which is the best software application to be used by a hotel manager​

Answer:

Here is the C++ program:

#include<iostream>  //to use input output functions

using namespace std;  // to identify objects cin cout

int CountSubArrays(int arr[], int size){   /*function that an array and the size of array as parameters and returns the number of ways it can be split into three non-empty contiguous subarrays such that the sum of the elements in the first subarray is less than or equal to the sum of the elements in the second subarray, and the sum of the elements in the second subarray is less than or equal to the sum of the elements in the third subarray */

   int previous[size];  //stores the sum of previous elements

   previous[0] = arr[0];   //sets the first element of previous array to first element of arr

   for(int i = 1; i < size; i++)  //iterates through the array

previous[i] = previous[i - 1] + arr[i];   //adds the present element i-th element of arr to the previous element of previous array

int next[size];   //to store the sum of next elements

next[size - 1] = arr[size - 1]; //sets the last element of previous array to last element of arr

    for(int i = size ; i >= 0; i--)    //iterates through the array

next[i] = next[i + 1] + arr[i];   //adds the present element i-th element of arr to the next element of next array

int i = 1, j = 1;   //sets two variable to move through the array

int current = 0, count = 0;  

while (i < size - 1 && j < size - 1)  { //moves through the array  

 while (j < size - 1 && current <=previous[i - 1])  {  // updates current array until  it is less than previous[i - 1]

 current += arr[j++];  }   //adds value of current to j-th+1 value of arr

 if (current <= next[j])   {  //if value of current is less than or equal to the j-th value of next  

  count++;    }   //adds 1 to the count and count stores number of ways array can be split

 current -= arr[i++];   }   //decrements current by arr[i++]

return count;  } //returns the number of ways arr can be split into three non-empty contiguous subarrays

int main()  {  //start of main function

int arr[] = {1,2,2,2,5,0};  //declares and assigns values to array arr

int size = sizeof arr / sizeof arr[0]; //computes the size of array arr

cout << (CountSubArrays(arr, size)); }  //calls method by passing arr and size to it in order to find the number of ways it can be split into three non-empty contiguous subarrays

Explanation:

The program generates the previous array sum by adding the present element i-th element of arr to the previous element of previous array

It then generates the next array sum by adding the present element i-th element of arr to the next element of next array

Then two pointers i  and j are declared in order to find the sum of the second subarray.

Then while loop iterates over the array, increments current array with arr[j++] and this loop continues to execute as long as current stays less than previous[i – 1] .

When the current array is greater than or equal to previous[i – 1], then the if condition checks if current array is less than or equal to next[j]. This part basically works for the condition that the sum of the elements in the first subarray is less than or equal to the sum of the elements in the second subarray, and the sum of the elements in the second subarray is less than or equal to the sum of the elements in the third subarray. The value of count is incremented to 1 when the if statement evaluates to true.

Now the current array is decremented by arr[i+1]

The program repeats the above steps and then the function returns the computed value of count.

The output of the program is attached.

Answer:

Costs will cover a need for more customer data. The further explanation is given below.

Explanation:

There have been some cases in which major corporations have chosen not to include law enforcement:

The three system management tools

The feature and functions of inventory management is that they are  said to be tools that are used to tell or know the right amount and type of input products, as well as the products in process and those that are finished products.

Note that it helps in the facilitating of any production and sales operations.

Therefore, The three system management tools

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Answer:

tee nut i think

Explanation:

Answer:yes there WAS a parrapa level but it was scrapped from the game I think you can find it in beta versions of the game but

Answer:

A laser jet printer uses toner, while an inkjet printer sprays ink dots onto a page. Laser jet printers generally work faster than inkjet printers. Although inkjet printers are cheaper than laser jet printers, they are usually more expensive to maintain in the long run as ink cartridges have to be replaced more often. Thus, laser jet printers are cheaper to maintain. Laser jet printers are great for mass printing as they are faster and, as mentioned earlier, cheaper to replenish. Whereas inkjet printers are better for printing high quality images.

Answer:

Clipboard, Slides, Font, Paragraph, Drawing, and Editing

Accessing the school's online library from home showcases how the Internet simplifies research and learning.

Hence, The correct option is C.

The objective of this question is to assess your understanding of the positive impact the Internet has on research and learning.

It aims to evaluate your ability to identify and analyze the benefits of accessing online libraries from home.

Accessing your school's online library from the comfort of your home is a great example of how the Internet has made research and learning more convenient and accessible.

Instead of having to physically go to the library, you can now easily access a vast amount of resources and complete your homework from the comfort of your own home.

It's a wonderful way to take advantage of the benefits that the Internet offers for education.

Hence,

Option C is correct.

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Answer:

The overall finding of the study is that this type of distraction can potentially decrease work performance and productivity, Increased Risk of Malware, Damaged Employee Productivity, Reduced Employee Relations, and Confidentiality and Company Image. Security. Using social media platforms on company networks opens the door to hacks, viruses and privacy breaches, Harassment, Negative exposure, Legal violations, Potential loss of productivity, and Wage and hour issues.

Answer:

Wait

it eases off.

Get home,

gathered,

very close and look up –

we find it’s all right.

Play:

they be.

For life,

but all vanished

picture faces –

matter: I do or don’t.

More,

something

out of hold

squeeze it tightly

my best,

my best life.

Opened,

something –

back at that moment –

all marchers

the room, the door, the front

rang through the outside

Explanation:

Answer:

: User intent is a major factor in search engine optimisation and conversation optimisation. Most of them talk about customer intent ,however is focused on SEO not CRO

Explanation:

A timer needs to be set after each frame is sent before waiting an ACK for that frame. The length of time it takes for a  timer take to be expired depends on only when the first outstanding frames has expires first.

Some do take 5 min., 10 minutes, or even 48 hours while others depends on what the sender has set.

A sender is one that is not entitled  to hold a timer for each frame. It has to hold a single timer.

When a  the timer expires, the sender can then  resends all the frames whose ACK has not been seen or received yet. The sender often starts the timer at the time it is sending the first frame , and because of that, it is only when the timer for the first set frames expires before the sender can resend any other outstanding frames.

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Answer:

Grain crusher is used to crush various kinds of grains, peas, buckwheat, beans, corn, linseed seeds and etc. Crushed grains are usually used to feed ruminant animals. Crushed grain are easier to digest, nutrients are assimilated more easily. Suitable as simply pellets chrusher.

Answer:

Main AI Approaches

There are three related concepts that have been frequently used in recent years: AI, machine learning, and deep learning.

Answer:

Definition - What does Abstraction mean?

Abstraction is a fundamental principle in some types of computer science. It is a key design aspect of object-oriented programming languages and application programming interfaces. It's also one of the least understood ideas in programming, partially for semantic reasons.

PLEASE MARK BRAINLIEST

Abstraction is commonly defined as the extraction of relevant information from a larger data set, where utilizing abstraction allows engineers and others to simplify a codebase.

Techopedia explains Abstraction

The reason this is confusing to many people is that abstraction doesn't “sound like” what it is, semantically. It sounds like making something more vague, because that's how we use it in general language.

However, in computer science, abstraction typically means simplification and separating the signal from the noise in order to make programming more efficient and effective.

Explanation:

Here is an example code snippet in Python that declares a boolean variable named matchescond, reads an integer incount from input, reads the remaining integers from input, and checks whether all incount integers are equal to 100:

matchescond = True  # Initialize matchescond to True

incount = int(input("Enter the number of integers to be read: "))  # Read incount from input

for i in range(incount):

   num = int(input("Enter an integer: "))  # Read the next integer from input

   if num != 100:

       matchescond = False  # If any integer is not equal to 100, set matchescond to False

       break  # Exit the loop early, since we already know that matchescond is False

print("matchescond =", matchescond)  # Output the value of matchescond

The code first initializes the matchescond variable to True. It then reads in the number of integers to be read from input, and loops through that many times to read each integer from input.

Within the loop, the code checks whether the current integer is equal to 100. If it is not, matchescond is set to False, and the loop is exited early using the break statement. Finally, the code outputs the value of matchescond to the console.

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Answer:

1. When an object of the class is passed (to a function) by value as an argument.

2.  When an object is constructed based on another object of the same class.

3. When compiler generates a temporary object.

Explanation:

Answer:

6 yards

Explanation:

if to convert 15 feet into yards it would 15/3 = 5

Answer:

import java.io.*;

public class Main {

   public static void main(String[] args) throws IOException {

       double baseLength = 0, baseWidth = 0, pyramidHeight = 0;

       Object[] volume;

       volume = calcPyramidVolume(baseLength, baseWidth, pyramidHeight);

   }

   public static Object[] calcPyramidVolume(double baseLength, double baseWidth, double pyramidHeight) {

       double area = calcBaseArea(baseLength, baseWidth);

       double volume = baseLength * baseWidth * pyramidHeight;

       return new Object[]{volume, area};

   }

   public static double calcBaseArea(double length, double width) {

       return length * width;

   }

}

Explanation:

The problem is flawed because it is completely inefficient for one to create two separate methods to calculate the volume and the area when they can be done at once.

The second problem is that it was never specified whether to return something from the calcBaseArea method.

I assumed it required it, so it is not advisable to initiate the method as a double, but rather create it as an Object so that it can return two values: the volume and the area.

Answer:

# Take in four positive integers

num1 = int(input("Enter the first number: "))

num2 = int(input("Enter the second number: "))

num3 = int(input("Enter the third number: "))

num4 = int(input("Enter the fourth number: "))

# Initialize the count of odd numbers

odd_count = 0

# Check each number for oddness

if num1 % 2 != 0:

   odd_count += 1

if num2 % 2 != 0:

   odd_count += 1

if num3 % 2 != 0:

   odd_count += 1

if num4 % 2 != 0:

   odd_count += 1

# Output the total count of odd numbers

print("The number of odd numbers is:", odd_count)

Explanation:

Enter the first number: 1

Enter the second number: 2

Enter the third number: 3

Enter the fourth number: 4

The number of odd numbers is: 2

Answer:

60%

Explanation:

After changing the number format of the percentages of T9 and T10, the value that now shows in T10 due to the change from the wrong format to the Right format is 60%

This is because when a value is entered into a column in a wrong format the value would be different from other values entered rightly but when the format is changed to the right format, the correct value would show up.

You improve your credit history

Answer:

I think that the grade my teacher gave me on my test is wrong

Answer: Digital Communications Specialist

Explanation:

Took The Test Myself

Students might earn either a Master of Arts (M.A.) or a Master of Science (M.S.) degree with an emphasis in digital communications, in order to become a: Digital Communications Specialist.

A bachelor's degree can be defined as an academic degree that is formally awarded by a tertiary institution (university or college) to a student after the successful completion of his or her high school, and it usually takes about 4 or 5 years to complete a bachelor's degree.

A master's degree can be defined as an academic degree that is formally awarded by a tertiary institution (university or college) to a student after the successful completion of his or her bachelor's degree programme.

In conclusion, students are required to earn either a Master of Arts (M.A.) or a Master of Science (M.S.) degree in digital communications, in order to become a Digital Communications Specialist.

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Clio is compatible with the firms other software in the since that it often integrate them.

Clio is said to often integrates along with software such as Quickbooks Online, Quickbooks Desktop, and Xero and they are known for their  full accounting capabilities.

Clio is known to often integrate with Square, QuickBooks and Xero.

Zapier is known to be one that allows users to be able to send information between Clio and Square in an automatic way without using code required.

In some other cases, . Clio is said to have some specific accounting integrations that it has with software such as Trust Books, Klyant, and that of Digitory Legal.

Hence, Clio is compatible with the firms other software in the since that it often integrate them.

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Answer:

It is important because it can promote the construction of relational algebra operators in a more complete, comprehensive and easy way.

Explanation:

The operators' ability to compose allows them to cooperate with each other's arguments, creating large, comprehensive concepts that address issues in a more detailed and consequently correct way. In this case, this interaction that the composition promotes, allows relational algebra operators to be created more easily.

Relational algebra defines operators and the ability to compose operators allows algebra and operators to cooperate with each other's argument.

Relational Algebra is a query language that involves procedures, it takes relation as input and also generates relation as output.

Relational algebras help to define operators that transform one or more input relations to an output relation.

It is important to compose an operator because,

Therefore, the ability to compose operators allows interaction that can create large and comprehensive concepts.

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Answer: Packet switching.

Explanation: The transfer of small pieces of data across various networks is known as packet switching. The faster and more effective transfer of data is made possible by these data chunks, or "packets." When a user transmits a file over a network, it is frequently transmitted in smaller data packets rather than as a single unit.

In this project, you will conduct an investigation to uncover the optimal loan solution for acquiring a second-hand car.

You will examine the various utilized automobile alternatives and financing approaches provided through banks and credit unions. By using an online credit calculator, you will compute the best choice for your scenario.

Your multimedia demonstration will include slides featuring pertinent information regarding the pre-owned car and funding options, calculations made, as well as a comparison between several potential lending contingencies.

Further, a works-cited slide should be included providing all the sources and data you employed to make your ultimate decision.

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Answer:

This is in python

Explanation:

Alter my code if you need anything changed. (You may need to create a new function to add a day to February if necessary)

months = [31,28,31,30,31,30,31,31,30,31,30,31]

monthNames = ['january','february','march','april','may','june',

            'july','august','september','october','november','december']

array = []

def test(y,m,d): #Does not account for leap-year. Make a new function that adds a day to february and call it before this one

   if m.lower() not in monthNames or y < 1 or d > 31:

       if m.lower() == "april" or m.lower() == "june" or m.lower() == "september" or m.lower() == "november" and d > 30:

           return None

       elif m.lower() == "february" and d > months[1]:

           return None

       return None

   num = monthNames.index(m.lower()) #m should be the inputted month

   months[num] = d

   date = months[num]

   for n in range(num):

       array.append(months[n])

   tempTotal = sum(array)

   return tempTotal + date

x = int(input("Enter year: "))

y = input("Enter month: ")

z = int(input("Enter day: "))

print(f"{y.capitalize()} {z} is day {test(x,y,z)} in {x}")

Answer:

Explanation:

The following program is written in Java and creates three levels with the different set of randomly generated arithmetic problems. As the player goes getting more points they advance every 5 points to the next level.

import java.util.Random;

import java.util.Scanner;

class Main {

   private static Random random = new Random();

   private static Scanner in = new Scanner(System.in);

   static int points = 0;

   public static void main(String[] args) {

       while (true) {

           System.out.println(points);

           if (points < 5) {

               System.out.println("Starting Level 1");

               levelOne();

           } else if (points < 10) {

               System.out.println("Starting Level 2");

               levelTwo();

           } else if (points < 15) {

               System.out.println("Starting Level 3");

               levelThree();

           }

       }

   }

   public static boolean levelOne() {

       int numberOne = random.nextInt(10);

       int numberTwo = random.nextInt((10 - numberOne));

       int answer = numberOne + numberTwo;

       int count = 0;

       while (points < 5 && count < 2) {

           System.out.println("What is " + numberOne + " + " + numberTwo + "?: ");

           int userChoice = in.nextInt();

           if (userChoice == answer) {

               points += 1;

               levelOne();

           } else {

               count += 1;

           }

       }

       return false;

   }

   public static boolean levelTwo() {

       int numberOne = random.nextInt(10);

       int numberTwo = random.nextInt(10);

       int answer = numberOne + numberTwo;

       int count = 0;

       while (points < 10 && count < 2) {

           System.out.println("What is " + numberOne + " + " + numberTwo + "?: ");

           int userChoice = in.nextInt();

           if (userChoice == answer) {

               points += 1;

               levelTwo();

           } else {

               count += 1;

           }

       }

       return false;

   }

   public static boolean levelThree() {

       int numberOne = random.nextInt(10);

       int numberTwo = random.nextInt(10);

       int answer = numberOne - numberTwo;

       int count = 0;

       if (answer <= 0) {

           levelThree();

       }

       while (points < 15 && count < 2) {

           System.out.println("What is " + numberOne + " - " + numberTwo + "?: ");

           int userChoice = in.nextInt();

           if (userChoice == answer) {

               points += 1;

               levelThree();

           } else {

               count += 1;

           }

       }

       return false;

   }

}