which fbd would most likely represent a car driving on a level surface with a constant velocity

Answer:

True

Explanation:

idk

Answer:

Distance covered 28 km

displacement is 22.8 km North-East

Explanation:

Distance shows how far apart objects or points are from each other. The distance he covered is the sum of all the distance travelled. Therefore:

Distance covered = 12 km + 6 km + 10 km = 28 km

Displacement is a vector quantity (has direction). It is the overall change in position.

The total distance traveled north = 12 km + 10 km = 22 km

The distance traveled east = 6 km

The displacement (d) is:

d² = 22² + 6² = 484 + 36

d² = 520

d = √520 = 22.8 km

Therefore the displacement is 22.8 km North-East

Distance covered 28 km

displacement is 22.8 km North-East

Distance covered

= 12 km + 6 km + 10 km

= 28 km

Now

The total distance traveled north = 12 km + 10 km = 22 km

And,  

The distance traveled east = 6 km

So,  

The displacement (d) is:

\(d^2 = 22^2 + 6^2\\\\ d^2 = 520\\\\d = \sqrt520\)

= 22.8 km

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A student is creating an electromagnet for an investigation, and the one feature of the electromagnet that will have the least influence on the magnetic force is the brand of the battery, which is the last option.

The magnetic force of an electromagnet is determined by a number of factors, such as the material of the core and the number of wire coils, and the size of the power source but the brand of the battery don't have an effect on the magnetic force of the electromagnet as long as the battery provides the necessary voltage and current to power the electromagnet.

Hence, the one feature of the electromagnet that will have the least influence on the magnetic force is the brand of the battery, which is the last option.

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Answer: There are not able to be electricity

Explanation: Essentially, this means that the electricity is able to pass through the birds without damaging them.

Answer:

hi i only dont understand want ur saying

The average acceleration of the car is 0.88 m/s² but the displacement of the car is zero.

Displacement can be defined as the overall distance traveled by an object or length of a strait line between final and initial position of the object.

It can be fined as the overall change in velocity of the object in given time. It can be given as:

\(a_{avg} = \dfrac {v_f- v_i}{t}\)

Where,

\(v_f\) - final velocity

\(v_i\) - initial velocity

\(t\) - time

Put the values in the formula,

\(a_{avg}= \dfrac {(85 {\rm \ m/s} - 60{\rm \ m/s}}{8.57 {\rm \ s}} \\\\a_{avg}= 0.88 {\rm \ m/s^2}\)

Therefore, the average acceleration of the car is 0.88 m/s² but the displacement of the car is zero because the initial final position is the same.

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Answer: The average acceleration of the car is 0.88 m/s² but the displacement of the car is zero.

What is displacement?

Displacement can be defined as the overall distance traveled by an object or length of a strait line between final and initial position of the object.

Average acceleration:

It can be fined as the overall change in velocity of the object in given time. It can be given as:

Where,

- final velocity

- initial velocity

- time

Put the values in the formula,

Therefore, the average acceleration of the car is 0.88 m/s² but the displacement of the car is zero because the initial final position is the same.

Explanation:

Answer:

One is heavier and one is lighter.

To get her violin perfectly tuned to concert A, she should tighten or loosen her string based on whether it was flat or sharp compared to the 6.00 Hz reference pitch.

If her string was flat, she should tighten it slightly to increase its tension and raise its pitch. If her string was sharp, she should loosen it slightly to decrease its tension and lower its pitch. The goal is to match the frequency of her string to the frequency of concert A, which is typically 440 Hz.  To get her violin perfectly tuned to concert A, she should adjust her string from the 6.00 Hz frequency that she heard.

To perfectly tune her violin to concert A, she should tighten or loosen the string depending on the current frequency compared to the target frequency of 440 Hz. If the current frequency is lower than 440 Hz, she needs to tighten the string. If the current frequency is higher than 440 Hz, she needs to loosen the string. This will ensure that her violin is tuned to the desired concert A pitch.

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The pathway is summarized as olfactory receptor cells. odorant nerves the olfactory bulb

Olfactory receptors detect odor molecules in the air that enter the nasal cavity as well as bind to olfactory receptors.

When olfactory receptors are activated, olfactory receptor neurons send an impulse to the brain's olfactory system.

The binding of odors to the ORs causes an electrical signal to travel along the axons to the brain's main olfactory bulb.

The data is then transmitted to other areas of the brain, resulting in odor perception as well as behavioral and emotional responses.

The olfactory nerve is a sensory nerve that transmits the sense of smell. Its receptors are found in the olfactory mucosa beneath the nasal cavity's roof.

The olfactory fibers pass through the cribriform plate's olfactory foramina and enter the olfactory bulb via the olfactory groove.

Thus, these are the olfactory receptors and pathways.

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The transfer of thermal energy that Ilva is experiencing is known as radiation. Radiation is the transfer of heat energy through electromagnetic waves that do not require a medium to travel through. In this scenario, the boiling water and stove are emitting infrared radiation which is absorbed by Ilva's body, causing her to feel the heat. Additionally, convection and conduction are two other methods of transferring thermal energy. Convection is the transfer of heat energy through the movement of fluids, while conduction is the transfer of heat energy through direct contact between two objects. However, in this scenario, radiation is the primary method of thermal energy transfer that Ilva is experiencing.
Ilva is standing a few feet away from boiling water, and she feels the heat from the boiling water and the stove. The term that describes this transfer of thermal energy is "radiation." Radiation is the process through which thermal energy is transferred through electromagnetic waves without the need for direct contact or a medium like air or water. In this scenario, the heat from the boiling water and the stove radiates outwards and reaches Ilva, allowing her to feel the warmth. This form of heat transfer is why you can feel the heat from a fire or a hot object without touching it directly.

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The term that describes the transfer of thermal energy that Ilva feels from the boiling water and the stove is radiation.


Radiation is the transfer of thermal energy through electromagnetic waves. Unlike conduction and convection, radiation does not require a medium (such as a solid, liquid, or gas) to transfer heat. Instead, it can transfer energy through empty space or air.

In Ilva's situation, the heat she feels from the boiling water and the stove is primarily due to the infrared radiation emitted by these hot objects. As the electromagnetic waves reach her, they transfer the thermal energy to her body, making her feel the warmth even though she is standing a few feet away from the heat source.

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If the position r of a particle moving in a cartesian plane is given by r= (3t^4-5t² )i (3t-7t^3j +(3t²) k in meters.

a) The position of the particle (1875i - 8620j + 75k) meters.

B) the velocity 2990i - 2628j + 30k

C)The acceleration  890i - 210j + 6k

a) To find the position of the particle at t = 5 sec, we simply substitute t = 5 into the expression for r:

r = (3t^4 - 5t^2)i + (3t - 7t^3)j + (3t^2)k

r = (3(5)^4 - 5(5)^2)i + (3(5) - 7(5)^3)j + (3(5)^2)k

r = 1875i - 8620j + 75k

Therefore, the position of the particle at t = 5 sec is (1875i - 8620j + 75k) meters.

b) To find the velocity, we take the derivative of r with respect to time:

v = dr/dt = (12t^3 - 10t)i + (3 - 21t^2)j + (6t)k

At t = 5 sec, we have:

v = (12(5)^3 - 10(5))i + (3 - 21(5)^2)j + (6(5))k

v = 2990i - 2628j + 30k

Therefore, the velocity of the particle at t = 5 sec is (2990i - 2628j + 30k) meters per second.

c) To find the acceleration, we take the derivative of v with respect to time:

a = dv/dt = (36t^2 - 10)i + (-42t)j + 6k

At t = 5 sec, we have:

a = (36(5)^2 - 10)i + (-42(5))j + 6k

a = 890i - 210j + 6k

Therefore, the acceleration of the particle at t = 5 sec is (890i - 210j + 6k) meters per second squared.

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Answer:

Explanation:

F = ma = (2 kg)(9.8 m/s²) = 19.6 N

a = F/m = 25 N / 2 kg = 12.5 m/s²

Answer:

3rd diagram

Explanation:

From the laws of reflection, we understood that the angle of incidence in equal to the angle of reflection.

For example, if a ray of light strikes a mirror at 60°, it reflected at the same angle (i.e 60°)

Considering the diagram given in the question above,

The ray of light strikes the mirror at 40°. Therefore, the light will be reflected with the same angle (i.e 40°)

Thus, the 3rd diagram gives the correct answer to the question.

Answer:

It would take 8.22037 hrs away. Wouldn't it?

Explanation:

Because

    4.11016

    4.11016

            15

= 8.22037

The plane's speed is 450 miles per hour, and the wind speed is 50 miles per hour. This is determined by solving the equations derived from the distances and times of the flight with and against the wind.

Let's assume the speed of the plane (without considering the wind) is P, and the speed of the wind is W.

When flying into a headwind, the effective speed of the plane is reduced by the wind speed. So the equation for the outbound flight is:

P - W = 2000 miles / 5 hours

P - W = 400 miles per hour (mph)  ---(Equation 1)

When flying with a tailwind, the effective speed of the plane is increased by the wind speed. So the equation for the return flight is:

P + W = 2000 miles / 4 hours

P + W = 500 miles per hour (mph)  ---(Equation 2)

Now we have a system of two equations (Equation 1 and Equation 2) with two variables (P and W). We can solve this system to find the values of P and W.

Adding Equation 1 and Equation 2 together, we eliminate the variable W:

(P - W) + (P + W) = 400 mph + 500 mph

2P = 900 mph

P = 450 mph

Substituting the value of P back into Equation 1 or Equation 2, we can solve for W:

450 mph - W = 400 mph

W = 450 mph - 400 mph

W = 50 mph

Therefore, the plane's speed is 450 mph and the wind speed is 50 mph.

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Answer:

=0.855V

Explanation:

The induced voltage can be calculated using below expression

E =B x dA/dt

Where dA/dt = area

B= magnetic field = 6.90×10-5 T.

We were given speed of 885 km/h but we will need to convert to m/s for consistency of unit

speed = 885 km/h

speed = 885 x 10^3 m/hr

speed = 885 x 10^3/60 x60 m/s

speed = 245.8 m/s

If The aircraft wing sweep out" an area

at t= 50.4seconds then we have;

dA/dt = 50.4 x 245.8

= 123388.32m^2/s

Then from the expression above

E =B x dA/dt substitute the values of each parameters, we have

E = 6.90 x 10^-5 x 12388.32 V

E =0.855V

Hence, the average induced voltage between the tips of the wings is =0.855V

Explanation: As the angle is increased the acceleration of the object is increased as the angle increases the component of the force parallel to the incline increases and the component of forced perpendicular to the inclined decreases it is the parallel component of the weight vector that causes the acceleration.

Answer:

129.12 ml

Explanation:

If answer is correct feel free to replay me for explanation.

Answer:

Explanation:

There is no picture!

The first two exercises are of the uniform rectilinear movement (MRU) is a type of movement that is characterized by a constant speed and a rectilinear trajectory. In other words, an object moving with MRU always moves at the same speed and in a straight line.

The formula to calculate the speed in the MRU is simple: v = d/t, where:

v is the speed

d is the distance traveled

t is the elapsed time

It is also possible to use the formula s = vt to calculate the distance traveled, where s is the distance and t is the time.

It is important to note that velocity in the MRU is a vector that has a magnitude (the velocity itself) and a direction (the direction of motion). In the MRU, the direction of movement is always constant and coincides with the direction of the trajectory.

First we get the data:

V = Velocity = 25 m/s

T = time = ?

D = distance = 350 m

We already know that the MRU formula is V = d/t. But we must calculate the time, we clear the time, then:

t = d/v

We continue, substitute data and solve for time, then

t = d/v

t = (350 m)/(25 m/s)

t = 14 m

To travel 350 meters, it takes me 14 minutes.

To solve this, we first get the data:

V = speed = ?

D = distance = 50 m

T = time = 15 s

We know that the MRU formula is V = d/t. It is also the same formula for calculating velocity.

How should we calculate speed? It is not necessary to clear the formula, we substitute data and solve, then

V = d/t

V = (50 m)/(15 s)

V = 3.33 m/s

If I ride a bicycle 50 meters in 15 seconds, my speed is 3.33 meters per second (m/s).

As for the third exercise, it is an exercise of a rectilinear motion uniformly accelerated (MRUA), since Lance's speed increases constantly in time. A rectilinear motion uniformly accelerated (MRUA) is a type of motion in which an object moves in a straight line and its velocity changes uniformly in time due to constant acceleration. In this type of movement, the acceleration is constant, which means that the speed increases or decreases at a constant rate in each unit of time.

The MRUA is a fundamental concept in physics and is used to describe many phenomena, from free-falling objects to moving vehicles. Uniformly accelerated rectilinear motion is described mathematically by a series of equations, relating position, velocity, acceleration, and time.

One of the most important equations in the MRUA is the velocity equation, which relates the final velocity (Vf), the initial velocity (Vi), the acceleration (a) and the time (t). The velocity equation can be expressed as:

This equation shows how the final velocity of an object in an MRUA depends on its initial velocity, acceleration, and elapsed time.

Another important equation in the MRUA is the position equation, which relates the final position (x), the initial position (x0), the initial velocity (Vi), the acceleration (a) and the time (t).

The position equation can be expressed as:

This equation shows how the position of an object in an MRUA changes as a function of time, initial velocity, acceleration, and initial position.

First we get the data, this is the first step to start solving:

Vf = Final speed = 12 m/s

Vo = Initial velocity = 2 m/s

t = time = 12 s

a = acceleration = ?

The velocity equation can be expressed as:

Vf = Vi + a * t.

We use this formula to clear the formula to calculate the acceleration,

We continue solving, now we substitute our data and solve:

a = (Vf - Vo)/t

a = (30 m/s - 2 m/s)/(12 s)

a = 2.33 m/s²

Its acceleration is 2.33 meters per second squared (m/s²).

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The Andromeda Galaxy distance is approximately 2.52 million light-years away from us.

The Andromeda Galaxy (M31) is indeed similar to our own Milky Way galaxy, but slightly larger with a linear diameter of 140,000 light-years along its longest axis. To determine its distance from us, we can use the angular diameter, which is 3.18°.

We can use the small-angle formula to find the distance. This formula relates the angular diameter (in radians), the actual diameter, and the distance between the observer and the object:

angular diameter (radians) ≈ actual diameter / distance

First, we need to convert the angular diameter from degrees to radians:

3.18° * (π radians / 180°) ≈ 0.0555 radians

Now, plug in the values into the small-angle formula:

0.0555 radians ≈ 140,000 light-years / distance

To solve for the distance, divide both sides of the equation by 0.0555 radians:

distance ≈ 140,000 light-years / 0.0555 radians
distance ≈ 2,522,522 light-years

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Answer:

100 cm

Explanation:

:) <3

Answer:

h = 20 m

Explanation:

Given that,

Force to lift a firefighter's equipment, F = 270 N

Work done, W = 5400 J

We need to find the height climbed by the firefighter. We know that,

Work done, W = Fd

So,

\(d=\dfrac{W}{F}\\\\d=\dfrac{5400}{270}\\\\d=20\ m\)

So, the firefighter climb from a height of 20 m.

Answer:

Its A

Explanation: I got it right on Edge *lip bite*

Answer:

Once used as a energy source they cannot be charged/used again.

Explanation:

The ability of a fluid to exert an upward force on an object is called buoyancy or upthrust. The upward force is called buoyant force.

The buoyancy as explained above is caused by the pressure exerted by the fluid in which the object is immersed. That pressure force is called an upthrust force or buoyant force.

According to Archimedes principle, the buoyant force is the upward force exerted by a fluid on an object placed in them. The magnitude of the buoyant force is equal to the weight of a fluid displaced by an object.

Due to the buoyant force, a body immersed wholly of partly in a fluid will to lose its weight. In other words, it appears to be lighter. This phenomenon makes it possible for fish, swimmers, ships, icebergs, and hot air balloons to stay afloat.

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Answer:

C. There is a difference in air pressure.

Explanation:

The time it will take her to land on the other side is 0.5 seconds.

In a triangle with three angles of 30°, 60°, and 90°, the hypotenuse is twice as long as the shorter leg and three times as long as the latter. To understand why this is the case, consider that the triangle is a right triangle given these numbers according to the Converse of the Pythagorean Theorem. The lengths of the three sides in a triangle of this kind are referred to as a Pythagorean triple.

distance = velocity x time

In this case, the distance is 3 meters and the velocity is 6 m/s, so:

3 = 6 x time

Solving for time, we get:

time = 3/6 = 0.5 seconds

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A cosmic catastrophe jolts earth so that its axis is perpendicular to the orbital plane between earth and the sun therefore the largest effect of this change would be the elimination of seasonal variation.

This is referred to as the period of the year that is distinguished by special climate conditions and examples include winter, summer etc.

In a situation where a cosmic catastrophe results in it being perpendicular to the orbital plane between earth and the sun there will be no seasonal variation as a result of it hindering the effect of the sun and other factors.

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