Which object is an example of a mechical wave

The force on the wire will be perpendicular to both the current and the magnetic field.

When a current-carrying wire is placed inside a magnetic field, a force is exerted on the wire due to the interaction between the magnetic field and the current. This force is known as the magnetic force or the Lorentz force.

If the magnetic field is perpendicular to the wire, the force on the wire can be determined using the right-hand rule.

According to the right-hand rule, if you point your right thumb in the direction of the current and extend your fingers, the magnetic field will be directed perpendicular to both your thumb (representing the current) and your fingers.

In this configuration, the magnetic force acting on the wire will be perpendicular to both the current and the magnetic field.

The magnitude of the force can be calculated using the following formula:

F = BIL

Where:

F is the force on the wire,

B is the magnitude of the magnetic field,

I is the current flowing through the wire,

L is the length of the wire segment inside the magnetic field.

Since the force is perpendicular to both the current and the magnetic field, the wire will experience a sideways or perpendicular force that tends to push it in a particular direction.

It's important to note that the direction of the force depends on the direction of the current and the magnetic field. To determine the exact direction, you can use the right-hand rule mentioned earlier or apply the cross product between the current vector and the magnetic field vector.

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Answer:

Burning fossil fuels contributes to climate change.

Fossil fuels are nonrenewable.

Explanation:

Fossil fuels are fuels formed from the remains of dead organic matters that have long been buried under the ground while hydrogen fuel cells are formed from electrochemical reactions.

Fossil fuel burning creates pollution in the environment and some of the pollutants generated contribute to global warming and associated climate change. This is as opposed to fuel cells that generate power through electrochemical reactions and whose products can be converted for other uses.

Also, fossil fuel deposits are finite and non-renewable. Once their deposits become exhausted, there is no way to artificially regenerate them unlike fuel cells.

Answer:

i hope this helps

Explanation:

Answer: The energy to move the fluid is provided by the pressure on the fluid surface.

Explanation:  The frictional losses in the suction pipework and rises in the suction pipework system will reduce the fluid pressure at the pump inlet. If the pump inlet connection is removed the fluid will not flow out of the suction pipework. Hope this helps! :)

Answer:

Explanation:

F = ma, so filling in:

15000 = 30000a and

a = .50 m/s/s

The acceleration of a train is 0.50 \(m/s^{2}\).

Acceleration is the rate of change of the velocity of an object with respect to time.

F = ma

a = F/m

a = 15000/30000

a = 0.50 \(m/s^{2}\)

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Answer:

The velocity vBW of the boat relative to the water is 4.0 m/s, directed perpendicular to the current, as in Figure 3.18.

Explanation:

The boat is perpendicular to the shore. Then the net velocity of the boat with respect to river is 5 m/s. The observer feels like the boat is moving slower than they appear actually.

Relative velocity is velocity of an object measured with respect to other object which can be of stationary or moving with a speed. Thus speed relative to another object is called the relative velocity.

The relative velocity is what's the speed for an observer but it differs from actual velocity. Sometimes it may slower or faster depending on the object with which a we are relating the speed.

Given that the speed of the boat = 4 m/s

speed of river = 3 m/s.

Both are perpendicular and the net velocity of the boat is :

r = √(3² + 4²) = 5 m/s.

Hence, the velocity of the boat relative to the shore will be 5 m/s.

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Answer:

400

Explanation:

We divide time (4.5 hours) and speed (1800 miles)

1800÷45=400

Answer:

D

Explanation:

this is because the formula for frequency is

f = 1/T

and it is a reciprocal

Answer:

Sharpening a knife reduces it's height as a wedge thus giving it more efficiency.

Explanation:

Mechanical advantage refers to the degree or quantity to which a force is increased or amplified by using a tool or a machine.

Mechanical Advantage can be calculated as follows:

Lenght of Incline (LI) / Height of Incline (HI)

Assume I have constructed a hedge with an inclination that run 10 meters from point x to point y (which is the back of a truck. Point y to the floor is 5 meters.

