Al2O3, or aluminum oxide, is an example of a compound that is amphoteric but not amphiprotic. Amphoteric substances have the ability to act as both an acid and a base, depending on the environment they are in. In the case of Al2O3, it can react with both acids and bases, forming salts and water. When reacting with an acid, it behaves as a base, and when reacting with a base, it behaves as an acid.
Amphiprotic substances, on the other hand, are a specific type of amphoteric compounds that can donate and accept a proton (H+ ion) in their reactions. Amphiprotic substances are always amphoteric, but not all amphoteric substances are amphiprotic.
Al2O3 is not amphiprotic because it does not have any protons to donate or accept in its reactions. The other compounds listed, HCO3- (hydrogen carbonate), H2O (water), and HS- (hydrogen sulfide ion), are all examples of amphiprotic substances. They can each donate and accept a proton in their reactions, making them both amphoteric and amphiprotic.
In summary, Al2O3 is an amphoteric substance due to its ability to react with both acids and bases, but it is not amphiprotic as it does not involve proton transfer in its reactions. The other listed compounds, HCO3-, H2O, and HS-, are examples of amphiprotic substances that exhibit both amphoteric and amphiprotic behavior.
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again with the chemistry questions all help is appreciated :’)
Answer:
The answer is Rubidium
Explanation:
The number of protons is unique for each element. It is also identified as an element’s atomic number. Look for an element with the number of protons as the atomic number to find the unidentified element.
Answer:
Hello again, I think the option will be the third one Rubidium im highly sure because the periodic table goes by the number of protons which in your question is 37. So yeah it will be rubidium.
Explanation:
Look for 37 protons in the periodic table.
show work on how you converted them. (also marking brainliest) <3
explanation for qn:
when converting units, u can show your working in the form
37.5 × 1g/1ml, then convert the g and ml into 1/1000 kg and L, and calculate from there. In the end, u find out its actually a trick qn and 1g/ml = 1 kg/L
Calculate the number of moles in 5.54 x 10^24 atoms of aluminum.
Answer:
9.55 mol of Al
Explanation:
To obtain the number of moles of a certain element given the number of atoms only, you have to divide it with Avogadro's number,
6.02 x 10^23 mol−1.
mol Al = (( 5.75 x 10^24 Al) atoms) ⋅ ((1 mol / 6.02 x 10^23 Al ) atoms)
mol Al= 9.55 mol
Hope this helped you out!
If an object’s mass is 65 kg and it accelerates at a rate of 2 m/s/s, how much force was applied?
Answer:
F = 130 N
Explanation:
We use the formula F = ma
∴ F is force, m is mass and a is acceleration
F = ?
m = 65 kg
a = 2 m/\(s^{2}\)
Substituting the values in the equation:
F = 65 x 2
F = 130 N
What is the density of a plastic ball that has a volume of 6cm3 and a mass of 12g?
Answer:
The answer is 2 g/cm³Explanation:
The density of a substance can be found by using the formula
\(density = \frac{mass}{volume} \\ \)
From the question we have
\(density = \frac{12}{6} \\ \)
We have the final answer as
2 g/cm³Hope this helps you
a scientist is testing if caffeine helps mice run games faster. 10 mice receive 10 mg and 10 get a fake dose, then try to solve the same maze and their time is measured while they do it. what are the following in this experiment
In the experiment in which a scientist is testing if caffeine helps mice run games faster;
the 10 mice are the subject of the experimentthe 10 mg caffeine dose is the independent variablethe 10 fake dose is the control variablethe speed of the mice is the dependent variableWhat is an experiment?
An experiment is a scientific test or study which is performed in order to prove or disprove a hypothesis.
Experiments can also be undertaken in order to further establish or improve upon already established.
Variables are those factors that are studied in an experiment.
In a scientific experiment, the following variables are present:
The independent variable - this is the variable that changes that occur in it produce a change in the variable under studyThe dependent variable - this is the variable that is under study that is affected by the independent variable.The control variable - this is the variable that is kept constant or unchanged.Learn more about experiments at: https://brainly.com/question/25303029
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Can someone help
Me out pls if your good at chemistry
The pair of electrons involved in a covalent bond is called a(n) electron pair, whereas the electrons not involved in bonding are called an unshared or pair.
