Which is the goal of technology?


to expand comprehension

to make life easier

to apply knowledge

to improve communication
pls help

Mona's conclusion that convection is the main way that energy escapes from the water when there is no lid may or may not be a good conclusion, depending on the context and information provided.

Convection is a process of heat transfer that involves the movement of fluids (in this case, the water) due to differences in temperature. It occurs when warmer portions of the fluid rise and cooler portions sink, creating a circulating flow.

To determine if Mona's conclusion is valid, additional information is needed. Factors such as the presence of other heat transfer mechanisms (such as radiation or evaporation), the specific setup of the experiment, and the conditions under which the observations were made are essential.

If Mona's experiment only considered convection as the primary mechanism for energy escape and excluded other factors, her conclusion might be incomplete or inaccurate. To draw a more comprehensive conclusion, it is necessary to consider other potential heat transfer mechanisms and perform further investigations or provide additional supporting data.

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Answer:

it's 9m

Explanation:

Answer:

9m

Explanation:

edge2o2o

The net force on an object will be equal to 27.1 N. The net force is in the right direction.

Force can be described as the influence that changes the state of the body of motion or rest. The SI unit of force is Newton and force is a vector quantity. Force can change the direction as well as the speed of the moving object.

The force can be calculated from the product of the mass (m) and acceleration (a) of an object. The mathematical equation of the second law of motion for force is written as:

F = ma

The force P is acting in the left direction or pulling the object in the left direction. The force Q pulls the object in the right direction.

The net force  \(=F_{P} -F_{Q}\) = 12.5 - 39.6

The net force = 27.1 N   in the right direction.

Therefore, the net force of 27.1 N  on the object is pulling the object in the right direction.

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Your question is incomplete, most probably complete question was,

An object is pushed to the left with a force of P and pushed to the right with a force of Q. where P = 12.5 and Q = 39.6.

What is the net force on the object? If the net force is to the right, enter a positive value and if it is to the left, enter a negative value.

Answer:

10) The distance between the archer and the tree is 50.074 meters.

11) The speed of the banana when it hits the water is approximately 13.554 meters per second.

Explanation:

10) The arrow experiments a parabolic motion, which is the combination of horizontal motion at constant velocity and vertical uniform accelerated motion. In this case we need to find the horizontal distance between the archer and the tree, calculated by the following kinematic equation:

\(x = x_{o} +v_{o}\cdot t \cdot \cos \theta\) (Eq. 1)

Where:

\(x_{o}\) - Initial position of the arrow, measured in meters.

\(x\) - Final position of the arrow, measured in meters.

\(v_{o}\) - Initial speed of the arrow, measured in meters per second.

\(t\) - Time, measured in seconds.

\(\theta\) - Launch angle, measured in sexagesimal degrees.

If we know that \(x_{o} = 0\,m\), \(v_{o} = 65\,\frac{m}{s}\), \(t = 0.85\,s\) and \(\theta = 25^{\circ}\), the horizontal distance between the archer and the tree is:

\(x = 0\,m + \left(65\,\frac{m}{s}\right)\cdot (0.85\,s)\cdot \cos 25^{\circ}\)

\(x = 50.074\,m\)

The distance between the archer and the tree is 50.074 meters.

11) The final speed of the banana (\(v\)), measured in meters per second, just before hitting the water is determined by the Pythagorean Theorem:

\(v = \sqrt{v_{x}^{2}+v_{y}^{2}}\) (Eq. 2)

Where:

\(v_{x}\) - Horizontal speed of the banana, measured in meters per second.

\(v_{y}\) - Vertical speed of the banana, measured in meters per second.

Each component of the speed are obtained by using these kinematic equations:

\(v_{x} = v_{o}\cdot \cos \theta\) (Eq. 3)

\(v_{y} = v_{o}\cdot \sin \theta +g\cdot t\) (Eq. 4)

Where \(g\) is the gravitational acceleration, measured in meters per square second.

