Which modulus is used to describe a force perpendicular to an object, such as wind blowing against a building

Answer:

First option, third option, fourth option, and the fifth option.

Explanation:

Kinetic energy is energy an object has when it's motion, the greater the speed the greater the kinetic energy. For example, a car moving and increasing in speed is kinetic energy since the object is in motion. If the car stops and parks in a parking lot that is potential energy. Potential energy is the amount of energy an object has when it's at rest or not in motion.

So, the answer for this question is as followed first option or "energy can be stored in the position of an object." Third option or "Energy can be stored in the position of the particles that make up a substance." Fourth option or "Energy exists as movement of the particles of a substance." The last answer will be the fifth option or "Energy is greater in faster-moving particles than in slower-moving particles."

Hope this helps.

Answer:

A. gravitational force always true.

B, C and D could be true under the correct conditions

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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The period of the pendulum, given that the pendulum has an angular velocity about the pivot point of 0.66 radians/sec is 9.52 seconds

First, we shall list out the given parameters from the question. This is shown below:

The period and angular velocity are related according to the following formula:

ω = 2π/ T

Inputting the given parameters, we can obtain the period of the pendulum as follow:

0.66 = (2 × 3.14) / T

0.66 = 6.28 / T

Cross multiply

0.66 × T = 6.28

Divide both sides by 0.66

T = 6.28 / 0.66

T = 9.52 seconds

Thus, we can conclude that the period of the pendulum is 9.52 seconds

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Answer:

the distance between two consecutive crests or troughs

Answer:

Approximately \(3.86\; {\rm N}\) (given that the magnitude of this charge is \(-7.35\; {\rm \mu C}\).)

Explanation:

If a charge of magnitude \(q\) is placed in an electric field of magnitude \(E\), the magnitude of the electrostatic force on that charge would be \(F = E\, q\).

The magnitude of this charge is \(q = 7.35\; {\rm \mu C}\). Apply the unit conversion \(1\; {\rm \mu C} = 10^{-6}\; {\rm C}\):

\(\begin{aligned} q &= 7.35\; {\mu C} \times \frac{10^{-6}\; {\rm C}}{1\; {\mu C}} = 7.35\times 10^{-6}\; {\rm C}\end{aligned}\).

An electric field of magnitude \(E = 5.25\times 10^{5}\; {\rm N \cdot C^{-1}}\) would exert on this charge a force with a magnitude of:

\(\begin{aligned}F &= E\, q \\ &= 5.25 \times 10^{5}\; {\rm N \cdot C^{-1}} \times (-7.35\times 10^{-6}\; {\rm C}) \\ &\approx 3.86\; {\rm N}\end{aligned}\).

Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.

Answer: MAGNITUDE AND DIRECTION OF A VECTOR

Explanation: Given a position vector →v=⟨a,b⟩,the magnitude is found by |v|=√a2+b2. The direction is equal to the angle formed with the x-axis, or with the y-axis, depending on the application.

a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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Answer:

-3525.000 m/s

Explanation:

In a perfectly inelastic collision, the two particles stick together and move with a common velocity after the collision. We can use the conservation of momentum to solve for this common velocity.

The initial momentum of the system is:

p_initial = m1 * v1 + m2 * v2

= (12.000 mg)(55.000 m/s) + (68.000 mg)(-48.000 m/s)

= -282.000 kg·m/s

Here, we convert the masses to kilograms to match the units of velocity.

Since the particles stick together after the collision, their masses add up:

m_final = m1 + m2

= 12.000 mg + 68.000 mg

= 80.000 mg

= 0.080 g

Now, we can use the conservation of momentum to find the final velocity:

p_final = m_final * v_final

where p_final = p_initial and m_final = 0.080 g.

Therefore:

v_final = p_final / m_final

= -282.000 kg·m/s / 0.080 g

= -3525.000 m/s

Answer:

a. 78 degree

Explanation:

According to Snell's Law, we have:

(ni)(Sin θi) = (nr)(Sin θr)

where,

ni = Refractive index of medium on which light is incident

ni = Refractive index of ethyl alcohol = 1.361

nr = Refractive index of medium from which light is refracted

nr = Refractive index of ethyl alcohol = 1.333

θi = Angle of Incidence

θr = Angle of refraction

So, the Angle of Incidence is know as the Critical Angle (θc), when the refracted angle becomes 90°. This is the case of total internal reflection. That is:

θi = θc

when, θr = 90°

Therefore, Snell's Law becomes:

(1.361)(Sin θc) = (1.333)(Sin 90°)

Sin θc = 1.333/1.361

θc = Sin⁻¹ (0.9794)

θc = 78.35° = 78° (Approximately)

Therefore, correct answer will be:

a. 78 degree

The angle relative to the normal interface of the two liquids at which the light is totally reflected is 78 degrees.

