Which has a quotient of 1.66? Use number sense to find the answer. Select all that apply. A. 4.15÷2.5 B. 0.415÷0.25 C. 41.5÷0.25 D. 4.15÷0.25 E. 0 . 415 ÷ 2 . 5

help plssssssssssss

Answer:

x = 50

Step-by-step explanation:

Since this is a quadrilateral, the sum is 360 degrees

2x+x+10 + 3x+x = 360

Combine like terms

7x+10 =360

Subtract 10 from each side

7x+10-10 = 360-10

7x = 350

Divide by 7

7x/7 = 350/7

x = 50

Answer:

\(x = 50\)

Step-by-step explanation:

Sum of the interior angles in a quadrilateral

= 360°

Let's solve now

\(x + 10 + 3x + x + 2x = 360 \\ 7x + 10 = 360 \\ 7x = 360 - 10 \\ 7x = 350 \\ \frac{7x}{7} = \frac{350}{7} \\ x = 50\)

hope this helps you.

Answer:

2 times

Step-by-step explanation:

the probability to get a 6 is 1/6. multiply it by 12/1, to get 12/6 which is 2

Answer:

SA = 397 m^2

Step-by-step explanation:

a = 10m

h = 14m

SA=a^2+2a \(\sqrt{\frac{a^2}{4} + h^2}\)

SA = (10)^2+2(10) \(\sqrt{\frac{(10)^2}{4} + (14)^2}\)

SA = 397.32137 = 397 m^2

Answer: which one do you prefer

Step-by-step explanation:

The probability of selecting an orange marble is 0.33.

Option B is the correct answer.

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

We have,

The number of times each marble is selected.

Green = 4

Black = 6

Orange = 5

Total number of times all marbles are selected.

= 4 + 6 + 5

= 15

Now,

The probability of selecting an orange marble.

= 5/15

= 1/3

= 0.33

Thus,

The probability of selecting an orange marble is 0.33.

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Answer:2.5%

Step-by-step explanation:

2.5% of the school has sibloings

55+45=100

100÷40=2.5

The expression (5a)(3a + 2) simplifies to 15a^2 + 10a. This is obtained by multiplying 5a with both terms inside the parentheses using the distributive property. The final result cannot be further simplified. So, Option B is correct. Option B.

To simplify the given expression, (5a)(3a + 2), we apply the distributive property to distribute the factor 5a to both terms inside the parentheses. This involves multiplying 5a by each term separately.

First, we multiply 5a by 3a. Multiplying these two terms gives us 15a^2, where the coefficient 15 comes from multiplying 5 by 3 and the variable a is squared due to the multiplication of two a's.

Next, we multiply 5a by 2. This multiplication results in 10a, where the coefficient 10 comes from multiplying 5 by 2, and the variable a remains unchanged.

Combining the two simplified terms, we have 15a^2 + 10a. This expression cannot be further simplified because there are no like terms to combine.

The term 15a^2 represents the enlarged area of the mural, obtained by multiplying the lengths of the sides of the original square mural (side length a) by the factor 5 and squaring the variable a. The term 10a represents an additional area added during the enlargement process, obtained by multiplying the side length a by the factor 2.

In conclusion, the simplified form of (5a)(3a + 2) is 15a^2 + 10a. So OptioN B is correct.

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Answer:One apple is 1.17

One pear 0.25

See below :)

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

7 x 5 =  35

35 + 3 = 38

Answer:

Step-by-step explanation:

From the given information:

The ratio of the limiting floor area to lot area is 0.60 to 1

i.e.

= 0.60 : 1

For instance, let's take that the remodel size as p sq.ft on 1140 sq.ft

Then, the ratio = \(\dfrac{p}{11400}\)

The proportion of these equations is as follows:

\(\dfrac{p}{11400} = \dfrac{0.60}{1}\)

\(p \times 1 = 11400 \times 0.60\)

\(p = 11400 \times \dfrac{60}{100}\)

\(p =\dfrac{ 11400 \times 60}{100}\)

\(p =\dfrac{ 114 \times 100 \times 60}{100}\)

\(p = 114 \times 60\)

p = 6840 sq ft

Thus, the maximum allowable size of a remodeled house is 6840 sq.ft

b.

Recall that, the size of the home remodeled by limiting floor to lot area is

0.60:1

Then the proportion equation form is as follows:

\(\dfrac{0.60}{1}= \dfrac{5040}{x}\)

By cross multiplying

\(0.60 \times x = 5040 \times 1\)

\(x = \dfrac{5040 \times 1}{0.60 }\)

\(x = \dfrac{5040 \times 100}{60 }\)

\(x = \dfrac{84 \times 60 \times 100}{60 }\)

\(x =84 \times 100\)

x = 8400 sq.ft

Hence, the size of lot area is 8,400 sq.ft

We know the value of x and y,

x = 6 and y = -1 [Given]

Substitute the value,

Answer:214.29

Step-by-step explanation:600 divided by 2.8

possibly the answer

Answer:

its c on edge

Step-by-step explanation:

Answer:

C. The risk of dying prematurely declines as people become more physically active.

Explanation: This is the correct answer on Edge 2021, just did the assignment. Hope this helps ^-^.

Answer:

∠ C ≈ 73.7°

Step-by-step explanation:

using the sine ratio in the right triangle

sin C = \(\frac{opposite}{hypotenuse}\) = \(\frac{AT}{CT}\) = \(\frac{48}{50}\) , then

∠ C = \(sin^{-1}\) ( \(\frac{48}{50}\) ) ≈ 73.7° ( to the nearest tenth )

60,20,,30 is the answer

A discrete probability distribution (c) is a listing of all possible values of a random variable (A) and assigns a probability to each possible value (B). It does not have a specific range, such as -1 to +1 (C), and the values it can assume depend on the nature of the random variable and its associated probabilities. The parameters of the distribution, such as mean and variance, affect the shape and characteristics of the distribution (D).

(a) The binomial distribution for which a normal approximation would be most acceptable is (D) n=400, pi=0.02. The normal approximation to the binomial distribution becomes more accurate as the sample size (n) increases and the probability of success (pi) is not too close to 0 or 1. In this case, with n=400 and pi=0.02, both conditions are satisfied, making the normal approximation suitable.

(b) The statement that is most nearly correct concerning confidence intervals is (B) we use the Student's t distribution when the standard deviation is unknown. The confidence interval is used to estimate a range of values within which the true population parameter is likely to fall. When the population standard deviation is unknown, which is often the case, the sample standard deviation is used instead. In such situations, the Student's t distribution is used to account for the additional uncertainty introduced by estimating the standard deviation from the sample. The z distribution is used when the population standard deviation is known, or when the sample size is large enough to rely on the Central Limit Theorem.

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A differential equation is a mathematical equation that relates a function with its derivatives. It describes the relationship between a quantity and its rate of change in continuous time or space.

To find the value of k for which the constant function x(t) = k is a solution of the given differential equation, we substitute x(t) = k into the differential equation and check if it satisfies the equation.

So, we have:

312 dx/dt - 5x - 7 = 0

Substituting x(t) = k, we get:

312 d(k)/dt - 5k - 7 = 0

Since x(t) = k is a constant function, its derivative is zero. Therefore, d(k)/dt = 0.

Substituting d(k)/dt = 0, we get:

-5k - 7 = 0

Solving for k, we get:

k = -7/5

Therefore, the value of k for which the constant function x(t) = k is a solution of the differential equation 312 dx/dt - 5x - 7 = 0 is -7/5.

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Answer:

8 cars

Step-by-step explanation:

8*50= 400

Answer:

\(\sf y =\dfrac{-1}{5}x-\dfrac{1}{4}\)

Step-by-step explanation:

Here, m is the slope and b is the y-intercept.

Substitute the values of m and b in the above equation.

  \(\sf m = \dfrac{-1}{5} \\\\b = \dfrac{-1}{4}\)

       Slope y-intercept form:

              \(\sf \boxed{y=\dfrac{-1}{5}x - \dfrac{1}{4}}\)

Split infinitives are grammatical structures where the words "to" and "infinitive" are separated. Move the phrase separating the infinitive from the split position to get rid of the split infinitive.

In the given question we have to explain, what is a split infinitive and how we fix it.