If   LI = 10m and

HI= 5m

The mechanical advantage is given as 10/5 = 2

The angle of incline is also called the effort distance. From our calculations above, by sacrificing horizontal movement, I reduced the amount of effort it would have cost to lift up that object from ground up -  a distance of 5 meters.

Think of a knife as a form of a similar wedge.

The more a knife is sharpening of a knife further reduces its angle of elevation. Thats why it becomes more efficient to use, hence our mechanical advantage.

Cheers

Guava fruit exhibits several adaptive features that contribute to its survival and reproduction in its environment. Here are five adaptive features of guava fruit:

1)Hard, protective outer layer

2)High vitamin C content

3)Numerous seeds

4)Aromatic scent

5)Tolerance to varied environmental conditions

Hard, protective outer layer: The outer layer of guava fruit is tough and thick, providing protection against physical damage and potential threats from herbivores and pathogens.

High vitamin C content: Guava fruit has a high concentration of vitamin C, which acts as an antioxidant. This feature helps the fruit endure exposure to sunlight and prevents oxidative damage caused by free radicals.

Numerous seeds: Guava fruit typically contains numerous small seeds. This adaptive feature increases the chances of successful reproduction, as more seeds are available for dispersal and potential germination.

Aromatic scent: Guava fruit emits a pleasant and distinct aroma. This scent attracts animals, especially birds and insects, which can aid in seed dispersal by consuming the fruit and subsequently dispersing the seeds through their droppings.

Tolerance to varied environmental conditions: Guava fruit is resilient and can tolerate a range of environmental conditions, including high temperatures, drought, and acidic soils. This adaptability enables guava plants to thrive in diverse habitats and ensures the survival of the fruit in different climates and ecosystems.

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Answer:

The drawdown in a confined aquifer under transient conditions can be estimated using the Theis solution for the non-equilibrium radial flow of water. This solution is given by:

s = Q / (4πT) * W(u),

where s is the drawdown, Q is the pumping rate, T is the transmissivity, and W(u) is the well function (also called the Theis function) which depends on the variable u, where:

u = r²S / (4Tt),

where r is the distance from the pumping well and t is the time since pumping began.

Given T = 2500 m²/day, S = 1.0 x 10-3, and Q = 500 m³/day, we can calculate the drawdown at 10 m (r1 = 10 m) and 50 m (r2 = 50 m) for t = 150 days.

For (i) r1 = 10 m:

u1 = r1²S / (4Tt) = (10 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.000667

s1 = Q / (4πT) * W(u1) = 500 m³/day / (4π * 2500 m²/day) * W(0.000667).

For (ii) r2 = 50 m:

u2 = r2²S / (4Tt) = (50 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.01667

s2 = Q / (4πT) * W(u2) = 500 m³/day / (4π * 2500 m²/day) * W(0.01667).

Explanation:

Unfortunately, the well function W(u) cannot be evaluated directly without more specialized knowledge or tools. The well function is related to the exponential integral function, which requires numerical computation. You would typically use a table of values, a calculator with this function, or a computer program to evaluate it. After obtaining W(u), multiply it by the remaining fraction to find the drawdowns.

Answer:

The rock will sink.

Explanation:

The density of water is about 1 g/cm cubed, the rock being more dense will sink in water.

Answer:

Here is the answer.

Explanation:

Answer:

Explanation:

The direction of the static friction force acting on the crate is opposite to the direction in which Craig is trying to push the crate, which is down the ramp. Therefore, the answer is a) Up the ramp.

In the context of this physics question, static friction acts in opposite direction to the force applied. Therefore, when pushing a crate up a ramp, the frictional force will be directed down the ramp.

The force of static friction acts in the direction opposite to the direction in which an object is being pushed or pulled. So, when Craig is trying to push a heavy crate up a wooden ramp, the frictional force is acting against his push. That means it's directed down the ramp. So, the answer is b Down the ramp.

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Answer:

We don't know how much it cost bc u didn't give us a number of how much one person cost or any details but if you add both of the balls together they have 1,400 balls

To calculate the cost of paintballing for Ryan and his dad, we need to know the cost per paintball. Once we have that information, we can multiply it by the total number of paintballs they used (700 balls each).