From the information given;

According to Snell's Law of refraction;

\(\mathbf{n_1 sin \theta _c = n_2 sin \theta_r}\)

\(\mathbf{1.361 \times sin \theta _c = 1.333 \times sin 90}\)

\(\mathbf{ sin \theta _c =\dfrac{ 1.333 \times sin 90}{1.361}}\)

\(\mathbf{ sin \theta _c =\dfrac{ 1.333 \times 1}{1.361}}\)

\(\mathbf{ \theta _c = sin^{-1} (0.9794)}\)

\(\mathbf{ \theta _c =78.35^0}\)

\(\mathbf{ \theta _c \simeq78^0}\)

Therefore, we can conclude that the angle relative to the normal interface of the two liquids at which the light is totally reflected is 78 degrees.

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Answer:

If theta is equal to 90, then both projectiles strike at the same distance from the projection point and projectiles are in air for the same time interval.

Explanation:

The cone emits a single-frequency sound of 100 Hz and moves in a straightforward harmonic manner. The cone moves a maximum of 2.0 millimetres when it is making a loud sound.

Simple harmonic motion is a particular type of periodic motion of a body that arises from a dynamic equilibrium between an inertial force that is proportional to the acceleration of the body away from the static equilibrium position and a restoring force on the moving object that is directly proportional to the magnitude of the object's displacement and acts towards the object's equilibrium position.

In mechanics and physics, SHM is sometimes used to refer to this motion. If friction or any other energy dissipation is not present, it leads to an oscillation that is represented by a sinusoid and that lasts indefinitely.

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The inductance would be therefore equals to : L'= μ₀ /8π

Ampere's law is a fundamental law of electromagnetism that relates the magnetic field around a closed loop to the electric current passing through the loop. Specifically, it states that the line integral of the magnetic field B around a closed loop is equal to the product of the electric current I passing through the loop and the permeability of free space μ₀:

∮ B · dl = μ₀ I

The goal of this problem is to determine the energy per unit length and then calculate the inductance using the equation. The magnetic field inside of the wire is, using the Ampere's law:2πsB=µ0I s²/a²

B= µ0Is/2π a²

The energy per unit length is:

\(\int\limits^a_0 \int\ \lim_{2\pi \to \ 0}\)〖µ0² I² s²/4π² a⁴ 〗sdsdφ

=µ0I²/16π

Obviously:L'=l/L=μ0/8π

so, Inductance = L/l

= μ₀ /8π

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Answer:

NE DIYON INGILIZ MISIN SEN

a) The kinetic energy of the bullet as it leaves the barrel can be calculated using the equation:

KE = (1/2)mv^2

where m is the mass of the bullet and v is its velocity. Substituting the given values, we get:

KE = (1/2)(0.015 kg)(780 m/s)^2 = 4,556.5 J

Therefore, the kinetic energy of the bullet as it leaves the barrel is 4,556.5 J.

b) According to the work-kinetic energy theorem, the net work done on an object is equal to the change in its kinetic energy. The net work done on the bullet using the equation:

W = ΔKE = KE_f - KE_i

where KE_f is the final kinetic energy of the bullet and KE_i is its initial kinetic energy (which is zero, since it starts from rest). Substituting the given value of KE_f, we get:

W = 4,556.5 J - 0 J = 4,556.5 J

Therefore, the net work done on the bullet is 4,556.5 J.

c) The magnitude of the average net force that acted on the bullet while it was in the barrel can be found using the equation:

W = Fd

where W is the net work done on the bullet, F is the average net force acting on the bullet, and d is the distance over which the force acts (which is the length of the barrel, given as 72 cm = 0.72 m). Substituting the given values, we get:

4,556.5 J = F(0.72 m)

F = 6,327.1 N

Therefore, the magnitude of the average net force that acted on the bullet while it was in the barrel is 6,327.1 N.

d) We can model the bullet as a particle under constant acceleration using the kinematic equation:

v^2 = u^2 + 2as

where u is the initial velocity (which is zero), v is the final velocity (which is 780 m/s), s is the distance traveled (which is the length of the barrel, given as 72 cm = 0.72 m), and a is the constant acceleration of the bullet. Substituting the given values, we get:

(780 m/s)^2 = 2a(0.72 m)

a = 3.41 x 10^5 m/s^2

Therefore, the constant acceleration of the bullet is 3.41 x 10^5 m/s^2.

e) We can find the net force that acted on the bullet during its acceleration using Newton's second law of motion:

F = ma

where m is the mass of the bullet and a is the acceleration of the bullet (which is the value calculated in part d). Substituting the given values, we get:

F = (0.015 kg)(3.41 x 10^5 m/s^2) = 5,115 N

Therefore, the net force that acted on the bullet during its acceleration is 5,115 N.

f) Comparing the results of parts c and e, we can see that the magnitude of the average net force calculated using the work-kinetic energy theorem (6,327.1 N) is greater than the net force calculated using Newton's second law (5,115 N).

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Answer:

3.33 Hz

Explanation:

The first step is to calculate the wavelength

= speed × period

= 13.3 × 0.3

= 3.99

Therefore the frequency of the wave can be calculated as follows

= speed/wavelength

= 13.3/3.99

= 3.33 Hz

In the figure provided, a 25.5° ramp in an airport has luggage sliding down to the owner.  If the ramp is 3.28 m long and the suitcase starts from rest, the time it will take for suitcase A to reach its owner is 1.25 seconds

The diagrammatic representation of the information given in the question is attached in the image below.

From the information given:

We are to find the time required for suitcase A to reach its owner.

To do this, let's compute the free body equation from the diagram.

Thus, both blocks tend to move together since the kinetic friction in A is larger than that of B.

So, summing up both equations, we have:

\(\mathbf{m_1 g sin \theta-m_2 g sin \theta - \mu_k_1 - \mu_k_2= (m_1+m_2)a}\)

Making acceleration a the subject, we have:

\(\mathbf {a = \dfrac{m_1 g sin \theta-m_2 g sin \theta - \mu_k_1 - \mu_k_2}{(m_1 + m_2)}}\)

\(\mathbf {a = \dfrac{(3.70 \times 9.8 \times sin25.5) +(9.69 \times 9.8 \times sin 25.5 )- 0.260 - 0.110}{(m_1 + m_2)}}\)

\(\mathbf {a = \dfrac{(15.610) +(40.88)- 0.260 - 0.110}{(3.70+ 9.69)}}\)

\(\mathbf {a = \dfrac{56.12}{(13.39)}}\)

a = 4.19 m/s²

Using the second equation of motion.

\(\mathbf{S = ut + \dfrac{1}{2}at^2}\)

Recall that the suitcase starts from rest;

∴

\(\mathbf{S = 0(t) + \dfrac{1}{2}at^2}\)

\(\mathbf{S = \dfrac{1}{2}at^2}\)

where;

\(\mathbf{3.28 = \dfrac{1}{2}(4.19) (t)^2}\)

By cross multiply;

3.28 × 2 = 4.19 t²

\(\mathbf{t^2 = \dfrac{3.28 \times 2}{4.19}}\)

\(\mathbf{t =\mathbf{ \sqrt{\dfrac{3.28 \times 2}{4.19}}}}\)

\(\mathbf{t =\mathbf{ \sqrt{1.566}}}\)

t = 1.25 seconds.

Therefore, we can conclude that it took suitcase A 1.25 seconds to reach its owner.

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Answer:

Below

Explanation:

EPE = 1/2 k x^2      for a spring  where x = amount of compression or stretch

 450 = 1/2 (100) x^2

  450 ( 2)/100 = x^2 = 9     so x = 3 m

The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:

k = Q / (A * ΔT * L) = Rth * (A * ΔT)

Reorganizing this equation gives:

Rth = k / (A * ΔT)

The given information in the problem is:

Rate of heat flow (Q) = 14.0 watts

Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C

Temperature difference (ΔT) = 28°C

Substituting these values into the equation, we have:

k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK

So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.

Answer:

The interaction with the highest electrostatic potential energy is:

A +1 and -2 particle separated by a distance of 5 nm.

Explanation:

The electrostatic potential energy between two charged particles depends on the magnitude of their charges and the distance between them. The formula for calculating electrostatic potential energy is:

U = k * (q1 * q2) / d

where U is the electrostatic potential energy, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and d is the distance between them.

In the given options, the interaction between +1 and -2 particles separated by a distance of 5 nm has the highest electrostatic potential energy because the charges have a higher magnitude (compared to other options) and they are close to each other, resulting in a stronger electrostatic force of attraction. The other options either have smaller charges, larger distances, or both, leading to lower electrostatic potential energy.

The vertical acceleration the rocket should have so that his apparent weight is equal to his true weight on earth is 8.2 m/s².

The given parameters;

acceleration due to gravity on moon, g = 1.6 m/s²

The true weight of the rocket is calculated from Newton's second law of motion;

F = ma

Apparent weight on moon = true weight on Earth

mg + ma =  mG

where;

G is the acceleration due to gravity on Earth

m(a + g) = mG

a + g = G

a = G - g

a = 9.8 - 1.6

a = 8.2 m/s²

Thus, the vertical acceleration the rocket should have so that his apparent weight is equal to his true weight on earth is 8.2 m/s².

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The level within a capillary tube with a radius of 0.45 mm rises to a height of 3 cm above the water's surface when submerged in it.

When water saturation decreases, Pnw outside the pore throat is larger than Pw within the pore throat, resulting in a positive pressure (Pc=PnwPw), which is the definition of capillary pressure.

A micron is equal to 0.001 mm in diameter, therefore the capillaries are just big enough for red blood cells to travel through in a single line. Endothelial cells, which also make up the smooth channel surface of the bigger vessels, are the single layer of cells that make up their walls.

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The value added by the baker is $3. The bread's contribution to GDP is the final sale price of the bread, which is $6

In this scenario, each person involved in the production and sale of the bread adds value to the final product. The concept of value added refers to the increase in the market value of a product at each stage of production.

The farmer grows the wheat and sells it for $1. The value added by the farmer is $1.

The miller processes the wheat into flour, increasing its value. The miller sells the flour to the baker for $3, so the value added by the miller is $3 - $1 = $2.

The baker uses the flour to make bread, further adding value to the product. The baker sells the bread to the engineer for $6, so the value added by the baker is $6 - $3 = $3.

The engineer consumes the bread, but since no further economic value is added, there is no additional value added by the engineer.

The bread's contribution to GDP (Gross Domestic Product) is the final sale price of the bread, which is $6. GDP measures the total value of all goods and services produced within a country's borders, and the sale of the bread represents the final output of the production chain.

Overall, the value added at each stage contributes to the final price of the bread, and the final sale price of the bread represents its contribution to GDP.

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The radius of the oil droplet in this experiment is approximately 1.11 x 10^-7 meters.

The Millikan oil-drop experiment was designed to determine the fundamental unit of electrical charge, the charge on a single electron, by observing the behavior of charged oil droplets suspended in an electric field. To calculate the radius of an oil droplet given the electric field strength and the charge on one electron, we can use the following formula:

q = mg / E

where q is the charge on the droplet, m is the mass of the droplet, g is the acceleration due to gravity, and E is the electric field strength.

Assuming that the droplet has only one excess electron and that its weight is balanced by the electric force of the field on that electron, we can write:

q = e

where e is the charge on one electron.

Equating these two expressions for q, we can solve for the mass of the droplet:

mg / E = e

m = eE/g

Next, we can use the density of the oil droplet to calculate its volume and then its radius:

\(V = (4/3)πr^3 = m/ρ\)

\(r = [(3m/4πρ)]^(1/3)\)

where ρ is the density of the oil.

Substituting in the given values, we get:

\(m = eE/g = (1.60 x 10^-19 C)(6.45 x 10^4 N/C)/(9.81 m/s^2) = 1.04 x 10^-14 kg\)

ρ = 0.90 g/cm^3 = 900 kg/m^3

\(r = [(3m/4πρ)]^(1/3) = [(3(1.04 x 10^-14)/(4π)(900))]^(1/3) = 1.11 x 10^-7 m\)

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Answer:

5kgm/s

Explanation:

Given parameters:

Mass of bullet  = 0.005kg

Speed  = 1000m/s

Unknown:

Momentum  = ?

Solution:

Momentum is the amount of motion a body possesses.

Mathematically;

        Momentum  = mass x velocity

Now insert the parameters and solve;

       Momentum  = 0.005 x 1000 = 5kgm/s

Answer:

3.8 x 10^-11N

Explanation:

Given

M=72 kg

R=95 m

G=6.67x10^-11

Equation

Fg= 6.67x10^-11((72kg*72)/(95)^2)

Plug into calculator and get

3.8127756 x 10^-11

Answer:

a. True

Explanation:

Pollution can be defined as the physical degradation or contamination of the environment through an emission of harmful, poisonous and toxic chemical substances.

Aside from toxic pollution, the other types of pollution includes the following;

I. Sediment pollution.

II. Nutrient pollution.

III. Bacterial pollution.

Furthermore, particulate pollution is a form of pollution that is responsible for the degradation of the environment.

Particulate matter is also referred to as particle pollution or atmospheric aerosol particles and it can be defined as a complex microscopic mixture of liquid droplets and solid particles that are suspended in air. Other forms of particle pollution includes space debris and marine debris.

Some examples of particulate pollution are dusts, soot, dirt, smoke, etc.

Answer:a

Explanation:

Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores

Explanation: