Answer: The motion of a ball falling down through the atmosphere, or a model rocket being launched up into the atmosphere are both examples of Newton's first law. The motion of a kite when the wind changes can also be described by the first law.
Explanation:
What does g stand for
Group of answer choices
gravity
The acceleration of gravity
The force of gravity
Answer:
the acceleration of gravity.
Answer:
g stand for the acceleration of gravity .
Explanation:
A skier at the bottom of a hill has 900J of kinetic energy. After sliding a ways along the flat, the kinetic energy is 300J. How much energy was lost due to friction?
Answer:
600 J
Explanation:
900 j = 300j = 600 j lost due to friction
Energy lost due to friction is 600 J.
The kinetic energy before and after friction is given as 900J and 300J.
What is friction?The force that resists the sliding or rolling over one object with another is called friction. The energy which possess in virtue of being in motion is said to be Kinetic Energy.
f = μN
Energy lost = 900J - 300J
= 600J
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what type of energy is kinetic energy? A nuclear energy B chemical energy C potential energy D mechanical energy
Answer:
I believe it is C, Potential
Explanation:
Google, since all types are either kinetic or potential, so it wouldn't make sense if kinetic was itself. I also know for a fact it isn't Chemical
2. A girl and her bicycle have a total mass of 40 kg. At the top of the hill her speed is 5.0 m/s.
The hill is 10 m high and 100 m long.
If the magnitude of the force of friction as she rides down the hill is 20 N, what is her speed
at the bottom of the hill? (Take g=9.8 m/s?)
(a) 5.0 m/s
(b) 10 m/s
(c) 11 m/s
(d) 18 m/s
(e) She stops before she reaches the bottom.
Answer:
Explanation:
1. First draw a free body diagram of the scenerio (a block sliding down a a slant surface).
2. Then we analyze the forces and write equations that satisfy Fnet = ma. This will give us the acceleration as the block slides down the surface.
3. Last, we can use the kinematic equation (vf^2 = vi^2 + 2as) and to solve the final speed of the block.
math
Determine if the function below is continuous.
graph of a piecewise function, with 2 pieces. The first piece is a line that starts at negative infinity and goes through point (-4,5) and ends with an open dot at (1,0). The second piece is a line that starts with a closed dot at (1,-1), goes through point (2,1) and continues to infinity.
A. not continuous at x = 1
B. not continuous at x = 0
C. not continuous at x = -1
D. continuous
The function is not continuous at x=1, so the answer is A.
At x=1, the two pieces of the function meet. The first piece ends with an open dot at (1,0), meaning that the function is not defined at $x=1$. The second piece starts with a closed dot at (1,-1), meaning that the function is defined at x=1 and takes the value -1 there.
Since the function is not defined at x=1, it cannot be continuous at that point. Therefore, the function is not continuous overall.
A ball is held at rest at some height above a hard, horizontal surface. Once the ball is released it falls, hits the surface, and starts bouncing vertically up and down. Suppose that with each bounce the ball loses a fixed fraction p (with 1>p>0) of its energy. This loss could be due to a number of reasons (inelasticity, drag, etc) that are left unspecified.How many times will the ball bounce before coming to rest (if at all)? Provide a detailed explanation of your reasoning, not simply a one-line answer.How long will it take for the ball to come to rest (if at all)? Give your answer as a formula that contains as variables only p and the time T1 from the moment that the ball was released to the first contact with the horizontal surface.
It can never theoretically become 0. After n bounces, it may be closer to 0 or extremely tiny, depending on the precise values of p and T1.
Briefing:initial height dropped =h = gT12/2
T1 - time from the moment that the ball was released to the first contact with the horizontal surface.
initial energy T = mgh
after first bounce energy loss = mghp
height it will raise after first bounce mgh1 = mgh(1-p)
after each bounce its energy is reduced by p
after n bounces it will raise to a height
mghn=mgh(1-p)n
hn= h(1-p)n = gT12/2 *(1-p)n
gT₁² (1-p)n/2
Theoritically hn can never become 0. It can be closer to 0 or can be negligibly small after n bounces, depending on the actual values of p and T1 .
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A boy starts at rest and slides down a frictionless slide as in the figure below. The bottom of the track is a height h above the ground. The boy then leaves the track horizontally, striking the ground a distance d as shown. Using energy methods, determine the initial height H of the boy in terms of h and d.
The initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track: H = h + d.
To determine the initial height H of the boy in terms of h and d, we can use the principle of conservation of energy. The total mechanical energy of the system remains constant throughout the motion.
At the top of the slide, the boy has gravitational potential energy given by mgh, where m is the mass of the boy, g is the acceleration due to gravity, and h is the height of the slide above the ground.
As the boy slides down the slide, there is no friction or other dissipative forces, so there is no change in mechanical energy. At the bottom of the track, the gravitational potential energy is converted entirely into kinetic energy.
Therefore, we can equate the initial potential energy to the final kinetic energy:
mgh = 1/2 m\(v^{2}\),
where v is the horizontal velocity of the boy when he leaves the track.
Since the boy leaves the track horizontally, the vertical component of his velocity is zero. Therefore, we can use the relationship between horizontal distance d and horizontal velocity v:
d = vt.
Solving these equations, we can express the initial height H in terms of h and d:
H = h + d.
So the initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track.G
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Which is a benefit of using synthetic polymers, such as nylon?
Synthetic polymers are lightweight.
O Synthetic polymers are produced in small
quantities.
Synthetic polymers are biodegradable.
Synthetic polymers are inexpensive to recycle.
Answer: Synthetic polymers are lightweight.
Explanation:
A benefit of using synthetic polymers is the fact that synthetic polymers are lightweight.
A polymer is a molecule composed of many repeating subunits.
Synthetic polymers are artificial polymers created by humans.
Most of the synthetic polymers are not biodegradable (unlike natural fibers such as cotton).
Synthetic polymers are classified according to their use into plastics, elastomers and synthetic fibers.
The advantages of synthetic polymers include: hard to break, being lightweight, and they last for a long time.
In conclusion, a benefit of using synthetic polymers is the fact that synthetic polymers are lightweight.
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can anyone write for me all the equation of linear motion
All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.
Equations of MotionIn terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.
s = ut + (1/2)at^2v = u + atv_avg = (u + v) / 2s = v_avg * ts = (u + v) / 2 * tv^2 = u^2 + 2asIn conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.
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why fan videos be streamed from the cloud to a computer with no lost quality
Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.
How do digital signals work?
An established or one that represents data as a step made up of discrete values is known as a digital signal. There is no noise produced by digital signals. Electronic signals sent as pulses are used to transmit digital signals to computers. These signals can be found in things like digital phones and computers.
Because digital signals are used to transport data to and from the cloud, it should be noted that videos are said to stream from the cloud to a computer without quality degradation.
Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.
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Austin invested $11,000 in an account paying an interest rate of 5.7% compounded quarterly. Assuming no deposits or withdrawals are made, how much money, to the nearest dollar, would be in the account after 6 years?
Answer:
15448
Explanation:
A=11000(1.01425)^{24}
A=11000(1.01425)
24
Austin invested $11,000 in an account paying an interest rate of 5.7% compounded quarterly. Assuming no deposits or withdrawals are made, the money to the nearest dollar, would be in the account after 6 years is 15448.
What is Compound interest?The compound interest occurs when the interest is reinvested rather than paying it out. It's basically earning interest over interest.
The formula is:
Compound interest, \(A = P ( 1 +\frac{r}{n} )^{nt}\)
Where:
A = final Amount
P = initial principal balance
r = interest rate
n = number of times interest applied per time period
t = number of time periods elapsed
Austin invested P=$11000 in an account with an interest rate of r=5.7% = 0.057 (decimal) during t=6 years compounded quarterly. Since there are 4 quarters in a year, n=4.
Thus, Substituting all the values in the given formula,
A = 11000 ( 1 + \(\frac{0.057}{4} )^{6*4}\)
= 11000 × 1.4043662796
= 15448.0290
The money to the nearest dollar, would be in the account after 6 years is 15448.
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7. A girl pushes her little brother on his sled with a force of 300. N for 750. m. How much work is this if the force of friction acting on the sled is (a) 200. N. (b) 300. N?
Answer:
a) 75000Joules
b) 0Joules
Explanation:
Workdone = Force * Distance
Given
distance= 750m
Force = 300N
a) If the frictional force = 200N
The Total force = 300N - 200N = 100N
Work done = 100 * 750
Workdone = 75,000Joules
Hence the workdone if the force of friction is 200N is 75,000Joules
b) If the frictional force = 300N
The Total force = 300N - 300N = 0N
Work done = 0* 750
Workdone = 0Joules
Hence the workdone if the force of friction is 300N is 0Joules i.e no work will be done on the sled
A 100 kg. football player and a 20 kg. child sit on rolling carts and push off
from each other. Which person applies more force?*20 kg. child applies more force
100 kg. football player applies more force
Same force is applied
Answer:
the forces are the same
Explanation:
Jacob is a white male who has lived in an economically depressed area for his entire life. His mother had him when she was very young, so he lives with her, his grandmother, his uncle, and his little sister in a small appointment. There is not a lot of space, so it is hard for Jacob to concentrate on homework and often he doesn’t do it. Is Jacob at risk for dropping out of high school?
A.
Yes. Jacob’s background suggests a lot of risk factors.
B.
Yes. It is clear that Jacob thinks he can succeed without school.
C.
No. Race is the most important factor in determining which students drop out.
D.
No. Jacob just needs to find a place where he can focus and complete his work.
The environmental and familial challenges he faces indicate an increased risk of dropping out. Yes. Jacob's background suggests a lot of risk factors is the most accurate response. Here option A is the correct answer.
Jacob's situation presents several risk factors that could increase his likelihood of dropping out of high school. First, living in an economically depressed area can limit access to quality educational resources and opportunities, making it harder for Jacob to thrive academically. The lack of space in his small apartment further compounds the problem, as it becomes challenging for him to concentrate on his homework. The absence of a conducive environment for studying can negatively impact his motivation and ability to complete assignments consistently.
Moreover, Jacob's family dynamics may also contribute to his risk of dropping out. Being raised by a young mother, living with his grandmother, uncle, and little sister in a crowded space could imply limited financial resources and potential disruptions at home. These factors may increase stress levels and make it more difficult for Jacob to prioritize his education and engage in school-related activities effectively.
While race and ethnicity can influence educational outcomes, it is essential to consider the specific circumstances and individual factors in Jacob's life rather than assuming that race alone is the most important determinant.
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You are pulling with 57 N on a heavy bookshelf, but the bookshelf doesn't move. What is the force of static friction in Newtons acting on the bookshelf?
Answer:
57N
Explanation:
Since the bookshelf isn't moving, the force you're exerting on the shelf must be equal to the force of static friction
So the force of static friction is 57N
The maximum speed with which an 1000 kg car makes a 180-degree turn is 10 m/s. The radius of the circle through which the car is turning is 24 m. Determine the force of friction and the coefficient of friction acting upon
the car.
Two equal and opposite charges are placed 40mm apart,if the force between them is found to be 0.5N Calculate the magnitude of the charge
7. A particle of mass 3 kg is held in equilibrium by two light unextensible strings. One string is horizontal, as shown in Figure 7.30. The tension in the horizontal string is PN and the tension in the other string is N. Find a) the value of 0 b) the value of P.
The tension in the strings are 31.47 and 19.25 N respectively.
Mass of the block, m = 3 kg
From the figure, consider the vertical components,
T₁ sin45° + T₂ sin30° = mg
(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4
Also, consider the horizontal components,
T₁ cos45° = T₂ cos30°
T₁/√2 = T₂ x√3/2
T₁ = T₂ x √3/2 x √2
So,
T₁ = 0.612T₂
Applying in the first equation,
(T₁/√2) + (T₂/2) = 29.4
(0.612T₂/1.414) + 0.5T₂ = 29.4
0.434 T₂ + 0.5 T₂ = 29.4
0.934 T₂ = 29.4
Therefore, the tension,
T₂ = 29.4/0.934
T₂ = 31.47 N
So, the tension,
T₁ = 0.612 T₂
T₁ = 0.612 x 31.47
T₁ = 19.25 N
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The graph below shows the variation with distance r from the nucleus of the square of the wave function, Ψ^2, of a hydrogen atom according to Schrödinger theory.
A. is most likely to be near a.
B. is always a.
C. is always less than a.
D. is always greater than a.
The region a represents the distance of the electron from the nucleus.
According to the wave mechanical model of the atom, the probability of finding an electron within a given volume element (representing the atom) is the square of the wave function psi.
Since a is the region in space where there is the greatest probability of finding the electron in the atom, it follows that distance of the electron form the atom is always a.
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An electron has an initial velocity of (12.0 j + 15.0 k) j km/s and a constant acceleration of (2.00 Times 10^12 m/s^2)i in a region in which uniform electric and magnetic fields are present. If B = (400 mu T)i, find (he electric field E.
An electron has an initial velocity of (12.0 j + 15.0 k) j km/s and a constant acceleration of (2.00x10^12 m/s^2)i in a region in which uniform electric and magnetic fields are present. If B = (400 mu T)i. Then Electric field E is \(\\=\ 2.26 * 10^5 V/m\)
To find the electric field E, we can use the equation of motion for a charged particle moving in both electric and magnetic fields:
F = q(E + v x B) = ma
where F is the net force on the particle, q is the charge of the particle, v is its velocity, B is the magnetic field, a is its acceleration, and E is the electric field.
Since the electron has a constant acceleration of (2.00 x 10^12 m/s^2)i and no force is acting on it in the x and y directions, we can set the x and y components of the equation equal to zero:
qBv = ma
qE = ma
where m is the mass of the electron.
Solving for B and E, we get:
B = ma/qv
\(= (9.11 * 10^{-31} kg)(2.00 * 10^{12} m/s^2)/(1.602 * 10^{-19} C)(15 * 10^3 m/s)\\ \\= 0.00380 T\)
E = ma/q
\(= (9.11 * 10^{-31} kg)(2.00 * 10^{12} m/s^2)/(1.602 * 10^{-19} C) \\=\\ 2.26 * 10^5 V/m\)
Note that we converted the given velocity from km/s to m/s and the magnetic field from μT to T.
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How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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If Janine is a typical middle-aged woman, she is likely to be concerned about all of the following things except for one. Identify the option that is generally not a concern for the average middle-aged woman ?
For a typical middle-aged woman, there are certain priorities for them such as job stability, kids, and so on, but one factor that is generally not a concern for the average middle-aged woman is how to train for the Olympics
Who is a middle-aged woman?Midlife, the stage of a woman's life between childhood and elder maturity, has been called a time of transition. Women between the ages of 40 and 65 have been the focus of midlife research because they often go through a number of social, psychological, and biological shifts during this time.
Hence, it can be seen that while there are genuine concerns for a middle-aged woman, the answer choice that is generally not a concern for the average middle-aged woman is to become an Olympian.
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If Janine is a typical middle-aged woman, she is likely to be concerned about all of the following things except for one. Identify the option that is generally not a concern for the average middle-aged woman ?
train for the Olympics
have kids
raise a family
An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of â3.45Ã10^â3 V .The charge and the mass of an alpha particle are qα = 3.20Ã10^â19 C and mα = 6.68Ã10â27 kg , respectively.
Mechanical energy is conserved in the presence of which of the following types of forces?
a. electrostatic
b. frictional
c. magnetic
d. gravitational
Answer:
Speed = 575 m/s
Mechanical energy is conserved in electrostatic, magnetic and gravitational forces.
Explanation:
Given :
Potential difference, U = \($-3.45 \times 10^{-3} \ V$\)
Mass of the alpha particle, \($m_{\alpha} = 6.68 \times 10^{-27} \ kg$\)
Charge of the alpha particle is, \($q_{\alpha} = 3.20 \times 10^{-19} \ C$\)
So the potential difference for the alpha particle when it is accelerated through the potential difference is
\($U=\Delta Vq_{\alpha}$\)
And the kinetic energy gained by the alpha particle is
\($K.E. =\frac{1}{2}m_{\alpha}v_{\alpha}^2 $\)
From the law of conservation of energy, we get
\($K.E. = U$\)
\($\frac{1}{2}m_{\alpha}v_{\alpha}^2 = \Delta V q_{\alpha}$\)
\($v_{\alpha} = \sqrt{\frac{2 \Delta V q_{\alpha}}{m_{\alpha}}}$\)
\($v_{\alpha} = \sqrt{\frac{2(3.45 \times 10^{-3 })(3.2 \times 10^{-19})}{6.68 \times 10^{-27}}}$\)
\($v_{\alpha} \approx 575 \ m/s$\)
The mechanical energy is conserved in the presence of the following conservative forces :
-- electrostatic forces
-- magnetic forces
-- gravitational forces
A cannon fires a cannonball directly upward at 300 m/s. How long (in s) does the cannonball move upward before stopping?
The time taken for the cannonball to move upward before stopping, given that is was fired directly upward at 300 m/s is 30.6 seconds
How to I determine the time?Velocity and time are related according to the following equation of motion
v = u + gt
Where
v is the final velocityu is the initial velocityg is the acceleration due to gravityt is the timeFrom the question given above, the following data were obtained:
Initial velocity (u) = 300 m/sFinal velocity (v) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Time taken to stop (t) = ?The time taken for the cannonball to move upward before stopping can be obtained as illustrated below:
v = u - gt (since the ball is going against gravity)
0 = 300 - (9.8 × t)
0 = 300 - 9.8t
Collect like terms
-9.8t = 0 - 300
-9.8t = -300
Divide both sides by -9.8
t = -300 / -9.8
t = 30.6 seconds
Thus, the time taken is 30.6 seconds
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6- If a mass of 600 g attached to a vertical spring stretches the spring 3 cm from its original equilibrium position, what is the
value of the spring constant?
The spring constant of the spring, is 1.96 x 10³ N/m.
Mass of the object attached to the spring, m = 600 g = 0.6 g
Displacement of the spring from equilibrium position, x = 3 cm =0.003 m
The restoring force is the force that makes anything return to its original size and shape.
In an idealised spring, the force acting in the direction opposite the deformation is proportional to the amount of the spring's displacement from its equilibrium length.
The expression for the restoring force of the spring is given by,
F = -kx
Therefore, the spring constant of the spring,
k = F/x
k = mg/x
k = 0.6 × 9.8/0.003
k = 1.96 x 10³ N/m
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A Ferris wheel rotates at an angular velocity of 0.25 rad/s. Starting from rest, it reaches its operating speed with an average angular acceleration of 0.027 rad/s2. How long does it take the wheel to come up to operating speed?
Answer:
t = 9.25 s
Explanation:
Given that,
Initial angular velocity, \(\omega_o=0\) (at rest)
Final angular velocity, \(\omega_o=0.25\ rad/s\)
Angular acceleration, \(\alpha =0.027\ rad/s^2\)
We need to find the time it take the wheel to come up to operating speed. We know that the angular acceleration in terms of angular speed is given by :
\(\alpha =\dfrac{\omega_f-\omega_o}{t}\\\\t=\dfrac{\omega_f-\omega_o}{\alpha }\\\\t=\dfrac{0.25-0}{0.027}\\\\t=9.25\ s\)
So, it will reach up to the operating speed in 9.25 s.
5One end of a wire is attached to a ceiling, and a solid brass ball is tied to the lower end. The tension in the wire is 120 N. What is the radius of the brass ball?
Answer:
Explanation:
Force of Tension = (m)(g)
120 = (m)(9.8)
m = volume(density)
120 = (4/3)πr³(0.308)(9.8)
\(\frac{(120)(3)}{(pi)(0.308)(9.8)}\) = r^3
solve
The radius of the brass ball is equal to 6.94 × 10⁻² m when the tension in the wire is 120 N.
What is tension?Tension can be demonstrated as the pulling force transmitted by the means of a string, or a rope or can be described as the action-reaction pair of forces acting at each end of said elements.
The tension in the wire attached to the ceiling will be given by:
T = mg ⇒m = T/g
The radius of the brass ball is given by: \(r =\sqrt[3]{\frac{3V}{4\pi } }\)
The density is given by: ρ = m/V = T/gV
V = T/gρ
Therefore, the expression for the radius can be written as:
\(r =\sqrt[3]{\frac{3T}{4\pi\rho g } }\)
Given the tension in the wire, T = 120 N
The density of the brass is = 8730 Kg/m³
\(r =\sqrt[3]{\frac{3\times 120}{4\times 3.14 \times 8730 \times 9.81 } }\)
r = 6.94 × 10⁻² m
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An intrepid hiker reaches a large crevasse in his hiking route. He sees a nice landing ledge 60.0 cm below his position but it is across a 2.3 m gap. He spends 1.2 s accelerating horizontally at 5.92 m/s2 [right] in an attempt to launch himself to the safe landing on the far side of the gap. Does he make it?
The hiker made it to a safe landing on the other side of the gap after travelling horizontally at 2.49 m.
What is the time motion from the vertical height?
The time taken for the hiker to fall from the given height is calculated as follows;
h = vt + ¹/₂gt²
where;
v is the vertical velocity = 0t is the time of motiong is acceleration due to gravityh is the height of fallh = ¹/₂gt²
t = √(2h/g)
t = √[(2 x 0.6) / (9.8)]
t = 0.35 seconds
The horizontal velocity of the hiker during the period of acceleration is calculated as follows;
Vₓ = at
Vₓ = (5.92 m/s²) x (1.2 s)
Vₓ = 7.104 m/s
The horizontal distance travelled during the time period of 0.35 seconds;
X = Vₓt
X = 7.104 x 0.35
X = 2.49 m
Thus, the hiker made it to a safe landing on the other side of the gap which is 2.3 m wide and smaller to his horizontal displacement of 2.49 m.
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What are the different ways that the simulation shows you that the equation is balanced, visually? For each balanced reaction, indicate the total number of molecules (the big coefficients) in the table. Reaction Total Number of Molecules Reactant Side (left) Product Side (right) Make Ammonia Separate Water Combust Methane Is the number of total molecules on the left side of a balanced equation always equal to the number of total molecules on the right side of the equation? Explain your answer. For each balanced reaction, indicate the total number of atoms (the individual atoms) in the table. Hint: This may requiring multiplying subscript numbers by coefficients for some atoms. Example: 2NH3–There are 2 N atoms, and 6 H atoms (2 x 3). Reaction Total Number of Atoms Reactant Side (left) Product Side (right) Make Ammonia Separate Water Combust Methane Is the number of total atoms on the left side of a balanced equation always equal to the number of total atoms on the right side of the equation? What strategies did you use when you played the balancing chemical equations game? Which atoms were the easiest to start examining to try to balance the equations? Did it require trial and error? In the simulation, were you able to use non-integer numbers (like ½ or 0.43) for the coefficients in a balanced equation?
Answer:
There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.
Reaction Total Number of Molecules
Reactant Side (left) Product Side (right)
Make Ammonia 4 2
Separate Water 2 3
Combust Methane 3 3
No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.
Reaction Total Number of Atoms
Reactant Side (left) Product Side (right)
Make Ammonia 1C, 4H, 4O 1 C, 4H, 4O
Separate Water 2H, 4O 2H, 4O
Combust Methane 2N, 6H 2N, 6H
Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.
Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.
No, you could not use a non-integer number.
Explanation:
PF
Answer: There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.
Reaction Total Number of Molecules
Reactant Side (left) Product Side (right)
Make Ammonia 4 2
Separate Water 2 3
Combust Methane 3 3
No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.
Reaction Total Number of Atoms
Reactant Side (left) Product Side (right)
Make Ammonia 1C, 4H, 4O 1 C, 4H, 4O
Separate Water 2H, 4O 2H, 4O
Combust Methane 2N, 6H 2N, 6H
Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.
Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.
No, you could not use a non-integer number.
How does increasing the width of a wire affect a circuit?
A. It restricts the flow of electrons.
B. It reduces the voltage
C. It allows electrons to flow more easily
D. It increases the resistance
Whoever gets this right I’ll give brainliest. Be sure that the answer is right. I’d love a explanation too if you could include one.
Answer:
The resistance of a wire decreases with increasing thickness.
Explanation:
Hope this helped!
Answer: C it allows electrons to flow more easily
Explanation:i got it right i hope this helps you