Which observation indicates that the kinetic-molecular theory has limited use for describing a certain gas? Gas particles are acting like tiny, solid spheres. Gas particles are obeying Newton’s laws of motion. Increasing pressure is reducing the volume of the gas. Increasing pressure is causing a smaller change in gas volume

[Kr]5s²4d10⁵p² represents iodine element. The fundamental components of matter are thought to be the elements.

A material is considered an element if it cannot be divided into two or even more simpler compounds by any kind of chemical process, including the use of light or warmth. For instance, when melting the chunk of gold, it nevertheless melts but remains as the precious metal element. 

The fundamental components of matter are thought to be the elements. There are currently 118 known elements, 94 of which are found in nature while the remaining 24 are created artificially. [Kr]5s²4d10⁵p² represents iodine element.

Therefore,  [Kr]5s²4d10⁵p² represents iodine element.

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Answer:

goggles

Explanation:

...................

Answer:

Strip

Explanation:

Strip mining removes Earth in long strips from the top to reveal the coal. This earth to be removed is known as 'overburden'. The overburden from the first strip is referred to as out-of-pit dumping. Strip mining is a part of surface mining.

Strip mining destroys forests, landscapes, forests and wildlife habitats as trees and plants are removed from the mining area.

Therefore,

this describes the Strip coal mine.

Answer:

strip Mining.

Explanation:

Answer:

B.) More NO would form.

Explanation:

If the amount of N₂ increases, the equilibrium will be out of balance. In order to restore the balance, the reaction will shift to the products side. As such, the amount of NO will increase.

According to Le-chatlier principle, if N₂ is added to the reaction system, then more NO will be produced so as to decrease the amount of N₂.

The Le Chatlier's Principle, also known as the Le Chatlier's Law, is a principle in chemistry that states that when a system at equilibrium is subjected to a change in conditions, such as temperature, pressure, or concentration, the system will adjust its equilibrium position to counteract the change and restore equilibrium.

In other words, if a system is disturbed from its equilibrium state, it will try to minimize the effect of the disturbance by shifting the equilibrium position in a direction that partially offsets the disturbance.

If any substance is added to the system, the equilibrium will shift to the direction in which the added substance is consumed. Hence, as  N₂ is added to the system, it will consumed to give the product NO.

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Answer:D.

Explanation:

The balanced net ionic equation for the reaction that occurs when hydroxylamine (NH2OH) and hydrochloric acid (HCl) are combined can be written as follows: NH2OH + H+ → NH3 + H2O

In this equation, hydroxylamine (NH2OH) acts as a base by accepting a proton (H+) from hydrochloric acid (HCl) to form ammonia (NH3) and water (H2O). The ammonium ion (NH4+) may also be present in the solution as a spectator ion, but it is not directly involved in the net ionic equation as it does not undergo any significant chemical change.

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The tonicity of each solution, with respect to body fluids, is listed below:

a) 0.45 percent NaCl solution: hypotonic solution. Osmolarity: 154 mOsm/L.

b) 50% glucose solution: hypertonic solution. Osmolarity: 1,715 mOsm/L.c) 1.1 percent

KCl solution: hypotonic solution. Osmolarity: 308 mOsm/L.

The tonicity of a solution refers to the concentration of solutes within it. When comparing the tonicity of a solution to that of body fluids, three categories are possible: isotonic, hypertonic, and hypotonic.

Isotonic: When two solutions have the same tonicity, they are isotonic.

As a result, they have an identical concentration of solutes and are in osmotic equilibrium.

Hypertonic: When a solution has a higher tonicity than another solution, it is said to be hypertonic. In this case, water moves out of the hypotonic solution and into the hypertonic solution through osmosis, causing the hypotonic solution to shrink.

Hypotonic: When a solution has a lower tonicity than another solution, it is said to be hypotonic. In this scenario, water moves from the hypotonic solution into the hypertonic solution through osmosis, causing the hypertonic solution to swell.

The osmolarity of a solution is a measure of the concentration of solutes within it.

The normal osmolarity of body fluids is between 290-310mOsm/L.

a) 0.45% NaCl solution: It is hypotonic. The normal osmolarity of body fluids is between 290-310mOsm/L, but the osmolarity of 0.45 percent NaCl solution is only 154 mOsm/L. As a result, the solution is hypotonic.b) 50% glucose solution: It is hypertonic. The normal osmolarity of body fluids is between 290-310mOsm/L, but the osmolarity of a 50% glucose solution is 1,715 mOsm/L.

As a result, the solution is hypertonic.c) 1.1% KCl solution: It is hypotonic.

The normal osmolarity of body fluids is between 290-310mOsm/L, and the osmolarity of a 1.1% KCl solution is 308 mOsm/L. As a result, the solution is hypotonic.

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Answer:

1 H

Explanation:

In chemistry , the chart shows that there is only on Hydrogen ( representing H) therefore the coefficient says two hydrogen and is possible that two hydrogens are used in the formulary for a specific reason

Answer:

Explanation:

imethyl pentane

70.9-gram sample of \(Cl_{2}\) gas will occupy Opton C. 22.4 liters at STP.

To determine the volume occupied by the sample of \(Cl_{2}\) (g) at STP, we can use the ideal gas law equation, PV = nRT

where P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature.

At STP (Standard Temperature and Pressure), the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K).

First, calculate the number of moles of \(Cl_{2}\) (g) using its molar mass. The molar mass  \(Cl_{2}\) is 70.9 grams/mol.

Number of moles (n) = mass (m) / molar mass (M)

n = 70.9 g / 70.9 g/mol

n = 1 mol

Now, we can calculate the volume using the ideal gas law:

V = (nRT) / P

V = (1 mol * 0.0821 L·atm/mol·K * 273.15 K) / 1 atm

V ≈ 22.4 L

Therefore, the correct answer is C. 22.4 L.

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Mass of carbon = 0.1927 g

Mass of hydrogen = 0.02590 g

Mass of nitrogen = 0.1124 g

Mass of phosphorus = 0.1491 g

Mass of Oxygen = 0.8138 - ( 0.1927 + 0.02590 + 0.1124 + 0.1491 ) = 0.3337 g

Moles of C = \(\frac{0.1927}{12.011} = 0.0160 mol\)

Moles of H = \(\frac{0.02590}{1.008} = 0.0257\) mol

Moles of O = \(\frac{0.3337}{15.999} = 0.0209 mol\)

Moles of P = \(\frac{0.1491}{30.974} = 0.00481 mol\)

Moles of N = \(\frac{0.1124}{14.01} = 0.00802 mol\)

So, the empirical formula will be: \(C_{0.0160} H_{0.0257} O_{0.0209} N_{0.00802} P_{0.00481}\)

To make it a whole divide the moles of all elements by 0.00481.

Therefore, \(C_3_3 H_5_5 O_4_3 N_1_7P_1\).

Molecular mass of ATP = 507 g/mol

Empirical formula = 164.063 g/mol

Molecular formula:

\(\frac{507}{164} = 3\)

So, molecular formula is \((C_3_3 H_5_5 O_4_3 N_1_7P_1)_3\) = \(C_1_0 H_1_6 O_1_3 N_5P_3\)

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Answer:

Explanation:

The percentage error of a certain measurement can be found by using the formula

\(P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ \)

From the question we have

actual number = 0.95 g/mL

error = 0.95 - 0.56 = 0.39

We have

\(p(\%) = \frac{0.39}{0.95} \times 100 \\ = 41.0526315...\)

We have the final answer as

Hope this helps you

Answer: 72.07%

Explanation:

P4 + 6 Cl2 --> 4PCl3

Since 123.90g/mol P4 is equivalent to 4(137.33g/mol PCl3)

So, 79.48g P4 = 4(137.33g/mol)(79.48g)/(123.90g/mol)

= 352.38g PCl3 formed

Percentage yield = (253.9/352.38) * 100 = 72.07%

Answer:

As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases

Explanation:

Since the static frictional force between the block and the plane is given by F = μN where

μ = coefficient of static friction and

N = normal force on plane = component of weight of block perpendicular to the plane = Wcosθ where

W = weight of block and

θ = angle of inclined plane

Now, F = μN

F = μWcosθ

Since μ and W are constant, we see that

F ∝ cosθ and cosθ ∝ θ

So, F ∝ θ

Since the static frictional force is directly proportional to the angle the plane makes with the horizontal, when the angle the plane makes with the horizontal is increased, the static friction between the block and the plane increases.

So, As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases

The daughter isotope which is present in the given radioactive decay is ²¹⁸₈₆R.

A daughter isotope is the isotope that remains following the radioactive decay of an original isotope.

In the question parent nuclei is given that ²²²₈₈R, and given chemical equation is:

²²²₈₈R → ²¹⁸₈₆R + ⁴₂He

In the above equation ²¹⁸₈₆R is the daughter nuclei and ⁴₂He is the emitted particle or rays.

Hence ²¹⁸₈₆R is the daughter isotope.

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Answer:

222 88Ra

Explanation:

Sucrose has the molecular  C₁₂H₂₂O₁₁ . if a sucrose sample contains 9.0x10²⁴ atoms of hydrogen, There are 1.4370 x10²⁶ molecules of sucrose are present in the sample.

Sucrose C₁₂H₂₂O₁₁ contain  C₁₂H₂₂O₁₁  Hydrogen

First we should how how many percentage of hydrogen in sucrose

The following formula will be used to determine the percentage of elements present in a molecule:

(Mass of Element / Mass of Molecule) / 100 equals the percentage of an element.

Sucrose's molecular weight is.

= (12)12 + (1)22 + (16)11, 

where 12 is the mass of an atom of carbon.

Hydrogen's atomic mass is 1, thus.

16 = Oxygen Atomic Mass

mass sucrose = 144 + 22 + 176

mass sucrose = 342 g/mol

% of H  =  (22 / 342) ×100    =  6.43 %

to calculate how many molecules sucrose are present we can compare percentage of hydrogen to % sucrose

 % hydrogen         =         % sucrose            

atom hydrogen           molecules of sucrose

6.43 %        =              100%              

9.0x10²⁴          molecules of sucrose    

molecules of sucrose    = 1.4370 x10²⁶ molecules

Therefore,  There are 1.4370 x10²⁶ molecules of sucrose are present in the sample.

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An electrolytic cell is an electrochemical cell that converts chemical energy into electrical energy. A reaction in an electrolytic cell can occur if the setup includes a salt bridge. Additional required components of an electrolytic cell include a cathode, an anode, and a source of direct current (DC).

An electrolytic cell is an electrochemical cell in which chemical reactions are caused by electrical energy. Electrolytic cells have two electrodes, which are electrical conductors where electric current enters or leaves the cell. When the electrode where the current enters the cell is called the anode and the electrode where the current leaves the cell is the cathode.

The electrolyte is an ionic solution that can carry electrical current to the electrodes. In an electrolytic cell, a non-spontaneous redox reaction occurs in which electrical energy is used to force electrons to flow from the anode to the cathode. The redox reaction that takes place in an electrolytic cell is generally non-spontaneous, and it occurs as a result of the supply of electrical energy into the cell from an external source.

As a result, the anode in an electrolytic cell is positively charged, while the cathode is negatively charged. Electrolytic cells are commonly used in industrial processes that require large amounts of electric energy to be converted into chemical energy, such as aluminum production.

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There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, chemical formula can be shown as below.

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound.  Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.

Compound                                                          chemical formula

alkane                                                                  CnH2n+2

alkene with one double bond                            CH\(_2\)=CH\(_2\)

alkene with two double bond                             CH\(_2\)=c=CH\(_2\)

cycloalkane                                                          C\(_6\)H\(_{12}\)

Therefore, chemical formula can be shown as above.

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Answer:

Sorry can't help

Explanation:

Cant help!

Gold is found in various ionic compounds, but one of the most well-known and commercially significant compounds is gold chloride, also known as auric chloride or gold(III) chloride.

The chemical formula for gold chloride is AuCl₃. Gold chloride is an ionic compound composed of gold cations (Au³⁺) and chloride anions (Cl-). It is a yellow-orange solid that is highly soluble in water. Gold chloride can be formed by reacting the gold metal with chlorine gas or by dissolving the gold metal in aqua regia, which is a mixture of concentrated nitric acid and hydrochloric acid.

Gold chloride has several uses and applications. It is commonly used in the field of nanotechnology for the synthesis of gold nanoparticles. These nanoparticles have unique optical, electronic, and catalytic properties, making them valuable in various fields such as medicine, electronics, and materials science.

In addition to gold chloride, gold can also form other ionic compounds with different anions, such as gold bromide (AuBr), gold iodide (AuI), gold sulfide (Au2S), and gold cyanide (AuCN). These compounds have their own unique properties and applications.

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Answer:

Correct me if wrong but its 162g of H₂O

Explanation:

I only did H₂O because you can apply this process for the rest but

Answer:

b

Explanation:

In an ecosystem, the  ozone depleting substance  is chlorofluorocarbon or the CFC's.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the ecosystem through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.There are different types of ecosystems.

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The reaction has not yet started, and the time required for 16.8% of the reactant to remain cannot be calculated using the given rate constant.

Given,The rate constant for this first-order reaction is 0.0830 s−1 at 400 ∘C.A⟶products After how many seconds will 16.8% of the reactant remain-The time taken for a first-order reaction to reach a particular percentage of completion can be calculated using the following formula:t = (ln(A/A₀))/kwhere A₀ is the initial concentration of the reactant, A is the concentration of the reactant at a given time, k is the rate constant, and t is the time elapsed since the reaction began.In this question, we are given the rate constant, k = 0.0830 s−1 at 400 ∘C, and we want to find out the time required for 16.8% of the reactant to remain.Let's assume that the initial concentration of the reactant is 100 units (we can assume any value as it does not affect the percentage of completion).Therefore, the concentration of the reactant remaining after 16.8% of completion would be: A = 16.8 units.Substituting these values in the above formula, we get:t = (ln(16.8/100))/0.0830t = (−1.7918)/0.0830t = −21.58 sThis time value is negative, which means that the reaction has not even started yet. Therefore, we need to check the given percentage of completion.

If it is less than 50%, we can assume that the reaction has not yet started. In this case, the percentage of completion is 16.8%, which is less than 50%.

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Each B-Cl bond in BCl involves the overlap of one of boron's 2p orbitals with one of chlorine's 3p orbitals. This allows the two atoms to share electrons and form a covalent bond.

In BCl, there are two B-Cl bonds formed, each involving the overlap of a boron orbital and a chlorine orbital. Boron has three valence electrons, and its electron configuration is 1s2 2s2 2p1. Chlorine has seven valence electrons, and its electron configuration is 1s2 2s2 2p6 3s2 3p5.
The boron orbital that overlaps with the chlorine orbital is the 2p orbital. This is because boron's valence electron is in the 2p subshell, and it forms covalent bonds by sharing this electron with other atoms. For each B-Cl bond, one of the boron's 2p orbitals overlaps with one of the chlorine's 3p orbitals.
The chlorine orbital that overlaps with the boron orbital is the 3p orbital. This is because chlorine's valence electrons are in the 3p subshell, and it forms covalent bonds by sharing these electrons with other atoms. For each B-Cl bond, one of the chlorine's 3p orbitals overlaps with one of the boron's 2p orbitals.
In summary, each B-Cl bond in BCl involves the overlap of one of boron's 2p orbitals with one of chlorine's 3p orbitals. This allows the two atoms to share electrons and form a covalent bond.

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The Ka for this monoprotic weak acid is 0.001. To solve this problem, we need to use the formula for the pH of a weak acid: pH = pKa + log([A-]/[HA]), where pKa is the acid dissociation constant, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the acid.

First, we need to find the pKa of the weak acid. Since the pH of the 0.001 M HCl solution is the same as the pH of the weak acid solution, we can assume that the [H+] concentration is the same in both solutions. Therefore, the pH of the weak acid solution is -log(0.001) = 3.

Next, we can plug in the given values into the formula: 3 = pKa + log([A-]/[HA]). Since the weak acid is monoprotic, [A-] = [HA], so we can simplify the equation to: 3 = pKa + log(1).

Solving for pKa, we get: pKa = 3.

Finally, we can use the equation for the acid dissociation constant: Ka = 10^(-pKa). Plugging in the value we just found, we get: Ka = 10^(-3) = 0.001.

Therefore, the Ka for this monoprotic weak acid is 0.001.

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Answer:

A calorie is the amount of energy needed to raise the temperature of 1 gram of water 1 degree Celsius. The complete combustion of a large kitchen match, for example, gives you about one kilocalorie of heat