The pair of electrons involved in a covalent bond is called a bonding pair, whereas the electrons not involved in bonding are called non-bonding pair or lone pair.
In a covalent bond, two atoms share a pair of electrons, which helps to hold the atoms together. These shared electrons are known as the bonding pair because they contribute to the formation of the chemical bond between the atoms.
On the other hand, in some molecules, there may be electrons that are not involved in bonding and are not shared between atoms. These electrons are often found on a single atom and are referred to as non-bonding or lone pairs. Lone pairs are usually depicted as pairs of dots around the atom in Lewis dot structures.
Both the bonding pair and the lone pairs of electrons play important roles in determining the shape, polarity, and reactivity of molecules in covalent compounds.
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what is the value of log1.004?
Answer:
−0.60205999
Explanation:
A solution is created by dissolving 3.44 g of KBr (0.0289 moles) in 6.22 g of H2O (0.346 moles). Calculate the mass percent, mole fraction and molality of KBr in the solution. (12 points).
The mass percent of KBr in the solution is 35.6%, the mole fraction is 0.077, and the molality is 0.083 mol/kg.
To calculate the mass percent of KBr in the solution, first, find the total mass of the solution by adding the masses of KBr and H₂O: 3.44 g + 6.22 g = 9.66 g. Then, divide the mass of KBr by the total mass of the solution and multiply by 100: (3.44 g / 9.66 g) × 100 = 35.6%.
For the mole fraction, divide the moles of KBr by the total moles in the solution: 0.0289 moles / (0.0289 moles + 0.346 moles) = 0.077.
Finally, to find the molality, divide the moles of KBr by the mass of H₂O in kilograms: 0.0289 moles / (6.22 g × 1 kg/1000 g) = 0.083 mol/kg.
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In the formation of sodium chloride, sodium__electrons and chlorine__electrons
Answer:
Sodium has 11 electrons and Chlorine has 17 electrons
Explanation:
You can find the number of electrons by looking at the atomic number
The atomic number is the number above the elements on the periodic table
The atomic number is also the number of protons there are too
hope this helps
a sample of silver has a volume of 6 cm^3 and a massage of 36 grams what's the samples density
Answer:
6g/cm³
Explanation:
Density of a substance can be calculated as follows:
Density = mass (g)/volume (cm³)
According to this question, a sample of silver has a volume of 6 cm³ and a mass of of 36g. The density will be
Density = 36/6
Density = 6g/cm³
it is the minimum amount of solute that can be dissolved in the solvent
A. Salt Solution C. Saturated Solution
B. Sugar Solution D.
Answer:A
Explanation:
A working model used to test a design is called a
Answer:
A working model used to test a design is called a
stop
when an oceanic plate converges with another plate subduction occurs the oceanic plate is pushed beneath the other plate a trench is formed when the plate is being pushed beneath the other what rock can likely result?
When an oceanic plate is subducted beneath another plate during a convergent boundary, the rock that can likely result is metamorphic rock.
Explanation:
This occurs because as the oceanic plate is subducted, it is forced deep into the Earth's mantle where it is subject to extreme heat and pressure. This heat and pressure cause the minerals and rocks in the oceanic plate to recrystallize, creating metamorphic rocks.
Examples of metamorphic rocks that can be formed from subducted oceanic plates include blueschist, eclogite, and amphibolite. These rocks can then be brought to the surface through a process called uplift and can be studied to understand the geological history of the area.
~ Zeph
which of the following does not contain a covalent bond ( please answer asap!! )
Answer:
Option 4
Explanation:
the radioactivity of a sample of cobalt-60 was measured. years later it was found to have 1/8 of the original radioactivity. how many years have passed?
The half life of cobalt -60 is 5.3 years. And if a half is 5.3 yrs long, then a period of 10.6 years have passed.
How to calculate years in a radioactive sample?The activity of a radioactive sample is defined as the rate at which radioactive particles are emitted.
After one life, 1/2 the mass of the original isotope remains. After another half life, 1/4 the mass of the original isotope remains
And if a half is 5.3 yrs long, then a period of 10.6 years have passed.
The half life equation is
A(t) = A0 (1/2) ^ t/t1/2
t1/2 = half life = 5.3 yes
A0 = intial quantity
A(t) = amount left after t years = 1/4 A0
t = time undergone =?
