C hopes this helps
A soccer ball sits on the playing field
The continuity equation shows that the ratio of fluid velocities within different openings is inversely proportional to the cross-sectional areas of those openings. Provide one example where this might be useful for finding differences in areas after measuring velocities, or in finding differences in velocities after measuring areas. Describe your example in detail making sure to talk about the different variables involved.
Answer:
A typical example of where the continuity equation can be applied, is in finding the cross sectional area of a laminar falling stream of water from a pipe at an elevation, at the point where it hits the ground.
The speed of the water through the discharge opening of the pipe can be measured with a flow-meter, and the cross sectional opening of the pipe is known.
As the water leaves the pipe, and falls towards the ground, the water stream is accelerated under gravity, and the speed of the water stream increase. The increase in the speed of the water stream causes the cross sectional area to decrease in obedience of the continuity law and equation. If the speed of can be measured, then the area of the water stream just before the water touches the ground can be calculated from the continuity equation.
If the speed of the water stream can not be measured, then it can be calculated using Newton' equation of motion
\(v^{2} = u^{2} + 2gz\)
\(v = \sqrt{u^{2} + 2gz}\)
where
v = the velocity of the water stream at the point where it hits the ground
u = the velocity of the water at the pipe discharge (measured with a flow meter in the pipe)
g = acceleration due to gravity
z = the elevation of the pipe above the ground.
After calculating the speed of the water stream at the point where it hits the ground, the cross sectional area of the the stream can be calculated from the continuity equation.
\(uA = va\)
where
u and v are the velocities of the water stream at the pipe discharge and at the ground respectively.
A = the cross sectional area of the pipe
a = the area of the water stream before it hits the ground.
the equation is simplified as
\(a = \frac{uA}{v}\)
One person shouts "Gone to Texas." If now 100 shout it then
Group of answer choices
A: The sound is 10 decibels higher.
B: The sound is 20 decibels higher.
C: The sound is 100 decibels higher.
D: The sound is 100 times as many decibels.
E: The sound is loud enough to make people's ears explode.
The sound intensity level would increase by 20 decibels if 100 people shout instead of one. Hence option B is correct.
The sound intensity level (SIL) increases by 10*log(N), where N is the number of people shouting. With the help of this equation, we can determine the rise in SIL as follows: N₁ = 1 (one person shouting) and N₂ = 100 (100 people shouting) simultaneously,
ΔSIL = 10log(N₂/N₁)
ΔSIL = 10log(100/1)
ΔSIL = 10*2
ΔSIL = 20 dB
Therefore, the answer is B that says "The sound is 20 decibels higher".
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please help! easy science! second pic is the question and possible answers (A B C or D) its one question! brainliest promised!
Answer:
Please do not take my word for this at all, but this is what I found, "When the pendulum swings back down, the potential energy is converted back into kinetic energy. At all times, the sum of potential and kinetic energy is constant." So I think the answer is B also you are anime fan too lol :DD I love hinata
Explanation:
When you increase the driving frequency of a wave on the string, does the wavelength decrease, increase, or stay the same? a) Decrease b) Increase c) Stays the same
When you increase the driving frequency of a wave on a string, the wavelength decreases. Therefore, the correct option is a) Decrease.
This phenomenon is known as the frequency-wavelength relationship or the inverse relationship between frequency and wavelength. According to this relationship, as the frequency of a wave increases, the wavelength decreases, and vice versa.
Mathematically, the relationship between frequency (f), wavelength (λ), and wave speed (v) can be expressed as:
v = f * λ
Since the wave speed is typically constant for a given medium, if you increase the frequency (f), the wavelength (λ) must decrease in order to maintain a constant wave speed.
Therefore, the correct answer is: a) Decrease
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A ray of light strikes a plane mirror at an angle of incidence equal to 35°. The angle between
the incident ray and the reflected ray is
A)
70°
B)
0°
C)
55°
D)
35°
Answer:
55 degrees
Explanation:
A ray of light strikes a plane mirror at an angle of incidence. The angle between the incident ray and the reflected ray is 70°. The correct option is A.
What is law of reflection?The law states that angle of incidence of the incident ray is equal to the angle of reflection through a plane surface.
Here, angle of incidence of light on a plane mirror is 35°, then the angle of reflection will also be 35°.
i = r = 35°
Then the angle between the incident ray and the reflected ray will be
i +r = 35 + 35 =70°
Thus, the correct option is A.
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In an rlc circuit connected to an ac voltage source, which quantities determine the resonance frequency?
The resonance frequency in an RLC circuit connected to an ac voltage source is determined by the : inductance and capacitance.
In RLC circuit, the resonant frequency is given by :
f = 1/2π √LC
where,
L is inductance.
C is capacitance.
So, it depends on The inductance and the capacitance.
➤ A resonant circuit is made up of R, L, and C elements, and its frequency response characteristic changes as the frequency changes.
In a series RLC circuit, there is a frequency point where the inductive reactance of the inductor equals the capacitive reactance of the capacitor. In other words, X = XC. The point at which this occurs is known as the circuit's Resonant Frequency and in the case of a series RLC circuit, this resonance frequency produces a Series Resonance.
The reactance value of a capacitor is very high at low frequencies but rapidly decreases as the frequency across it increases.
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c. we may think of a bulb as presenting an obstacle, or resistance, to the current in the circuit. 1. thinking of the bulb in this way, would adding more bulbs in series cause the total obstacle to the flow, or total resistance, to increase, decrease, or stay the same as before. 2. formulate a rule for predicting how the current through the battery would change (i.e., whether it would increase, decrease, or remain the same) if the number of bulbs connected in series were increased or decreased.
All light bulbs contain a filament that has some form of resistance hence adding more bulbs in series will increase the total obstacle to the flow, or increases the total resistance
Resistance is the degree to which a substance obstructs or opposes an electric current and electron flow is referred to as electric current.
As electricity passes through the filament, it encounters the resistance due to presence of filament and the energy is converted into light and heat.
According to the Ohm's law, V = IR
if the voltage remains constant then the current(I) is inversely proportional to the resistance(R).
So increasing the number of bulbs connected in series would decrease the current through the battery as it is having constant voltage.
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A ball thrown vertically upward is caught by the thrower after 4.00 sec. Find the initial velocity of the ball and the maximum height it reaches.
Answer:
Initial velocity = 39.2m/s
Maximum height is 78.4m
Explanation:
Given
\(Time, t = 4s\)
Solving (a): Initial Velocity
Using first law of motion:
\(v = u + at\)
Where
\(v = final\ velocity = 0\)
\(u = iniital\ velocity = ??\)
\(a = acceleration = -g\) [g represents acceleration due to gravity]
\(t = 4\)
Substitute these value in the above formula:
\(v = u + at\)
\(0 = u - g * 4\)
\(0 = u - 9.8 * 4\)
Take g as 9.8m/s²
\(0 = u - 39.2\)
\(u = 39.2m/s\\\)
Hence, initial velocity = 39.2m/s
Solving (b): Maximum Height
This will be solved using second equation of motion
\(s = ut + \frac{1}{2}at^2\)
This becomes
\(s = ut - \frac{1}{2}gt^2\)
Substitute values for u, t and g
\(s = 39.2 * 4 - \frac{1}{2} * 9.8 * 4^2\)
\(s = 156.8 - 78.4\)
\(s = 78.4\)
Hence, the maximum height is 78.4m
A 15,000 kg tugboat is moving East at 6.0 m/s. A1.2 x 105 kg barge is moving West at 1.2 m/s.
What is the momentum of this system?
The water of the Dead Sea is extremely salty. which gives it a very high density of 1240 kg/m^3. Explain why a person floats much higher in the Dead Sea than in ordinary water.
The Dead Sea has a high salinity, which causes the saline and minerals to be concentrated most heavily there. A person's buoyancy is increased since body weight is less dense than the waters in the Dead Sea.
Why would you float in the Dead Sea so much higher?Because of the increased water density caused by the high salinity, items in the water float more easily. In the Dead Sea, all that is required is to lie back and float. In reality, due to the buoyancy, swimming in the Dead Sea is challenging.
In the Dead Sea, would a human body float?The Dead Sea contains a lot of salt. As a result, the sea has a higher water density than other seas. Because the density of human bodies is lower than that of the dead sea, humans float atop it.
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a 6 kg object starts from rest. it is then pushed by a 10 n force for 8 seconds. how much momentum does it have afterward?
The momentum of the object afterwards will be 80 Kgms-1.
Given the following data as per the question:
Mass of the object is given as 6 Kg
Force is given as 10 N in the question
Time is given as the following 8 sec
The value of the Momentum is same as impulse.
So, the formula of impulse is given as:
I = Ft
Where
I is the impulse
F is the force
and t is the time
From the given information,
F = 10 N
t = 8 secs
Therefore,
I = 10 × 8
I = 80 Ns.
Momentum is 80 Kgms-1.
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A flat coil of wire has an inductance of 40.0 mH and a resistance of 5.00 v ?. It is connected to a 22.0-v battery at the instant t = 5.0. Consider the moment when the current is 3.00 A. (a) At what rate is energy being delivered by the battery?__________W (b) What is the power being delivered to the resistance of the coil?_________W (c) At what rate is energy being stored in the magnetic field of the coil?_______w
(a) Energy being delivered by the battery: 66.0 W. (b) Power delivered to the resistance: 9.0 W. (c) Energy being stored in the magnetic field: 57.0 W.
In this scenario, a flat coil of wire with an inductance of 40.0 mH and a resistance of 5.00 Ω is connected to a 22.0 V battery. At t = 5.0, the current in the coil is 3.00 A. (a) The rate at which energy is being delivered by the battery can be calculated using the formula P = IV, where P represents power, I is the current, and V is the voltage. Thus, P = (3.00 A) * (22.0 V) = 66.0 W. (b) The power being delivered to the resistance can be determined using the formula P = I^2R, where R represents resistance. Therefore, P = (3.00 A)^2 * (5.00 Ω) = 9.0 W. (c) The rate at which energy is being stored in the magnetic field of the coil can be calculated by subtracting the power dissipated by the resistance from the power delivered by the battery. Thus, 66.0 W - 9.0 W = 57.0 W. In summary, the battery is delivering energy at a rate of 66.0 W, 9.0 W is being dissipated as power in the resistance, and the remaining 57.0 W is being stored in the magnetic field of the coil.
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a bird flying west has an air speed of 14 km/h. if there is a southeasterly wind of 5 km/h, find the magnitude of the true speed and direction of the bird relative to the ground.
(use decimal notation. Give your answers to there decimal places)
||Vg|| = ____ km/h
The magnitude of the true speed and direction of the bird relative to the ground is 15.44 km/h and 25.5° respectively.
The magnitude of the true speed and direction of the bird relative to the ground can be calculated using vector addition. The vector representing the air speed of the bird (vA) is 14 km/h at a bearing of West (270°). The vector representing the wind (vW) is 5 km/h at a bearing of South East (135°).
The resultant vector (VG) can be calculated by adding vA and vW as follows:
vG = √((vA)² + (vW)²) = 14 km/h at 270° + 5 km/h at 135°
Using the trigonometric identities for sine and cosine, we can calculate the magnitude and direction of V as:
vG = √[(14)² + (5)²] = 14.86 km/h
Bearing (θ) = tan¹(5/14) = 25.5°
Therefore, the magnitude of the true speed and direction of the bird relative to the ground when the bird flying west has an air speed of 14 km/h and there is a southeasterly wind of 5 km/h, is 15.44 km/h at 25.5°.
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Fig.4.1
The switch S is closed for a period of 5.0 minutes. Calculate
(a)
the current through each resistor.
чре
(b)
the current through the battery.
rad
rad
(c)
the total charge which passes through the battery.
ma
(d)
the energy supplied by the battery.
ars
Answer:
A
Explanation:
28) Refraction results from differences in light's. A) frequency. B) incident angles. C) speed. D) all of the above. E) none of the above.
Refraction results from differences in light's speed. The correct answer is C) speed.
Refraction is the term for the bending of light as it passes through transparent materials (it also occurs with sound, water, and other waves). We are able to create lenses, magnifying glasses, prisms, and rainbows because to this bending caused by refraction.
Refraction occurs when light passes through different mediums and changes its speed. This change in speed causes the light to bend, creating the effect of refraction.
This is why objects appear to be in different positions when viewed through water or a lens. The frequency and incident angles of the light do not affect refraction, only the speed of the light does.
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an underwater scuba diver sees the sun at an apparent angle of 45º from the vertical. how far is the sun above the horizon? (nwater = 1.3)
The sun appears approximately 45.19º above the horizon for the underwater scuba diver.
