Which electromagnetic wave is used in dental scans?

Answers

Answer 1

Answer:

X-rays are most often used to examine bones and teeth.

Hope this helps!


Related Questions

Pls Help Me with this problem

Pls Help Me with this problem

Answers

Answer:

explanation

Explanation:

1 = C

2 = A

3 = D

4 = E

5 = B

1) C, 2) B, 3) D, 4)A, 5)E

A kangaroo can jump over an object 2.20 m high with a vertical speed of 6.57 m/s. how long is it in the air

Answers

The kangaroo is in the air for approximately 0.667 seconds.

What is the velocity?

Velocity is defined as the displacement of the object in a given amount of time and is referred to as velocity.

A kangaroo with a vertical speed of 6.57 m/s may jump over an object 2.20 m high.

To find the time a kangaroo is in the air, we need to calculate the time it takes to reach the peak of its jump and then double that time (to account for both the ascent and descent).

We can use the formula for vertical motion under constant acceleration (g = 9.8 m/s²):

t = √(2h / g)

where h is the height of the jump (2.20 m) and g is the acceleration due to gravity (9.8 m/s²).

Plugging in the values, we get:

t = √(2 × 2.20 m / 9.8 m/s²)

t = √(0.447)

t ≈ 0.667 s

So the kangaroo is in the air for approximately 0.667 seconds.

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The ancient fish fossils were dated using C-14. If 1/16 the original amount of C-14 remains in the skeletons, approximately how old are the fish. The half-life of C-14 is 5730.
a) 11,460 years
b) 17,190 years
c) 22,920 years
d) 28,650 years​

Answers

Answer:

c) 22,920 years

Explanation:

The half-life of C-14 is 5730 so in 5730 years , amount of C-14 is reduced to half.

In 5730 x 2  years , the amount of C-14 is reduced to 1/4 .

In 5730 x 3 years ,  the amount of C-14 is reduced to 1/8 .

In 5730 x 4 years ,  the amount of C-14 is reduced to 1/16 .

In 22920 years ,  the amount of C-14 is reduced to 1/16 .

So the answer is 22920 years.

Voltage


Depends on the amount of resistance
Depends on the amount of current
Is the measurement of electrical pressure
All of the above

Answers

Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.

According to the Ohm's Law,  the current through a conductor between two points is directly proportional to the voltage across the two points.

Mathematically,

V ∝ I

V = IR

where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.

Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Hence All of the above option in the given question are true.

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An ac series circuit contains a resistor of 20 ohms, a capacitor of 0.75 microfarads of 120 x 10-3 H. If an effective (rms) voltage of 120 V is applied, what is the effective (rms) current when the circuit is in resonance

Answers

Answer:

The effective (rms) current when the circuit is in resonance is 6 A

Explanation:

Given;

resistance of the resistor, R = 20 ohms

capacitance of the capacitor, C = 0.75 microfarads

inductance of the inductor, L =  0.12 H

effective rms voltage, \(V_{rms}\) = 120

At resonance, the impedance Z = R, Since the capacitive reactance (Xc) is equal to inductive reactance (XL).

The effective (rms) current, = \(V_{rms}\) / R

                                              = 120 / 20

                                              = 6 A

Therefore, the effective (rms) current when the circuit is in resonance is 6 A

An object is stretched 5 mm by 180 N. Assuming the elastic limit is not exceeded, what is
the force that will be needed to stretch it 8 mm?

36N
180N
288N
468N

Answers

Answer:

288N

Explanation:

Engineers are working on a design for a cylindrical space habitation with a diameter of 7.50 km and length of 29.0 km. The habitation will simulate gravity by rotating along its axis. With what speed (in rad/s) should the habitation rotate so that the acceleration on its inner curved walls equals 8 times Earth's gravity

Answers

Answer:

The speed will be "0.144 rad/s".

Explanation:

Given that,

Diameter,

d = 7.50 km

Radius,

R = \(\frac{7.5}{2} \ Km\)

Acceleration on inner curve,

= 8 times

Now,

As we know,

⇒ \(\omega^2R=8g\)

or,

⇒ \(\omega=\sqrt{\frac{8g}{R} }\)

On substituting the values, we get

⇒     \(=\sqrt{\frac{8\times 9.8}{\frac{7.5}{2}\times 10^3 } }\)

⇒     \(=\sqrt{\frac{78.4}{3750} }\)

⇒     \(=\sqrt{0.0209}\)

⇒     \(=0.144 \ rad/s\)

An owl accidentally drops a mouse it is carrying, while flying horizontally at a speed of 16.0 m/s. The mouse drops to the ground 15.0 m below. What is the impact speed with which the mouse hits the ground?

Answers

The impact speed of the mouse is 23.3 m/s as per the data given in the question.

What is velocity?

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

To solve for the impact speed, we can use the following equation:

\(v^2 = u^2 + 2as\)

Where:

v = impact speed,

u = initial speed (which is the horizontal speed of the owl),

a = acceleration due to gravity (9.8 m/\(s^2\)), and

s = vertical distance fallen (15.0 m).

Substituting the known values, we get:

\(v^2 = 16.0^2 + 2 X 9.8 X 15.0\)

\(v^2\) = 256 + 294

\(v^2\) = 550

v = sqrt(550 )

v = 23.3 m/s

Thus, the impact speed of the mouse is 23.3 m/s.

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A string of length 75.0cm has fixed ends. Two consecutive harmonics are 420 Hz and 315 Hz. Find the wave speed and the fundamental frequency.

please use equations: f=vλ and λ=\(\frac{2L}{n}\)

Answers

The wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

Frequency is the number of cycles of a periodic waveform that occur per unit of time. It is measured in Hertz (Hz).

We can use the equation λ=2L/n, where λ is the wavelength, L is the length of the string, and n is the harmonic number. Since the string has fixed ends, the harmonics must be odd-numbered, so we have n=1 for the fundamental frequency, n=3 for the second harmonic (315 Hz), and n=5 for the third harmonic (420 Hz).

Using n=1 and λ=2L/n, we get:

λ = 2L/1

λ = 2L

Using n=3 and λ=2L/n, we get:

λ = 2L/3

Using n=5 and λ=2L/n, we get:

λ = 2L/5

We can use the formula f=v/λ to relate the wave speed v, wavelength λ, and frequency f. For the two consecutive harmonics, we can write:

v/λ1 = f1

v/λ2 = f2

Since the two harmonics are consecutive, we can assume that they correspond to adjacent values of n, so we have:

λ1 = 2L/1 = 2L

λ2 = 2L/3

Substituting these values into the above equations and solving for v, we get:

v = f1λ1 = f2λ2 = (420 Hz)(2L) / (2L) = (315 Hz)(2L)/(2L/3) = 840 cm/s

To find the fundamental frequency, we use the formula f=v/λ1:

f = v/λ1 = 840 cm/s / 2L = (840 cm/s) / (0.75 m) = 1120 Hz

Therefore, the wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

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.Given the displacement vectors A = 6f-4j+8k B = 2î+4ƒ^ − 14k
Find the magnitude and the unit vector of the vector 0.5A + 0.5B

Answers

Answer:

Explanation:

A = 6i - 4j + 8k

B = 2i + 4j - 14k

A + B = (6+2)i + (-4+4)j + (8-14)k

A + B = 8i +0j -6k

A + B = 8i - 6k

(1/2)(A + B) = 4i - 3k

d = √ (4² + 3²) = 5

e = (4/5)i -(3/4)j

A device that has the capacity to receive and store electrical energy is a(n)
.

Answers

A capacitor is used to receive and store electrical energy.

Answer:

Yes, capacitor is the correct answer

Explanation:

Define sporulation and fragmentation​

Answers

Answer:

Sporulation

the formations of spores from vegetative cells during unfavorable environmental conditions

Fragmentation

The asexual reproduction, where the body of the organism breaks into smaller pieces

Fragmentation: The breaking up of the body of organisms into two or more pieces or fragments on maturing, each of which subsequently can grow into a completely new organism is called fragmentation.