Substitute
1/4 A0 = A0 (1/2) ^ t/5.3
= 1/4 = (1/2) ^ t/5.3
Take the log of
log (1/4) = log { (1/2)^t/5.3}
= log)(1/4) = t/5.3 log (1/2)
Dividend both sides by log (1/2)
log (1/4) / log (1/2) = t/5.3 log(1/2) /log(1/4)
2 = t/5.3
t= 2.53 = 10.6 yrs
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Would helium gas or oxygen gas have a greater entropy?
Entropy is a measure of the degree of randomness or disorder in a system. It is represented by the symbol S and is a thermodynamic property that is often used to describe the behavior of gases.
When it comes to comparing the entropy of helium gas and oxygen gas, it is important to consider the physical properties of each gas. Helium gas is a noble gas that has a relatively low atomic mass and a very low boiling point. It is a monoatomic gas, meaning that each helium atom exists as a single atom rather than a molecule. Because helium has a low atomic mass and is monoatomic, it has a very low entropy.
Oxygen gas, on the other hand, is a diatomic gas, meaning that each molecule of oxygen consists of two oxygen atoms. Oxygen gas has a higher atomic mass than helium, and it also has a higher boiling point. Due to these properties, oxygen gas has a higher entropy than helium gas.
In conclusion, oxygen gas has a greater entropy than helium gas due to its higher atomic mass, its diatomic nature, and its higher boiling point. These factors contribute to a greater degree of randomness and disorder in oxygen gas compared to helium gas, making oxygen gas more likely to behave in unpredictable ways.
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4. How does the sun release its heat?
Answer:
radiation i think
Explanation:
thts why the solar panels can maķe electricity
All toxic substances are hazardous, but all hazardous substances are not toxic. This is because, unlike toxic substances, hazardous materials ______.
All toxic substances are hazardous, but not all hazardous substances are toxic because, unlike toxic substances, hazardous materials can pose risks due to their flammability, reactivity, or corrosivity, rather than their potential to cause harm through poisoning or toxicity.
What are Hazardous Materials?Hazardous materials are not necessarily toxic because they may pose a danger to health and the environment for reasons other than their toxicity. Hazardous materials may have physical or chemical properties that make them flammable, explosive, corrosive, reactive, or pose a risk of radiation exposure. These properties can create hazards such as fire, explosion, chemical burns, or environmental contamination that may cause harm to human health or the environment, even if the substance itself is not toxic. In summary, while all toxic substances are hazardous, not all hazardous substances are toxic.
This is because, unlike toxic substances, hazardous materials may pose a risk due to their physical or chemical properties, such as flammability, reactivity, or corrosiveness, without necessarily being toxic to humans or the environment. For example, gasoline is a hazardous substance due to its flammability, but it may not be toxic unless ingested or inhaled in large quantities.
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in an equilibrium reaction with a Keq of 1×10^8,the-
A) reaction are favored
B) reaction is exothermic
C) products are favored
D) reaction is spontaneous
Levoxyl is a drug used to treat hypothyroidism. If a patient takes one 13 μ
g tablet per day, how many milligrams of Levoxyl are in their 1 month (30 day) supply?
A 30-day supply of Levoxyl at a dosage of one 13 μg tablet per day contains 0.39 mg of Levoxyl.
For a patient taking one 13 μg tablet of Levoxyl per day, the total amount of levothyroxine they are receiving is 13 micrograms. To calculate the total amount in a 30-day supply, we simply multiply this amount by 30.
13 μg/tablet x 1 tablet/day x 30 days = 390 μg
Note that the microgram (μg) is a unit of mass equal to one millionth of a gram, while the milligram (mg) is a unit of mass equal to one thousandth of a gram. To convert μg to mg, we divide by 1000:
390 μg / 1000 = 0.39 mg
Levoxyl is a medication used to treat hypothyroidism, a condition where the thyroid gland doesn't produce enough hormones to regulate the body's metabolism. The active ingredient in Levoxyl is levothyroxine sodium, which is a synthetic form of the hormone thyroxine (T4).
Levoxyl tablets are available in several strengths, ranging from 25 mcg to 300 mcg. The recommended dosage depends on the patient's age, weight, and the severity of their hypothyroidism. In general, adults with normal thyroid function usually require about 1.6 mcg of levothyroxine per kilogram of body weight per day.