As we know that,

Split infinitives are grammatical structures in which an adverb or adverbial phrase separates the "to" and "infinitive" halves of what is more often known as the to-infinitive in modern linguistics.

A split infinitive is created when the word "to" and the infinitive verb are separated by an adverb. To eliminate the split infinitive, move the phrase that divides it from the split place.

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Answer:

3/5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(8-5)/(3-(-2))

m=3/(3+2)

m=3/5

====================================================

Work Shown:

n = number of nickels

22-n = number of dimes

5n = value of the nickels in cents

10(22-n) = value of the dimes in cents

5n+10(22-n) = total value in cents

5n+10(22-n) = 180

5n+220-10n = 180

-5n+220 = 180

-5n = 180-220

-5n = -40

n = -40/(-5)

n = 8 is the number of nickels

22-n = 22-8 = 14 is the number of dimes

-----------------

Check:

8 nickels = 8*5 = 40 cents

14 dimes = 14*10 = 140 cents

8 nickels + 14 dimes = 40 cents + 140 cents = 180 cents = $1.80

8 nickels + 14 dimes = 22 coins total

The answers are confirmed.

Answer:

the answer is C, I got it too from the website, I got the answer from it

Carl Friedrich Gauss, the "Prince of Mathematicians," made groundbreaking contributions to number theory, geometry, physics, and statistics, leaving a lasting impact on the field of mathematics.

We have,

Carl Friedrich Gauss, known as the "Prince of Mathematicians," made significant contributions to number theory, geometry, physics, and statistics.

He formulated the fundamental theorem of arithmetic, developed concepts in differential geometry such as intrinsic curvature and Gaussian curvature, and formulated Gauss's law for electric fields.

Gauss's work laid the foundation for modern mathematics and his emphasis on rigor and precision influenced subsequent generations of mathematicians.

His legacy as one of the greatest mathematicians of all time is based on his profound theorems, laws, and concepts that continue to shape the field.

Thus,

Carl Friedrich Gauss, the "Prince of Mathematicians," made groundbreaking contributions to number theory, geometry, physics, and statistics, leaving a lasting impact on the field of mathematics.

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Idon't Know the answer srry

Answer:

The minimum number of pounds of cans they need to collect is 77. I hope this helps you.

Step-by-step explanation:

You would have to divide $27.20 divided by $0.35 and you would end with 77.7142857143 but basically 77.

The global maximum value of f(x, y) on the closed triangular region occurs at either (4, 0) or (0, 4), both of which have a value of 16.

The global minimum value of f(x, y) occurs at the critical point (0, 0), with a value of 0

To find the Optimization of multivariable functions i.e, global extreme values of \(f(x, y) = x^2 - xy + y^2\) on the closed triangular region in the first quadrant bounded by the lines x = 4, y = 0, and y = x,

We need to first find the critical points of the function in the interior of the region and evaluate the function at these points, and then evaluate the function at the boundary points of the region.

To find the critical points of the function in the interior of the region, we need to solve the system of partial derivatives:

\(df/dx = 2x - y = 0\\f/dy = -x + 2y = 0\)

Solving this system of equations, we get the critical point (x, y) = (0, 0).

To check whether this point is a maximum or a minimum, we need to evaluate the second partial derivatives of f:

\(d^2f/dx^2 = 2\\d^2f/dy^2 = 2\\d^2f/dxdy = -1\)

The determinant of the Hessian matrix is:

\(d^2f/dx^2 \times d^2f/dy^2 - (d^2f/dxdy)^2 = 4 - 1 = 3\)

Since this determinant is positive and \(d^2f/dx^2 = d^2f/dy^2 = 2\) are both positive, the critical point (0, 0) is a local minimum.

Next, we need to evaluate the function at the boundary points of the region. These are:

(4, 0): f(4, 0) = 16

(0, 0): f(0, 0) = 0

(0, 4): f(0, 4) = 16

(y, y) for 0 ≤ y ≤ 4: \(f(y, y) = 2y^2 - y^2 = y^2\)

Therefore, the global maximum value of f(x, y) on the closed triangular region occurs at either (4, 0) or (0, 4), both of which have a value of 16.

The global minimum value of f(x, y) occurs at the critical point (0, 0), with a value of 0.

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