer. As a result, cancer cells no longer perform the specialized functions of the tissue or organ they are derived from, and they can interfere with the normal functioning of nearby healthy cells.

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The complete question is, "What is TRUE about cancer cells?

a. They are just like normal cells except for the way they function.

b. They form an encapsulated tumor that keeps them in one area of the body

c. They do not function appropriately in the tissue or organ they are a part of.

d. The mutations in cancer cells are caused by environmental factors."

Regardless of their location in the ambulance, portable oxygen cylinders should always be secured properly.

This is to ensure the safety of both the patients and the medical personnel. Here are the steps to secure portable oxygen cylinders:

First, check the cylinder for any damages or leaks. If there are any issues, do not use the cylinder and replace it immediately.

Ensure that the cylinder is stored in an upright position. This helps prevent the oxygen from escaping and maintains the pressure inside the cylinder.

Use cylinder holders or brackets to secure the cylinder in place. These holders should be specifically designed for securing oxygen cylinders in vehicles.

Position the cylinder away from any heat sources or electrical equipment that may cause a fire hazard.
Make sure the cylinder is easily accessible in case of emergencies. Medical personnel should be able to quickly reach and use the oxygen cylinder when needed.

Regularly inspect the cylinder and its attachments for any signs of damage or wear. Replace any damaged parts promptly.

Regardless of their location in the ambulance, portable oxygen cylinders should always be secured properly to ensure the safety of everyone involved.

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Answer:

1.5 m\s Ans ......

Explanation:

Data:

f = 0.5 Hz

w = 3 m

v = ?

Formula:

v = fw

Solution:

v = (0.5)(3)

v = 1.5 m\ s Ans ........

Answer:

1) 2,641,895.5 m

2) 1.85903476 × 10⁻⁹ kg

3) 9.32 C

4) 38.7 kg

Explanation:

1) The gravitational force of attraction between the object and the mass of the Earth is given by the following formula;

\(F} =G\dfrac{M_{1} \cdot m_{2}}{R^{2}} = m_2 \times g\)

Where;

M₁ = The mass of the Earth = 5.97 × 10²⁴

m₂ = The mass of the object

G = The universal gravitational constant

R = The radius of the Earth = 6,378,100 m

g = The acceleration due to gravity = 9.8 m/s²

By comparison, we have;

\(\dfrac{G \cdot M_{1}}{R^{2}} = g\)

When the object is r meters away, g is halved, therefore, we have;

\(\dfrac{G \cdot M_{1}}{r^{2}} = \dfrac{g}{2} =\dfrac{G \cdot M_{1}}{\left (2\times R^{2}\right )}\)

Therefore, r² = 2·R² = 2 × (6,378,100 m)² = 8.13603192 × 10¹³ m²

r = √(8.13603192 × 10¹³ m²) = 9019995.52217 m

The distance of the object from the surface of the Earth = 9,019,995.52217 - 6,378,100 = 2,641,895.52217 m ≈ 2,641,895.5 m

The object needs to be approximately 2,641,895.5 m from the Earth's surface to experience half of the acceleration due to gravity experienced on the Earth's surface

2) The electrostatic force between the charges = k×q²/r²

Where;

q = 1.602 × 10⁻¹⁹ C

r = Distance between the charges

k = Coulomb constant = 8.9875517923 × 10⁹ kg·m³·s⁻²·C⁻²

We have;

The electrostatic force between the charges = 8.9875517923 × 10⁹ × (1.602 × 10⁻¹⁹)²/r²

The gravitational force between the charges = 6.67408 × 10⁻¹¹ × m²/r²

Given that the ratio between the two forces = 1, we have;

(8.9875517923 × 10⁹ × (1.602 × 10⁻¹⁹)²/r²)/(6.67408 × 10⁻¹¹ × m²/r²) = 1

∴ m² = (8.9875517923 × 10⁹ × (1.602 × 10⁻¹⁹)²)/(6.67408 × 10⁻¹¹) = 3.4560102×10⁻¹⁸ kg²

The mass m = √(3.4560102×10⁻¹⁸ kg²) = 1.85903476 × 10⁻⁹ kg

The mass of each particle will be 1.85903476 × 10⁻⁹ kg

3)  F = k×q²/r²

q² = F × r²/k

Which gives;

q² = 50 × 125000²/(8.9875517923 × 10⁹) ≈ 86.93 C²

q = √86.93 ≈ 9.32 C

The charges of each object = 9.32 C

4) \(F} =G\dfrac{m^2 }{r^{2}}\)

r = 0.25 cm = 0.0025 m

F = 0.016 N

G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Therefore;

m² = F·r²/G = 0.016 × (0.0025)²/(6.67408 × 10⁻¹¹) ≈ 1498.334 kg²

m = √(1498.334 kg²) ≈ 38.7 kg

The mass of each object = 38.7 kg.

The Coulomb and gravitational laws together with Newton's second law allow to find the results for the questions are:

    1) The distance where the acceleration of gravity measures half its value on earth is;  r’= 2.64 106 m

    2) The mass of the particle is:   m = 1.86 10-9 kg

    3) The charge of the particles is:   q = 9.32 C

    4) The mass is:   m = 38.7 kg

Part 1

The Universal Gravitational Law says that the force between two objects is proportional to their masses and inversely proportional to the square of their distance

     F =\(-G \frac{Mm}{r^2}\)  

Where F is the gravitational force, G the gravitational constant, M and m the mass of the two bodies and r the distance between them.

They ask to calculate the distance to the point where the acceleration is half that of the gravitation acceleration at the earth's surface.

            a = g / 2

If we use Newton's second law that gives the relationship between the net force, the mass and the acceleration of the body.

          F = m a

Let's substitute

        \(-G \frac{Mm}{r^2} = m \frac{g}{2}\)  

         r² = \(\frac{2GM}{g}\)  

Let's calculate

        r² = \(\frac{2 \ 6.67 \ 10^{-11} \ 5.97 \ 10^{24} }{9.8}\)  

        r = \(\sqrt{81.360 \ 10^{12}}\)  

        r = 9.02 10⁶ m

This is the distance from the center of the earth, the distance measured from the surface of the planet is

       r = R + r '

       r ’= r- R

       r ’= 9.02 10⁶ - 6.378 10⁶

       r’= 2.64 10⁶ m

Part 2

Coulomb's law states that the electric force between two charged bodies is:  

      F = \(k \frac{q_1q_2}{r^2}\)

Where q₁ and q₂ are the charges of the leather and k is the Coulomb constant

They ask what mass the particles must have so that the electrostatic force (Fe) and the gravitational force (Fg) have been equal

Indicate the charges of the particles q₁ = q₂ = 1.602 10⁻¹⁹ C

Let's equalize the two forces

     \(F_e = F_g \\k \frac{q_1q_2}{r^2} = G \frac{m_1m_2}{ r^2 } \\k q^2 = G m^2\)

     \(m = \sqrt{\frac{k}{G} } \ q\)  

     m = \(\sqrt{\frac{8.99 \ 10^9 }{ 36.67 \ 10^{-11}} } \ 1.602 \ 10^{-19}\)

     m =  \(\sqrt{1.3478 \ 10^{20} } \ 1.602 \ 10^{-19}\)  

    m = 1.86 10⁻⁹ kg

Part 3

They indicate that the electrostatic force between two objects is F = 50 N and the distance between them is r = 125 km = 125 103 m, they ask what is the charge of the objects.

Let's use Coulomb's law

        F = \(k \frac{q_1q_2}{r^2}\)  

        q² = \(\frac{F}{k} \ r^2\)  

        q² = \(\frac{50 \ (125 \ 10^3)^2 }{8.99 \ 10^9 }\)  

        q = \(\sqrt{86.93}\)  

        q = 9.32 C

Part 4

Indicate the gravitational force between two objects is F_g = -0.016 N when they are separateda distance  r = 0.25 cm = 0.25 10⁺² m, ask the mass of the bodies.

Let's use the law of universal gravitation.

      \(-G \frac{Mm}{r^2} \\m^2 = - \frac{F}{G} \ r^2\)

Let's calculate

      m² = \(- \frac{(-0.016) }{6.67 \ 10^{-11}} \ (0.25 \ 10^{-2})^2\)

     m = \(\sqrt{1498.33}\)  

     m = 38.7 kg

In conclusion using the Coulomb and gravitational laws together with Newton's second law we can find the results for the questions are:

   1) The distance where the acceleration of gravity measures half its value on earth is;  r’= 2.64 106 m

    2) The mass of the particle is:   m = 1.86 10-9 kg

    3) The charge of the particles is:   q = 9.32 C

    4) The mass is:   m = 38.7 kg

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Decrease

The mathematical relationship between heat, internal energy and work done by the system is given as:

△U = Q + W

where △U is the change in the internal energy

W is the workdone by the system

Q is the heat energy in the system

Since the workdone by the system is negative, when a system does work, there is a depletion in the amount of energy possessed by the system.

Due to this loss of energy by the system as a result of the workdone, the internal energy decreases.

Answer:

Joule (J)

Explanation:

Joule (J) is the SI unit of heat energy (any energy - thermal, electrical, mechanical..).  It is named after the English physicist James Prescott Joule.

The rock produced by the solidification of molten material, either lava or magma, is called igneous rock, which forms from the cooling and solidification of molten material either on the Earth's surface or beneath it.

Igneous rocks are one of the three main types of rocks found on Earth, alongside sedimentary and metamorphic rocks. The formation of igneous rocks depends on factors such as the cooling rate, chemical composition, and presence of gases during the solidification process. This results in a range of textures and mineral compositions in igneous rocks, from fine-grained basalts to coarse-grained granites. Some examples of igneous rocks include pumice, obsidian, andesite, and basalt. The study of igneous rocks is important in understanding Earth's geological history and the formation of mineral resources.

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Answer:

I think its A

Explanation:

Not 100 percent sure tho but they do go up and down in big movements.

