Which equation should you use to solve this
problem? (Don't solve it, just pick the right
equation.)
A car slows down from 27.7 m/s to 10.9 m/s
in 2.37 s. What is its acceleration?
A V2f = v2i + 2a(delta)x
B (Delta)x =1/2 (Vf +vi) t
C Vf=Vi + at
D Delta(x) = 1/2 (vft-1/2at^2
Answers
The equation C Vf=Vi + at is the equation for average acceleration. In this equation, Vf is the final velocity (10.9 m/s), Vi is the initial velocity (27.7 m/s), and t is the time (2.37 s). Solving for a gives the acceleration.
What is acceleration?Acceleration is the rate of change of an object's velocity over time. It is a vector quantity that measures how quickly an object's speed or direction of travel changes. Acceleration can be caused by a variety of forces, such as gravity, friction, and thrust. Acceleration can be uniform, in which the object's velocity changes at a constant rate, or non-uniform, in which the rate of change is variable. When an object's acceleration is in the same direction as its velocity, its speed increases; when acceleration is in the opposite direction, its speed decreases. In cases of uniform acceleration, the object's velocity will increase or decrease in direct proportion to the acceleration. Acceleration is an important concept in classical mechanics, in which it is related to momentum, force, and energy.
The equation you should use to solve this problem is:
C) Vf = Vi + at
This equation is one of the kinematic equations that relates the final velocity (Vf) of an object to its initial velocity (Vi), acceleration (a), and time (t) traveled.
To solve the problem, you can plug in the given values for the initial and final velocities and the time traveled, and solve for the acceleration (a).
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Related Questions
3. A traffic light has a total resistance of 22 kN and requires 10 mA of current to
operate. What is the voltage required to operate the traffic light?
Given: Resistance (R) = ____ KΩ × (1 000 Ω/1 K Ω) = ____ Ω
Current (I) = ____ mA × (1 A/ 1000 mA) = ____ A
Required: Voltage(V)
Solution: V = IR
V = (____ A) (____ Ω)
Answer: Voltage = ____ volt
I REALY NEED THE ANSWER
Answers
Answer:
V = 220 [V]
Explanation:
In order to solve this problem we simply need to replace the given values of current and resistance in the expressions proposed.
R = 22 [kΩ] = 22000 [Ω]
I = 10 [mA] = 0.01 [A]
Voltage (V)
\(V = 0.01*22000\\V = 220 [V]\\\)
How does the amount of a relationship between a ball’s height above the ground ( 0m, 1m, 2m, 3m, 4m 5m ) affect the gravitational potential energy (J).
Answers
Answer:
They are linearly proportional, i.e. the higher the ball is, the more potential energy it has.
Explanation:
The formula for gravitational potential energy is PE=mgh where m is mass of the object, h is height above the ground and g is the constant of gravitational acceleration (9.81 m=s²). So, if we increase the heigth, the potential energy also increases.
The solenoid for an automobile power door lock is 2. 7 cm long and has 185 turns of wire that carry 1. 8 a of current. part a what is the magnitude of the magnetic field that it produces?
Answers
The magnitude of the magnetic field produced by the solenoid can be calculated using the formula B = μ₀ * (n * I), where B is the magnetic field, μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current.
In this case, the solenoid has 185 turns of wire and is 2.7 cm long. To find the number of turns per unit length, we divide the total number of turns by the length of the solenoid: n = 185 turns / 2.7 cm.
Now, we need to convert the length from centimeters to meters to ensure consistent units. Since there are 100 cm in 1 meter, the length of the solenoid in meters is 2.7 cm * (1 m / 100 cm) = 0.027 m.
Substituting the values into the formula, we have n = 185 turns / 0.027 m = 6851.85 turns/m.
The current flowing through the wire is given as 1.8 A.
Finally, we can calculate the magnetic field by substituting the values into the formula: B = μ₀ * (n * I). The value of μ₀ is a constant equal to 4π *\(10^-7\) T·m/A.
Therefore, B = (4π * \(10^-7\) T·m/A) * (6851.85 turns/m * 1.8 A).
By performing the multiplication, we get B ≈ 0.003 T.
Hence, the magnitude of the magnetic field produced by the solenoid is approximately 0.003 Tesla.
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Native people are
in films.
Select the best answer from the choices provided.
O A. almost always cast in supporting roles
OB. rarely allowed to speak
OC. rarely allowed to display a real personality
OD. All of the answers are correct.
Answers
Answer:
D.
Explanation:
all of the options are true.
where do reduction and oxidation occur in an electrolytic cell
Answers
Answer:
Oxidation occurs at the anode and reduction occurs at the cathode
Explanation:
A + 9.4 nC point charge and a - 2.31 nC point charge are 4.94 cm apart. What is the electric field strength at the midpoint between the two charges?
Answers
Given:
The charge is q1 = 9.4 nC
The charge q2 = -2.31 nC
The distance between them is r = 4.94 cm
To find the electric field strength at the midpoint between two charges.
Explanation:
The electric field strength at the midpoint will be the sum of electric field strength due to q1 and q2.
The electric field strength can be calculated by the formula
\(E=\frac{kq}{r^2}\)Here, k is the electrostatic constant whose value is
\(k=9\times10^9\text{ N m}^2\text{ /C}^2\)The electric field strength due to the charge q1 is
\(\begin{gathered} E_1=\frac{kq1}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times9.4\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =1.39\times10^5\text{ V/m} \end{gathered}\)The electric field strength due to the charge q2 is
\(\begin{gathered} E_2=\frac{kq2}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times2.31\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =3.4\times10^4\text{ V/m} \end{gathered}\)The electric field strength at the midpoint will be
\(\begin{gathered} E=E_1+E_2 \\ =(1.39\times10^5)+(3.4\times10^4) \\ =173000\text{ V/m} \end{gathered}\)Thus, the electric field strength at the midpoint between the two charges is 173000 V/m
what best describes a reference fram?
Answers
Answer:
A reference frame is that frame to which the qualities of an object are related:
For instance - an object may described by - mass, speed, acceleration, size, etc,
It is important to remember that Newton's Laws of motion do not hold in accelerated reference frames -
Einstein's laws of special relativity are only true in frames that move with contant speed to one another
What percentage of high school students did not meet the recommended level of physical activity in one study?
A.
25%
B.
45%
C.
65%
D.
85%
Answers
Answer:
c
Explanation:
what poping
manganese dioxide is used in the dry cell as
Answers
Answer:
Electrolytic manganese dioxide (EMD) is used in zinc-carbon batteries together with zinc chloride and ammonium chloride. EMD is commonly used in zinc manganese dioxide rechargeable alkaline (Zn RAM) cells also. For these applications, purity is extremely important.
Explanation:
hope this helps...
skier accelerates down the hill at a speed of 18 and reaches the bottom of the hill at a speed of 36 in 6 seconds
What an acceleration of the skier
Answers
Answer:
3 m/s²
Explanation:
Initial Velocity, u = 18
Final velocity, v = 36
Time, t = 6 seconds
Acceleration is the change in velocity of a body with time. It obtained using the relation :
Acceleration = (v - u) / t
Acceleration = (36 - 18) / 6
Acceleration = 18 / 6
Acceleration = 3m/s²
Hence, acceleration of the skier is 3m/s²
1-Calculate the longest and the shortest wavelength for the following scries: Lyman series Balmer series Paschen series Brackett series Pfund series 2-Find the wavelength and frequency of photon emitted for hydrogen atom, When: n=1→n=2 3-When an electron in the hydrogen atom moves from level n to the second level and emit photo with wavelength 4.34×10
−7
m Find the value of n
1
4-(a) What are the frequency and wavelength of a photon emitted during transition from n= 5 state to n=2 state in the hydrogen atom ? (b) In which region of the electromagnetic spectrum will this radiation lie?
Answers
1. The longest and shortest wavelengths for the following series are:
Lyman series: The shortest wavelength in the Lyman series occurs when the electron transitions to the n=1 energy level. The longest wavelength occurs when the electron transitions to the n=∞ energy level.Balmer series: The shortest wavelength in the Balmer series occurs when the electron transitions to the n=2 energy level. The longest wavelength occurs when the electron transitions to the n=∞ energy level.Paschen series: The shortest wavelength in the Paschen series occurs when the electron transitions to the n=3 energy level. The longest wavelength occurs when the electron transitions to the n=∞ energy level.Brackett series: The shortest wavelength in the Brackett series occurs when the electron transitions to the n=4 energy level. The longest wavelength occurs when the electron transitions to the n=∞ energy level.Pfund series: The shortest wavelength in the Pfund series occurs when the electron transitions to the n=5 energy level. The longest wavelength occurs when the electron transitions to the n=∞ energy level.2. When an electron transitions from n=1 to n=2 in a hydrogen atom, it emits a photon. The wavelength (λ) and frequency (ν) of the emitted photon can be calculated using the Rydberg formula:
1/λ = R * (1/n₁² - 1/n₂²)
ν = c / λ
where
R is the Rydberg constant (approximately 1.097 x 10^7 m⁻¹), c is the speed of light (approximately 3.0 x 10^8 m/s), n₁ is the initial energy level (1 in this case),n₂ is the final energy level (2 in this case).Plugging in the values, we have:
1/λ = R * (1/1² - 1/2²) = R * (1 - 1/4) = R * (3/4)
λ = 4/3 * (1/R)
ν = c / λ = c / (4/3 * (1/R)) = 3c / (4 * (1/R)) = 3cR/4
3. The wavelength of the photon emitted when an electron in a hydrogen atom moves from level n to the second level is given as 4.34 x 10⁻⁷ m. We can use the Rydberg formula mentioned in the previous answer to find the initial energy level (ni).
1/λ = R * (1/n² - 1/2²)
1/(4.34 x 10⁻⁷) = R * (1/ni² - 1/2²)
ni² = 2² * (1 - 2² * (1/λR))
ni² = 4 * (1 - 4 * (1/(4.34 x 10⁻⁷ * R)))
ni² = 4 * (1 - 4 * (1/(4.34 x 10⁻⁷ * 1.097 x 10^7)))
ni² = 4 * (1 - 4 * (1/4.7618))
ni² = 4 * (1 - 0.839)
ni² = 4 * 0.161
ni = √0.644
ni ≈ 0.803
Therefore, the value of ni is approximately 0.803.
4a) To find the frequency (ν) of a photon emitted during the transition from n=5 to n=2 in the hydrogen atom, we can use the Rydberg formula:
1/λ = R * (1/n₁² - 1/n₂²)
ν = c / λ
Given n₁ = 5 and n₂ = 2, we can plug these values into the formula:
1/λ = R * (1/5² - 1/2²) = R * (1/25 - 1/4) = R * (4/100 - 25/100) = R * (-21/100)
λ = -100/21 * (1/R)
ν = c / λ = c / (-100/21 * (1/R)) = -21c / (100 * (1/R)) = -21cR/100
b) To determine the region of the electromagnetic spectrum in which this radiation lies, we can calculate the wavelength using the equation:
λ = c / ν
Given that ν = -21cR/100, we can substitute this value into the equation:
λ = c / (-21cR/100) = -100/(21R)
Since the value is negative, we can take the absolute value to get the positive wavelength:
|λ| = 100/(21R)
The wavelength lies in the infrared region of the electromagnetic spectrum since the value is positive and is in the denominator (indicating longer wavelengths).
The correct format of the question should be:
3 1-Calculate the longest and the shortest wavelength for the following series:
Lyman series
Balmer series
Paschen series
Brackett series
Pfund series
2-Find the wavelength and frequency of photon emitted for hydrogen atom,
When: n=1 → n = 2
3-When an electron in the hydrogen atom moves from level n to the second level and emit photo with wavelength 4.34 x 10⁻⁷ m Find the value of ni
4-a) What are the frequency and wavelength of a photon emitted during transition from n = 5 state to n = 2 state in the hydrogen atom?
(b) In which region of the electromagnetic spectrum will this radiation lic?
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A power station that is being started up for the first time generates 6120 MWh of energy over a 10 hour period. (i) If the rated power at full capacity is 660 MW, calculate how long it takes the power station to reach its full power output. (You may assume a constant increase in power from zero to full power) (ii) State what type of power station can be started up fastest and explain why the start-up times for other types of power station are slower. Explain briefly, how this is relevant to optimising the usage of windfarms. c) What is the Bremsstrahlung effect and how can it be avoided in shielding design? d) Sketch the electromagnetic field output from an antenna, describing in detail the two main regions in the output field.
Answers
(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.
(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:
Energy = Power × Time
Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:
Time = Energy ÷ Power
Converting the energy to watt-hours (Wh):
Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh
Converting the power to watt-hours (Wh):
Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh
Now we can calculate the time:
Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours
Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.
(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.
In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.
This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.
(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.
In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.
(d) The electromagnetic field output from an antenna can be represented by two main regions:
Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.
Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation. The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.
The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.
In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.
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If a 5-kg bowling ball is projected upward with a velocity of 2.0 m/s, then what is the recoil velocity of the Earth (mass = 6.0 x 1024 kg).
-1.7 m/sec
10m/sec
0
+1.7m/sec
Answers
The recoil velocity of the Earth is approximately +1.7 x 10^(-23) m/s. In practical terms, this is an extremely small value, indicating that the recoil velocity of the Earth due to the bowling ball's upward motion is negligible. Hence the correct option is D).
The recoil velocity of the Earth can be calculated using the principle of conservation of momentum. According to this principle, the total momentum of an isolated system remains constant.
Given that the initial momentum of the system is zero, the final momentum of the system should also be zero. The momentum of the bowling ball can be calculated as the product of its mass and velocity.
Initial momentum of the system = Final momentum of the system
(5 kg) * (2.0 m/s) = (6.0 x 10^24 kg) * (recoil velocity of Earth)
Solving for the recoil velocity of the Earth:
(recoil velocity of Earth) = (5 kg * 2.0 m/s) / (6.0 x 10^24 kg)
(recoil velocity of Earth) ≈ 1.67 x 10^(-23) m/s
Therefore, the recoil velocity of the Earth is approximately +1.7 x 10^(-23) m/s. In practical terms, this is an extremely small value, indicating that the recoil velocity of the Earth due to the bowling ball's upward motion is negligible. Option D) is the correct answer
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An electric field of 4.0 muV/m is induced at a point 2.0 cm from the axis of a long solenoid (radius = 3.0 cm, 800 turns/m). At what rate is the current in the solenoid changing at this instant?
The answer should be 0.40 A/s
Answers
The rate at which the current in the solenoid is changing at this instant is 4.4 A/s.
To determine the rate at which the current in the solenoid is changing, we can use Faraday's law of electromagnetic induction. According to Faraday's law, the induced electromotive force (emf) is equal to the negative rate of change of magnetic flux through a circuit. In this case, the solenoid acts as a circuit.
The induced electromotive force (emf) is given by:
emf = -dΦ/dt
Where:
emf is the induced electromotive force,
dΦ/dt is the rate of change of magnetic flux.
For a long solenoid, the magnetic flux (Φ) can be calculated as:
Φ = B * A
Where:
B is the magnetic field strength,
A is the area of the solenoid.
The magnetic field strength inside a solenoid is given by:
B = μ₀ * n * I
Where:
μ₀ is the permeability of free space (4π × 10^-7 T·m/A),
n is the number of turns per unit length (turns/m),
I is the current flowing through the solenoid.
Let's calculate the magnetic field strength (B) inside the solenoid:
B = μ₀ × n × I
= (4π × 10^-7 T·m/A) × (800 turns/m) × I
= (3.1831 × 10^-4) × I T
The area (A) of the solenoid can be calculated using the formula for the area of a circle:
A = π × r^2
Where:
r is the radius of the solenoid.
Let's calculate the area (A) of the solenoid:
A = π × r^2
= π × (0.03 m)^2
= 0.002827 m^2
Now, substitute the values of B and A into the formula for magnetic flux:
Φ = B × A
= (3.1831 × 10^-4) × I T × 0.002827 m^2
= 9.0 × 10^-7 × I Wb
Next, we differentiate the magnetic flux (Φ) with respect to time (t) to find the rate of change of magnetic flux:
dΦ/dt = d/dt (9.0 × 10^-7 × I)
= 9.0 × 10^-7 × dI/dt Wb/s
Finally, we can equate the rate of change of magnetic flux (dΦ/dt) to the induced electromotive force (emf) given in the problem statement:
emf = -dΦ/dt
= -9.0 × 10^-7 × dI/dt Wb/s
Given that the induced electromotive force (emf) is 4.0 μV/m = 4.0 × 10^-6 V/m, we can solve for the rate of change of current (dI/dt):
4.0 × 10^-6 V/m = -9.0 × 10^-7 × dI/dt
\(\frac{dI}{dt} = \frac{-(4.0) (10^-6 V/m)}{(9.0) (10^-7)} = -4.4 A/s\)
Therefore, the rate at which the current in the solenoid is changing at this instant is 4.4 A/s.
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. The 4.00 A current through a 7.50 mH inductor is switched off in 8.33 ms. What is the emf induced opposing this
Answers
The emf induced opposing this is -3.60 V.
The given inductor is 7.50 mH and the time is 8.33 ms. We need to find the emf induced opposing this. Inductor: The inductor is a passive electrical element which stores energy in a magnetic field when electric current flows through it. Inductance is a measure of how much electrical energy an inductor can store in the form of magnetic energy.
The unit of inductance is the Henry (H).
We use the formula of emf induced opposing inductor, which is given by:ε=−L(ΔI/Δt)
where ε is the emf induced opposing inductor,
L is the inductance of the inductor, and(ΔI/Δt) is the change in current per unit time.
We obtain the following values for L(I/t) by passing the given current values through a 7.50 mH inductor.
time: (4.00 A/ 8.33 ms) = 7.50 x 10-3 H (480 A/s).ε= - 3.60 V The induced emf opposing this is therefore -3.60 V.
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light of wavelength 460 nm falls on two slits spaced 0.3 mm apart if the spacing between the first and third dark fringes is to be 4,0 mm what is the distance from the slits to the screen
Answers
The distance is 0.0013.4 mm
For dark fringe is 4,0
light of wavelength 460 nm
slits spaced 0.3 mm.
\($y=\frac{D}{d}(2 n-1) \frac{\lambda}{2}$$\)
For First dark fringe put n=1
For third dark fringe put n=3
\($\begin{aligned}& y_1=\frac{D \lambda}{d 2} \\& y_3-y_1=\frac{5 D \lambda}{2 d}-\frac{D \lambda}{2 d}=\frac{5 D \lambda}{2 d} \\& \Delta y=\frac{2 D D \lambda}{2 d} \\& L_1 \mathrm{~mm}=\frac{2 \times D \times 460 \mathrm{~nm}}{0.3 \mathrm{~mm}} \\& D=\frac{4 \times 0.3}{2 \times 460} \mathrm{~mm}=0.001304 \mathrm{~mm}\end{aligned}$$\)
Therefore, the distance from the slits to the screen is 0.001304 mm.
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Int this setup of YDSE distance from the slits to the screen is 1.739 m
As we all know from the young's double slit experiment the position of n(th) dark fringe width is given by
\(y=(n+\frac{1}{2} )\)λ\(\frac{D}{d}\)
here, y= position of minima on the screen
n= no. of minima
D= slit- screen separation
d= slit width
λ= wavelength of light used
Given,
λ= 460nm= 460×10⁻⁹ m
Δy= 4×10⁻³ m
d= 0.3mm= 0.3×10⁻³ m
According to question, y₃-y₁= Δy= 4×10⁻³ m
For first dark fringe n=0
For third dark fringe n=2
On putting all the values and solving we get
D= 1.739m
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Alkaline earth metals have a low density
true
false
Answers
true
Explanation:
this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons
Suppose an electric power company in your area charges $0. 06/kwh. of you charged the same amount for the power you devolp climbing stairs, how kuch money would you earn by climbing stairs for 1h
Answers
Based on the charge of power expended per kwh, the amount earned is calculated from the power developed in climbing the the stairs for 1 hour and the charge per kWh.
What is power?Power is defined as the time rate at which work is done.
Power = work done/timeThe power developed in climbing a set of stairs is calculated as follows:
Power = mgh/twhere;
m = mass in Kgg = acceleration due to gravity = 9.8 m/s^2h = height in meters t = time in secondsFor 1 hour, the power developed will be the multiplied by 3600 seconds and divided by 1000.
The value is them multiplied by $0.06.
Therefore, amount of money depends on the power developed in climbing the the stairs for 1 hour and the charge per kWh.
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The fire alarm goes off, and a 75 kg firefighter slides down a pole with a constant acceleration of a = 6 m/s square. What is the upward force F exerted by the pole on the firefighter? *
Answers
Answer:
450N
Explanation:
Given data
Mass m= 75kg
Acceleration= 6m/s^2
From the Newtons first law, F=ma
substitute
F=75*6
F= 450N
Hence the force is 450N
1. when all other factors are constant, the ______ determines the length of a projectile's trajectory.
Answers
When all other factors are constant, the initial velocity determines the length of a projectile's trajectory.
A projectile is an object that is thrown or projected into the air and follows a path determined by the forces of gravity and air resistance. The length of a projectile's trajectory is determined by the time it takes for the projectile to reach its maximum height and the time it takes for the projectile to return to the ground. Initial velocity is the velocity at which a projectile is launched, and it determines the initial speed and direction of the projectile.
The greater the initial velocity, the farther the projectile will travel before hitting the ground, this is because the projectile spends less time in the air, so it has less time to slow down due to air resistance. In contrast, a projectile with a lower initial velocity will travel a shorter distance because it spends more time in the air and slows down more due to air resistance. Therefore, the initial velocity is a crucial factor that determines the length of a projectile's trajectory.
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Between ball B and ball C, ball ____ has LESS potential energy because ___
a: c;its mass is greater
b: b;its mass is smaller
c: c; its mass is smaller
d: b;its mass is greater
Answers
Answer: b
Explanation:
Ec= (1/2)m × v^2
By the formula, you can see that the bigger the mass, the bigger the Cinetic Energy.
b: b; its mass is smaller
Between ball B and ball C, ball B has LESS potential energy because its mass is smaller.
A potential energy, stored energy that depends upon the relative position of various parts of a system. A spring has more potential energy when it is compressed or stretched.
Potential energy is given by formula.
\(P.E= m*g*h\)
Since, P.E is directly proportional to mass. Thus, the ball having smaller mass will have the less P.E.
Thus, option b is correct.
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Help please!!!! Why is it especially important to not waste energy from fossil fuels?
Answers
They have a limited supply in nature, therefore if they are used excessively, they will become exhausted.
What is the fossile fuel?Today, we recognise that using fossil fuels has a negative impact on the environment. Fossil fuels produce and utilise local pollutants, and their continued use permanently alters the temperature of our entire world.
Wastes from combustion sources are those that result from carbon pollution (i.e., coal, oil, natural gas). Included in this are all ash and particles taken out of the flue gas.
The fossile fuel is limited in nature. So, it should not waste energy from fossil fuels.
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A karate student trying to break bricks in half is wondering if it would be more effective to strike these bricks and stop her hand at the top surface of the blocks, or to let her hand bounce after she strikes.
How would you advise her, using physics?
Stop hand or bound?
Why?
Answers
stop your hand so it doesn't hurt as much and if u stop your hand it would make more of an impact because if your hand bounces it means not enough strength so she should stop her hand
A train is traveling N at 45 m/s. After 10s, it is traveling at 90 m/s. What is it's acceleration?
Answers
Answer:
The train's acceleration is 4.5 m/s²
Explanation:
The train's speed increased by 45 m/s after 10 seconds, which means that it's speed increased by 4.5 m/s each second, or rather 4.5m/s²
A crate slides down a ramp that makes a 20∘ angle with the ground. To keep the crate from sliding too fast, Paige pushes back on it with a 69 N horizontal force.
A) How much work does Paige do on the crate as it slides 3.3 m down the ramp?
Answers
,Paige does 182.9 J of work on the crate as it slides 3.3 m down the ramp.
To determine the work done by Paige on the crate as it slides down the ramp, we need to calculate the component of Paige's force that is parallel to the direction of motion of the crate. This component will do work on the crate by exerting a force in the same direction as the crate's displacement.
We can first calculate the weight of the crate, which is given by
W = mg
where m is the mass of the crate and g is the acceleration due to gravity. We can assume that the crate is on a frictionless surface, so the force of friction is zero. Therefore, the weight of the crate is the only force acting on it parallel to the ramp. Using the angle of the ramp, we can calculate the component of the weight that is parallel to the ramp:
F_parallel = mg sin θ
where θ is the angle of the ramp, which is 20∘. We can also calculate th
m = W/g
where g is the acceleration due to gravity, which is 9.81 m/s^2.
Substituting the values, we get:
m = (F_parallel/sin θ)/g
m = (mg sin θ/sin θ)/g
m = g
Therefore, the mass of the crate is equal to g.
Next, we can calculate the force applied by Paige, which is given by:
F_applied = 69 N
Since Paige is pushing back on the crate, her force is in the opposite direction of the crate's motion, so we need to calculate the negative of F_parallel. Therefore, the net force acting on the crate is:
F_net = F_applied - F_parallel
F_net = 69 N - g sin θ
Finally, we can calculate the work done by Paige on the crate using the formula:
W = F_net d
where d is the distance traveled by the crate, which is 3.3 m. Substituting the values, we get:
W = (69 N - g sin θ) x 3.3 m
Using the value for g and θ, we get:
W = (69 N - 9.81\(m/s^2\)x sin 20∘) x 3.3 m
W = 182.9 J
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You drive 45 miles to Kingwood from Richmond at 30° North of East. Determine how far north and how far east you traveled.
How would i answer this ?
Answers
Answer:
22.5 miles due North
38.7 miles due East
Explanation:
From the information given above, we infer :
Let there be a vector AB (indicating distance travelled) with magnitude = 45 mi and makes an angle of 30° with East axis as well as an angle of 60° with North axis.
Displacement covered in North Direction :
AB Cos 60° = 22.5 miles due North
Displacement covered in East Direction :
AB Cos 30° = 38.7 miles due East
A compound microscope that has an eyepiece lens with a magnification of 10X and an objective lens with a magnification of 25X will have a total magnification of __________ times.
Answers
Answer:
35
Explanation:
total magnification = eyepiece lens x objective lens
TM = 10X x 25X
TM = 250X
The Lambda-CDM model contains a cosmological constant, denoted by a lambda (λ) which is associated with dark energy and
.
Answers
Answer:
Dark matter?
Explanation:
Answer:
matter
Explanation:
I will give Brainliest to WHoever answers truthfully!!!!!T/F net force charge and net electric force are the same thing
Answers
Answer:
it's true I'm pretty sure
Answer:
the answer is true.I'm sure
a fisherman notices that wave crests pass the bow of his anchored boat every 2.0 s . he measures the distance between two crests to be 5.0 m .how fast are the waves traveling?
Answers
The waves are travelling with a speed of 2.5m/s.
The wave crest noticed by the fisherman passes through the anchored boat every two seconds.
The distance between the two crest measured by the fisherman is fine to be 5m.
The speed of any body is given by,
Speed = distance travelled by that object / time taken by that object to cover the distance.
Now putting the values in the above relation,
We get the speed of the wave to be,
= 5m/2s
= 2.5m/s
So, the speed of the wave is 2.5 m/s.
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