Which number is greater . 84 or 9.3

Answer: (9,-5) (1,-3) (-3,-2)

Hope this helps!

The slope intercept form would be y= 1/-4x-11/4

Answer:

m = -1/3

Step-by-step explanation:

Answer:

< C

Step-by-step explanation:

because 23 is the largest number on the triangle so the angle opposite of that side would be C

Answer:

The answer is 25 feet.

Step-by-step explanation:

You have to apply Pythagoras Theorem :

\( {c}^{2} = {15}^{2} + {20}^{2} \)

\( {c}^{2} = 625\)

\(c = \sqrt{625} \)

\(c = 25 \: feet\)

The distribution function of M, FM(-), is given by FM(x) = x, 0 ≤ x ≤ 1.

The probability density function of M is\(fM(x) = n * x^(^n^-^1^)\), 0 ≤ x ≤ 1.

In order to understand the distribution function of M, we need to consider the probability that M is less than or equal to a given value x. Since each Xi is uniformly distributed over (0,1), the probability that Xi is less than or equal to x is x.

For M to be less than or equal to x, all of the random variables Xi must be less than or equal to x. Since these variables are independent, their joint probability is the product of their individual probabilities. Therefore, the probability that M is less than or equal to x can be expressed as the product of n x's: P(M ≤ x) = x * x * ... * x = \(x^n\).

The distribution function FM(x) is defined as the probability that M is less than or equal to x. Therefore, FM(x) = P(M ≤ x) = \(x^n\).

To find the probability density function (PDF) of M, we differentiate the distribution function FM(x) with respect to x. Taking the derivative of \(x^n\)with respect to x gives us \(n * x^(^n^-^1^)\). Since the range of M is (0,1), the PDF is defined only within this range.

The distribution function of M is FM(x) = x, 0 ≤ x ≤ 1, and the probability density function of M is \(fM(x) = n * x^(^n^-^1^)\), 0 ≤ x ≤ 1.

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Step-by-step explanation:

its a photo hope this will help you

Answer:

0.25%

Step-by-step explanation:

Answer:

0.25%

Step-by-step explanation: you`re welcome :)

Answer:

Step-by-step explanation:

The answer is d

There are 41 ways to distribute five distinguishable objects into three indistinguishable boxes.

The boxes are indistinguishable, there are 5 different ways to arrange the number of balls in each box: (5,0,0), (4,1,0), (3,2,0), (3,1,1), or (2,2,1).

There is 1 way to put all 5 balls in one box i.e (5,0,0)

(4,1,0): There are 5 choices for the 4 balls in one of the boxes.

(3,2,0): There are 10 choices for the 3 balls in the boxes.

(3,1,1): There are 10 choices for the 3 balls in one of the boxes, and we can simply split the last two among the other indistinguishable boxes.

(2,2,1): There are 10 options for one of the boxes with two balls, then 3 options for the second box with two balls, and one for remaining for the third.

Therefore the boxes with two balls are indistinguishable, we are counting each pair of balls twice so we have to divide by two.

So there are (10×3)/2=15 arrangements of balls as (2,2,1).

Hence the total number of arrangements for 3 indistinguishable boxes and 5 distinguishable balls is 1+5+10+10+15=41.

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The cost of the apples is 2.9 dollars.

The cost of the bananas is 5.7 dollars.

The total cost is 6 dollars, each apple cost $1.50 each banana cost $.30 and there’s two more bananas then apples.

Therefore,

let

x = number of apples

y = 2x

where

Therefore, using equations,

1.5(x) + y(0.30) = 6

Hence,

where

y = 2x

1.5(x) + 2x(0.30) = 6

1.5x + 0.6x = 6

2.1x = 6

divide both sides by 2.1

x = 6 / 2.1

x = 2.9 dollars

y = 2(2.9) = 5.7 dollars

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Answer:

1.  16 ft

\(\sf 2.\quad \dfrac{29}{99}\)

Step-by-step explanation:

Formula

Area of a square = s²  (where s is the side length)

Given:

Substitute the given area into the formula and solve for s:

\(\sf \implies 256=s^2\)

\(\sf \implies \sqrt{256}=\sqrt{s^2}\)

\(\sf \implies s=\pm 16\)

As distance is positive, the length of one side of Keisha's kitchen is 16 ft.

Converting a recurring decimal to a fraction

Let x equal the recurring decimal:

\(\implies \sf x=0.292929...\)

Create another number with recurring 29s by multiplying the above by 100:

\(\implies \sf 100x=29.292929...\)

To solve these two equations and write x as a fraction, subtract the first equation from the second to remove all the recurring digits after the decimal point:

\(\begin{array}{r r c l}& \sf 100x &= &\sf 29.292929...\\- & \sf x&=& \sf \phantom{..}0.292929...\\\cline{1-4} & \sf 99x&=& \sf29\\\cline{1-4}\end{array}\)

Therefore:

\(\implies \sf 99x=29\)

\(\implies \sf x=\dfrac{29}{99}\)

Therefore:

\(\sf \implies 0.\overline{29}=\dfrac{29}{99}\)

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The density function for the pitch diameter of threads of a fitting is provided as f(x) = (6/√3) * φ(1+x²) for 0 < x < 1, and otherwise undefined. We need to calculate the expected value of X.

In probability theory, the expected value of a random variable represents the average value that we would expect to obtain from repeated measurements. To calculate the expected value of X in this case, we need to integrate the density function f(x) over the range of X and multiply by X.

Given the density function f(x) = (6/√3) * φ(1+x²), where φ denotes the standard normal distribution function, we want to find E(X), the expected value of X. Since the density function is defined only for 0 < x < 1, we will integrate over this range.

Using the definition of expected value, E(X) = ∫(x * f(x)) dx, we can substitute the density function and limits to obtain:

E(X) = ∫[0,1] (x * (6/√3) * φ(1+x²)) dx.

To evaluate this integral, we would need a specific expression for the standard normal distribution function φ(x). Without that information, we cannot calculate the expected value precisely.

In conclusion, to find the expected value of X for the given density function, we would require further details or an expression for the standard normal distribution function φ(x).

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9514 1404 393

Answer:

  (b)  -15

Step-by-step explanation:

The area under the curve from -5 to +5 can be divided into two trapezoids. The one from x=-5 to x=1 has an area of ...

  A = 1/2(b1 +b2)h = 1/2(1 +6)(5) = 17.5

The one from x=1 to x=5 has an area of ...

  A = 1/2(4 +3)(-1) = -3.5

So, the total area from x=-5 to x=+5 is 17.5 -3.5 = 14. This is the amount by which f(x) increases from f(-5) to f(5). That is ...

  f(-5) +14 = -1

  f(-5) = -15

They can complete k(1/x + 1/y) portion of the job if they work together for k hours.

We have,

If Mr. Ng can complete a job in x hours and Mr. Luciano can complete the same job in y hours, their individual rates of work are given by 1/x and 1/y, respectively.

Working together, their combined rate of work is the sum of their individual rates, which is 1/x + 1/y.

If they work together for k hours, the amount of the job they can complete is given by the product of their combined rate and the time they work, which is k(1/x + 1/y).

Thus,

They can complete k(1/x + 1/y) portion of the job if they work together for k hours.

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The rate at which the distance between the tips of the hands are changing at one o'clock is 16.3 mm/h

The rate of change of a function is the rate at which the output variable changes with respect to the input variable.

Let m represent the minute hand, let h represent the hour hand, and let s represent the distance between the minute hand and the hour hand, we get

s² = m² + h² - 2·m·h·cos(S)

The angle, ∠S = 2·π/(12) = π/6

Therefore;

s² = 6² + 5² - 2×6×5×cos(π/6) = 61 + 60·(√3/2)

s = √(61 + 60·(√3/2))

s² = m² + h² - 2·m·h·cos(S)

\(\dfrac{d}{dt} (s^2)= \dfrac{d}{dt} \left(m^2+ h^2-2\cdot m \cdot h\cdot cos(\theta)\right)\)

\(\dfrac{d}{dt} (s^2)= 2\cdot s\cdot \dfrac{ds}{dt}= -2\cdot m \cdot h\times (-sin(\theta)\right))\dfrac{d\theta}{dt}\)

Which indicates that we have;

\(2\cdot s\cdot \dfrac{ds}{dt}= -2\cdot m \cdot h\times (-sin(\theta)\right))\dfrac{d\theta}{dt}\)

\(\dfrac{ds}{dt}=\dfrac{ -2\cdot m \cdot h\times \left(-sin(\theta)\right))\dfrac{d\theta}{dt}} {2\cdot s}\)

\(\dfrac{d\theta}{dt}=-\dfrac{11\cdot \pi}{6}\)

Therefore;

\(\dfrac{ds}{dt}=\dfrac{ -2\cdot m \cdot h\times \left(-sin(\theta)\right))\dfrac{d\theta}{dt}} {2\cdot s}\)

\(\dfrac{ds}{dt}=\dfrac{ 2\times 6 \times 5 \times 0.5)\dfrac{-11\cdot \pi }{6}} {2\times \sqrt{61 + 60\times \dfrac{\sqrt{3}}{2}} } \approx -16.3\)

The rate at which the hour hand is changing is approximately 16.3 mm/h

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She cannot draw an array of 17 counters with three rows.

The given parameters are:

Counter = 17

Rows = 3

An array is represented as:

Array = Rows * Columns

Where Rows and Columns are integers greater than 0

So, we have

3 * Column = 17

Divide by 3

Column = 5.667

Recall that Rows and Columns are integers greater than 0

This means that she cannot draw an array of 17 counters with three rows.

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This gives us a total of 1,583,616 ft-lbs of work required to pump the water out of the pool.

Amount is a numerical value that refers to the total sum of money or other type of payment due. It is used to quantify the size of a transaction, the cost of goods or services, or any other type of financial transaction. Amounts can be expressed in a variety of different currencies, and they can be negative (owing) or positive (owed).

To calculate the amount of work required to pump all the water from the rectangular swimming pool into a drain at the top edge, we must first calculate the volume of the water in the pool. Volume is calculated by multiplying the length, width, and depth of the pool, which in this case is 20 ft x 20 ft x 8 ft = 3,200 cubic ft. Since the pool is filled to 1 ft below the top, the volume of water is 3,200 ft3 - 20 ft3 = 3,180 ft3.

Next, we must calculate the weight of the water, which is the volume multiplied by the weight density of water (62.4 lb/ft3). The weight of the water in the pool is 3,180 ft3 x 62.4 lb/ft3 = 197,952 lbs.

Finally, to calculate the amount of work required to pump the water from the pool into a drain at the top edge, we must multiply the weight of the water (197,952 lbs) by the height of the drain (8 ft). This gives us a total of 1,583,616 ft-lbs of work required to pump the water out of the pool.

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Answer:

x = 2

y = 0

Step-by-step explanation:

Here are the simultaneous equations:

\(y=2-x\\6x+5y=11\\x+2y=2\\2x+y=1\\\)

There are only two unknown values, so only two equations are needed to find the answer. I will use these:

\(y=2-x\\x+2y=2\)

Substitute the first equation into the y in the second equation:

\(x+2(2-x)=2\)

Simplify

\(x+4-2x=2\\x=2\)

Use the value of x to find y in equation 1:

\(y=2-x\\y=2-2\\y=0\)

The interval of convergence for the given power series is (2, 8).

To find the interval of convergence for the given power series. We have the power series:

∑(n=2 to ∞) ((x-5)ⁿ)/(3ⁿ)

To find the interval of convergence, we'll use the Ratio Test. For the Ratio Test, we need to compute the limit:

L = lim (n → ∞) |(a_(n+1)/a_n)|

For our series, a_n = ((x-5)ⁿ)/(3ⁿ). Therefore, a_(n+1) = ((x-5)(n+1))/(3(n+1)). Now, let's compute the ratio:

|(a_(n+1)/a_n)| = |(((x-5)(n+1))/(3(n+1))) / (((x-5)ⁿ)/(3ⁿ))|

Simplify the expression:

|(a_(n+1)/a_n)| = |(x-5)/3|

The series converges if L < 1. So we have:

|(x-5)/3| < 1

Now, we'll solve for x to find the interval of convergence:

-1 < (x-5)/3 < 1

Multiply each term by 3:

-3 < x-5 < 3

Add 5 to each term:

2 < x < 8

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The translations performed are

From the question, we have the following function that can be used in our computation:

f(x) = ln(x)

g(x) = -ln(x + 1) - 3

First, we have the transformation to be:

From f(x) = ln(x) to f(x) = -ln(x)

This means a reflection across the x-axis

Next, we have

From f(x) = -ln(x) to f(x) = -ln(x + 3)

This means the function is translated left by 3 units

Next, we have:

From f(x) = -ln(x + 3) to f(x) = -ln(x + 3) - 3

This means the function is translated down by 3 units

Hence, the translation is 3 units left and 3 units down

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The general solution of the given differential equation (x + 1) dy/dx + (x + 2)y = 2\(xe^{-x}\) is y = \(Cx^{-x}\) + x - 2, where C is a constant.

In order to find the general solution, we can rearrange the equation by dividing both sides by (x + 1):

dy/dx + (x + 2)/(x + 1)y = 2\(xe^{-x}\)/(x + 1).

Next, we notice that the left-hand side can be rewritten as the derivative of y with respect to x times a function of x. This suggests that the equation can be solved using an integrating factor. The integrating factor is given by the exponential of the integral of (x + 2)/(x + 1) with respect to x:

IF = e^{(∫(x + 2)/(x + 1) dx) }  = \(e^{x+2}\)ln|x + 1|.

multiplying both sides of the equation by the integrating factor, we obtain:

\(e^{x+2}\)ln|x + 1|dy/dx + (x + 2)\(e^{x+2}\)ln|x + 1|y = 2xe^(-x)\(e^{x+2}\)n|x + 1|.

Simplifying the equation further, we have:

d/dx (\(e^{x+2}\)ln|x + 1|y) = 2xln|x + 1|.

Integrating both sides with respect to x, we get:

\(e^{x+2}\)ln|x + 1|y = x^2ln|x + 1| + C,

where C is the constant of integration. Finally, solving for y, we obtain the general solution:

y = (\(x^{2}\)ln|x + 1| + C)/(\(e^{x+2}\)ln|x + 1|) = Ce^(-x) + x - 2,

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Answer:

Step-by-step explanation:

Answer:

42 km apart

Step-by-step explanation:

1 cm : 7km scale

6 cm apart on map means 6*7km.

6*7 = 42km apart.

The correct option is A: the probability distribution for the winning ticket:

1          2        3       4      5      6       7       8       9      10

0.10  0.10  0.10  0.10  0.10  0.10  0.10  0.10  0.10  0.10

A frequency distribution that has been idealised is a probability distribution.

Total people = 10 (1 - 10)

One ticket is selected at random from each person.

As the selection is independent events of each other, each will have the same probability.

So,

probability = favourable outcome / total outcome.

probability = 1/10

probability = 0.10.

Thus, the correct option is A: the probability distribution for the winning ticket:

1          2        3       4      5      6       7       8       9      10

0.10  0.10  0.10  0.10  0.10  0.10  0.10  0.10  0.10  0.10

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The solution to the matrix equation [3 2 -1 5] X = [-10 -11 26 -36] is X = [-150/17 -53/17 92/17 -182/17].To solve the matrix equation [3 2 -1 5] X = [-10 -11 26 -36], you need to find the value of matrix X.

Here are the steps to solve the equation:

Step 1: Write the matrix equation in the form AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the constant matrix.

[3 2 -1 5] X = [-10 -11 26 -36]

Step 2: To isolate X, multiply both sides of the equation by the inverse of matrix A.

A^(-1) [3 2 -1 5] X = A^(-1) [-10 -11 26 -36]

Step 3: The inverse of matrix A can be found by using the formula (1/det(A)) * adj(A), where det(A) is the determinant of matrix A and adj(A) is the adjugate of matrix A.

Step 4: Calculate the determinant of matrix A.

det(A) = (3 * 5) - (2 * -1) = 15 + 2 = 17

Step 5: Calculate the adjugate of matrix A.

adj(A) = [5 -1; 2 3]

Step 6: Calculate the inverse of matrix A using the formula (1/det(A)) * adj(A).

A^(-1) = (1/17) * [5 -1; 2 3] = [5/17 -1/17; 2/17 3/17]

Step 7: Multiply both sides of the equation by A^(-1) to isolate X.

[5/17 -1/17; 2/17 3/17] [3 2 -1 5] X = [5/17 -1/17; 2/17 3/17] [-10 -11 26 -36]

Step 8: Simplify the equation.

[1 0 0 0; 0 1 0 0] X = [-150/17 -53/17 92/17 -182/17]

Step 9: The value of X is the right-hand side of the equation.

X = [-150/17 -53/17 92/17 -182/17]

Therefore, the solution to the matrix equation [3 2 -1 5] X = [-10 -11 26 -36] is X = [-150/17 -53/17 92/17 -182/17].

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Using equation 0.3, to obtain a straight-line relationship from which the value of k can be determined, you can plot the natural logarithm (ln) of the content loaded against time. By doing this, you will get a linear graph where the slope represents the rate constant (k).
Equation 0.3 refers to the exponential decay equation, which can be used to model a process in which a quantity decreases exponentially over time. To obtain a straight-line relationship from this equation, we can take the natural logarithm of both sides:

ln(y) = ln(y0) - kt

where y is the quantity at time t, y0 is the initial quantity, k is the decay constant, and ln denotes the natural logarithm. If we plot ln(y) versus t, we will obtain a straight line with slope -k and y-intercept ln(y0).

To obtain the value of k from this line fit, we can use the slope formula:

k = -slope

Therefore, the value of k is simply the negative of the slope of the line fit. This means that the larger the slope (i.e. the steeper the line), the faster the decay process. Conversely, a smaller slope indicates a slower decay process.

In summary, if we have content loaded using equation 0.3, we can plot ln(y) versus t to obtain a straight-line relationship from which the value of k can be obtained. The value of k is related to the resulting parameters of the line fit through the slope of the line, which is simply the negative of k.

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