Definition of sporulation

: the formation of spores

sporulation refers to the formation of spores from vegetative cells during unfavorable environmental conditions. As such, it may be described as an adaptive response that allows the organism to survive given adverse conditions (radiation, extreme heat or cold, lack of nutrition etc).

A factory is closing in 15 minutes. A box on one of the factory's conveyor belts is 8meters from a storage area and is moving at a constant velocity of 40metersperminute down the conveyor belt. How long will it take the box to get to the storage area?

Answers

The time taken for the box to get to the storage area, given that the box is moving at a constant velocity of 40 meters per minute is 0.2 minutes

How do i determine the time taken?

Speed is defined as the distance travelled per time as shown below:

Speed = Distance / time

Cross multiply

Speed × time = distance

Divide both sides by speed

Time = Distance / speed

The following data were obtained from the question:

Distance from storage area = 8 metersConstant  speed of box = 40 meters per minuteTime taken =?

The time take can be obtained as follow:

Time = Distance / speed

Time = 8 / 40

Time = 0.2 minutes

Thus, the time taken to get the storage area is 0.2 minutes

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Three identical point charges, Q = 2 PC, are placed at the vertices of an equilateral triangle as shown in the figure. The length of each side of the triangle is d
= 2 m. Determine the magnitude and direction of the total electrostatic force on the charge at the top of the triangle.

Answers

Answer:

The total force on the charge at the top of the triangle is approximately

\(1.56\,\,10^{-14}\,\,N\)

Explanation:

Please look at the attached image to follow the explanation.

Since all charges are of the same positive value, the force exerted on the top charge by the other two are going to be on the line that joins the top charge with each of the other vertices of the triangle, pointing away from the top charge (illustrated by green vectors of the same length in the image).

We need to find the x and y components of these force vectors in order to find the resultant force by combining the x  components among themselves, and the y components among themselves. Notice that the angle needed is in all cases \(60^o\).

The x- components include the cosine of \(60^o\), while the y components include the sine of \(60^o\).

Notice as well that the x-components cancel each other (they have the same magnitude but point in opposite directions), while the y-components are both of the same value but pointing in the same direction (pointing up).

Then we just need to multiply by two the y component of one of the forces to find this total force.

Now, the magnitude of the forces in question are given by Coulomb's Law:

\(F_C=k\,\frac{q_1\,\,q_2}{d^2} =9\,\,10^9\,\frac{2\,\,10^{-12}\,\,2\,\,10^{-12}}{2^2} =9\,\,10^{-15}\,\,N\)

therefore we can calculate what the y-component of this is using:

\(F_y=F\,sin(60^o)=9\,\,10^{-15} \,\frac{\sqrt{3} }{2} \\\)

and twice this value becomes:

\(2\, \,F_y=(2)\,\,9\,\,10^{-15} \,\frac{\sqrt{3} }{2}=9\,\,\sqrt{3} \,\,10^{-15}\approx 1.56\,\,10^{-14}\,\,N\)

Three identical point charges, Q = 2 PC, are placed at the vertices of an equilateral triangle as shown

WILL GIVE BRAINLESS IF U ANSER ALL CORECTLY
1 What does wind do as it goes up and over a mountain range?

2 What is the climate on the windward side of a mountain range like?

3 What is the climate on the leeward side of a mountain like?

4 What are rain shadow deserts?

5 What are the characteristics (wind, precipitation, vegetation) seen on the windward side of the Sierra Nevada Mountains?

6 What are the characteristics (wind, precipitation, vegetation) seen on the leeward side of the Sierra Nevada Mountains?

Answers

Answer:

1-As winds rise up the windward side of a mountain range, the air cools and precipitation falls.

2-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls.

3-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks.

4-Rain shadow deserts are formed because tall mountain ranges prevent moisture-rich clouds from reaching areas on the lee, or protected side, of the range.

5-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.

6-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.

Explanation:

#6 and 5 are the same

Which option correctly matches the chemical formula of a compound with its name?

A. N2O3, dinitrogen trioxide
B. N2O, trinitrogen dioxide
C. N2O, dinitrogen trioxide
D. N2O3, trinitrogen dioxide

Answers

Answer:

A is indeed correct

Explanation:

just did the question

The option that correctly matches the chemical formula of a compound with its name is NO dinitrogen trioxide.

What is dinitrogen trioxide?

Dinitrogen trioxide is one of the simple nitrogen oxide. The chemical compound formula of Dinitrogen trioxide N₂O₃.

That is, it consists of 2 molecules of nitrogen, hence the prefix "Di" and 3 molecules of oxygen given the prefix tri.

Thus, the option that correctly matches the chemical formula of a compound with its name is NO dinitrogen trioxide.

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In Figure 10.13, the author illustrates a book being raised at constant speed. Which of the following statements are true? Select all that apply.

There is no change in the kinetic energy of the book.

The potential energy of the book-Earth system decreases.

The potential energy of the book-Earth system increases.

The potential energy of the book increases.

In Figure 10.13, the author illustrates a book being raised at constant speed. Which of the following

Answers

Answer:

There is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

Explanation:

This is because velocity is constantly increasing. This supports the idea that the kinetic energy of the book doesn't change and that the potential energy of the book-Earth system increases.

The true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

We have to note that from the law of conservation of mechanical energy, the sum of the kinetic and potential energy of the book at any point remains constant.

If the book is being raised at constant speed, the the true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

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explain why the ray does not bend when it enters the semi circular glass block

Answers

The ray does not bend when it enters the semi circular glass block - Light ray incident on semicircular block at 90 degrees, therefore there is no change in the direction of ray at P.

Electromagnetic radiation that falls within the region of the electromagnetic spectrum that the human eye can see is known as light or visible light.

Light is electromagnetic radiation that the human eye can perceive. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than around 1 1011 meters, electromagnetic radiation occurs throughout an incredibly broad range of wavelengths.

Light governs our sleep-wake cycle and is crucial to our health and wellbeing. In actuality, "light" that is visible is a type of radiation, which is just energy that moves in the form of electromagnetic waves. It can alternatively be explained as a flow of "wave-packets," or particles, known as photons.

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Ex 2) A cannon ball is shot straight up into the air with an initial velocity of 25 m/s[Up).
What is the maximum height of the cannonball?

Answers

Explanation:

The final velocity at the cannon ball's maximum height is zero (\(v_y = 0\)). We can use the equation

\(v_y^2 = 0 = v_{0y}^2 - 2gy_{max}\)

\(\Rightarrow y_{max} = \dfrac{v_{0y}^2}{2g}\)

\(y_{max} = \dfrac{(25\:\text{m/s})^2}{2(9.8\:\text{m/s}^2)}\)

\(\:\:\:\:\:\:\:=31.9\:\text{m}\)

what is the mass on grams of 0.56 moles of NaCl

Answers

Answer:

1 mole of Na = 23 g

1 mole of Cl = 35 g

1 mole of NaCl = 58 g

.56 * 58 g = 32.5 g

it is desired to produces a resonant circuit in the laboratory with 1H inductor at 100Hz. What capacitance should be used?​

Answers

To create a resonant circuit with a 1H inductor at 100Hz, a capacitance of 0.0159 microfarads (uF) should be used.

1. Determine the frequency of the resonant circuit, which is given as 100Hz.

2. The formula for calculating the resonant frequency of an LC circuit is: f = 1 / (2π√(LC)), where f is the frequency, L is the inductance, and C is the capacitance.

3. Rearrange the formula to solve for C: C = 1 / (4π²f²L).

4. Substitute the given values into the formula: C = 1 / (4π² * 100² * 1).

5. Calculate the capacitance using a calculator or mathematical software: C ≈ 1.5915 × 10^(-5) farads.

6. Convert the capacitance to microfarads for convenience: 1 farad = 1,000,000 microfarads, so C ≈ 15.915 uF.

7. Round the capacitance to an appropriate number of significant figures, resulting in a capacitance of 0.0159 uF (or 15.9 nF).

Therefore, to produce a resonant circuit with a 1H inductor at 100Hz, a capacitance of approximately 0.0159 microfarads (uF) should be used.

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A string of a given length and diameter and density is under a tension of 100 N and produces a sound of 200 Hz. How many vibrations per second will be produced if the tension is changed to :A. 900 NB. 25 N

Answers

Given,

The length, diameter, and density are given, i.e., the length, diameter and density of the string are constant.

The tension on the string, T₁=100 N

The frequency of the sound, f₁=200 Hz

The tension on the string and the frequency of the sound is related as,

\(T=4ml^2f^2\)

Where m is the mass of the string and l is the length of the string.

On rearranging the above equation,

\(\frac{T}{f}=4ml^2\)

As the length, diameter, and density of the string is constant,

\(\begin{gathered} \frac{T}{f}=\text{constant} \\ \frac{T_1}{f_1}=\frac{T_2}{f_2} \end{gathered}\)

A.

Given,

Tension in the string, T₂=900 N

The frequency of the string after the change in the tension is given by,

\(\begin{gathered} \frac{T_1}{f_1}=\frac{T_2}{f_2} \\ \Rightarrow f_2=\frac{T_2\times f_1}{T_1} \end{gathered}\)

On substituting the known values,

\(\begin{gathered} f_2=\frac{900\times200}{100} \\ =1800\text{ Hz} \end{gathered}\)

Thus the frequency of the sound after the tension on the string changes to 900 N is 1800 Hz, i.e., 1800 vibrations are produced per second.

B.

Given,

The tension on the string, T₃=25 N

The frequency of the string after the tension changes to 25 N is given by,

\(\begin{gathered} \frac{T_1}{f_1}=\frac{T_3}{f_3}_{} \\ \Rightarrow f_3=\frac{T_3\times f_1}{T_1} \end{gathered}\)

On substituting the known values,

\(\begin{gathered} f_3=\frac{25\times200_{}}{100} \\ =50\text{ Hz} \end{gathered}\)

Thus the frequency of the sound after the tension changes to 25 N is 50 Hz, i.e., 50 vibrations are produced per second.

what is the Vector product of A=2.00i+3.00j+1.00k and B= 1.00i -3.00j -2,00k

Answers

The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.

To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:

C = A × B

Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.

Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:

C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)

Now, let's expand the cross product using the properties of vector products:

C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +

   (3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +

   (1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)

Now, let's calculate each of these cross products:

C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +

   (3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +

   (1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)

Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:

C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k

Combining like terms, we get:

C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)

Simplifying further:

C = 6.00i - 12.00j + k

Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.

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Final answer:

The vector product of A and B is -3i - 5j - 9k.

Explanation:

The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.

In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.

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A seesaw is balanced on a pivot point. If a 20 kg child sits 1 meter from the pivot point, how far from the pivot point should a 40 kg child sit in order to balance the seesaw?​

Answers

Okay, here are the steps to solve this problem:

1) The seesaw is balanced when the sum of moments is 0.

2) The moment created by a force depends on the force and the perpendicular distance from the pivot point.

3) The 20 kg child sits 1 meter from the pivot. So its moment is 20 * 1 = 20 kg*m.

4) We want to find the distance for the 40 kg child to create a moment that balances the 20 kg child's moment.

5) So the moment of the 40 kg child must be 20 kg*m.

6) The moment depends on force and distance. We know the force is 40 kg.

7) So we set: 40 kg * distance = 20 kg*m

8) And solve for the distance: distance = 20 / 40 = 0.5 meters

Therefore, for the seesaw to balance with a 20 kg child 1 meter from the pivot and a 40 kg child on the other side, the 40 kg child should sit 0.5 meters from the pivot point.

Let me know if you have any other questions!

pls help!!

An object is placed 3.0 cm away from a convex lens of focal length 2.0 cm as shown in fig.


1. Use the lens equation to calculate the image distance.

2. Is the image real or virtual? how do you know ?

pls help!!An object is placed 3.0 cm away from a convex lens of focal length 2.0 cm as shown in fig.

Answers

(1) The distance of the image formed by the lens is determined as 6 cm.

(2) The image formed is real.

What is the image distance?

The distance of the image formed by the lens is calculated by applying the following formula as follows;

1/f = 1/v + 1/u

where;

v is the image distanceu is the object distancef is the focal length of the lens

The distance of the image formed by the lens is calculated as;

1/v = 1/f - 1/u

1/v = 1/2 - 1/3

1/v = 1/6

v = 6 cm

Since the sign of the image of the image is positive, the image formed is real.

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Which common characteristic of planets do Saturn and Earth share?

They have rings.
They have moons.
They are made of rock.
They have thick atmospheres.

Answers

i believe it’s
“they have thick atmospheres”
i hope i’m right and this helped you

The common characteristics  of planets do Saturn and Earth share is they both have moon. Saturn have 13 moons and earth have only one moon.

What is moons of planets?

Moons of planets are spatial objects which revolves around a planet and experiences gravitational pull from the planet. Both saturn and earth are planets of solar system.

The earth that is the only planet planet with living things have only one moon which is called moon itself. Earth is entirely different from the composition and nature of all other planets.

Saturn have 13 moons namely, enceladus, janus, mimas etc. Saturn have some rings made of dust and gases which are not found for any other planet. The composition and gaseous matter in saturn is different from that of earth.

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is burning trash a physical change or chemical change?

Answers

it's a chemical chemical change

Which statements accurately describe mechanical waves? Check all that apply.

Answers

The accurate statements that describe mechanical waves are: Mechanical waves require a medium , Mechanical waves transfer energy, Mechanical waves can be longitudinal or transverse, Mechanical waves can be categorized as compressional or shear waves, Mechanical waves obey the principles of reflection, refraction, and interference, Mechanical waves have measurable properties such as wavelength, frequency, and amplitude.

Mechanical waves are a type of wave that require a medium, such as a solid, liquid, or gas, to propagate. They are characterized by the transfer of energy through the oscillation or vibration of particles in the medium. Here are the accurate statements that describe mechanical waves:

1. Mechanical waves require a medium: This statement is true. Mechanical waves cannot propagate in a vacuum because they rely on the interaction of particles in a medium to transfer energy.

2. Mechanical waves transfer energy: This statement is true. Mechanical waves transport energy from one location to another as the particles of the medium vibrate or oscillate.

3. Mechanical waves can be longitudinal or transverse: This statement is true. Mechanical waves can exhibit different types of motion. In longitudinal waves, the particles of the medium oscillate parallel to the direction of wave propagation. In transverse waves, the particles oscillate perpendicular to the direction of wave propagation.

4. Mechanical waves can be categorized as compressional or shear waves: This statement is true. In a compressional wave, the particles of the medium undergo compression and rarefaction as the wave passes through. In shear waves, the particles move perpendicular to the direction of wave propagation, resulting in a sideways displacement.

5. Mechanical waves obey the principles of reflection, refraction, and interference: This statement is true. Mechanical waves can reflect off surfaces, change direction when passing through different media (refraction), and exhibit interference patterns when two or more waves interact.

6. Mechanical waves have measurable properties such as wavelength, frequency, and amplitude: This statement is true. Mechanical waves can be described by various properties. Wavelength represents the distance between two consecutive points in the wave, frequency is the number of wave cycles per unit of time, and amplitude is the maximum displacement of particles from their equilibrium position.

These statements accurately describe mechanical waves and their properties, highlighting the key characteristics of this type of wave propagation.

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When measuring the critical angle, in which medium do we need the refracted ray to be (air or glass)

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Answer:

N1 sin theta1 = N2 sin theta2       Snell's Law

For the refracted ray to be reflected then sin theta2 = 1

N1 sin theta 1 = N2

Also N2 must be less than N1 for complete reflection

sin theta1 = N2/N1

If you are considering air and glass then N2 = 1   (for air)

sin theta1 = 1 / N2    where N2 must be for glass in this case

What is the power rating of a heating coil with a resis-tance of 12 12 that draws a current of 20 A?

Answers

According to the problem, we have the following

\(\begin{gathered} R=12 \\ I=20 \end{gathered}\)

We have to use Ohm's law

\(V=I\cdot R\)

Let's replace the given information

\(V=20\cdot12=240\)Hence, the power is 20 Volts.
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