Which equation could be used to find m∠e in △efg? m∠e = cos""1(startfraction 3 over 4.6 endfraction) m∠e = cos""1(startfraction 4.6 over 3 endfraction) m∠e = tan""1(startfraction 3 over 4.6 endfraction) m∠e = tan""1(startfraction 4.6 over 3 endfraction)

Answer:We have 70 dogs

Step-by-step explanation:

dogs: cats: total5          2      7We want 98 animals98/7 =14We need to multiply each number by 14dogs: cats: total…

hope this helps

The negative regulation is the type of regulation in which the transcription of a gene is prevented by the binding of a repressor protein to the DNA, which blocks the binding of RNA polymerase to the promoter region.

The gene expression regulator illustrated in the picture below is an example of what kind of regulation?

The gene expression regulator illustrated in the picture below is an example of the negative regulation. It is known as the trpR Repressor R.

How does it get that name and how does it work?

The TrpR protein is an allosteric protein that binds to the Tryptophan (Trp) molecule. It plays an important role in the regulation of gene expression, as it controls the transcription of the trp operon.

The Trp operon is a cluster of genes that are involved in the synthesis of the amino acid tryptophan. In the absence of tryptophan, the trpR protein is inactive.

However, when tryptophan is present, it binds to the TrpR protein and changes its shape. This change in shape activates the TrpR protein, which then binds to the trp operator region of the DNA.

Binding of the TrpR protein to the trp operator region prevents RNA polymerase from binding to the promoter region, thereby inhibiting the transcription of the trp operon.

Gene expression is regulated in both prokaryotes and eukaryotes, but the mechanisms of regulation differ between the two.

Negative regulation is the type of regulation in which the transcription of a gene is prevented by the binding of a repressor protein to the DNA, which blocks the binding of RNA polymerase to the promoter region.

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The gene expression regulator illustrated in the picture, known as trpR repressor, is an example of negative regulation. It is named after the trp operon, a set of genes involved in tryptophan biosynthesis in bacteria, where this regulator is commonly found.

The trpR repressor works by binding to a specific DNA sequence called the operator region, which is located near the trp operon genes. This binding occurs in the presence of tryptophan, the end product of the trp biosynthesis pathway. When tryptophan levels are high, it binds to the trpR repressor, causing a conformational change that enables it to bind to the operator region of the trp operon DNA.

By binding to the operator region, the trpR repressor physically obstructs the RNA polymerase from transcribing the genes in the trp operon. This prevents the synthesis of enzymes involved in tryptophan biosynthesis. As a result, the production of tryptophan is reduced or halted when there is already an adequate amount available in the cell.

The negative regulation exerted by the trpR repressor is based on the principle of feedback inhibition. When the end product (tryptophan) accumulates, it acts as a co-repressor and binds to the repressor, leading to the repression of its own biosynthesis. This mechanism ensures that the cell only produces tryptophan when it is needed, preventing wasteful energy expenditure.

In summary, the trpR repressor exemplifies negative regulation by binding to the operator region of the trp operon genes in the presence of tryptophan. This binding inhibits the transcription of genes involved in tryptophan biosynthesis, allowing the cell to regulate its production according to its needs.

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The fundamental questions of risk management that would benefit from using pairwise ranking are those related to prioritizing risks and deciding which risks to address first.

Pairwise ranking is a technique used to compare and prioritize items by comparing them in pairs and determining which one is more important or has a higher priority. This technique can be used to prioritize risks based on their likelihood and impact.
The risk management that would benefit from using pairwise ranking include:
- Which risks should be addressed first?
- Which risks have the highest likelihood of occurring?
- Which risks have the highest impact on the project or organization?
- Which risks should be given the most attention and resources?
By using pairwise ranking, risk managers can prioritize risks and make more informed decisions about which risks to address first and which risks to allocate the most resources to. This can help ensure that the most important risks are addressed first and that resources are used effectively to manage risks.

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Answer: a) 26.2 cm

Step-by-step explanation:

Perimeter of rectangle = 2 (l + w)

2 (l + w) = 2 (9 + 4.1) = 2 (13.1) = 26.2 cm

Hope this helps!

Answer:

\(\angle BAC=180^{\circ}-\frac{13\sin 23^{\circ}}{6}\)

Step-by-step explanation:

\(\frac{\sin(\angle BAC)}{13}=\frac{\sin 23^{\circ}}{6} \\ \\ \sin \angle BAC=\frac{13\sin 23^{\circ}}{6} \\ \\ \angle BAC=180^{\circ}-\frac{13\sin 23^{\circ}}{6}\)

The graphed rational function is:

\(f(x)= \frac{6}{x + 2}\)

Here we can see that we have a rational function of the form:

\(f(x) = \frac{q(x)}{p(x)}\)

Now we notice two things, as x increases, we have a horizontal asymptote that tends to zero.

Then q(x) is a constant, let's say:

q(x) = k

We also can see that we have a vertical asymptote at x = -2, then:

p(x) = (x + 2)

So the rational function is:

\(f(x) = \frac{K}{x + 2}\)

Now, notice that when x = 0, the curve intercepts the y-axis at y = 3, then if we evaluate the function in x = 0 we must get:

\(f(0) = 3 = \frac{K}{0 + 2} = \frac{K}{ 2} \\\\3*2 = K = 6\)

Then the rational function is:

\(f(x)= \frac{6}{x + 2}\)

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The skier can choose from a total of 35 different combinations of three Dale of Norway sweaters to take with him to Aspen.

To determine the number of combinations of three Dale of Norway sweaters the skier can take from a total of seven, we can use the concept of combinations. The number of combinations of selecting "r" items from a set of "n" items can be calculated using the formula for combinations: C(n, r) = n! / (r!(n-r)!).

In this case, the skier has a total of seven sweaters (n = 7) and wants to select three sweaters (r = 3). Therefore, the number of combinations of three sweaters the skier can take is: C(7, 3) = 7! / (3!(7-3)!) = 7! / (3!4!) = (7 * 6 * 5) / (3 * 2 * 1) = 35. So, the skier can choose from a total of 35 different combinations of three Dale of Norway sweaters to take with him to Aspen.

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I think that for a its 1.12 and for b its 39424

100 + 12 = 112
112/100 = 1.12

35200 * 1.12 = 39424

Answer:

I was not able to see the picture, i am so sorry

The reference angle when θ is 120 = 60°, when θ is 120 = 60°

A reference angle is usually represented as θ and it is the positive acute angle between the terminal end side of the angle θ and the value of the x-axis.

From C;

Given that the angle of 120° is in the second quadrant, then we can subtract it from 180°

θ = 180° - 120°

θ =  60°

when θ =  315°, the angle 315° is in the fourth quadrant, then we can subtract 315° from360°.

θ =  360 - 315°

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Answer:

the answer is 5x +8

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

To prove that the explicit formula for the nth term of a geometric sequence is given by an = a₀.rⁿ, we will use mathematical induction. Mathematical induction is a proof technique used to establish a statement or property for all natural numbers or integers greater than or equal to a starting value.

Step 1: Base Case

For n = 0, the formula gives a₀.r⁰ = a₀, which is the first term of the sequence. So, the formula holds true for the initial value.

Step 2: Inductive Hypothesis

Assume that the formula holds for some arbitrary value k, i.e., ak = a₀.rᵏ.

Step 3: Inductive Step

We need to prove that the formula also holds for k+1, i.e., a(k+1) = a₀.r^(k+1).

Using the definition of a geometric sequence, we have:

a(k+1) = r.aₖ

Now substitute the inductive hypothesis into the above equation:

a(k+1) = r.(a₀.rᵏ) = (r.a₀).rᵏ = a₀.r^(k+1)

Therefore, we have shown that if the formula holds for k, then it also holds for k+1.

Step 4: Conclusion

By the principle of mathematical induction, the explicit formula for the nth term of a geometric sequence, given by an = a₀.rⁿ, is true for all non-negative integers n.

Thus, we have proved the claim using mathematical induction.

The question should be:

Recall the following definition of an Geometric Sequence.

A sequence a₀, a₁, a₂, ... is called an geometric sequence if, and only if there is a constant r such that

ak = r.a_k_-1 where k≥ 1.

Also recall that we "claimed" the explicit formula for the nth term of the geometric sequence is given by

an = a₀.rⁿ  where n≥ 0. Use mathematical induction to prove that our claim is true.

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This equation cannot be met, Robinson and Friday are unable to trade grain for meat under the accepted norms of the closed economy.

To find the maximum quantity of grain Robinson and Friday can jointly consume per week when they produce 16 units of meat, we need to substitute the given quantity of meat (M = 16) into either Robinson's or Friday's production possibility curve equation and solve for G.

Let's use Robinson's equation: G = 21 - 7M

Substituting M = 16:

G = 21 - 7(16)

G = 21 - 112

G = -91

Since the result is negative, it implies that Robinson and Friday cannot jointly consume a positive quantity of grain when they produce 16 units of meat per week.

Regarding the second part of the question, the maximum admissible terms of trade between Robinson and Friday refer to the exchange rate at which they can trade grain for meat within the closed economy.

We need to find the rate at which the marginal rate of transformation (MRT) between grain and meat for either Robinson or Friday is equal to the given terms of trade.

Using Robinson's production possibility curve equation: G = 21 - 7M

Taking the derivative with respect to M: dG/dM = -7

For the closed economy, the MRT should be equal to the terms of trade (11.8 units of grain per unit of meat):

-7 = 11.8

This equation is not satisfied, which means that there is no admissible terms of trade within the closed economy that allows Robinson and Friday to exchange grain for meat.

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Answer:

265

Step-by-step explanation:

First, find 8^3. 8^3 is equivalent to 8*8*8=64*8=512

Now you have 9+512/2

Divide 512 by 2, which is 256.

9+256=265

\(~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill\\\\ (4)^{\frac{-4}{2}} \implies (4)^{-2}\implies 4^{-2}\implies \cfrac{1}{4^2}\implies \cfrac{1}{16}\)

Answer: 955.04 in^2

Step-by-step explanation:

Answer:

------------------------

We have a repeating decimal 4.6(1).

Let's express it as a GP:

Fund the sum of infinite GP, with the first term of a = 0.01 and common ratio of r = 0.1:

Add 4.6 to the sum:

Hence the fraction is 4 11/18.

If A is similar to B, and A is invertible, then B is also invertible and the inverse of A, denoted as A^(-1), is similar to the inverse of B, denoted as B^(-1). This can be proved by showing that B^(-1) = (P^(-1))^(-1) A^(-1) P^(-1), where P is the invertible matrix that relates A and B.

Given that A is similar to B, we have B = P^(-1)AP for some invertible matrix P. If we multiply both sides of this equation by P, we get BP = P(P^(-1)AP). Since P^(-1)P is the identity matrix, we have BP = (PP^(-1))AP, which simplifies to BP = A.This shows that B is invertible, with B^(-1) = P^(-1)AP.

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Answer:

12.3 degrees

Step-by-step explanation:

-3.1 degrees + 15.4 degrees = 12.3 degrees

loss= 30%

sold amount= rs 63000

the original price of the laptop.

\(cp = \frac{100 \times selling \: price}{100 - loss\%} \)

\(cp = \frac{100 \times 63000}{100 - 30\%} \)

\(cp = \frac{100 \times 63000}{70} \)

\(cp = 100 \times 900\)

\(cp = 90000\)

therefore, the original price of the laptop is rs 9000.

Answer:-1 as said in the bottom of the equation

Step-by-step explanation: it is at the bottom of the equation if wrong sorry.

Answer:

The answer is the fourth option.

Step-by-step explanation:

The reason is that when a number has the line above it means it is continuous which is the meaning of rational numbers.

Answer:

2 3/4

Step-by-step explanation:

There are 16 ounces in a pound so 8 ounces is 1/2 a pound.

1 1/2 + 1/2 + 3/4

2 + 3/4

2 3/4

if ​Y=1​+X+u​, where X​, Y​, and ​u=v+X are random​ variables, v is independent of X​; ​E(v​)=0, ​Var(v​)=1​, ​E(X​)=1, and ​Var(X​)=2, then Var(Y|X​) = Var ( 1 + X + u | X)  = 0 + 4*2 + 1 = 8 + 1 = 9

if ​Y=1​+X+u​, where X​, Y​, and ​u=v+X are random​ variables, v is independent of X​; ​E(v​)=0, ​Var(v​)=1​, ​E(X​)=1, and ​Var(X​)=2, the variance of the following cases are calculated as:

Var(u|X​=1) = Var( v + X | X = 1) = Var( v + 1 )    

                = Var(v) + Var(1)                            

                 = 1 + 0 = 1

Var(Y|X​=1) = Var( 1 + X + u | X = 1 )

                = Var (1 + X + v + X|X=1)

                = Var(1 + 1 + v + 1)                      

                = Var(3) + Var(v)                      

                = 0 + 1 = 1

​Var(u|X​) = Var ( v + X | X)

            = Var ( v + X)

            = Var(v) + Var(X)

            =  1 + 2  = 3

Var(Y|X​) = Var ( 1 + X + u | X)

            = Var ( 1 + X + v + X | X)

            = Var ( 1 + 2X + v)

            = Var(1) + Var(2X) + Var(v)

              = 0 + 4*2 + 1 = 8 + 1 = 9

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9514 1404 393

Answer:

  367 miles per hour

Step-by-step explanation:

The speed of the faster train is half the total plus half the difference:

  s1 = (723.1 +10.9)/2 = 367 . . . . miles per hour

_____

Check

The slower train is 367-10.9 = 356.1, and the total is 723.1 mph, as required.

_____

If you want an equation, you can let x represent the faster speed. Then the total is ...

  x + (x -10.9) = 723.1

  2x = 723.1 +10.9

  x = (723.1 +10.9)/2 = 367

The answer is Critical value.

Lets try to answer this :

A critical value is a value used to determine whether or not to reject a null hypothesis when testing a hypothesis. A critical value is also referred to as a cut-off point or rejection region. A critical value is a point on a scale that separates the rejection area from the acceptance area in a statistical hypothesis test.

A t-test is a statistical hypothesis test that involves comparing the mean of two populations. A t-table is used to look up critical values for a t-test. When the t-value is computed, it can be compared to the critical value to determine whether or not to reject the null hypothesis.

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Answer: 7.5 cups of sugar.

Step-by-step explanation:

Add all of the above:

2+1.5+0.5+3+1.5= 8.5 cups of sugar

Since Zach only needs 1 cup of sugar, subtract 1 from 8.5.

Therefore, your answer is 7.5 cups of sugar.