which is a correct way to check that 4,358 divided by 7 is 622 remainder 4

Answer: 408

Step-by-step explanation:

The present worth of Rs 2040 is due 4 years hence reckoning interest at 5% per annum will be Rs 2448.

Simple interest is a way to figure out how much interest will be charged on a sum of money at a specific rate and for a specific duration of time.

Simple interest has a constant principal amount, as opposed to compound interest, which multiplies the interest from the principal of previous years to calculate the interest of the subsequent year.

Given,

Principle amount =  Rs 2040

Time period = 4 years

Rate of interest = 5 %

Simple interest = PRT/100

Simple interest = 2040 × 5 × 4/100 = Rs408

Present worth =  Principle amount + Interest

Present worth = 2040 + 408

Present worth = Rs 2448.

Hence present worth of the amount of Rs2040 in 4 years will be Rs 2448.

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Answer:

13

Step-by-step explanation:

use distance formula \(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\d= \sqrt{(7-2)^2+(7-(-5))^2} =13\)

The future value of the investment is equals to $\(32,582.78\).

The number of monthly payments over 4 years is:

= 4 years x 12 months/year

= 48 months.

We will use future value of an annuity formulae to solve which is FV = PMT x [(1 + r)^n - 1] / r

Plugging in the values, we get:

FV = 650 * [(1 + 0.022/12)^48 - 1] / (0.022/12)

FV = 650 * (0.09190014604/0.00183333333)

FV = 650 * 50.1273524766

FV = 32582.7791098

FV = $32,582.78.

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Answer:

25 remainder 11

Step-by-step explanation:

used a calc

The value of x is 1.75 and y is 5. The solution is obtained using properties of congruent triangles.

What is a congruent triangle?

Two triangles that are congruent will have precisely the same three sides and three angles.

The dimensions of the triangles' sides and angles determine whether two or more triangles are congruent. A triangle's size is determined by its three sides, and its shape by its three angles. Pairs of corresponding sides and corresponding angles in two triangles are said to be equal if they are congruent. They share a similar size and shape. In triangles, there are numerous congruence conditions.

The triangles are congruent by SAS congruency because

AC = CD (Given)

∠ACB = ∠DCE ( Vertically opposite angles)

BC = CE  (Given)

Thus, Triangle ABC ≅ Triangle DEC

Since, the triangles are congruent, therefore

⇒AC = CD

⇒4y-6 = 2x+6   ...(1)

Also, BC = CE

⇒3y+1 = 4x

⇒(3y+1)/4 = x    ...(2)

Now, substituting the value of x in (1), we get,

⇒4y-6 = 2(3y+1)/4+(6)

⇒4y-6 = (6y+2 +24)/4

⇒16y-24 = 6y+2 +24

⇒10y = 50

⇒y = 5

Now putting the value of y in (2), we get

⇒(3(2)+1)/4 = x

⇒7/4 = x

⇒ x = 1.75

Hence, the value of x is 1.75 and y is 5.

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The capacity of the bottle is 16 ounces

From the question, we have the following parameters that can be used in our computation:

A water bottle is 3/4 full.

When half of the water is drained, we have

Remainder = 1/2 * 3/4x

Evaluate

Remainder = 3/8x

Where x is the capacity of the bottle

We understand that 6 ounces of water remain in the bottle.

This means that

3/8x = 6

So, we have

x = 8 * 6/3

Evaluate

x = 16

Hence. the capacity of the bottle is 16 ounces

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Before doing the question, let's recall the quadratic formula which is used to find the roots of a quadratic equation ;

For any quadratic equation of the form ax² + bx + c = 0 , it's roots are given by the quadratic formula as :

Where , D = b² - 4ac (Discriminant)

Now , simplifying the equation :

\({:\implies \quad \sf -3\{(x)^{2}+2^{2}-2\times 2\times x\}+17=0\quad \qquad \{\because (a-b)^{2}=a^{2}+b^{2}-2ab\}}\)

\({:\implies \quad \sf -3(x^{2}+4-4x)+17=0}\)

\({:\implies \quad \sf -3x^{2}-12+12x+17=0}\)

\({:\implies \quad \sf -3x^{2}+12x+5=0}\)

Dividing both sides by -1 will yield :

\({:\implies \quad \sf 3x^{2}-12x-5=0}\)

Now , it's in the form of the standard quadratic equation , where a = 3 , b = -12 , c = 5 , and D = (-12)² - 4 × 3 × -5 = 144+60 = 204

Now, By quadratic Formula ;

\({:\implies \quad \sf x=\dfrac{-(-12)\pm \sqrt{204}}{2\times 3}}\)

\({:\implies \quad \sf x=\dfrac{12\pm 2\sqrt{51}}{2\times 3}}\)

\({:\implies \quad \sf x=\dfrac{\cancel{2}(6\pm \sqrt{51})}{\cancel{2}\times 3}}\)

\({:\implies \quad \bf \therefore \quad \underline{\underline{x=\dfrac{6\pm \sqrt{51}}{3}}}}\)

Answer:

d = 4.8 units

Step-by-step explanation:

( \(x_{1}\) , \(y_{1}\) )

( \(x_{2}\) , \(y_{2}\) )

d = \(\sqrt{(x_{2} -x_{1} )^2 + (y_{2} -y_{1} )^2}\)

~~~~~~~~~~~

( - 3, 2.6 )

( - 3, - 2.2 )

d = \(\sqrt{(-3+3)^2 +(-2.2-2.6)^2 }\) = √(- 4.8)² = 4.8 units

Answer:

42 square feet.

Step-by-step explanation:

Answer:

3 rounds of bingo

Step-by-step explanation:

Let x represent the number of bingo rounds

For adults, the total cost can be represented by 2x + 13, since it is $2 per game and there is a $13 entry fee

For children, the cost can be represented by 3x + 10, since it is $3 per round and there is a $10 entry fee

To find how many rounds are needed to make the cost the same, set these expressions equal to each other and solve for x:

2x + 13 = 3x + 10

13 = x + 10

3 = x

So, costs will be the same with 3 rounds of bingo

The missing amounts for Work in Process - Blending Department are: 25,700 units, and $70,944 for direct materials.

Cost of Production Report

Bavarian Chocolate Company processes chocolate into candy bars.

The process begins by placing direct materials (raw chocolate, milk, and sugar) into the Blending Department.

All materials are placed into production at the beginning of the blending process.

After blending, the milk chocolate is then transferred to the Molding Department, where the milk chocolate is formed into candy bars.

The following is a partial work in process account of the Blending Department at October 31:

ACCOUNT Work in Process—Blending Department ACCOUNT NO.

Date Item Debit Credit Balance

Debit Balance

Credit

October 1 Bal., 2,300 units, 3/5 completed 46,368

31 Direct materials, 26,000 units 429,000 475,368

31 Direct labor 100,560 575,928

31 Factory overhead 48,480 624,408

31 Goods transferred, 25,700 units.

1. Prepare a cost of production report, and identify the missing amounts for Work in Process—Blending Department. If an amount is zero enter "0". If required, round your cost per equivalent unit answers to the nearest cent.

Bavarian Chocolate Company

Cost of Production Report—Blending Department

For the Month Ended March 31

Bavarian Chocolate Company

Cost of Production Report—Blending Department

For the Month Ended October 31

Equivalent Units Schedule

Direct Materials Conversion Costs

Units to be accounted for:

Work in process, October 1 (3/5 completed) 2,300 2,300

Units started in October 26,000 26,000

Total units to be accounted for 28,300 28,300

Units accounted for:

Goods transferred to the Molding Department (25,700 units × 100%) 25,700 25,700

Work in process, October 31 (1/5 completed):

Total units accounted for:

Costs to be accounted for:

Direct materials cost $429,000

Direct labor cost $100,560

Factory overhead cost $48,480

Total costs to be accounted for $578,040

Costs accounted for:

Direct materials cost (26,000 units × $15 per unit) $390,000

Direct labor cost (2,300 units × $44 per unit) 101,200

Factory overhead cost (2,300 units × $21.12 per unit) 48,576

Total costs accounted for $539,776

Cost per Equivalent Unit:

Direct materials cost ($429,000 ÷ 28,300 units) $15.16

Direct labor cost ($100,560 ÷ 2,300 units) $43.74

Factory overhead cost ($48,480 ÷ 2,300 units) $21.12

Total cost per equivalent unit $80.02

Work in Process—Blending Department

Direct Materials Conversion Costs Total

Balance, October 1 $27,820 $18,548 $46,368

Current costs $352,380 $222,548 $574,928

Total cost $380,200 $241,096 $621,296

Less: Goods transferred to the Molding Department (25,700 units × $80.02 per unit) (2) $2,048 $2,048

Balance, October 31 (2) $378,152 (2) $239,048 (2) $617,200

(1) Equivalent units of direct materials and conversion costs have been calculated based on the weighted-average method.

(2) The missing amounts for Work in Process—Blending Department are:

Units, October 31: 2,600 units (28,300 total units – 25,700 transferred units).

Direct Materials, October 31: $352,380 (current costs) - $390,000 (costs accounted for) = -$37,620 (overallocated)

Conversion Costs, October 31: $222,548 (current costs) - $241,096 (costs accounted for) = -$18,548 (overallocated).

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The capacity of this swimming pool is between B. 500 gallons to 1,000 gallons.

Capacity refers to the product of the length, width, and height of a three-dimensional object or space.

The capacity of an object means the same as its volume.

Olympic-size swimming pools have the following standard dimensions:

Length = 50 m

Width = 25 m

Height = 2 m

Capacity of an Olympic swimming pool = 2,500 m³ (50 x 25 x 2)

= 660,000 gallons (2,500 x 1,000 ÷ 3.785)

An interval estimate shows the lower and upper limits.

6 x 105 gallons = 630 gallons

Thus, the capacity of the swimming pool is Option B.

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A. 100 gallons to 500 gallons

B. 500 gallons to 1,000 gallons

C. 1,000 gallons to 1,500 gallons

D. 1,500 gallons to 2,000 gallons

So in this case f(x) is number of pollinated flowers and x is the days. First you will need to determine the number of flowers pollinated at days 4 and 10 and the days in between.  f(4)= 3(4^2)= 3*16 = 48  f(5)= 3(5^2)= 3*25 =75  f(6)= 3(6^2)=3*36=108  f(7)= 3(7^2)=3*49=147  f(8)= 3(8^2)=3*64=192  f(9)= 3(9^2)= 3*81=243  f(10)= 3(10^2)=3*100=300    Now we need to find the average increase, so that will be the average of the differences between days  [(75-48)+(108-75)+(147-108)+(192-147)+(243-192)+(300-243)]/6  =(27+33+39+45+51+57)/6=42

Answer:

39 3/8 ft ^2

Step-by-step explanation:

To find the area of a rectangle, multiply the length times the width.

A = l*w

  = 7 1/2  * 5 1/4

Change the mixed numbers to improper fractions.

A = 15/2 * 21/4

    =315/8

Change back to a mixed number.

8 goes into 315 39 times with 3 left over.

 = 39 3/8

Answer:

(you can round to 39.4)

Step-by-step explanation:

Find the area of the rectangle shown

7 1/2 ft

5 1/4ft

7 1/2 = 7.5 ft

5 1/4 = 5.25 ft

Area = L x W

Area = 7.5 x 5.25

Area = 39.375

Answer:

a) r(t) = (10, 5, -5) + (5, 5, 0)*t

b) (0, -5, -5)

Step-by-step explanation:

a) 2x + 4 -2y -5 = -3z -6

2x - 2y +3z +5 =0

(10, 5, -5)

(15, 10, -5)

(5, 5, 0)

r = (10, 5, -5) + (5, 5, 0)*t

b) The yz plane is given by the equation x = 0.

x = 0  in the vector equation of a straight line if and only if  t = -2, than r ( - 2) = (0, -5, -5) is the desired intersection point.

The best way to represent histograms is by decreasing to increasing order.

The mean is the arithmetic mean and is calculated by adding a group of numbers and dividing by the count of those numbers. For example, the average of 2, 3, 3, 5, 7, and 10 is 30 divided by 6, which is 5.

Given the values:

50 42 32 35 41 44 24 46 31 47 36 32 30 44 22 47 31 56 28 37 49 28 42 38 45

We have that:

(22+24+28+28+30+31+31+32+32+35+36+37+38+41+42+42+44+44+45+46+46+47+47+49+50)/25=37.88.

The average age that a large construction company wants to know is 38.

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a. The expected value is $12

b. She is expected to win money

To find the expected value of playing the game, we need to calculate the average value of the winnings or losses.

(a) Expected Value:

The probability of drawing an even-numbered card is 5/10 (since there are 5 even-numbered cards out of 10), and the probability of drawing an odd-numbered card is also 5/10.

If Leila draws an even-numbered card, she wins an amount equal to the value of the card. So the expected value of winning is:

(5/10) * (2 + 4 + 6 + 8 + 10) = (5/10) * 30 = 15/10 = $15

If Leila draws an odd-numbered card, she loses $6. So the expected value of losing is:

(5/10) * (-6) = -3

To find the overall expected value, we subtract the expected value of losing from the expected value of winning:

Expected value = (15) + (-3) = 12

Therefore, the expected value of playing the game is $12

(b) In the long run, after playing the game many times, Leila can expect to lose money. Since the expected value is positive $12 , on average, she will win $12 per game.

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Answer:

Step-by-step explanation:

Draw a picture. You have an isosceles right triangle. Each leg is 50 ft.

tanθ = 50/50 = 1

θ = arctan(1) = 45°

Among the given options, 90 degrees (option A) is not a solution to the equation sin(2θ) = 1. The equation sin(2θ) = 1 represents the values of θ for which the sine of twice the angle is equal to 1. To determine which option is not a solution, we need to evaluate each choice.

A) 90 degrees: If we substitute θ = 90 degrees into the equation sin(2θ) = 1, we get sin(180 degrees) = 1. However, sin(180 degrees) is actually 0, not 1. Therefore, 90 degrees is not a solution to the equation sin(2θ) = 1.

B) 45 degrees: Substituting θ = 45 degrees gives sin(90 degrees) = 1, which is true. Therefore, 45 degrees is a solution to the equation sin(2θ) = 1.

C) 225 degrees: When we substitute θ = 225 degrees, we get sin(450 degrees) = 1. However, sin(450 degrees) is also 0, not 1. Thus, 225 degrees is not a solution to sin(2θ) = 1.

D) -135 degrees: Similarly, substituting θ = -135 degrees gives sin(-270 degrees) = 1. However, sin(-270 degrees) is 0, not 1. Hence, -135 degrees is not a solution to the equation sin(2θ) = 1.

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Answer:

I think 4

Step-by-step explanation:

1/3 is how many are yellow. so if u do 12/3=4

Answer:

4

Step-by-step explanation:

1/3 is equivalent to 4×1 and 2/3 is equivalent to 4×2 and 3/3 is equivalent to 4×3 which equals 12 so there are 4 counters that are yellow.

Answer:

The claim that all ages have purchase rates proportional to their driving rates is false.

Step-by-step explanation:

The complete question is:

A random sample of 160 car accidents are selected and categorized by the age of the driver determined to be at fault. The results are listed below. The age distribution of drivers for the given categories is 18% for the under 26 group, 39% for the 26-45 group, 31% for the 45-65 group, and 12% for the group over 65. Calculate the chi-square test statistic used to test the claim that all ages have crash rates proportional to their driving rates.

Age      >26     26-45       46-65      45<

Drivers 66    39            25          30

 A) 95.431

     B)101.324

     C)85.123

     D)75.101

Solution:

In this case we need to test whether there is sufficient evidence to warrant rejection of the claim that all ages have crash rates proportional to their driving rates.

A Chi-square test for goodness of fit will be used in this case.

The hypothesis can be defined as:

H₀: The observed frequencies are same as the expected frequencies.

Hₐ: The observed frequencies are not same as the expected frequencies.

The test statistic is given as follows:

\(X^2=\left \{ { \right. \frac{(O-E)^2}{E}\left\)

The values are computed in the table.

The test statistic value is 75.10.

The degrees of freedom of the test is:

n - 1 = 4 - 1 = 3

Compute the p-value of the test as follows:

p-value < 0.00001*

Use a Chi-square table.

p-value < 0.00001 < α = 0.05.

So, the null hypothesis will be rejected at any significance level.

Thus, there is sufficient evidence to warrant rejection of the claim that ages have crash rates proportional to their driving rates.

Chandler ended up 8 feet below sea level. The negative sign indicates that his final position is below sea level. This means that he has descended further into the lake compared to the starting point on the cliff.

Chandler started on the cliff at 32 feet above sea level. When he jumped for 40 feet, we need to determine the final position in relation to sea level.

Since Chandler jumped down, the distance below sea level will be calculated as a negative value. To find how far below sea level Chandler ended up, we subtract the jump distance (40 feet) from the starting height (32 feet above sea level):

32 feet - 40 feet = -8 feet

It's important to note that negative values are used here to represent the direction and magnitude of Chandler's descent relative to sea level

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Answer:

-8 feet

Step-by-step explanation:

Given:

The roots of the quadratic function are:

X = -1

X = 4

Therefore, we can express the function as follows:

Answer:

f(x) = (x − 4)(x + 1)

Answer:

what the expression, lmk in comments and then i will help you :)

Step-by-step explanation:

Answer:

a. A hen needs 9,125 grasshoppers per year

b. 3,330,625 grasshoppers are needed for a year's supply of hens for the farmer each year

c. The total mass, in kilograms, of the grasshoppers needed to feed all the hens for one year 3330.625 kg

d. 99918.750 kg of soybeans are needed to feed all the grasshoppers for one year.

Step-by-step explanation:

a. To calculate the number of grasshoppers a hen needs per year.

There are 365 days days in a year.

From the question,  1 hen eats 25 grasshoppers/day

If 1 hen eats 25 grasshoppers per day, then

1 hen will eat 25 × 365 grasshoppers per year

25 × 365 = 9125

Hence, a hen needs 9,125 grasshoppers per year.

b. To determine how many grasshoppers are needed for a year's supply of hens for the farmer each year

From the question, The farmer lives on 1 hen/day for a year.

That is, for a year, the farmer lives on 365 × 1 hen = 365 hens

Now, we will determine how many grasshoppers 365 hens will need for a year.

Since, a hen needs 9,125 grasshoppers per year

Then, 365 hens will need 365 × 9125 grasshoppers per year

365 × 9125 = 3330625 grasshoppers

Hence, 3,330,625 grasshoppers are needed for a year's supply of hens for the farmer each year.

c. To determine the total mass, in kilograms, of the grasshoppers needed to feed all the hens for one year

From the question, 1,000 grasshoppers have a mass of 1 kg.

That is, 1,000 grasshoppers have a mass of 1000 g

(NOTE: 1000g = 1kg)

If 1,000 grasshoppers have a mass of 1000 g

Then, 1 grasshopper will have a mass of (1 × 1000) /1000 = 1 g

From b., the total number of grasshoppers needed to feed all the hens for one year is 3,330,625 grasshoppers.

Now, we will determine the mass of 3,330,625 grasshoppers

1 grasshopper have a mass of 1 g

∴ 3,330,625 grasshoppers will have a mass of (3,330,625 × 1) / 1 = 3,330,625 g

Now, we will convert this to kilograms (kg)

If 1000 g = 1 kg

Then, 3,330,625 g = (3,330,625 × 1) / 1000 = 3330.625 kg

Hence, the total mass, in kilograms, of the grasshoppers needed to feed all the hens for one year 3330.625 kg.

d. To determine how many kilograms of soybeans are needed to feed all the grasshoppers for one year

From the question, 1 grasshopper requires about 30 g of soy/yr

From b., 3,330,625 grasshoppers are needed for a year's supply of hens for the farmer each year

If 1 grasshopper requires about 30 g

Then, 3,330,625 grasshoppers will require (3,330,625 × 30) / 1 = 99918750 g of soy/yr

Now, we will convert this to kilograms

If 1000 g = 1 kg

Then, 99918750g = (99918750 × 1) / 1000 = 99918.750 kg

Hence, 99918.750 kg of soybeans are needed to feed all the grasshoppers for one year.

Answer:

The slope is 1/3 because of rise/run

Step-by-step explanation:

Answer:

1/3

Step-by-step explanation:

Because slope equation is vertical over horisantal so it would be 1 and 3.

Hope this helps!

Answer:

81.2 feet (nearest tenth)

Step-by-step explanation: