Answer:
a delta
Explanation:
The landform produced at the location E where the Mississippi River enters the Gulf of Mexico is a delta.
A delta is a depositional landform where a smaller body of water enters into a larger one.
The Gulf of Mexico contains a larger body of water and as the Mississippi river enters into it, it splits up into many distributaries.
So, this feature is a delta.
How did the approximate speed
of the marbles belore each collision compare
to after each collision?
Answer:
i think this may help you
Explanation:
In an inelastic collision the total kinetic energy after the collision is not equal to the total ... If there are no net forces at work (collision takes place on a frictionless surface ... Momentum is equal to the product of mass and velocity. ... bodies before the collision is equal to the total kinetic energy of the bodies after the collision.
a cube totally submerged in water . calculate the buoyant force acting on this cube . given : g=10N/kg , volume of the cube =24m3 , density of water = 1000 kg/m3?
Answer:
\(F_B=235200\ N\)
Explanation:
Given that,
The volume of the cube, V = 24 m³
The density of water, d = 1000 kg/m³
We need to find the buoyant force acting on this cube when it totally submerged in water. The formula for the buoyant force is given by :
\(F_B=dgV\)
Substitute all the values,
\(F_B=1000\times 9.8\times 24\\\\F_B=235200\ N\)
So, the required force is equal to 235200 N.
URGENT HELP PLS
(a) Find the frequency ratio between the two frequencies f1 = 320 Hz and
½2 = 576 Hz.
S) If we go down from / by an interval of a fourth, find the frequency ratio filfi.
(c) Find the frequency of f3.
The frequency of f3 is approximately 716 Hz.
What is frequency?The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.
a. Given two frequencies, f1 and f2, the frequency ratio is as follows:
frequency ratio= \(\frac{f2}{f1}\)
Inputting the values provided yields:
frequency ratio = \(\frac{576}{320Hz}\) =1.8.
As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.
b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:
frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)= \(\frac{f}{ (f1 / 1.3348) }\)
By dividing the numerator and denominator by 1.3348, we may make this more straightforward:
frequency ratio= (f × 1.33348)/f1
As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.
c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831
Therefore, the frequency of f3 is:
f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz
Therefore, the frequency of f3 is approximately 716 Hz.
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A brick of gold is 0.1 m wide, 0.1 m high, and 0.2 m long. The density of gold is 19,300 kg/m3. What pressure does the brick exert on the table if the brick is resting on its side?
Answer:
The pressure exerted by the brick on the table is 18,933.3 N/m².
Explanation:
Given;
height of the brick, h = 0.1 m
density of the brick, ρ = 19,300 kg/m³
acceleration due to gravity, g = 9.81 m/s²
The pressure exerted by the brick on the table is calculated as;
P = ρgh
P = (19,300)(9.81)(0.1)
P = 18,933.3 N/m²
Therefore, the pressure exerted by the brick on the table is 18,933.3 N/m².
SHOW WORK.
What is the acceleration of the object
whose motion is described by the graph
above?
-0.0 m/s^2
-9.0 m/s^2
-4.5 m/s^2
-4.0 m/s^2
Acceleration is the rate of change of velocity, so if velocity is linear, the acceleration is the slope of its graph.
Here, the line passes through the points (0, 1) and (0.5, 3), so its slope is
(3 m/s - 1 m/s) / (0.5 s - 0 s) = (2 m/s) / (0.5 s) = 4 m/s²
If a planet has an orbital eccentricity equal to 0.70, then its orbit is
Closer to a perfect circle then a straight line
Almost rectangular
A very elongated ellipse
Almost parabolic
If a planet has an orbital eccentricity equal to 0.70, then its orbit is
a very elongated ellipse.What is eccentricity?Eccentricity is a measure of how squashed an ellipse is compared to a perfect circle.
The value of eccentricity ranges from 0 to 1, where 0 represents a perfect circle and 1 represents a parabolic orbit (which is not a closed orbit).
An eccentricity of 0.70 indicates that the planet's orbit is significantly elongated and not close to a perfect circle.
Therefore, the correct answer is - A very elongated ellipse.
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A straight wire, labeled as Wire A, lies horizontally on a tabletop and is oriented to run north-south. A conventional current of 1.0 amperes runs in the wire directed towards the north. A second wire, labeled as Wire B, is also laid on the tabletop oriented north- south. Which of the following statements is true?
a. If Wire B carries no current in it and lies to the left (west) of wire A, then it will experience an attractive force to the right towards wire A).
b. If Wire B carries a northward conventional current and lies to the left (west) of wire A, then it will experience an attractive force to the right (towards Wire A).
c. If Wire B carries a northward conventional current and lies to the right (east) of wire A, then it will experience a repulsive force to the right (away from Wire A).
d. If Wire B carries a southward conventional current and lies to the left (west) of wire A, then it will experience a repulsive force to the left (away from Wire A).
Answer:
b. If Wire B carries a northward conventional current and lies to the left (west) of wire A, then it will experience an attractive force to the right (towards Wire A).
d. If Wire B carries a southward conventional current and lies to the left (west) of wire A, then it will experience a repulsive force to the left (away from Wire A).
Explanation:
Two parallel conductors experience attractive force when the current flowing in the conductors are in the same direction.
Also two parallel conductors experience repulsive force when the current flowing in the conductors are in opposite direction.
Therefore, b and d are the correct options.
b. If Wire B carries a northward conventional current and lies to the left (west) of wire A, then it will experience an attractive force to the right (towards Wire A).
d. If Wire B carries a southward conventional current and lies to the left (west) of wire A, then it will experience a repulsive force to the left (away from Wire A).
0.55 kg mouse moving E at 60m s or a 900 kg elephant moving E at 0.03m Which has the most momentum?
Answer:
the mouse
Explanation:
the mouse has a momentum of 33 m kg/s
while the elephant has a momentum of 27 m kg/s
i found this out using p=mv
Which formula is used to find an objects acceleration
Answer:
a=∆v/∆t
Explanation:
The definition of Acceleration is the change in velocity in a given time. So this means you first calculate ∆v (Change in velocity), and you calculate ∆t which is the time taken to apply that change in velocity. Then you find a= ∆v/∆t. This gives us the equation of Acceleration.
Answer:
C. a=∆v/∆tExplanation:
If the velocity of a particle is nonzero, can the particle’s acceleration be zero? Explain.
If a particle's velocity is nonzero, then its acceleration can be zero, because acceleration is the rate of change of velocity. If the velocity is constant and does not change, the acceleration is zero.
What is acceleration?The rate of change of an object's velocity with respect to time is defined as acceleration. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.
Because velocity is both a speed and a direction, there are only two ways to accelerate: modify your speed or your direction—or both.
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The wave equation says that a waves __ is equal to its wavelength times is frequency.
Answer:
speed
Explanation:
The wave equation says that a waves speed is equal to its wavelength times is frequency.
A vector has the components Ax=29 m and Ay= 18 m. What is the magnitude of this vector? What angle does this vector make with the positive x axis?
The magnitude of the vector is approximately 35.85 m.
The angle that this vector makes with the positive x-axis is approximately 32 degrees.
What is the magnitude of this vector?
To find the magnitude of the vector with components Ax=29 m and Ay=18 m, we use the Pythagorean theorem:
|A| = √(Ax^2 + Ay^2)
|A| = √(29^2 + 18^2)
|A| = √(841 + 324)
|A| = √1165
|A| = 34.13 m
To find the angle that this vector makes with the positive x-axis, we can use the inverse tangent function:
θ = tan^-1(Ay/Ax)
θ = tan^-1(18/29)
θ = 31.82 degrees
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5. The baseball player does 1234 J of work when hitting a baseball into left field.
Assuming the baseball landed 100 m away from home plate, how much force did
the player use to hit the ball?
Answer:
12.34 N
Explanation:
Work Done = Force × Displacement
1234 = Force × 100
Force = 12.34N
a man lifts up a 1500 lb car with his hands what is the mass of the car in kilograms 2.2 lbs=1kg
When you drop a 0.37 kg apple, Earth exerts
a force on it that accelerates it at 9.8 m/s² to-
ward the earth's surface. According to New-
ton's third law, the apple must exert an equal
but opposite force on Earth.
If the mass of the earth 5.98 x 10²4 kg, what
is the magnitude of the earth's acceleration
toward the apple?
Answer in units of m/s².
The earth is accelerating toward the apple at a rate of 6.2 × 1025 m/s2.
How is this acceleration determined?The apple weighs m = 0.37 kg.
The apple's speed when it approaches the earth's surface is 9.8 meters per second.
Earth's mass, M, is 5.98 × 1024 kg.
Using Newton's Second Law of Motion, we may now:
The strength of the force exerted by Earth on the apple is,
F = ma
⇒ F = 0.37 × 9.8
⇒ F = 3.626 N
We are informed that the apple must exert an equal but opposite force on Earth in accordance with Newton's third law of motion.
Therefore, the force exerted by the apple on Earth will be of the following magnitude:
F = 3.626 N
Let "A" be the acceleration of the earth relative to the apple in m/s2.
Thus,
The following will be used to determine how quickly the earth is moving toward the apple:
F = MA
⇒ 3.626 = [5.98 × 10²⁴] × A
⇒ A = 3.626 / [5.98 × 10²⁴]
⇒ A = 0.606 × 10⁻²⁴
⇒ A = 6.06 × 10⁻²⁵ m/s²
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The form of energy found in moving objects is ___??
Answer:
kinetic energy
Explanation:
It is kinetic energy because it is an energy in motion. In order words it is an energy which the body or object moves.
A detailed graph of angular velocity versus time is shown. What is the angular displacement, in radians, during the time interval from 0.75 s to 14.2 s?
0.116 rad/s is the angular speed in radians, during the time interval from 0.75 s to 14.2 s
ω=Δθ/Δt
Δθ= 90° = 1.571rad
Δt=13.45
ω=1.571/13.45
ω=0.116 rad/s
The rate of change of angular displacement, or the angle a body travels along a circular path, is the definition of angular speed. Calculating angular speed involves dividing the quantity of rotations or revolutions made by a body by the amount of time required. Omega is a Greek letter that represents angular speed. The SI's angular speed unit is rad/s.
As is well known, angular speed is determined by dividing the rate of displacement change by the time. As a result, the angular speed equation is = /t. Despite the procedure stated above, a different and more well-liked formula is used to determine angular speed in competitive testing. As ω = θ/t
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PLEASE HELP!!!!
Do you think we will ever be able to get rid of our dependency on fossil fuels? Why or why not?
Answer:Probably because we've been so dependent on them,and we took to long to find new reusable resources.
Explanation:
I don't know what I'm doing wrong I just can't seem to get the answers right. Help please.
The current and potential difference in the lumped element model of electrical circuits are dealt with by Kirchhoff's circuit laws, which are two equalities. German scientist Gustav Kirchhoff published the first account of them in 1845. This was done before James Clerk Maxwell and generalized Georg Ohm's work.
Because the sum of the currents entering and leaving the junction is equal, Kirchhoff's first law is based on the conservation of charge. The algebraic sum of potential drops in a closed circuit must equal zero, according to Kirchhoff's second law. Therefore, it is based on energy conservation.
A stream of charged particles—such as electrons or ions—moving through a conductor for electricity or into empty space is known as an electric current. It is determined by measuring the net rate of electric charge flow through a surface or into a control volume.
The amount of resistance in an electrical circuit represents the resistance to current flow. The Greek letter omega (Ω), which stands for resistance, represents ohms.
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03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.
Hooke's Law can be given as follows sometimes:
The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:
F = -kx
Where, F = Restoring force of a spring (Newtons, N)
k = Spring constant (N/m)
x = Displacement of the spring (m)
The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.
Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.
The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.
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a body of mass 8 kg is acted upon by the two perpendicular forces of 16 Newton and 12 Newton find the magnitude and direction of the acceleration of the body
body of mass m is 5 kg
R=
(8)
2
+(−16
2
)=
64+36
=10N
θis angle made by force of 8 N
θ=tan
−1
(−6/8)=−36.87
0
the negative sign indicates theta clockwise direction respect to the force of magnitude 8N
force is m X a
a=f/m=10/5=2ms
−2
A 1.0-kg object moving 9.0 m/s collides with a 2.0-kg object moving 6.0 m/s in a direction that is perpendicular to the initial direction of motion of the 1.0-kg object. The two masses remain together after the collision, and this composite object then collides with and sticks to a 3.0-kg object. After these collisions, the final composite (6.0-kg) object remains at rest. What was the speed of the 3.0-kg object before the collisions
Answer:
v₃ = - (3 i ^ + 4 j ^) m / s
v₃ = 5 m / s, θ = 233º
Explanation:
This is a momentum problem. Let us form a system formed by the three objects so that the forces during the collisions have been internal and the moment is conserved.
Let's start working with the first two objects. As each object moves in a different direction let's work with the components in an xy coordinate system
X axis
initial instant. Before the shock
p₀ₓ = m₁ v₁₀ + 0
final instant. After the crash
p_{fx} = (m1 + m2) vₓ
the moment is preserved
p₀ₓ = p_{fx}
m₁ v₀₁ = (m₁ + m₂) vₓ
vₓ = \(\frac{m_1}{m_1+m_2} \ v_{o1}\)
Y axis
initial instant
p_{oy} = 0 + m₂ v₀₂
final moment
p_{fy} = (m₁ + m₂) v_y
the moment is preserved
p_{oy} = p_{fy}
m₂ v₀₂ = (m₁ + m₂) v_y
v_y = \(\frac{m_2}{m_1 +m_2 } \ v_{o2}\)
We already have the speed of the set of these two cars, now let's work on this set and vehicle 3
X axis
initial instant
p₀ₓ = (m₁ + m₂) vₓ + m₃ v₃ₓ
final instant
p_{fx} = 0
p₀ₓ = p_{fx}
(m₁ + m₂) vₓ + m₃ v₃ₓ = 0
v₃ₓ = \(- \frac{m_1+m_2 }{m_3} \ v_x\)
Y Axis
initial instant
p_{oy} = (m₁ + m₂) v_y + m₃ v_{3y}
final moment
p_{fy} = 0
p_{oy} = p_{fy}
(m₁ + m₂) v_y + m₃ v_{3y} = 0
v_{3y} = \(- \frac{m_1+m_2}{m_3} \ v_y\)
now we substitute the values of the speeds
v₃ₓ = \(- \frac{m_1+m_2}{m_3} \ \frac{m_1}{m_1+m_2} \ v_{o1}\)
v₃ₓ = \(- \frac{m_1}{m_3} \ v_{o1}\)
v_{3y} = \(- \frac{m_1+m_2}{m_3} \ \frac{m_2}{m_1+m_2} \ v_{o2}\)
v_{3y} = \(- \frac{m_2}{m_3} \ v_{o2}\)
let's calculate
v₃ₓ = - ⅓ 9
v₃ₓ = - 3 m / s
v_{3y} = - ⅔ 6
v_{3y} = - 4 m / s
therefore the speed of vehicle 3 is
v₃ = - (3 i ^ + 4 j ^) m / s
It can also be given in the form of modulus and angles using the Pythagorean theorem
v₃ = \(\sqrt{v_{3x}^2 + v_{3y}^2}\)
v₃ = \(\sqrt{3^2+4^2}\)
v₃ = 5 m / s
let's use trigonometry for the angle
tan θ' = \(\frac{v_{3y}}{v_{3x}}\)
θ' = tan⁻¹ (\frac{v_{3y}}{v_{3x}})
θ' = tan⁻¹ (4/3)
θ' = 53º
That the two speeds are negative so this angle is in the third quadrant, measured from the positive side of the x axis
θ = 180 + θ'
θ = 180 +53
θ = 233º
Need ASAP!! An object lies motionless on a rough inclined surface .
Answer:
yes
Explanation:
yes
Answer:
that's true
Explanation:
if the rough inclined plane was rough enough than it would be true
HELP!!!
How does Dr. Hewitt define Potential Energy?
•Extra energy
•Energy that might or might not be there
•Energy of motion
•Energy of position
•Potent energy
Answer:
energy of position
Explanation:
I think that is the answer
64) A popular make of dental drill can operate at a speed of 42,500 rpm while producing a torque of 3.68 oz ·in. What is the power output of this drill? Give your answer in watts.
The power is given by:
\(P=\tau\omega\)before we calculate we need to convert the values given to the correct units.