Answer:

distance 1 metre

Explanation:

displacement 3 metre

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

The names of meteor showers (Geminids, Leonids, Perseids, Quadrantids) are names of meteor radiant points which are in the apparent direction of the luminous tails of individual meteors seen all over the sky.

The Quadrantids, for example, appear to radiate from the constellation Boötes.

The names of meteor showers (Geminids, Leonids, Perseids, Quadrantids) are names of radiant points which are in the apparent paths of the luminous tails of individual meteors seen all over the sky.

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Yes, the change in enthalpy and change in entropy values can indicate whether a reaction is spontaneous. In general, for a reaction to be spontaneous, the change in Gibbs free energy (∆G) must be negative. The change in Gibbs free energy is related to the change in enthalpy (∆H) and change in entropy (∆S) through the equation: ∆G = ∆H - T∆S, where T is the temperature in Kelvin.

If the change in enthalpy (∆H) is negative (exothermic) and the change in entropy (∆S) is positive (increase in disorder), the reaction will be more likely to be spontaneous. This is because the negative ∆H term contributes to a negative ∆G value, while the positive ∆S term enhances the driving force for the reaction.
However, it is important to note that the temperature (T) also plays a crucial role. At low temperatures, a positive ∆S term can be outweighed by a negative ∆H term, resulting in a positive ∆G and a non-spontaneous reaction. Conversely, at high temperatures, a positive ∆S term can dominate, even if the ∆H term is positive, leading to a negative ∆G and a spontaneous reaction.
In summary, both the change in enthalpy and change in entropy values contribute to determining whether a reaction is spontaneous, but the temperature is also a critical factor.

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20 joule is your answer

Answer:

here

mass m =100kg

distance d=50m

acceleration due to gravity a =10m/s²

work =force×displacement

= ma/d=100×10/50=20joule

Answer:

A

Explanation:

The critical depth in the hydraulic jump can be calculated using the specific energy equation. In this case, with a flow rate of 1.17 m³/s, channel width of 1.7 m, and a depth of 149 mm, the critical depth can be determined.

To calculate the critical depth in the hydraulic jump, we can use the specific energy equation, which relates the flow rate, channel dimensions, and water depth. The equation can be written as:

E = (Q² / (2g)) + (y² / (2g)) + (A² / (P * g))

Where:

E is the specific energy,

Q is the flow rate,

g is the acceleration due to gravity,

y is the water depth,

A is the cross-sectional area of flow,

P is the wetted perimeter of the channel.

In this case, we have a flow rate of 1.17 m³/s, a channel width of 1.7 m, and a depth of 149 mm (or 0.149 m). We need to find the critical depth, which occurs at the hydraulic jump. At the critical depth, the specific energy reaches its minimum value.

To determine the critical depth, we need to set the derivative of the specific energy equation with respect to the water depth equal to zero and solve for y. This will give us the critical depth. However, calculating the critical depth requires knowing additional parameters such as the cross-sectional area and wetted perimeter, which are not provided in the given information. Without these values, it is not possible to calculate the critical depth accurately.

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An electrical circuit refers to the combination of various electrical components that are connected together. - True

An electrical circuit refers to the combination of various electrical components that are connected together in a closed loop, thereby allowing electrons to flow through the circuit. Electrical circuits are essential for the operation of most electronic devices and are made up of a variety of components such as resistors, capacitors, inductors, and transistors.

These components are connected together using conductive materials. The conductive material is generally the copper wire which is used to create the circuit. The flow of electrons through the circuit can be controlled and manipulated using various techniques, such as switching and modulation, to perform a wide range of functions.

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Answer:

the final potential energy of this system is 3U0/10

Explanation:

We are given

charge at left end  and another test charge at point p

Potential energy is given by  = \(\frac{k*Q1*Q2 }{R}\)

where k is electrostatics constant = \(9 *10^9\)

Q1 = first charge , Q2=  test charge

R= distance between charges

potential at point p

U0 = k*Q1*Q2 /3 ⇒ kq1q2 = 3U0 ..............1

now the test charge moves to point R

using Pytahgoreou theorem

R(distance) = \(\sqrt{8^2 + 6^2}\) = 10

New Potential energy

U1 = kq1*q2 / 10

substituting  kq1q2 = 3U0 from 1

U1 = 3U0/10

So this is the final potential energy of this system.

The closest object that can be photographed is 81.63mm and the magnification of this closest object is -0.404.

The focal length of a lens is determined when the lens is focused at infinity. It is obtained from the reciprocal of objects' distance and image distance. Magnification is the enlarged image that is formed over the object size.

From the given,

focal length (f) = 23.5mm

object's distance (u) = 33mm

imagen distance(v) =?

Focal length, (1/f) = 1/u + 1/v

1/v = 1/f - 1/u

    =1/23.5 - 1/33

1/v  = 12.2mm

v = 1/12.2 mm

  = 81.96mm

Thud, the image distance is v= 81.96mm.

Magnification (M) = -v/u

M = -33 / 81.96

  = - 0.402.

Thus, the magnification is -0.402.

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