If we know that \(v_{o} = 7.6\,\frac{m}{s}\), \(\theta = -40^{\circ}\), \(g = -9.807\,\frac{m}{s^{2}}\) and \(t = 0.75\,s\), the components of final speed are, respectively:

\(v_{x} = \left(7.6\,\frac{m}{s} \right)\cdot \cos (-40^{\circ})\)

\(v_{x} = 5.822\,\frac{m}{s}\)

\(v_{y} = \left(7.6\,\frac{m}{s}\right)\cdot \sin (-40^{\circ})+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.75\,s)\)

\(v_{y} = -12.240\,\frac{m}{s}\)

And the speed of the banana right before hitting the water is:

\(v = \sqrt{\left(5.822\,\frac{m}{s} \right)^{2}+\left(-12.240\,\frac{m}{s} \right)^{2}}\)

\(v \approx 13.554\,\frac{m}{s}\)

The speed of the banana when it hits the water is approximately 13.554 meters per second.

Answer:

wouldn't it be 25 miles?? yeah

Explanation:

C) a bicyclist riding up a steep hill

The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:

A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.

     Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.

A. The work done by the gas enclosed in a cylinder equipped with a light, frictionless piston and maintained at atmospheric pressure, when 254 Kcal of heat is added to the gas, its volume increases slowly from 12.0 m³ to 16.2 m³ = 420 x 10³ kal.

B. The change in internal energy = 6.74 x 10⁵ Joule.

The concept of thermodynamics is an attempt to convert heat into energy, including the process of the flow of energy and the consequences produced by the transfer of energy.

The first law of thermodynamics is an example of the law of the conservation of energy. That is, energy cannot be created and cannot be destroyed. Energy can only change from one form to another. The first law of thermodynamics states that for every process if heat (Q) is given to the system and the system does work (W), there will be a change in internal energy (ΔU).

The equation is:

ΔE = Q + W

ΔU : change in internal energy (Joule)

Q: the amount of heat (Joule)

W: system work (Joule)

We have,

P = 10⁵ ⇒ atmospheric pressure

Q = 254 Kcal = 254 x 10³

ΔV = 16.2 m³ - 12.0 m³

= 4.2 m³

So, the work done by the gas:

W = PΔV

= (10⁵) (4.2)

= 420 x 10³ kal

And, the change in internal energy:

ΔE = Q + W

= (254 x 10³) + (420 x 10³)

= 6.74 x 10⁵ Joule

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

The equation can be used to determine the average force the nail applies to the hammer.

\(F = \frac{mv}{t}\), where m is the hammer's mass, v is its speed, and t is the time at which it made impact with the nail. The average force in this situation is given by:

\(F = \frac{(2.5 kg)(6 m/s - 2.0 m/s)}{(0.002 s)}\\ F= 4500 N.\)

To solve this problem using force vs. time, you would need to plot a graph of force versus time, with the time of contact between the hammer and the nail representing the x-axis and the force exerted on the hammer by the nail representing the y-axis. The force exerted on the hammer increases from 0 to 4500 N as the hammer moves from rest to its maximum velocity. The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

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Answer:

A compound

Explanation:

A compound is a substance formed when two or more elements are chemically joined

Answer:

Compound

Explanation:

A compound is a substance derived from the chemical combination of two or more elements

e.g Water ;

= \(H_2O\\Hydrogen\:and\:Oxygen\)

Salt ;

\(NaCl\\Sodium\:and\: Chlorine\)

The amount of stretch, x, is 0.0815 m (or 8.15 cm).

When two springs are connected in series, they act as a single spring with an effective spring constant given by:

1/keq = 1/k1 + 1/k2

where keq is the effective spring constant.

Substituting k1 = 160 N/m and k2 = 240 N/m, we get:

1/keq = 1/160 N/m + 1/240 N/m

1/keq = (3 + 2)/480 N/m

1/keq = 5/480 N/m

Therefore, keq = 480/5 N/m = 96 N/m.

When a mass m = 0.80 kg is attached to the springs, the weight of the mass is given by:

F = mg

F = 0.80 kg × 9.81 m/s²

F = 7.848 N

The amount of stretch, x, can be calculated using the formula for the stretch of a spring:

x = F/keq

Substituting F = 7.848 N and keq = 96 N/m, we get:

x = 7.848 N / 96 N/m

x = 0.0815 m

Therefore, the amount of stretch, x, is 0.0815 m (or 8.15 cm).

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The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.

Step 1: Identification of the given data:

- Elevation at point 1 (h1) = 10.0 m

- Elevation at points 2 and 3 (h2 = h3) = 2.00 m

- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)

- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)

Step 2: Determination of the discharge rate:

As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.

Therefore, the discharge rate is 0 cubic meters per second.

Step 3: Determination of the gauge pressure at point 2:

To find the gauge pressure at point 2, we'll use Bernoulli's equation:

P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2

Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.

The equation simplifies to:

Patm + ρgh1 = P2 + ρgh2

We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:

\(P_g_a_u_g_e\) = P2 - Patm

Now let's substitute the given values into the equation:

\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm

\(P_g_a_u_g_e\) = ρgh1

Plugging in the values:

\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)

\(P_g_a_u_g_e\) = 98100 Pa

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The advantages are Optical fibers can be expensive to install and maintain. They require a direct line of sight to the sun, which may be blocked by tall buildings or trees. Without proper insulation, the light can be very hot and create a fire hazard.

Optical fibers are thin strands of material, usually glass or plastic, that are used to transmit light signals over long distances. Optical fibers can be used for a variety of applications, including telecommunications, medical imaging, and sensing.

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1. Gas particles move randomly and rapidly in all directions and collide with each other and the walls of the container, creating pressure, 2. Liquids and solids have more ordered and restricted motion compared to gases, 3. Solids have fixed positions, liquids can move around each other, and gases move rapidly in all directions, and 4. The phase diagram shows the relationships between the states of matter at different temperatures and pressures and is important for predicting the behavior of substances and optimizing chemical reactions.

A phase diagram is a graph that shows the relationships between the different states of matter of a substance at different temperatures and pressures, providing information on the behavior of the substance under different conditions. It is an essential tool in understanding the behavior of materials in various conditions and in designing chemical processes that operate efficiently under different conditions.

1. Gas Properties simulation allows you to observe the behavior of gas particles. When you put a little gas into the box using the pump, you can see that the gas particles move randomly and rapidly in all directions. They collide with each other and with the walls of the box, creating pressure. When you pump in some lighter particles, such as helium, you can observe that they move faster and more chaotically than the heavier particles. They also bounce off the walls of the box more easily than the heavier particles. Changing the temperature of the gas affects the behavior of the particles. When the temperature increases, the particles move faster and collide more frequently, creating a higher pressure. When the temperature decreases, the particles move slower and collide less frequently, creating a lower pressure.

Based on the observations, a gas can be described as a state of matter in which the particles are widely spaced, move rapidly and randomly in all directions, and are not held together by any significant forces. The gas particles have a large amount of kinetic energy and exhibit rapid motion.

2. States of Matter simulation allows you to see how well liquids and solids match the description of gas particles. When you compare the behavior of gas particles to that of liquids and solids, you can see that liquids and solids have much more ordered and restricted motion than gases. In liquids, the particles are close together and move more slowly, while in solids, the particles are tightly packed and vibrate in fixed positions.

3. The motion of particles in solids, liquids, and gases can be explained using diagrams. In a solid, the particles are packed closely together in a regular pattern and vibrate in fixed positions. In a liquid, the particles are also close together but are not in a fixed pattern and can move around each other. In a gas, the particles are widely spaced and move rapidly in all directions. To create a diagram, you can use circles to represent the particles and arrows to show their motion.

The similarities between the three states of matter include the fact that the particles that make up each state are constantly in motion. The differences lie in the level of motion and the degree of freedom of the particles. Solids have the least amount of freedom, followed by liquids, and gases have the most freedom. Liquids and solids have definite shapes and volumes, while gases have neither definite shape nor definite volume.

4. The phase diagram is a graph that shows the relationships between the different states of matter at different temperatures and pressures. It is important in structure analysis and chemical reaction as it provides information on the behavior of substances at different temperatures and pressures. The phase diagram can help to predict the behavior of a substance under different conditions and can be used to identify the different phases that exist at different points. The phase diagram is also used in industrial processes to optimize chemical reactions and to design chemical processes that operate efficiently under different conditions. Understanding the phase diagram is essential in chemistry and materials science as it provides insight into the behavior of materials under various conditions.

Therefore, 1. Pressure is created when gas particles collide with one another and the container walls while moving randomly and quickly in all directions, 2. Compared to gases, the motion of liquids and solids is more controlled and ordered 3. While liquids can move around one another and gases move quickly in all directions, solids have fixed positions, and 4. The phase diagram is crucial for predicting the behavior of substances and optimizing chemical reactions because it depicts the relationships between the states of matter at various temperatures and pressures.

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Answer:

Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.

Explanation:

Hope this helps..

Answer:

In mathematics, a percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%", although the abbreviations "pct.", "pct" and sometimes "pc" are also used. A percentage is a dimensionless number; it has no unit of measurement.

And

A percentage is a portion of a whole expressed as a number between 0 and 100 rather than as a fraction. All of something is 100 percent, half of it is fifty percent, none of something is zero percent. ... A percentage can also mean a portion of something but only when it has to do with numbers.

hope this helps

Answer:

Explanation:

You can use \(Q = mc\Delta T=(550)(4.184)(28.8-12.7)=37049.32\) joule.

The magnitude of the net force on the block while it is sliding is most nearly is 14m/s when A 2 kg block, starting from rest, slides 20 m down a frictionless inclined plane from X to Y, dropping a vertical distance of 10 m.

The Plane by which no opposite force is applied on the sliding or moving object is termed as  Frictionless plane.

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Answer:

a) Nonconservative Work

\(W_{disp} = 9\,J\)

Final Gravitational Potential Energy

\(U_{f} = 0\,J\)

Final Translational Energy

\(K_{f} = 35.131\,J\)

b) Nonconservative Work

\(W_{disp} = 6.5\,J\)

Final Gravitational Potential Energy

\(U_{f} = 12.259\,J\)

Final Translational Energy

\(K_{f} = 25.373\,J\)

c) Nonconservative Work

\(W_{disp} = 4\,J\)

Final Gravitational Potential Energy

\(U_{f} = 24.518\,J\)

Final Translational Energy

\(K_{f} = 15.614\,J\)

Explanation:

The nonconservative work due to water resistance is defined by definition of work:

\(W_{disp} = F\cdot (y_{o}-y_{f})\) (1)

Where:

\(W_{disp}\) - Dissipate work, in joules.

\(F\) - Resistance force, in newtons.

\(y_{o}\) - Initial height, in meters.

\(y_{f}\) - Final height, in meters.

The final gravitational potential energy (\(U_{f}\)), in joules, is calculated by means of the definition of gravitational potential energy:

\(U_{f} = m\cdot g\cdot y_{f}\) (2)

Where:

\(m\) - Mass of the rock, in kilograms.

\(g\) - Gravitational acceleration, in meters per square second.

The final translational kinetic energy (\(K_{f}\)), in joules, is obtained by means of the Principle of Energy Conservation, Work-Energy Theorem and definitions of gravitational potential energy and translational kinetic energy:

\(m\cdot g\cdot y_{o} = U_{f} + K_{f} + W_{disp}\) (3)

\(K_{f} = m\cdot g\cdot y_{o} - U_{f} - W_{disp}\)

Lastly, the mechanical energy of the system (\(E\)), in joules, is the sum of final gravitational potential energy, translational kinetic energy and dissipated work due to water resistance:

\(E = U_{f} + K_{f} + W_{disp}\) (4)

Now we proceed to solve the exercise in each case:

a) Nonconservative Work (\(F = 5\,N\), \(y_{o} = 1.8\,m\), \(y_{f} = 0\,m\))

\(W_{disp} = (5\,N)\cdot (1.8\,m - 0\,m)\)

\(W_{disp} = 9\,J\)

Final Gravitational Potential Energy (\(m = 2.5\,kg\), \(g = 9.807\,\frac{m}{s^{2}}\), \(y_{f} = 0\,m\))

\(U_{f} = (2.5\,kg) \cdot \left(9.807\,\frac{m}{s^{2}}\right)\cdot (0\,m)\)

\(U_{f} = 0\,J\)

Final Translational Energy (\(m = 2.5\,kg\), \(g = 9.807\,\frac{m}{s^{2}}\), \(y_{o} = 1.8\,m\), \(U_{f} = 0\,J\), \(W_{disp} = 9\,J\))

\(K_{f} = (2.5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (1.8\,m) -0\,J-9\,J\)

\(K_{f} = 35.131\,J\)

b) Nonconservative Work (\(F = 5\,N\), \(y_{o} = 1.8\,m\), \(y_{f} = 0.50\,m\))

\(W_{disp} = (5\,N)\cdot (1.8\,m - 0.5\,m)\)

\(W_{disp} = 6.5\,J\)

Final Gravitational Potential Energy (\(m = 2.5\,kg\), \(g = 9.807\,\frac{m}{s^{2}}\), \(y_{f} = 0.5\,m\))

\(U_{f} = (2.5\,kg) \cdot \left(9.807\,\frac{m}{s^{2}}\right)\cdot (0.5\,m)\)

\(U_{f} = 12.259\,J\)

Final Translational Energy (\(m = 2.5\,kg\), \(g = 9.807\,\frac{m}{s^{2}}\), \(y_{o} = 1.8\,m\), \(U_{f} = 12.259\,J\), \(W_{disp} = 6.5\,J\))

\(K_{f} = (2.5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (1.8\,m) -12.259\,J-6.5\,J\)

\(K_{f} = 25.373\,J\)

c) Nonconservative Work (\(F = 5\,N\), \(y_{o} = 1.8\,m\), \(y_{f} = 1\,m\))

\(W_{disp} = (5\,N)\cdot (1.8\,m - 1\,m)\)

\(W_{disp} = 4\,J\)

Final Gravitational Potential Energy (\(m = 2.5\,kg\), \(g = 9.807\,\frac{m}{s^{2}}\), \(y_{f} = 1\,m\))

\(U_{f} = (2.5\,kg) \cdot \left(9.807\,\frac{m}{s^{2}}\right)\cdot (1\,m)\)

\(U_{f} = 24.518\,J\)

Final Translational Energy (\(m = 2.5\,kg\), \(g = 9.807\,\frac{m}{s^{2}}\), \(y_{o} = 1.8\,m\), \(U_{f} = 24.518\,J\), \(W_{disp} = 4\,J\))

\(K_{f} = (2.5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (1.8\,m) -24.518\,J-4\,J\)

\(K_{f} = 15.614\,J\)

Answer:

C

Explanation:

Diagram C is the correct answer, because the ball is at the point with the highest height relative to the ground, in this way all the kinetic energy has been transformed into potential energy.

We must remember that potential energy is defined as the product of mass by gravity by height

Ep = m*g*h

where:

m = mass [kg]

g = gravity acceleration [m/s²]

h = elevation [m]

So when we have a great value for h in the above equation, we will have a big value for potential energy.

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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E: "Removing charge from the rod" will increase the electric field strength at the position of the dot.

The electric field strength at the position of the dot depends on the charge and the distance from the charge. Therefore, any change that affects the charge or the distance will also affect the electric field strength.

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The distances to stars are mainly measured in parsecs, a light-year is larger than an astronomical unit (AU), and for calculations, astronomers use the metric system. Therefore, B and C are the correct options.

The metric system refers to the international decimal system of measurement. Since it is used internationally, it is a good idea that scientists use the metric system as a standard system of measurement. Astronomy is a science, so astronomers do use the metric system, though they prefer units (such as astronomical units, light years, and parsecs) that describe very long distance since space is huge.

Astronomers use light years to measure the distances between stars. But to measure the distances (from Earth) to stars, astronomers prefer to use parsecs.

A light-year is much greater than an AU (astronomical unit). A light year is defined to be equal to 63,240 AU.

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Answer:

Seafloor spreading occurs at divergent plate boundaries. As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense. The less-dense material rises, often forming a mountain or elevated area of the seafloor. Eventually, the crust cracks.

Explanation:

eventually the crust cracks.

The number of distinct ways of placing four indistinguishable balls into five distinguishable boxes is 20.

To solve this problem, we can use the stars and bars method, which is a combinatorial technique used to count the number of ways to distribute indistinguishable objects into distinguishable containers. In this case, we have four indistinguishable balls and five distinguishable boxes.

The stars and bars method works by representing each ball as a star and using bars to separate the balls into different boxes. For example, if we wanted to distribute two balls into three boxes, we could use the following diagram:

* | * * | *

In this diagram, the first and last bars represent the boundaries of the containers, while the stars represent the balls.