Let's say the cost per paintball is $0.50.

For Ryan:

Cost for Ryan = Cost per paintball × Number of paintballs used by Ryan

Cost for Ryan = $0.50/ball × 700 balls = $350

For his dad:

Cost for Dad = Cost per paintball × Number of paintballs used by Dad

Cost for Dad = $0.50/ball × 700 balls = $350

Total cost for both of them:

Total Cost = Cost for Ryan + Cost for Dad

Total Cost = $350 + $350 = $700

So, the total cost of paintballing for Ryan and his dad is $700, assuming the cost per paintball is $0.50.

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Answer: An independent variable is the variable which is changed. Experiments are usually published to communicate findings to the scientific community.

Disproving a hypothesis means it cannot be tested again.

Explanation: i hoped that helped.

The force of 30.5 N applied tangentially at the rim of the bicycle wheel with a mass of 44.6 kg and a radius of 0.260 m will result in an acceleration of approximately 0.687 m/s².

The torque, or turning force, applied to the bicycle wheel is equal to the force applied at the rim multiplied by the radius of the wheel, according to the equation τ = Fr, where τ is the torque, F is the force, and r is the radius. In this case, F = 30.5 N and r = 0.260 m.

The moment of inertia, which measures the resistance of the wheel to rotational motion, is given by the equation I = ½mr², where m is the mass of the wheel and r is the radius. In this case, m = 44.6 kg and r = 0.260 m.

Using the torque and moment of inertia, we can apply Newton's second law for rotational motion, which states that τ = Iα, where α is the angular acceleration. Substituting the values we have, we get Fr = ½mr²α.

Rearranging the equation to solve for α, we get α = (2Fr) / (mr²). Plugging in the given values for F, m, and r, we can calculate α as follows:

α = (2 * 30.5 N * 0.260 m) / (44.6 kg * (0.260 m)²)

α ≈ 0.687 m/s²

Therefore, the acceleration of the bicycle wheel's rotation due to the applied force is approximately 0.687 m/s².

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Using the free body diagram, let's determine the scenario the diagram illustrates.

From the free body diagram, we can see that the weight is acting on the object while the tension will be the force which supports the object.

The tension in this case, helps hang the object while the weight is the product of the mass of the object and the force of gravity acting on the object.

Tension can be defined as the pulling force transmitted through a rope or string.

Therefore, the best scenario which is represented by the free body diagram is a sign board supported by two strings.

ANSWER:

A signboard supported by

The particle moves to the right through a potential difference of Vb-Va = 3.20×10^-19 J / q.

The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 3.20×10^-19 J. To determine the direction and potential difference through which the particle moves, we can use the relationship between electric potential difference (V) and electric force (F) on a charged particle.

The electric potential difference between two points is defined as the work done per unit charge to move a particle from one point to the other. The work done on a charged particle by an electric force is given by the equation

W = Fdcos(theta)

where F is the electric force, d is the distance moved by the particle, and theta is the angle between the direction of the force and the direction of the displacement.

In this case, since the particle is only acted upon by the electric force and moves along the x-axis, the angle between the direction of the force and the direction of the displacement is 0, and the work done by the electric force is given by W = Fdx.

Therefore, the potential difference between point a and point b is given by Vb - Va = W/q, where q is the charge of the particle.

Given that the particle's kinetic energy increases by 3.20×10^-19 J and the work-energy principle states that work done on a particle is equal to the change in kinetic energy, we can say that the work done on the particle is equal to 3.20×10^-19 J.

Now, the direction of the force can be determined by the sign of the potential difference, since the electric force is given by

F = -q(dV/dx).

Given that the potential difference is positive, the electric force is negative, meaning that the force is directed opposite to the direction of motion of the particle, therefore the direction of motion is to the right.

Therefore, the particle moves to the right through a potential difference of Vb-Va = 3.20×10^-19 J / q.

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The maximum rate of change of f at the point p(1,π/4) is (π/4) √(3/2) and it occurs in the direction of (1/√17)i + (2/√17)j.

Given function is f(x,y) = sin(xy), and p(1, π/4). We have to find the maximum rate of change of f at point p and the direction in which it occurs. According to the theorem of partial derivatives, the rate of change of f in the direction of a unit vector a = ai + bj is given by

Daf(p) = ∇f(p) . a, where ∇f(p) is the gradient of f at point p.

So, the maximum rate of change of f at point p will occur in the direction of

∇f(p).∇f(p) = ( ∂f / ∂x)i + ( ∂f / ∂y)j

On differentiating f(x,y) = sin(xy) partially with respect to x and y, we get ∂f / ∂x = y cos(xy) , and ∂f / ∂y = x cos(xy)

Therefore, ∇f(p) = (∂f / ∂x)i + (∂f / ∂y)j = y cos(xy) i + x cos(xy) j

Hence, ∇f(1, π/4) = π/4 i + π/4√2 j

Now, we know that the maximum rate of change of f at point p will occur in the direction of ∇f(p).

So, the direction in which the maximum rate of change of f occurs at point p is

(π/4 i + π/4√2 j) / |π/4 i + π/4√2 j| = (1/√17) i + (2/√17) j

And the maximum rate of change of f at point p is

|∇f(p)| = √[(π/4)² + (π/4√2)²] = (π/4) √(1 + 1/2) = (π/4) √(3/2).

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Answer:

2000mg = 2g

5L = 5000mL

16cm = 160mm

1) kg

2) m

3) g

4) mL

5) mm

6) L

7) km

8) cm

9) mg

10) 2g

11) 104000m

12) 4.8m

13) 5600g

14) 8cm

15) 5000mL

16) 0.198kg

17) 0.075L

18) 0.15m

19) 560cm

20) 16mm

21) 25km

22) 6500mg

23) 66mm

24) 0.12g

Answer:

S = V0 t + 1/2 a t^2   standard equation

Where S is the distance traveled and V0 the initial speed

The wavelength of a wave is the distance between two consecutive points on the wave that are in phase.

The wavelength is the distance between two consecutive nodes or two consecutive antinodes.

The first harmonious wavelength on a rope is given by the equation

λ = 2L/ n

where λ is the wavelength, L is the length of the rope, and n is the harmonious number. For the first harmonious, n = 1.

In this case, the length of the rope is L = 4m. Substituting into the equation over, we get

λ = 2( 4m)/ 1

λ = 8m

thus, the first harmonious wavelength on the rope is 8 measures.

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The acceleration of an object due to gravity is known as the acceleration due to gravity, denoted as “g.” The slope of a t2 versus l graph and g are directly related. The acceleration due to gravity can be calculated using the slope of the t2 versus l graph. The slope of a t2 versus l graph is equal to 4π2/g, implying that the slope and g are inversely proportional. How is g related to the slope of the t 2 vs l graph? The period (t) of a simple pendulum can be determined using the length (l) and acceleration due to gravity (g) of the pendulum. The graph of t2 versus l is linear, and the slope of the graph can be calculated using the following formula:slope = Δt2 / Δlwhere Δ represents the change in the quantity. The slope of a t2 versus l graph is proportional to the acceleration due to gravity, denoted by g. The slope of a t2 versus l graph is given by the equation:y = mx + c where y is t2, x is l, m is the slope of the line, and c is the intercept. The slope of the graph can be calculated using the following formula:m = Δy / Δx = Δt2 / ΔlThe slope of the graph is inversely proportional to the acceleration due to gravity. The slope of the graph is given by:m = 4π2 / gThis implies that if the acceleration due to gravity (g) is known, the slope of the graph can be calculated. Similarly, if the slope of the graph is known, the acceleration due to gravity can be calculated. Is the slope equal to g? Explain.No, the slope of the graph is not equal to g. The slope of the graph is equal to 4π2 / g. The slope of the graph is inversely proportional to the acceleration due to gravity. If the acceleration due to gravity is known, the slope of the graph can be calculated using the formula:m = 4π2 / gHowever, the slope of the graph is not equal to the acceleration due to gravity. The slope of the graph is equal to 4π2 / g, which is inversely proportional to the acceleration due to gravity. The acceleration due to gravity can be calculated using the slope of the graph using the following formula:g = 4π2 / m.Therefore, the slope of the graph is not equal to g, but it is inversely proportional to g.

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The slope represents g, the slope of the t2 vs. l graph is always equal to g.

The slope of the t2 vs. l graph represents g. This is the relationship between g and the slope of the t2 vs. l graph. Therefore, the slope is equal to g.

The graph of the time squared against the length is referred to as the t2 vs l graph. The time it takes for an object to fall to the ground is represented by t. The height at which the object was dropped is represented by l. The relationship between the two is expressed by the equation t²=2l/g, where g is the acceleration due to gravity. Therefore, in order to find g, one must first calculate the slope of the t2 vs. l graph. As previously said, the slope of the t2 vs. l graph represents g. As a result, the slope is equal to g.

It is expressed as: Slope = Rise / Run

In the same way, g is calculated by the formula: g = 2L / T². The slope of the t2 vs. l graph and g are inextricably linked. Since the slope represents g, the slope of the t2 vs. l graph is always equal to g.

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Explanation:

The ratio of the areas is the square of the ratio of the radii.

A/A = 3.16² = 9.99

The ratio of the volumes is the cube of the ratio of the radii.

V/V = 3.16³ = 31.6

Answer:Korotkoff Sounds. -tapping sounds created by turbulent blood flow in arm. -pressure is slowly being released from cuff, so systolic pressure is above that of the cuff, but diastolic is still below, so the artery opens in systole and collapses in diastole.

Explanation:

The Absolute Refractory Period is primarily caused by the inactivation of voltage-gated Na+ channels. During this period, the membrane is unable to generate a new action potential regardless of the strength of the stimulus. The Relative Refractory Period is primarily caused by the increased activation and opening of voltage-gated K+ channels, as well as the slow closing of voltage-gated Na+ channels. During this period, a stronger-than-usual stimulus is required to generate a new action potential.

To provide the requested information for each phase of the action potential, we will go through each phase individually:

Neuron at rest:

(A) Relative conductance (g) for Na+ and for K+: The relative conductance for Na+ is low, while the relative conductance for K+ is high.

(D) What types of channels are open?: The voltage-gated Na+ channels are closed, and the voltage-gated K+ channels are closed.

Rising Phase:

(A) Relative conductance (g) for Na+ and for K+: The relative conductance for Na+ is high, while the relative conductance for K+ is low.

(B) Relative voltage driving force for both Na+ and K+ [VM-Ex] and [VM-ENJ]: The voltage driving force for Na+ (VM-Ex) is positive, while the voltage driving force for K+ (VM-ENJ) is negative.

(C) Relative amount of K+ and Na+ current (lk and Iya): The Na+ current (Iya) is large, and the K+ current (lk) is small.

(D) What types of channels are open?: The voltage-gated Na+ channels are open, and the voltage-gated K+ channels are closed.

Falling Phase:

(A) Relative conductance (g) for Na+ and for K+: The relative conductance for Na+ is decreasing, while the relative conductance for K+ is increasing.

(B) Relative voltage driving force for both Na+ and K+ [VM-Ex] and [VM-ENJ]: The voltage driving force for Na+ (VM-Ex) is decreasing, while the voltage driving force for K+ (VM-ENJ) is increasing.

(C) Relative amount of K+ and Na+ current (lk and Iya): The Na+ current (Iya) is decreasing, and the K+ current (lk) is increasing.

(D) What types of channels are open?: The voltage-gated Na+ channels are closed or inactivated, and the voltage-gated K+ channels are open.

Undershoot:

(A) Relative conductance (g) for Na+ and for K+: The relative conductance for Na+ is low, while the relative conductance for K+ is high.

(B) Relative voltage driving force for both Na+ and K+ [VM-Ex] and [VM-ENJ]: The voltage driving force for Na+ (VM-Ex) is negative, while the voltage driving force for K+ (VM-ENJ) is negative.

(C) Relative amount of K+ and Na+ current (lk and Iya): The Na+ current (Iya) is very low or almost absent, and the K+ current (lk) is high.

(D) What types of channels are open?: The voltage-gated Na+ channels are closed or inactivated, and the voltage-gated K+ channels are open.

The Absolute Refractory Period is primarily caused by the inactivation of voltage-gated Na+ channels. During this period, the membrane is unable to generate a new action potential regardless of the strength of the stimulus.

The Relative Refractory Period is primarily caused by the increased activation and opening of voltage-gated K+ channels, as well as the slow closing of voltage-gated Na+ channels. During this period, a stronger-than-usual stimulus is required to generate a new action potential.

Note: It is important to consult relevant sources or materials for specific and accurate information when studying action potentials, as the details and terminology may vary depending on the source and level of study.

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Let's first resolve the two forces into their components as shown in the diagram below: The larger force (617 N) makes an angle of 46° with the horizontal axis.

Therefore, the horizontal component will be given by:

H = 617 cos 46°H = 617 × 0.69H = 425.73 N

The vertical component will be given by:V = 617 sin 46°V = 617 × 0.73V = 450.66 NOn the other hand, the smaller force (411 N) makes an angle of (90° - 46°) = 44° with the horizontal axis. Therefore, the horizontal component will be given by:H = 411 cos 44°H = 411 × 0.72H

= 296.52 N

The vertical component will be given by:V = 411 sin 44°V = 411 × 0.67V = 274.47 N The resultant horizontal component, R will be given by:R = 425.73 + 296.52R = 722.25 N The resultant vertical component, R will be given by:R = 450.66 + 274.47R = 725.13 N The magnitude of the resultant, R will be given by:R² = (722.25)² + (725.13)²R = √(522198.06)R = 722.82 N The angle that R makes with the larger force (617 N) will be given by:θ = tan⁻¹(725.13/722.25)θ = 45.23° Therefore, the magnitude of the resultant is 722.82 N and it makes an angle of 45.23° with the larger force.

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The kinetic energy associated with this impact is 5.53 x \(10^{24}\) J or 1.32 x \(10^{10}\) megatons of TNT (as 1 megaton of TNT yields 4.2 x \(10^{15}\) J). Hence, the kinetic energy of the impact was 1.32 x \(10^{10}\) megatons of TNT.

An explosion at ground level leaves a crater with a diameter that is proportional to the energy of the explosion raised to the power is related to the energy released by the explosion as well as the mass, velocity and the angle of impact.

This question concerns a crater that appeared below Lake Huron in Michigan, and the goal is to find out the kinetic energy that was associated with the impact in terms of megatons of TNT.

Therefore, the relationship between the diameter of the crater and the energy of the explosion is proportional, which implies that an increase in the energy of the explosion will lead to an increase in the diameter of the crater.

Hence, for an explosion of 1 megaton of TNT, the diameter of the crater is 1 km.
Thus, the energy associated with this impact crater is:
E = \((50 \:km / 1\: km)^3\) x (1 MT) x (4.2 x \(10^{15}\) J / 1 MT)
E = \((50)^3\) x (4.2 x \(10^{15}\))
E = 5.53 x \(10^{124}\) J

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Work is equal to energy. Since your braking distance is 10.8 m. you will not stop before you hit the oil spill

Energy is the ability to do work. The work done on an object is tantamount to energy used on the object.

If you are first place in Mario Kart at the moment. Your 5.0 kg Mario Kart is moving at 5.5 m/s when you see an oil spill 10 m ahead. If your maximum braking force is 7.0 N, will you stop before you hit the oil spill? What is your braking distance?

By using the concepts of work and energy, that is,

1/2mv² = F × s

Where

Substitute all the parameters into the formula

1/2 × 5 × 5.5² = 7 × s

75.625 = 7s

s = 75.625/7

s = 10.8 m

Since the calculated distance is greater than the given distance (10 m), you will not stop before you hit the oil spill. And your braking distance will be 10.8 m

Therefore,  you will not stop before you hit the oil spill.

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