Which group on the periodic table is a noble gas most likely to bond with?

Answer:

(A) It matches the universal pH indicator and is indicating the proper pH.

Explanation:

Correct on edge 2021

Given the data from the question, the correct statement is:

This is simply a measure of the acidity / alkalinity of a solution.

The pH measures the hydrogen ion concentration while the pOH measures the hydroxide ion concentration

The pH scale is a scale that gives an understanding of the variation of the acidity / alkalinity of a solution.

The scale ranges from 0 to 14 indicating:

These are devices / equipment used to indicate if a solution is acidic, neutral or basic.

From the question given above, we were told that the universal and the cabbage pH indicator gives the same result.

Therefore, we can conclude that the cabbage indicator is indicating the proper pH (Option A)

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Answer:

-BaCl₂.

-KBr.

-C₆H₅COOH.

-C₆H₁₂O₆.

Explanation:

As the problem states, conductivity is related to the number of ions in solution, the larger the number of ions, the greater the conductivity.

Meaning the ranking from most conductive to least conductive is:

Answer:

7.93E24 molecules of water

Explanation:

determine no. of moles of water: 237 g/18 g/mole H2O= 13.17 moles H2O

13.17 moles H2O x 6.02E23 molecules/mole= 7.93E24 molecules of water

Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 7.93×10²⁴  molecules are in 237 g (about a cup) of water. The correct option is option E.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.

Mathematically,

number of moles of water=237 g÷18 g/mole

number of moles of water = 13.17 moles

number of atoms/molecules=number of moles × 6.022×10²³(Avogadro number)

molecules of water=13.17 moles x 6.02×10²⁴

molecules of water=7.93×10²⁴  molecules of water

Therefore, 7.93×10²⁴  molecules are in 237 g (about a cup) of water. The correct option is option E.

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To measure reaction heat under isochoric conditions, a bomb calorimeter is needed.

This device is designed to maintain a constant volume (isochoric) during the reaction, allowing for accurate measurement of reaction heat. To improve the accuracy of the coffee cup calorimeter for measuring reaction heat under isobaric conditions, a modification that could be made is to use a stirring device to ensure uniform mixing of the reactants and to minimize heat loss to the surroundings.

Additionally, a lid with a small hole could be placed over the top of the calorimeter to prevent heat loss while still allowing for pressure equalization. These modifications would help to minimize errors in heat measurement and improve the accuracy of the results obtained.

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Answer:

Explanation:

The answer is 32°F or 0° Celsius.

Hope it helped you.

(a) the molecular formula of the compound is C₆H₁₂.

(b)  the molecular formula of the compound is NH₂Cl.

(a) Given the empirical formula CH₂ and a molar mass of 84 g/mol, we need to determine the molecular formula. To do so, we need to find the factor by which the empirical formula needs to be multiplied to achieve the given molar mass.

The empirical formula CH₂ has a molar mass of 14 g/mol (12 g/mol for carbon + 2 g/mol for hydrogen).

To find the factor, we divide the molar mass by the empirical formula mass:

Factor = (molar mass) / (empirical formula mass) = 84 g/mol / 14 g/mol = 6

Therefore, the molecular formula is obtained by multiplying the empirical formula by the factor:

CH₂ × 6 = C₆H₁₂

Thus, the molecular formula of the compound is C₆H₁₂.

(b) Given the empirical formula NH₂Cl and a molar mass of 51.5 g/mol, we follow a similar approach.

The empirical formula NH₂Cl has a molar mass of 51.5 g/mol (14 g/mol for nitrogen + 2 g/mol for each hydrogen + 35.5 g/mol for chlorine).

To find the factor, we divide the molar mass by the empirical formula mass:

Factor = (molar mass) / (empirical formula mass) = 51.5 g/mol / 51.5 g/mol = 1

Therefore, the molecular formula is the same as the empirical formula: NH₂Cl

Hence, the molecular formula of the compound is NH₂Cl.

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The theoretical yield of Fe is 335.1 g.

54.0 g of C is needed.

The volume of CO2 produced is 0.992 L.

198.05 g of CO2 was produced.

The percent yield of the reaction is 75.2%.

The balanced chemical equation for the reaction is:

2Fe2O3 + 3C → 4Fe + 3CO2

Using the equation, we can calculate the theoretical yield of Fe and the amount of C needed.

To calculate the theoretical yield of Fe:

Convert the given mass of Fe2O3 to moles:

480 g Fe2O3 x (1 mol Fe2O3/ 160 g Fe2O3) = 3.0 mol Fe2O3

Use stoichiometry to find the moles of Fe produced:

2 mol Fe2O3 → 4 mol Fe

3.0 mol Fe2O3 x (4 mol Fe / 2 mol Fe2O3) = 6.0 mol Fe

Convert moles of Fe to grams:

6.0 mol Fe x (55.85 g Fe / 1 mol Fe) = 335.1 g Fe

To calculate the amount of C needed:

Use stoichiometry to find the moles of C needed:

2 mol Fe2O3 → 3 mol C

3.0 mol Fe2O3 x (3 mol C / 2 mol Fe2O3) = 4.5 mol C

Convert moles of C to grams:

4.5 mol C x (12.01 g C / 1 mol C) = 54.0 g C

To find the volume of CO2 produced, we need to calculate the number of moles of CO2 produced using stoichiometry.

Use stoichiometry to find the moles of CO2 produced:

2 mol Fe2O3 → 3 mol CO2

3.0 mol Fe2O3 x (3 mol CO2 / 2 mol Fe2O3) = 4.5 mol CO2

Convert moles of CO2 to volume using the ideal gas law:

PV = nRT

V = nRT/P

V = (4.5 mol) (0.0821 L atm mol^-1 K^-1) (298 K) / (1 atm)

V = 0.992 L

To find the mass of CO2 produced:

Use the molar mass of CO2 to convert from moles to grams:

4.5 mol CO2 x (44.01 g CO2 / 1 mol CO2) = 198.05 g CO2

To calculate the percent yield of the reaction:

Use the given mass of Fe (252 g) and the theoretical yield of Fe (335.1 g) to calculate the percent yield:

Percent yield = (actual yield / theoretical yield) x 100%

Percent yield = (252 g / 335.1 g) x 100%

Percent yield = 75.2%

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Answer:

C3H8 + 5O2 = 3Co2 + 4 H2o

Explanation:

we can balance this equation by algebric method ( ABC method)

Answer:

83.86g/mol is the molecular weight of the acid

Explanation:

Molecular weight is the ratio of mass in grams and moles present. That means we need to determine the mass in grams (400.0mg = 0.400g) and the moles of the acid that can be detemined by using its reaction with NaOH:

Moles acid:

First, we need to assume the acid is a monoprotic acid (Only 1 proton is acid and reacts with a base).

when the acid, HX, reacts with NaOH there is produced:

HX + NaOH → H₂O + NaX

Where 1 mole of HX reacts per mole of NaOH. That means the moles at the endpoint of NaOH = Moles of HX:

Moles NaOH:

15.90mL= 0.01590L * (0.0750mol / L) = 1.193x10⁻³ moles of NaOH = Moles of HX are present.

The acidic solution was diluted to 100.0mL but only 25.00mL were taken, that is:

25.00mL / 100.00mL = 1/4 of the acid was titrated.

And moles of HX in the original solution are:

1.193x10⁻³ moles of HX * 4 = 4.77x10⁻³ moles of HX

It is multiplied by 4 because the real amount of acid is 4 times the titrated amount.

Thus, molecular weight is:

0.4000g / 4.77x10⁻³ moles of HX =

Answer:

b- 4.4 * 10^-12.

Explanation:

Hello.

In this case, as the reaction:

A + 2B → 3C

Has an equilibrium expression of:

\(K_1=\frac{[C]^3}{[A][B]^2}=2.1x10^{-6}\)

If we analyze the reaction:

2A + 4B → 6C

Which is twice the initial one, the equilibrium expression is:

\(K_2=\frac{[C]^6}{[A]^2[B]^4}\)

It means that the equilibrium constant of the second reaction is equal to the equilibrium constant of the first reaction powered to second power:

\(K_2=K_1^2\)

Thus, the equilibrium constant of the second reaction turns out:

\(K_2=(2.1 * 10^{-6})^2\\\\K_2=4.4x10^{-12}\)

Therefore, the answer is b- 4.4 * 10^-12.

Best regards.

Answer:

Alpha particles

Explanation:

Alpha particles, also called alpha rays or alpha radiation, consist of two protons and two neutrons bound together into a particle identical to a helium-4 nucleus. They are generally produced in the process of alpha decay, but may also be produced in other ways.

Answer:

because of it less attraction and its neutral position

Answer:

The existence of isotopes relates to the number of neutrons within the nuclei of an element because isotopes contain the same amount of protons (based on what element they are) but different number of neutrons in their nuclei. Because they have a different amount of neutrons, than the original element

,they also have a different atomic mass.

Explanation:

hope it helps!

Answer:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia. ... If that velocity is zero, then the object remains at rest.

Explanation:

Answer:

Before Galileo and Newton, many people thought that objects lost speed because they had a built-in natural tendency to do so. But those people weren't taking into account the multiple forces here on Earth - for example, friction, gravity, and air resistance - that cause objects to change their speed. If we could see the motion of an object in deep interstellar space, we would be able to observe the natural tendencies of an object that is free from any external influence. In deep interstellar space we would observe that if an object had a speed, it would continue to move with that speed until there was some force causing a change in its motion. Likewise, if an object were at rest in interstellar space, it would remain at rest until there was a force causing a change in its motion.

Explanation:

Hope it helped you =)

Answer:

sperm cell

Explanation:

The male portion of a zygote is called the sperm cell. The sperm cell are produced by the male organism and they fertilize the eggs.

Answer:

There are 0.017252 moles in SnO2

Explanation:

n= m/M

n=2.6/(118.710 + 2(16))

n= 2.6/150.71

n= 0.017252

Remeber to round based on the significant digits in the question.

Answer: Hợp chất CTHH 0 °C 10 °C 20 °C 30 °C 40 °C 50 °C 70 °C

Actini(III) hydroxide Ac(OH)3   0,0022    

Amonia NH3 1176 900 702 565 428 333 188

Amoni azua NH4N3 16  25,3  37,1  

View 42 more rows  

                    hehe

The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Answer:

Condensation

Explanation:

Zoe is quite keen to have noticed what we call condensation. Air contains many components, one of those being water vapor. Like how sugar is soluble in water, water can be said to be "soluble" in air. Water will evaporate into the air to a certain extent. The higher the temperature of the air, the more water the air can hold. If the air has more water that it can hold (potentially because of a temperature decrease), the extra water will come out of the air. Zoe's water bottle was cold, and because the air around Zoe's bottle had cooled down, the air can not hold as much water as it could when it was warm, so the air deposited the extra water in the form of liquid water onto the bottle, giving the illusion that her bottle was sweating.

The mass of brass in the cylinder is approximately 5.39 grams.

The first step is to calculate the volume of the cylinder:

V = πr^2h

Where

r = 0.49 in / 2 = 0.245 in

V = π(0.245 in)^2(0.7 in) ≈ 0.039 in^3

Next, we need to use the concept of weighted density to calculate the density of the brass. We can assume that the density of brass varies linearly with the composition of copper and zinc. The density of brass can be expressed as:

ρ_brass = ρ_copper × % copper + ρ_zinc × % zinc

Where

We are given that brass is 73% copper, so % copper = 0.73 and % zinc = 0.27. Substituting the given values:

ρ_brass = 8.86 g/mL × 0.73 + 7.62 g/mL × 0.27 ≈ 8.31 g/mL

Finally, we can use the density formula to calculate the mass of the brass cylinder:

m = ρV

m = 8.31 g/mL × 0.039 in^3 × (1 mL / 0.0610237 in^3) ≈ 5.39 g

Therefore, the mass of brass in the cylinder is approximately 5.39

grams.

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Answer:

0.962 atm.

97.4 kPa.

731 torr.

14.1 psi.

97,434.6 Pa.

Explanation:

Hello.

In this case, given the available factors equaling 1 atm of pressure, each required pressure turns out:

- Atmospheres: 1 atm = 760 mmHg:

\(p=731mmHg*\frac{1atm}{760mmHg} =0.962atm\)

- Kilopascals:: 101.3 kPa = 760 mmHg:

\(p=731mmHg*\frac{101.3kPa}{760mmHg} =97.4kPa\)

- Torrs: 760 torr = 760 mmHg:

\(p=731mmHg*\frac{760 torr}{760mmHg} =731 torr\)

- Pounds per square inch: 14.69 psi = 760 mmHg:

\(p=731mmHg*\frac{14.69}{760mmHg} =14.1psi\)

- Pascals: 101300 Pa = 760 mmHg:

\(p=731mmHg*\frac{101300Pa}{760mmHg} \\\\p=97,434.6Pa\)

Best regards.

The removal of hydrogen or any other electropositive element, or the addition of oxygen, is said to be the process of oxidation in classical or earlier concepts. An atom or ion gains one or more electrons during the process of reduction.

1. The oxidation half-reaction of copper is:

Cu  → Cu²⁺ + 2e⁻

The reduction half is:

Cu²⁺ + 2e⁻ → Cu

3. An anode in electrochemistry is, in its simplest form, the site of an oxidation reaction. Due to the anode's electrical potential, negative ions or anions usually react there and release electrons. After that, these electrons ascend and enter the drive circuit.

In chemistry, the cathode is referred to as the electrode where reduction takes place. In an electrochemical cell, this is typical. Here, the cathode is negative because the cell's electrical energy supply causes chemical molecules to break down.

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Answer:

1.92402 kilohertz

Explanation:

hope this helps

Answer:

• From wave equation :

\({ \rm{v = f \lambda}}\)

\({ \rm{3.0 \times {10}^{8} = (1.89 \times {10}^{18}) \times \lambda}} \\ \\ { \rm{ \lambda = \frac{3.0 \times {10}^{8} }{1.89 \times {10}^{18} } }} \\ \\ { \boxed{ \rm{ \: \lambda = 1.587 \times {10}^{ - 10} \: }}}\)

Answer:

431536.9mL

Explanation:

Answer:

your answer would be the last one gold

a. The different properties of metals and nonmetals are given below:

Matter is defined as any substance or material that has mass and occupies space. Everything in the whole universe including things we can see and see all are matter. The food we eat, the laboratory equipment, the kitchen utensils, our body perfume are typical examples of what matter is.

From the task given above, the second jar is a solid substance simply because it has a definite shape and is at the same time visible.

That being said, matter exist in four different forms, states or forms. These are as follows:

In conclusion, it can be deduced from the explanation given above that the properties of matter defines their identities and purpose.

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Answer:

A.  fossil fuel combustion

Explanation:

According to the solubility of  of sparingly soluble electrolytes by conductometer and potentiometer.

Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.

The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.It can also be determined for electrolytes.

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In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.

To calculate the rotational constant B, we can use the formula:

B = 1 / (2 * π * Δν)

Where:

B = rotational constant

Δν = spacing between consecutive lines in the rotational spectrum

Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:

B = 1 / (2 * π * 0.71433 cm^(-1))

B ≈ 0.079 cm^(-1)

The moment of inertia (I) of the molecule can be calculated using the formula:

I = h / (8 * π^2 * B)

Where:

h = Planck's constant

Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:

I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))

I ≈ 2.11 x 10^(-46) kg·m^2

The bond length (r) of the molecule can be determined using the formula:

r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)

Where:

μ = reduced mass of the molecule

r_e = equilibrium bond length

To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:

ν = 2 * B * (J + 1)

Substituting J = 9 into the formula, we get:

ν = 2 * 0.079 cm^(-1) * (9 + 1)

ν ≈ 1.58 cm^(-1)

To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:

I ∝ exp(-E / (k * T))

Where:

E = energy difference between the levels

k = Boltzmann constant

T = temperature in Kelvin

At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.

To calculate the number of revolutions per second, we can use the formula:

ω = 2 * π * B * J

Where:

ω = angular frequency (in radians per second)

J = rotational quantum number

For J = 0:

ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s

For J = 1:

ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s

For J = 10:

ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s

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Nitrate is created in an amount of 91.24 grams. The balanced equation for the formation of nitrate from the reaction of ammonia and oxygen is: 4 NH3 + 5 O2 4 NO + 6 H2O.

These can be found in the air, water, and soil naturally. The body can produce nitrite and nitrate as well. The majority of nitrate used in industry goes toward fertilizing lawns or crops. Moreover, nitrate and nitrite are used to make explosives, ammunition, and various medicinal medications in addition to being utilized to preserve food.

Ingestion of nitrate or nitrite under circumstances that cause endogenous nitrosation, which could result in cancer, is classified by the International Agency for Research on Cancer (IARC) as "probably carcinogenic to humans" (Group 2A).

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