The force equal but opposite to the one shown is : ( D ) The force that the branch applies to the kitten
Opposite and equal forcesThe force of gravity/weight of an object is equal and opposite to the reactive force because it cancels the effect of the weight of the object on the surface. In option D the force that the branch applies to the kitten resting on it is equal and opposite to the weight of the kitten.
Hence we can conclude that The force equal but opposite to the one shown is The force that the branch applies to the kitten.
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Your questio lacks the diagram but I have provided a general answer within the contest of your question
Cordell bought new tires for his bicycle. As he rode his bike on the hot street, the temperature of the air in the tires increased. If the volume of the air stayed the same, what happened to the pressure inside the tires?
A. It decreased. B. It increased. C. It stayed the same. D. It was inversely proportional to the temperature
Answer: The answer is B. The pressure inside the tires increased.
Explanation:
The relationship between the pressure, volume, and temperature of a gas is described by the ideal gas law, which is usually written as:
\($$PV = nRT$$\)
where:
- \(\(P\)\) is the pressure,
- \(\(V\)\) is the volume,
- \(\(n\)\) is the number of moles of gas,
- \(\(R\)\) is the ideal gas constant, and
- \(\(T\)\) is the temperature (in Kelvin).
In this case, the volume \(\(V\)\) and the number of moles \(\(n\)\) of air in the tires stay the same. The temperature \(\(T\)\) is increasing. Therefore, for the equation to remain balanced, the pressure \(\(P\)\) must also increase.
So, the answer is B. The pressure inside the tires increased.
List the following elements in order of decreasing atomic radii (largest to smallest) B N Li He. Li, B, N, He.
The order of decreasing atomic radii (largest to smallest) for the given elements is Li, B, N, He.
The positions of these elements in the periodic table.
Li (lithium) is in Group 1 and Period 2.
B (boron) is in Group 13 and Period 2.
N (nitrogen) is in Group 15 and Period 2.
He (helium) is in Group 18 and Period 1.
the general trends in atomic radii across the periodic table.
Atomic radius generally decreases across a period from left to right due to an increase in effective nuclear charge.
Atomic radius generally increases down a group due to an increase in the number of electron shells.
these trends to the elements in question.
Within Period 2, Li has the largest atomic radius, followed by B and then N.
He is in Period 1, which is above Period 2, so its atomic radius is smaller than the others.
Arrange the elements in order of decreasing atomic radii.
Li, B, N, He
So, the elements B, N, Li, and He in order of decreasing atomic radii (largest to smallest) are: Li, B, N, He.
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Describe the formation of ionic bonds between elements from Group I and Group VII, including the use of dot-and-cross diagrams
Explanation:
In a physical change the nature of the substance, the particles of which it is composed and the numbers of particles remain unchanged. In a chemical change the properties of the new substances are different from the original, the particles are different and the number of particles can change
The formation of ionic bonds between elements from Group I (alkali metals) and Group VII (halogens) occurs through a transfer of electrons. Alkali metals have one valence electron in their outermost shell, while halogens require one more electron to complete their outermost shell and achieve a stable electron configuration.
Let's take the example of sodium (Na) from Group I and chlorine (Cl) from Group VII to illustrate the formation of an ionic bond. Sodium has one valence electron, while chlorine requires one electron to complete its outer shell.
In a dot-and-cross diagram, sodium is represented by the symbol Na, with a dot next to it representing its single valence electron. Chlorine is represented by the symbol Cl, with seven dots around it representing its seven valence electrons.
To form an ionic bond, sodium will transfer its single valence electron to chlorine. This results in sodium losing one electron to become a positively charged sodium ion (Na+), as it now has one less electron than protons. Chlorine, on the other hand, gains the electron from sodium, resulting in a negatively charged chloride ion (Cl-), as it now has one more electron than protons.
In the dot-and-cross diagram, the electron transfer is represented by an arrow from sodium to chlorine, indicating the movement of the electron. The final configuration shows the sodium ion (Na+) with no dots around it, indicating the loss of its valence electron, and the chloride ion (Cl-) with eight dots around it, representing the complete octet in its outermost shell.
The resulting sodium ion and chloride ion are held together by the strong electrostatic attraction between the oppositely charged ions. This attraction forms an ionic bond, creating an ionic compound known as sodium chloride (NaCl), commonly known as table salt.
This process of electron transfer and formation of ionic bonds occurs between elements from Group I and Group VII, leading to the creation of stable compounds with full outer shells for both elements.\(\huge{\mathcal{\colorbox{black}{\textcolor{lime}{\textsf{I hope this helps !}}}}}\)
♥️ \(\large{\textcolor{red}{\underline{\texttt{SUMIT ROY (:}}}}\)
How many moles of silane gas (SiH4) are present in 8.68 mL
measured at 18 0C and 1.50 atm?
Answer:
5.45*10⁻⁴ moles of silane gas (SiH₄) are present in 8.68 mL measured at 18°C and 1.50 atm.
Explanation:
An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P * V = n * R * T
In this case:
P= 1.5 atmV= 8.68 mL= 0.00868 L (being 1000 mL= 1 L)n= ?R= 0.082 \(\frac{atm*L}{mol*K}\)T= 18 C= 291 K (being 0 C= 273 K)Replacing:
1.5 atm* 0.00868 L= n* 0.082\(\frac{atm*L}{mol*K}\) *291 K
Solving:
\(n=\frac{1.5 atm*0.00868 L}{0.082 \frac{atm*L}{mol*K}*291 K}\)
n= 5.45*10⁻⁴ moles
5.45*10⁻⁴ moles of silane gas (SiH₄) are present in 8.68 mL measured at 18°C and 1.50 atm.
co2(g)+H20+148Kcal---->H2Co3 Endotérmica o exotérmica
endothermic
requires energy to occure
renata developed a hair dye additive that is guaranteed to cover grey hair. she granted the right to use this additive to a major hair collor manufacturer, and renata now recives a
What Renata has granted to the manufacturer of the colored hair dye is called a patent.
What is a patent?A patent is a right given to a manufacturer to be the sole producer of a product for a given period of time. Usually, the patent has to last for a given number of years after which the technology becomes commonplace.
Hence, what Renata has granted to the manufacturer of the colored hair dye is called a patent.
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3) the rate law for a reaction between no(g) and h2(g) to produce n2(g) and
a
h2o(g) is: rate = k[no]2 [h2].
a. what is the order for the reaction with respect to no?
b. what is the order for the reaction with respect to h2?
c. what is the overall order of the reaction?
d. what are the units for the rate constant, k?
The rate law for the reaction between NO(g) and \(H_2\) (g) to produce \(N_2\)(g) and \(H_2O\) (g) is given as rate =\(k[NO]^2[H2]\).
a. The order of the reaction with respect to NO is 2. This means that the rate of the reaction is directly proportional to the square of the concentration of NO.
b. The order of the reaction with respect to \(H_2\) is 1. This means that the rate of the reaction is directly proportional to the concentration of \(H_2\) .
c. The overall order of the reaction is the sum of the individual orders, so in this case, the overall order is 2 + 1 = 3.
d. The units for the rate constant, k, can be determined by substituting the units of concentration and time into the rate law equation and solving for the units of k. In this case, the rate has units of concentration over time (e.g., mol/L s), and the concentrations of NO and \(H_2\) are in \(H_2\) mol/L. Therefore, the units of k would be \((mol/L)^{-2+(-1)} s^{-1}\), which simplifies to \(mol^{-1} L s^{-1}\).
In summary, the order of the reaction with respect to NO is 2, the order with respect to \(H_2\) is 1, the overall order is 3, and the units for the rate constant, k, are \(mol^(-1) L s^(-1)\).
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Circle the significant figures in the following 55.0
Answer and Explanation
There are 2 significant figures.
Polymerization of ethylene gives ________.A) PropyleneB) AcetyleneC) PolyethyleneD) Polyacetylene
Polymerization of ethylene gives C. Polyethylene.
Ethylene is a simple hydrocarbon with the formula C2H4. During polymerization, many ethylene molecules join together to form a larger molecule called polyethylene. This process is known as addition or chain-growth polymerization. In this reaction, the double bond between the carbon atoms in ethylene molecules is broken, and new single bonds are formed to connect the ethylene units, creating a long chain of repeating ethylene units in the polyethylene molecule. Polyethylene is a versatile and widely used plastic, commonly found in products such as plastic bags, bottles, and food packaging. Therefore the correct option is C. Polyethylene
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A 18 g sample of metal is heated to 96°C and placed in a calorimeter containing 21 g of water at an initial temperature of 24°C. After the metal cools in the water bath, the final temperature inside the calorimeter is 26°C. What is the (positive) specific heat of the metal rounded to the HUNDREDTHS place? (hint: final temperatures of metal and water are the same). Do NOT include units. *
Answer: 140
Explanation:
Given the following :
Mass of metal = 18g = 0.018kg
Mass of water (calorimeter) = 21g = 0.021kg
Initial temperature of metal = 273 + 96 = 369k
Initial temperature of water = 273 + 24 = 297k
Final temperature inside calorimeter = 273 + 26 = 299k
Temperature change of metal = 299 - 369= -70k
Temperature change of water = 299 - 297 = 2k
H = mc ΔT
m = mass
c = specific heat capacity
ΔT = change in temperature
Heat lost by metal = heat gained by water
mc ΔT = mc ΔT
Specific heat capacity of water = 4200
18 * C * ( 299 - 369 ) = 21 * 4.2 * ( 299 - 297)
0.018 × C × -70 = 0.021 × 4.2 × 2
- 1.26 × C = 0.1764
C = 176.4/1.26
C = 140
HELP!! b. At the equivalence point, all of the acid has been neutralized by the base. Why does the pH change so
sharply around the equivalence point? (HINT: the pH is neutral, just like the water example in the
previous question.)
At equivalence there is no more HA and no more NaOH, for this particular reaction. So that means we have a beaker of NaA and H2O. The H2O contributes 1 x 10-7 M hydrogen ion and hydroxide ion. But NaA is completely soluble because group 1 ion compounds are always soluble. So NaA breaks apart in water and it just so happens to be in water. So now NaA is broken up. The Na+ doesn't change the pH but the A- does change the pH. Remember that the A anion is from a weak acid. That means it will easily attract a hydrogen ion if one is available. What do you know? The A anion is in a beaker of H+ ions! So the A- will attract H+ and become HA. When this happens, it leaves OH-, creating a basic solution, as shown below.
A teacher has given a lab student a white chemical sample and asks her to confirm that it contains 7. 03 x 1023 formula units of sodium hydroxide
(NaOH). Using the balance in the laboratory, what mass of NaOH would the student have to find to verify that her teacher was correct? Round your
answer to 3 significant figures.
( ? grams)
The NaOH given to the student should weigh 46.3 grams.
The formula units can be calculated as moles multiplied by the Avogadro number.
Avogadro number is, 6.023 × 10^23.
The formula units are given to be 7.03 × 10^23.
Formula units = Avogadro Number × Number of moles
7.03 × 10^23 = 6.023 × 10^23 × Number of moles
Number of moles = (7.03 × 10^23)/(6.033 × 10^23)
Number of moles = 1.16
One mole of NaOH has the mass 39.99 grams.
1.16 moles of NaOH has mass = 1.16 × 39.99 grams.
= 46.38 grams.
Hence, the NaOH should weigh 46.3 grams.
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Help me asap, due today
1. The equation is not balanced. The balanced equation is \(4NH_3 + 5O_2 --- > 4NO +6 H_2O\)
2. The equation is balanced.
3. The equation is not balanced. The balanced version is \(2H_2O --- > 2H_2 + O_2\)
Balancing chemical equationsA balanced chemical equation usually has the same number of atoms of different elements in the reactants and the products, even though the forms of the atoms might have changed.
Consider the first equation: \(NH_3 + O_2 --- > NO + H_2O\)
The number of hydrogen atoms is not balanced. Thus, the equation that shows balanced atoms of different elements would be: \(4NH_3 + 5O_2 --- > 4NO +6 H_2O\)
Consider the second equation: \(N_2 + 3H_2 -- > 2NH_3\)
There are 2 atoms of nitrogen in the reactants and there are also 2 in the product. The number of hydrogen atoms is 6 in the reactants and 6 in the products. Thus, it is a balanced equation.
Consider the third equation: \(2H_2O --- > H_2 + O_2\)
There are 4 hydrogen atoms in the reactant and only 2 in the products. The balanced equation would be: \(2H_2O --- > 2H_2 + O_2\)
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In order to go to a lower energy orbit, an electron
A) must be transferred to another atom.
B) loses energy of a specific amount.
C) must disappear.
D) must combine with other electrons.
calculate the wavelength of light produced if an electron moves from n = 6 to n = 3.
The formula to calculate the wavelength of light produced if an electron moves from n = 6 to n = 3 is as follows:`ΔE = -Rh (1/n²f - 1/n²i)`Where `ΔE` represents the energy absorbed or emitted, `Rh` represents the Rydberg constant, `ni` represents the initial energy level, and `nf` represents the final energy level. Since the electron moves from a higher energy level to a lower energy level, energy is released.
Therefore, `ΔE` is negative. The Rydberg constant, `Rh`, equals 1.09678 x 10⁷ m⁻¹.Substitute the given values into the formula:`ΔE = -Rh (1/n²f - 1/n²i)ΔE = -1.09678 x 10⁷ m⁻¹ (1/3² - 1/6²)ΔE = -1.09678 x 10⁷ m⁻¹ (0.1111 - 0.0278)ΔE = -1.09678 x 10⁷ m⁻¹ (0.0833)ΔE = -9114.83 m⁻¹Therefore, the energy released is 9114.83 m⁻¹.To calculate the wavelength of the light produced, use the equation:`c = fλ`Where `c` represents the speed of light, `f` represents the frequency of the light, and `λ` represents the wavelength of the light.Substitute the given values into the equation:`c = fλ`λ = c/fλ = (3.00 x 10⁸ m/s) / (9114.83 m⁻¹)λ = 3.29 x 10⁻⁸ mTherefore, the wavelength of the light produced is 3.29 x 10⁻⁸ m.
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the electronic structures of atoms x and y are shown. X and Y form a covalent compound. what is its formula?
This compound has the chemical formula XY₃ indicating that for every one atom of X, there are three atoms of Y bonded to it through covalent bonds.
Atoms X and Y have a specific arrangement of electrons, which allows them to form a covalent compound with each other.
A covalent bond is a chemical bond that involves the sharing of electrons between two atoms. In a covalent bond, both atoms share one or more pairs of electrons in order to achieve a more stable electron configuration. This type of bond is typically formed between nonmetal atoms that have similar electronegativities, which means that they have similar tendencies to attract electrons. Covalent bonds can exist in simple molecules or in more complex structures such as polymers and biological molecules.
A covalent bond is a chemical bond that involves the sharing of electrons between two atoms. In a covalent bond, both atoms share one or more pairs of electrons in order to achieve a more stable electron configuration. This type of bond is typically formed between nonmetal atoms that have similar electronegativities, which means that they have similar tendencies to attract electrons.
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The complete question is:
Atoms x and y's electronic structures are depicted. X and Y form a covalent compound. what is its formula?
For the following reactions, identify the element that gets reduced and the element that gets oxidized.2AgCl+ Z----->2Ag +ZnCl24NH3+3O2----->2N2+6H2OFe2O3+2Al---->Al2O3+2Fe
In the first reaction, Zn is oxidized and Ag is reduced. In the second reaction, N is reduced and O is oxidized. In the third reaction, Al is oxidized and Fe is reduced.
In the given reactions:
1. 2AgCl + Zn → 2Ag + ZnCl₂
- The element Zn is getting oxidized. It loses electrons and increases its oxidation state from 0 to +2. Therefore, Zn is the element that gets oxidized.
- The element Ag is getting reduced. It gains electrons and decreases its oxidation state from +1 to 0. Therefore, Ag is the element that gets reduced.
2. 4NH₃ + 3O₂ → 2N₂ + 6H₂O
- The element N is getting reduced. It gains electrons and decreases its oxidation state from -3 to 0. Therefore, N is the element that gets reduced.
- The element O is getting oxidized. It loses electrons and increases its oxidation state from 0 to -2. Therefore, O is the element that gets oxidized.
3. Fe₂O₃ + 2Al → Al₂O₃ + 2Fe
- The element Al is getting oxidized. It loses electrons and increases its oxidation state from 0 to +3. Therefore, Al is the element that gets oxidized.
- The element Fe is getting reduced. It gains electrons and decreases its oxidation state from +3 to 0. Therefore, Fe is the element that gets reduced.
In summary, in the given reactions, Zn gets oxidized and Ag gets reduced, N gets reduced and O gets oxidized, and Al gets oxidized and Fe gets reduced.
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if the solubility product constant for aluminum hydroxide, another common antacid, is 1.2 x 10-33 at 250c, which is more soluble, magnesium hydroxide or aluminum hydroxide. justify your prediction.
The difference in solubility can be attributed to the difference in Ksp values. Since magnesium hydroxide has a significantly higher Ksp value compared to aluminum hydroxide, it is more soluble in water.
The solubility product constant (Ksp) is a measure of a compound's solubility in water. A lower Ksp value indicates lower solubility, while a higher Ksp value indicates greater solubility. In this case, aluminum hydroxide has a Ksp of 1.2 x 10^-33 at 25°C.
Comparing this to the Ksp of magnesium hydroxide, which has a Ksp of 5.61 x 10^-12 at 25°C, it is clear that magnesium hydroxide is more soluble than aluminum hydroxide.
Here, magnesium hydroxide (Mg(OH)2 has a significantly higher Ksp value compared to aluminum hydroxide Al(OH)3, and so is more soluble in water. This higher solubility of magnesium hydroxide means it is more likely to dissolve and dissociate into its ions when mixed with water, making it a more effective antacid. In conclusion, based on the Ksp values provided, magnesium hydroxide is more soluble than aluminum hydroxide at 25°C.
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T or F? Energy is the performance of work.
Answer:
True. The term is mechanic / kinetic energy.
Answer:
your answer should be True.
Energy is the performance of work.
Explanation:
What else is produced when sodium carbonate decomposes?
Na2CO3 → Na2O + ?
Answer:
Na2CO3 → Na2O + CO2
Explanation:
CO2 is your answer
Answer:
CO2
Explanation:
I Just Took The Quiz
Have A Good Day :)
Marie Curie's work with radioactive materials eventually lead to her death. At the age of 66, what
disease did Madame Curie die from?
Answer:
Radiation-induced Luekimia
Explanation:
They worked with many radioactive elements, so it caused Leukemia which is
a disease in which the bone marrow and other blood-forming organs produce increased numbers of immature or abnormal leukocytes.
Hoped this helped
Convert −55 ◦C to Kelvin
Answer:
-459.67 good luck and hope you pass
What is formed when a sodium atom and chlorine atom react chemically ?
Answer:
NaCl
Explanation:
NaCl is common table salt
Reacts together due to Na having a 1+ charge and Cl having a 1- charge
they bond together because their charges neutralize
Answer:
A neutron
Explanation:
WENOMECHAINSAMA TUMAJARBISAUN WIFENLOOOF ESELIFTERBRAUN
jk
its because they neutralize each other because one has a positive charge and one has a negative charge.
Which of the following reactions would be the fastest?
A large lump of zinc with high concentration of sulfuric acid.
Small strips of zinc with high concentration of sulfuric acid.
Powdered zinc with low concentration of sulfuric acid.
Powdered zinc with high concentration of sulfuric acid.
2 DONT KNOW
Answer:
it should be powdered zinc with high concentration of sulfuric acid
A gas in a balloon at constant pressure has a volume of 120. 0 mL at -123C. What is its volume at 27C?
At 27°C and constant pressure, the volume of the gas in the balloon is approximately 240.0 mL.To solve this problem, we need to use the combined gas law, which relates the pressure, volume, and temperature of a gas:\((P_1V_1)/T_1 = (P_2V_2)/T_2\)
Where \(P_1\)and \(T_1\) are the initial pressure and temperature, \(V_1\)is the initial volume, \(P_2\) and \(T_2\) are the final pressure and temperature, and \(V_2\) is the final volume we are trying to find.We are given the initial volume \(V_1\) = 120.0 mL, the initial temperature \(T_1\)= -123C, and the pressure is constant, so we can assume \(P_1 = P_2\). We need to convert the temperatures to Kelvin, so \(T_1\) = 150 K and \(T_2\)= 300 K.
Using the combined gas law, we can solve for \(V_2\):
\((P_1V_1)/T_1 = (P_2V_2)/T_2\)
\((P_1)(120.0 mL)/(150 K) = (P_2)(V_2)/(300 K)\)
Simplifying, we can cancel out the pressures and cross-multiply:
\(V_2\) = (120.0 mL)(300 K)/(150 K)
\(V_2\) = 240.0 mL
Therefore, the volume of the gas in the balloon at 27C is 240.0 mL.To answer your question, we'll use Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure remains constant.Charles's Law formula: \(V_1/T_1 = V_2/T_2\)
Where:
\(V_1\) = initial volume = 120.0 mL
\(T_1\) = initial temperature = -123°C
\(V_2\)= final volume (what we want to find)
\(T_2\) = final temperature = 27°C
First, we need to convert the temperatures from Celsius to Kelvin:
\(T_1\)(K) = -123°C + 273.15 = 150.15 K
\(T_2\)(K) = 27°C + 273.15 = 300.15 K
Now, we can plug in the values into Charles's Law formula:
(120.0 mL / 150.15 K) = (\(V_2\) / 300.15 K)
To find \(V_2\), we'll rearrange the equation and multiply both sides by 300.15 K:
\(V_2\) = (120.0 mL / 150.15 K) × 300.15 K
\(V_2\)≈ 240.0 mL
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Direct Combination and the product
Cobalt (III) + nitrogen -> ??
The chemical equation for Direct Combination of Cobalt (III) and nitrogen, with the product given can be represented as given : Cobalt (III) + nitrogen → Cobalt nitride (Co3N2)When Cobalt (III) and nitrogen are combined using direct combination method, the product formed is Cobalt nitride (Co3N2).
The balanced chemical equation for this reaction is shown below.2 Co (III) + 3 N2 → Co3N2.Cobalt nitride is a blackish gray powder with a melting point of 1750 °C and a density of 6.5 g/cm3. Cobalt nitride is an important metal nitride that is used in the preparation of cobalt metal catalysts, magnetic alloys, and other materials.
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What is the approximate volume of a 0.600 mole sample of gas at 15°C and a pressure of 1.10atm?
a. 12.9 L
b. 22.4 L
c. 24.6 L
d. 129 L
The 0.600 mole gas sample has a capacity of approximately 12.9 L at 15 °C and 1.10 atm of pressure. The right answer is (a) 12.9 L.
To calculate the volume of a gas sample, we can use the ideal gas law, PV = nRT, where P is the pressure in atm, V is the volume in liters, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.
First, we need to convert the temperature from Celsius to Kelvin by adding 273.15 to it.
T = 15°C + 273.15 = 288.15 K
Now, we can rearrange the ideal gas law to solve for V:
V = (nRT) / P
Substituting the given values, we get:
V = (0.600 mol x 0.0821 L·atm/mol·K x 288.15 K) / 1.10 atm
Simplifying this expression, we get:
V ≈ 12.9 L
Therefore, the approximate volume of the 0.600 mole gas sample at 15°C and a pressure of 1.10 atm is 12.9 L. The correct option is (a) 12.9 L.
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What mass of sulfuric acid, H2SO4, is required to react with 3.27 g of potassium hydroxide, KOH? The products of this reaction are potassium sulfate and water.
Have both the unbalanced and balanced chemical equations.
Explain how to find the molar mass of the compounds.
Explain how the balanced chemical equation is used to find the ratio of moles
Explain how many significant figures your answer needs to have.
The numerical answer
Answer:
pa help din ako jan pleaseAnswer:
Don't plagiarize here.
Explanation:
Your online teacher knows that you are looking here for the answer!!!!
write a balanced chemical equation for the decomposition reaction. do not include phases.
2NaHCO3 → Na2CO3 + CO2 (g) + H2O (g)
The balanced chemical equation for the decomposition reaction of sodium bicarbonate (NaHC\(O_{3}\)) is:
2NaHC\(O_{3}\) → \(Na_{2}\)C\(O_{3}\) + C\(O_{2}\) + \(H_{2}\)O
The balanced chemical equation for the decomposition reaction of sodium bicarbonate (NaHC\(O_{3}\) ) is:
2NaHC\(O_{3}\) → \(Na_{2}\)C\(O_{3}\) + C\(O_{2}\) + \(H_{2}\)O
In this reaction, two molecules of sodium bicarbonate decompose to form one molecule of sodium carbonate (NaHC\(O_{3}\) ), one molecule of carbon dioxide ( C\(O_{2}\) ), and one molecule of water (\(H_{2}\)O).
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What does change in different types of milk?
1.
2.
Answer:
the flavour or the taste or the packaging