\Which expression is equivalent to Negative 2 and one-fourth divided by negative two-thirds?
StartFraction 9 over 4 EndFraction divided by three-halves
Negative StartFraction 9 over 4 EndFraction divided by (negative two-thirds)
Negative StartFraction 9 over 4 EndFraction divided by two-thirds
StartFraction 9 over 4 EndFraction divided by (negative three-halves)

Answer:

m=1/2

Step-by-step explanation:

m=y2-y1/x2-x1

m=12-10/8-4

m=2/4

m=1/2

Answer:

  10.35 kg

Step-by-step explanation:

Given a bag of sugar weighs 3.45 kg, you want the weight of 3 bags.

The weight of 3 bags will be three times as much as the weight of one bag:

  3 × 3.45 kg = 10.35 kg

Three such bags weigh 10.35 kg.

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Answer:

B. 1

Step-by-step explanation:

1. Simplify everything in the parentheses (4^4) = 256

2. Simplify 256^9 = 4.7223665e+21

3. Divide your answer by 4^36 (= 4.7223665e+21) which equals 1.

If the standard deviation of a set of data is 6, then the value of variance is 36

The formula for determining variance is variance = √Standard deviation

Variance of a set of data is equal to square of the standard deviation.

If the standard deviation of a set of data is 6 then we get variance by putting the value of standard deviation in the formula

variance = √Standard deviation

Take square root on both sides

Standard deviation² = 6²

Standard deviation= 36

Hence,  standard deviation of a set of data is 6, then the value of variance is 36

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Answer:

16

Step-by-step explanation:

The most important factor is the total budget $1816.50, for the soccer tournament.

1. Subtract $880.50 from $1816.50 = $936

2. We have $936 left, and a budget of $58.50 per player for meals

3. Divide 936/58.50 = 16

4. 16 soccer players can be brought to the tournament

In evaluating the determinants when a = 2, b = 5, and c = -1, we find the following results. (a) The determinant of the matrix [0 b 0 a 0 0 0 0 c] is 0. (b) The determinant of the matrix [a 0 1 0 c 0 b 0 -12] is 28.

(a) To evaluate the determinant of the matrix [0 b 0 a 0 0 0 0 c], we can expand along the first row. We get 0 times the determinant of the submatrix [a 0 0 0 c 0 0 c] minus b times the determinant of the submatrix [0 0 0 0 c 0 0 c]. Plugging in the given values, we have 0 times (-c²) - b times (0) = 0. Therefore, the determinant is 0.

(b) For the matrix [a 0 1 0 c 0 b 0 -12], we can expand along the first column. This yields a times the determinant of the submatrix [0 1 0 -12 b 0] minus 0 times the determinant of the submatrix [1 0 -12 b 0 -12]. Substituting the given values, we have a times (-12b) - 0 times (1)(-12) = -12ab. Since a = 2, b = 5, the determinant becomes -12(2)(5) = -120. However, we are asked to evaluate the determinant when a = 2, b = 5, and c = -1. Thus, we obtain -120 when substituting the values.

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Answer:

There are 28 marbles in the box. Some are red (12), others are yellow (6) and others are blue (10).

If in this box there 28 marbles and 6 of them are yellow, we substract to get the quantity of marbles that aren't yellow: 28-6 = 22

So 22 of the 28 marbles aren't yellow: 22/28, which we can simplify dividing the numerator and denominator by 2: 11/14

Answer:

(2x + 1)(x - 3)

Step-by-step explanation:

\(y = 2 {x}^{2} - 5x - 3\)

\(2 {x}^{2} - 5x - 3 = 0\)

\((2x + 1)(x - 3) = 0\)

\(x = - \frac{1}{2} \)

\(x = 3\)

Janet had $450 at first.

Let's assume that the bag cost x dollars, then the watch will cost (x + 120) dollars. Janet used 1/3 of her money to buy the bag, which means she spent (1/3)M = x dollars on the bag. This implies that she had 2/3M dollars left, where M is the amount of money she had at first.

Now, we know that Janet was short of $50 to buy the watch, which means she had (x + 120 - 50) = (x + 70) dollars left after buying the bag. This amount is equal to 2/3*M dollars. So, we can write the equation (2/3)*M = (x + 70).

Substituting x = (1/3)*M in the above equation, we get: (2/3)*M = (1/3)*M + 70. Solving for M, we get M = 450.

Therefore, Janet had $450 at first.

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Answer:

1/15

Step-by-step explanation:

10 blocks altogether

P(Y,G) = 3/10 x 2/9

Answer:1/15

Step-by-step explanation:

Answer:

75%

Step-by-step explanation:

15+15+25+5=60

15/60=25%

100%-25% = 75%

Answer:

236.5 is correct Answer. Please mark me as brainlist answer.

Answer: 236.5 milles

Step-by-step explanation:

Let's make a proportion:

387 milles - 18 gallons

 x   milles - 11 gallons

Hence,

\(\displaystyle\\x=\frac{(387)(11)}{18}\\\\x=\frac{(9)*(43)*(11)}{(9)(2)} \\\\x=\frac{(43)(11)}{2}\\\\x=\frac{473}{2} \\\\x=236.5\ milles\)

The 8 painters will take 12 hours and 9.6 minutes to paint the office. The result is obtained by comparing the two variables, worker and time duration.

If the they work at the same rate, find the time needed for the 8 painters to finish their job!

Let's say

We convert the unit of time in hours.

t₁ = 7 h 36 min

t₁ = (7 + 36/60) h

t₁ = (7 + 0.6) h

t₁ = 7.6 hours

If they work at the same rate, the number of workers and time durations of each day are directly proportional. So,

w₁/w₂ = t₁/t₂

5/8 = 7.6/t₂

t₂ = 8/5 × 7.6

t₂ = 12.16 hours

In hours and minutes,

t₂ = 12 h + (0.16 × 60) min

t₂ = 12 h 9.6 min

Hence, to paint the office, the 8 painters will take 12 hours and 9.6 minutes.

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The value of a₃₁ of the arithmetic sequence exists 77.4.

Given: a₅ = 12.4 and a₉ = : 22.4

For the arithmetic sequence a₁, a₂, a₃, ..., the n-th term exists

where d = common difference

a₅ = 12.4,

a₁ + 4d = 12.4 .........(1)

Because a₉ = 22.4,

a₁ + 8d = 22.4 .........(2)

Subtract (1) from (2), we get

a₁ + 8d - (a₁ + 4d) = 22.4 - 12.4

4d = 10

Dividing throughout by 4, we get

d = 2.5

From (1), we get

a₁ = 12.4 - 4 \(*\) 2.5 = 2.4

a₃₁ = 2.4 + 30 \(*\) 2.5 = 77.4

Therefore, the correct answer is a₃₁ = 77.4

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Answer:

Step-by-step explanation:

john lennon

Answer:

5.7 units

Step-by-step explanation:

Answer:

x=-3

Step-by-step explanation:

x=-12/4 divide both sides by 4

Answer:

x = -3

Step-by-step explanation:

Let's solve your equation step-by-step.

4x=−12

Step 1: Divide both sides by 4.

4x/4 = -12/4

x=−3

The after-tax salvage value be $10,600.

The after-tax salvage value is the market price minus (or plus) the taxes on the sale of the equipment, so:

After-tax salvage value = MV + (BV – MV) tc

1st year Depreciation Amount = $50,000 * 0.20 = $10,000

2nd year Depreciation Amount = $50,000 * 0.32 = $16,000

3rd year Depreciation Amount = $50,000 * 0.19 = $9,500

4th year Depreciation Amount = $50,000 * 0.12 = $6,000

Book Value of machine at the end of 4th year = [$10,000 + $16,000 + $9,500 + $6,000]

Book Value of machine at the end of 4th year = $41,500

Book Value of machine at the end of 4th year = [$50,000 - $41,500]

Book value of machine at the end of 4th year = $8,500

After-tax salvage value = MV + (BV – MV) tc

After-tax salvage value = $12,000 + ($8,500 - $12,000) 40%

After-tax salvage value = $12,000 + (-$1,400)

After-tax salvage value = = $12,000 - $1,400=$10,600

Therefore, the after-tax salvage value be when the machine is sold at the end of year 4 is $10,600.

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The height of the kite is approximately 68.4 ft.

To solve the problem, we can use trigonometry. We know that the string is the hypotenuse of a right triangle, with the height of the kite as one of the legs. The angle of elevation, which is the angle between the string and the ground, is also given. We can use the tangent function to find the height of the kite:

tan(46°) = height / 94

Solving for height, we get:

height = 94 * tan(46°)

Using a calculator, we get:

height ≈ 68.4 ft

Therefore, the height of the kite is approximately 68.4 ft.

We use the given angle of elevation and the length of the string to set up a right triangle with the height of the kite as one of the legs. Then, we use the tangent function to relate the angle to the height of the kite. Finally, we solve for the height using a calculator and round to the nearest tenth as requested.

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Complete Question:

A kite flying in the air has a 94-ft string attached to it, and the string is pulled taut. The angle of elevation of the kite is 46 °. Find the height of the kite. Round your answer to the nearest tenth.

Answer:

.17 per once for the smaller box and .15 for the bigger box

Step-by-step explanation:

Using system of linear equations he will require 20kg of 15% copper and 30kg of 70% copper to produce an alloy of 48% in 50kg

The system of linear equations is the set of two or more linear equations involving the same variables. Here, linear equations can be defined as the equations of the first order, i.e., the highest power of the variable is 1. Linear equations can have one variable, two variables, or three variables.

To solve this problem, we need to write a system of linear equations and find the equivalent amount of the metal required to make the desired amount of the alloy.

0.15x + 0.7y = 0.48(50) ..eq(i)

0.15x + 0.7y = 24 ...eq(i)

x + y = 50 ...eq(ii)

solving equation (i) and (ii)

x = 20, y = 30

He needs 20kg of 15% copper and 30kg of 70% copper to get 48% of 50kg of alloy.

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Answer:

The sailboat and speedboat meet at x=3.

Step-by-step explanation:

Assuming your first equation is \(-x^{2} +2x+8\) (you missed the square).

\(-x^{2} +2x+8=-x+8\\x^{2} -3x=0\\x(x-3)=0\\x=0\\x=3\\\)

Answer:

The answer is "descriptive statistics".

Step-by-step explanation:

Descriptive statistics are short descriptive factors that add up a production set, that can be either a reflection of a whole or a sample population. It is broken down into cumulative frequency measurements and variance measurements. The study uses descriptive statistics to explain the profile of the respondents. People give simple summaries about the sample as well as the actions.

Answer:

1/5

Step-by-step explanation:

a. The regular rate of markup on cost is approximately 26%.

b. The rate of markdown on the demonstrator unit is approximately 20%.

c. The operating profit on the demonstrator unit is approximately $3.73.

d. The rate of markup on cost that was actually realized is approximately 0.28%.

a. To calculate the regular rate of markup on cost, we need to find the difference between the selling price and the cost, and then calculate the percentage markup based on the cost.

Let's denote the cost as C.

Selling price = Cost + Markup

$1,690 = C + (26% of C)

To find the cost:

$1,690 = C + 0.26C

$1,690 = 1.26C

C = $1,690 / 1.26

C ≈ $1,341.27

Markup on cost = Selling price - Cost

Markup on cost = $1,690 - $1,341.27

Markup on cost ≈ $348.73

Rate of markup on cost = (Markup on cost / Cost) * 100

Rate of markup on cost = ($348.73 / $1,341.27) * 100

Rate of markup on cost ≈ 26%

The regular rate of markup on cost is approximately 26%.

b. The rate of markdown on the demonstrator unit can be calculated by finding the difference between the original selling price and the clearance price, and then calculating the percentage markdown based on the original selling price.

Original selling price = $1,690

Clearance price = $1,345

Markdown = Original selling price - Clearance price

Markdown = $1,690 - $1,345

Markdown = $345

Rate of markdown on the demonstrator unit = (Markdown / Original selling price) * 100

Rate of markdown on the demonstrator unit = ($345 / $1,690) * 100

Rate of markdown on the demonstrator unit ≈ 20%

The rate of markdown on the demonstrator unit is approximately 20%.

c. Operating profit or loss on the demonstrator unit can be calculated by finding the difference between the clearance price and the cost.

Cost = $1,341.27

Clearance price = $1,345

Operating profit or loss = Clearance price - Cost

Operating profit or loss = $1,345 - $1,341.27

Operating profit or loss ≈ $3.73

The operating profit on the demonstrator unit is approximately $3.73.

d. The rate of markup on cost that was actually realized can be calculated by finding the difference between the actual selling price (clearance price) and the cost, and then calculating the percentage markup based on the cost.

Actual selling price (clearance price) = $1,345

Cost = $1,341.27

Markup on cost that was actually realized = Actual selling price - Cost

Markup on cost that was actually realized = $1,345 - $1,341.27

Markup on cost that was actually realized ≈ $3.73

Rate of markup on cost that was actually realized = (Markup on cost that was actually realized / Cost) * 100

Rate of markup on cost that was actually realized = ($3.73 / $1,341.27) * 100

Rate of markup on cost that was actually realized ≈ 0.2781% ≈ 0.28%

The rate of markup on cost that was actually realized is approximately 0.28%.

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Answer:

20% off is better

Step-by-step explanation:

because 20% of 5000 is 1000

and 1000 is greater than 500

hope this helps!!!

20% discount

Step-by-step explanation:

20% of 5000 is 1000

which would mean they would only pay 4000$

and that is less than 5000-500=4500

nearly 3 pounds of salmon she bought spending $19.32.

What is division?

A division is one of the fundamental mathematical operations that divides a larger number into smaller groups with the same number of components. How many total groups will be established, for instance, if 20 students need to be separated into groups of five for a sporting event? The division operation makes it simple to tackle such issues. Divide 20 by 5 in this case. 20 x 5 = 4 will be the outcome. There will therefore be 4 groups with 5 students each. By multiplying 4 by 5 and receiving the result 20, you may confirm this value.

At the neighborhood grocery 0. 5 pounds of salmon cost $3. 45

So in $1 she will get 0.5/3.45 pound

For 19.32 she will be get = 0.5/3.45 * 19.32  = 2.8 pounds

Hence, nearly 3 pounds of salmon she bought spending $19.32.

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