To determine how far the sun is above the horizon for an underwater scuba diver, we can use Snell's law, which relates the angle of incidence and the angle of refraction when light passes through different mediums.
Snell's law states:
n1 * sin(θ1) = n2 * sin(θ2)
where n1 and n2 are the refractive indices of the two mediums, and θ1 and θ2 are the angles of incidence and refraction, respectively.
In this case, the light is passing from air (n1 ≈ 1.00) to water (n2 = 1.3). The angle of incidence (θ1) is the angle between the vertical and the line connecting the observer's eye to the sun, which is given as 45º.
To find the angle of refraction (θ2), we can rearrange Snell's law:
sin(θ2) = (n1 / n2) * sin(θ1)
Substituting the values, we have:
sin(θ2) = (1.00 / 1.3) * sin(45º)
Calculating this expression, we find:
sin(θ2) ≈ 0.724
To determine the angle θ2, we take the inverse sine (arcsin) of 0.724:
θ2 ≈ arcsin(0.724)
Using a calculator, we find:
θ2 ≈ 45.19º
The angle θ2 represents the deviation of the light ray from the vertical due to refraction. Therefore, the sun appears approximately 45.19º above the horizon for the underwater scuba diver.
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Which of the following is an example of a chemical property? Density Solubility Flammability Magnetism
Answer:
Flammability.
Explanation:
I took the test.
6)which types of telescopes will be able to detect flux from objects if the telescopes are located on earth? use figure 5.6 for guidance. bold the correct answers.
The types of telescopes that will be able to detect flux from objects when located on Earth include optical telescopes, radio telescopes, and infrared telescopes.
Optical Telescopes: Optical telescopes are specifically designed to gather and focus visible light, enabling the detection of flux from astronomical objects. They come in two main types: refracting telescopes, which use lenses to gather and focus light, and reflecting telescopes, which use mirrors to capture and direct light to a detector or eyepiece.
Radio Telescopes: Radio telescopes detect and analyze radio waves emitted by astronomical objects. They are designed to capture a wide range of radio frequencies and are crucial for studying celestial sources that emit primarily in the radio part of the electromagnetic spectrum. By analyzing the received signals, astronomers can study phenomena such as pulsars, quasars, and cosmic microwave background radiation.
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_____ is why the earth's interior is layered
Answer: The inner core is solid, the outer core is liquid, and the mantle is solid/plastic. This is due to the relative melting points of the different layers (nickel–iron core, silicate crust and mantle) and the increase in temperature and pressure as depth increases.
Explanation: I just did a quiz with this question
True or False
1. Scientists have complete knowledge of atoms and this knowledge can never change?
during weathering, the surface area of the rock exposed will ________. because of this, the rate of weathering will ________.
Answer:During weathering, the surface area of the rock exposed will increase. This is because the outer layers of the rock will gradually erode or break down, exposing more surface area of the underlying rock.
As the surface area of the rock exposed increases, the rate of weathering will also increase. This is because there is more surface area available for weathering agents, such as water, wind, or chemicals, to react with the rock. The greater the surface area exposed, the greater the contact between the rock and the weathering agents, which leads to faster and more effective weathering.
Therefore, increasing the surface area of the rock by weathering accelerates the process of weathering.
Explanation:
A Carnot refrigeration cycle is used to maintain a room at
23 °C by removing heat from groundwater at 15 °C.
Refrigerant R-134a enters the condenser as saturated
vapor at 40 °C and leaves as saturated liquid at the
same temperature. The evaporator pressure is 351 kPa.
a) If the room is to receive 2kW, what is power input to
the compressor?
b) Net power input to cycle?
a) The power input to the compressor in the Carnot refrigeration cycle, in order to supply 2 kW of cooling to the room, will depend on the efficiency of the cycle and the heat transfer involved.
b) The net power input to the cycle can be determined by considering the work done by the compressor and the work done on the system.
a) To calculate the power input to the compressor, we need to determine the heat transfer from the groundwater to the room. The Carnot refrigeration cycle is an idealized cycle, and its efficiency is given by the equation: Efficiency = 1 - (T_evaporator / T_condenser), where T_evaporator and T_condenser are the temperatures at the evaporator and condenser, respectively. Using this efficiency, we can calculate the heat transfer from the groundwater and convert it to power input.
b) The net power input to the cycle takes into account the work done by the compressor and the work done on the system. It can be calculated by subtracting the work done by the compressor from the heat transfer from the groundwater. The work done by the compressor can be determined using the power input calculated in part a), and the heat transfer from the groundwater can be obtained using the given temperatures and the specific heat properties of the refrigerant.
Overall, the Carnot refrigeration cycle involves several calculations to determine the power input to the compressor and the net power input to the cycle, considering the heat transfer and work done in the system.
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For each of the distances marked on the ruler below give the measurement in centimeters and millimeters
One centimeter is divided into 10 equally spaced portions that are designated by tiny lines on the ruler, which you can see if you look at it. A millimeter is represented by each line.
What is distance ?Distance is a measurement of how far apart two things or points are, either numerically or occasionally qualitatively. Distance can refer to a physical length in physics or to an estimate based on other factors in common usage.
Distance is the length of an object's real route in its entirety. The displacement of an object between two points is defined as the straight line (shortest) distance between those two points when directed from one position to another. The metre is the SI unit for measuring distance and displacement (m).
Thus, One centimeter is divided into 10 equally spaced portions that are designated by tiny lines on the ruler, which you can see if you look at it. A millimeter is represented by each line.
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what is the schwarzschild radius of a 10 solar mass black hole? what is the schwarzschild radius of a 10 solar mass black hole? 30 billion km 10 km 3 billion km 1 billion km 30 km
The Schwarzschild radius is a measure of the event horizon of a black hole, which is the point of no return beyond which nothing, not even light, can escape. It is named after the German physicist Karl Schwarzschild who first calculated it in 1916.
The formula for calculating the Schwarzschild radius is given by Rs = 2GM/c^2, where Rs is the Schwarzschild radius, G is the gravitational constant, M is the mass of the black hole, and c is the speed of light.
For a 10 solar mass black hole, we can plug in the values into the formula and get Rs = 29.96 billion km, which is approximately 30 billion km. This means that the event horizon of a 10 solar mass black hole is a sphere with a radius of 30 billion km.
To put this into perspective, the distance between the Earth and the Sun is about 150 million km, which means that the event horizon of a 10 solar mass black hole is about 200 times the distance between the Earth and the Sun.
In summary, the Schwarzschild radius of a 10 solar mass black hole is 30 billion km. This is an important measure of the size of a black hole and helps us understand the behavior of matter and energy around it.
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Why is it important to assess flexibility both before and during a workout regimen? a. to assess flexibility progress b. to keep muscles warm c. to establish flexibility baselines d. none of the above please select the best answer from the choices provided. a b c d
It important to assess flexibility both before and during a workout regimen because to assess flexibility progress.
What is a flexibility exercise?Flexibility exercises, as the name implies, help to increase the stretch of the muscles, improving the range of motion. More flexibility is also important to help prevent possible post-workout soreness.
In this case we have that the reason to continue doing stretching before and during the exercises is about to assess flexibility progress.
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Answer:
A
Explanation:
The two properties that are
parts of refraction are ...
Answer:
-Relative refractive index– It is the ratio of speed of light in one medium to the speed of light in another medium
-Absolute refractive index– It is the ratio of light in vacuum to the speed of light in another medium.
Explanation:
Consider the two-dimensional scalar potential function phi(x, y) = x^3 - 3y^2 x.
(a) Make a plot of the equipotential contours for three positive and three negative values for phi. (b) Find nabla^bar phi.
(c) Show that the nabla^bar phi field lines are given by setting 3x^2 y - y^3 equal to a series of constants. (d) Plot six representative nabla^bar phi field lines. Be sure to indicate the direction of the field and comment on its magnitude. (e) Find nabla^bar middot nabla^bar phi, the divergence of the nabla^bar phi vector field, and show that your field lines of part (d) agree with this divergence.
(a) To make a plot of the equipotential contours for three positive and three negative values for phi, we need to set phi equal to each value and plot the resulting curves. For positive values, we can use phi = 1, 2, 3, and for negative values, we can use phi = -1, -2, -3. The resulting curves are shown in the figure below.
(b) To find nabla^bar phi, we need to take the partial derivatives of phi with respect to x and y. Thus, nabla^bar phi = (3x^2 - 3y^2, -6xy).
(c) To show that the nabla^bar phi field lines are given by setting 3x^2 y - y^3 equal to a series of constants, we need to set the components of nabla^bar phi equal to some constants kx and ky, respectively. Solving for y in terms of x and using the result in the other equation, we get:
3x^2 (ky/kx) - (ky/kx)^3 = y^2
y = ±sqrt(3x^2 (ky/kx) - (ky/kx)^3)
Thus, the field lines are given by the above equation with different values of kx and ky.
(d) To plot six representative nabla^bar phi field lines, we can choose six different values of kx and ky and plot the resulting curves. The direction of the field is given by the direction of nabla^bar phi, which is shown by the arrows in the figure below. The magnitude of the field is proportional to the density of the field lines, with denser lines indicating stronger fields.
(e) To find nabla^bar middot nabla^bar phi, we need to take the divergence of nabla^bar phi. Thus, nabla^bar middot nabla^bar phi = 3x^2 - 6y^2. This agrees with the equation for the field lines we found in part (c), since the constants kx and ky correspond to different values of 3x^2 - y^3.
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g kyle, a 90.0 kg football player, leaps straight up into the air (with no horizontal velocity) to catch a pass. he catches the 0.430 kg ball precisely at the peak of his jump, when he is 0.488 meters off the ground. he hits the ground 0.0345 meters away from where he leapt. if the ball was moving horizontally when it was caught, how fast was the ball traveling?
The ball was captured in 0.347 seconds if it were going horizontally and at a 15.1 m/s speed.
To make the computation easier, convert the distance & length data to meters.
The player and ball can be regarded as one entity when the ball is caught, and the preservation of momentum can be used to determine their velocity. When the ball is caught, the player's leap has no horizontal component and no vertical velocity, therefore the player's velocity plus the mass of the ball is
mP + BvP + B = mPvP + mBvB
vP + B = (0.430 kg × vB) ÷ (90kg + 0.430 kg)
vP + B = 0.00475 m/s
At the point where they start to fall, this velocity is horizontal. The kinematic equation is used to
y = vt + (1 ÷ 2)gt²
The duration of their fall, assuming that gravity's acceleration is 9.81 m/s², is,
t = √(2y ÷ g)
t = (√(2 × 0.589)) × 9.81 s
t = 0.347s
We can use our equation to get the beginning velocity of the ball since we know the entire horizontal distance covered by the player and the ball.
R = vP + Bt
0.0345m = 0.00657vB × 0.347s
vB=15.1m/s
The player thus caught the ball while it was moving at 15.1 meters per second.
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A string that is stretched between fixed supports separated by 79.8 cm has resonant frequencies of 1024 and 896.0 Hz, with no intermediate resonant frequencies. What are (a) the lowest resonant frequency and (b) the wave speed
(a) The lowest resonant frequency can be determined by finding the fundamental frequency of the string.
Since there are no intermediate resonant frequencies, the fundamental frequency will be the first harmonic.
The first harmonic is given by the equation f1 = (1/2L) * √(T/μ), where L is the length of the string, T is the tension, and μ is the linear mass density. Rearranging the equation and plugging in the values, we have f1 = (1/2 * 0.798 m) * √(T/μ).
By substituting the given resonant frequencies, we can solve for T/μ. Finally, substituting this value into the equation for f1, we can calculate the lowest resonant frequency.
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what is the specific activity of an 8 ml purified enzyme sample that converts 450 μmole of its substrate to product per minute at 25 °c when the protein content is 10 mg/ml?
The specific activity of the enzyme can be calculated by dividing the amount of substrate converted to product per minute (450 μmole/min) by the volume of the enzyme sample used (8 ml) and the protein content of the sample (10 mg/ml). This gives a specific activity of 56.25 μmole/min/mg.
The specific activity of an enzyme refers to the amount of substrate converted to product per unit time per milligram of protein. In this case, we have an 8 mL purified enzyme sample converting 450 μmoles of substrate per minute at a protein concentration of 10 mg/mL. To calculate the specific activity, we can use the following formula:
Specific activity = (amount of substrate converted) / (protein content × volume of sample)
In this case: Specific activity = (450 μmoles/min) / (10 mg/mL × 8 mL)
Specific activity = (450 μmoles/min) / 80 mg
Specific activity = 5.625 μmoles/min/mg
Thus, the specific activity of the purified enzyme sample is 5.625 μmoles of substrate converted per minute per milligram of protein at 25 °C.
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