which equation represents a parabola opening to the right with a vertex at the origin and a focus at (9,0)?

Answer:

x=80

Step-by-step explanation:

my god this should be easy and I thought I was a bit slow

Answer:

Step-by-step explanation:

if you connect the 2 pointy parts of this shape at the top, what you have is a square. That means that the cut out part is a half circle. To find the area of the shaded portion, subtract the area of the half circle from the area of the square. Let's start with the square, cuz that's the super easy one.

A = s*s so

A = 64 in squared.

Now for the half circle. Let's just do this: let's find the area of the whole circle and then cut it in half, how about?

If the length of one of the sides is 8, then half that length is 4, right? Since the circle is touching the sides of the square, the diameter of the circle is the same as the measure of the side of the square. That means that the radius is 4. The area for the circle is

\(A=\pi r^2\) and filling in:

\(A=(3.14)(4^2)\) so

A = 50.24 in squared. Divide that in half and the area of half the circle is 25.12 in squared.

Subtract 25.12 from 64 to get 38.88 in squared

Answer:

60 miles per hour

Step-by-step explanation:

We need to simply divide the total distance he traveled by the total time it took him.

At 10:00 AM, he is 200 miles from New York.

At 12:00 PM, he is 80 miles from New York.

This means that 2 hours has elapsed and the distance he has traveled is:

200 - 80 = 120 miles

Therefore, his average speed is:

120 / 2 = 60 miles per hour

The volume of the oblique pyramid with a square base edge length of 5 cm and height of 7 cm is  58.33 cubic centimeters.

To calculate the volume of this oblique pyramid,

We can use the formula V = (1/3) A h,

Where A is the area of the base and h is the height of the pyramid.

Since the base is a square with an edge length of 5 cm,

We can find its area by squaring the edge length:

A = 5²

  = 25 cm².

Plugging in the values we have:

V = (1/3) x25x7

V = (1/3)x175

V = 58.33 cm³ (rounded to two decimal places)

So the volume of the oblique pyramid is  58.33 cubic centimeters.

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Answer:

  (a)  s = 33.75

Step-by-step explanation:

You want the sum of the infinite geometric series that begins 21 +9 +3.86 +....

The ratio of the first two terms is 9/21 = 3/7. This is a value less than 1, so you know the series converges. The first two terms have a total of 21+9 = 30, so you know the sum is more than 30 and last two answer choices are incorrect.

Of the available answer choices, the most likely answer is 36.75.

The formula for the sum of an infinite series with first term a1 and common ratio r is ...

  S = a1/(1 -r)

Here, the first term is 21 and the ratio is 9/21 = 3/7, so that sum is ...

  S = 21/(1 -3/7) = 21·7/4 = 33.75

The sum of the series is 33.75.

4:21 are the odds against exactly 55 cars passing over the bridge in that time.

What is Probability?

Probability of 0.16, thus, for 100 trials, 16 successes and 84 failures, and the odd is:

16:84, which, simplifying by 4, is 4:21.

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No, the current optimal solution may not remain optimal.

To determine if the current optimal solution remains optimal after adding a new variable x3, we need to examine the relation between primal optimality and dual feasibility.

In the primal LP, the current optimal tableau indicates that the artificial variables a1 and a2 are present in the basis. This suggests that the original problem is infeasible. The presence of artificial variables in the basis indicates that the original problem had no feasible solution. Thus, the current optimal solution is not valid.

When we add a new variable x3 and modify the primal LP accordingly, we need to solve the modified LP to determine the new optimal solution. The modified LP has a different constraint and objective function, which can lead to different optimal solutions compared to the original LP.

Therefore, the current optimal solution may not remain optimal when we add a new variable and modify the primal LP.

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The answer to this question is A. It is not reasonable to conclude that heart or respiratory diseases were the cause of approximately 29% of U.S. deaths in 2011 because there is a possibility of overlap.

This means that some people who died from heart disease may have also had respiratory diseases, and vice versa.

Therefore,

It is impossible to accurately determine the exact percentage of deaths caused by each individual disease.
It is important to note that the Centers for Disease Control lists the causes of death in the United States as the underlying cause, which is defined as the disease or injury that initiated the train of events leading directly to death.

However,

Many people who die from one disease may also have other underlying or contributing conditions.

This makes it difficult to determine the exact cause of death in some cases.
There could be potential overlap between heart and respiratory diseases, it is not reasonable to conclude that heart or respiratory diseases were the cause of exactly 29% of U.S. deaths in 2011.

In summary,

While heart and respiratory diseases were listed as the cause of a significant percentage of deaths in the United States in 2011, it is not accurate to conclude that they were the sole cause of approximately 29% of deaths due to the possibility of overlap.

It is important to consider all contributing factors when analyzing causes of death data.

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Answer: 100km = 62.5 miles.

Step-by -step explanation: given 5miles = 8km. now, 5miles — 8km. X miles — 100km. now do cross multiplication.

The right triangle is rotated one time to the right with respect to the left triangle. Then the pairs are:

e and g, f and h.

Here we have two similar triangles, this means that one of the triangles can be a rotation + dilation of the other.

If you look at the dimensions of the second triangle and multiply these by 2, you see that the dimensions become:

2*2 = 4

2*3 = 6

2*4 = 8

Which are the same dimensions of the left triangle, but rotated one time to the right.

Now, knowing that, we caonclude that the corresponding angles are:

Then the correct option is the third one.

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For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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Answer:

For 1: Absolute value of -4/5 is 4/5

For 2: Absolute value of 6.43 is 6.43

For 3: Absolute value of -22 is 22.

For 4: 4 < | -8 |

For 5: | -7| > -12

For 6: -7 < | 3 |

Answer: 20

Step-by-step explanation:

4 x 2 = 8

4 x 2 = 8

+

---------

16 round to twenty

Answer:

19.6

Step-by-step explanation:

using the Pythagorean theorem:

x² = 28² - 20²

x² = 784 - 400 = 384

x = 19.6

Answer: for C it is that 1/2 is half of an whole therefore 1/2 is  half is less than the rest

for D you will have to add more 1/2 for it to be greater than but for now, it is less than.

for E you will have to add more 1/2 for it to be greater than

Answer:

48

Step-by-step explanation:

81 - 33 = 48

Answer:

48

Step-by-step explanation:

81 - 33 = 48

Do 81 - 30 first = 51

Then do 51 - 3 = 48

The statement "the expected value of an unbiased estimator is equal to the parameter whose value is being estimated" is true.

An estimator is a function of the sample data used to estimate the value of a population parameter. An estimator is said to be unbiased if its expected value is equal to the true value of the population parameter. In other words, if we were to repeatedly take samples from the population and calculate the estimator for each sample, the average value of the estimator over all the samples would be equal to the true value of the population parameter. The expected value of an unbiased estimator is a key property because it ensures that the estimator is not systematically overestimating or underestimating the population parameter. Instead, the estimator provides an unbiased estimate of the population parameter on average across all possible samples. It is important to note that not all estimators are unbiased. Biased estimators may systematically overestimate or underestimate the population parameter, leading to incorrect conclusions. Therefore, unbiasedness is a desirable property for an estimator to have.

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The inequality given by (x/3) + 5 ≥ 1/6 has the solution x ≥ -29/2 or [-29/2 , +∞).

Inequality refers to the relationship between two non-equal expressions. It can be denoted by > for greater than, < for less than, >/= for greater than and equal to, and </= for less than and equal to.

To solve an inequality is to find the values of x such that when we substitute that number for x we have a true statement.

Given the inequality (x/3) + 5 ≥ 1/6, subtract 5 from both sides.

(x/3) + 5 - 5 ≥ 1/6 - 5

x/3 ≥ -29/6

Multiply both sides by 3.

3(x/3) ≥ 3(-29/6)

x ≥ -29/2

To check, let x = -29/2

x = -29/2 ≥ -29/2

Substitute this value to the inequality.

(x/3) + 5 ≥ 1/6

(-29/2)/3 + 5 ≥ 1/6

1/6 ≥ 1/6

let x = -14,

x = -14 ≥ -29/2

Substitute this value to the inequality.

(x/3) + 5 ≥ 1/6

-14/3 + 5 ≥ 1/6

1/3 ≥ 1/6

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Answer: 80%

Step-by-step explanation: In the store every 4 out of 5 costumers purchase an product.

If you multiply numbers by 20, you get the demoninator to be 100, which then you can get the percentage by finding 4x20=80.

Therefore, converted, 4/5=80%.

When the weight moves from x = -8 cm to x = 8 cm, the spring moves from its maximum stretched position to its maximum compressed position.Hence, the spring oscillates between its maximum stretched and compressed positions when the weight is set in motion. Therefore, the spring is a simple harmonic oscillator.

Given: Displacement x

= 8 cos t

= Acos(ωt+ φ) where A

= 8 cm, ω

= 1 and φ

=0. To find: What is the spring?Explanation:We know that displacement is given by x

= 8 cos t

= Acos(ωt+ φ) where A

= 8 cm, ω

= 1 and φ

=0.Comparing this with the standard equation, x

= Acos(ωt+ φ)A

= amplitude

= 8 cmω

= angular frequencyφ

= phase angleWhen the spring is at equilibrium position, the weight attached to the spring does not move. Hence, no force is acting on the weight at the equilibrium position. Therefore, the spring is neither stretched nor compressed at the equilibrium position.Now, the spring is set in motion resulting in a displacement of x

= 8 cos t

= Acos(ωt+ φ) where A

= 8 cm, ω

= 1 and φ

=0. The maximum displacement of the spring is 8 cm in the positive x direction. When the weight is at x

= 8 cm, the restoring force of the spring is maximum in the negative x direction and it pulls the weight towards the equilibrium position. At the equilibrium position, the weight momentarily stops. When the weight moves from x

= 8 cm to x

= -8 cm, the spring moves from its natural length to its maximum stretched position. At x

= -8 cm, the weight momentarily stops. When the weight moves from x

= -8 cm to x

= 8 cm, the spring moves from its maximum stretched position to its maximum compressed position.Hence, the spring oscillates between its maximum stretched and compressed positions when the weight is set in motion. Therefore, the spring is a simple harmonic oscillator.

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The displacement of the weight attached to the spring is given by the equation x = 8 cos t. The amplitude of the motion is 8 centimeters and the period is 2π seconds.

The equation x = 8 cos t represents the displacement of a weight attached to a spring in simple harmonic motion. In this equation, x is measured in centimeters and t is measured in seconds.

The amplitude of the motion is 8 centimeters, which means that the weight oscillates between x = 8 and x = -8.

The period of the motion can be determined from the equation T = 2π/ω, where ω is the angular frequency. In this case, ω = 1, so the period T is 2π seconds.

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The quadratic equation, x(2) + 2 =420 can be used to find x.

you can use trial and error

x(2) + 2 =420

210(2)=420 but we need to add the two so lower the \(120\)

209(2)=418+2 = 420

so, the x value must less than 21.

A quadratic equation with variable x is written in standard form as \(ax2 + bx + c = 0\), where a, b, and c are constants such that the value of an is non-zero but the values of b and c can both be zeros.

Let's change \(ax2 + bx + c = 0\) from its standard form to its vertex form, which is \(a (x - h)2 + k = 0\), where (h, k) is the vertex of the quadratic function \(f(x) = a (x - h)2 + k\). Keep in mind that 'a' has the same value in both equations. Just set them equal so we can determine how the variables relate to one another.

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Multiply the mass in pounds by 0.45359237 to convert 145 lbs to kilogrammes.

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Autumn's physiological response, characterized by her increased heart rate, sweaty hands, and flushed cheeks, indicates that her sympathetic nervous system has been activated.

Autumn's physiological response, such as an increased heart rate, sweaty hands, and flushed cheeks, is a typical manifestation of the fight-or-flight response, which is controlled by the sympathetic nervous system. In this situation, Autumn's body is reacting to a perceived threat or a stressful stimulus, which in this case is the presence of the boy she has a crush on.

When the sympathetic nervous system is activated, it triggers the release of stress hormones like adrenaline, which leads to various physiological changes in the body. These changes include increased heart rate, dilation of blood vessels, increased blood flow to the muscles, and sweating, all of which prepare the body for action in response to a perceived threat. This response is part of the body's automatic reaction to stressful or arousing situations and helps to mobilize the body's resources to deal with the perceived threat or challenge.

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Annual Medical cost = 1269.86

monthly premium cost to Ronald for the Blue Shield plan = $48.48.

For all doctor office visits, prescriptions, and major medical charges, Ronald will be responsible for 35 percent and the insurance company will cover 65 percent of covered charges.

The annual deductible cost = $630.

Ronald decided to review his medical bills from the previous year to see what costs he had incurred and to help him evaluate his choices. He visited his general physician 6 times during the year at a cost = $105 for each visit.

He also spent $71 and $95 on two prescriptions during the year.

= (Monthly premium cost × 12) + Deductible cost + (Coinsurance percent × Coinsurance expenses)

= (48.48 x 12) + 630 + (0.35 x 166)

= 1269.86

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If the discount rate is 4%,the present value of the savings account is $5,448.50.

From the question above, :Savings amount = $7,942

Discount rate = 4%

Time period = 9 years

We need to calculate the present value of the savings account.To calculate the present value, we will use the formula,PV = FV / (1 + r)n

Where,PV = Present value of savings account

FV = Future value of savings account

r = discount rate, and

n = Time period

In this problem,PV = ?

FV = $7,942

r = 4%

n = 9 years

Substitute the values in the formula,

PV = 7,942 / (1 + 0.04)9

PV = $5,448.50

Therefore, the present value of the savings account is $5,448.50.

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Yes it is possible to make the prediction about Ramiro's School but not completely.

It is possible to use the information from Ramiro's sample to make predictions about the school-wide results, but it is important to note that the sample may not be fully representative of the entire population of students at the school. There may be sampling biases or other factors that affect the results.

With that said, based on the information provided, we can calculate the proportion of students in Ramiro's sample who use the library in a certain way, and then use that proportion to estimate the number of students at the school who use the library in that way.

For example, if Ramiro's sample shows that 40 out of the 60 people he surveyed use the library to study, we can estimate that approximately 40/60 = 67% of the school's students use the library to study. We can then use this proportion to estimate that approximately 540 x 67% = 361 students at the school use the library to study.

It's important to note that these predictions are based on sample data and they may not be accurate. To make more accurate predictions, a larger, more representative sample would be needed.

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