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Fritz Haber, a German chemist, discovered a way to synthesize ammonia gas (NH3) by combining hydrogen and nitrogen gases at extremely high temperatures and pressures. a. Write the balanced equation for this reaction. b. If 10 kg of nitrogen combines with excess hydrogen at 550°C and 250 atm, what volume of ammonia gas is produced?
a. The balanced equation for the synthesis of ammonia gas is: N\(_{2}\) + 3H\(_{2}\) → 2NH\(_{3}\).
b. The volume of ammonia gas produced is approximately 1934.74 liters.
To determine the volume of ammonia gas produced, we need to use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
Given:
Mass of nitrogen = 10 kg
Temperature = 550°C = 823 K
Pressure = 250 atm
First, we need to calculate the number of moles of nitrogen. The molar mass of nitrogen (N\(_{2}\)) is approximately 28 g/mol. Using the given mass of nitrogen (10 kg), we can convert it to grams (10,000 g) and then divide by the molar mass to get the number of moles (357.14 mol).
From the balanced equation for the synthesis of ammonia (N\(_{2}\) + 3H\(_{2}\) → 2NH\(_{3}\)), we know that 1 mole of nitrogen reacts to produce 2 moles of ammonia.
Therefore, the number of moles of ammonia produced is twice the number of moles of nitrogen, which is 2 * 357.14 = 714.29 mol.
Now, we can use the ideal gas law to calculate the volume of ammonia gas. Rearranging the equation, V = (nRT) / P, we can plug in the values:
V = (714.29 mol * 0.0821 L·atm/(mol·K) * 823 K) / 250 atm = 1934.74 L.
So, the volume of ammonia gas produced is approximately 1934.74 liters.
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Which is not a chemical element needed to build sugars?
Answer:
Nitrogen
Explanation:
release of additional flammable materials can lead to secondary fires. what might cause the release of additional flammable material?
The release of additional flammable materials can be caused by a variety of factors, including sparks or flames from the initial fire, mechanical or electrical malfunctions, or other sources of ignition.
The release of additional flammable materials can be caused by a number of factors, including:
Damage to storage containers or pipes that contain flammable materials Overheating of equipment or machinery that can ignite flammable materials Improper handling or disposal of flammable materials Sparks or flames from the initial fire spread to other flammable materialsIt is important to be aware of the potential sources of additional flammable materials in order to prevent secondary fires from occurring.
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The Earth has been through many periods of warming and cooling in the past.
Identify what these periods known as. Propose what you would expect the climate on Earth to be like during a warming event and a cooling event.
The periods of warming and cooling that the Earth has been through in the past are known as climate cycles or glacial-interglacial cycles.
During a warming event, we would expect the climate on Earth to be generally warmer, with a higher concentration of greenhouse gases in the atmosphere and higher sea levels due to melting ice caps. This could lead to more extreme weather patterns, including more frequent and intense heatwaves, droughts, and hurricanes.
During a cooling event, we would expect the climate on Earth to be generally colder, with lower concentrations of greenhouse gases in the atmosphere and lower sea levels due to expanding ice caps. This could lead to periods of widespread glaciation and colder temperatures, which could have significant impacts on ecosystems and human populations.
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15.0 moles of gas are in a 8.00 l tank at 23.8 ∘c . calculate the difference in pressure between methane and an ideal gas under these conditions. the van der waals constants for methane are a=2.300l2⋅atm/mol2 and b=0.0430 l/mol .
The difference in pressure between methane and an ideal gas under the given conditions is approximately 5.93 atm.
The difference in pressure between methane (using the van der Waals equation) and an ideal gas can be calculated using the formula:
ΔP = [(an²/V²) - (2bn/V)] * (RT/V)
where:
ΔP is the difference in pressure,
a and b are the van der Waals constants for methane (a = 2.300 L^2·atm/mol^2, b = 0.0430 L/mol),
V is the volume of the gas (8.00 L),
R is the ideal gas constant (0.0821 L·atm/(mol·K)),
T is the temperature in Kelvin (23.8 °C + 273.15 = 296.95 K).
Substituting the given values into the formula:
ΔP = [(2.300 L^2·atm/mol^2 * (15.0 mol)^2) / (8.00 L)^2 - (2 * 0.0430 L/mol * 15.0 mol) / 8.00 L] * (0.0821 L·atm/(mol·K) * 296.95 K)
Simplifying the expression gives:
ΔP = [(2.300 * 15.0^2) / 8.00^2 - (2 * 0.0430 * 15.0) / 8.00] * (0.0821 * 296.95)
Calculating this expression will give the difference in pressure between methane and an ideal gas under the given conditions.
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PLZ HELP
Select the correct answer from each drop-down menu.
Water pollution and air pollution in an area have been steadily increasing. What can students do to address these environmental hazards?
A. Pass Laws
B. Organize seminars
C. Create a tax collection
to educate other students about the deteriorating environmental conditions and the steps needed to
improve the area. Also, encourage other students to volunteer for workshops about
A. recycling and waste disposal
B. Poaching
C. Deforestation
Students can address water and air pollution by organizing seminars to raise awareness and educate others about the issues,
A. Organize seminars
B. recycling and waste disposal
Water pollution and air pollution are significant environmental hazards that require collective efforts to address. Students can play a crucial role in raising awareness and taking action to mitigate these issues. Here are the appropriate answers from the given options:
What can students do to address these environmental hazards?
A. Organize seminars
B. recycling and waste disposal
A. Organize seminars: Students can organize seminars or workshops to educate other students and the community about the deteriorating environmental conditions and the steps needed to improve the area. By sharing knowledge and information, students can raise awareness about the causes and impacts of water and air pollution, as well as the potential solutions to mitigate them. Seminars can provide a platform for experts, scientists, and environmentalists to share their expertise and inspire action.
B. Recycling and waste disposal: Encouraging other students to volunteer for workshops about recycling and waste disposal is an effective step toward addressing environmental hazards. By promoting proper waste management practices, such as recycling, composting, and reducing single-use plastics, students can contribute to minimizing pollution and conserving resources. These workshops can educate students on the importance of responsible waste disposal and provide practical tips and techniques to implement in their daily lives.
In summary, students can address water and air pollution by organizing seminars to raise awareness and educate others about the issues, as well as by promoting recycling and proper waste disposal practices. Through these actions, students can foster a culture of environmental stewardship and inspire positive change in their communities.
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How many grams are in 869 moles of FeCL2?
The first step we have to follow is to find the molar mass of FeCl2 using the atomic masses of each element:
\(\begin{gathered} Fe=55.845g/mol \\ Cl=35.45g/mol\times2=70.9g/mol \\ FeCl_2=126.745g/mol \end{gathered}\)It means that each mole of FeCl2 has a mass of 126.745g/mol.
Use the molar mass to find the mass of the given amount of moles:
\(869molFeCl_2\cdot\frac{126.745gFeCl_2}{1molFeCl_2}=110,141.405gFeCl_2\)It means that there are 110,141.405 grams of FeCl2.
In scientific notation it would be 1.10x10^5g.
there are 110,141.405 grams of FeCl2
Which statement is incorrect for red blood cell?
A. they prefer CO2 at pH 7.35
B. they have a higher affinity for O2 compared to CO2
C. they prefer O2 at pH 7.45
D. they bind CO2 at the tissues because pp CO2 is higher at the tissues
E. they bind O2 at the lungs because pp O2 is higher at the lungs
The incorrect statement for red blood cells is A. They prefer CO2 at pH 7.35. Red blood cells have a higher affinity for CO2 compared to O2. Hence, they bind CO2 at the tissues where the partial pressure of CO2 is higher due to metabolic activity.
Similarly, they bind O2 at the lungs where the partial pressure of O2 is higher due to respiration. Therefore, options D and E are correct.
Moreover, the oxygen dissociation curve of hemoglobin is shifted to the right at lower pH, which means that at pH 7.35, the affinity of hemoglobin for oxygen is decreased, and it is more likely to release oxygen to the tissues. On the other hand, at pH 7.45, the affinity of hemoglobin for oxygen is increased, and it is more likely to bind oxygen in the lungs. Therefore, option C is also correct.
However, option A is incorrect because red blood cells actually prefer CO2 at lower pH (i.e., acidic conditions), not at pH 7.35, which is closer to neutral pH. At lower pH, the affinity of hemoglobin for CO2 is increased, which helps in the transport of CO2 from the tissues to the lungs for elimination.
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