One rpms is equal to 0.10472 rad/s; and 1 oz*in is equal to 0.0070615518333333 N*m; with this convertion in mind we have:
\(\begin{gathered} P=(42500\cdot0.10472)(3.68\cdot0.0070615518333333) \\ =115.66 \end{gathered}\)Therefore the power is 115.66 W
If the greenhouse effect is natural, then why is today's climate change a bad thing?
A.)A small increase in greenhouse gas concentration can have a large effect of increased warming.
B.)Humans have altered a natural process and exaggerated changes that might normally occur over millions of years.
C.)Once released into the atmosphere, greenhouse gases remain potent for many years, making it difficult to reverse the process.
D.)Abrupt changes to the climate system may have unintended outcomes that may pose challenges for societies, like more extreme weather, spread of diseases, a decline in marine life, or an alteration of ocean circulation patterns.
E.)All of these
Answer:
B.)Humans have altered a natural process and exaggerated changes that might normally occur over millions of years.
Explanation:
While the greenhouse effect is natural and in fact, helps maintain a climate suitable for life as we know it, humans have altered a natural process. A small change in the amount of greenhouse gases in the atmosphere has a large and long-lasting effect. Furthermore, humans have changed the composition of the atmosphere over a short time span, and the resulting warming us many times faster than natural changes. We are already seeing consequences like heat waves, melting sea ice, rising sea level, increased wildfires, and increases in extreme weather.
A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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100 points easy physics
A feather (mass = 0.1kg) and a bowling ball (4.5kg) will both fall at the SAME rate on Earth (g=9.8m/s2) if there is no air resistance. How much force does each item have if it is falling due to the acceleration of gravity?
use,
F = mg
For feather,
F = 0.1*9.8
F = 0.98N
For bowling bowl,
F = 4.5*9.8
F = 44.1N
Therefore the forces for the feather and the bowling bowl are 0.98N and 44.1N respectively.
The amount of force each item has is 0.98 Newton and 44.1 Newton respectively.
Given the following data:
Mass of feather = 0.1 kgMass of bowling ball = 4.5 kgAcceleration due to gravity = 9.8 \(m/s^2\)To find how much force each item have if it is falling due to the acceleration of gravity, we would apply Newton's Second Law of Motion:
Mathematically, Newton's Second Law of Motion is given by this formula;
\(Force = mass\) × \(acceleration\)
Substituting the given parameters into the formula, we have;
For the feather:
\(Force = 0.1\) × \(9.8\)
Force = 0.98 Newton
For the bowling ball:
\(Force = 4.5\) × \(9.8\)
Force = 44.1 Newton
Therefore, the amount of force each item has is 0.98 Newton and 44.1 Newton respectively.
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This mathematical model describes the changes that occur in a sample of
water as its temperature increases. Based on this model, how do you expect
the motion of the molecules in ice to compare with the motion of molecules
in water vapor
200°C
Vaporization
150°C
melting
100°C
Temperature (°C)
water vapor
50°C
liquid water
0°C
-50°C
10
20
ice
30 40
Time (min)
50
60
70
O
A. This model does not provide enough data to answer the question
B. I expect the molecules in water vapor to move more quickly than
the molecules in ice.
a
C. I expect the molecules in ice to move more quickly than the
Answer:
I think it might be (a) if that helps
The wave in the liquid travels towards the surface at an angle. Fig 9.2 shows the centres of the compressions of the sound wave in liquid. Some compressions shown have reached the liquid-air boundary. The parts of these compressions in the air are not shown on Fig 9.2 These waves are also reflected at the boundary. Draw on the diagram the reflected wavefronts.
The reflected sound wavefronts at the given boundary are waves that have bounced off a surface and changed direction.
The reflected sound wavefront is shown in the attachment.
What are reflected wavefronts?A reflected wavefront is a wavefront that has bounced off a surface and changed direction. When a wave, such as a light wave or sound wave, encounters a surface, some of the wave energy is reflected back in the opposite direction.
An example of reflected sound wavefronts in water can be seen in underwater sonar imaging.
In sonar imaging, a sound wave is emitted from a source and travels through the water. When the sound wave encounters an object, some of the wave energy is reflected back toward the source.
Reflected wavefronts play an important role in many areas of science and engineering, such as optics, acoustics, and electromagnetism. They are used to model the behavior of waves in complex systems and to design and optimize devices such as mirrors, lenses, and antennas.
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