The second bar separates the first two balls from the last ball, indicating that the first two balls are in the first container and the last ball is in the third container.

To distribute four balls into five boxes, we need to use three bars to separate the balls into four groups. We have a total of six spaces to place the bars (including the boundaries), and we need to choose three of them to place the bars.

Therefore, the number of distinct ways to place four indistinguishable balls into five distinguishable boxes is the same as the number of ways to choose three spaces out of six, which is:

6 choose 3 = (6!)/(3!3!) = 20

Therefore, there are 20 distinct ways to place four indistinguishable balls into five distinguishable boxes using the stars and bars method.

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An insulating vessel contains 80 g of a block of ice at -12 °C. If 450 g of water at 60 °C is added to the ice in the vessel, Energy required for complete melting = \(80 g X (3.33 X 10^3 J/kg)\).

To determine whether the ice will soften absolutely and calculate the final temperature of the system, we need to do not forget the strength transferred among the ice and water at some stage in the procedure.

(i) To decide if the ice will melt completely, we need to examine the energy won by using the ice to the electricity required for complete melting.

Energy received by way of the ice = mass of ice × particular heat capacity of ice × alternate in temperature

Energy won by using the ice = eighty g × 2100 J/(kg·°C) × (final temperature - (-12°C))

Energy required for complete melting = mass of ice × latent warmth of fusion of ice

Energy required for whole melting = 80 g × (3.33 × 10^3 J/kg)

If the strength received via the ice is extra than or same to the electricity required for entire melting, the ice will soften completely.

(ii) To calculate the very last temperature of the gadget, we want to keep in mind the power transferred between the ice and water.

Energy won by the water = mass of water × unique heat ability of water × trade in temperature

Energy received by using the water = 450 g × 4200 J/(kg·°C) × (final temperature - 60°C)

Since electricity is conserved inside the machine, the power gained by means of the ice and water need to be identical:

Energy gained through the ice = Energy won by the water

Using the equations above, we will installation the following equation:

80 g × 2100 J/(kg·°C) × (very last temperature - (-12°C)) = 450 g × 4200 J/(kg·°C) × (very last temperature - 60°C)

Thus, this the final temperature of the system.

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The coefficient of restitution between two objects is a measure of the elasticity of the collision between them.

It is defined as the ratio of the relative velocity of separation to the relative velocity of approach between the two objects.

In this problem, the velocity of block b after the impact is observed to be 2.2 m/s to the right. Let us assume that block a is moving to the left with a velocity of v1 just before the impact. According to the law of conservation of momentum, the total momentum of the two blocks before the impact is equal to the total momentum of the two blocks after the impact. Therefore:

\(m1v1 + m2v2 = m1v1' + m2v2'\)

where m1 and m2 are the masses of block a and block b, respectively, v1 and v2 are the velocities of block a and block b just before the impact, and v1' and v2' are their velocities just after the impact.

Since block b is moving to the right after the impact, we can take v2' = 2.2 m/s. We also know that the two blocks stick together after the impact, so v1' = v2'. Therefore, we can simplify the above equation to:

\(m1v1 + m2v2 = (m1 + m2)v1'\)

Solving for v1', we get:

\(v1' = (m1v1 + m2v2)/(m1 + m2)\)

The coefficient of restitution (e) is defined as the ratio of the relative velocity of separation (v2' - v1') to the relative velocity of approach (v1 - v2) between the two blocks. Since the two blocks stick together after the impact, the relative velocity of separation is zero. Therefore:

\(e = (v2' - v1')/(v1 - v2) = 0/(v1 - v2) = 0\)

Hence, the coefficient of restitution between the two blocks is zero.

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Answer:

Earth-orbiting astronauts are weightless for the same reasons that riders of a free-falling amusement park ride or a free-falling elevator are weightless. They are weightless because there is no external contact force pushing or pulling upon their body. In each case, gravity is the only force acting upon their body.

Answer:

Conservation Tillage  preparation of soil by digging, stirring, and overturning.

Pros: reducing soil erosion, reducing the costs of soil preparation and conserving soil moisture

Cons: you will always need herbicides for weed management, planting may be delayed because of wet or cool soil temperatures. You will always have problems with weed ,insects, and plant disease.

hope that helps you

Explanation: