Which factors affect the performance of a solar cell?

Hi there!

(A)

We can solve for acceleration using the following equation:

Δd = vit + 1/2at²

The shuttle lifts-off from rest, so:

Δd = 1/2at²

Rearrange to solve for 'd':

2Δd/t² = a

2(350)/(3.5²) = 57.14 m/s²

(B)

Now, we can use this equation to solve for final velocity:

vf = vi + at

vf = at

vf = 57.14 × 3.5 = 200 m/s

(C)

Now, we can use the following equation to solve for displacement:

Δd = vt

Δd/v = t

350/200 = 1.75 sec

Answer:

the same

Explanation:

if that is what you are asking

The two closest isotopes for gold-197 are gold-196 and gold-198.

The atomic number of gold is 79, which means it has 79 protons. Gold-197 refers to the isotope of gold with a mass number of 197, indicating the total number of protons and neutrons in the nucleus.

The two closest isotopes to gold-197 are:

1. Gold-196: It has 79 protons and 117 neutrons (197 - 79 = 118).

2. Gold-198: It has 79 protons and 119 neutrons (197 - 79 = 118).

Therefore, the two closest isotopes to gold-197 are gold-196 and gold-198, with the number of neutrons being the only difference between them.

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For an electron in the N shell, the maximum value of the orbital angular momentum (L) in any chosen direction (z) is given by the formula: Lz, max = ℓℏ where ℓ is the maximum value of the azimuthal quantum number for the N shell, which is n-1.

1. The principal quantum number (n) determines the energy level and corresponds to the shell number. In this case, n = N.
2. The azimuthal quantum number (l) determines the shape of the orbital and ranges from 0 to n - 1. For the maximum orbital angular momentum, we should choose the largest value of l, which is l = N - 1.
3. The magnetic quantum number (m_l) determines the orientation of the orbital in space and ranges from -l to +l.
The largest orbital angular momentum (Lz, max) occurs when m_l = l, which is equal to N - 1. Therefore, Lz, max = (N - 1) ℏ.

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Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9

Answer:

Explanation:

Projectile Motion. Projectile motion is different than free fall: it involves two dimensions instead of one. ... Balls traveling in two dimensions, only one of which experiences acceleration, require two sets of equations: one set for the x-direction and the other for the y-direction.

Values for P1, V1, and P2 to find the size of the tank needed to contain the helium at atmospheric pressure.

To determine the size of the tank needed to contain the helium at atmospheric pressure (1 atm), we need to use the ideal gas law formula:

PV = nRT
Where:
P = Pressure (in atm)
V = Volume (in liters)
n = Moles of gas
R = Ideal gas constant (0.0821 L atm/mol K)
T = Temperature (in Kelvin)
From the student question, we know that the initial pressure (P1) and volume (V1) are given. We also know that the final pressure (P2) is 1 atm. We need to find the final volume (V2).
Step 1: Calculate the moles of helium gas (n) using the initial conditions.
P1V1 = nRT1
n = (P1V1) / (RT1)
Step 2: Calculate the final volume (V2) using the moles of helium gas (n) and atmospheric pressure (1 atm).
P2V2 = nRT2
V2 = (nRT2) / P2
Since we want the tank size for the same amount of helium at atmospheric pressure, we can assume the temperature remains constant (T1 = T2). Therefore, you can simply use the initial conditions to find the final volume:
V2 = (P1V1) / P2
Plug in the given values for P1, V1, and P2 to find the size of the tank needed to contain the helium at atmospheric pressure.

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The merged corporation is Corporation Delta. The equation "d e = d" shows that Corporation Delta absorbs Corporation Echo. The letter "d" is on both sides of the equation, which indicates that Corporation Delta is the surviving entity.

The letter "e" is on the left side of the equation, which indicates that Corporation Echo is the disappearing entity.

In other words, the equation "d e = d" can be read as "Corporation Delta absorbs Corporation Echo, resulting in a new entity called Corporation Delta."

This is a common way to represent mergers and acquisitions in mathematical notation. For example, the equation "a b = c" would represent a merger between Corporation A and Corporation B, resulting in a new entity called Corporation C.

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Answer:

P.E = 2934.75

Explanation:

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

\( P.E = mgh\)

Where, P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Given the following data;

Weight =645

Height = 4.55

\( P.E = mgh\)

But we know that weight = mg = 645N

Substituting into the equation, we have;

\( P.E = 645 * 4.55 \)

\( P.E = 2934.75 J\)

Potential energy, P.E = 2934.75 Joules.

Lengths of time it takes for new light bulbs to burn out are an example of quantitative data. Quantitative data refers to any information that can be expressed numerically or measured.

In this case, the lengths of time are numerical values that can be measured in hours, days, or any other unit of time. This data provides information about the lifespan or durability of the light bulbs. Quantitative data is often used in statistical analysis and can be used to draw conclusions, make predictions, or identify trends.

It is important to collect accurate and reliable data to ensure meaningful analysis. Quantitative data is often used in statistical analysis and can be used to draw conclusions, make predictions, or identify trends. In summary, the lengths of time it takes for new light bulbs to burn out represent quantitative data.

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Answer:

Time, t = 10 seconds

Explanation:

Given the following data;

Mass = 10kg

Force = 10N

Final velocity = 10m/s

Initial velocity = 0m/s

To find the time;

First of all, we would find the acceleration of the box.

Force = mass * acceleration

10 = 10 * acceleration

Acceleration = 10/10 = 1m/s²

Now, we can find the time by using the first equation of motion;

V = U + at

10 = 0 + 1t

10 = t

Time, t = 10 seconds

Therefore, it will take 10 seconds for the box to come to a complete stop.

To determine the final position and size of the image formed by the combination of the converging and diverging lenses, we can use the lens formula and the lens-maker's formula. Here are the steps to solve the problem:

Determine the position and size of the image formed by the converging lens:

Given: Focal length of the converging lens (f₁) = 60 cm

Object height (h₁) = 3.7 cm

Object distance (u₁) = -80 cm (negative sign indicates the object is in front of the lens)

Using the lens formula: 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance.

Substituting the given values:

1/60 = 1/v - 1/(-80)

Solving for v₁, the image distance formed by the converging lens:

1/v₁ = 1/60 - 1/80

1/v₁ = (4 - 3)/240

1/v₁ = 1/240

v₁ = 240 cm

The image distance (v₁) is positive, indicating that the image formed by the converging lens is real and on the opposite side of the lens from the object.

To determine the magnification (M₁) of the converging lens, we can use the formula: M₁ = -v₁/u₁

M₁ = -240/(-80)

M₁ = 3

The magnification (M₁) is positive, indicating that the image formed by the converging lens is upright.

Determine the position and size of the image formed by the diverging lens:

Given:

Focal length of the diverging lens (f₂) = -44 cm

Object distance (u₂) = 240 cm (distance between the two lenses)

Using the lens formula for the diverging lens:

1/f = 1/v - 1/u

Substituting the given values:

1/-44 = 1/v₂ - 1/240

Solving for v₂, the image distance formed by the diverging lens:

1/v₂ = -1/44 + 1/240

1/v₂ = (-6 + 1)/240

1/v₂ = -5/240

v₂ = -48 cm

The image distance (v₂) is negative, indicating that the image formed by the diverging lens is virtual and on the same side of the lens as the object.

To determine the magnification (M₂) of the diverging lens, we can use the formula: M₂ = -v₂/u₂

M₂ = -(-48)/240

M₂ = 1/5

The magnification (M₂) is positive, indicating that the image formed by the diverging lens is upright.

Determine the final position and size of the combined image:

To find the final position of the combined image, we add the image distances of the converging and diverging lenses:

v = v₁ + v₂

v = 240 + (-48)

v = 192 cm

To find the magnification of the combined lenses, we multiply the magnifications of the individual lenses:

M = M₁ * M₂

M = 3 * 1/5

M = 3/5

The final image distance (v) is positive, indicating that the combined

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Answer:

Explanation:Health-related fitness activities can be integrated into everyday activities that are often characterized as lifetime activities. In contrast, skill-related physical fitness includes health-related components, but it also covers components related to physical performance.Health-Related components are those components that contribute to the development of health and functional capacity of the body such as cardiovascular endurance & strength, muscular endurance & strength, flexibility and body composition, while skill-related components of physical fitness are components that contribute

Precision refers to the closeness of two or more measurements to each other. Using the example above, if you weigh a given substance five times, and get 3.2 kg each time, then your measurement is very precise. Precision is independent of accuracy.

The Aurora Borealis, also known as the Northern Lights, is normally only seen in the most northern regions, like Canada, Alaska & the North Pole. However, in 1859, there was a geomagnetic storm so big the Aurora Borealis was seen as far SOUTH as the United States, Japan, and Australia.

The Aurora Borealis are spectacular lights that are seen in the polar regions.

These lights are produced as a result of interaction between solar winds and the earth's magnetic field.

The solar wind emits from the sun's corona and contains charged particles traveling at a speed of 400 miles/second.

When these charged particles collide with the atoms and molecules of the atmosphere after entering into Earth's magnetic field they produce lights in the northern and southern poles. Big Aurora Borealis is also called geometric storms.

To put it simply, auroras are produced by the collision of different atomic particles such as green and red lights formed by oxygen, blue, pink, and violet lights by nitrogen and helium particles emitting purple light.

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Answer:

Explanation:

2) From F=ma

Force =15×40=600N or kgm/s2

3)From the same equation making acceleration the subject of the formula will give

a=f÷m

=24÷4=6m/s2

4)m=f÷a

=45÷15=3kg

The  central bright fringe and the 2nd order dark fringe on the screen are 9.41 X 10^(-4) m apart.

The distance of the first dark fringe from the central bright spot will be equal to the width of the fringe.

Fringe width = λL /w

where λ is the wavelength of light, w is the slit width, and L is the distance of the screen.

So required distance

= \(\frac{670 * 10^{-9} * 1.25 }{0.89 * 10^{-3}}\) m

= 9.41  X  10^(-4) m

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Answer:

A.BB is 000 with A.B is 0.00

Answer:

\((a)\\1.97\times 10^8 m/s\\(b)\\1.99\times 10^8 m/s \\(c)\\2.21 \times 10^8 m/s\)

Explanation:

According to the definition of refractive index, the refractive index of the material is defined as the ratio of speed of light in vacuum to the speed of light in medium.

(a) refractive index, n = 1.52

\(n=\frac {c}{v}\\\\1.52 = \frac{3\times 10^8}{v}\\\\v = 1.97\times 10^8 m/s\)

(b) refractive index, n = 1.51

\(n=\frac {c}{v}\\\\1.51 = \frac{3\times 10^8}{v}\\\\v = 1.99\times 10^8 m/s\)

(c) refractive index, n = 1.36

\(n=\frac {c}{v}\\\\1.36 = \frac{3\times 10^8}{v}\\\\v = 2.21\times 10^8 m/s\)

Answer:

Explanation:

speed=distance/time = 200/25=8m/s^2

Answer:

The weight of the load can be calculated by using the principle of mechanical advantage of a lever. The mechanical advantage of a lever is the ratio of the force exerted on the load (F_L) to the force applied to the lever (F_A). In this case, the mechanical advantage of the lever is given by the ratio of the distance the load moves (0.2 m) to the distance the force is applied (1.2 m), or MA = 0.2/1.2 = 1/6.

So the force exerted on the load (F_L) is 6 times the force applied to the lever (F_A) and the weight of the load can be calculated as:

Weight of the load (F_L) = Mechanical advantage x Applied force (F_A)

F_L = (1/6) * 50 N = 8.33 N

So the weight of the load is 8.33 N.

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Answer:

a) A = 3 cm,  b)  T = 0.4 s,   f = 2.5 Hz,

2) A standing wave the displacement of the wave is canceled and only one oscillation remains

Explanation:

a) in an oscillatory movement the amplitude is the highest value of the signal in this case

          A = 3 cm

b) the period of oscillation is the time it takes for the wave to repeat itself in this case

          T = 0.4 s

the period is the inverse of the frequency

         f = 1 /T

         f = 1 /, 0.4

         f = 2.5 Hz

2) a traveling wave is a wave for which as time increases the displacement increases, in the case of a transverse wave the oscillation is perpendicular to the displacement and in the case of a longitudinal wave the oscillation is in the same direction of the displacement.

A standing wave occurs when a traveling wave bounces off some object and there are two waves, one that travels in one direction and the other that travels in the opposite direction. In this case, the displacement of the wave is canceled and only one oscillation remains.

The magnitude of the vector sum of the two vectors V and W is determined as 240.84 m.

The given vector can be resolved into x and y axis as follows;

Vx = Vcosθ

Vx = 448cos(224)

Vx = -322.26

Vy = Vsinθ

Vy = 448 x sin224

Vy = -311.2

Wx = 336 x cos(75.9)

Wx = 81.86

Wy = 336 x sin75.9

Wy = 325.88

∑X = -322.26 + 81.86 = -240.4

∑Y = -311.2 + 325.88 = 14.68

R = √[(-240.4)² + (14.68)²]

R = 240.84 m

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In accordance with the Aufbau principle, electrons occupy atomic orbitals from the lowest energy to a highest energies.

One electron represents the initial energy level. Larger atoms have more electrons. Always start by adding to the lowest energy level until it has all the electrons it can have. Electrons are subsequently filled in at the higher energy level below, and so on.

Nuclear energy is the term used to describe the energy present in the nucleus, or core, of an atom. Nuclear energy can be used to generate electricity, but first it needs to be freed from the atom.

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The initial temperature of the water was approximately 81.67°C.

To solve this problem, we can apply the principle of energy conservation. The heat lost by the copper block is equal to the heat gained by the water.

The heat lost by the copper block can be calculated using the formula: Q1 = m1 * c1 * ΔT1,

where m1 is the mass of the copper block (40 g), c1 is the specific heat capacity of copper (0.39 J/g°C), and ΔT1 is the change in temperature (final temperature - initial temperature of the copper block).

The heat gained by the water can be calculated using the formula: Q2 = m2 * c2 * ΔT2, where m2 is the mass of the water (105 g), c2 is the specific heat capacity of water (4.18 J/g°C), and ΔT2 is the change in temperature (final temperature - initial temperature of the water).

Since the copper block and the water reach equilibrium, Q1 = Q2. Therefore, we can equate the two equations:

m1 * c1 * ΔT1 = m2 * c2 * ΔT2

Substituting the given values:

(40 g) * (0.39 J/g°C) * (95°C - initial temperature) = (105 g) * (4.18 J/g°C) * (24°C - initial temperature)

Simplifying the equation and solving for the initial temperature of the water gives us approximately 81.67°C.

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The resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.

Given:

Pressure head in the aquifer = 100 ft (or 30.48 m)

The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:

Fluid pressure (P) = ρ * g * h

Where:

ρ = density of the fluid (water) = approximately 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = pressure head

Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)

The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.

Now, let's consider the changes in the hydraulic head due to pumping:

Change in hydraulic head = -12 ft (or -3.66 m)

The resulting changes in each parameter will be as follows:

1. Pressure head:

The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).

2. Fluid pressure:

The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.

3. Effective stress:

The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.

4. Total stress:

The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.

Therefore, the resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

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Answer:

the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Explanation:

In this hypothetical system the electric force is of type

       F = \(k' \frac{q_1 q_2 }{r^2}\)

in this case the force decays to zero much faster,

if we call Fo the force of Coulomb's law

         F₀ = \(k \frac{q_1 q_2 }{r^2}\)

assuming the constant k is the same

the relationship between the two forces is

        F / F₀ = 1 / r

        F = F₀ / r

when analyzing this expression the force decays much faster to zero.

In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law

Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Answer:

4 seconds

Explanation:

Answer: A, B, and C

Explanation: A standard room-vacuuming robot doesn't unpack itself from the box it comes in.

Answer: A) and D)

Explanation: